0 like 0 dislike
6.6k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 6.6k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ***** ****** *** * ** *** i=0;
* ** * * * *** ** ***
* * *** **** * * *** * * **** ** ** * *
*** **** ** *** * * * * * * ******** * ***
** *** * **** ** * * * * * *** ** * *
** ****** * * * ******* *** i;

}



int check2(char c)

{
***** *** * * ***** * ** * j=0;
* ** **** ** ** * **** ** * *
*** ****** * * ********** ** ** *
* * ** * *** ** *** ***** * * ***** * ***** * * **
* * ***** * * *** *** ** * ** * * * ***** **
* ** * **** * *** * * j;

}

int main()

{
************** * * * **** c;
**** * * * *** * * * * * ***** i=0,j=0;
******* * * *** **** ** * *** ** ** *

    
* ** * ****** * ** * ** c!='.')
* ** * * * * * * * **** **


** * ***** * * * * ** * * * * * ****** * * * * **
** * * * *** * ** * * * * *** *** * * * ***
* * * **** *** * ** * * * ***** * * * *** ***** ** * *** **** ** *
**** ** * * ** *** * *
*** ****** ** *** * * **** *** ***** ********* * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ******** * * *
* * ** ** * *** *

int main (void)
** *** *

char c;

int i = 0;

void * * * c)

{
*

i++;
****

i++;
* *** * * ** *
* ************* * * * **** *** ** ***
* **** * * * ** * * **** 0;

}
*** ;

}
** *** *** ** **** * * * *
** ** * ** * ** **** ** * *
** *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* ** ** * * * *** * * * a1=0,a2=0,a3=0,a4=0,in;
*** *** * * ** * ***** * && c[in];in++)

    {
* ** * * **** * ** ** * *** ** **** * *** * *** (48<=c[in] && c[in]<=57)
* ** ** ** * * *** ** * * ** * **** ** * *
* * * ** **** * * ** * * *** * ** * ** **** * ** **** ** * *
*** ** * * **** * * * ** * ** ** * *** * * *** *
*** *** * * * ** * * ** * ** ** * * ** ** *** * * * ** if(65<=c[in] && c[in]<=90)
*** * ** * ** * * *** *** * * * ** *** *
* ** * * * **** ** * * * * **** * ******* * * * * ** *** **
****** *** ** * *** ****** **** * *** *** *
* * * ** * * *** * * ** ** * **** * * * * if (97<=c[in] && c[in]<=122)
* ** *** * *** * ***** ** ** * * ** *
**** **** *** **** * * ** * * *** ***** * ** ** ** * * **** * ** **
** **** * * * *** ** ** **** * * * **** *
*** *** *** * ***** ** **** ** *** ****** * * if(39<=c[in] && c[in]<=46)
* ** ***** * * **** * *** ** *** **** *
** * ** *** ** ******** **** ******* *** * * **** ****** * ******** *** * ** * * **
* * *** **** ** * * * * ** * * * ** **
** ** ** * ** ** ** * ** * * * ** * * ** *
**** * ***** * * * ** * *** *** *** *** **
** * * ** * ** *** ** ** * ** *** * * *** *** * * ** *
** ****** ** **** **** ** *** ** * ** ** ** * * * **
*** * * * ** ** * ***
* * * * *** * * ** ** ** * ** * * * * *

 }

 

 int main()

{
* ** ** ******* * **** c[100];
* *** *** ** * *** *
* * * *** * **** ** * *

    
* *** * * ***** ** * * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* *** ** ** * * * ** i=0;
*** *** ** *** * * ** ***
* ** *** * ** ****** ***** * *** * *
* *** **** *** * * * * *** * ****** * * * * * *** *
** ** *** * *** *** ** *** ** * *
** *** ** * *** ******* ** * * * i;

}



int check2(char c)

{
* *** ***** ** * * ** j=0;
***** * * ** **** * * *
**** * ** *** ** ** * * *** * * ***** *
******** * ** * * ** **** *** * * ** * ** *
*** * * ** ** ** **** * **** * * *
* * ** ** ** * * j;

}

int main()

{
*** * ** * * *** c;
*** ** ** **** * i=0,j=0;
*** * ** ** ** **** * * * *** **

    
* **** ** *** * * ** **** ** c!='.')
* * * * * ** *** ****


* ** ** ** ** **** * *** **** *** ** ** ** *
**** ** ** **** * * *** * ** * *** * ** *** **
* **** * * * * ** * * * * *** ****** * *** *** * * * ** * ** **
* ** * *** ** ******
** ** ******** * * * * ** *** *** ** ** * ** * ** ***** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** * **** * ** * * *** i=0;
* *** *** ** * **** * **** ** *
* * * ****** ** *** * **** * ** * * * * **
** * * ** *** **** * ** * * * ** * *** **
* * * *** * ** *** ** ** *** **
**** ****** * ****** * i;

}



int check2(char c)

{
** * * *** ** **** * ** j=0;
* *** *** ** * * * * * ** ** **
** * * ** **** * *** * ** *
* ** *** ***** * *** * * ** * * ***** ***** *
*** * ** *** * *** **** *** **** * * ***
* ***** * ** * *** * * j;

}

int main()

{
* * ** ******* * * ** * c;
** **** **** ***** * ** * ** i=0,j=0;
*** ** * *** ** ** * * * * * *** ** ** *** * **
** * * *** * * * * * * *** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* ** **** * ** ** * * *
* * * *** *** * ** * * * * * * * ** **** *** * *** * * * *
* * * *** * *****
**** * * * * * * *** ** c!='.')
* * * * ** ** **


* * * ** ******* * **** ***** * * ** ** ** ***
* ***** * *** * * * * * * ** * * ** ** *
*** **** * * * ***** * ** * *** ** * *** ** * ** * * * * * ** *
** ** **** ** * * * ** *
** * *** *** ** * * ** ** * *** * ***** * * **** * ***** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
***** ** *** **
*** ** * ** * * **

int main **
* * **

char c;

int i = 0;

void **** ** * c)

{
* ** *
*
*** ****
*
** * * *** *
* * * **** ** * ** * 0;

}
*** ;

}
* * * *** * ** ** * ** ** ***
* *

}
**** * * ** * *
**** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
***** *** * ******** * * c;


* * ** * ** * ** **** i = 0,b = 0;


* * * *** ******* * * ******* * * * ** &c);
* ** ***** *** *** c != '.')
* * * * * *** ***
******* *** * ** ** ** * * * * ** * ***** *






** * ** * * * ** * ** ** ** * ** * * ******** += 1;


** ***** * * **** * * * ** ** * **** **** * **** *** ***** *** ** * &c);
* * ** *** ** * *** * ** *** * * * ** * **** * *
* * * * ** * * * * * *** ** * ** ** ** * * **


* * ** * * ** * ** * ***** * ** ** ** ** i);


*** ** * * *** ** ** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
**** ** * *****
**** * ******* *
* * main **
* ****
* * c;

int i = 0;
* ** * c)

{
* ****
** *
* * *
*
** ;

}
** * * ** ** *** * * *** *** **
**

}








**** * *** ***
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** ** *** * * i=0;
* ** * ****** * * * ** ** * ***
* *** ** * *** * ** * * ***** ** ** * *
* ** * * * * * ** **** * ** ** * ****** * * * **
** *** * * ** * * * ** ** ***
** ** **** *** * ********* i;

}



int check2(char c)

{
** ** * ** ** * * j=0;
** * **** * * *** *** * * *
*** * *** ***** ** ** * * **
* * * * ** ** ******* * * ** * * * ***** **
* * ******* * *** * * **** ***** * ** * *****
***** *** ** ** * * * * j;

}

int main(void)

{
* * * * ** **** * ** c;
** * ** * * *** i=0,j=0;
** * ** * ** * ** * *** ** * ** * *
*** ******** ** ****** * c!='.')
* * * * * ******* ****


* **** ** * ** ** ** ** * ******* * **
* * * ***** ** * * * * * ** * *** * ** **
****** * ** * * * ** * *** ** * * **** **** * **** * ** ** * *

    }
* * * * * * *** * * **** * * *** * ** * * * * **** ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * * *** **
*** *** ** **** * *

int main *
* *
*** * c ;

int i = 0;
** * ** ***** * * ** *
** *


* * * c)

{
**** *

*
* *
** ;

}




** *** * * * *****
**** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.54
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users