0 like 0 dislike
6.6k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 6.6k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<ctype.h>

int main(void)

{
*** * ** *** *** ** **** c;
*** * **** * * * sum=0;
** ** ** * ** ** * * *** * ******* * *** *** *
* ** ** * * ** * ** != '\n')
* * * ******** **
* ** * * *** ** * * * **** *** * * ** **** **
** * * * * **** ** * *** * ******* ** * ** * * ******* * = sum+1;


*** ** ** ** * * * ** *** ***** ** *** *** * ** * ** ** * *



    }
**** * * * * ** * **** * * * **




*** * * ** * * *** * * * ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<ctype.h>

int main(void)

{
* * ***** *** ** * c;
**** * *** * **** ** * sum=0;
*** * ** ** * * ** **** * * * * **** **
** ** ** **** * ** * * != '\n')
*** * *** ** * *** * *
* ***** * ******** * * * * * * * * * * * * ** *** ****** * *
*** * * *** ** *** ** ** ** * * ** * ***** *** * * *** ** ** = sum+1;
* ** ** * * * * * * * ** ** ** * **** ** ***** *** sum = sum +1;


** * ***** ** ****** * * ** *** ** * ** * * ** ****** ** ** * * **** * *** * *



    }
** ***** * * *** **** * *** *** ****




*** * * ** * * **** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<ctype.h>

int main(void)

{
****** ** ** * * * * * c;
**** * * ****** **** ** * sum=0;
*** * * ****** ** * * ** * ** ** ***** * ***** * **
**** * * ** **** **** * * != '\n')
** **** ***** ** * ** * *
*** * * * ***** *** ** ** * ** *** * *** * c == '.')
** * **** ** ** ****** * * * * **** * ** * ** * *** ** ******* = sum+1;
* * * * * ** *** ** ** * * * * * * *** *** *** sum = sum +1;


* ** * **** * ** ** * *** * **** * * ** * ** ** * *



    }
****** * *** ** * ****** ** * * * ** **** *




**** * ** ** * *** ** ** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
# include ** ** * **

# include ** ** * *****  

int n;

void check (char c);

int main ()

{
** *** ***
** * ** * *** * c;
* * * * * * *****
** * * * *** ** ** * ** ( * ** **** * );
* ****** ** ** ( c!= '.' )

** ** ***** *
*** *** ** * *** * * * ** (c);
* * * *** ** * ** * ( **** ** ******* * * );
** **** ** *****
** * * ** * *
****** ********* * * * * ** *
* ** * * *** ***** *** 0;

}

void check (char c)

{
* * * *** ***** ** *
** * ****** * * *
** ** ** **** * (ispunct(c))
* * * * ******** *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<ctype.h>



int main(){
******* * * * * *** c;
** * ***** ***** * i = 0;
** **** ** ** * **** * ** * ** *** * *** ** &c);


* ** * ** * * * * *** != '.'){
* *** ** * *** *** ** ** ** **** * * *
* ***** ** ** * ** *** * * ***** ** * **** * *** *
** * * ** **** * ** * * * * ** * **** * * * *** ** ** ** ** ** &c);
* *** ** * **** ** * ***
***** * ** ** * ** *** * * * * ** i + 1);



return 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ** * * * * *** * i=0;
*** ** * * * ** ** * ** ** *
* * ** *** * *** * ***** * **** * * ** **
**** ** *** **** * * * * * * * ** ******** ** *
* * * ** * ** * * * * *** ** ** ** **
** ** * ** *** * * i;

}



int check2(char c)

{
*** ** ** * * * * ** ** ** j=0;
* * ** * * * * ** ** ***
** * *** ** * * ** ** ** * * * ***
**** * ** * ** * * * * * * ** ** ***** ** **** *****
* **** * ** ** *** ** * ***** ** ** **
* ** * *** * ** * j;

}

int main()

{
* * * * *** * * c;
* ** * * *** ** * * ** * i=0,j=0;
**** *** * * * *** ** * * * * * **** *
** ** * *** * ** ** * ** * c!='.')
* * ** * * * * * **


** ** **** ** * ** *** *** ** * **** * *** *
*** * * * *** * ** ** * ** ******* * * * ** ** * *****
* **** * ** ** * ** *** ** * ** * *** * *** *** * *

    }
* ******* ** *** * * * * *** * * * ** ****** * ** ****



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** * *** *** * i=0;
* * * ** ** ** * * *
** * ** * ** * * * * **
* * ** * * * *** * *** ** ******** ****** **** *
* *** * ***** ***** ** **** ** * *
* *** * *** *** * i;

}



int check2(char c)

{
* * * **** ** * j=0;
** *** ** *** * ******* ** * *
***** * * * *** * **** * * * *
* * ** ** * ** * * **** ** * * * ** ** *** *
* ** * * ** * **** * ***** * *** * **
* *** *** * * * * **** * j;

}

int main()

{
*** *** ** * **** * * c;
* * * *** ** ** * * * i=0,j=0;
** * ** * * ******* **** * ** ** ** * *
******** ***** ** ** * * c!='.')
** ** * * * *** **


** ** ** * ** * *** ** * ***** * * * **
** *** * * * ** * ** ****** * ** ***
** * *** *** *** ** *** * *** ** **** ** ** * * * *** ** * *

    }
**** *** *** * ** * ** *** * ** ** ** *** * ** ******** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include * **** * *

#include ** ** ** * **
* **** main()

{
* * * * ** a = 1, i = 0;
* ******** *** c ;
* * * * * * **** * * *
** *** ** ** ( c != '\n')

{
* ** * **** * ** *
*** ** ** ** += 1;


***** *** * *** ****** * *** ** * *

}


* **** ***** * **** * * * ***
* ***** ** * 0;



}
answered by (43 points)
0 like 0 dislike
Hidden content!
#include * ** * *

#include ***** *** * ** *

#include * * ** ** * * **


** * ** main(void)

{
*** *** * * * *** * **** count=0;
** * ******** ** *** **** ** c;
* *** * ** ** **************** * * *** * * ****
** ** * * **** *** * (c != '.')
** * ** * ******

if ****



count++;

else if ***

count++;


** * ** * * * ** ** ** *** ** * ** ** * * *
*** ** * * * * *** ***
* * * * *** * *** * ****
* * * ** * ** ** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * *

#include ******** ** *

#include ** * *


** * * main(void)

{
* ** * * * *** ***** ** count=0;
** * * * *** * ** ** ** ** ** c;
****** * *** * ** * * *** ** &c);
* **** ***** * * ** * * ** (c != '.')
* ** *** * * *
*** *****

count++;

else if * ** ***

count++;


* * ** * * **** * * * * ** ** * ** **** *
* * * * * * ** * ***
** * * * **** * * **** *
* * * * *** * * * ***



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.25
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users