[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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* **  ****** **  *** ** ***** * ***  ** your input:"); //DO NOT CHANGE
 ** * **    *  ** * **** *** ****  * * *   *  **
    
* ** * *   * * * *  **  *   ** *** Your conditions start from here
**** ** ** * * ** *   ****  ** = 'A'; a <= 'Z'; a++){
** * * * ***  ***  * *  * *    ** **   ******   **   * **   *   ***      * 
* *** *         *** * ***   * * ** *  **     ****   *** *     **  * a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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* * * *** ****  *  *** **    * ***  **** ** *   ***   ** *****  ** * ** * *  * * * *  ***    ** 
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    *  * **  *      * *** **  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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******     * *    *   **   

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include   ***  **  ****
#include * *   ** *    *   

int main(int argc, char *argv[]) {

**     **   char a;
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*** *  ***  *** * * **  * ** *  **** *  * *  *** a++;
   * * *  **  }

 * *   * **** *   return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include ** ** **  **   * 
#include *   *  *      **

int main(int argc, char *argv[]) {

* *        * ** char a;
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* **    * ** return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include    * * * * * 
*  *   *    *  *** ***  

int main(int argc, char *argv[]) {

**    ** **  *  char a;
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**    *   *** *  *  *     **    **  *  **  a++;
  * ** ** *   }

  *       return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include  ** **  **  *
#include  ** * *  **    

int main(int argc, char *argv[]) {

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 * * * *    *  *  * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include   *  *   * ** ** 
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int main(int argc, char *argv[]) {

** *    **  int a;
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**   ***  *           ** * * *  ** *    a++;
    * ** *     }

 *  **  *  * **  ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int **  * * argc, char * *** {
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**** ** *  *** ***  ** * *  *  *  a++;
** *** * ****** *  }
*  **  *     *  * 
** * *    * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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** ** **** *  ** ****     **  * ***** *  *   &a);
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* *  *  * * * * * *  ***  ***   **  *    *******
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
**      *     ** * **      **  a;
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   *   **** ** *****    **    ******* *       * * * ** *
*  ****   *   **  *  *  * *  *
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output