0 like 0 dislike
9.5k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 9.5k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ****** ** * * * i=0;
* ** * * * * ****** ***** ** **
* * ** **** * * ** *** * * ** * **
* *** * ** * * **************** ** * * ** * * * **** *
*** *** * ** * *** * *
*** *** ** * ** ** * i;

}



int check2(char c)

{
* * * ** * **** * * j=0;
** ** ** * **** * * * ** *** * *
* *** * ***** * **** * ** *** * **
* * ***** ** * * ** *** *** ****** * ***** ** * ** *
** ** * ** **** * **** *** ** * ** *****
***** * ******* * ****** j;

}

int main()

{
** * * **** * ** * * c;
*** *** ** * * i=0,j=0;
** ** *** * * * ** ****** * * ** * **

    
** * * * **** * * * c!='.')
* **** **** * **** *


* **** ** *** ******* ** ** * * ** * ***
** * * ** ** * * ** ***** ** ** *** *** * ** ** **
** * * * * * *** ** * * * * ** * **** * * * *** ****
*** * * * *** ** * ** ** *
** *** ** **** * * * * ** * ** * ** ** * * * ***** ** ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ******** **** *
******* *

int main (void)
* **

char c;

int i = 0;

void * * c)

{
*** * ** *

i++;
* **

i++;
** ***** * * * *
*** ***** ** * * ** * * ** ** * ** **
** ** ** ** ***** ** ** * 0;

}
* ;

}
* ** ** * * * ******* **** ** *
** **** * ** *** *
*

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * * ***** ** * * **** a1=0,a2=0,a3=0,a4=0,in;
* * **** * * ** * ** ***** ** * && c[in];in++)

    {
********* ***** *** *** * * ** *** *** * ** * (48<=c[in] && c[in]<=57)
** ** * * *** * ** ** * *** ***** * ** *** *
* ** * ***** **** *** ** ** * * * * * *** *** * ** * * * *** **
* * * * * ****** * * ** ** * * *** * ******* ******
* * * *** * ***** * ** *** * * * ****** if(65<=c[in] && c[in]<=90)
* * *** ** ** * * ** * ** * * * ** * *
* * * * **** * *** * *** *** * ** * *** * * *** **** ** * **
* * * * **** **** * ** ** * **** **
*** * * * ** * *** * * ** if (97<=c[in] && c[in]<=122)
** ** ** * **** ** **** * ** ** * * * * ***** **
*** * ** * **** ** ** ***** ** ** *** * * * * *
* *** ** *** * ** * *** * * * * ***** ** **** * ** *
* * ****** *** ** *** ** *** * * * ** ** * * * * if(39<=c[in] && c[in]<=46)
** **** ** * ** * * *** * * * * ** ** * ****
*** * *** * *** ** ** ** *** *** ** * * ** ****** *** * ***
* * ** *** ** * * * * * * * ** * * * *
*** * * ** * ** ** **** * * * * *** * ** ** ** * * ** ** ** *
** ** * * * **** ** * *** * ******* *** * ** *
* * * * * *** * * * ** * * *** * **** * ** * * * * * ** ** * *
* * *** * **** ****** ** * * * *** ** **** * ** * *
**** * * * *** * * * * ***
* **** * * * * ** *** ** * * * * ** ** * *

 }

 

 int main()

{
* *** * ** * * ** ** ** *** c[100];
* * * **** ** ** * * * *
** * *** * * ** ** * * **

    
**** * * * * * * * * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * *** ***** * ** * i=0;
**** ** * * *** * ** *** **** *
* * * ****** *** ** * * *** * * * *
** * * * * ** * **** ** *** * * * *** **** ** * *
**** ** * ** ** ** ****** ** *** * *
***** ** *** ** **** * * i;

}



int check2(char c)

{
***** * * * * * * * j=0;
** * *** * **** * * ** * **** ***
*** ** * * * *** * ** * ** * * **
** *** *** **** * * * * ** **** ** **** * ** * * * **
****** * ** *** *** * **** ****** ***
* ***** * ** * ** ** j;

}

int main()

{
** * ** ** * **** *** **** c;
**** * * * * *** *** * * **** i=0,j=0;
** **** ****** ** ** ** * * * * * ***

    
* ** *** ** * *** * ** c!='.')
* ******** * *** **


** * ** * ** * * * *** * ** ** * * ***
** ** ** **** **** *** *** ** *** ****** *
* ** ** ** **** ****** ** * ** *** ** ** ****** **** * **
** ** *** *** *** * **
* ** *** * *** ** ** ** ** * * * *** ** ** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ***** * **** * ** *** i=0;
**** * ** * * * * ** *** * *
***** ** *** ** ** * * *** ** *** *** *
* ** *** **** * ** ** * * ** **** * * * ** ** *
* ***** * * * ** ** *** ** ** **** ** * *
*** ** ** **** ** * ** **** i;

}



int check2(char c)

{
* **** * * ** ** * * j=0;
** * * * * ******* ** *** *** * *
* *** * * * ** * * **** *** *** **** *
** ** ** *** * ***** ** * ** * * * *** **** *
** **** ** ****** **** ***** * * *** *
* * * * *** * * ***** ** j;

}

int main()

{
* ***** * ** *** * c;
* ** * * ** i=0,j=0;
* ** **** ** * * * ** ****** ** *** * *
** * **** ** ** * * **** * ** ***** * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
** ** * ** ** **** *
****** ** **** * * *** * ** **** * ** ** * * *** ** ** *
* *** *
**** ** ** * * * * ** * * c!='.')
*** ** * **** ** *****


*** ** * **** * ** * * * *** ****
* ** ** * * ** * *** * ** * ** * ** * * * *
* *** * ** ** * *** ** ** * ** * * ** ** * ** *** ** * * * *
* **** * *** * ***
*** * * * **** * **** *** * * * * ** *** * * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** * * * ** **
* * ** ** ** * ***

int main *
***

char c;

int i = 0;

void * ** * c)

{
* *
* **
* ** *
*
* ** ** ** * **
** * *** *** * ** 0;

}
* ;

}
* ** * ** * * * **** * ** *
*****

}
** ** ** * * * **
* * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
** * * * * **** *** ***** * ** c;


* * * * * * * ** ** i = 0,b = 0;


**** * * *** ** * * * * * ** *** * * &c);
* ** * * ** ** * *** c != '.')
* * ** * * * ***
***** *** *** ** ** *** * ** *** ** * **






* * *** * * * ** *** ** ** * * * * += 1;


* ** * ******* ** * ** ** * ** *** ** ** ** ** * * * *** * * * *** * ** &c);
* * ** * * *** * ** *** ** ** ** *
* ** * * * * **** * ** **** * * * ** * *


*** * *** * * *** * * *** * * * *** * i);


* *** *** ** * *** ** ***** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* * ** ***
* ** * ** * *
** main * *
** *
* c;

int i = 0;
** * c)

{
****** *
*
***** ** *
*
* *** ;

}
* * ***** *** * * *** ****
*

}








*** * * ** **
*** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
***** *** * ** ** * i=0;
*** * **** *** * * * * **
***** ** ** * ****** ** ** ** *** * ** ** ***
* * ** ** * ** * * * ** * ** ***** * ** ** ** *** *
* ** **** ** * * ** * * * * *
** * * * ***** * ** * ** i;

}



int check2(char c)

{
** * * * ** *** * ** j=0;
* ** * ** * * * ** ***
* * **** * *** * **** * * * ** **** **
** * * ** * ** * * ** * *** **** * ** * * *** * ***
** * *** *** * ** ** ** * **** * **** * * * *
***** *** *** * * * * * * j;

}

int main(void)

{
**** **** * * *** ** *** ** c;
*** ** * ** * * * * * ** i=0,j=0;
* ***** * *** * * * * * *** ** ** **** ** *** *
*** * ****** ** * c!='.')
*** * ** ** * *** **** **


* ** * ** ** * * ** ***** ****** *** * * * * **
*** ** ** ** * ** ** ********** * *
* ** * * ****** * *** ** * * * * *** *** * * ** * ** ** * * * ***

    }
** ********* ** * **** * * ** ** * * *** ** * *** * * *** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** * * * ** **
* ** ** **

int main *
*
** c ;

int i = 0;
* * ********* * * ** ** * *** * **
*** * **


* * c)

{
* *****

*** *
****
*** ;

}




* * ****** * *
***** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.115
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users