0 like 0 dislike
13.1k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 13.1k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** * ** ** ** ** **** i=0;
** ** *** * * * ** * * * *** * *
*** *** * ******* ** * ** * *
* * * ** ** ***** * ** * * * * * ** ** * **
* * * ** * ******* * * * *** **
***** * * **** i;

}



int check2(char c)

{
* * * * * ** * ***** ** * j=0;
* *** ***** ** ** * *** *
* * * **** ** *** * * * **** *****
***** * * * * * * * * * * ***** * * * * ** * *
**** **** ** ** * * * *** * * ***** ** * **
** * * ** ***** * * ** ** j;

}

int main()

{
** * ***** ** **** c;
***** * ***** ** * * * i=0,j=0;
** * **** * * *** ** * *** *** * * * *

    
* ** * * * *** *** * * * c!='.')
* * * ** ** * * ****


**** * * *** * ** **** * ***** ** ** *** * *** * ** **
** * ** ** * ** ** ***** * ** * ***
* *** ** * *** *** ********* *** ******** * *** * * * * * *** ** * * *
** ** ** ** *
** **** **** * *** *** ***** **** * ** * * **** * * * * ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * * ****
* * * * *

int main (void)
* *

char c;

int i = 0;

void **** c)

{
* **** * *

i++;
** ***

i++;
* * * *
* * * * * ** * * * * ** * * ** *** **
* ** ****** * ***** ****** * 0;

}
* * ;

}
*** * * * * ** *
**** ** ** * * * *** * * *
** *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* **** * * * * * **** a1=0,a2=0,a3=0,a4=0,in;
** * * * ** ** * * ** ******* * ** * && c[in];in++)

    {
* ** * *** * ** * ** * * * *** * * ***** (48<=c[in] && c[in]<=57)
** * * * ** ** **** * *** ** ** ** ** * * * * ** *
* * ** ******* ** * * * * * * * * * *** *** * * * *** ******
** * *** * ** ** * ** ** *** * ** * *
*** * ** * * ******* * ** * ****** * *** ** if(65<=c[in] && c[in]<=90)
** * *** ***** * ** * * ** ** ** ** * ** * **
* *** ***** * ** ** * *** * ****** * ** * * ** ***** ******* * *** ** **
* **** *** *** ** *** ** * **** * **** * *
** * * * * * ** * * *** ** * * * * ** if (97<=c[in] && c[in]<=122)
* ** ** * ******** * ** **** * **** * * * ** *
* ** * ** * *** * ** * * ** * * * * ****** * * * * ** * *** *
**** * * ** * * ** * ** * ** * ****** ** *
* * *** **** *** * * *** * * * ** * ** **** if(39<=c[in] && c[in]<=46)
** ***** * *** * **** ** * * ** ** * ** ** *
* **** * * ** * *** ** * *** ** ** * * * * ** ** ** * * ***
* * ** * * * * * *** * * * * * ** ** *
***** * * ** * ************ ** * ** * * * * ** * * ***
** *** ** *** **** *** ** * ********* * *** * **
* *** ** * * ** *** * * ***** * *** ** ** ** * *** **** ** *** *** * ** **
*** ***** * ** * * * * * *** * ***** * ** * * * **** * ***
** *** * * **** * ** *** *
* * * ** *** ** ** * * * * ** * ** * **

 }

 

 int main()

{
* * *** ** * *** ** c[100];
**** * ** * * ********
** * ** *** *** ** **** ** * **

    
* **** * **** * * * * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
**** **** ** ** ** * ** i=0;
** * ****** ** * * ** *** **
** ** *** * ****** * **** * * ** **** ***
* ***** * *** * * **** ** * * * ***** * ******
* *** *** * * ******** * *** * ** * *
* * * ** ** **** ******* i;

}



int check2(char c)

{
* ** * *** * * * * ****** j=0;
*** * *** ** * * ** * *
*** * * ** ** *** * ** * * *** * ** * * *
* ** * ** *** *** * * * ***** * *** * * ***
** * * * * *** ** * * * * ** *
*** ******** * ** * * * * ** j;

}

int main()

{
* * * * * ** * * *** * c;
**** *** *** ** * * * * i=0,j=0;
** * * ** **** * * * * *** ** * ****

    
* * ** *** ***** ** c!='.')
**** ** * ** * *


* ****** * * *** **** * ****** * ***** * *** * **
** * * * * ****** * * * ** * *** ** ***** ****
** ***** * * * ** * * ***** * ********* **** *** * * * * * ** *
* ** **** ** ** * * *** *
*** ** ** * ** ** * * ** * * * * * ***** ***** * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ***** ** * ** ** * ****** i=0;
* ** ** ** ** * ** ** *
* ** *** ***** * * *** * ** * * *
*** * *** **** * **** * ******* *** *** * **** * ** * * **
* * * * * * *** * * * * * * * **** *
*** * * *** *** i;

}



int check2(char c)

{
** * * **** ** * * j=0;
* ** * ***** ** * ****** * ***
* * ** * **** * ** * * *** ** * * ** *
* * * ***** **** * * *** * * * ** * * * ** * **** *
* * * * ** * * ***** ** * * * *
* *** *** ** * *** * *** j;

}

int main()

{
* **** ** ** * ** * c;
** **** * **** **** ** * i=0,j=0;
*** * * * *** ******* ** ** * * **** * ** ** ***
* * * ** *** * * *** ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* * ***** ** * * * * *
* * ** ****** *** ** * ** * ****** *** * * * * **** * * ***
*** ** ***** **
* * * * *** * **** *** * c!='.')
** * **** * * ** *


****** ****** ** * ** * * ** ** *** * * ** **
* * ** * *** * *** * * * * * *** ** *** * **** * *
* * *** ** * **** * ** * *** * * * ** ** * ***** * ** * ****
** **** **** * * ****
* *** * *** * **** ******** * * * * *** * * * * * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*********
* *** * ***** *

int main *
* * **

char c;

int i = 0;

void ***** c)

{
** *
*
* *

***** * ** *
** * ** * *** *** * *** * 0;

}
*** ;

}
** ** * *** * * ** * * ** ****
* **

}
** * * ** * *
* * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
**** ** * * * *** * ** c;


** * ** ******* * **** * * * i = 0,b = 0;


*** * * * *** * * **** ** * * ** * &c);
* * * * ** ** ** * * * c != '.')
* * ****** ***** * *******
* ***** *** ***** * * **** * * * ** *** * * * * **






** * * * ** * * ** *** ** *** *** ****** += 1;


* * **** ** * ** ** ** ** * ** * * **** * * ** * &c);
* ** *** *** ***** * * * * * ** * * * * *
* * ** ** ** ***** * * * ** ** ** ** **


**** ** **** ** ** *** ***** ***** *** i);


*** ** * *** * * ** * ** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
** * ******** ***
* * ** ** ** *
* main *
* *
c;

int i = 0;
** * * c)

{
*********
* *
* *** **
**
*** ;

}
*** * ** *** ** * * * **** *
** *

}








* ** **** * *
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * ***** ** * * * * i=0;
* ** * * * ** *** ****
* **** * * **** ** * * * ***** * ****
*** * * *** * *** ** **** **** * * **** ** *** **
**** ** **** *** * * * * ** * * ***
* ** ** * *** * * * *** * i;

}



int check2(char c)

{
** * * ** * * ** * * j=0;
* * ** ** *** * * *** *
****** ** *** * ** *** ** *** ******* *
* ** * *** *** * * ** * *** ** *** ** **** ** ** *
* ** **** **** * * ** * ** * ** * * *
* ** ** * * *** * ** * **** j;

}

int main(void)

{
* * ** ** ** ** c;
*** * *** **** * ** ** ** * i=0,j=0;
** ** * ** **** ** *** *** * ** * *
* ** ** ** * *** * ** c!='.')
* * * *** ** * * *** **


* *** ** * *** * * * ****** ** * * * * *
****** * * **** * ** *** * * * ** ** ** * * ** ** *
*** ***** * *** * * * ****** *** ****** * * **** * *** * ** ** * *

    }
* ** ** ** ** **** * * *** * * ** * *** ** ****** *** ** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ** ** * * * *
* ** * **** * * * *

int main * **
* * * *
* c ;

int i = 0;
* * ** ** **** * ** **
* **


* **** c)

{
*****

*** * **
* *
;

}




** ******** *** *** *
* 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users