Final Exam 3 (20%)

1 like 0 dislike
12.1k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 12.1k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **   * * ** *
#include *       * **** 
char a[100],sum[200],space,i;
int main()
{
* * *  ****** *  ** *   **** * ** * 

 **    ***** ***   * *    ***    **** * *  * * *
 *   *** ****  **  *  **      *  ***     * *****    * '){space=i;}
 **     **    *     * * * *  **  

  ***    **   *     ** * **   ** *     **  *** ***   *  
 *  ***** *** * *      ** * **  *** *     *    *    ** * * **  * **   ******     ** * *
  * *  *  * **   *      * ** * 


*  *  *   *  **   * *  **   **  0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *   *   *** * 
*   * * *       * **** * *  
*** ** ** * ** * **  
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
 ****  * *   ***     * *  ***** num1[51],num2[51];
**   ***** ** *  **  *** *   i,m;
*  **   *** *** *** **  * **   arr[51]={0};
 * ***    *    ** *****  
* **** *   *** **        * ********    * * %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
   **  * **       ***  * *    ** *  **** *****  *   * **  *  *   *  *     * *    *  **
    }
 ** **** * *** * *    * *** (i=0;i<(strlen(num2));i++)
     * * *       *** * 
*   **  **   *    * *** *  *  * **     **  *   ** *   ***  ** ** **** ****  *     ***  *
  * *  *   * ****** *    
* **  **  * ***    * *  *  ** (i=0;i<=50;i++)
  *** *   * ******  * 
*  **   ****** *     * **  ** ***  * ***** **  ***** * * ***
***    * ** *    **   **   **** ****   **  **   ****** *  
 *   *   ** ****  ** *   ****   *   * * * *  *  *   * *  **** * *    **** ***   *   * 
** **  *  **  * * * *  **  **  ** * **       *** * ****     ****   ****** * * ***** *     *   *
 ** * *  *    *** *  **  **** *  *       **  *     *  **
    }
  *    ** ***    ** * * *  * *   *  ******* 
    {
* * ***  ***  *** ***    *** *  **      **  **       *** ** 
*** *     * *** * **  * ***  *    ***** * ** * *
       **   ***  ****   *   *** *  ***** *  * ** * * * ** **   ** * * * **  ** * * ****
 ****** *    * ***  *  * * ** *   *  *  ******  *  *** **  
 *** *  *   *  * *    * ** * *   *  *  *** ** *   *   ****   **  ***  
*     * * * *     * **** ** * ******** **  *  *****    * 
* *** ** ****  *  * **  ******* **** ****** *** ** * * ** * ** *     ** **     *   * 
**  * *  * * ** ** **      * **** **  **    * *    *** * *  **   * ** *    *  ***       ** ***   **  
** * **** * ****  * ***    **  **    *   *  *        *    *
    }
**    *  *     *** *  ** **   *** 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
 ** * ** *** *** ****     *   a[n],b[n];
* **** ******    ** ** *  * ** *  *  * ****  ***  *  * 
  * *****  ** * *  **     **  * l1,l2;
  **   ***    *** ** * ** *    ** *  i=0;
  *  ** *   * *   *  *  ***  * ****
**  **   ********* *  **    *  *  *
*  ** ** ** *** * **** *** *****   *  *  * **** * ** 
    * **  * **  * * * * ** **  **    **  ** *   **  
* **  **       ***** **  ******   ***        *** * ** 



**** **  ****  * *  *  **   * **      **     ****  **  ****  **  *** ** ***  *** * ** ** *** *** *    * *  **  **





* ***     *  * ****** **** * *  ** *       ** * * ****  



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
   **      * * **  * **** * a[50];

  * ***  *  ** ** ****  ** b[50];

 *  * * *   *  *  *  ****  **   * c[51] = {0};

  ** *  ****   ***   ** *  * *   ***  *   **   ** a, b);

**    *  *    *  * *     i = 0;

***** **  *    *  *** * len_a = strlen(a);

* * * ***  * **** ***  ** ***  len_b = strlen(b);

 * *** **  *** *  **   * ***  ***    = 0; i < len_a; i++)
*  * ** ***  * * ** *** 
 * *  **  * * * ***     *     *** **   **   * ** ** ***  = a[len_a - i - 1] - '0';
 * **  * * **   *     *** *****
   *** **** *** **** **  *  *  = 0; i < len_b; i++)
 *  ** *     ** ******  *  *****
  * * ***** **  *****  ** * **     *  **    *         **** += b[len_b - i - 1] - '0';
***   ** *   **  ** *     

* *** * ** * *****     **    = 0; i < 51; i++)
  ** *  * ******    ** * ****
*      *    * ****     * *     *** * ***** ***** * ******   * > 9)
*   ** ****  **  *** *******  *  *  * **** ** *   *** **
 *** * *  *   * * * ****** * ****  *  *** ** *      * *** ***   *** * *  *  * * * **   * * **  * + 1]++;

** *  *  *    * ***  *    *    * *    *** *  * * *   ** *    *   *   *  *  **** **** * ***  * %= 10;
 ***   *  **  * **** * **   *** *   **  ** *** **
* *  * *  **   *    ***** **

*   * *** * ******       ***  ** nonzero = 0;

 * * * * * **  ** ******** ****** = 50; i > -1; i--)
* ** * ***  *** * **  *   
*   * *** *  **  *** *      ** * *** **** **** **** **   != 0)
 **  **  **      *** ** * * *  ****  * ** * * ** *  
****     ***  * ***  * * *  *  ** *   ** * ** ****  * * **        * *** *** **** ** * * **     *   = i;

 ********  *  *     **  ** * *     *  *  *      *  * * *  *  *** *   * * ******* * **
*    ** * *    *********** ****   **  ** *** *    **** 
    }

    ******   ****  *   ***  **  = nonzero; i > -1; i--)
***   *** * **    *  *   
 *  * * *** *  ****  ** * **** **   ** **     ***  ***  *** * **  * *  * *   **    c[i]);
    ***    *  *****  *   *
*** * *    * * ** * * *   **  *  *  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

** * ***     * * * **** * *  ** *     * ****  * **  ** ***    * ***** 
    for(i=0;i<strlen(a);i++)
 *  *  *  *   ***  ** *   * ** ** * *   ****  **  
 ** *  ***     * ** **   * **  * **** ****  ** **     *  *  *     * *     *    ** * **
 ** * * ** ** *   *  * **     *   *  **  *** ****  *    
    for(i=0;i<strlen(b);i++)
  * **    *   ***  ** ** ***  ***   * * **** **  **  *
     *  **     * * *** **  **** * * *  *   * * ** ** **   **        ****  * *      * **   *
*  * ***   *     ** * **   *     *** * * *** ** ****  **    *
    for(i=0;i<50;i++)
*  * *****  **** * ** *  **     * **  **** * ** *  ***  
****** ***    **     *  ***  *** *  **** * **   * * ** ** ***  ** *  ** ***   *** ** > 9)
** ******* * * * ** **  ****  **  *  *      ** **** ******* ***  ***     **  ** ***     ****** ***   ** **** ** **
       *   * *   ******  *** ** *  *   *  **********  *   **  *    *  ** ***  *   *  *     * * **** ****  * **   *** *   **        *** 
  *    * ** * *  *** *  ** ****  * **  **   *   ***  *  *  **   *  *  ** *** * *  * *** * ** ****** * * ***   ***    **   **** * * **  **  
* *   **  * ** *  ** *   ***** *  *** *   **  * *   *    ** * * * ***  **** ***** *    ****  * *** *** ***
  *  ***** ** * * * ** * *  * *    *      ** **  ***  * ** **  
    for(e=51;e>0;e--)
 **** *   **** ***    ****** * *  **** * * *  *** *
* *  * **  * ** * ****** * * *   ***   ***  **    * * * ***  *  *  *   ** **  *  ** * != 0)
** * *  * *  * *    **  *   * ** **     **** * **  ***********   *  ***     *   *** ******* *******  * **  ** ***
****    *  ***** *    ** ***    ** * * * ** *   * ** **  *** ** **   ** * * ****** *   ** *    *** * * *  *   **** * *** ****    ***  ***  * ** ** *   
**     * *        *******    ***   **  *   ***  *** ** **     * **   *** * * * **   *  * *   ****  **      *** * **    ****  ******* ** * 
**** * * **** *  **** * ********   *    **  *     *  * **     *   *  ** * *       ** **** *** ** **   ***     * *** 
 *** * **   **  *   * * ****      **  ** ** *  ** * **** 
***** *** * ***   ***  *    *     ** *   * *** *  **  ** *****  *** ****** *  **  *  ** 
    for(i=begin;i>=0;i--)
 *     ** **       *    **  *  * *** ** *     *** ****  **  
     *   ***       ** *   ***  * * ***** ****** ******* * * *  **** *    **    **     **    *   *    ** 
   * *  ** *   * ** * ***** * ** * *      *****  * * * **   
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *  ***   * *     **     * i,j,k,l;
* * **  ****   *    **** * **    * a[100];
***  *     * ** * *** ** *   b[100];
* ***     **      ***      *** **  * *    *   * *  ***     
   * *   ******   * ** *  *  **        * ****  ***     &&          *    *  **   ***
     ***  **** *   *  *   ***    
**  *  *  *       * *      **  * *  **** ** *  *  **    *  * **   * * *   **    * * ** * 
 ** ***** ***  ** ****    **
 *** *** ** * ***      *****  ** 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
*  * *  *  *     *  ******  *  * * ** ** *    a[50],b[50];
  ** ****       ** *** *  **  ***   **    ***   * * * c[51];
* ***  *** ****   *** *   ****  ** *  * **   ** * * **  n1, n2;
  **   *    * *  ****  *  *   *  * *     * i,j;

 *  **    **    ** * *     * **   **     **   * *    *** *
*          * ****   **        **  * *****  ****  * *   * ***

*   * * *  *** *   ** *    *      *  *** **** ***  *  ***  *** * *
       {
* ******* ***   **   * * ** * *  ****** * **    ***  ** *****  *** **   **  *** * ** *   *  ** *   * *   );
*  ***   *  * ****  *   **    *   *        ***** * 

  ****** * *   ******** ** ***** * ******* *** ******** * *   *  **
* **  * *  ***** **  ** ***  * * ** *  **** ***
 ** ***** * *   * * **  *   *** ******  *   **   *   * **   ** *   * *  * ******  * ******** b[i]);
* * **  ** ****  ****  * * **     *   *  *



* * *  *    ********* *  *   *  *    * *** *** *** ***  ***** * * ** * **
**   *    * ****    * ** ** *****   *   *   * *****
** ***    * *   * *   **** *          * ****** ****  **  ****  **  * * * *  **    
  * **  ******   ** * ** *** * **   *   **** **    
** * ****  * *  ** * *    *      **  * ** *   ****  ***  * * *  * **
**  ***  *  ***   *** *  * ****   ***** **
**     **** *   ***   * *   ******** * *  *   * * *  * ** * ** *    * * **** * *   *
 *  * * * * *    *    * *  ***   ** *  *** ** ***   * *

     ***  **       ** * *  *  * *  *** * *   *** * *
* **  ** **** **** * ****  ***** **  * * ***   
 ****   *      *****   * *   *   * *  * * ****   *   *****  * *    * **** *** ** *
* *   ****   * *   ***   *  ** *** *     ** ***    **  * ***  *  ** **    *    ***
       }

**   **   * * ** ****      * **** *   *  *   *     ** **  *   ***  
       {
 *    *   **** *   *   ** *** * * ** ******* * ** *  * * *  ** ****** **    *  **** **  ** ***** *
       }

 *  **** * *   *    ***** **    ****  * *   
*** *   * ***     * ** * ***   * **  ****          * *    * *
*  ** ** ** *   ***  **   *   ** *     * **  * * * ****    **  * *** ***       * *** ***** *** * **
* ***   **** **    ****   *   ** *   * * * *** * *  **  *


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *** **   * 
#include  *  ** *  ***  
#include ***   **  * **  ** 
int main ()
{
 * * **  * * *** *** ****  * * ** i,n,m,c=0;
** ***   * **** * * **  ** A[60]={0};
 * **  **** ** *        * * * * * ** *** **  **** 
**  *     * ** ***** *  ** ** **  ("%s *****   * *  *
*** *  ** *** * ***** * *      *    **** *   ** *****  **** * ****** *****
*      * ******    ** ** **    *  0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 *** *     ** *  **     * *   ***  *******  ** * *     *****   ** * *
    }

  ****     *******  * * * * *   *  ** *  ** *** * a);
     **  *    * * * *   ** ***    ****      **   b);

    for(;;) {
*    **   * ***   *  * * * * * *   **** ** **  **      *****  * *  *   *** {
*   *  * **  * * **      * * *  **  ***  ******   **  *    * ** **** * *  *  ** *   *
 *  ** ********  *  * *   *** ***   **  *   *  *  ** ***  ***  ** ** * * *** * * *    *   
**  **  *  ** **** * * **    ***      * ** **   * * **   *    * *     *****  *  * *
 **  ** * * * **** *  * ** **   ****     
**      ** *  * * ** **  * *** **   * * ** * *   *  *   * {
* *  *    *  **  * ** *  *    * *      **  **    ******  ***** ********     *  ** *   ** * 
    *  * ***** * *    *  ** ** ***  **** * **     **  **
    }

    for(;;) {
 *  *    * ***  ** * ***   * ***  **  **      *   *   *   *  * * *  ****   * {
     * *** ** **     *     * ** ******   ** ****  **  ** *****   **** *  *  *  * * ****  
  *    * * * *  **  **   ******  * *    *  * * **** * *   ***   *   ** *****  *
* **   *    *  *   **      *    **** * *  ** *** * ***  * ** ***  ** ** * *  *   **    
*  ** *         * ** *** * * *  **  * ** ** * * *** 
      **    **** *  ** *  ******  ***  *** *  * *  * *   * * *  {
   *          **  * *   *   *     **** * **    *   *  * ***  *************  **
  * ***   ***  *  * **** *   ****    *** **    **  **
    }

   * *   * *  *** *  ********  * *** ** {
**  ***     **  * * *  * *** *** **  *  * **  * ****** * * * * **  **  * && a[i]<=57) {
* *** ***    *    *  ***   ** * *  *       *  *  * ** **  *  ** * *   *  **     **** * ** * *
 **  ****   **   * ***  *  *** ** **  *** **** *  * **
*** *** ***  ***  ***** *** * * **      *** *  ***** * * *  ** *** ** * && b[i]<=57) {
 * *  * ** ***       ** ***   * **   * **      ***** ******    **  *  *   **  * * * **
    * ******* ***** * ** ***** * **  *** **         * * * 
    }

    for(j=50;j>0;j--) {
**    ***** ** ** *   *    **  **  *** *    * *** **  ******  ** **** *   {
**** **     **  *   ***    * *  *  *  ***      *** ***** * ***  *****   *** ** ***  ** 
** **  ** *** *  * ** *******    * *  ** * **** ** * * 
* *  *  *** ** ****  * **   *  * * * *   ** * * ** * * if(sum[j]+a[j]+b[j]==10) {
  **    *  * *    * ***   * **  ** * **       ***** **  ******   *** ** ***  
 **  *   * **  **  **** **** *  ***  **     ** * ****        **  *******  *  ** *** **
**   ***  ******* ***** *  **   * *  **  **     **** ** *
*  * * * **   ** **     *   * ***  *** ** *** *   ** if(sum[j]+a[j]+b[j]>10) {
* *  *   *  **  * * **  *  ** ** *  * *  *  * *   ***       *  * * *****   *  **   **  ** ***   
*     *   * *  * **** * *  * * ** ****    *  * ***    *  ** *   * ** * **      *  *
  *     *  *  *   ****     *    *     *  *** ***    * * 
    }

    for(j=0;j<50;j++) {
*  *** * * ***   * * ** ** *  * * ********      * *    ** ** ** {
 *  ** *****   *   **** * * ** * ***   * **   * * * * **   *****      *  *   *  * *   ** 
** **  ** *  *   *** * *****      **  * *      * *  *   ****  * 
    }

    for(;j<=49;j++) {
     *  * ******* * * *  *      * * *   *  * *   *  **** * *     *  * sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.105
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.9k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.8k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.9k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9.6k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users