0 like 0 dislike
14.3k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 14.3k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ** **** ***** i=0;
** * * *** * * **
*** * * * * **** ** *** * * * * * *** *
* * * * ** *** ** * * ** * * * ** *
****** ** ** * ** ** ** * * * ***
* ** ** * * ** ** * * i;

}



int check2(char c)

{
**** * * ****** * *** * j=0;
* **** ** **** ** * *** * *
* * ** *** * *** * * * *** * ****
** *** * * * *** * *** *** *** * ***
* ** ****** ** **** * * * ** * * ****
*** * * *** ***** ** * ** j;

}

int main()

{
* ** *** ****** * *** * c;
*** **** ***** * ** * ** ** ** i=0,j=0;
** *** * * * * ** * * * * **** ** ***** **

    
* * * **** * ** * * * * ** c!='.')
** * ****** *** *


** ** *** * * * * ***** ** * *** ****** ** *** ** *
* ** * ** * ** * ** ** * * ** * ** *******
***** ** *** ****** * * * * * ** * *** ** ** ** * *** * * * *
* ** ** ** ***** ***
* * * * * * * * * ** * **** *** * ** *** * *** * ** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** ** *
* * * ****** *

int main (void)
****

char c;

int i = 0;

void *** c)

{
*** * *

i++;
** * * *** *

i++;
* * ** * * *** *
* ***** *** * ** *** * ***** * ** ***
* * * * * ***** ** ** * 0;

}
*** ;

}
* * * * **** ******
** * *** ** * * * ** * * **
** *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * ** * **** * ** a1=0,a2=0,a3=0,a4=0,in;
* * * ** *** ****** ** ** ** && c[in];in++)

    {
** ** * * * **** * ***** * * ***** *** *** (48<=c[in] && c[in]<=57)
* ** * ** ** **** **** ** * * *
* *** * * * * * * *** ** ** * ** * * * * * * * ** *** *
* ** * * * * ** ** ** * ***** * * * **** ** *
* * ** * * * ** ** *** ** ****** * ** ** * * * if(65<=c[in] && c[in]<=90)
* * * ** * * ** ***** ** * * * * * * * ***
** * ** * ***** * *** *** *** * * * **** *** * ***** * * ******* * ** * * *
**** **** * ** * * * **** **** *** * **** **** ** *
* * **** ** ** *** * *** * * ******* if (97<=c[in] && c[in]<=122)
* *** ** * * ** ** * ** * **
* *** ***** * * * *** ** *** ** * * * *** * * **** * * * *** * ** **
*** * * * ** *** ** **** ** * * * ** **** **
** *** ****** * * * **** ** ****** * * if(39<=c[in] && c[in]<=46)
* ** ** ***** ******** * * ** ** ** * ***
** * * *** ** * * * *** * * * * * * **** ** * ** * * * * * ***
** ***** ** *** * * * ** ** ** * **** * * * * **** *
* *** **** *** ** ** ** ****** ** * ***** ** * **** *
** * * ** ** * ***** * * * ** *
* * *** * **** * *** * ***** ** *** * * *** * ******** * *** *
** ** ***** *** ** * ** * * * * ****** ** *** *
* * ** * * ** ** **
** **** * * ** * *** ** * * * ** ** ** * *

 }

 

 int main()

{
** ** *** * ** * * c[100];
* * ****** ** **
* *** * * *** **** ** **

    
*** ** ** ** * * *** *** ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * *** * * **** * * i=0;
* * * ** * **** ***** * *
**** ***** * *** ***** * * *
* * *** * ** ** * * * ** * ** * **** * **
* * * * * * * *** *** * ** *****
* * **** ** * * ** * * ** i;

}



int check2(char c)

{
* * * ** * ** * * ** j=0;
*** * ** * ** * * * *
* * ** * * ** * ** *****
** ** *** * * * * * ** * * * ** ** * *** ** ** * * ***
* * ** *** * ** ** ** * ******* **
**** ** **** * * * * ****** j;

}

int main()

{
* * * * * * * ** **** c;
* ** * *** * ****** * * * i=0,j=0;
* ** * * ** * * * * * * * * *** * * *** *** *

    
** * ** * **** ** * * ** c!='.')
**** *** * ** * ** ** **


**** * ** * ***** **** * ** ** ******* * *** * ** *
*** *** * *** * ** *** * * ***** * ** *
*** * * * * ** * ** * * * * * ****** * * ** * * * * ** *
* * ** * * **
** * * ** *** ****** *** * * ** *** ** ** * * **** * * * * ** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * **** * ** i=0;
* *** * *** * * **** ** * ** ****
** * * * * *** ** * * *** * ********* * *
** * * ** * * * * * * * ** **** * *** * ** ** **
*** * * * **** *** * ** ****** ** * *
*** ** * *** ** ** * ** **** i;

}



int check2(char c)

{
** * ** *** ****** * j=0;
* * * ** * ** ***** * *
** * ** ** *** * * ***** **** * **
**** * *** * * ****** *** ** * ** * ***** * * *
* ************* ** ***** ******* ***** * ***
* * * *** *** ** ** * * * j;

}

int main()

{
**** * * ** **** * * * c;
** ******** * * ** * *** * ** i=0,j=0;
* ** **** ** **** * * *** * ** *** **
* * ** * * ***** * * **** ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
**** ** ** ** *** ***
********* *** * ** * ** * ** ** *** ** * * ** * ******** * *** *
* * * * ****** *** *
*** ** * * *** ** *** c!='.')
** ** **** * * * * * * *


***** * * * ** * ********* * * * *** * ** **
** * * *** * ***** * **** * ** *** ** * *
*** * * **** * * * ** * **** ** *** * *** ** * * ** ** **** *** * ****
* * * * * * *
** * * ***** **** ** *** *** **** ** * *** * ** *** * * **** *****



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** ** * * **** ***
* ***** * ** **** **

int main
** **

char c;

int i = 0;

void ** *** c)

{
* ** **
*
*** ***
*
* ** ** * **** **
**** * * * * * * ** 0;

}
** * ;

}
** * ********** * * * * ****
* ** *

}
* * * * *** ***
*** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
*** * * * ** * * c;


* * ******** ********* * i = 0,b = 0;


* ***** *** *** *** *** * ** ***** ** * &c);
** *** ** ***** ** * * **** * c != '.')
* * ** * * *** ** *
*** * *** * * ** * ** * ***** * ** *** * ** *** * * *






* * *** * *** * ****** ** *** ** * ****** += 1;


* * * * * * * * * * * * * * * * * ******* ** *** * &c);
** *** * * * ** * ** **** ** *** *** ** * * ****
*** * * ** *** ** ** * ** * * * * *


* *** * *** * * **** ** * ** * * ** i);


* * ** **** * * * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* ** ** ** * **
** * * **** * *
** main *
* *
** * c;

int i = 0;
** * ** * c)

{
* *****
* *
* * *
*
** * ;

}
** ** **** * * ** ***
* **

}








** *** **** * * *** *
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * *** * * * * i=0;
* ** ** * *** * * *** ** ** * **
* * * **** * ** ** * * * * *** * * *
* *** * * ** ***** * *** * * ****** * * * *** **
* * ** *** * **** * ** *** *** *
** * * ** * ** * * * ***** i;

}



int check2(char c)

{
** * * * * ****** * * * j=0;
***** * * * * *** * *
** *** * ** ** *** * **** *** * ** *
**** * ********* *** ** ** ** * **** **
* ** * * ** ** *** ** *** * **
* * ** * ***** *** ******* * j;

}

int main(void)

{
* ** *** ** * * ** *** * * * c;
* ***** ** ** * * * * *** * * i=0,j=0;
* *** * * ** ***** * * ****** * **** * * * ** * * *
* *** * * * ** * * c!='.')
* * ******* * * **


*** ** * ** * ** * **** ** ** * * **** * ** ***
* **** ***** ** * *** * *** * * ****** ** **
* * *** ** * * * * *** * * * * ** * *** * ** ** * * * *

    }
* * * * ** ** ** * * * ***** ******** ** ****** * **** ***** * * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ***** *** *
*** * **** ***

int main ** *
* * ******
** c ;

int i = 0;
********* * * * * * * *
** *** *


** * ** * c)

{
* * *

** *
***
*** ;

}




* ***** * * ****
0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 8.2k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users