0 like 0 dislike
6.9k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 6.9k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** * ** * * * *** i=0;
**** * * ***** * ** *** * *** *
* ** * * *** * *** * *** * **
* ** ** *** ** * * ** * ****** ** *** * ** ** **** ** * **
* * ** ** * * *** ** * ** ***** * **
** *** ** * ** **** ** *** * i;

}



int check2(char c)

{
* *** **** ** * * **** j=0;
*** * * * *** * *** *
** ** * ******* * ** * **** * ** ****
** ****** *** ****** ***** * * * * * * * * * * ** * *
* ** * * *** ** ** ***** * *** ** **
*** ** * ********* ****** * * j;

}

int main()

{
* ** * * ** * * ** * ** c;
** * ** ** * * * ** * * ** i=0,j=0;
***** ** * ** * * ** * ** * ********

    
* * * * * * **** * c!='.')
* * ******* *****


* * *** ** * * * *** * * * * * * ** ***
*** ** * ****** ** * * ** * ***** * ** ** * *
* ** ** *** ** * * * **** * ***** *** * *** * **** ***
**** * * *** ** * ****
* * * *** * ** ** * * * ** ** * *** * *** ***** ***** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ** * ** *
* ** * ** * ** * **

int main (void)
* * * *

char c;

int i = 0;

void **** ** c)

{
** ** *

i++;
* **

i++;
* *** * *
* * ** * * *** ** * *** * *** * *
* * * ** * ** * * * ** 0;

}
* ;

}
* ** * * ** *** * ****
** **** * * * *** * * *
*

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* ** *** * *** * **** a1=0,a2=0,a3=0,a4=0,in;
* ** * ** **** * ****** * * ** *** && c[in];in++)

    {
* * * * ** **** ** *** ** * *** * * * (48<=c[in] && c[in]<=57)
**** * ** * * * * ** * * *** **** * * * *
** ** *** * ** ** * ** ** ** * *** ** * * * * * *** **
** * * * * ** *** * *** ** ** ***
* ** ** * *** * * **** * * *** * ** if(65<=c[in] && c[in]<=90)
**** ****** ** ** ******* ******** ****
* *** * * ******** * ***** * * * *** ** *
*** * ****** * * ** *** *** ** ** * * * * ** **
* * ***** *** * * * ******** * ******* ** *** if (97<=c[in] && c[in]<=122)
*** *** ***** ** ** * *** * **** * * * * ** **
** **** ** * * ** ** * * *** *** ** * * *** *** * * ** * * * *** * * * *
***** ** ** *** ** * *** * * * ** * * *** *
* ** *** * ** *** ** * * ** *** *** * * if(39<=c[in] && c[in]<=46)
** * **** * * * *** ** ** ** *** * ** ****
* ** * *** ******** * ** ** * ** ** * * * *** * *** * **
**** ** * *** ** ** *** * * ** ** * * * * ** * ****
** * ** * * * *** *** ** ** * * * * * * ** *
***** * * * **** * * ** * * * ** ** ** ******* ** *
** *** ** *** ** ** * ** ** **** * * * * ** *** * **** *** *** * *
** * * * *** **** * * * *** ** ** * *****
* *** * ** * * **** * * * *
*** * * **** * * * * ***** *** * **

 }

 

 int main()

{
* * ** * ** *** * * * c[100];
* * * * *** * ****** **
* * * * ******* ** ***** *

    
* * * * ** * ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * ******** * *** i=0;
* ** ** ** * * *** ** * *
** * * * * * ** * ** *** * * ** *
* * * * * * ** ** ** ** ** * ***** ***** * **
* *** * ** **** ** *
* * **** ** * ** ** ** * i;

}



int check2(char c)

{
** ** ** * ** ** * ** ** *** j=0;
* ** * * **** ** * * * *** **** * *
** ** ** * * * * * ** **** ** * **
* * **** ** * * * * ********* * * **** *** * * *** **
** ** * ***** ***** ** * ** ** *** ** * *
** * ** ** * * * ** * *** * j;

}

int main()

{
** * * ****** c;
* ****** *** * * ** i=0,j=0;
*** * ** **** * ** * ** * ** *** *

    
** * ** ***** * *** ******* c!='.')
** * *** ** * ***** *** *


** * * * ** * ***** * *** **** * *** **
** ** * * * ** * * *** *** * * *
*** *** ** * *** * * ** **** * *** * *** * ** * **** **
* ** * ** * ** ** ****
* * * * ** ** ***** *** * * ** * *** * * ***** * ** *** *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * *** ***** ** * * **** i=0;
** ** ****** * * * ** * * *
** ** ** ** ** ** * **** * * *
** ****** ***** * ** ** ****** *** ** * ** * **
** ** * **** ***** * * * * *** *
* **** * ** ****** ** ** * i;

}



int check2(char c)

{
** * * ** * ** * * * j=0;
** *** ** ** * ***** * ** *
* * ******* **** ** * ** * * * *
* * *** * *** * * *** ** ** * ** ** * ***
**** ** *** ** *** * * ***
** * ** ********* * j;

}

int main()

{
** * ** *** * * ** ** * c;
* * ** ** * ** ******* i=0,j=0;
* * * * ** * ** * * * ** * *** * * ****
* * * **** ** ******** ** * * * * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
**** * ** *** * *
*** * ** **** * ** * * * * * ** * * * * *** * * ** ** * * *
* * * * ** ** ** * * *
* ** *** * ** * c!='.')
* *** * * ** *** *


* ** ** * *** *** * *** ** * * * *** **
* ** * * ** * ** * ** *** ** ******* ***** * *
* *** * ** **** * *** ** *** *** *** ***** *** **** *
** * ******* * *** * ***
***** *** ** * ** ** * *** * * ** * * ** *** *** ** *** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * * * **
*** ** *** *** ** *

int main ** * *
** *** **

char c;

int i = 0;

void *** * c)

{
*** **
* *
* ** ****
* *
* * ** ** * *
* *** * *** * * * * 0;

}
* ** ;

}
* * ******* ** ***
* **

}
** ****** *** ** *
** ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
*** ** ** * * ** * * * ** * * c;


* *** * **** * ** * ** i = 0,b = 0;


* **** ** ** ** * * ******* ******* &c);
*** * * ** **** ** * c != '.')
****** **** * *** *
*** * **** * * ** ** * ** *** * * ** ** *






* **** ** ** **** ** ** *** * * * * * *** * += 1;


*** ** ** * ***** ****** ** * * ** *** ** **** ** ** ** ** &c);
* * **** ** * * **** *** ******* ******* * *** **
* ******* * * *** **** ************* ** * **


****** * ** ** * ** * * *** ** ** i);


* * ****** ** **** * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* ***** *** **** ****
* * * *** *** ** * *
* main * *
* * *
** c;

int i = 0;
* * * * c)

{
** ****
* *
*** *****
*
* * ;

}
*** ***** ** ** ** * * * * * ***
* *

}








** **** *** * * ***
** *** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* *** *** ** * * * * ** ** *** i=0;
** *** ** *** ***** * ****
* * ***** * **** ***** * * * * * ** ** *******
*** * ***** * ** * *** * ** ** **** *** * ** *** *
* * ***** *** * * * ** **** * ** *
********* *** ** * *** *** ** i;

}



int check2(char c)

{
** * ** * * * ** j=0;
* * * *** ****** *** * *
* ****** * ** ** * * ***** * ****
**** ** * ** ** * ** * * ** * * * ** ** ***
***** *** * * **** ** ****** **** * * ***
* ** ** **** ** j;

}

int main(void)

{
* * * ** *** * * * c;
* * *** **** **** * ****** i=0,j=0;
*** *** **** ** * * * * * *** **
*** ** * ** * ** ** * c!='.')
** **** ** * * ** * *


* *** ***** ** * ** ** ** **** * * ** * *
** * ** *** * ** ** ** *** * * * * * ** *
*** * **** ***** ** * ***** **** *** * * *** * ** *

    }
* * * ** ** ** * * *** *** ** ** * * ** * * ** *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ***** ***** **
* **** * *

int main *
*** *****
* ** c ;

int i = 0;
* * * * ** *** * *** ** *
****


* * * ***** c)

{
* * * *
***
***
*
* * ;

}




* * ** ** *
* ** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.28
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users