0 like 0 dislike
14.3k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 14.3k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** ** * * * * i=0;
** * ** ** **** * *
*** * *** ** * * **** * * ** * *** *
* * ** * *** * * *** * **** * * * ** * * ** *** * *** ** ** *
* ** * *** * *** ** * * ** * ** ****
*** * *** * * ***** **** * i;

}



int check2(char c)

{
** ** ** **** * * * j=0;
** * * ** * * ** *** **
*** *** * * *** * * **
****** * ** * * ** * * *** ********* **** ** **
* ******* * ** * ** ** * * * * ***
* * * * ***** *** * j;

}

int main()

{
* * *** * * *** c;
* * * * ** * *** * ** i=0,j=0;
* * * *** **** ** **** *** * ** ** * ****

    
* ** * * ** **** * ** * *** c!='.')
*** * * * ** * * **** *


*** * * * **** ** * ** *** ** * * * **** **** ***
**** * * ** * * ** ** ** * *
* *** * ***** **** * * ****** ** **** * * * ** * * * **** ** ** ** *
*** *** * * * **
* * * *** * * ** * * ******** * *** *** ** ** *** * ** * * ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** * * ** * * *
*** * * * *

int main (void)
** **

char c;

int i = 0;

void ** c)

{
* ** *

i++;
** **

i++;
* ** *** ** *
** * * ** ** ***** ** * * ** ** * * * *
**** * * ** * *** * * * 0;

}
* ** ;

}
* ** * * * * *** ** ***
* ** * ** * ** ** ** ***** * * ***
* *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * ** * **** **** * a1=0,a2=0,a3=0,a4=0,in;
*** * * *** * *** *** ******* && c[in];in++)

    {
* * *** * * * ** **** ** ** * (48<=c[in] && c[in]<=57)
**** *** ** * **** *** ** ** * * * * * * *
* *** * * * ** *** * ** ** ** ** * * **** ** * * * **
*** * * **** ** * *** * * *** ***** * * * * * **
*** ***** * * * ***** ****** **** if(65<=c[in] && c[in]<=90)
**** * * ** * ** *** ** * * * ** ***
** * ** * * **** * * * * *** * ** **** * ** * * *** * ** * ***** ** ** *
** ** * * ***** *** * *** ** * *** ** *** * * **
* * ** **** * ** ** * * * * * * **** *** * * if (97<=c[in] && c[in]<=122)
* * * * *** * * ** * * * * * ** * *
** * *** ** **** ** ** *** **** * * * ***** * * ** * ** ****
*** ** ***** * *** * **** * ** * ***
*** ** * *** * ***** ** * **** * * * ** * * * * if(39<=c[in] && c[in]<=46)
** ** * *** *** * ** ** * ** ** * * * * * ** *
* * ** * * ** * ** * * * ** ******* ** ******* * * * ****** *** ****
*** * * ** * ** * * * * *** *** * ** *
* ** * ** ****** * * * *** *** * ** *** ** * * *
* * * * * * * * * * *** ** * ** * **** **
* ** * *** * * *** * ** ** ** * ********* * * * * * * * * * * ** *****
* *** * ***** * ** ** ***** * * ** * *** ***
*** * ******** *** ***** ***
* * **** * * *** * **** * *** * * * *** * *** ** * *** *

 }

 

 int main()

{
* *** ** **** * * * ** c[100];
* * * ***** * * ** * * *** *
* * ** * * * * * * *

    
** ** * * * * * * *** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** ** *** *** *** * **** i=0;
*** * ** ** ** ** ** * ** *
*** **** ** **** ****** ** * * * * * *** * *
***** ** ** * * * * * * * ** * ** **** * *** *
* ** * *** * * * *** ** ** * ** ** * * * *
**** ***** ** **** ****** i;

}



int check2(char c)

{
* ** * * * ** * ** *** * j=0;
***** *** *** * * ** * * ***** * *
** * * *** * * * * * *** * ******** * *
* ******** *** *** * * ** * * * * ******** * * **
*** *** * ** * ** * * *** * ***** ** * * ** *
**** * ** * * **** * * ****** j;

}

int main()

{
******** ** * * * * ** * * c;
*** * * ** * ** * *** i=0,j=0;
* ** ** **** * ** ** **** *** *** *** *** * *

    
* * * ** * * c!='.')
*** * **** * ** ** *


* *** * * *** * * * *** ** ** * * * * *
** ** *** *** * * * **** ****** * *** ***
**** * * * ****** * ** *** * ** * * ** * * *** * ******
****** * * * * * ***
* * * ** **** ** ** ** * * * ** **** * ** * * * * ** ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
**** *** ** *** * ** i=0;
**** * * * *** * **
* ** * * ** * ** * * **** * ** * * *
*** * * * * ** ** * * ***** * ***** ** * *
** ** *** * * * ***** * * * * **
** * * ** * * * i;

}



int check2(char c)

{
* *** *** * * ** * *** * j=0;
** * * *** * * ******* ** ** **
** ** *** * * * ** ** ** ** * *** *
*** ********* * ** ** * * **** * * *
* * * ** * ** *** * * ** **** *
** * * * *** ** * * j;

}

int main()

{
*** ** **** **** ** ** * c;
* **** ***** * * * * * ** i=0,j=0;
*** * ** * *** **** ****** * *** * **
** *** * * * * * ** ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
** * * * **** * ** *** ***** **
*** * *** ** ***** **** ** * ** * * * * * *
* * ** ** * * * ***
** * * * **** * c!='.')
* * * ** * ** *


* * ** * **** * **** ** ** ** * ***
** ** * ** *** * * *** * * * * ** * *** ** ** *
* * ** * *** ** **** *** * * ** * * * * ******** *** ***
* * ** *****
* ** * * ** * * * * * ** ** * **** * * * ** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * ***
** * * * * **

int main * *
*** *

char c;

int i = 0;

void * c)

{
* ** *
* *
* ** * **
**
* * *
*** *** *** ** **** **** * ** 0;

}
** ;

}
*** * * ** * **** * * * ******
** *

}
** * ***** * * *
* * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
*** * *** *** * **** * ******** ** c;


*** * ** ** * *** * i = 0,b = 0;


* *** ** *** ** * ** * * ** *** * ***** &c);
** * * ***** * * * *** * c != '.')
*** ******** ** *** ** * ***
* * ** * ** * * **** ** * * * * * * **** * *






* * * *** ** **** * ** * * *** ** += 1;


** ** *** *** * * ** **** * *** ** ***** ** &c);
* *** ** * *** * * **** * * **** **
*** ** ********* *** ****** ** ** *** ** * ** *


****** ***** * ** **** * ** * * * **** * i);


****** * **** ** * ** * * ** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
**** * *****
* * * *** ***** ** * *
*** main * *
*******
* c;

int i = 0;
* ** ** * c)

{
* **
**
** * **
**
** ;

}
* * *** * ****** ** **
*

}








**** ** * * * *
* *** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** * * * i=0;
* * ** ** **** * ** * ** * *
* * ** ** * * ** * *** ** ** * *
*** * * * * * ** * *** ** ** ** ** ** *******
** ******** * ** *** *** *** *** ****
* *** * ** * ******** i;

}



int check2(char c)

{
** * *** *** * **** j=0;
*** *** * * *** ** *** *
** * ** *** ** ** *** ***** *********
* * * * *** ** * ** * ** * * ** **** * **** **
* * *** ** *** ** * * ** *** *** ** * *
* * **** *** *** ** ** * ** j;

}

int main(void)

{
**** *** **** ** ** * * * * c;
* * **** * ** i=0,j=0;
*** *** ** * * ***** * ********* * * *
* *** * **** *** * * ** c!='.')
** * ** * *** * ****


* ** ** **** ** ***** *** * * * ** ** *** *
* ** *** ***** * * ***** ** * ** *** * * * *
* * * * * ** * *** * ** * * *** * ****** ****** * ** **

    }
* ****** **** * * *** * *** ***** * **** *** * * **** * * * ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
****** * ** * **
* ** ** **** * * * * *

int main **
* *** *
* c ;

int i = 0;
* ** * ** * * * **** * * **
* *


** * *** * c)

{
** * ** *
**
* * * *

* ;

}




* ** * * * *
* * *** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 8.2k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users