Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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trả lời bởi (-285 điểm)
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#include<stdio.h>
#include<string.h>

int main()
{
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trả lời bởi (-301 điểm)
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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}
trả lời bởi (-193 điểm)
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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{
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

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 ****  * * *  **   * **    *   * ** **    **********  **    * ** ****** * **  *** ***  ***   
 *****   *   ** **  ** *** **** **  *  *  ***      ** ** 
 * *  * ***  *  *  * *  **    *  *   *  *    * ** ** * {
** ****     * ** * ***  ** *** ** ** * ** * *** ** *  *  **  ** **** * **     *      *  ******
****** *      *  **** *  * * ** *** *  **** *   *   *
    }

    for(;;) {
**  * * ***** * ** * *  ***  * *** ** * ***  **  * * ****  *     *  *  {
* *       * **** ** ** **    *   *   *       * **   * *** *********   * *   **   ****
*******    *  * *   ***   **  * ** * * ** *  ***** **   * ***     *   *    ** ** ** **  
   **      *******       * ** **  ** ** * ***** **** **  * *  ** ** * ** * *** **
  *** *  *** *    ******* *  * ***   * *****    **  *** 
** *   * ** *** * *** **  * * *     *    ***   ********* ** ** {
* **** **  * ** *** **  ***    ** ***   * *   ** **  **  ** ** **   * ***   * * **   ***   * 
* * * *     ***   **** * *  *** ******   * ***  * **  *
    }

   *  ***  **       *** *   ***  ******* {
  *   * *** *** ****** *      * ** *  * ***** *  * * *** * **  && a[i]<=57) {
**** ** ***** **** * **  * ***       * ****   *       *******     *     *   ** *     * *** *
** * * *****  *  ** *  *  ** *   *****   * * * **  *
** * *    **     ** *     ***   *  *** * * *  *  **  *  * && b[i]<=57) {
     *** ****   *      * ****** *  ** * * * ** *  * ****      *  *  *   * *  *** *  **** ** 
 ** * **  *** **    ** * ** * * *** ** **  *** * *** *****
    }

    for(j=50;j>0;j--) {
*      **  **     ** ****   **       *   * ***  **   *      * * *   ***  *   *  {
 **    *  **   **  * * * * ***   ****   ** * *** *  **  **  ** ***  **** ***  * ****   *  **  ***  
  ****   *** * *  *** ***  **** *     *   ***  ***
* ** *    * * *   *** *  ** ********        **** *  * if(sum[j]+a[j]+b[j]==10) {
* *  ** * ***    ** *** *  ** ***  ** **     * ***   ** ** **  *  ******    **  *  **     * 
*  **  ****  * *** * ***   *** * *  *   ** ** *    **   *   *  *    **  * *  ******** *   * ****  *
  **  *  ***** *  **        ** *** * * *   *******  **  
** * *** * *   ******* **** ***  * *  *** **** *****    if(sum[j]+a[j]+b[j]>10) {
* *** **     **** * * **  **    ** *   *  * ***   * * *****    *** ** * ** ***   *    * ********
*  *    **  * * **  * *    *   ****  ** ** ***** *  * ***      * *** ****** ** **    **  *
*  *  ****** * *      * * *   ******  * * ** ** ** ***
    }

    for(j=0;j<50;j++) {
* *   ***     *  ** *****  * *    * * * *   ** ******  * *  **   {
*  *  *   * * ** ***       *    *** **   **  * * * **    *  ** *  * * **** **    *  *** *** 
   ** ** **    ** * **  ***    ** ** *   ******
    }

    for(;j<=49;j++) {
*** *** * *  ****     * **   * * ******* **   ** * *  **  ** *  **  ** sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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