Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-32 điểm)
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Case 1: Wrong output
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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đã bình luận bởi (4.3k điểm)
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đã bình luận bởi (4.3k điểm)
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trả lời bởi (-285 điểm)
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#include<string.h>

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trả lời bởi (-301 điểm)
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdlib.h>
#include <string.h>
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trả lời bởi (-193 điểm)
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0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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int main ()
{
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
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    for(;;) {
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 * **** * ***  * ****** *       **** *** ** ***** *  * * ***   * **   **** *  ** *****  *  *** *
* * ********** ***   **     ******   * ******    *  * *  **  ** *  ** *  **    
*  * * *  *   ************    *  ***  *  **  ** ** * ****   * *   ***   ***  * 
* ****  * *  ***   * ***  *  * *****  *   ** * * * *  
 *  * *    * *  *   *  * *   * **  *   ***    **  *** **** ***        {
 *** * *   **  *** * *     * ****   * ** **** ** * * ** *      ** *    *  
* *  *******  **  *    * * *** *** *   *  *  *
    }

    for(;;) {
 * *  *      **** ***** *** *****   ****  * ** *  ****** ****** *  {
* **** *** ********** ***    * ***      ***  ** ***    * * * * ** ** * *     * * * ** ******* *  
   **   *  *   *  ***  * * **    * * **     * *   ** *********   ** * ** ** **    * *  *    
**  ***  ****  * * **  * *  **** **  ****   **    ** *  * *** *   **     **** * **
 ***** **  *       *      * * *   * **   ******  ** *****  *
*  ****   * *    *   *  ** * **   * ** *   ** *  ***  **   *   * *** {
*  ****  * * *   ****   ***** ** **  ** ** ****** ** *    ** *******     *** * *       **** 
* ********      *******  * *   *  * **  *** * 
    }

   * ****      ****  *  ***** ***   * *    {
    * * * *  ***    ** * **   ****    * **  * * *** **   * *  *** * && a[i]<=57) {
*  *     ***  **** *  **** * ***  * * *    *   * * * * *** *  * * ***   *  *** *** **    
**** *  *   *  *  **   * **   ** ** *  ** * * 
   **  **  **  **  ***  * **  ***  **  *  ******* *** * *  **   *  ** && b[i]<=57) {
 *  ***  ** *  *  * *  **  *  * *  *** *       * * **  * *    *  * ****   ***   ***    ** 
*  *   * ** *****  **    ** *   *   * * *   **  *** * *   
    }

    for(j=50;j>0;j--) {
 ** * * *** *  *****  * *   * *  ** *       *****  *  *** * * ** * ** *   * {
* * *      *  ***    * *  *** ***** ****   * **  *       ** *    * ***** *   ****    ***
 *  * ***  * ** *** ** ***** **** * ** *  **** *  * * 
 * **    ** * **   *** * * *  * *   **  *** ** ******** if(sum[j]+a[j]+b[j]==10) {
*****    ** ***   *  *      ** ****  **   *   ** * * *       ***** ** *  ***
 * *   *   *   * * *   *   **  ***           *   * *  *  * **   * * ** * *  ****   * *   *     ***  
*   * **  ** **** * **     ***   **   *  **
*  ***  ***   ** ** *   *** **  *     ******* **** ***  if(sum[j]+a[j]+b[j]>10) {
   **  ****** *** * * *  *   *  **   ***    * * **  *** ***       *  ** ** **  *  ***********
  *****  ** * ** *       **  *  *** *  *  ****  ** ****    * * ** **  *** ** ** ** **  *  **  ** * 
   *  *   *  *   * ***        *   * * **      *   ****
    }

    for(j=0;j<50;j++) {
 ** ** *  * *   *       ** * *** *   **** **  ** *** *****  * ** {
*** * *  **   **   *   * *** *  *  *   * *****  ****   **  **   * ** *    ****  * * *   * 
* ** * ****  ***  * ***     *  **** **** * * * * *   **  *     
    }

    for(;j<=49;j++) {
 **  **  **  * *****    **  ****  * ** * **  *  **  *   ** *****  *  sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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