Final Exam 3 (20%)

1 like 0 dislike
7.5k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 7.5k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * * * ********* * 
#include  *** *  * **** *
char a[100],sum[200],space,i;
int main()
{
**   ****** **    *******  ** *** ****    

   * ***  *       ** * *** *    * ** * *** ** ****
 * *    *   **  ** ***  * **** ** *    * ******* **  **** *** ** *** '){space=i;}
**   * *  * *  ** * *  **    *

**  *   * ** *  ** *    *     *  *   * ** *  *    
 *    *          **  ****   *  * **   *       ***    **  ** * *  ** *  ***
* * * **   ***      *     


 ** **   * **** * *   ***** * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
        ******  * **** **
** *   * *  **** *  **
    *  *   ** *****     
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
* *** *   *  *** **  * *** **  *** num1[51],num2[51];
   ****   ******* * *      *  *  i,m;
 * **  *   *  *****  **   ** * arr[51]={0};
*   *   *   *      **** *   ****
** *  *  **    *  *   **** **    *  *  * *  %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
  ****        *  ****** *  ********  ***  ****  * * ** *** *** * **    * *  ***   *  
    }
* *********** * ***  *  *   *   ** (i=0;i<(strlen(num2));i++)
 **** **** *      *    *   
 *     ***  * *  * **  ****   *  **  ********  *****  ** ***  *   *  *     ****
 ******  **   **  * **** ***  
*  ** ** ***** **  * **  * ****     (i=0;i<=50;i++)
   *  * ** *   ***  *    **** 
 * * ***  ** *** *     * **   *    ** * * * ** ** * *** * 
*    **  **  *    ** ** ** ***    * *       **   *    
  ** **  ** *     ***  *    ** **** ***   *  *  * ** **** * **  *** *   *  ***  ****   * ** ***
 ** *  *  *    *    **   *  *   ** *  *  **  * * * **    ***** *** *  ** **  *   ****     
  * ***** *  **  * **** *  *   **    *  * *   ** **    *** 
    }
 *****  ** * *****  ** *  * *     *     **  **
    {
   *  *  ***  *** *  ****  ****   **   **** *     *    **** ** 
   ** ***  **   * *  *****   *  * ** *   *  * *  ** **  ***
*       *** **  *   **  ** **  ******  **** **  * ** *  ****    * * ** *** ** * *  *** * 
* **  **   **  * *** **  ** * ** ***    *  **  * 
**  * * ***  *  **   *        *      * *    * ***   *    
*  * ** *   * ***** *  * **      ** * ** ** **  *  ****       *
* ** *  **** * *  **  *** ****  *  * *   *     * *   *  ******  *  * ** ***     ***   *
  * ** * ******* *   * *     * * *  *  ** * **    **   * * * ** ***           ****** **  *    *  *  * * * *
**  ******* ****  * **  * **   *   ******   ** ***  **** 
    }
 *** ****  ** ** * ***  *  *  ** * 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
*** **   * ***  *  ** **    ** * a[n],b[n];
**  * ** * **  ** **************   * **   **
   ** *     *  **   ** ** * l1,l2;
 **   * * ** * *  *    **  *  i=0;
 **        ** *****   * * **** * ***  
  * **  ** **    **  ** **   * *
   **   * *** **** *** * *        * *   ***  ** * **
* * ******  ***  **  **  *** * * *  ** * *  *    *
**  *  **  * *** * ***  * ** **     * * ** ** *** **    



***  * * *  * *  * *******  * *   ********* * **** * ******* * ** ** *  ** * *  *  ****   ** *    * *  * **  *   * * * *





*   ** *     **  *** * ** ** **    * ***  *     * *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
 *  * **** ** ***   *  **    * * a[50];

**  **   ****   ** * * *** * * * b[50];

   *    * **  *  **** c[51] = {0};

  *** * *** *   * * * ** * **** ** *  * ***** * a, b);

*** *** *  ** ****  ***    i = 0;

  *******    ** ** *** *   * len_a = strlen(a);

**  * ******** ***  ****     * len_b = strlen(b);

 ** **** *  ** ** ********* = 0; i < len_a; i++)
  **   * *   * *  ***     *
*    ******** **  * * *  *     ** *     **    *  **   *** * * = a[len_a - i - 1] - '0';
** *** **   **  * ***  * **
 * * *   * * *   *   *  * *  = 0; i < len_b; i++)
 *    *  ** * ******** ***     
 *  *****  *  *  ** *     *  ** *  **   **  ***** ** *   *** += b[len_b - i - 1] - '0';
***** **  ** **  * *  ***

 * ** * **   **  *** **   *   ** * = 0; i < 51; i++)
  * *   *  *   * * **  * * **
  ***   ** **  *** *  ** ** **  *    *** *  *  *  ** ** * > 9)
* ** ***** * *   * * * *  *******  *  **** **
**** *  *   *  *  **  **  **  ***** ** ***** **  *   *** *  * ** *     *   *  *******   + 1]++;

** **    **   * ***   * ** ***  ** **** **   *    *  *   * ** *  ****** *  * **** %= 10;
   ******* ***** *        ****    ****** ** *** * 
** **  ***   *** ** *** *  * ***

****  * ** *  *  ** **         nonzero = 0;

 *    *** *****  ** * *   **    = 50; i > -1; i--)
 * * *  *  * *** **  ** *  *
    **  *    * * ****    *   * * *  ***  *** **  *  *****  * != 0)
 *  ** ****** * *  ***  ****** * *  ***  *  * **** ***  ***
 *   *  * *  ****    **  *   *  *      *  * * *    ********* *  *   ** ***  *****  ** * = i;

  *** *  * **    ***     * **   *  ****      * * ****    ****  ** **  *     ** *  *   * 
*** * *   *** **  **    *  ** **  *  * ** *** ** ** *   * *
    }

  ****  **  **  * ** * **  = nonzero; i > -1; i--)
**   ****  ****   **** *  * *
**  *   *   ** *  *** * **** * ***  *** * *  ** * **  ****   ***  c[i]);
*****      *** *  *   
**** * * * ** *  ***  *** *     0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

  ****  ** **  *   *  *   **   * * ***   *** * *  *** *   * ****  * *  * **  **  * ** * ** 
    for(i=0;i<strlen(a);i++)
 ** ***  ****  * * * ** ** *   ** ***  ***    * *****
* * *** *  *  * *** *  ***    *   **   ****      **  *    * ***   ******   *** *** *  * **
*** * **   ****** *    *** *   ***  **** *      * **
    for(i=0;i<strlen(b);i++)
************    ** *** **    ******    *  * *** ***
** *   **    ** * ** *   *    ** ** *** * * **   ****   *      * * ***      ***   *  **     
   * *  ****  *   ** *** *** **** *  **    *** *  ** * 
    for(i=0;i<50;i++)
 *    * *** **  * ***  ***  *   *   * ***   *  **   **** *  ** 
*** * * *  * **    * *   ** * *   *   *** *  *  *   *** * *  *   ***********    **   ****  > 9)
*   ** **  ** *   *  *  ***  ***    *  *   **    * * *** *  ** **  *****  *   *  * *   * *    *  ***** 
**  * * **** *     * ** *  *  *** * **   *  ** *    ** **    * *** **   ** **  ***  **  *** *   * *   **** * *  * ** ***** ** * *
****** *****    *             ** ** *    ****   ** ** ***  * * ***  ** ***  *   *  ***   ** *** ** *   **   * *   *  *   * ***  *** ***** **
*  * *  ***  *    **     **  *  ****  ** * *   *   * ***  *  *  *******  **** *  ***     *   ** ****** **  
   * * * *    *     *   *       *** *** **  **** * ****** * 
    for(e=51;e>0;e--)
** ** *** *  * *  *  ***  ***  *** * *** *  **  * ****
*   * *      *  ** *    *     * ***        *   *****   ****** * *  *   ****  ** != 0)
**  * ** **** *    *  ** ****  *  *   ** ******  *  * *       ***  *  *  ***    * *  **   **   *** * ** *   * 
 * **  **   * **    ***** **     ** *** ****** *    **  * ** ***    * * *  * * *** *      * **  **** * ** * ** *     ** *  ** ** *  * *
 *  * * *  *  *       *** **  ***** ****  ** ** **  *** **  *  ** *  *** * * ** ***  ***** * * **   ** * ** ** * *   **** ***** **  ** 
* * ****    *  * * ***** * * * * *** *  *   **  ** **  *   * **  * **   ****     * ***  **   **** * * ***
*  *  ****    ***   **  * **  ** **   *   **      
*   *   * ****** *  *** *     **  *** **     **   *  *  ** *  *  ** *  *     * **** 
    for(i=begin;i>=0;i--)
** **  *  ** * *    ** *   ** *    * *** *  ** * 
*   *   ***   * *****    ** **  * ** ** * * ** *  *    ** *     *  * *  ** ** *  *      **    *** * * * * 
   ** *  * * *** *  *     * *******  *****   ** ***    * ****  
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 *   * **    *   **   ***  *  i,j,k,l;
 * ** *  * *  **  * **  ****  a[100];
**   *  * **** *  *  *   *** * b[100];
*   ****** **    ** * **** *** *****   * *** * * ** 
*  *   *   * ** ***    *** *  * **  **     * ** *  &&   ******     ****  **** *
*  ** *   ******  **  *   
** * *         **            * ***   *  * ***   **  *    *     ***   * * *  *  * *  * **      **
    ***      **  ***    
   ** *  ** ******   *   **** *** 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
*****     **** ****   ***  * * * **  *    *** * * a[50],b[50];
 * *    *  *****   **  * * * **    *   ***  **    c[51];
** * *  *  *    ***   * ** *  *     **  * *** * **  n1, n2;
  **  ** * * ********* ****  * *    * *** *  *** i,j;

* * ***  *   *  * ****  **  **  **  * ** * * *** * * *   
*     * **   ***   ** **    **  ** ***** ****     ** * 

* *      **  ** ** ** ** *  * **   * *  ** ** * ** * * **   ****
       {
** * ***  * **   *  * ** *  * * *   ** ** **     * ** *********** *** * *******  *    *   * ** );
  *  ** **  *    ** **   *     * *   * ****      

*  *** * * *** ****    * *  **    * * * * ** *  * * ** * *****
** ***  *       *   *  *** ** **    **  *** 
   *** ** *  * *** ***  *  **** ** * * ****  * * ** ****   ** **   *****   * **** *** ****** * b[i]);
  ****** ***  *  *  *  **  *  ** * *    * *** * *  



* ** **** * * * *  **  *  *  ***  **  **   *** *** *   *** **** * **** 
    **  *  **  * **     * *  * *  ***  *   * **
*   * ****    *   **  *   **  * * *    *  * * **** *   * *  * ** * ** ** * * ******   * *
**  *  **         * *  ***** * ***      
*     **      *     * ***** **  *** ** **  *  *  **** **  ** * ***
*  ** * ** ** * * *****  **** * ***** **   **** * ***
* *****     * ***   *  *  ******   *    ***  ***   *   **  *       * ********* * * * *
*     * ** * **  * ***     ***  ** *      **  **   * 

*** * *  * *   **   **** *** **      *** ***** *  *   *  ** * 
  * **   *      ***  * **   ******** *  **** *  *  
   **   ****  **  * **   * ** * * * **  * * **   **       **** * * ***  * **      * ** **
*  *******       ** *   * **   ** ****     *     *  *** **    *** **** ** * **
       }

***** ** *   * * **  **  * ***  ***  **  ****** *  * ***   **   *
       {
*  **  **  ** *    *   *   *** ****  ** *  ** ****  * * **************** *** * * * ** ** * ***** * 
       }

*   * *******    ****   * *  * *  *     ***   ***  ** **
 *****  * * ** **   *** * * *  * *    * *****   **** *   **  
           ** **   ****** *     * * ***   ***  ** ** ******* *  *      **  *   ******   ** ***  *** *      *  ** * 
** ** * *** ***  * * **  ***    *  ** * **   *  * *


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  *** *
#include  **  **  ** ***  *
#include **    *  ** *  *
int main ()
{
   **  **   * ***** *      *** * i,n,m,c=0;
 *** * * ******* *** *  * A[60]={0};
*  *   * **   * ** * ** **     ***  * ***
 * ****   ******  *    * **    ("%s *  **** *****
*   * *      ***  * ****     *   *****   * ***   *   ** **   * * *   *  * *   
** * *   *   * *  *   * ****  ** 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
*****  **      *   *  ***   ** *     **    **  * *   *** *  ***
    }

*   * ** *  *  * *  ** ***   ******        *****    a);
* * *  *   ***** **  **   ** *****   **  ***  ** b);

    for(;;) {
** ****  * *   *  *** ** *  * ***  **********  *    *      * ***  **** *  {
 ** *   *     *   * *  ** *** *** ***  *  *  * ** * * *   **  *  *   *     * ****
  *  *** *   *** **** ***   *** ** *  ** ***    ***  ***  ******** ***    ****  * *  *
*    ** **  ***    *   *** ** *  *** * **  *** ***** *   * ****  *    * ** *  ** ***    *** 
     **** ** *****   *   *  ** *  ***  ** **** *  *   *
* * *  ***  * **  **  ***** *  ******    * * ** * ** ** *   {
  ***** *  ****   *      * ***  **     ******   * *** *   *** * *      *  *******
** * ** ** *  *  * *  * **  *         *** *    * * *  
    }

    for(;;) {
* * *    ****** **** *   ***   ** **** ******* **  ****  *  * *  * **** ***    {
 *  ** *       *   *   **** *   ****    **  ****  *  ***  **  ***  **  ** **  *   * *
**         *** ** * ****  * * * *   ** ** *****    *        *** * ***      **    *  * ****  
* * *     **     ******* * ***  *  ****  **   ****** * **********  **   **  * * * ** ***    
   **  * * * * *** ****  ***  *  *    ***  ****    *   * *** 
   * * * *** **    * * * ****   ***    * ** ***** *  *     * {
    ** * **   ** ** *** *  * ** * *  **** *  *    ****  **  *****  ** *** **    * * 
 *   ** *  * * * * *  * *     **  ********  **       ** * 
    }

*  * *  *** *  * * **  * **  ** * * **      *  {
*  ** ***  * *  *** * *** ***  ** *   * * *** *  ***   * **  ** *** *  && a[i]<=57) {
* *    * * ***    *** * *  *    **  ***  ** ***  ***    ****   *  * ***   ** **   ** 
   *   **   ** * ** * ****  *      *      ****** 
***   *    * *  **   * *** * * *** *  * *    *     **     && b[i]<=57) {
* ** ** ***** ***  * *  *  **  *     *   **    **  **    **     * ****** * **** * ***  * * 
* *****  *  * ****** **  * *  ** *  **    * ******  *
    }

    for(j=50;j>0;j--) {
**  ** * ***    ****** *    ******* ***** ** ** **  *     **  **   * **   {
*   **  ***** *  * ***      *** *******  ** * ***** *** * ** * *     * *  ********* * *   *
**  * * *** **** ** * *   *   ** **** ****** *** *   *   
 ** * **   **  ** ***  * *   ** **   * ** ** ** *   ***   ***  if(sum[j]+a[j]+b[j]==10) {
* *   * *   ** ****** * ** *   *  * *** * *  ***  *   *******   * *  *   *   * **  ******* ** 
** * * *** * **  ***** *** *  * **** *   *****  *  *** **   *  ***    *****  * *** **    * *    *     **
**   ****  ***** **   * * *    * *  *  *** **   ***      
***  ***** ** *   * * *  **  *  **** ***  **  *   * if(sum[j]+a[j]+b[j]>10) {
     * ** ***** ** *  ** * * *** *  ** **  ** **** ******* ***    *** ** *  * ***   *****  ** ** ********  
*  * * *   ****    *** **   **** ** ** *              *  **  **   *  ***  *  *  * **** 
**** * * *** *  **** * ** * **   * *** **  * *  
    }

    for(j=0;j<50;j++) {
 ** **   * * *  ***  * **  * * ** ** *  ***   *****  **  * {
****   **** **   ***** ***  **     **   *** *       **  **  *    **  *** * *** *  *    **    *
 **  ** *** **  * ****     * ** * *  ** ***   *** **  ***   
    }

    for(;j<=49;j++) {
   * *  ***  ** * *  *  ***  ***  *  * * * *  **            ** ***   ** *        sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.195
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.4k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.2k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users