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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* ** **** * * * ** str[500];
* * *** ** * ** **** * * * sizeof(str), stdin);
***** ** ** * ** * **** i=0;
* ** **** * **** ** d=0,a=0,o=0;
**** ** ** * *** * ** *****
** * * ******* ** ***** * ****** *** * * * ** * * * ** * * * *** ***** * ** * * * * d++;
* *** ** ***** * * ***** * ** *** *** * * ** * ** ** ** *** ** * * **** ** * ** * * ** * * *** *** * * * * ** a++;
* ** * ** * * ****** * ****** ** ** ** * ** *** o++;
*** ** * * **** **** * * *** * * *
    }

** * ** **** *** ** ** * *** *** * *** ** ** * *** *

* * * **** **** * ***** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * *** * * ** * * ** * *** str[500];
* ** *** * ** * * * * sizeof(str), stdin);
* * *** * * * ** * **** i=0;
* * ** *** * ******** d=0,a=0,o=0;
* *** * * * * * ** * * *** **
** * ** ** ** ** * * * ****** ** *** ** * ***** * * * ** ***** ** ** * * * *** d++;
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* * * * ** * ** * * *** * * **** * * * o++;
*** ** * ** ******* ******* ** ** ** **
    }

* * ** * ** ****** * *** * ** * * *** * * ** * ** ** // remove enter count

** ** * ** * **** ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * * *
#include *** *** ** ***

int main()
{
* * ** * * * **** **** A[1000];
* * *** *** ** * * i, digit=0, * **** * other=0;
** * ** *** *** 1000, stdin);

*** * * * ** * *** * * * * ** * * i++)
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**** *** * * ** *** **** *** *** * * * * **** * *** ** >= '0' * ** * * A[i] <= '9')
*** * **** * * ** * ** * ** * * * ** * * ** ****** * *** ** = digit + 1;
* * ** * ******** * *** * ** * ** * *** * ** ** ** * if((A[i] >= 65 * * ** * * A[i] <= 90) || (A[i] >= 97 * *** * A[i] <= 122))
**** * * ***** * * *** ** ** ** *** * *** * ** **** *** ** *** ** ***** = alphabet + 1;
* * * * * * * * ** * ****** *** * * *** *** ** if(A[i] > 31)
* * ** **** *** ******** * ** ****** *** * * *** *** ** * ** = other +1;
**** * * * * * * *

**** ** ** * * * *** ** * * * * * * * * digit);
******** ***** ** ** ** * * * * ****** **** alphabet);
*** * ** * * ** * ** **** * other);

* * * ** ** *** * ** * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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