Final Exam 3 (20%)

1 like 0 dislike
2.6k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.6k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include        * * *** *
#include     * ****  ***
char a[100],sum[200],space,i;
int main()
{
 * *** *  *      ***  *** ** ** **     **

  ** **      ******* *  ***** * **       * *** * ** **
* * * ***  ** *  * *  **  **  ***       ** * * *  **  * *  '){space=i;}
   ** * * **        **** *  ***  

* **  *** *   *  * *  **** * ** **  *  ***
****  *  **  ** *   * ****    * *    ***   *    *  *    *  **  ** * * *
*** **  *  * ****    *


 * *  **     ** ****  **** * *** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *** **   *** ***    *
 * * *    * * ******  * 
**   **   *    **   **  
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
*   *  ***  *** **** ***  * **   ***** num1[51],num2[51];
**   * ****  *    *     * **** ** * i,m;
***  ******** * ** * * * * arr[51]={0};
*   **   * *  **   * * ***     **
* *     **** *  *** ** *** * ***  *   ** %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
 * **** * * *  *  ***    ***   * * **    * ** *  * * * ****    ****   *   **    * ** *** *
    }
 ** *** * * **** **  **  *  **   (i=0;i<(strlen(num2));i++)
***   * **** *  *   **  *  ** 
   * **         * *   * **** *   ** *******   *  *      * *** * ** * ** **  *
******   *  **  * **** *** **  
 * *       ** ***     *   (i=0;i<=50;i++)
***    ***  * *** * *  ** *** 
   * *  * ***** *  ***** * **** * *   ********* ****   **  ** 
   *    * *   **        ****  **  **     **** *  *  * *    
  ****** *   ***  **** *****    * *   * *  ****  ****************   **** * * * **    *****  *  *** 
   *      *  * **** *****  **  ***** **  * * ***  **   *** **   ***** *   * ** * * *** * **      * *   * 
  *  *  * *   ** * * * * *  ** *** **  * *  ** * * ****
    }
** ****  *    * **     * * * * *    ***     **
    {
    *  ****    * **  ** **  **    **       *** * * * *** * * *   * * 
  ****  **      **  **  ** * * ***  *** *  ** **
  *** ***** *   ** **   ****   ** *  * *   *  ** * * * ** **    * ** *** **  ****
  * * * ** *******  *****      *  ****     **  *     
**      *  *    ***  ** ** **** * **      * *** ********  ** **  *** 
*** **  * *  ***   *****   **  ** ***     ****  *
 *******   **  * ******       ***  **   **    ** * * ***   ***    **   **  * **  ** 
 *** **   * * * **  * *  *** **  ****  * * *  *  *** ** ** ** * ** **  **** *** * * *  **  *********** **
  ****** *  * *     **       ****       ****    **  **
    }
* * ***  **** *** *  **   * ***  0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
********** *  *  *  * **     a[n],b[n];
  *** ** ****  * *  ****  **   * * **  * * *** *
**  ****  ****  **** *   **  *** l1,l2;
  *** *** *** ** *   * * *  i=0;
** **** * *   **    ** ***  ** ***   **
** * ******  *  *   ***   * ***  *  
 *** ** * *     **  * *    * * ** * ***  ***  
  *** ** *    *** ****   **   *   * ** *  ** *  
 *    *  *** * * *  **    *  * *     * *  *** **  *   



 *   **  **  *   ***  ***  *** * *  * **  * **    * *  ** *    **  * *  ****     ***** *     * **       *** * **  **  ***   *





** *   **     *** **  ** *  *  *  *** **** * ** *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
** ** * ******* ******     a[50];

*   ** ** *** * *     *  * *  b[50];

   *      **  **** * * * **  c[51] = {0};

*  ****  *** **  ****   ** *   ****  * ******   *  * * a, b);

  *   ** ** * ** **  **  ** * i = 0;

***** *******  ** * *** ** len_a = strlen(a);

 *** ***** **  * ** ** ** *** len_b = strlen(b);

 *   ** *****   ** * ***** *  * * * = 0; i < len_a; i++)
  *  ***  ****** ***    *
** ****  * *  **  *****  *   * * **     ** * ** ** ** ****   = a[len_a - i - 1] - '0';
* * ***   ** * * * * * * *
 *  * ***  **   ***   ** *     = 0; i < len_b; i++)
 ***  **** ***  **  * **     *** 
**        ** ****** **   ***  **** *  *  **  **    ** * * += b[len_b - i - 1] - '0';
** * **    *  *    * ***  *   ** 

**** ***  ** * * * * * ***        = 0; i < 51; i++)
*   *** ** * * * *** ***** *   
 *  * **   **   * * *** *  ***   * ***   * *  **  ** * * **   > 9)
***   ** * * * * *  ** *   ** *        * ** ***  *    
  **  **    ** ** *** ** **    *    **  *   *** * *   ***** *    *** * ** **   **  **   + 1]++;

  **   ** ****   ** *  * * * ***    ****  ****  *   *  **   **   **  ****  * ** ***** %= 10;
*   * * *   * *     * *** *  *  ** * * ****  * *  ****
** **  *  * * ** * **** * 

 * *  * *** * * *  ** ** **      nonzero = 0;

***     * * *** * ***   *****  = 50; i > -1; i--)
* ** *    *    ** **** ***** *
*  **     *** **  * * *     *  **   *  * * *  * * *   *  * * * != 0)
 *** *****   ** *    **     *     ** ********    *    * ** ***
 **   * *****     **  * *  *** ***  **    *  * * * *  **    ****  * *  ** * ****      * = i;

**    *  ** **** * *   **  *  *  *** * * ***** ****      *     *  * ** *** *  ****  ** *
** * ** *    **    ** ***** ***  * * *  * *  ** *** 
    }

*   *  *      ** *** * *** **** = nonzero; i > -1; i--)
 *      **    ** *  * **  *
  ** **** ** * **  ** * *  **** ** ***     ** **     * **   ***            c[i]);
 *******  **  **  *** *   
 ****  ****  **  *    **  *  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

* * *  ** *** * *  * * *** *  *   *** ** ** ** *     * * * * * *     *  ** *  
    for(i=0;i<strlen(a);i++)
* *  * ** ** ** * ***** *  ***** *** * ***** *   ****  
***    *****       **   ** ** * ***** *  ** *    *** * * *    *     *   ***       *  * **  ***  
  * *  *    *     **     ** **  *  ***  * *   *** 
    for(i=0;i<strlen(b);i++)
       *  * *        * * *  * *   **  *  **  **
******   * **  *   * *  * ** *** *    **** * ***   *    **   * *    * * ** *   **  * * * ** ***
**  **   **  *******  **  **   *   * *  **  * *****  * 
    for(i=0;i<50;i++)
 ***** **  *  **      **  **  *   *     * **  *      ***** * 
***** **   ****** **   ***   * ** ** ***   ** *   ***    * *  *  ** **  * **** ***  *  > 9)
    **      * *     ** *   **  *  ** *  **  ** **  **   ** ** **  *   ***  ** ***   **    **   *** * * *
  * * * ** ***  **     *  ***  ** *  *  *    **  * *  *  **     ** ***  **         **        ** **   *****   *    * **     * *** ****   **  * 
 *  ** * ***** * *** **   *     ** *  **    * *******    ****** ** **  * *     *  *  ** *  **  * *   **** * *  ***  ****** * * **  * 
      **  * *   **  *   ******   ** * ***  **  * *** ** **  *  **  ***   *  * *    *  * * *    *    * * *  * 
      ** * * * **   *  **  ***   ** *   * *** * *** ** ***
    for(e=51;e>0;e--)
* *      **        *   **  *    **  *   **  *  ** ** ** 
** *** *** **  *     * *     *     * *    *  *   * ********      ********  ***  != 0)
 ** ***   **   * *******  *  ** * * ***  *    *  *  *    *** ***  *  * *****  **   * **** **** * *****  ** **
*  ** * ****  *  *  ***    *****  *  *   *****    *** *  *  ** ***      *** *  ***** *  * **** * ***  *****  *** ** *    ** *  *   * *     *     
 * * ** ** ** *  *** *   ***  * ***** **  **    ** ***  **** *** *   *        *      ******* *** **  **     * *   *  *    * ** * *** **
 ****   ** *     * * *   * ***  ** * **  **  * ** * ** **** *       *** *** *  *  **  ** * *   * * *** *
 ** *  **  * *** * *      * * * * **  *  **     ** ****
**  * * *   **    *    * * * ** * *** *    **     * * * * **  *    *** * 
    for(i=begin;i>=0;i--)
* *  ** ** * *   **** ** * * ***      * **  *   **   *  
**** ** **  **    *      *   * * **  ***** ** ** * * *** **** *** *  ****    * *** ****  *   *   ** ***   **  **
  ***    ****  ****    * * ***  *  ** * *   ** ** *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** **       *  *      ****  i,j,k,l;
****   ** ** ** ** *** ** * a[100];
* *     *     **     **    b[100];
* * * * *** **  *   *  *** *  *   * *  **    *     *    * *
  ***    **  * ** *** *  **       *    *** ** * **   *  && * * * *  ***  ** **  
    *  * ** ** * * *  *   *
* ***   * * *  ** * ***   *** ***** *** * *    *  * *  **   *  * * ****** * *** **   *  ** ** ****
 ** *  *   ** *    ***   
 ***   ** **     *  **   *   *  0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
*   **  ****     *  *  *    *** * * ** **  * * *    **  a[50],b[50];
 * **    *****   * **     ***  *   * *  *    **       c[51];
       * **   *     ***   *   *** * *****     *  * * n1, n2;
*****  ** ***        ** **    *     *  ** *  ** i,j;

**** *   *** **           ** *  * *   *  *** *  *
     * **** ***    **  ***** **  ****** * *   * ***   *

  *** *  ** * * * **  *  ** ****   * ** *    ** **  *** ***
       {
  *   *  *** * ***  *** *** ** ** ****** * *   * *       * * *   *  *   ****** * * **    *  *** * **** * );
*      *    ** * *   * ** *******    **   *  

* ***  *  **       **    *  *   **  *  **    ****  ****   *
    * **** ****    ** **  ****** ** *  ** * *** * 
* *** *** *  *  ** *** * **    * *   **  **  * **  * **** *   ** ******  * * * ** * *** *  **     b[i]);
**   * ***   *  **  **  *** *   * ***** **** 



 **  **     *** * ** **** **  *    *   ** * *  *  *  *  *  * * ** ** *  
   *   **    **  * *** ***      * **   ** *  
   ** **** ***       * *  **   *** *  ****  **    *    * ***   *   ****** * * **  * * 
** ****   *****    ******       *   ** * ** *   * *
**  ** **** ****** **   **  * *  **  *** * *  **  ***  **  * **  
 *   *** *  *** * ** *****       * * * ** 
* * *    *   *** *** * *  ** *   *   * * *  ****   *** ****     * ** ** * ** ******
*  **   * * *** ** ***  ** ******  * *  **   *  

**   * ** ** *  **** * **  *  *** *  *** * *  * ****  **  **  *  *
 ** **    * *  ***   *  ** ***  ****** ** ** ***
   ***** *  *   * *  ***     *** **  ** *   **  **   *   **   * *     *   *    ****  
** **    **  ***   ** *    **      *   **    *******    *** *     ** **    * 
       }

 *   **   * ** ***  *   *  * *** **   **  *  ***  ***** *  * ***
       {
 ****** **  *  * * ** ********   ** ***  **   **   * ** * * ***   *** * * **  *****   * 
       }

   * ** *  *  *  * *   **  * *  ****   *  *    **    **** 
 * *  *** ***    ** **    ***  **     ****     * *
 ** **  * ** *** ** * **     *            *   * ** * * * *  *  **   *  *** *******  * * ****  *  ****   ****   ***  *   
 *  * *  ** * * **  *** * *****  **  *       


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * *** * *  *
#include  **** * * **    * *
#include   ** *  * ** *
int main ()
{
  *  ** ***  *****    **     i,n,m,c=0;
 ***      ****   *  * * *  A[60]={0};
 *  * *  **  ****** ***  * *    *** * *  *** 
 *  *   ** ** ** ** * ****   * *** ("%s       **  ** 
   * *   * * * * ****  ** *    * ** ** *  ****    ***  **  * *  
 ** *  *****   *  *****  ** * 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
**** * * * ***   *  *** *  * *   *  * *** **    ***   **  *    *   
    }

    * * ** *  * ** * * *** *  * *     * ** *****  a);
  ***  **  ****  *  * **  * * **    *     ** b);

    for(;;) {
   * *** * **     ***     * ***** ****    ** **** *   ** *  * **  *     *  {
* *   * * * ** * **  ***   ** *  **** **  ******    * * *  ***   * * ********* **     * 
**  *  ******** *  *   ****** *  *   * *  **** *  ** * ** ** ** * *  **  *   * ** ** * *     *
**  * *  * ****  **** * *  ** * * **  * **** **  * ** ****  **  * ** **  *  * *  **  *  ***
 *   *   ***** * ***       *****  * *** ****** * ***  
**** *** *   **   **  * ***** * * *** **        *   * **    {
* *** ** * *  * ** * * *    * ***   *       *** *    ***** *** * ***  ** *  *  * ** **** *
******* ** **   *  *  **   *** * **  ** **  * *   *  *
    }

    for(;;) {
    ***** * ** **   ***  ****  *** **    ***  **** ** *  **** * {
** *** *   * *  * *****  *** * * *   **  ********* *   ** * **  *   **  ** *  ** *  * *  *** 
*  *    ***** ** *  *  *   ***    ******* *     ****  **** ** *****   *   * * *** *  * *   *   ****
*  ***  * * ** *  *      ** * ** ***   *** * *    *  ** ** **** ** *  * ******
  ** ****** *   ** *** *     *  *  ***    *  ****   * 
**  * *  * ****** ****       *  * *** *  * *   *  ** *****  {
 *****   **** * *** *   ***** *   *   *****  * **    *   * ***  *    *
*  ***** *   ** *  * **  **** *** *** *  *   ** ***  * *  
    }

* * ****   **  *  * ** ** * * *** * * {
*     **  *     * * ****  *   *** * * ** * *  *   *  * ***  * ** ** * && a[i]<=57) {
****** * ****  *** ** **  ** ***  *    * *   * * * ***  **** *     ** *** **** *** *****
***** *      *   * * *   * **  * *** * *** *   **** * **
****** ** ****** ****  ***  ***  *** *  ** *      **** *** *    * && b[i]<=57) {
***** * *  *****     * ** *    **   *     *  ***  ** ***  *    * ***   **  *** **   *
 ****   ** *** *  **  ** ****  *  * * *****  *  ** *
    }

    for(j=50;j>0;j--) {
*  * **   ** * *  *  * ** * * ****     * *  **   *    ** *  *  ** ** * *  {
**   * * *** **  **      **  ** **** **  * ***   * **  *   * *  * *   *  *  * ***  **  
** **** ******* *   * ** ** **  *  *     **  *    *
** *  ***  **** **  * * *** *   *  ** *    *** * *     ** if(sum[j]+a[j]+b[j]==10) {
    * *   *    * ** ****  * ***** ***     **   ** ** ***  * ** *    ** *  * ****    **    *
  ** ** *   * * *  *  ***   * * **** *** ******         * *** *** ** ****   *  *   **  * * 
 * *****  **    *   * ** ** ** * *  ** ***  *** ****** *  * 
 * *  *  *  * * ***  ** ****     **** *  ****** ***  *  * * if(sum[j]+a[j]+b[j]>10) {
** *******    * *     * **    **  **** ***  **    **     *  *** **  *   * ***  * *      *  ****
* * *******    * *  * *****  *  *    * **** *   *     * *** *    **    *  *  ** *** * *
***   * * *** **  ***** ** *     * *  ** **   *  ** ****
    }

    for(j=0;j<50;j++) {
* * *  *   ** *  *  * **** *  *   **     **  *  ***  * ****   {
**  *  * ** **    *   *** *  * *  ******     ***  *     ***  * * * ***    ***** *****
*  *   ** * *** * **     ** *  * * **   * *  ****
    }

    for(;j<=49;j++) {
     *** * **** * *  * *** **     ** * **   **   *    * ***   * ***** ***  sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.180
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.3k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.2k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.6k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 495 views
12,783 questions
183,443 answers
172,219 comments
4,824 users