Final Exam 3 (20%)

1 like 0 dislike
13.5k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 13.5k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * ***    *******
#include **  ** **     
char a[100],sum[200],space,i;
int main()
{
**   ***  ******* ** * **  *  * * **    **

*   *  ***  ***  ** **** *** ***  ***  ** *****
 * *      * * * **    ** *  * *   *   * *  *   **  ** * * '){space=i;}
*  * **** *  *    *  ** * 

*********        * *  **** * * * ***** *   * **
  *** *  ***** **      **   *    *  * * **   *  * *  ****   ***  **** * ***  *  *
  ** ** * ***    * ** 


*** *   *   *  *    ****   0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   **  *** *  
 ** * ****   * ** *  *   **
 *      **  ** * * 
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
*  ***  **     * * *       * num1[51],num2[51];
  * ****** ****  ***      i,m;
*  **  **   *** * **   ***  arr[51]={0};
  ** ** ** ** **   *****  ** *
 * ***    **    *  ****** ***  *   *** %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
 * * ****** * * *  ** *   *   **  ***  *  **  **   ***  * ** * ** ** *****  *  ** 
    }
*  ** *** * ****   **  *     (i=0;i<(strlen(num2));i++)
***   *   *   *  **   * *  
  ***   *  *  *  * *  ***  ***     ****           ** *** **  *  *  ***  * ** * *
***  *  *   ***   *   *   
****  *****  **  * *    ** (i=0;i<=50;i++)
 * * * *** * **   * * *   * *
 **  *  * *   ** * ****  * **  *  ***** *  **  *  *   *** *    
  **       **** **  * * *   ** * *  *   *  **  *   * 
* * ** *** * *     *** ** ***** *   *** * ********  ** ******  *  **    **      *** **   *
**   ***     *  **    *  * ***   *** ** * * **         ** *     ** **       * * *** ** *
**     * *  *  **  **   ****  *** ** *  *  *  *    * * *  *
    }
** *   ** ** ** * * **   *   ********  * *** *
    {
*** **    ** **** * ** * * **** *  **  ********  ** **     **
 *  ** **** **   *******  *     ** ** *  *  * **  ****** * * ** 
    **  ** * *       **   **  * * * ****** ***   *****  *     *****  ** * *  ** 
***  *****  *** ** * *  ******   ***  *** *** *** **
***  ** * **   ** * *   *  *** ******  ***** * ** * *  **  * **** *****
 **      ** **    * * *      ***** *       ***  * *  ** **  *
****  * *** **** **  ***   ** *   **    ***  * * ***** ** ** ***    *    * ** *       **** ***
**** * *  ***  *  *** * ****  *      ** * ***        **  **   **   ********** ******* * **  * ***  *  *** 
 **   ***   ** **** ****   * *   * *** **    * **  *  ****** *
    }
  *  * * * ****** * ***   ***  *  0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
* *  * *   * * ****  *****     **    a[n],b[n];
*  * *** ***** *  **       *  * **  *  * **** *    * * 
***** ** * ***  *** **  ** * l1,l2;
   *    *** **  * *   * **    i=0;
**  ****  ****    *** *  * **    **  *
 **  *   **   *  *  **  **      *
 * ****    **  ****  **       *   **** ** *** *    *
* ***   ** * *    *   *** * *** *  *** ** *   **  
*  *  * ** *  **  ** ***  *  *  *   *  ** *   **   * *  *  *



**   **  * * * **** ** * *     *    *  ** ***  *   * **    ** *****  ***  *  **** ******  ** * *       *** ****   * *  * *





 *   **      **  * **     ***   **** *  * *** *      ***



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
* **  ****     ** ** * *  ** a[50];

     * **  **  *** ***   * **** b[50];

 * * ***  *     *   * c[51] = {0};

 * ** ****  *  *   * * ** ***       **** **       a, b);

  * ***** **  **  **** *** **  i = 0;

  **     ** ** *** *** *  * len_a = strlen(a);

  * ** ** ***       ******  *  len_b = strlen(b);

  * *** ** * *  **  *  * *  * ****  = 0; i < len_a; i++)
*  ****  *** *   *   *  ** 
   * * ** ** * * ** *** **   * *** *       ********* *** = a[len_a - i - 1] - '0';
   **  * * *  **   **
  *  * ** **      **** * * **   = 0; i < len_b; i++)
    **  ***   * ****   *    *  
*     ** * ** ****    *  *  *   * *    *     **  * ** += b[len_b - i - 1] - '0';
 ***  ** **   ** * ** **   * *

** * * * **  ****  **  *** ** ** = 0; i < 51; i++)
**    ***      ** *   ** *
  *     * ***    * * **    ** * *      ** * **  *  *  ******  * ** > 9)
 ***   *    **  **   ** * *  * * *   * *  *  * * **   
  * *      *** **    ***    ***    ** *  * ** **   * *** ** *   ****   * ***    * *  * ** + 1]++;

** * ***       *  *  **      ** *   * ******  *     * * *  *   * **** ** * * **  **   * **  *  %= 10;
   *       *** **   * *** **  *   * *    ** * * *   ** * *   
* ** **** **  *     *   *****

* *****   * ****  *  nonzero = 0;

 **      *****  * ** *   *  ** *** = 50; i > -1; i--)
*  * * * *  * *   ** **   *
****  * **  **  ** *** * * *** *   **** *    ** * *** *** != 0)
** *    *   *  *   *   ******  * ***  ** **   ****   
   *      *   **  *   *** * *  ** *   * *    *     *****  ***   * *    ****   *** *  = i;

 *  *   *    * * **** *******  ***  * ** *** *****  *  ** * ****   * ** * * **    ** **
 * *   **** * ***** *** ** ******   *****  **  *   ***
    }

  *  *    *    **  *    **  ***  = nonzero; i > -1; i--)
    **  * ** *  **** * *** *    *
 ***  *   *****  * * ** * ** * *** *  *  * *  ***  * ***       ***** * * * c[i]);
** * * **  ***  * *** *****  **** 
  *   **   *   *** **  ***    0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

***  ** *  *   ****  *  * *****  ** * * *** * *     **  *   ***   ** ** * 
    for(i=0;i<strlen(a);i++)
***     * * ** **    ** ***    * * * ** ** * ***** **
      *** ****** * *  **  * * ***    * *    **  * * **** *     *** **  ***  *  *    **  ** *****  
  * * ***** *  **** *   * **** *  ** **      * *   
    for(i=0;i<strlen(b);i++)
* *   * * * * ** *  *  ****      *** * *    ** * *      
**   * ** ** * ** *  ** *   *** *  * **  * *   * * * *      ** * * ** *** **  ***  **** *
* ****  ****  *  *** * *  *  *  ***      **   * * * * ***
    for(i=0;i<50;i++)
   ***   * *    **   *  *****     * * * * * **  *   
****** ***** *  *  * * ***   *** * *  *** * *  *   ** * *** ***    ** **** ***    *** > 9)
 * ****   * * * ** ** *** * * ****  *    *** ********     * **   *   *** ** * *    * * * *       * ***       *      
   *****  * *** ** * *  **   ** ***** *** * *  * **    * **      * **  * *  *** **   **   *  **** *** ** *  ***  *   * * *  ****  *** *** *
***   ** *  ** ***** * ****  ***    ***** ***   *  *    * ** ***  **  ****** *  * *     * * * * * *  *** * *  ****   * *****  *****   *  * ***** 
** *     *  ***  **  **** * **  **  *  *    ***   *     ** *  ******* * * * **  * ** ***   *     *** *
 ** **  ** *  *     *  *      *** * *   ** **  ***      
    for(e=51;e>0;e--)
** * *    *** * * ***  *  *   *** * * **  ***  **** * * * 
  *  *    ** * *** *    ** *** *  *     **   * *   * *  **    * * * * *    * * * * **  **  *  != 0)
 * *    ****  *  ** ***  **    **  *     * ****** *  *   ***** *** **   ** *  * * **  *   ** *** ** 
 ***** ** * *******  **  ** * ** * ***  *  ** * *  ****    *     *******   *    *  * ** **** * ** *    *   *****    ** * *** * ***  
    **   *** ***** ** * * **   * ** *  *  ** **    *** *     ***      **  * ********** ** *   ****   * *  *     **   *  **    ** ** * 
    * **        ***   *   ** ** *  ***    *******   *****  *  **** *   *  ** **  *  * * *   *** **  * * 
** ** **   * **     **** ** * *    **** **       * *  *  *
* *  **  **  *   *  * *** ****** **    * * *  * *  *    * * * *   * **  *  *   * ** *** 
    for(i=begin;i>=0;i--)
* *   **   * ** *  **   ** ** ***  ** *  ****  *    * ** 
  **** ** **  **  **** **   *  ** ***** ** ** *  * **** *   **  *  ***  ** * ** ** **  *** ** **   * * *  
   * * * *  ** * *     *  * * *** * ** *     * *   *  **** 
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ***  ********    * ** *   **  i,j,k,l;
****** ** **  **** ***    **  a[100];
  **  *** * ***    ***   b[100];
***   *  * * * *  * *  ** *   *  *   ** ** ** * * **
****     *  **  *   *      **   *  * * **    *******    &&   ****        **   **
***  ** *   **** *   * * ** *
*  ******  **  *  *** * ****    * ****  *  **  **  ** *** ***    *   **   * *  ***    * ***    *
*   *       **  ***** **   * *
* *  **  *   *   **   *  *** **  0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
** * ** * ** **  **    *** * * *** **** ** **  **  ****** a[50],b[50];
* * *      ** * **  *      *   *   *** *      **  *  ** c[51];
*  *  *** * *   * *  *   *** * ** ****  **  * *** * n1, n2;
 **  * ******     *****   * *****       ***   ** i,j;

*  * *    ** **     **  ** * *** * **** ** *** * ** *    ** ***
********* ***  *  * ****   * * **  *    * ***  **  * 

**********  ***  ***** ** ***    ********* **  ** ***  **
       {
*** *  * *    *  * *******   * ****  ***  **  * **  *       *   **** * *   *   * **   * * ******* );
 * ***** *** *  ***   ***** *   ***  *  *  ****   

*    *  * *   * *  ***   ** **   ***   ******** * *   * * ** * * *  * 
  *  *** *** *  **  *  ** * * *  ** **** ** * * * 
 ** *** *****     ** **    * *   *** *     **  **      *  *  ******   ***   ** **   *    b[i]);
  ***********  ***  *** *  * ***** * *   * ** *



    **  *****   ** ***  ***** **  ** *  **  ***    *** *       *   *** *
**   * **  *****    *    ** * * **  *************
 * ***   ***   * **  * ** **** * * ** *   **  * **    *  *****      **  ** ****  
       * * * ** * *  *  **     *   ****** *      
* *  ** * **   * *  *  *  ***  *   **     *  *  ** ***  **  * 
 **** * * *   * **    ****   *   *   ** *  ** ** *
*  * ** * *     * **   * *  *  ***   **  **** ** ****    *** **  *   * *  ** 
  ****    *  ** *  **  *     * *   *  ** ** *   *   ** * 

*  *  *** *     *** ***  *  * * ** *    *****  * ****
  * * **   **** *  ****   *** * * *      * **
* *  **    * * ********  ****       ***   *   *    ***   **** **  ***** **    **** * **  ****
       * *   *** ****** * ***  ***   *     * *   *** ** ****     *     ** * 
       }

  ** * *     ***    * **  * ****** *** *  * ** *   *   ***  *     
       {
********** *** ** * **** ** **     ***  ** *  **** **   * ** *   *  ***** *   **  *** * *  **  *  * 
       }

**** **** ****    *     * * * * ****   ** ***    *    
* *  * ***  * **  * * *  *  * ***   **** *  *    *
**  *   *   *   ** *  *  ****** *** **     *****   * * **  *** **   ** * * * ****     *  * ** * *   
 ****   * **  *** *** *     **** *  **** ********


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** * * **  
#include *   ** *** *
#include * ***  * * * *  
int main ()
{
 **** * ** * * *   * ***  **  i,n,m,c=0;
**** *   * * ** *  ** **  * A[60]={0};
  *   * **** ****** **      *   * *  *** * 
*  ****** * ***         **       ("%s * *  * * *  
*  ** **** * * **  ** **  ***     *  * **    *** * * **  *** ***  *** 
* **  * ***  * **  ** ********* 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
* * * *  ** ***   ** ******   *** * **          **  ** *  *  *
    }

* ***  **  **** **   ***    **   **** **  *  a);
 * ** ***   ***** ** *      ***    * ****  b);

    for(;;) {
 * * ** * * *        *  ***** * **  **  * *    *  *      * *** **** *   ** {
*** *** **  **      **** ** ** **  ** *  *    ***   * *    **  *      *  ** *     
  * ** ** * ***   * ** ***    *****  **     ****   **        *  * ******  **   ** *  *   **** ***
 *  *   **      * ** * *        * *  **  ***  *    **   ***** ** *   *       * *  * *** *
* * *  ** *** *  ****  *** *   **           *      **   * 
  *      * **  *  ***** *  *  * *** * * *** * * *** *   *****   {
  * ** **   *******  *  ***** ** **  ***  ***  ** **    *  *  * *  *  *  * *   *   *** ** **
 ** ** ** * *   *  ****   * ** * *  ****  ** *  * ***  **  
    }

    for(;;) {
 ****  ** *** * ***   *  * * ** **  * *  * *   *  * *****  *  * * **    {
*    ** ********  **  *   *  *  **    ******   ***  *   * **   ** * *  ** **  
  * * *     **  *  ***  ********  * *** **   *   ******   *  ** * *** *** **     *  * *****   ***  
  ***     * **   **  ***  ** **  *  **   **  * ***    * *** *  * *** * * ***  ** *  ***** *
   *  **** ******  * *      *   *    **    * * *    * **    *   
* *    **   *** *  * ** **  *** *     *  *  ***** *****  *  {
  *  *  *   **  ***  * * * **   * **   ***    ******* *** *   **  *  *     
  ***       *   * **  *  ******   *  **** *      *** *  
    }

* * **** * *  *     * * * ****  ** ** {
**  *  ** *    ** * *    *   ***    * *  ** * *     *     ***  && a[i]<=57) {
 *     ****   * **  * **** **  **  *****      * *   * *  * *   *     * *** ** * * **  ** *** 
* * **     * ****     ** ** *  ** * **  * *** *     *  * *
  *** * * ***   *  **  *** ** * ** ** **  *** * ***  **** * && b[i]<=57) {
*   **  **   ***  ** *  * *** **        ****  *  *  **    *   *   * * * * * * **      
** ***  ****  ** * *  ** ** ** * * *** *** * *  ***   **    
    }

    for(j=50;j>0;j--) {
***** ***     * * ** * **** **** ** *   *** *  ****    * ** * ***    *     {
 * ***** * *** * ** ** *****  ***   *  ***   *  *  ** *  * ***  *  *  *    **  ***** 
 **** *    **  *   *** **      *      *** **  * * ****  *
 * **    **  * **   * * ****  *   * * ********  ** *  *       ** if(sum[j]+a[j]+b[j]==10) {
 ***  *  **  *** *   *  **    * *** ** *** ** *  *** *  *    ** *****    *   * *  ** **
*** *         ****  **     * **** * * *   *****  * *** *     ***  ** * * * ***   *** *    * * *
*          ** ***  *** * *  **      *    * * **   
**  ** ****  * * * *   * **  **  ** *** ***  ***    *** if(sum[j]+a[j]+b[j]>10) {
 ** *    ** *  ** **  **   **   ****   ****  **    *  ** *  *      ** * ** **  * *   *
  ***** ***  ***  *** *     **    ***    * *** **   *** ****  *******   *** ** * *  
*** * * **   * *  * * *** *****   ** ***  * *   * * *  * 
    }

    for(j=0;j<50;j++) {
** **     ** * * * *  ** ****   ** * * *** * *** ** **    * *   * * ***  {
      ** *     **   *  ****  * * *****  * ******  * ***** **      *** * **  *   *
    ****   *       *    *    *   *******  *  *   *
    }

    for(;j<=49;j++) {
***    * **   *  **  * **          * *****  **  *** ******* ***** * ** *** ** sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.164
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.6k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.6k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.1k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.3k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users