0 like 0 dislike
7.4k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 7.4k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * ***** ***** * ** * i=0;
** * * ** ** * *** ** *
***** * ** * ***** * *** * ** *** ** * * *
*** ** ** ** * * ** ** * ****** *** ** * * *
*** *** ** * * * ** ** * * *** * * * **
* * * *** *** **** * *** * i;

}



int check2(char c)

{
** * * *** * * * ** j=0;
**** * * **** * * * *** ***
* ** **** ** ** ** * * *** ***
***** ** * **** *** * **** * *** * **** *** * ** * *
* * * **** * * * * ** **** * ** ***
* ****** * **** * * * *** * j;

}

int main()

{
* * ** * * ** * ** * c;
* *** * *** *** ** **** i=0,j=0;
* * *** * *** * ***** * ** ** * * * **

    
**** * ** *** ** * ** c!='.')
* * * * ***** ****


* ** * *** * **** * * * ** **** ** ******
** * * * ** * ** ** * * ** * * * * ****
** * * ** ** *** * * * * * *** * ** * * * * *** * * * *
****** ** * ** * *
*** * * * * ** ** ** * * * *** **** *** * *** ** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
**** * * **** *****
* ** ** *** **

int main (void)
*******

char c;

int i = 0;

void * * * c)

{
* * *** *

i++;
*****

i++;
** ** * * * *
***** ** ****** * * * *** *** * * *
****** ** * * * ** 0;

}
** ;

}
*** *** * * * ** **
*** * * * * * * ** **** * ** **
** *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * * ** ** **** **** a1=0,a2=0,a3=0,a4=0,in;
* * * * * * * * * *** * && c[in];in++)

    {
* ***** * ** ** * ** * * * * **** * ** **** ** ** (48<=c[in] && c[in]<=57)
* ** * * ****** * **** * ** ** * * **** ** *
****** ****** * ** ** * **** * ** * * ** * *** * *** *
***** ** * *** *** ** * ****** * *** * * * * * *
** *** * ** ***** *** ***** **** ** ** * * **** ** if(65<=c[in] && c[in]<=90)
* ** * ** * ****** ** * * **** **** *
*** ****** *** * ** * ** * ***** * *** *** * * ** ***** **** *** *
* * * ******* * * * * *** * *** * ****** *** ** ** *
*** **** ** * * * * * * * *** if (97<=c[in] && c[in]<=122)
*** ** * ** *** *** * ** * * ** * * *
* ** ****** ***** *** * * ** * * * * ** ** ** *** * * * ** ***** ** * *
** **** ** ** * * **** ** * ******* ***
***** *** * * * * *** * * *** * * * ** if(39<=c[in] && c[in]<=46)
** * *** ** * ** * *** * * * *** *** ** * *
** ** ** **** * **** *** * * *** * ** **** * ****
* * * * ** * ** ** *** * **** **** * ** ** **
** * * ** ** *** * *** ****** **** * **** ******
* * ** * *** * *** ** ** ** ***** * * ** * ** *** * *
* * * ***** * *** * ** * *** ** ** *** **** * *** *** ** ** * * * **
******* ****** * * * * ** * ** * ** * ***
* * ***** * * * ** * *** *
* ** * * * *** * ** ** * *** * * ****

 }

 

 int main()

{
*** ** ** ** * ** c[100];
* * ** * **** * ** ** ***
** *** * ***** * ** * * * *

    
* **** ** *** **** * ** * * * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** * * *** ** * ***** * ** i=0;
* ** ***** * * ** * ***
** ** ** * ** **** * * * * * * ** *
* **** * *** ** * ** * ** *** * * **** ** **
* *** * * * * ******* **** ** * *** * ** *** * *
* **** ** ** * *** ***** i;

}



int check2(char c)

{
** ** * * ** * ** * j=0;
* ** *** ** * **** * ** ** ****
** ** ** * * * ** ** * **
*** * **** ** ** ** * * * * * * ** *** ** * *
**** * * ** ** ** ***** * * * **** **
** ** ***** *** * j;

}

int main()

{
*** **** ** * * * * * c;
* * * * ** **** * ** * * i=0,j=0;
* * * * ** * ** * * * * * *** ******

    
*** ** * **** ** * * ** c!='.')
* ** ** *** *** **


* * ** * * ** * ** * * ** * **** *** *
* *** ***** * **** * **** * * **** * ***
* * * **** ** * * ****** *** * * * * **** ** * ** * * **** *
** * * *** * * **
*** * *** * ** * **** * ** * **** ******** * * **** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ** **** * ** i=0;
** * * ** **** * * ** * * * **
* ** ** * * ** * * ** ** * * ** ** *
*** ** ** *** * ***** * *** * ** *** * * **
* ** * * * ** ** * ** *** ** *
* ** ** * *** * ** * ** i;

}



int check2(char c)

{
** ** *** * * * * ** * j=0;
** *** * ** ** * * * * *
** *** ****** ** * ** * ** * * **** **
******* * * ** ** * ** * ** * *** ****** *
****** *** * *** * ** ** * ** ** ** **
* *** ********* * * j;

}

int main()

{
* * * ** *** * ***** * * ** c;
* * * * ** * * * * *** i=0,j=0;
* * * ** *** * **** * * * *** * * ** * *****
** * ***** *** *** *** * * * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* ** ** * *** ** **
* * * **** ** * * ** ** *** * *** ***** * *** ** * **** *
***** ** ** ** ****
* ***** * * * * * c!='.')
* ** ** * * * *** ***


* ** * * * *** * **** *** * ** * *
* ** ** * ** * ** * * ** * * ** ** * ***
* * **** ** * * *** *** ** **** ** * * * *** * ** * **** ***** *
* **** ** ** * * *
* ** ***** ** ** *** *** **** ** ** * ** *** ** * ** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * *** ***
* * ** * ** *****

int main *
**** ** *

char c;

int i = 0;

void * *** c)

{
** ** *

* ****
* *
* ** * * * * *
** ** * * ** * * 0;

}
;

}
** ** * * * * **** * ** * * *
* *

}
** ** * ***** *
*** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* * ** * **** * * *** * * c;


**** * * * ** * * * ** i = 0,b = 0;


* * ****** * * * ** * ** * ** * ** * ** &c);
** ** * ** * * * c != '.')
* * * ** *** ** **
*** * * *** * *** *** * * ** ** * ** * * * *






**** **** *** *** * * ** * * ** ** ***** * += 1;


** * * ** ****** * ** * * ** * *** * *** **** ** * &c);
* **** * ** * * ** ****** *** * ** * * * * *
* **** ** * ** *** *** *** ** * * * *** ******


* * * * * * ** * * * * **** *** * i);


** * * * * ** * * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* * * * * *
* ***** ** ** * * *
** main ** **
* **
* c;

int i = 0;
* * ** * c)

{
****
**
** ** *
* *
** ** ;

}
* ***** ** * * * * *** ***** * * **
** ** *

}








* * ** ** * * *
*** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** *** * ** *** * * i=0;
*** ** * * ***** *** **** *
* *** ** * * * ** * ***** * **** *****
*** * **** ** ** * *** * * *** * *** ***
* * * * * ** ** *** * ****** * * ** * * *****
* * * * * * * **** ***** i;

}



int check2(char c)

{
*** ** * ******** j=0;
* * * * * ** ** ****** * * *
* *** * ** * *** ****** *
** ** ** **** * * * ** ***** * ****
* ** * *** ** * * * * * * ***
* ** ****** ** * * ** j;

}

int main(void)

{
***** *** * ** * **** * c;
* ** * * ** * * ** ** i=0,j=0;
** **** * * * ****** ** * ** ***** * * **
* * * * * ***** ** c!='.')
** ** ** * ** ***** *** *


*** * *** * ***** * * * * * * **** * ** * **
*** * * * * * * * * **** **
* ** * ** * ** **** ** * ** ** * ** ** * * * * *** ****** * ** *

    }
* * ***** * * ****** * **** * ** ** * * * * **** * * ** ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* *** ** *
*** ** * *

int main * *
*** ***
*** c ;

int i = 0;
* ** * * ****** *** *
* * * **


** * * ** c)

{
******

*****
** **
*** ;

}




** * ** * * ***** *
* 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.236
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.9k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users