Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-286 điểm)
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Case 1: Wrong output
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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trả lời bởi (-285 điểm)
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#include<stdio.h>
#include<string.h>

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trả lời bởi (-301 điểm)
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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trả lời bởi (-193 điểm)
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

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* *** * * * ***  ** * *    ****  ** * ** ***  ** *      **    ** ****   *  *    * * ***  
 **** *  ** *****  * *    *  *  * **  * *** **    *    *
*** ** * * *    **  * *  *   **    *  *     **   * ** * {
 ** *  * *  ** **** *  * **  **  *   ** *   **** **   *  ** * * ****  ** ** ***
 *    * *** * *** **  **  **** * * *  * **    
    }

    for(;;) {
  ***  *   *   *** *  * **  *  ** *  **  ** ***** ** *   * * ***   * {
***  **  *  *  * *  * ****    *   *** *****  * *      *    * **   * * * *  * 
 **  *** *  *** *  ****       * ** ******  *    ****    ***   *  **** *   **** *       
* * *** *** *******  * ****  ********  ** **  ** ******  **  ***** * *  *** ** **** *** **   ***   
 ** * * *** ** ****** *   ** *** *  * * *  ** **  * *
** ***     *  * *** * *** ***  *    ***** ** **     *  {
*******   *   ** *  * **       *     ******   ******* ****** *     * ***     ***  
 ****      *** * **      * * ** **   *    **  * *   * *
    }

  **   **  **  * * ****   * *  *   *   ***** * {
  *** ******   *  *   *   * **** *****  ** * *****   * **  && a[i]<=57) {
 *   *  * **  **  * ****   **   ***  *     **       *** ** *  *  *** **   **** ** * ** **
 **  *  **   ***   * * **  **  **        **  ****   *** * 
 *** ** *   * **   * * * **   *****  *  **  **** *  **  ** * **  * ***  && b[i]<=57) {
  *   ** * *****  *  **     ****** *****     ***     *   *             *** *   * ** * 
*********  **  *     * * **   *      * * ** **     *  ****** *** 
    }

    for(j=50;j>0;j--) {
  *  *  **** ******** ********* * * *****    **      * ** *   * * ** *     {
**** *       **  *  ****** *** * **    *      **   *   *    *  * *   * **    *** ** * 
*** **** * ****  ** **  *  *   * ****    **  *   * *   *   
  * ** ** * *  **   * ** **    **       *  ** ****    *  if(sum[j]+a[j]+b[j]==10) {
** * ** *  *  ** * ********  * **       * ****** ** **  *** ** *  *  *** *  *   *** *** *   
  *** ****  *** ***  ** *   **** **  *  ***        ***   *  *   **  **** **  * * ** **** *** *** * *     
  ** *  *  * * ** * *       *  *    * *  **  ** *   **** 
** **    * *** **    ***** ***** **     ***  * * if(sum[j]+a[j]+b[j]>10) {
* * * ** * * * *  *  * *   *  * * *****    *    **** *  *  * **  *   * ** *  ***    *** **  *
    *  * *** *  ** ***   *   **  * ** ******  ** ** ** * ***  *  ** *    ****  
*      *  **  **    ***   *****   ******   * **  *
    }

    for(j=0;j<50;j++) {
 ** ** *   *  *** **  ***** * *  ** ** ****  * ** * *  {
*** *   ***  ** * * ** ***    * * * * ***  **   *  **  *   *  *  *   * *** ******
*   *    *   *** ***    *     ****  ***    *  *  **** ***** 
    }

    for(;j<=49;j++) {
* ***  ****   *    *****     *    * **  * * * *  ***  ****   ******  * **  *    sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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