0 like 0 dislike
6.7k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 6.7k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* **** * *** * ** * i=0;
** * *** * ** * ** ** * * * ** * **
** * ** ***** * * * ***** **** * *
****** * * * * **** ** ** * ** * * * * **** ** **
* ** * * ** *** * **** ** **
* * * ** * ****** **** i;

}



int check2(char c)

{
********* * * * * * ** *** j=0;
** * **** * ** * ** * *
** * * * ** * * ** * * *** * ** * *
* * * *** ** * **** *** *** * ** * * * * *** *
* ********* ** * **** * *** * ** *
** **** * * * * * ***** * ** ** ** j;

}

int main()

{
* *** ** * * * *** c;
* * ** * *** * *** * ** i=0,j=0;
* *** ** * ***** *** * * * ** ** ** ** * * * *

    
*** * ***** * *** * ** c!='.')
******* * * * * **


* * ***** ****** * ** ** *** ** * **** * * *
* ** * **** *** * * ** * ** * *** * **
*** **** * * * ** * * *** * * * * * ** * *** * ** *** ** *
* ** **** * ****** ** * *
* *** * ********* * ** * ** * * * * *** * ***** * *** * *** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
**** * **** ** * ***
* ******* *

int main (void)
* **

char c;

int i = 0;

void ** ** c)

{
*** ** **

i++;
*** ***

i++;
* ** * ** * * *
**** * ** * ** ** * **** * ***
* ** ******* * ** * * * * 0;

}
*** ;

}
** ** * * ***** * * * ***
* ** ** ** ** * * ** *** *
* *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
**** * * * ** ** a1=0,a2=0,a3=0,a4=0,in;
* * * *** *** ** * * * * ** ** && c[in];in++)

    {
*** *** ** * * ** ** ** **** ** **** ***** ** (48<=c[in] && c[in]<=57)
* * * * * ** * ** * **
** * * * ** ****** ** **** ** * *** * * * *** * ***
*** **** * ** ** * ** *** * * ** * * * * **
** ** * ***** **** *** * **** * ** * *** if(65<=c[in] && c[in]<=90)
*** ** ** ** * * * * *** ** ** * * * ** **
*** * * ** * * * * ** * * ***** ***** **** * ** ******** *
* ** * ** * ** ******* *** * * * * *** * *** ****
* * * * **** * ** * * ** ****** * * ** * if (97<=c[in] && c[in]<=122)
* ** *** * * * ** ** * *** *** * * *** **
* *** ** ** * **** * * * * * ** * * ** *** **** * ** * ** * * *
* ** * ** * * *** * ** *** * * * * **
* *** *** ** ** ** ** *** * * ** * *** ** * * if(39<=c[in] && c[in]<=46)
* * * * * * * * * * ** * * * * * **
* * ***** **** * * * * *** *** * ****** **** ** ** *** *** *
** ** ** * ** **** *** * * ** *** * * * * * *
* ** * * * * * * ** ** * * ** *** * * * * *
* * * **** *** * * * ** * * * * * * * *
* * * *** * * ** ** * * * ** * ***** * * * * *** * *** **** ** *
* ** * *** ** ** * ** **** * **
* *** * * *** * * * * ** **
* * ** **** * * ** ** *** * * **** *** ** * *

 }

 

 int main()

{
*** ***** ** ** * * * *** * c[100];
* **** ** *** *** ** *
* * ***** *** *** * * * *

    
** *** ***** * *** ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* *** ** * *** * i=0;
* * * ** * * *** **** *
* ***** ** ** * * * * **** ******** * **
* * * ** * * ** * * ** * * ** *** ** *****
* * * * * ** ** ** * * **** **
* ** ******* * *** * ** * ** i;

}



int check2(char c)

{
* * *** *** *** * * * j=0;
* * * ** **** *** ** *** ****
** * * * ** * * * * * **** * *** ** *
* ** ** * ** *** * * * ** * ** * ** *** * * ****
* * * ** * ***** * * ** **** ** * * *
*** * * ** *** * * * * * ** * j;

}

int main()

{
** * ** ** * * * c;
** ** ***** *** * * * i=0,j=0;
* * ** * *** ** *** ** * *** ** * **** * **

    
* ** * *** ** *** ** c!='.')
* * * * * ** ** *** ** * *


* * * * * *** * * *** ** * * * * ******* ** **
** * **** * * * ****** ****** ** *** *****
***** * ** *** * ** * * * * ** * ** * * * *** ** *** ****** *
* *** * * * ** * * ** ***
* * *** *** * * *** * * * *** * * *** * * *** *** * * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
**** *** ** * ** * * * * * i=0;
*** * * * ** ** *** *
* * * * ** ** * *** * * *** * * * ** *
** * ** **** * * * * * *** * ** ** *** *** * ***
* * * *** *** * * * ** * ** * * * ****** ** ***
* * * ** * * *** * * * i;

}



int check2(char c)

{
* * * * * * ** ** j=0;
* * * * ** *** * * ***
* * ****** * ** * *** **** * * *** * * * *
** * ***** **** ****** * * ** ** *** **** **
** ** **** * **** ** * * *** * * ***
* * ** * * ***** ** ** j;

}

int main()

{
* * ** *** *** *** * c;
* * ** *** * * ** ** ** i=0,j=0;
**** * *** ** * * *** * * ** ** *** ** * *** * **
* ** * ** *** * ** *** *** ** ***** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
**** * ** * ** **** * **
** * **** ** ** ** **** **** * * * ****** * ** *** **
* * * ** ***************
***** * * ******** ** ** c!='.')
** *** *** *****


** **** * *** **** * ** * * * * ******* **** **
* * ** * * ** * * ********* * *
* ** * * * * * * ** **** *** ** * * * * *** ** * *** * * *** **
*** * **** ******
* * * * * **** ** * * * ** ** * * * * * ** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * * * * * *
** * ** ** * * *

int main ** *
** * *

char c;

int i = 0;

void * ** c)

{
* ** * *
**
** * * * *
* * *
* * * ****** ** *
** * *** * ***** * **** * 0;

}
** ;

}
* ** ** * * * *
****

}
*** * * ** **
0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
** ** * **** * * * ***** * * c;


* **** ** * ** **** * *** i = 0,b = 0;


****** ** *** ** * * * * ** * * ** &c);
**** * ** **** ** c != '.')
* * * ** ** ***
******* * ** * * * * * * * *** ** * * *** ** ** **






*** ** * ** * *** *** ********** * ** * *** += 1;


* * ** ******* *** * * **** *** * * * ****** ** &c);
**** * * * * **** * * * * * **** *** *
**** * * * **** * *** *** ** **** * * * * * **


*** *** * * *** * * *** ** *** * *** i);


** * ** * ** * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* * *** ** *
* *** * *** *
* main *
*** * *
*** c;

int i = 0;
* * c)

{
* * * **

* * *
***
*** ;

}
* ** ** * ** *** ** * * ** *
*

}








* * * * * ***
0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
****** ** * * ** *** *** i=0;
* * * ** * *** * *** * * * * *
* ***** ** * ** * ** ******* * *
* * * *** * ** * **** * * * * *** * ** *
* *** *** ***** * ** * ** ** *** * * ** ****
** * * * ** * *** ** i;

}



int check2(char c)

{
** * **** ** ** ***** * j=0;
* *** * *** * ****** * *
******** *** * * *** ** ** * *** ** *****
******* * **** *** **** *** * ***** * * * * ** *
* ** * * *** *** * * * ** * ** * * **
* * * *** **** * ****** *** * j;

}

int main(void)

{
***** * * **** *** *** ** c;
* * **** * ** ** * * i=0,j=0;
* * ** ** ***** * ** ** ** * ******* * ***
** ** * * * ***** * c!='.')
* ** ** * * ** **** ***


* ***** *** ***** * * * * * * **** * * *** *
* ****** * **** * * * * * ** * ***
* * * ***** **** * * ** **** * ** *** ** ** ** ** ** * * ** *** ***

    }
******* ** * * ** * * **** * **** * ** ** * * * * ******



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** * * * * *
**** ** *

int main * ***
*** ****
** c ;

int i = 0;
***** * **** * ** ** * ****
*


* *** c)

{
* **

* **
*****
* ;

}




** * *** * *** * * **
* 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.160
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users