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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 18.1k views

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Hidden content!
#include <stdio.h>

int main(){
* * * * * *** ******** *** str[500];
** ** *** ** ****** * * * * * * sizeof(str), stdin);
** **** ** ** *** *** * ** i=0;
** * * * * **** *** * * ** d=0,a=0,o=0;
** **** ***** ******* * * **
*** * ** * * *** **** ** **** ** *** * ** * * * *** **** *** * d++;
** *** * ** * *** * *** ** ** ** * **** * * ** * * ********* **** * * ** * *** * * * **** *** * * a++;
** * * ** ** **** * * * * ***** ********* * ******* * o++;
* *** * * * ** * * * * * ** * ** **** *** ***** * *
    }

* **** ** * ** ** * ** * * *** *** * ***** *** *

** *** * * **** ******* * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
*** *** ** **** ** * ** * * str[500];
* *** ** * * **** * ** * ** sizeof(str), stdin);
* ** ** *** * ** ** * * ** i=0;
*** ** ***** * * * * * d=0,a=0,o=0;
* * ** * * ** ** * ******
* ** ** * ** * * * ** ** * ** ** * ** *** * * ** * ** ** * * * ** *** d++;
* * * *** * *** * *** **** * * **** *** ** * * * ** ** * ** *** * ** ** * * * ** * * * * *** *** a++;
* * *** **** ** * * ****** ** *** **** o++;
* * * ** * ** * ** * * * ** * * **** ****
    }

* ** * **** * * **** ** ** ** ***** * ** ** * * // remove enter count

* ** * * ** *** ** *** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** *** ** * **
#include **** ** ***

int main()
{
** * **** * ** **** * ****** A[1000];
** * * * * i, digit=0, ** ** ** other=0;
* **** ** *** ** * * ***** * 1000, stdin);

*** * ***** * ** * ** **** * * ******* i++)
* ** ****** * * **
** * *** ******* ** ******* **** *** * ** * * >= '0' **** * A[i] <= '9')
*** *** * * * * *** * * *** * ** ************** * ** **** * = digit + 1;
*** **** ** ** * * ** * * * * ********* ** ** if((A[i] >= 65 ****** A[i] <= 90) || (A[i] >= 97 * **** A[i] <= 122))
** ***** *** ****** *** **** **** **** ** **** * * * ***** ** * *** = alphabet + 1;
* ** * * * ** ** * *** *** * * ** *** if(A[i] > 31)
* * * *** ** **** ****** * ** ** * * ** *** ****** * ** * * ** **** = other +1;
**** **** *** ** * ***** *

****** *** * * * ** **** * * **** * *** * ** * digit);
**** * *** * ***** * *** * * * * alphabet);
* * * * **** * ***** * * ** * ** ** *** * * other);

**** * ** ** * * ** *** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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