1 like 0 dislike
18.7k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 18.7k views

32 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * *** ** *
#include * * ****
char a[100],sum[200],space,i;
int main()
{
*** * ** * * * **** * * * ***

* * * * *** * ** * * * * ** * * *
**** * * *** * **** * * * ** ** ** * * *** * '){space=i;}
*** * ** * ** **** * *

** * ** *** *** **** * *** ** *** *
* * * ** ** ** ** * * * *** ** * * ** ***** ** **
*** ** * ** *


* * **** *** * ******** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
*** * *** * * ** **
** * * ** * **
* * ** ** * **** **
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
****** * ***** *** **** * num1[51],num2[51];
**** * **** ** *** * * i,m;
** ** ** *** * ** * * arr[51]={0};
* * ****** ***** * ** * *
*** * * **** * **** * * * * * ** * %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
*** ** ** ** *** ** ***** ** * *** ** * * **** ** * ** ** * ***** *
    }
* * ** * ** * **** (i=0;i<(strlen(num2));i++)
* * * ******* * ****** ****
** ** * **** * **** * ** ** *** * **** * * * * ** * **** * *** *
** ** * * ** * * * * *
** * ******** ** * ***** * (i=0;i<=50;i++)
** * ******** * ******
***** * * *** * *** ** ****** *** * **** ** * **** ****
*** ***** ********* * ** ** * ** * * *** *
* ** * *** *** * *** ** **** *** ** * ** ** **** * * *** * * * **** *
* ** *** * * ** * *** *** * * **** ** * * * * *** * ** ** * * *
* ******** * * * * * ******** **** * *
    }
* * * ** * *** * * ** * ** **
    {
* ****** *** * ** ** * ** * * ** ** *
** ******* **** * ** * * *** *** **** * *
* * * ** *** *** ********** **** * * **** *** ** **** *** ***** * * ** * ** *
* *** * * **** ** **** * * ** **** *
** * ** ** *** *** *** * * * *** *** ** * **** ** *
** * * ** ** ******* ** * *** * **
**** * * ** * ** ***** ** ** * ** ** * * **** *** * * * * ** ***** *
* * * * * **** * *** **** **** ** * * **** ** * * ** * ** ** ***** * * * * * * ** ** *
** * * * * * **** * *** * * ** ** *** ** *
    }
** * * ** * * ***** *** * * 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
* *** ******* ** * * *** a[n],b[n];
*** ** ** * * ** ***** ** ** * * * * **
* ****** ** *** ** * *** * * l1,l2;
* * * * **** ** * * i=0;
* * * ***** * ** ** * * *****
** * * * ** ***** * ** *** ***
** **** * ** *** ** ** *** * * * ** *
* * ******* ** * ** * ** ** *** **** *
** ** * *** ***** * *** *** ** * * * *



* **** ** * ** * **** * * ** * ** ** ** **** * * ** * ** * * ** ** ** *** * ***** ** * ****





*** *** * ******** ***** ** *** ***** ** ** * * *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
* **** ** * ** ** ****** * ** a[50];

** **** * * * * b[50];

* *** *** * * ** ***** * c[51] = {0};

** * ****** * ** * *** * ** ** a, b);

* ** * **** ** * ** i = 0;

**** ** * *** * *** len_a = strlen(a);

* *** *** ***** ** ****** len_b = strlen(b);

** * * * ***** * ** ** * = 0; i < len_a; i++)
** **** * * ***** * ** *
** ** *** * *** * * * * ** ** ** ** ** ***** = a[len_a - i - 1] - '0';
***** * ***** * * *
*** * * **** * * * * * ** * = 0; i < len_b; i++)
*** * * * *** * ** *
*** * * * * * * * * ** * * * *** += b[len_b - i - 1] - '0';
*** * * * * * ****

** * ** * ** ** ** ** = 0; i < 51; i++)
******* ***** ** *** * *
* *** * * **** ** * * * * * ** * ** ** > 9)
* * ** ** ** * ** *** **** * * * ***** * *
* ** ** ** *** ** * ** ** * * ** **** ** * ** ** * * * * * * ** * * + 1]++;

* *** * *** **** ** * * ** * ** *** * *** ** *** * ** ** ****** ****** ** %= 10;
** ** *** **** * ** * *** * ******
**** * * * ** * * **

**** ** * *** * * * nonzero = 0;

* *** **** *********** ** ** * = 50; i > -1; i--)
*** * * * ** * *
* * ** * ** ****** ** * * ******* ** * * * * != 0)
** * * * ** * ** * * * * * ** *** * * ** ** * *
** * ****** ***** * ** * * * * * * ***** * * * * ** ** * * * * ** * **** = i;

*** * * ** ** *** * * * * ** * * **** *** * *** * ** ** ****
** * * ** * * * * * ** * ** * **** **
    }

* * * * * *** * ** ** * * = nonzero; i > -1; i--)
* *** ** *** *****
* * * ** * ** *** * ** *** **** *** * * ***** * * * **** *** **** * * c[i]);
* ** * * *** * *
* * * *** * **** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

**** * * * * * ** ** * ** * * ** ** * * *
    for(i=0;i<strlen(a);i++)
** ** * * * * *** ***** *** *** * * * * ** *
* * * *** * ** ****** ** * *** ****** * *** * * **** **** ** ** * ******
* ** * *** **** * * * ** * * *
    for(i=0;i<strlen(b);i++)
** * * * * *** * ** ** ** * ** * * ** **
******** * * ** * ***** ** ***** * ** * * ******** ** * ** * ***** *** * *
* * * ***** * * **** * * * * * * * **** *
    for(i=0;i<50;i++)
* * * * ** * ** *** *** * ** * * ** *** **
** * ** * **** * * ** **** *** * **** * ** * * * ** * ** ** * > 9)
* **** * * ****** *** ***** * ** *** * ** * *** * **** **** * ** * * * ** * * ** * **
* ** ** ** ** * * ** ** *** ** * * * ** * * ** ******** * * ** * * *** * ** ** ** * * * **** * ****** * * ** ** **
*** *** * * * * * * ****** *** * ***** * ** *** ** * * **** * * ** ** * * ** **** * * * * * *** *
* ** * ** ** * * ** * **** ** ** ****** **** ** * **** *** ** ** ** * * * ** ** * * **
* * * * * ** * ** ** ** * * *** * ** * ***
    for(e=51;e>0;e--)
*** * ** *** * ** * ** ** ** * ***
******** *** ** ** ** * * ***** *** ** *** *** * * ** * * ** ** ****** *** != 0)
* * *** **** * ***** * * **** ******** ** ** *** * * ** * * *** *** * * * * ***
* ** * ** ***** * * * * ** ******* ** *** * ** * *** * * ****** ** ** * * ******* ** * * ** ** * ******
* *** ** ***** ** ****** **** * *** *** ** * ** * ****** * * * ** * * * *** * * **** * **** * * ** * ***
** * **** ** ***** * * * ** * * * ** **** * * * *** ** ***** ** * ** *** ** * *** *
* *** * * **** * ** * * * * * * **
* ** ** * * * * ** ** * ** ** * ** ** * ** * * ** *** ***
    for(i=begin;i>=0;i--)
* * ** * * ** * **** * ****** *** * *
* * * * ** ** *** * ** ** * * *** * *** *** * * * * * * * * * * **** * * * **
*** * **** * *** * *** * ** *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * **** * * ** * * i,j,k,l;
** * * * * ** ** **** a[100];
* * * * * * ** ** b[100];
* * * **** ** * * * * * * ** * *** *
* *** * * ** * *** ** * * * ** ** * && * * ** *** ** *
* * * * ** * * ** *****
* ***** * ** * * * **** * **** ** * *** * * * *** ** *
**** ** **** *** * ***
**** * * * * ** ** ** * 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
* ** * ******* * *** *** * * * ***** *** ** a[50],b[50];
* * * * *** ***** ** *** ** * c[51];
* ** * ** ***** ** * * * * * * * * ** * ** n1, n2;
******* ** *** * ****** * * *** ***** ** i,j;

* * ****** * ** * ****** *** * ******* **
* ** * ** *** * **** * **** **** * * *** * * **

* *** * * *** * * * * ** *** * * ****** ** *** ** *
       {
* * ** * *** * * *** **** * * ** * * *** * *** * *** ** ** * ** ** * * );
** **** **** * * * ** * *** * ** ***** **

**** * * * **** ** * * ** * *** ** **
* ** ***** * *** ** * ** * * * * ** ***
**** * * ** * * ******* * * * ** ****** * * ** * * * * **** *** * * b[i]);
**** ** * ** * **** * * * **** **



****** * ** ** *** **** *** * * * * * * * * *
**** * * * **** ** * * ** * *
* ***** ** *** * * * ** * *** ** ** * ******* ** * ** ***
*** * * ** ** * ** * * * ** ** *
* ** *** ** ** * ***** ** * * * * **** ** ** **
* * * **** * ** *** * ** **** **
***** *** * *** * *** ***** * * ** ** * * * ***** * *
* * * * *** * **** * ** ****** *** *

* * ** * * ** * * * ** * * ** * ***** * ** *****
* * * **** ** * ** *** ** *
* ******** ** ** ** * ** * **** ** * ** ** *** * ** *** ** **
**** ** ** **** ** ** *** ** * ** ** **** ** * ** *
       }

* ** ** ** *** ***** ** ****** *** *********** * *
       {
* * * * * ** ** ***** * * ** ** **** ** ** * **** ** * * * * **** * * *
       }

* ** * *** ** *** * *** ** **** * *** * * *** **
** ** *** * * * *** ** * * * * ***
**** * * * ** * * ** * * ** *** * ** * ** * *** * * * * *** * ** **** ** * *** **
** **** *** * ** *** * ** * * *


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
0 like 0 dislike
Hidden content!
#include * ** ** * * *
#include ********
#include ** * ** ** *
int main ()
{
** *** * * ** * * ** ** i,n,m,c=0;
** **** * * ** ****** A[60]={0};
*** * ** ** ** * * * ** * *** *
* *** * * * ****** ** *** * ("%s **** * **
** *** * ** * *** *** ******* * * ** * ** ** **
* ***** * ** * ** ** 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
* * * * * * **** * ** * * * *** ** ** * ***
    }

* *** ****** * * * * *** a);
** *** ** * * ** * * **** * * * *** ** b);

    for(;;) {
***** **** **** * *** ** *** ***** ** * **** ** * ** ** *** * {
** *** * * ** **** * * * *** ** * ** * * ** * ****** * *
**** * * * * ** ** * * * * *** ** * **** ** * *** * ** * * *** * * * *
* *** ** * * *** * * *** ** ***** * * * **** * * ** * *** ** ** *
*** *** ** * *** ** *** **** * * **
** * ** * ** ***** * * ** * **** * *** *** * * * {
*** * * ** * ***** ***** *** ** ****** ****** * ** * * * ***** *
** * * ******** * ***** ******* **** ** * **
    }

    for(;;) {
* * * * * * ** * * * * * ******** *** * * * ** *** * {
* * * * ** ****** * * ** ** * ** * * * * ** * *** *** ** **** * *
** * *** ** ** *** * * * ***** * ** ** * * * ** ** *** * ** *** * **
** * *** * **** ** * * * * ** * *** **** *** *** * ** * * * ***** * * *
* *** *** * ** **** * *** * * * * * * **
* **** ** * * * * **** *** * ** * * **** ** ** * *** ** {
* * ** *** * * ** **** *** * * **** *** *** *** *** * ** ** ** *** * ** * *
**** ** ** * * * ** ** ** ** * **** *****
    }

*** * * * * ** ** * *** * * ****** {
** * ****** * ** **** ** * ** ** * * * ** * && a[i]<=57) {
** **** **** ** * *** **** * * * * * ** * ****** * ** * * *** * * * *
* * * * ** * * * ** * ********* ** *** ** * * * *
*** ** * ** ** *** *** ******* ******* * * ** * *** * && b[i]<=57) {
* ****** * *** * ******* * **** *** * * **** * * ****** * *
* * * * *** ** * *** * *** ** **** ***
    }

    for(j=50;j>0;j--) {
* * ** ** * **** ** * ** *** ***** ** **** ** * ***** ** ***** {
********** ***** * * * * * ***** * * * * ***** * ** *** * ** * ** * ***** * * ***
***** *** * * ** * ** * * * *** ** * * **
**** *** * * * ** ** * ** * if(sum[j]+a[j]+b[j]==10) {
* *** *** ** ** *** * ** *** * ** *** * * * ***** * * * **** * *** **
** * * * * ** ** **** * ** * ** * ****** * * * *** * * * * ** * * * * * * **
** * **** ** ** ***** ***** * ** ** * **
*** * * * ** ** ** **** * * ***** ** * * * ** if(sum[j]+a[j]+b[j]>10) {
** * ** * ** ***** * * ***** ** ** * ** ** **** * ** * ** * **** * ****
* *** **** ************ * **** * ** **** * * ** ****** ** *** **** *
*** ** ** * * ***** *** **** ** ** * *** * **
    }

    for(j=0;j<50;j++) {
**** ** * **** ***** ** * * *** ** ** *** ** {
* *** ** * * * * * ** * * ** ** ***** * * * * ** *** ******
* * * ***** * ** ** ***** **** ** * ***
    }

    for(;j<=49;j++) {
* *** * * * * * ** * *** ***** * * * * * * ******** sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 17.3k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users