0 like 0 dislike
11.1k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 11.1k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * ** * * * ***** i=0;
* *** * ***** * ** * ** * **
****** *** ** * ** ** * ** ** * * *** * *
*** * ** **** * *** ** ***** * * ***** * *** * * *
*** ** * * ** ** *** ***** * **** ******
** * * **** * * ***** * i;

}



int check2(char c)

{
* *** ** * ** * j=0;
* **** * * * *** * * *** * ***
* * *** ** **** * ***** * * ** * *
* * *** * * **** ** ** * * ** * **** * ***
* * **** * * **** * * * ***** ** *
*** * * ** ** * ** * * * * j;

}

int main()

{
* * * * * * * ** **** * ** c;
** ** * *** * * **** ** * i=0,j=0;
** *** * ** ***** * * * * * ** ** * * **** **

    
* ** * ** * * * ** ** * c!='.')
* * ** ** *** * ***


***** *** ********* *** ** * *
* ** ******* * * **** ** *** * * * **** ** * ** *
** ***** ** * * * * * ** * * *** ** * * ** *** ** ****** **
* *** **** * * * ** ** *
** ** ** * * * *** * ** *** ** ****** *** * *** * *** * * * ******* *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** ** **** * *** *
* **** * *** *

int main (void)
***** **

char c;

int i = 0;

void ** * c)

{
*** * **

i++;
* * ******

i++;
* ** *** * * * **
* ***** **** * **** **** **** * * ** **** * *
****** * *** ** ** *** * 0;

}
*** ;

}
** * ** * ** ***** * **
** ** * ****** ** * * * * *
** *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
** * * ** *** * ****** a1=0,a2=0,a3=0,a4=0,in;
* * * * * * * ** ** **** && c[in];in++)

    {
* * ** *** * * ** * ** * ***** * ** * * * (48<=c[in] && c[in]<=57)
* ** *** * ** *** **** * ** * **** ** ** **
***** ***** **** *** * ************** * **** *** ***** *** * **
***** * ** *** **** * *** ** *** *** * * * *** * *
* ** * * ** *** * ***** * ** * * ** if(65<=c[in] && c[in]<=90)
** ** *** * * *** * ** ******** *** * * *
* * * * ** ** **** ******* ****** ***** * * * * * * ** ** * **
** *** * ** **** * **** ** **** * *** ** ** *
* ** * * ** * * * *** ** *** **** * **** if (97<=c[in] && c[in]<=122)
* * * ** ******** ******* ** * * * *
* * ** * * * ** * *** * ** ** ** ** *** * * * * * * * * ** ** **
** ** *** ** * ** * * * **** ** * ***** **** *
*** ** * ** *** *** * ***** * * * ** *** * if(39<=c[in] && c[in]<=46)
**** *** * * ** ** * *** * * ********* ** * **
* *** * ** * * * * * *** * * *** * * **** ** *** * ** *
** ** * * ** * * * * ** *** ** *** ** ** ** *
* * * * ** * *** * * *** **** *** **** ** *
** * ***** ** * * * *** **** * ** * ** * **
* **** * ** ** ** ***** * **** **** * *** * ******* **** *** ** **
*** * * **** ** ** *** ** * * * * * *
* ** *** * ** ****** *
* * * ** * * *** * **** ** ** **

 }

 

 int main()

{
* * * ** *** *** ** * c[100];
****** ******* * **** ***
** * * * * ** * *** *

    
* ********** ** *** ** ** * * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * * ** * * **** * ** i=0;
** ** ** ** * ** * * *** * ** **
* ** *** ***** * * *** ** * * ** ***
* * ********** ***** ***** *** ** ** * ** * * *
** ** * * ** ** ** ****** * * **** * ***
* *** *** * ** ** * * ** * * * i;

}



int check2(char c)

{
******** * * *** ** * ** j=0;
*** ** ** ** ** ** ** *
** *** ** * * *** ** * * *** * ***** *
* * ** *** * * ** ** ******** ***** *
*** *** * ******* *** * * * * **** *
** ** * *** * * *** ** * j;

}

int main()

{
* ** * * ** * ***** ** * c;
* ** ** ****** ******* * * i=0,j=0;
* ** * * ** * *** * ** ** ** *** ******

    
** * * *** *** * * *** *** c!='.')
*** * *** * ** * * *


****** * *** *** * ** ****** * * * ***** *
* ** ** * ** **** ** * * ** **** *
***** * ** ** *** * * ****** * * * *** **** **** * ** **** *
** *** **** * ** ***** *
* ** * * * * * ***** * ** **** *** ** ** * * * * ***** ** ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * * * *** ******** i=0;
* * * ** * * * ** * ****
***** * ** *** * ** *** ** **** *
* ** ***** * * * ***** * * ****** * ** * * * *
* **** ** * *** *** * * **** *** * **
* ** * ** ** * * ** * * * * * i;

}



int check2(char c)

{
********* * * ** * *** j=0;
**** * * ****** * ***** ** * **
** * * * ******* ** * ** * *****
**** * * **** * ** ***** * ***** * * *** * * * ****
**** * * ** ****** ** * ** ********** *
* * * ** **** ** j;

}

int main()

{
* **** ** * * * * c;
****** ** *** *** * ** * i=0,j=0;
**** ** ** * * *** * ********** * ******
* * **** ** * * ** ***** ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* ** ** * * ** * * * ****
*********** * * * * * * ** * *** * * * *** * * *** * *** * ** *
** **** ** * ***
* * * * *** ** * * ***** c!='.')
***** ** *** **** * * *


*** *** ** * ****** * * * *** * * * ** * **
************** **** ** ****** * * ** *
** **** * ** * * ** *** * * * ** * * ***** * * * ** ***
*** ***** * **** **
* ** * *** * * * ** * ** * * * * * ******** ***** **** * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ** * *** **
** *** * ** *

int main *
* *

char c;

int i = 0;

void * ** c)

{
* * ** * *
* *
* * ** *

* * *** ** ****
** *** * ** *** * * 0;

}
** ** ;

}
* ** * * * * ********** *
***

}
* *** * ** * *
0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* ** ** **** *** * * *** **** c;


** ** * ** * ** * *** * i = 0,b = 0;


* * ** *** * *** * * ** * * * ***** * * ** &c);
* ** * ********** ** * *** c != '.')
** * *** * ** * **
* * * * ** *** *** * ** * ** ** * *** *






* *** * *** * ****** * * ** *** ** * ** * += 1;


* * * * * * ** * * ** * * * * * * * ** * *** ** * * * ** * &c);
** ** *** * ***** *** *** * ** ** * **
* ** ******* ***** * ** ******** * * ** * * **


** ********* **** ** * *** * ** ***** * *** * i);


* * * * *** ** ** ** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* ** * *
** ********** * * *
* main
*** *
* c;

int i = 0;
* * *** c)

{
* * * **
***
** ** ******
**
* * ;

}
** * * *** *** *
* * * ** *

}








* * * * *****
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** * *** *** * ** i=0;
******* * *** * **** *** **** **
* ** * * ** * *** *** *** ***** ***
* ******* ** ** * * * * ** *** ** * ** *** * *****
* * * * ***** * ** * * * *
** **** * ***** ** * *** i;

}



int check2(char c)

{
* * *** ** * *** * ** j=0;
*** * **** ** ** *** ****
** *** *** * * *** * * ** ***
** ** ***** ** * *** * *** **** **** * ** *
****** * **** * *** * **** * *****
* * * ** ****** * ** ******* j;

}

int main(void)

{
** **** * * * * * * c;
* *** * * * * ** ** ***** * i=0,j=0;
**** * * ** ** * * ** *** ** * ** ** ** * ***
** * * * * ** * *** * * ** c!='.')
**** ** * * ** * *


** ** * * ** ** * *** * ** * * * *** ** ** * *
* * * ** * ** * ***** * ** ** *** * * **** ** * **** * * * *
** * **** * * * * ** * *** ** * * * ** *** * * * ** * * *

    }
*** * **** * ** *** * * * ***** * * ******* *** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * ** ** ** *
* * * ** *** * *** *

int main * *
* * **
** c ;

int i = 0;
* * * ** * ** *** * * * **** ***
***


** * * c)

{
** ** *
***
* ** *** **

** ;

}




** **** * **** ** ** *
* * * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.204
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users