Final Exam 3 (20%)

1 like 0 dislike
16.2k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 16.2k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  **  * * 
#include ** * ** ***  
char a[100],sum[200],space,i;
int main()
{
   *  ***   * *  ******* *** * *   ** * **  *   

***  ***    ** *  **   *  *  **    ** * * * ***    *   * *
*** **   ***** *  * *****  * ****  **** **  ** **  *     * * '){space=i;}
* *****    *****   * * ** * **

 ******   * **   * * **    *  **    **      * ** * 
 *  ****   * * ** *     *     ** * ** ** ** *      *** *****   *  *     * *** 
** *** **      ******    * 


   *   ****  ***   * *  **  * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*   *   ** * *      **
 ***  *****      
  *  **  * *      **
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
** *  * *   ** **  ** *****   num1[51],num2[51];
***   * *  **** * * ****  **   i,m;
 * *   ** *      *  *  ** arr[51]={0};
*    *  **   **    ** **  *** *
* *****   *     * **  * * **   ****   %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
 ** ** ***  * **  ** *  **  * *  *  * ****  *  ******  **** *  *  * * *   **        
    }
**** **** **  **      * *    (i=0;i<(strlen(num2));i++)
***  ***  ** **   ** ****
**  *  ** ****  ****  * * *************  * **   ** *** *   ****  *** *** ***   
***  ** * ****** ** **  * ** 
*******  *** *  * *    *    **     (i=0;i<=50;i++)
 ****  **    **** ** *  **
* * * ** *     *  * *   ***    **    * **** ***  *  * * * *    
************ * ** ***** *** ** ***  ***     * **  * * *** 
 *  **** * ** * * ***   * * *       *  *  * * *** **  *** ** **   **   ***** *    * **  *
* *      *** ** *  **** * **    *  *  * * * *   * *  ***  *  **** *  * ****     *  ** ** * *
*  *  *  *    *   * **** ** ** ** **  * * **   ** *    ***  *
    }
*****   * ***** * *  * * *    *****      *   * *
    {
 *  ***  **    *** * ** *  *  *********  * *    *    **    **
 *  * * * **  *   **   *     ****  *  **** *
 ** ****   ** **   *** * *  ****** **      *   **  * * *****   * *   *  ** * * *** *  *
 * ** *  * ** ****  * *** **    **** *** * *    *     
****   * ** *******  ****    ** * **** ***** *   *  *** * *        *** **
 *** **** * *  ***  ***  * ******    *  *** *   ** * 
  *  * ****   * *****  * * ** ** ** **         **   **** ** ***  * *    *** **** *  *** *
*** *    **   * ** *    *  **  ***    **  * ** * * ** **   **  *  * *   * * * **** *    * * *  ***** ** 
****     * ***** *** *    *******  * ******  ****
    }
* *** ** ***  * ** **   * ***** 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
    **** * **** ********    *** a[n],b[n];
*    * **** **** * **   *** **  ***  **  ** *** **  ** *
*  *** *  *     **  *  *** l1,l2;
 **  * **** ** *  ****     i=0;
  **** ***  * *      * * ** * *** 
   * * * ** ***  * *** *  ******* **** *   
   * * *      ***** ** **  * ** * * *  * **   *** 
**  *   *  ***** * *    *   * ******* * * ****
 ***  **  *  *  * ** * **  *  ** **   *** **********



 **    * * *   ** **  *  *  * *  ****   **  * * *  *   ******   ***  **     *** *   **    ** * ** ***  *     * ** **





* * * ***  * *** * **      ***  ** * * *********    ** * * 



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
  **  **  ****   *** * * * ** *    a[50];

* * **  **  * * ** **  * *  b[50];

 **   * ****  *  ** *** ** *  *  *  c[51] = {0};

* *  *** ***  ** **** ** ** *****  *  ***   ** * ** a, b);

*** * *  * * **** * * ** *  * i = 0;

* *   ** *   **  * * *  **    len_a = strlen(a);

      * **    ** * * * *** * * len_b = strlen(b);

* **  ** ** ** ***  * ** *  *   = 0; i < len_a; i++)
       *** * ***  ** ****
 **       ***** * ** *   * *  *  **   * *    ***  **  * **   = a[len_a - i - 1] - '0';
* *    * *  ****    * ***   *
        ****    *   **** *  *  *  = 0; i < len_b; i++)
 * ***  *  **  ***  **  * *
 * **** *  *** **    * *  *  *    * ****    ****  * * *   * *  += b[len_b - i - 1] - '0';
* * * * * *** *** **  **    **

  *  *  ****  ** * *  ***** * **  = 0; i < 51; i++)
   *    **  * *  *    **    **
   *  *  *** * **********  * *   *  *  **    *** > 9)
 *   *** * ** * * * *   ****** *     * **  ** ** * ** **  
 *   *    ** * * ***   ****   ** ***  *** *  * **  *    *   *******  * *            + 1]++;

** ** * ***  ***  *  ** **  *   **  ***** **  **   * ** * *  * * * *  * * %= 10;
**  * **   ** *** *    * * * ** * *   ***   * *   *   * *
* *  ** *    ****     **

***   * **  *      *   *   * nonzero = 0;

*** ** ** **    ******** *     = 50; i > -1; i--)
 *  *  *  *  * * **   **   *
 *** **    ***  **  *  *** *   ***  *  *  * **      != 0)
* *** *  *    * ***   ** **   * **   **   *         *  * * 
* * **   * ***   **   *  ****   *  *** *  **   **  **  **  * *   *  **** ***   = i;

     *     * * **  *   **  *   *     ** **     *   ****   *** ****** **  * *
  *  *   ******* *    **** *     *   *  * ** * * *    **
    }

 **  ***  *****   * *      **   *  *  * = nonzero; i > -1; i--)
* **  *     ***** * ** 
* *******  *  *** * ***  **       *   *   *   * ***** *  **         *  * * c[i]);
*   ***** **  *         * * 
* ***  * ****** ** ***         0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

**   *  ** ** * *      **  * *   **** ** * ** ****  **  *   ****   ** **  
    for(i=0;i<strlen(a);i++)
 *****  **      *** *  * * * * *  * ****  * *      ***** * 
*     **   **  **** ** *  ***   ** ****   *** * *  * ** ** * * **  * *  **  ** * *  ***  
 * ****  ** **          *        ** **   * * * *   **
    for(i=0;i<strlen(b);i++)
****    **  * *  ** ***   * ** *  * *** **    *  ***
*** *  *   ****** **** *  *** * ** *** *    * *  **  ** ***   *    ***  * **** *** **
  * *   ** ****   ***  ** *  ****   **       *   *  ** *   *** 
    for(i=0;i<50;i++)
***  * ***   * ** * * * ***  **   **  ***  * * *
**  * * * *  *   * **   **  * *  * ** ********   ****** ** *   ****** *  * *******      * ** > 9)
** **  ** *****    **  ***    *      **  * **  *     ** *  **** *  **********   *  *   **  *  ***     * *
* * **   **  * ** ** * * ***   *  *    *   ***   ***      * ******* *  * *  *        * **      *  * * **   *         *  **    ***  *** *  * *  *
*  * ** *    * *   ******    *** ** *  * * * * * *   ** ***  ** * * **  **    * **   ******** *** ** * * *  **  * **   * *  *    **** ***** **
* ** * *    * **  ** **  ***** **   ** *  * * *  ** **** * ** *    **  * *** *  * *  ** ** ****    * * *     * ** 
 *    **   ***     *   ***  *  * *****   * **** *   * *
    for(e=51;e>0;e--)
 *  *   *    ** *  **    *  * * * ******** *   *  **
*   ****  * **  ** ***** * ** ** ****  *** * **    ********* * **      ****  * **  != 0)
   *****    * *  *****  * *  ** * **  **** **  * * *  *** ** ***     ** *    * * *****    ***  *** * *  
 *** ********** * *****  ***   ******   *  ***    ** **     ** ** *  *  *         *****  *  *  **         ** **   *  **   * * *    * **  ****** *  * *
 * ** *** *   ****  ***  *  ** ** ******  *****  *   ***  ***********   **   *   **   ** *** ******* **   **   *  ** *    *   ** *
**** * ******  *   * * * * ******  ** ** **** *  * *  **   * *  *  * *  * ** ****** ******   ****     ***
**   *    ** *  *  ***   * **** *   ***  * * ** ** * *
 *  * **** ***  ***** * ******* *  *** *  * ** *****  *   ** * * **** *** ***** *   * *
    for(i=begin;i>=0;i--)
  ** *****   *  * ** * *           **      **** * *
** * * **     * * *   *      * * *  *   ******   ***  *   *  * * *  *  *  **  **  *   *  **   ** ***    
**  *   *** ******   ****   **  ***** **** ***   **  
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 * *    ** * * **   *** ****  *  * *  i,j,k,l;
*** * ****  ****  *** **      ** a[100];
 *** *   **     *    ***   **  ** b[100];
  *   *****  *****  * ****  **     **  **  ****   **
**** *  ** ** ** * *** *   **   *      *     ** **  *** *    &&        **   *** ** 
**  **** *  ******* * ****      
 ** *  *  **** * *        **  *   * **  *  ***  *          ** * *   ** ** **   * *  * *  * *
 **  * ** ** ** *  ****  
  **    * *** ******* ****  * *  0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
** ***   *   **** *** *   *      *    *  * ****   a[50],b[50];
*   ** * *  *****     **** *  *  *    *** **** **  * c[51];
  * ** **   ************* ***  *    ** *  ******  n1, n2;
*****   *      *  *  ***  ** ** ***   **** *****  i,j;

 * * * *   ** * ** **      * *  ** *  * **  ****  *
* ** *  * *** * * *   * * *   **** * **** *  * **   * 

****** ***  *  * *        * **  *   *  *  ** *   * ***      ***
       {
**    *    **** ***** **     ** ** * **** *  ****** ** * *  ***  **  ****   ** ** *********  ** * *  );
    ** ****   **     **************     ***  

   *** * *  ** *   ** *   * * ***  **  **  *  ** *      *
    *     **** **  ****  * *****  *  ** *****  ****
 * ***    **  *     *  * ***  ******    * ***  **  * * *   *** ***   * *      *      *  ***  b[i]);
*****   **      * * * *  *   * ***** *  *** ** ** * 



* *****  * *****     * * * ** * ** * **  *** * * * *  * * *   ** **    ** 
 *** * *****  *  ** **** **  * * ***** *   **
 *  * * * *  * *  *  ** **  ** **  *        ** * ** * * **  *****  **   ** *    *  **  *
     **  ** ***    **    * *     ****   * *  *  
  *** *  *** * **   *  ******  * **   *****  ***  * *  *   * * **  *
*  ** *  **  *  ** *   ****   ****  ****  * ***   * 
 *******     * **  **** **  *      * *** * ****  **      *  * ****  ******** *  ** **  
 **  * **** *   ** *  ***   ********  * **    ***

  **   *  ***  **  ****   **** ***   *  * *    *  **  * 
***  *    ****** *    * *  * * **    ** **  *   * 
 **** *   *** *** **  *   ** * ** * **   ***** *  **  * * *          * * ** ***    
*      *    *     *** **  * *** ***    *  ***  * * **** *    *  *       * * *** ** * ***   
       }

  * **   *  ***   ***    * **   *   ***  **    ** *  * **       * * 
       {
 *       *    *** ** *      *****    **  ** *  *  * * ** ******* ** *    **** ****    * * * **   *   
       }

  ** **  *  * *** *  ** * * * * * * *****  * **  * **   *
****  **** * *  *  ***** * **  *    **  *** * **     * * *
 *  **      **  **    *  ***   *********     * *   ***  **** * *****  **  * *** **    **   ********* ** ** * ***
** *   ** ***** * * ***      *  *  * ** ********** * 


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      * ** *   *  
#include ***    * * * * *
#include  *** *  *   
int main ()
{
*** *** *  * **  *  **     **  i,n,m,c=0;
*  *    **  ** *** ****** *   A[60]={0};
**  ***  *****    ****  ***  * ***** * 
*   ** *****   * * *********  ("%s ** ****** * 
 *  *  * **  ** ***** ** ** * * * * * ******      *  * *  ** ***  *
** * *  ** **    *  **** *  *   0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
***********  * * * * *    *** ***    **  **  * *  ** **** ** **   ****
    }

*    *   * *** *  *    ***   ***   *** * **    ** a);
*  *  ***** *** *  * **          *    ***   * b);

    for(;;) {
*  *  **   ****  ****** *******    * * * *  **** ***** *** ** *   ***  *  ** {
 ************ *  ***    * *       *     ***  *  * *** ** *** * *  *** *   ** * ***  * **
*  ** **   ***     * ****  * *   * ** *  ** *** *      *  *** *  *** ** ** **  *** *** *** * 
 **  **  *  **  * * *   ***** ********    *     *** *  ***  ** *****  **    * ***  * ***
***  * * *  ** * *  ***  **   ***  * * *  ***  ****     
   ** ******* *   ***  * * *     * *   **   **  **  * *  *   {
*  *  * *   ***** *  ****  *** ** ***   * ** ****   ***** **  * ***  *  * *  * ** *  ****
** * *** ***        **         ** * * **    *   **  * *****
    }

    for(;;) {
 ****     *  *   *    * *** *   ***   ***  *** *** **   **     *** * {
******** *   * **  * *** **  ***  ** * * **** *   * * *** * *  *   * ** ***   ** ** *** ** 
**  * * *   *  ********  **   *       ***** **   * *     * * *** **  *  * *   * *
* ***  *  *** ******     ***** *     **    ***  *   ** ****  **    **  ** *   *  * *** *
*  ***** ** ** **  * *** * * *  **  *  ***  ** * *
 *** ****  **   * *    ** ***** * *  *  *    ** * *  *   *** * ** {
*  *** * ** * *  *** **  *  * * *** ** ***  ***    ** **   * * * * *  **** ***   **
****    **** * * **  ** *****     ** *   *  *   *******  *  ***
    }

*** * * *  *       *  * ****  * * *******  * * {
 ** **** *  *****  *     *   * *  * ** ** ******  * ****** ** ******  && a[i]<=57) {
 * *   *   **     * * *  * *** *** *** ** *   * *  ** **  *** *   ** * **   * *** *   ** *** * * *
 * **** **   **** *  **  * *** * *    *** *  ***    * *  
 *   * ***     *  ** *  *  * *** * ** * *  *  ** *** * * * ** * && b[i]<=57) {
  *  * **    ***  *   *** * *  ****** * *   * ***    * ** * *     *          * * *   ** * *
*  ***** * * *  **  *  *         ***   *  **  * *  *     
    }

    for(j=50;j>0;j--) {
 *   *   **      *  **  *** **  *  *    *  * ****   ** ** * ** * {
**   ** *  * ** ** *****        * ***** * **  *** *      **  ***  ****     *     * *    ****
** **  ** *** *      ******   * ***  * ******  * **  *
** *     **** ***      * ** **   **     * * **  * ** * *     if(sum[j]+a[j]+b[j]==10) {
   * * *   *** *  ** * ****** *  * ** * *** * ** * ** *********  ** *    *  **  * *       ** 
*       **   * * *   ** **  * **       ***** **  ***   * **** *  *   ***  * ** **  * * ***   
*   ***  *   ** **** * * *  *  * ****     * *      *** 
   ** **  *  *  ** *    *** ** * ** * * ** **  ** ****  if(sum[j]+a[j]+b[j]>10) {
 * ** * ** *  ***  ** *** ** * **       *** *** **** *** ** ** * * *   *  * ***  * ** * ** 
** *  ***    *  * * **  ****** ***   ***  *  * ** *   *    ** ** *  ** * *  *** 
 *** * *  ***   *** ** * ****   ** ***  ** * ** *   ****    * 
    }

    for(j=0;j<50;j++) {
**      * * **** ***  ***** *   *  * ** **  *     *  *     ** *  ** * * {
 * **  * ** * *   * **      *****  *** * ***  * *** *  * **  * ** *  *** **   **** *   * *   
 ***    ** *    *** *  *** * *  **** *** * ***   *   * **
    }

    for(;j<=49;j++) {
**** *** * * *  *   **   * **** *** **     * *    **** *  * ** **    * * *  sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.7k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.9k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 14.9k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.2k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users