Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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32 Trả lời

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trả lời bởi (-286 điểm)
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trả lời bởi (-32 điểm)
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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trả lời bởi (-285 điểm)
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#include<stdio.h>
#include<string.h>

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trả lời bởi (-301 điểm)
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0 0
Case 0: Correct output
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
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trả lời bởi (-193 điểm)
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0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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{
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

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  *     *********  ***  **  *   * ***** * *  * * ** ** *   *  * *** * *****   *  **  **
** * ***  *****  **   *    ****   *       *   *   * *    *  *********   * ****   *  * 
**   ** * *    **  * *     ***  * *****   **    *       
* **** * ** *   **  ** * * * ****   *  *   **   * ***    ** ***  {
   ***** * * *** **  *  * * *  *   *  *  * ** *   * * *   *   ****     **  *  *  ****
 **** * * ****  **** ****** ** ** * ***    ** * *   **  *    **
    }

    for(;;) {
**   **  **** **  *  ** ****  *   ** *** * *  *    *  *  * * ****** * ****** ** {
**  *  ** *** * *  *  *    ***     *** * * *   *  * **   *     ** * * *  *        ** ****
*    **       * * * ****   * **  * * *  * *** **    * **    **   **  *   * ** ****** * *
     *  **  ****   *** ** **   * **   **** * **     *    *** **  *   *    *   *   **  **
* **  *  ********       *  * *******  **** ** *** * 
* *** **  ****  * ** *   **  *******   **** * *   ** *  {
  ***** **** * **    *   *****  *    *     ** **** ** **** *** *** * *  ********  * 
** ******   **    * **  *** ***     * *** *******   *
    }

 *   *   ***  *   *      ****      *** {
 ** *         *   *   ** **   ***  ****     ******  ********  *  ** && a[i]<=57) {
*   *** **   * *  *  * *  *  ** **  *** *  * **  *** ***** *** *******    * *  *    *  
**  *  ** * *  ** ******** * *   ** ** *  * * *  *
 *** *****  * *  *     * **** * ***** **    ***** ***** * ** *  * && b[i]<=57) {
*  * ***      *      *  ***  ** ** *** *** * *****  * **** **   **     ** * * * ****  *  *** 
   ** *    ***  ***  **   **** *   ** * **** ***
    }

    for(j=50;j>0;j--) {
 *  *  * * * * *        ***  ***   *   ** **** * *   **  *   *  ** * * * {
*** **         *** ** * ** *** ***     *    *  *   *   **  ****  * *  *******       **  **  * *    ** 
 *****    * * *** **   ** *** * ********   *    * * ** * *
*  *      * * *      ** ** ** ***  ** * **   **     * * * if(sum[j]+a[j]+b[j]==10) {
* ** *  *     * ** ** ** *   ***  *** *  ** **  ** ****  ****  *   *  *** *  **  *  *  **   **  ** **
  *****     ** **  ***     * ******   ** *  *  *    *  **    *     ***   * * * * * *  * * ** ***  
   * *** * *   ***  * * **  ** ******* **  **  * * 
  ** * * * *  *  ****      *    *  * *  *     *  * *    *   if(sum[j]+a[j]+b[j]>10) {
*   * ** * ****    * ** * * *** *******     * * *    **** ** ***   ** *  * * **  * **     ** * * **  * ****    *
** * ** ***   * * * ***       *   ****  * ***      * * * ** * *     * ** *  * **  **  **    
***  ** *** * *    ** *   * * *** *   *  * * * *  *****  
    }

    for(j=0;j<50;j++) {
**       *   * *** ** * *   *  *** ***  *  * *********  *  {
* ** ****   * * *    *  * **** * * *   ***  *  **     * *     **  **  *** *  *      *  **   
* *  * *** **    *   ** ** **   *   **  *** **  *** * *
    }

    for(;j<=49;j++) {
* *******  **   *  ***   *     **     ** * *** *   **** * **  * *** *  *  ** sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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