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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
** *** * * * ** ** * ***** str[500];
* *** * * *** * * *** sizeof(str), stdin);
* * *** * * * * * * ***** i=0;
**** ****** * * d=0,a=0,o=0;
* ** ** ******** * ** ** **
* * ** ** * ** ** * * *** ** ** ** **** * * *** * * * * ** ** ** * d++;
** ** ** ** * * ***** ** * * ***** * ** ****** ** *** ****** ** * * ***** * * ** * * * ** * ** * * a++;
**** *** * * * ** *** * * **** ** ** * ** * o++;
* * *** * * ** ** * ** * ** * *
    }

* ** * * ** * *** ** **** **** * **** * * ******

* *** * *** * *** * *** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** *** * * * * str[500];
* * * * ** * * sizeof(str), stdin);
** ** * ** * * * i=0;
******** * *** *** ** * * ** d=0,a=0,o=0;
** * *** ***** ** **
*** ** * ***** *** *** * ** *** * * * * ***** *** * **** * * * *** ** * * ** d++;
** **** *** * * ** ** *** *** ** * * ***** *** ** *** * * **** **** * *** ** ***** * ***** ******* * * ** *** ****** * a++;
** * ***** * ******* * ***** *** ** * ** ** *** o++;
* * * ****** * * * * * * * *** * * ** ** * *
    }

** ******* * *** * ** * * * *** * * *** * * ** // remove enter count

*** * * * *** * **** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** ***** * ***
#include *** * * ** **

int main()
{
*** * * * ** * ** **** * A[1000];
* ** ** * * i, digit=0, * ** other=0;
******* ** * ** * ** 1000, stdin);

* ** * *** * ***** * ** * *** * * *** i++)
* * ** *** ** ** * *
***** ******* ** * * * * *** * ***** ** * >= '0' * ** * A[i] <= '9')
* * ** ** ****** * * * * *** ** * ** * ** * *** ****** * = digit + 1;
*** * * * * *** * * * * * * ** ** * if((A[i] >= 65 **** ** A[i] <= 90) || (A[i] >= 97 ** *** *** * A[i] <= 122))
***** **** * ** * ** *** * ** * * * * * ** *** **** ** = alphabet + 1;
* * *** * * * * * *** ***** *** ** * * if(A[i] > 31)
*** ** * * ** * *** * * *** ** **** * * * ** **** **** * * **** = other +1;
* * ****** *** ***** *

* * ** * ** * ***** ** ******** * * * * *** digit);
* * * * ** ** *** * * ** * * * * ** * *** ** * * **** alphabet);
* ***** *** * * ** * *** * ** ** *** other);

***** ** **** *** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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