Final Exam 3 (20%)

1 like 0 dislike
17.5k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 17.5k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *   * * *** * 
#include   **   ********* 
char a[100],sum[200],space,i;
int main()
{
**** **    *  ** *****    *   ***    * 

  ** * *   **** *      ** *     *   *   **   *   
   * *** ***    * * *  ***      ****  ***     * ** *  * * *   '){space=i;}
* * *   ** ** * ** * *** 

*  ** *   ***  *  ** *  * *  ****** **     ***  ***  
   **  *    ** ****    * ** **       **  *   * *   ** ****** *  **    ****** ** ****
 *  * ***** *  *  ******


 *** * * ** *  * * *** * *** *     0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ****** *  *** *** 
  **   ** *   **** 
 ***** ** * *** ** 
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
* ** * **    *** * *  ** *    num1[51],num2[51];
***   *   *   **  ***   **  ** i,m;
**  *  * * * **   * **** *   * *  arr[51]={0};
 *  * *   ****  *  *  **    ** * 
***    *    ****   * ********** **    *  %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
* * *    *  ***  *  * ** *     * * * * ***    * *     *****  *   *** ** ** 
    }
 * * * *** **  **     ******* (i=0;i<(strlen(num2));i++)
 * * *  *  * ****  * ***
 * * ****  ***   *** ** ** *  * * *******    **** *   * ** *****  ** ****   * 
** * ****    ****  *    *   
***   ** * *** *    ***  * ** **** (i=0;i<=50;i++)
 ***  ******  *  * *  *    ** ****
   * * ** **** ** **   ***   *   ** * *   ***  *  ********  * ** * ***** ***
**  * *  *   * *** *  ** ** *  * *** **** ***   
** ***** * *  *** * **** * *****    **   **  **** ** * *****   ***  **   * *  **    * ****
 *   *  ** ** ***   **** **  ** **  *  * * ** **    ** ****  *  *  *  ***** * * *  * *    ** ** 
*   * *  *** *** *** **  * * * * * *    ** * *** *
    }
* * ***   *  * ***      **   * **   ****  
    {
    *  **** ** ***  *** ****    *  *    ****   *   ****     *  *    
* * **** *   * *** *** ** *  *   * * ** **** *   *
* **  *  ** **        *** ***  ***  ***  ****   *   ***** *** *  ** *******
**     ** **** *     **   * **   ***  **   * **     * 
 *** ***** *** * *      *    *** *** * *   ** ******** **  ***  ***   
* *  *  ** ***  *   * * *    *    *   ** *  *   * *** 
*    *  *** ***      *  ** **** ***  *** **  * ***** * ** *****  * * ** *  ***      * ***** ** ***   
**    ***     *  ** **     * * **  ******* * ** ***   ***   ** ***  ***      * ******  ***  ****     **      **
*  * **  ** ** *  **  **   ***  **   *      *** *  * *  *    *
    }
** * ****  *   *  * **  ** ***  *  0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
 * **  **** *   *  *  *  *  a[n],b[n];
 *** **** ** ***** *  *  * *  *** * * ****   ** * 
* ***  *****      *** ** **  l1,l2;
 ** *    **  * *** * **   ***   i=0;
 *  ***** * *  ****  ****** *  **
 ** ** *** *    *** ** ** * * *   *
  **    ****  * * *   **     * * * *   * * *     *
*  * *  *   *   *   * ** ** * *** *   ** *    * ** * ***
* * *   * *    *  ** ***   * ** * * **   ***  ** * *



   *  *   *** ***     * **   * ** ** *   *  *** *  * *  ** * *  * **    *  **** * **   *   **   * *** * **  *     *   * ***   * *  *





 ** ** * ** ***  *** **    ****** * *  **  ********  * *  



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
   ** ** ** *     ** **  * * ** a[50];

    ** *    * ** ** *** ** ***   b[50];

 ***  *   * **  *  **   *  c[51] = {0};

* *  *** *   *   *  *  **  **  *   *  *  ***** a, b);

 * * * **   * *  ****  i = 0;

    ** ***   *   * * * *  len_a = strlen(a);

** *  *  * *********  * * * * * * len_b = strlen(b);

  ** **  **  * *  ***  * * ** * * = 0; i < len_a; i++)
**********     ** ***  * * * **  
*   * ** **   *   *    **        * ****      *  *** = a[len_a - i - 1] - '0';
  ***  *    **  ***    ** **     *
***  ** *  **   * ** *** * *  = 0; i < len_b; i++)
  ***  ** * **    * *** *  * *  
* ** *** *    ** ** *  *    *  *   *  * ***  **** ** * ** += b[len_b - i - 1] - '0';
 ***  * * * *  *    ***  ** 

****  ***  *  *    ** *  * **   = 0; i < 51; i++)
* **** *     *  * **  ****   *  *  **
 ****  * * * * **      ** *** ** *   * *   ***** ****   ** > 9)
*       * **** *  ** **  ***  *** ** *   ***     * *  *    
*  *  * ** *    ** *** **   * *   **  *      * ******       *** * **    **  * **   + 1]++;

   **  ****  ****   *  * ** **    *  **   ** * ****** *  **        *      * ** %= 10;
 **  **  ****** * *  *  *  * *    *  ****  * * *  **  *** 
 *    ***** * **    * *  *  *

    * ****    * **   *   ***  nonzero = 0;

    * ****  **  * *   *****   = 50; i > -1; i--)
    *  ** * ***  *  ** *  ** 
***    *    ***** *  **    *   ******** ** * **  *     * *   * *  != 0)
 ** **** **** *      ***   *****  * *   * * *     * * *
* * ** **  ** ****  * * *  **** *  **  * * **  ****  * *    **  *         *** * * ** *   = i;

*** *  ***** **** ** ***** * *** * ** *   ** *  *****  *  * * ** ** ** * ***  *  ** *   *
 ** *** *    **  **  *  ***   * * *   * *  *  ******  *
    }

*** *** ******  *   ***    *  = nonzero; i > -1; i--)
 **  *  ** ***  *  ***  * * * * 
* * * *  *  *** *   *   *   *** **  *  **    *****   *  **   ** * **    c[i]);
**  ***  *   *   * **  * * **  ** 
   ***** ****** ***      *      0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

* * ** *   **  * ******  * ****     **         * ** ** **     ** *  ***  * ***  *  
    for(i=0;i<strlen(a);i++)
*  ** *         *    *  **     ******** ** *    *
 * ***    * **  * ****       **  * ****   ** ** *** **  * * ** ** *** * * *** * *  *** ****
*      ******* * *  * *  *  **   ***   *      ***   **   
    for(i=0;i<strlen(b);i++)
* ** * *  * * ******  **  * **   *    ** *  *  ***    *
*  **     **  * *** *     ***** *** * *  **  * ***** ****** ***  **   *  *******  ****** * **  *
* *  **** ** *     ****    ****  ****   *  * * ***** 
    for(i=0;i<50;i++)
****      *  **** *** **  * ***  *****    ** **** * ***** * *  
***  ** ***   * *** * * ** **     * *  ****** *** *   * *   * *   ****  ** *   > 9)
      *** ****   *   *  **  ******   *  ** *  *  ** *** *    ** * ** * * *  *  **     **  **** *  **** 
 ***   *  **  *  *** ** *******      ***   *** *  * *  *** * * * ***  ** **** *  *  ****** *  *** **  * ** * * * *    *      * *   **  
  **  **** **  * ** * ** * *    *  **** * * *    **  ***   * * * *    *** *   *   * ** *  ***  ******    * **** *   ** **** ***   **** * ***** *  ** **   
     *    **** *  ****  *    ** * **    *  *      ****  *    * *  * *    **     *  *  ***    **     ** ** *  * *
* *  * *    ** * **      * *** **    * *  ***  ***** * 
    for(e=51;e>0;e--)
 ** *  * ****  *****  * *  **   * ** *   *  * ***   * *** 
 *  ** * *   * * ** **  ******  ** ****  ** *** ****  **   ****  *  *   * != 0)
******   ** *  **     *  * *  **      **  **** * ***  * ***   **  ** *   ****  ** * ****   ***  * ***  *** **      *** 
 *** *   ** * ** ****    ****   * * ** **** *** ***** * *       *   * * **    ** **    ** **     *  ** * *   *** ***   *** ***** ***   * **
    ** *** * * ** *     * *** *** *     ****** * *   * **   * *** **   *** ** **** * * * * ** ***** * *   * **  * ****  **  **
* * ** *  * *  * *** ** **  ** * ** *  **** **   ************ ** *  ***** *   *  **   *    *** **   * *** 
 *** *  * *    ***    *   *   * **  * * *   **   *
** *  * **** *  ***   *    **  *****     *  ** * *      *   * ** * * *  **  * ** 
    for(i=begin;i>=0;i--)
**    * **  **  **  *  ** *   * * ** *   *  *   *** ***
* ** *  * ** *   ** ** *  ***** * ****** ****   * *  ***  **   ***** ***  * **  **    * **  *** * ***  * *  ***
  **** * *  *  * *    ** *** **         **  ** ****  
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**     *   * **  *  ** *   ** ** i,j,k,l;
*   ****** *     **   **  * ***  * a[100];
  *   *  *  * *    *** **  * b[100];
*** * *   *  **   * * * ******      **** *  *** **   *
    *** *   ******  **    * ** * * *   ** *** * && * ** *********  ***  
 * *  *******   *    ******  
***    *   *   *****   *   * *  *      **  ** * * **  *   * * * * * ***  *** **    *     ** **   
 *   *    ** * * * **  
 * *  *     * ****  *    * *  * 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
   ** **  ***      *  *   **  ***  *   * ****  *  *  a[50],b[50];
     ** *   * *  *    *** *** **  ** *** * *    ***    c[51];
*  *   ***     *    *  **** *** * **  ** * ** n1, n2;
*  ******    ** * *   * * *   ***  * * ***** * **  *  i,j;

* * **  *** ***    **  * **   * *** **** *  *** *  
        * *  ****      **  *** ** ****** *  ** * ****** **

 ***** ** ** ** ** ** **  ** **** * *     ***** ** **   **  * * *  
       {
** * **   * **  *    **    *   ***  * *    *** * ***  ** **      *  * * **** *    *  * **  *  *****  );
*   ** ** *     *   *    ****  ** ** **  * *

 **  *   *     **  *   * ***** ** *      ** * *******   * *
** ***    **   ** *** **   **    *  * * * *   *  **
* ***  ***  **  *  **  * *   *   ** **  *       *   * * * *   **  **  ***  **    * **  ****   ***   b[i]);
*  ***  * **   **** ** * *  *   *  *  * **  ******



   **   *  **** ***** *   * *     * ******** *  * *  * * * *****
***  * **    *** * ** ***** ** * *      *    ****
****** ***** * * ***   * *       ** *     ******* *  *** **  ** *   ***   *   **  
* * *     ** *         * ** *  ** ***  *
***   *   *  **    ** ***   * ***** ***   **   ***  *  * ******* *** *
*  **   ****   * **** *****  ****** ** *****   *  
 ****** **    * *    *** **  ***  *   *       **   *  ***  *   *   ***  ***   * *   
*** **  **   **** * *   ** * **  * * ****    *******   

  ******  **** *       **   **   *   * ** ** * *  *     **   *
 *   **  * ** ***  *** *** * *   ************** * 
*   ** ** * * * * **** *    *   *  *  **   *** ** ** ** *  *  ** *  *  *
    ***      *   *   **     *** *  *** * *      *   ** ****  * ***  ***     *
       }

    ** *  *** * ***   *  *     **   ** * **     *  **    ***   *
       {
*  *  *   * * ** **** ** *  **** ***  *    ** *****  *  * * *  * **  *  * * * *  ******** *    *
       }

*  * * *** *   ******  ** **     **  **  * ** *   * 
*** * * * **   ** **    *     **** *   *****     ***     *
    *   ** **** *     * *     *   *  * ***  **    ****  ***     **     * *    ****  *  ******** *   * ***
  ** *    * ***   ** ****   *    * ** ******  * * **    *  * 


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * ***  * *
#include *  *  *    
#include * * *  *  
int main ()
{
*  ** * *   ** * * ** *** i,n,m,c=0;
**    ***** *  *******       A[60]={0};
*  * *   * ****  * **  ** *   *    **** **  ** *
    ** *  *    **    ****   * ("%s *  * ***  ** 
*  * * ** ***** *  ***   *** ** ** *   *   * *  * *  * * *     * *  
* *    ** * *** * *** *** *  **** 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 *****  * *    ** **  ** ** ** **  **** ***  *  ** *   **  * *        * 
    }

** *    *  ******   * * ***** **  *    ****   a);
  * * *   *   *   * ** *  *  **** *    **   b);

    for(;;) {
 *** * **  * **** ********   * * * *  * **   ** *   **** * *   * *  {
  ** *  *   *  **  *******      *** *  ***** *** *  * * ***** *  ** **   *** * ****  **  *  ** *
** ***    *  * * * **** * *   *** *       * *  *   * ***   ** *    *    ** *** * *   
*   *  ***  * *   *    ***** * **** ** ** **** ** *        ** *****     ** *  ** * * * 
***  * * ** ***     **  * *   *    **** * *** * **** *  
*  *  ** *  * * *        * ***** ** *       *  ** **  ***** **     {
* ****** * *  *  *******  *   * * * ** *** **  *****    ** *       * ** ** *   * *    * *    
** ****** *   * ***  ***** *  *** *    ** *  **   * * * 
    }

    for(;;) {
**     *  **   ** *   * **    ** *    ***     ** * *  ***   *  **    ** *     {
*  *  *  *  * *   **  ****  *   *  *  ****      *****     ***   ****  *  *
**** * *** * *  *   *  *  **** *    ***  ** *  ***         ** **** *** **** **     ****** ** ****
*****   *  * **** ** *  *  * **  **   ******   *    * * **** ****    *  *    **  *  *  ** 
   * ***** ** *  *** **  **  ** ** *    *** *  *  **   **   
  ****   *    * ** ******  **    *   **   ** * ******   ********* {
    *** * ***  * **** * ****  ** * * *  **  *   ****  **  ** * ** * ***** *     **  * **    
    *   * *   *  ** *    *   *** *        *  * 
    }

  **    *       *  **   *  * ***  *  * * *    {
*  * *    ** * ** *   **  *** *   **** ***  *   ** * *   *** *  * && a[i]<=57) {
* **  **  ***         ****** * * ***** *  **   ** *   **     **   *   * ***       * ** ***   
       * ** *****     *  * * **  * ***** **  ** **  ***
    ****  **  ***  ***  * *  * *** ** *   ** **    **  *   && b[i]<=57) {
* * * *****  *    **  * ****  *  ** **  ***   * * **** ***    *  **  * ** * *   * ****   * ***
  ** ****   *    *  * ***** *   ***   * ** ***   * *
    }

    for(j=50;j>0;j--) {
**   **  ** *       * * *  **    * ** *  ***   * *  *  *   * * *** *  **  **** {
   * *****   **  ** *  *    * ***       ****  ** * * * * **  *  ******   **   * * ** * *
   * *    ****  * **   **** * ****  ***       ***  *
** ****  *   ** *   **   **     *  ****   ****     * * *    if(sum[j]+a[j]+b[j]==10) {
 *  ** ***    *****  **   * ** **   **  *  ***  ***   **     *      ****     ***    *****  *   * *
***  * * *    * * * *** *   **    *  * * **    ***     * **  ******* **** *    ** *   **  *   *    
   ***** *    ** **    *  **  * *   **   * ** * **  *  
***    *   * **     ** * **  *    *  **  *** *** * ****  **** * if(sum[j]+a[j]+b[j]>10) {
* *   * ** ** * *  *** ***      **  * *  *****  **** ****    *  * *  * **** ** ***** *  *    **
* *   *  *** *  ** * * * ** *** * ** ******* * ** **  ****  **    ****  *   *   **  ****   **** * 
  * *  *  *   * **   *  * *      **    ** *** ********    * 
    }

    for(j=0;j<50;j++) {
* * * **  *  *   *  *** ***   *     *   ** ****** * *  *  *   * {
 * * * * *** ***  **  ****  ****   ***** **** **   **    ***   * ******* *
   *  *   ****      ** ** *** **  **   **** * **   *     
    }

    for(;j<=49;j++) {
 * *  * * *  *** * **   *** * *   ** * *** *  * *  * *** *** ****  *  sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 15k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 14.2k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 16.4k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.2k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 3.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users