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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 9.7k views

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Hidden content!
#include <stdio.h>

int main(){
* *** * * * * ***** * str[500];
***** * * * *** * ** ***** ** sizeof(str), stdin);
* * ** *** * * * * * i=0;
* * *** *** ** * ** * * ** d=0,a=0,o=0;
* * * * * ** ****** * * *
* *** ** * * *** * ** ** * ** * * ** ** ***** * * *** * * * * d++;
* ** * * * *** * ** ** * *** * * **** ***** * ** * * * * ** * **** * ***** ** * ** * *** * * ** * *** *** * ** a++;
* * **** * ****** * * * * * ** **** * o++;
*** ** *** ** * * **** ** * * **** ** ** ** ** ** *
    }

* *** *** * ** * ** ** * *** ***** * ** ** * * * * ****

**** * * ***** * * *** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* ** * * * * * ** * * * str[500];
* ** ** *** * ** *** *** sizeof(str), stdin);
* ** * *** ** * * * i=0;
**** * ** ** ***** * ** * d=0,a=0,o=0;
* * ** ** * * *** * * ***
** * ** **** *** * * * * ** * ** * ** **** * * ** ********* * * d++;
* * ***** ** **** * * ****** * * * ** **** * *** * * **** ******* * * * * ** * ** * * * *** * * * * * a++;
*** ** * * * * ** * ** * ****** * * ** o++;
*** * * * ** *** ** * * * * * * * * * * **** **
    }

* * * **** *** **** ** ****** * *** *** *** *** ** ** ******* // remove enter count

* ** * **** * * * * * * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * ** * * ** ***
#include * ***** ** * *

int main()
{
* * *** * * *** * * * ** * A[1000];
***** ** * * ** * i, digit=0, * *** other=0;
* ****** ** * * ** * * * 1000, stdin);

* * ** * * * * ** **** * *** * i++)
* **** *** ** * ***** **
** *** ** ** *** ** *** * ** ** ** ** * >= '0' ** *** A[i] <= '9')
**** ** *** * ** ** *** *** ** * **** * ** * ** * ** *** * * ** ** = digit + 1;
* * * ** ** * * * * ** * *** *** if((A[i] >= 65 ** * * * A[i] <= 90) || (A[i] >= 97 * ** ** A[i] <= 122))
* * ******** * * *** * ** * * *** *** * * * * * * *** ** = alphabet + 1;
**** * * * * ** ** * ** * * * * * * * * if(A[i] > 31)
**** *** **** ****** * ** * **** * *** ** ** ** * * ** ** *** = other +1;
***** ** * ** * ***** *

* ** ****** *** ** ** ** * * ** *** *** * * digit);
* ** **** * * * * ** ** *** * ** ** ** alphabet);
* **** * ** * **** * * * ** *** other);

**** * ******** * ** * ** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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