Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-168 điểm)
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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0 0
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0 0
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đã bình luận bởi (4.3k điểm)
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trả lời bởi (-285 điểm)
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Case 1: Correct output
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Hidden content!
#include<stdio.h>
#include<string.h>

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trả lời bởi (-301 điểm)
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Case 0: Correct output
Case 1: Correct output
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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}
trả lời bởi (-193 điểm)
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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Hidden content!
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int main ()
{
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

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 *      ******* *******  ******     * * *     ** * **  ** ***  **   **  *  ** **  * * *
 * *    ***    * ***  ** * *** ** *  * **** **   
**    *  *** * **   *  * * *   * ***  *     ** *   *   *   ** ** {
**  * * *  * * * * **    ** ** **   **** ** * * ** **   *   **    * **   **** * ** *  ** 
 *  *    * ** * *     * * **   * ***     * *  ***  *  * 
    }

    for(;;) {
*  * *   *  ***   ** **     * * * *  *   **   * * ***  ** ***** {
* *    * ***  *  * *  *   * ** * ***** * * **  * * * * ** **    *    ** * ***   ***     ****  ** 
***  ****   **   **    * *   ** *  ***  *   * * * *  *    * **** *  * ***  ***     * *  ** ***
**** ***    * *   ***   * *  ** * * **  **   ***  *  * * ***   *** ** *** **  
* **     *** *    *  **  **** ****    *  *   *** * 
* *    * * **  **   ** *  * *  *  *** *** ** **   ** **  {
**** * * ***** ******     ** **  *    ** *   * ***  *      *** * *** **  **   **** ***
 *  ** *     ******** ***  *****    ** *   * * **  * ** 
    }

  *** **     * *  **** ** ***  *  *    **    {
*****    **  **  ** * * **  * **  *** *****    * * * ****   && a[i]<=57) {
* * *   ** * **  **** * *     ** *** **   ****     **********   ** ***  *    *  ****  * **
* ***** ***  *********  * *****  *** * *** ***  ** *
*  *   *   ** ** * *** ** ***    **  * ** **  **  ** **** **      && b[i]<=57) {
  * **  **  *   * *   * *    *  * ** *** **   *  ***       **  *     * ** ** *    **  * *
 *      **  ** **** * *      **    *** *      *  ***** *
    }

    for(j=50;j>0;j--) {
* ***  **    *  ***   * *  **  ****  * ** *     *     **   ******   **  ** *     {
** * *  ***  ** ****  ****     **  * * ****  ****  *  **   ** ** *   *              *
 **** ***    ** ** * **  *  **  ** *        ** * **** *
   * ** * ***  *   *****   *****   * *  **    *    *  * * if(sum[j]+a[j]+b[j]==10) {
**** * **** ****  **  * *** *** * *  **   *****  *  *** ** ****   ***    ** * ****  ***  *
  *    *  *  * **   * **** ** *  ****  * ** ** *     *     **  * **     ***  *  ******* 
* ** ** * * ********* ***  * * ******  * ****  *  ******   
*** **    ** *  **   *  *****  *   **  *    *  **  **    ** * if(sum[j]+a[j]+b[j]>10) {
 *   *** ** ***** * **         * *      **      **** *** *** *****    *** **   ***  *** **     * ***   ** 
*    **  ** **    *** **  * *      ** **    **   ****    *  *    ***     *    * *    
* ** *          *   *** ***  *****    * **    * *  ***
    }

    for(j=0;j<50;j++) {
   ** ***** * **** *    ** * ***** * * *    *       * *  * * {
 *     *  * * *** *  * * ***   **   ** ***   ** * * ** ** **** *** **   ** 
**  * *  *****  ****  *   * *  ***       *  *** ** * ** *** 
    }

    for(;j<=49;j++) {
**** *  *  **** * * *  ** * ** *  *****   *** * ***  **  **  *   ***  sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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