Final Exam 3 (20%)

1 like 0 dislike
8.4k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 8.4k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include         ** *** * *
#include *  * ** * * * *******
char a[100],sum[200],space,i;
int main()
{
  *** *  ** *  * **  * *  ***  *  ** ******

** * *** ****  ******* *  *  **   *  *  * *  * **
   ****  * *   *  **     ** *   * **   ***      *    * * **   ***  '){space=i;}
******  ***  **** * * *********

   * **    ***  **  *** * * *  * * * **  *
  * **    *  **** ** ****  *   * * *  *** **    * * *    **** ****** * **  *  **
 ******     ** *  * **   *  *


* ** * ***  ***** *  ***  *   0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  ** *  * * ****  
 *  *** * * ****   **
  *  *** * *** **  *   * *
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
 *** *  *  *** *  * **  *   num1[51],num2[51];
 *     ****  ******    **** i,m;
*     ** ***** *  *    *   *   arr[51]={0};
  ****   *  *     **     ****  
*** **     * * *******   **   **   * %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
 **** ** * **    ** ***** * * *******   *  * *   ** *  ** *   * *  *  **** ** * **  
    }
  **   **  ***  **** **** ** (i=0;i<(strlen(num2));i++)
   **  *    * * *  *  **   
 *** *   ***  ** *  ** ****  ***   * * *** ** **  *  **   *    ** *      *
* ***** ***   *     *  **  
******* *   * *********     * ***  * (i=0;i<=50;i++)
  ** **   ***  **  * ** **  
** * *** **  * **    *  * *     ** *  * ** ** * *   ******* **  *** * 
* * ****        *    **  *   * * * ** *  *  * 
   * *** * **  * *** ** *  **  * *  ** ** ** *  ******** *** ** *  * ****   **   * *  * *** *
  ***  *    *  ** * **    ** **** * * *     *    **    *  * ***  ** ****** *  ***    *  *****
  **  **** ***** **   * ***  *  **    **  *      *    *
    }
 *      * *   * **   **   **   * * ****
    {
** * *     *  ****** *** * *   *     *****  ** *   **  *   *  ** 
**** * *  * **  **** ** *   ** *   *  * **
  **        * *  ***** ***  *** *       **  * *** * * *** * * *****  ** *    **  *  **  
**** *  *  ** *   *** *  ** * ** * * ***  * * * *** *
*  *** ***   **  * *   ***  **  *  * * ** ** ** **** *   ** *** ** 
** * ** **  * *      * ***  **** **  * * ** * *   **  
   * *************     ** * * *** *** *  * ******* * * ********** * ****** *  *  ***   
*** *** **      **  ****  ****      **   ****  *   * * ** ** **  ** **      *** * ** **** *  *  * ***** ****
 ** *  *   *  ***  *    ***   ** *   *  * *****   *  *  ** 
    }
 *    ***** *** ***  *   ***  *** 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
  *    ***** ** * *    * ** a[n],b[n];
   * * **     * * ** *  **  **  ** *  * **    ** * * 
** *   * *  * * *** ***  **   l1,l2;
 * ** *       *   **** i=0;
  **  ***  *  *      * *  **  *    *  * * 
****** ***   * *   **   * * ** 
     * * ** ****  *     **  **  * * ** * * * *
**  * **** **** *   *   * ********* * ** **  *  *
     **     ***     **   * * ***       **     ***   



****   * **** *   ***** *****   ****     * *  ***   *  * ** ** ****** ***  * *     ** *      ** ***** *   ****  *    * ***** **





 *  * * * * ** * * *           **** * *  ****** * *   



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
   * **   ***     * * ** **    a[50];

 **   *  * * ****       * **  b[50];

*  * *   * * ****      * *  *** c[51] = {0};

 *  ***  * * *  ***** * *    ***  *****    *****  * a, b);

**     * *  * *** *** * * i = 0;

 *** ***  **   ** ***  * ******  len_a = strlen(a);

 **  ** *   ****   *   ***  ** * len_b = strlen(b);

**   ** * *           *   **   * = 0; i < len_a; i++)
**    *  **** *    *** *   
***   ****  *    * ***    *  **** *   *   * *   ****  *  * = a[len_a - i - 1] - '0';
 ** * * *    **  ** ***** ***
         **       **** * = 0; i < len_b; i++)
 *      * * ** ****  * * *   * 
*****   * * ** ******  *   * ** *** * *  *    ** *  ** * += b[len_b - i - 1] - '0';
     * **     *  *******  * 

** *   * *  *  *    **   * **   *   = 0; i < 51; i++)
*  ** ***  *  * *** **  *** 
***  *   *** * ** *    *      ***  *   * ** ** ***** * *  ** > 9)
  * **  ***  ** ***  * ***  ***   *** * * *  ** *   
 ***      *** **    * *****  **   * *      * * ** *   *  *  **  *** ***  **    + 1]++;

*  *   **      *** *** **     *    ****  **   * ** *   ******* ***   *    *   ****  ****    %= 10;
**  ****      **** ***  *  *** *** ** ***   ** *** * *     *
*     ****  ** **  ** *

*   **   * ********  *  *     ** *   nonzero = 0;

** * **  *  **  *  * *    *  ***   = 50; i > -1; i--)
 *  *  *  *     *** *** ***     
 * *   ****** * **  ***** **** *   *     *  **  **  *   != 0)
** * *   *  * * **  *  **** *******  *     **  * *****   *  
* ***        *** *  **  ** ***  ** ***   ** * *  * * **  *  *  *  *****  * *** *** *  ***** **    = i;

**** ** * ** *  * * ***    * *****    *  *   *   ******** *  **  *** **   ** ** **
******  *  * * * ***  ******  *  * * * **  * * *   **   
    }

* **** ****** *** * ***** * = nonzero; i > -1; i--)
    ****   *  **  * ***
****  **** ***  * *   *        *** *********** * ** **   *  *** *** ****  **   * c[i]);
**   ** *****   **             
****   *   *** * *  ****  **  *  * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

** *  *  **    ****  ** * ***  ** *     * ** ****  ****     * ***  * 
    for(i=0;i<strlen(a);i++)
 *   *    ****    ***** ***** ******  **** ** *  *   **   *
***** ** **   * ** ****  * * * * *  ****  **   *   **   * *  *    ***   * **** *  *    
  ********  ***          * * ****   ***  * ** *   ** *
    for(i=0;i<strlen(b);i++)
***** *  *  *   ***  *    *    *****   **  * ** *** *   **
*  * *  **** * ** ****  *  ***    ** * *   * ** **  *  ****  * ******* ** ********* *   ** * *  ***
* * **** *  *   *** * *     *  *****   ****   *    ** *
    for(i=0;i<50;i++)
* *** * *  ** * *  *** * * ***   ** * ****  *     * 
 **  ** ****     ** **   *     **   *   * ** ************* *  ** **    ** **  *** > 9)
** ****** *  * *  *    ********   * * **     *** ** * **** * *    * *  * * * * ** ** **********  **  *
  *   * * * * *** *   **  * ** *  *  *****  *** **  *** *  **** **** * *  ****  * * **      *  ***  *        **  *      ** ** ****  ****    * * * *
*  ******   *  **** * *   ***    * **** ** ** ****     * * ** * **  ******   *       * **   * ** ** ** ** ** ** * ***   * *   **  *  *  * * 
 *  ***** ** **  **     *    *** * * * *   * **  * *** ** *  ******* *** **    **  ** *   * * ********    
*********  ** * ***   ** ** ***   **   * *  *  **    * *
    for(e=51;e>0;e--)
** *   ****  *****     ***   ** ** ** * ** *  *   *     *
* *******      *** * *** ***** * ** ***  **    *  * * * * * ** * ******  ****     != 0)
  ** **  ****  * ***    * * ***    *** **   *   ** * * *** * * **     ********   ***    **   
* * * *  *     * *  * *  *   *  *   *  ****   ** * *** * * ****  * ***   **   * ***   * ***    *** ***    **  *   ****   *   ***   **   *   
**  *** *** *** *   * ** *   * ***  * ***  ***   * * * ** *** **  *     **  **** * * *** *  *   *    **  *  * ****** *     ***   *  *    
*    *    ***  **    * ** *  ** * * ** * *** * *** **** **** ** * *  *  *    * * **     ** *  *   **    
*   ****  *  * *  ******   *  **   ** *********      *  * * 
*   *  *  ***  * *** ** *    *** ** **   *   *  * *******  *   * * *   *******
    for(i=begin;i>=0;i--)
**   ** **  ****  * * * *****    *** * *   *** * * ** 
*** **  *  *    ****  * ****  * * ** *****   ** * **** *** * *  * *  **     *** * *    * ****** 
 *    **   ******     *** *  * ** ***** * ** *  *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
   *  **** **** **  ** * **  **   i,j,k,l;
* * * *  *    *** * *** * ***   a[100];
*** ** * ********* *  b[100];
*   * **  **  * * * * *  **   *** * * *  *  *  *** * * * 
****  * *  *   *  *     * **  *** ** ** **** *  ******    && **** **     **** ** *
*   * ***** **  ** *   **  
*   * *  *** *  ****  ** * * *  **  * *     *   *  *   *    * * * *  ** * **  *** * ***** * *
   *******  ** ***   ***    *
*****  *  ** ***** *****   * *  0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
*  ***         * *  ** **   * **  * **   *     *   ** a[50],b[50];
 **** *    * * * * * *  **  ***  *** * ** * * c[51];
   * *    ** * **   * * ***** *** ***   * **   *   n1, n2;
 ** * ** **  * * ** *    ** ** * *  * *  *****   ***** * i,j;

 * **    ** *   ** **  **   ** *  * * *  ****  *  ** *      *
* ** * ***** **    **** *   *  ******  *   * *    *

 **** ** * **  **    ** *  * *   *  *  ***   * *** ** *    ***** * 
       {
* **** **  **  **   * *  *     ***    **   *   **  *** *      ** *********  * *****  * **    **** *  *  );
   * * **  ***              **    **    ** *

 ** *** *   **** * ***     * * * *   * *** **   *** **  *  *  ****
*   * * *  * *  **   * *      *** **** ***  ** * 
* *** *****   *    **   ***   ** * ******  ** ** *    *****   * * *  ***  **** ******  *  b[i]);
     ***  *** *    **   *    *     **  **     **



 * **   * * *  ****  *  ** *****            *  *  **  *   ** *  * ***** **
 *  *      **  *  **** ** **   *      ** *  ***
 *** ****  *  * * * *** *  * ***  **  **   *** *****      * * **** *  *  *     **     
  * * *    *   * *  * ****** * * * *  **      *   *  
 **** **** *   *  ****** *  * ****  *  *       *** * *    * ***** * *  
 * *   * *  * ** ** **   **      ** * *  * ** * 
 * *   ** * * *****  * *  *** ** *   * * * *   **   **  *   **   * ***  **  * ****** **
* **   ***   *     **   * ******** *   ** ** ***

 *** *    * **** *     *  **   **  ** *  ***  * ******
* *   * * *     * ***  ***    *** **** **   * ** 
 ****  * ***   *  * ** ***    ** *****   *  ****** **** *** * *** **     ****   *   *
****** ****  ***** *  **          *    *** * ** ** * *   *  *  * * ***    * ** * *** 
       }

 *    *** ** *  ***  ** ****** *  *   *    * *  * *  **     * *
       {
 ** *   **** *  ******  **      * * * *  **  * *** * *  ** * * ******* * * ***  ** ** *
       }

*  * * *   **  * *  **  * * *  *       **  *****   
* ***   * * *    *** *   * * *   * **   * **    ***
 ** **     ****** * *     ** * ******   ***   *  ***  * **  **  *  **  * *  * *    *  ** **      * ***    
 ** **** ****  * * *  * **  * *    ****  * ** 


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * ** *  ** 
#include  *** *        
#include       ** ** 
int main ()
{
*** * **** *    ***     i,n,m,c=0;
** *  * * * ****** *   ****  *** A[60]={0};
*   ** ***     *    *     **   * ***    *   
 ** * * * ****  **   ***   ***  ("%s  * *  ** 
  *  * ** *  ** *  ** *   ***     *  **      * *  ** *******     *
 * * *  ******** *  **   * *  *  0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
* *** * *  ***  * ** ***   ****  *  ***    *  *** **     **
    }

 * *   ***  **    * **     *  **** *  * *   *  *  a);
**    **  *    **  * * **       ** **** ** *   b);

    for(;;) {
 **   *** *** ***    ****  *** *   * ***  ***    * * *  ****   *  * {
  **  ******  *    ******    **   *  *** *** *    * ** ** **   * ** **  *     *  ******
*    **      *    * * *** **   *** ***********     **  ** * * *** *   ** * * *  * *  **** ** **  
 ***    * ******* * *  *  *** *   *   *    **  *** *****    ******      **** *     * 
***** **  *   *  *****  **   * *  ** *** *    *    *  *  **
 ** *   *   *  * **  *** *****   *****  * * *  *     ** {
   **   ** *** *  *  *   * ****** * ***  * *****    *   ******** ***   ** *** * *** **  * 
*** *  ***  ** *    **    *  *   *** ** **    *    *****
    }

    for(;;) {
** * ***********  ***   * *  *  * *   **         * *** * * ** ** * {
**  *  **   **   ***  **  **    *** *** ****** * *  * * ***    * * *  * ** *****  ** * *  *
*  *** *  ****   ***   ** *  *   ****   **** **** *   **  **   ** *  ** * *  ** * 
*  ***   ** **** **** ****   *           **  * *** *   ***   **      * **  **  ** * **
** *      ******* ** **  * **     *** ******** *       *  *  
* ***** * ****  * **** **   *** *  ***  ****      ** *  *  {
 *  ***   *** * ** * *   * ***          * *  * **  ** *    *  **  *   * * *   
* *   *  ** *   ***********    *   ***   *    * 
    }

**  ****  *   *****  **  * **** *  *** {
 ***   * **** **  **  ** **********  *     * ** * ****   **** && a[i]<=57) {
  * * * *  * * ** *    *   *******  *  * * *  ****** **** ****   ****** *** ** ****   *  *****
** *    *   *** **** **** ***** *   * *     *  ****
** **   ** * *  * *******  *** *       *** *  *     * * *       ** && b[i]<=57) {
 *  * * * **  *  * * *  **     * **   * * * *  *  *   * ** * * *  *     *  ** *****  * * ** 
* * * *** *** *** * * *  *  *     *** *** *** **** * **  
    }

    for(j=50;j>0;j--) {
 * * *  * *   * * * *  **** *   ***  *  *****   *  ****   ******* **   ***  *    {
 ** *  *      **  ***  * *   * ** ** *    ******* *  * *   ** **  *  *  ******  **  *   *
   *    ****  *   ******** * * * *** ***    * ** *  ****  ** 
* **** *    * *** *  * **     *    ***      **** *  * ** **** * if(sum[j]+a[j]+b[j]==10) {
 **          * *      *  *       * ***   * *    *  **  *** ** * *    ** *  **  *   * **  * *  ** **
**   ***  * *    * *    ***      *    **   * * *  **  ***** ***   ***  *** *  * * **  ******
*      **   **  ** * **     *** * **   *   *  **  * *
 * * *   * * * *****  *    * ***   * * ***  *** **   **  if(sum[j]+a[j]+b[j]>10) {
*   ** ***  ****   **   **** **    *   ***     *       **** * * *******  ** **   ** *** *********   * ** 
 *** ***  *  *   * *  ***     * *** * *  **   * *  * * ****  ** **   *  * * * **
*  *    ** *  * ** **   ***   *    **           *
    }

    for(j=0;j<50;j++) {
    ***  ** *** *  *** * *** *   * *   * * ** ***** ** {
*        * ***  ** * *   **       ** *  * ***  *****   * * * * *    *  * *    *  **  
 ** * *******   *  * *** **      * ** ****  *  * *      
    }

    for(;j<=49;j++) {
    *****    *** ****     ** * ****** **** * **   * ***  * *    *  sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.21
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 8.4k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.3k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 8k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.5k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users