Final Exam 3 (20%)

1 like 0 dislike
7.5k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 7.5k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ** * * *   ****
#include ***     * **** 
char a[100],sum[200],space,i;
int main()
{
 *    **** * *  *    * *  ** ** * ** *     

 * * * ** ****  **  ** ***   * *** * *  *****
   **   * **  *   * *   * ****** * * ******  *   **   **** '){space=i;}
        * ***** *  ***    **

 * **  ***** *** ****       **   * *   *  ****
   * * * * ***   *** **  ***** * * *     **   **  *   * ** ** *    ****      * *** ** 
* **  ** **  ****    *   ** *


       **     ** * **  *     0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* **  ***    *   ****
**  ***** *  ****     
* **   * *   ** * 
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
 **    **  ***  * * * ***  ** num1[51],num2[51];
*  **    ****  * ****  **  *  i,m;
* *** *   * ** * ***** ****  * arr[51]={0};
* ** **  **  *** * *** * ** *** 
* * **     **** ** *** **    *    **  %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
*  ***  ***  *   * **       *** * ****  *  *  *  * *   * *  * **            *
    }
  ** *  *   *** **  ***  * (i=0;i<(strlen(num2));i++)
 *  ** ** **  **  * **   ****
 * ** * * *  *** *   * ***  ** ****     * * ** *   * *  *  **      **  *     *  *  ***
  **     * *** *  ***  
    * ** **  **** * **  ** (i=0;i<=50;i++)
    *   *** ** * * ****    *   * 
* ** ** ***  ** * *  * *     * ****** ** * ***** ***  ********* 
*****   ** **   ****    *  *** ** *** * ** **   ***
** **  * * ***    * ** *  ** ** *     **     ****     ** ****** * *******   * ******   *
  **    **  *  ** * * ** **** * * *** * * *  *  * *  ** *  ** * * *** *  * ***  *   **   *  ** 
** **** **   *  ***     *** *     **** *  * * **   * *** 
    }
***  * *   ***    *** ***** * * * **  
    {
  * * ** *** * *  *    **  *   *  ******* ****** ** * ****   *
*   *  * **  *  *   * ** **** *   * **** * *     *
 * ****** **** *   ********  *    * ****  * * *  ***** ** * **   * ***   **  ***   *** *   *  ****   
 *   * **  *** * *     *  ** **  ***  ***         *  *
*** * ***   * * ****** *     **  *  ***  * *  **  *  *** *   ******* 
* *  ***   * *** *** ***  ********     *  ** ** **** 
** *** ** * * *****  * * ****** ***  *  *** ** *** *  **  *  *   *** *** ***** *** * 
**   * *** * *    * **  *** *   *  *  ** * *   ** *   ***** *   *       * ***  **  **** ***  * ** * 
*     * *** *   *    *  *** ***    * *     ****   * * 
    }
**  ****     ******  *   *    * 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
  * ** **      *  *  * **    *  a[n],b[n];
 **  ** *  *** *     ** **** **    * **   ***   **    
  **** *** *  **     ***  *  l1,l2;
  **  ****   ***     * ** * *    i=0;
* ***** * ***  * ****  *   ***  * *
** * **** * ** *  *   *   ***** ** *
 *  ****  * *******  **  ***** ** ** *** *  * 
 ** ***  ****** ** *** **    *    ** *** ***   
 **    **  ** *  ** *  **   * **** **   * *  ** **  **  



*  ** * ** *   * **  *   *     **** ** *** **  **       *     ** * *** * **** *   *********  ***  * *  * *  * **   * *** 





***   *   ** **     ** ***** ***   *    * **     **** * *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
*  ** ***  ****  * *     **  * a[50];

   ** *  ***    ***    *  ***** ** b[50];

  **** * ** **  ** *  ** ****** * c[51] = {0};

*  * ***  ***   *    ** ** *   *  **** ** ** *  *** a, b);

       *        * * *   * * ** *   i = 0;

  ***** *  * *   *****    **  * len_a = strlen(a);

 ******** ** ****** * ** *  ***  len_b = strlen(b);

* *  **  *    * **        **** = 0; i < len_a; i++)
**  **   *** * ** *** *     
**  **  ***  * * * *** *  **  * * *    **    ** ****   = a[len_a - i - 1] - '0';
*** * * *    * * ** **** ** *
* *** * *  **    **  **** *   ***** = 0; i < len_b; i++)
* ** * **** **** * ***   ***** *
*     **  **** * *** **       *   *  *   ***  **    ***   += b[len_b - i - 1] - '0';
*****     * * *  *** *  ***

  **** ****  *    **        *** = 0; i < 51; i++)
  **  ** *********** *      *
* ********  * ***  *** *******  ** ******  *  * *   **   ** > 9)
  * ** **    **   *   * ***  **  **** *  **  * * 
  *  ** *   **  *  * * *** ** ** ***  *  * **   **  ******* * *  *   ** ****   **  + 1]++;

 * ** *** * ******   * *   ** *** *  *****    *****  ** *** * *******    * *  *  %= 10;
* ** **  ** **   ******* * ** ** *  *** ***** * * *     *
 ****  * * ***    *** **    

*** ** *   * **  * * *** **    nonzero = 0;

  * **  *    ****  *  **  = 50; i > -1; i--)
  * * *******   ** * *** ** 
 ** **** * *  * *** * *** ** ***  **    *  **  **        *  != 0)
*** *   *    ** ** *  ***** *  **   ** *  *** * *    ** * 
*  ** **** *  ***     * *  *   **   **    * *   *  * ** * *    **   ** ** **  **    *   ** ** = i;

**** ** *    * *  * ** * * * * *      **   *   *  ** *  *** ** ***   *  *  ***** * *  **
***   *  **    *    *** * *** *   *     * *  **
    }

*  **** ***    *** * ** * *     = nonzero; i > -1; i--)
*     *  **   ***   **  **** **
* ****** *  **   * *   *** * *** **      *  *** *** *     ****  * *** ***   c[i]);
  ** *** *  *  ****  * **   
*   * **  * ** **   *  *   *  *  *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

  *    * * ** *   **     ** ** *    **  * *** *** *** *   *  * *  **  ****  * *** 
    for(i=0;i<strlen(a);i++)
*    * ***     **  ** *  *   *  **   ***    *  *  *  
 ** ****  **  ***** ** * **    *** *   *** *  * ***   * ** ***  ****  *  *  ** *         
  *  *  *   *     ***      * *  * ******* * ******
    for(i=0;i<strlen(b);i++)
* ***** **  *  *  * * *     *  ***   ** ** *  **** * * 
 *  ** *   *  **    * ***  **** **  **  ** **** *   ****  *    **** *  *** *  * * *  *  
   **  *  ***  *   *    **  ******* ***** ***  **   *
    for(i=0;i<50;i++)
***   ** *     *    * ****** ** *   ***  *    ** ***  
   * ****  *** *  *  ** *   **             * *  *  * * ** **  *** * ** ** ***     *  > 9)
 *   * *  ** ** **     *  * **   *   *   ******   *** *  *****       *** * * * **  *   *** *  *  *   **  **** 
*     ********   * ** ***         *  * ** *******  ** * ** * *  *  ***** * ** ******   ** ** * * * ****** * ** ********  **  *   * * ***
*  *  ****  ** ** **   *     ******** *   *  *** ***  ** ****    * ***    ********   * **   ** *     * *** **  * * ** ** *  *** *** *  
* *  **  *  ***  **   *      ***  *** **    *** ** * *** * * * *   * *  * * * * ****** ** ***     ****  *  
   **     *   * * * ** * *    ** *  **    ** ******  * *
    for(e=51;e>0;e--)
       ** ** ***    * * *    ** * *  *  *     *****      
*   *    **  ***    *  * **   ****   ******     *  * ******   **** * * ***** *** *   *  * != 0)
* **   ** *  *  * *   *** ****  *** ** * **  *****       ***   **    **    **  **     * **   * *     * **   
 *      **  * * **** * * *  **       * ***** *** ***    *********   **  *  *  * ****** *   **** *   **   * ********* ****     *** *  * * *** 
**** * ** * *** ** *   *   **  * * ***** **  *  * *  * ***   *  *  *** *******   *  * *   ***** * *   ******* * ** *****  **  
  *  *  ** * *  **** ** ***      * *   **** *  ** ******   ****   **** *  *****   ***    **   *  * **   *  **** 
  * ** *******            **    * **** *****  *  ****** 
*  *        *****  ***  * * * ***    ** **     **    * ** *  **     ****** *   
    for(i=begin;i>=0;i--)
  *** ***   **    **  **   *   *   * *  *** **** 
** **  *******   ** **   * *  ***    *  **   *   ** ***  * ***   ** ****** *** ***   * *** * * 
        *      * *****  * *  **   ***   **   ****  
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*   ** *          *   *       i,j,k,l;
   * ** * **  *    *   ***  **    a[100];
  ***   *****  ** **   *  * * b[100];
 ** *** **** ** * ***     ** ** **      * ** ***  ** *
  **** ******  *   *   **   * *   *     * * * **  *** &&  *    *   ** *   * * *
* ****     ** ** *  * * *** 
  *  * *      **     * * *   * *** **  ** ***    * *** * * *  * * *  ***  * ****  ** ***** **
*** *** *   **** *  *   ** ** *
 ****   * ** *    * ** *****  0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
* *  *  *  ***   ** *   *****   ****  ***   ***** a[50],b[50];
  ***         **  ** * ** ** **** *  ***  **      * ** c[51];
     **  * ** *  ***  **     **    **   ** ***  **** n1, n2;
****     *  ** * * *  * ** *   *   **** *  *****  i,j;

  *     **** * ****   * * *   * **  *  *  **    * ****
 ** *  ***   *   ******   * * *   * *  * ** *  ***** **

**  *     * *     * **   *         **   *   **    ** **  *  ***** * * 
       {
* * *           *    *** ***     *******  *   *** ****   * *** **  **    * * *** ***       * ***  ** );
 * * **** * ****** **  ** * *    *** ******  * *   *

 * * * ***    *  ***** * * * ****  **    * ****   * ***   * * *   *** 
* ****  ** ** **** * *   *    *  * **   * **  **
 *** ** *** *    *** *  *   *** * *  * *** ** **  *****  *   *   *  ** *  ***  ** ** *  *   * * ** ** * b[i]);
 *** ***    *  *  ** *  ***  **      ***       *** *



   ***  *  ** ** *  *  **    ** *  **   *  *      *      *    * * 
 * * * * * *  *     ***   *   ** **   * ***  *** 
*  **** * ********  *** * *    *     **    ** *** * * * ****  **  *** ** * *  **   
*    *  *  *****   **  ****  * *    *  *** * ***
** ** *  *      * *  ***      ****    * * * *    ***** ***** ******   * *
 ***    * * * **  *****  * *** * **     **   ** 
  *  ** * *  **   **** **  **   ** * ** **  ** *  * *  * **  * * * *** *  * *** * 
***    * ****  ***** *    **  * * *  * ** * *   *****   

* * *   **** ***** *  *   *** *  * **  *   **  ***** **
*** ** ******   * **  *  * * ****** **   * * *** 
   *    *** * ** **       *    * *** * ** *   * * ***  * *** *  *  *    * ****   
  *  ***    * ** * *   *    **   ** *       * ** *   * ******     *   ****  * *  *******
       }

****  **** * *     *  **      **    **   *  *  *  ***    ** *  
       {
  *** *   *   * *   *   *   * **  *  * **  *  ** ** * ***  *  ***** ***  * *  ***     ** *   ***  
       }

  *  *   * * * ******   *****    *  ** *   **   * *
  *  ***** * **** * ****  *  *    *  *   * ******** * 
***  ** ****   *   ** ***  *  *   *** *** * ****** * **    * *     * *** **        * * **  * * *** *
 *  *   * **  *******  * ** **   *  ***    *     *  * **  *   


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * *        
#include   * **    *  * *   
#include  * ** 
int main ()
{
  *   **     * ***   ***  *****  i,n,m,c=0;
* *      ** ***         A[60]={0};
   ***  *  * ** *** * *  *     *** *****   
* *     *  *    **  **    ** ("%s ****  * ****
*  *****  ** *  ****   *** ***      ** * *  **    * ***    * **   
* *****  * *******    ****  * * ** 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
** ** ** ** *  ** **   **   **   *** * ******  ** **  ** *  *  *** * 
    }

** **** **   *******    ** * ***    * ****** ** a);
* ****    * ** * * * ***   ** ** * * ** *****  b);

    for(;;) {
 * *     *  *  **  ***   *** ** ** **  **   *  **** **     *   * * **    ** {
  * ** **  ** * * **   * *   ***** * * ***** *  *  * * *      ***   * *    * ** *  **   
 *  * **  ****     * *  ****   **  *  * ** **     * ***    * * ** * *  *** ** ** ** * * ** * **
 * *  *    * *   *  * ***  *  * * **   ** * **  **    ***** * * ****   * **** **   * 
  ***   *  * * * * * **  *** *   *   **  *  *   * * *
***** **   ****   ** * *  ** ****     * * ** ***  * * ** **   * {
   * *  *  *    ***  * *  **  ** ******* *        *   ** *  *   ** *** * *** *  *    *
*  ** *   *  *      * *** * *    *  *** *   *   *** 
    }

    for(;;) {
* ** * *** **  *  *         **     **    * *    ** ******     ******** *  {
* ** ** **  * * *  * *** ***   ** * * ** * *   *  ***   * **   * **  **  * *  *   * ** ***
*  *  ** * * * * **  **  *      * * *** *  *   * *****    **     *       * *   **   *** 
    *   *      ** * **  *    *  **** * *      * ** * *  **  *     **     * *  * *    *
 **   ***     *  ** **** *** *  *** **** *** ** ** *  ***
  **  *    ** ** *** *  * *** *** **** ****** * ******* ** {
  * * ****   ***  * * ***  * * * ***** *   ***** * * *     * * ** ****  ** * ** **
**  ** *    * **** *** * *        *  * * **   ***    * *
    }

 * * * *  *  * ************ *** *        {
* *  **   *  * * **  **** *   *  *  *   *** *   **  *** ***  * * *    && a[i]<=57) {
** **  *   ***  *** * ** ** * *   ***** *** **  *  ** * ***    ******   *  ** * *  **  
  ** ***   **** *   ** * * *  * ***    ** *** *  * * ***
** * *   **   ****  ***** *  ** ****** *  ***     *   ** ***   ***  * && b[i]<=57) {
*** ** * *  ** **  * *  *** * * * **    * *    ** ** * * * *   *  * **  * **  * ** 
  * **** *  ** * * ***    ***  **   * *  ** ****  *      ******
    }

    for(j=50;j>0;j--) {
****** *     *   ** **  * *** **  ***** *   * **  ** **  *** *    * {
     *****    **   *** ** *******     ** ***   * ****  ** * * ** *  *      ***  **** *** *      
*****    **********  * *** ***      **  * *** *  *****
           * **** * **      **  *  ***** * **  *   **** **** if(sum[j]+a[j]+b[j]==10) {
**       ** * *  * *** ** * *   *  *     ***** ** * * ******** * *  ***** *** *   
  *  ****  **** * ********** **    * *   *    ********  *  *     ** ****  **** *** * * * ***
*** *   *  ***** ***   *  ***    * **   **  ** **   * 
* * * ***     ** **  ****  ***  * **  *   * *    * * ***** * * * if(sum[j]+a[j]+b[j]>10) {
***    *  * *  *** *** * *   ***  ****** **  ** **       *  ****  ** ** ** ***  * * * *  *   **  * * ***
   **   * *** *** * *  **  *   *** ** * *    *  * *** ***  *      **** * * *  *** *   **  
 *  *****    *  * ** *** *** ** **     *** ***  * * * * *    ** 
    }

    for(j=0;j<50;j++) {
*    ** * *   ** *** *        **  **** *  ***  *    *  * {
**  * **  **** ** ** *  ** **  ***        * ***   *  * *  * *****  *  * *** **   *   *
 **     *     *  * ** ***** *  ***** * **** *   **   * 
    }

    for(;j<=49;j++) {
 *  *  * **    * ** ***   ***  **     *   ******* *** **  *  *  *  * ** sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.135
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.4k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.2k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users