Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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#include<string.h>

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trả lời bởi (-301 điểm)
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdlib.h>
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}
trả lời bởi (-193 điểm)
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0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
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**  * *  ***   **** * *  *   * *********** ***** **    **  ** * * * *   **   ** *   *   **  
  ***   ** ** *      ******* * *   ***  ** * * **   *   * **     ******      **
     *** **  *************    ** * *****  *****  *  ******* *  **  *  * ***  *   **  * ****** 
  * *    **  * **   ** * *   *    ***** *** * ** * *    
    * **  ** **   **** *    * ****    ** **    * **** {
 *  * ** * **** *  ****** * ** **   * *    ** *  *  **      *      **** * * ** * **      ***
**     * * * **  *     ******* **** ** ** *** ****      *
    }

    for(;;) {
*   *  **  *   **      **   * ** ***    * ****       *   **  *      *** {
  ***    *  * * ***  **  *  *  **   ****    * * * *  * **   ** *  ** ******   ** *      **  ***  
    ** *****    *  ***  * *** ***   * *    **** **  **** ***** **  **  **  *   **        
*** * ***   **   *****  ** * * **** *   ******     * * ***  * ****** *** *  **      * 
*  *  **  ***   ***   * ** *  **** * * *  ** * *
**** *****    *    **    * ** *   * * * ** *  *** * * * ***    *  *    {
 *    ***       **    ** * **        ** **   *    *** ** *    *  ***     ***  * 
****   *  **  *****  *   * ***   *  ***** *** * ***  *** 
    }

 *     ****   * *** * **** ** *    *** {
******** ***    *   ** *   *  ***  ** ** * ** *  *  ** **** * *     && a[i]<=57) {
*  *** * * *  *****     * * *   ***     ** **  * **** *** *   ***** * *  ***   * *
***   **   * **  * ** **  ****** ** ** ** ******     **
  *   ****** ** **   *** ***   ** ****  *   *** *****  * * *  && b[i]<=57) {
****  ******    *     **  * *     ** *  **   **** **** *     ** *  * *   ** ** *  *   * 
   *  *   **** *   * *      * * ************  * *  ***  
    }

    for(j=50;j>0;j--) {
*    ** * **    *    *  * * *   ****   ** **** * * * *  ** * *  * **** ** *  * {
 *    * * *** ** **  *  ***   * * *     *  *  * ****   * ****** ** **  *  *   *   *** * * *
**   *   * *  *    * ***  *  **     ** *****   ***  *
* *    *     ** * * **  **   **  **   *     * ** ** **  **** if(sum[j]+a[j]+b[j]==10) {
 * * *     ******** *    **     *** ***   ****   * **  *   * **** ***** ** * ** ** ****    
 *  **** *********   *  **      * *  * ***   ***  * *** * * **  **** ** ** * **   **     * *** 
*  **   *** * *********** *  **  *** ** *  * *** *** *
  ***  * *  *   **    *  ** ** ** ******** * **  * if(sum[j]+a[j]+b[j]>10) {
*   *     **  *** * ***** *       * ** ** *   **  ***     * *   **   **** *** ****  ** ***    * 
** *** *  *      *   * * ***** ***   ******   ******** * *  ***  **   * *      *** *     * * * *
*     *      **  **      *  *         ****      *** 
    }

    for(j=0;j<50;j++) {
*       ****   **   * **   * *   ** ************  *   * **   * {
  ** * ***** *       * ***     **    *  *   ***** * **  ** **   **    ** * ** *   *   
*** ***** *   ** **  *** * ** * * **   *  * **
    }

    for(;j<=49;j++) {
*    **  ** ***** **   ** *   * *  * **  **** ***  ***    **  **   ***   sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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