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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 16.4k views

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#include <stdio.h>

int main(){
** ** ** ** * ** * ** str[500];
** * *** ******** * * sizeof(str), stdin);
* ***** * * *** i=0;
** ** ** * *** *** d=0,a=0,o=0;
* *** * ** * ******* * ** * * ******
* * *** * *** * * ** *** **** * ** * **** *** *** ** ***** * ** *** *** d++;
** *** * ** ** * * **** ** * *** *** ** ** **** * ** * * **** * * * * * ****** ** *** * *** ** ** ** * ** *** * a++;
* * * * ** ** *** ** ***** ********* * *** ** * o++;
*** ** ** * *** ** * * *** **** ** *** *
    }

* * **** ** **** * ***** ** * * ******* ***** * * **** * *

* **** *** ** * ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** * * ** * * * * * * * str[500];
** * ** ** * ** * *** ** sizeof(str), stdin);
* * * * * * *** *** ** i=0;
*** * * *** ** * *** *** d=0,a=0,o=0;
* * * * * ***** ** * * **** *
* ********** ** * * ** * ** *** ** * ** * ***** ** **** * ** * **** ** d++;
*** *** * * ** * ** **** * * * * * ** ******* ** **** * * * *** * ** * * *** * ** * ** * * * * a++;
*** *** * * * * * ** * * * *** *** * * *** o++;
*** *** * *** ** * * * ** ***** * **** * **** * *
    }

*** *** * ** * *** * ** * ** * ** *** * * *** ** ***** * ****** * // remove enter count

* ** * * ** ** * * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** ** * **
#include * * ** * * ** *

int main()
{
* ** * **** ** * ****** * A[1000];
** * ** * ** ** **** *** ** i, digit=0, ** *** * other=0;
* ******* * * ***** * * 1000, stdin);

* **** * ** * * * ** ** * ****** i++)
* ** ** * * ******
** * * ** * ** * *** * ** * * ***** * >= '0' * ** A[i] <= '9')
* * ** * *** * ** *** * * *** * * ** * **** * * * *** * ** = digit + 1;
* * * ** ***** * ***** *** ** *** ** * * * * if((A[i] >= 65 ** ** * A[i] <= 90) || (A[i] >= 97 * * ** *** * A[i] <= 122))
****** *** ********* *** * * *** * ******** *** * * * * * *** ** ** = alphabet + 1;
* * * * ** ** **** *** ** * ** * ** * * * if(A[i] > 31)
**** * * * ** *** * * ********* * * * ** * ** ** ** * ** *** * *** * = other +1;
** ** ** ** *

* * ** ** ********** * *** *** * * ** *** digit);
*** ** ** * * * **** * ** * * ** alphabet);
* * * ******* ** ** *** * ** * * other);

* * * ** *** ** *** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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