Final Exam 3 (20%)

1 thích 0 k thích
15.9k đã xem

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
chọn từ khóa lại bởi | 15.9k đã xem

32 Trả lời

0 thích 0 k thích 
Hidden content!
#include <stdio.h>
#include  * ***   * *  *  
#include      ** *  **  
char a[100],sum[200],space,i;
int main()
{
  *     * ******* ***   **  *****  * *  * * ****

* *      *  ** *   ** * ** *   * **  *   * ***  
*** *    *     ******  * ****  ***    ***  *** *    *  **  **  ** '){space=i;}
   *** *** **   ***   

**** *** ** *** *      ***  ***    *****  *  *** 
** *   *  **  * * *** *  ******* **** ** * ***  ***** *   *  *  *     **  
* **    * ******** *  *  *** *


*  **       * *  * *** **    0;
}
trả lời bởi (-286 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
   *    ** * * ** * 
   ** *  ***  *     *
*** *   *    * * * **  *  
int main(){



}
trả lời bởi (-32 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
*  *    *  *  *******   ***  ** num1[51],num2[51];
     * * * * *  * ****   i,m;
** ***** ** *** ** *  ** **  **  arr[51]={0};
***  * **  *** **** ** ******
 *   ** ** * * ****** ** *    *  * *   * %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
 * *   *   *   **   **  ** **  ****    *** * **   **   ** **  ** * *** **    *  * ***  ***
    }
  * ****  ***   *** ***  * (i=0;i<(strlen(num2));i++)
** **  **  ***  ** *  *  * **
* *  ** ***  * *  **** * * ***    * *  *   *** **** *****    *** *   **    *
 **        *   *   *****
    * *  **   * *      **  (i=0;i<=50;i++)
*   ***   *       * * ** ***
 ****** * ** * * ****** *   * *** * ***** *** ***    ***** ** *  
         ** ** * ** ****   * * * * * *  *** ***  *  
*** * ** ******* **  ****    *  *      *   * ** *    *  ** ** *    *     ***  *  **  *   ***  * **  * 
*  ** ***       *  * ** *      ****** ***  ****    *    **   *** ****** *   ***  * *****   ******
   *  **    * **     **  *  ***  *   *   * * ***  ***    ***  
    }
*     ** *  ****** * ** * *  * *     * *  * * 
    {
  ***     **   *  * ***  *  **  **** ******   **  *  *  **
*  * ** * *  * * ******    ***** **  *   * *  ***** 
**  * *  ***   *   *   *  ***** * *  **** * * * **   * ******  * *   *** **     **
   *    ***  *** *  **** **   *   **  * * ** *  *  **  **   
**  ** * ** ** ***         * *** * * ****  *    * ** *  ****** * * *  
 *    ****** ** **  * *    **          *  *  ***  ***
 ** ***     *    ** ** *  **   ** *      *** *  **** ** *** **       ***** **        **** * * *   **
* *  *  **  * * *     *  ********   * **    * *** * * *  ** * **** ****** *   *    *  *  ** *  ***  
** **  **  *   * *   ** ***  * *     ** ***     **
    }
**  **** ****   *** **** **  0;

}
trả lời bởi (-168 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
**     * ** ** **    *    * *** * a[n],b[n];
* ** * ***** * * **  * ****  **   *     ***** ***
*  *   ****** *** * * * l1,l2;
*** ** *** ***      * *  * ** i=0;
**          *   *     * ***   ** 
*** ***    *    ***   ** ****  **
* * ***  ***** **     **    ** **** * * *  ****  * * 
**   ***  ***   *   * **        *  **** * ***
 **  **   ***** * * * * **  **   * **   **  *** * **** * *  



* * * *** * **     **   *** ***** ****** * * *  * *  ** ** **   * ****   * **  *  * * *   * ** **   *       **  *  ** 





 ******* ****  **** *    * ** *   **  * *   * **  



}
trả lời bởi (-329 điểm)
đã sửa bởi
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
đã bình luận bởi (4.3k điểm)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
* * *  ** ** * *   *    * **  a[50];

  ***   **** *  *  ******   * b[50];

 *    **     *** **  *** ***  c[51] = {0};

 ***   ** **  ** * *    * **      * * **** ** ***   a, b);

 * *   *   ******   * * ***** i = 0;

* * ***   ** ******  ** ** *  len_a = strlen(a);

 **          **    *** **    len_b = strlen(b);

  *** * *  *  *   *  * *  *  ***** = 0; i < len_a; i++)
*   ** ****** ***   * ** ****  
**   * *      *******  **   * *  * **  *     * *  ** = a[len_a - i - 1] - '0';
*    *  * ** * ** *  *  *
  *  ***** *   ***   ***** ** *  = 0; i < len_b; i++)
****** **   * *  *** ** *  *   * 
      **  *** * * **  ***  * * **  * ****  *  * ** *   * += b[len_b - i - 1] - '0';
  **   ** *  * ** **  

  **  ***    *    *  ** *** = 0; i < 51; i++)
* * *** *  ** **  *  * * ** ** 
    **** *  ***   ***  *  * *  *      **  * * * *****  * ** > 9)
  * * ***   * ****** * *  *  *  **  ****   ****  * **
**  * ** ****  *  * **** ** * * * *   **  *** * * *  ***  **  ** *   *    ** *  *  + 1]++;

* ** ** ** * ***   **  ** * * *    *     *  ** * *  **  * *****  **** *   *** *    %= 10;
    * *  *  *     * ****      **** **    * **   ***  
*   ***  * *  * * * * ****

  * ********    *   **      *  nonzero = 0;

 * **     **     ** ** * **  ** = 50; i > -1; i--)
*  ** *   *** **** ** ** 
  * ** * ** *  ** *    *****  **    ****  * ** * * *  ** ****    != 0)
 ** ** *  *****  * *** *  * *       *  *   ***  *  *  *
   * ** ** **  *  *   *   *   *  ** *  *   * * *  ***   **  *  * ***** ** * ** *    = i;

*      * *   **     ******* ** ** ***  **   * *    * *   ***** *** ******     ** ** * *  
 * *****  **    *  * * ****   *  **    **  *    * 
    }

   ***   * **  **  *   *      = nonzero; i > -1; i--)
 **  ***** *      * *** **  *   
*** ***** *     ** *  *     *   * **    *    ****     *   *** * * * ** *   c[i]);
 *** * *  **  *  * ****   *
*    **  *   ** ****** *****  * **  * 0;
}
trả lời bởi (-285 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

  * **   *** * ** ** * * ** ** * *  * * * *  * ** ***     * * *  * * *     *  **   * *
    for(i=0;i<strlen(a);i++)
 *  *   * ** ***             **  * *  * *  * ****   *** ***
 * ***  ** * *** *** *  * *  ****** **  * *  *      *  **  **   * *  * * **  *   * **** * 
 * *    **    **  * * ** *  *** * **    ** * ** ** * 
    for(i=0;i<strlen(b);i++)
      ******** *  * * ** ** ***** ** *** * **    *  * **
  * *   * **  * **   **   ** * *    ***   *  * * **       **    **     *** * * * * ***   * ***** *   
 *** *** *  *     * **** * ** **  **  *   *** *   * ** *
    for(i=0;i<50;i++)
*  *     ** *** * *  ***  *  **  ** **    ***  ******      *
***  * **     * ****   ** *    ** **** ** *** *  *     * ***  * *  ** * *  * ****    *  **** *  > 9)
****  ** * *  **     *** ****    *   *****   * *     *   *      *  ** * ** ** ******  *  ***   *  * ** ******
** * * * **  * * * ***** ***       *****  ****  ****  *   **   **   ****   ******  ***   ***    ** ***** **     * *  ***   *    **   ** ******
*** *  ***  * *** ** *   ***  *  *   *  *   **  ** * **  * *  *  **  ** * *     **     *   *  *   * ***      * *    ** ** *****
 ** ** * *  *  * ****** * * *  ****** *   *** *  ***    *  *****   *****    ***  * ***    * **   * *        ***
****    ***  *       ** ****    *** *  * ***  *   * ****** * 
    for(e=51;e>0;e--)
   *** * * * * ** *****     ***  ****   * **  ** ***  *  **
  ** * *   *****   * * ***   *     *  ** *  *  * ***** ** ** **   **** *    ****  * * != 0)
**  * * *   * ***   *   * * * *** *  *  *  ****** * ** ** *   * * *     *      * ***    **  **  *     *****
*   *     * *****  **             ******* **** **** *** ***     *   *    * **   ******** * *  ** **   *  *      ****    ** ** **  *    
* **  *   **    * **  * **** *** * * ***   ****  ***  **  * *  ** **   ***    **  * * **     ***** *** *     *       ***  ** ****** * *  *** **
  * * **    * ***** *****  ******  *    *   * * *  **   **  **   **   *  **    **  *  ****  **     * * * **
 *** **   * ***     * ******  *   *  *    **  *** *  *  * ** 
  *     **   **    **** * **      *    *** *  **   *  * *** **** * **    *  **
    for(i=begin;i>=0;i--)
 ******  *  ****  *** * ***   *****   *  ** *  *******  
******* ****  *  * *   * * *** **  ***    *********  ** * * ***  ****** ***   * *    **  ** **   *  **** * *** **
*     *****     * *  * ***  **  * ** ** * * * *****
}
trả lời bởi (-301 điểm)
đã sửa bởi
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ** ** *  ***  *  * i,j,k,l;
**   *** ***  * ** * *  a[100];
**  *  ***  *   ** *** *   b[100];
*   ** *   *******  * *    *  ** *  * **     *  ***** * *  *
** * ***  ** *    * *   *  **** *    *       *  *  * ** && ** * *** ** *   ***
 * *    **   *** * ****** 
  ** *  * **    **** **    ** *  *      **** * **  **   ***      ***   *       * ***  ** 
 ******** *   * *   * *    
*   * **   *  ***  *** * * **   0;
}
trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
**** ***  *     ****   *  *   * * ****  *  * *   a[50],b[50];
*  *   * ** ** ** *  * ** ** ** * * ***    ** * * **  c[51];
**  *   *********   * ** * ***  * ***** **  ***    n1, n2;
 *  *  *** *   ** *   *** * *   *  * *      ** *   i,j;

*  *      ** **    ** **** *   *  **  * * *  *  ** ** 
   *** ** ** ** *  * **    ****** **  *  **   *** *  * ***  *******

   * ***** ****  * *    ** ***  *  ** *  ******  * * * 
       {
** ** ****  ******* *    **  *  *   ** **** * *  **  ***  ** * *  *  *** * ** **          ** * );
* *  ** * ******* *    *  ** *      ** ***   ***

    *   ** *  * **** **     * ****    *****  *   **  *** * **   * 
* ** **** ** * *   **** * * **** *** * *   
** ** **  **   *** *     * *** ** **  * *   * ** *** *** **** *   * **      ***   * **  * * b[i]);
*    *     * * *** *     ***   *  **  *****  **



* *  *   *  ***  * * *  ******** ****  **** **  **      ***      * *  **  
* ** *****  *** **      *   * **** ** **  *     
 ** * *     *  ** * *****     *** * ****  *  ** *  * *** *  **** *  *** * **** 
  *  ***** **     *     *   * **   ****  ** * 
**  * * * *  * * *  **  *  ***   * * *  ******   *  * ** ** **  
 ******    **  ***** **  ** * ***** **   *  ***** * * 
****** *  ***    * * *    *     ** ** ** * * * ** * ** ** * ***  * ** * ***** ** **** ***
*     ***  ******   **   *    * **   *  * ****  *

  *      ** *  * *  * **  *   ******** ***  ** ***
** * *    *      *   * *  **    ***    ***  ** **
  *     ** *  *   * * **  *** *  *** *** ***   *** *  ** *** ***** * **   *    ***  *  *
 *   *   *  **  **    **   * ** * * * **  ** *** *  * ***   ** **   * * * ***   
       }

**     ** ***    **** ** *     * * * * * ****  *     ***   **  
       {
 ***   **** *** * *  ***** **  ***** **    * *  *      * *   ***** *****  **** *** **** *** *    
       }

* **  **   **********      * ***  *** * ** ***     **   
*     *       * *  * ** ** * ****    **  *   * * ** *
  *** *  *** ** *  *  *  *  *  **** ** *    *  *   * *** **** **** ****  *** ******  **  ** *     
** * **  * **    *** *** ** * * ***  ****** * ***   **   * ** *


    return 0;
}
trả lời bởi (-193 điểm)
đã sửa bởi
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
đã bình luận bởi (4.3k điểm)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
đã bình luận bởi (4.3k điểm)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include *** * *      ***
#include **    * ** *** *  
#include  * ***  * ** * 
int main ()
{
**  **     * * * ** * * * *  i,n,m,c=0;
*  * * ** **  *  **  * ****   ** A[60]={0};
 **  ** * *****    **  *** * **   **** *** *
 *  **** * *** *   *   *   * ("%s ***  **** * *
*  * * ****** * *     **   ** * ***  * * *  *  * **  ** *****
  * **  *  *   ***    *** ***  0;
}
trả lời bởi (-32 điểm)
đã sửa bởi
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
đã bình luận bởi (4.3k điểm)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
đã bình luận bởi (4.3k điểm)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
0 thích 0 k thích 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
    *  * ** * *       ** ***       * *  ** *******  *  * *   ***  
    }

   * ** *   **  ***** *       *      *  *****  a);
**** ** ** *** *** ** *** ****  **** *******   * b);

    for(;;) {
***        *    ** ** *  *     *    ******  **  *** * **** ** *   **  **   *   {
 ****   * * *    *    * ****  * ***  ****  * * *   *     * ***    ** *** 
      * **** * *  *  ***   **** *   *        **  * ********     * * *  **
*          *  * * ** * ***   *  * * * **  *  *** ** *** *  ***   * **  * **       *
 * ******  * ********   ***   *** * *   ***** *  ** ** ***
  *     * * ***    ** *   *** *****   **  *  ** *** *  *** * {
  * *     * **   * *** ** **** ***  * *  ** * *** **  *       * ** * * ***  **   *  *
 * * *   **    *    *  *    ***  ****   ** ** ** ***  ** ** *
    }

    for(;;) {
*** *  * * *     **** * * *** * *** ** **  *   ****  *  *** ***** {
  * * **  * * **** * * ** * *   * ***   * * ****     *   *   * * * ***  *  **      *
  ***** * * **  ** **** *****   **  ** *   *** *  ***  *** ** *  *********   * * **   ***  *  *
 * *  * ** *  *** *  ** * **   ***    * ** *      ** * *    *   * *      * *** 
  *  ** *   * ****  * * **** ***  ***  * *    ***** * ***  *   
** * ****     ***       *****        *** **  * *** * * * * * ** **  {
    **  ***** ** * ** * ***   ***  *   * ****     ** ****** * * * *   *****    **
 *   *  *** *** * * *** * * *  ******** *  **** *   * * *
    }

 * ***      *    **** **** *  *  * {
* * **** *** * * * *   *** *  *   *   ** **  * ** ** *** * ** && a[i]<=57) {
 **  *  * * ***  ** *** *        * **     ** **** * **** *  * *  *    *   * *** * * *   * *
* **    * *** ** **   ** ***   *   * **    *   ** * **   
  * **   ** ******* *  **  *  **   * **   *    ** ** *** * * * *  * && b[i]<=57) {
**  **** **   **   * *   **  ** *** *** *  *  * *  *      **** * **   *      *      **  
**** ** *** ***** *** *   **  * *  ****  ** **  *** * *  *
    }

    for(j=50;j>0;j--) {
 * * *      ****  *     *** *    *** *   * *** * * ***  **** *** ****         * {
* * *** ** *  **** *  **** **   * ***  ** * *     ** **   ***  **  *****   *  * * ** ***    
  *  **  *     *  **   ** * * ****** *  **   **    **       *   
 * ****  ** * *  **   *     ***      * *** * *** *****  * * if(sum[j]+a[j]+b[j]==10) {
   *  *  *   * * ****** ***  *** *    * ***  * ***  * *    * * *** **     *** *****  *     ****
 * ***      *   ** * * ** ** ** *  **** *        * *  *   *    * *    * *****   **
  ****** * *  *** *  * *****  * ** ***  *  ** * *  *  * ** * 
**  **   * * *** **   **** * *   **** ****  **** *   * *   if(sum[j]+a[j]+b[j]>10) {
 ****  * * ****   * * ***  *  *****  * * ****  *   * * *   ***   **  ***** **    ***   ** * * * *
  * * ** *** **  * ** *******    *  * *   **** *    * *   * *  * *     ***  ****    ***
 **** **    * ***  ***** ***   ** *    *****      
    }

    for(j=0;j<50;j++) {
  *** ** * *  **  ** *   *****  *   *   * * *  **** * *  * ** *    {
* ** **   **    **  * *** *** *    *      ***  * *** **  **  **  * * * *  *   *  *  * *
*   * * *  *  **     * *** *** *  *   *  **    *
    }

    for(;j<=49;j++) {
**  *   ******* *  ***     **  ** *** *  **** ** **** *  *  *** *   * *  sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
đã bình luận bởi (4.3k điểm)
Trang:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.31
©2016-2026

Những câu hỏi liên quan

1 thích 0 k thích
37 trả lời
Final Exam 5 (20%)
[Exam] đã hỏi ngày 16 tháng 1 năm 2018 trong Final Exam
ID: 42302 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn | 13.4k đã xem
2 thích 0 k thích
31 trả lời
Final Exam 4 (20%)
[Exam] đã hỏi ngày 16 tháng 1 năm 2018 trong Final Exam
ID: 42301 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn | 12.5k đã xem
1 thích 0 k thích
37 trả lời
Final Exam 2 (20%)
[Exam] đã hỏi ngày 16 tháng 1 năm 2018 trong Final Exam
ID: 42299 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn | 14.6k đã xem
2 thích 0 k thích
30 trả lời
Final Exam 1 (20%)
[Exam] đã hỏi ngày 16 tháng 1 năm 2018 trong Final Exam
ID: 42298 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn | 11k đã xem
0 thích 0 k thích
8 trả lời
[Makeup] Final Exam 3 (20%)
[Exam] đã hỏi ngày 19 tháng 1 năm 2018 trong Final Exam
ID: 43461 - Xem được từ: 2018-01-20 09:00 - Hiệu lực đến: Không giới hạn | 2.9k đã xem
12,783 câu hỏi
183,442 trả lời
172,219 bình luận
4,824 thành viên