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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* *** *** * *** * * str[500];
*** **** * * * * *** ** * * sizeof(str), stdin);
* * * *** ** ** ** ***** i=0;
* ** *** ** *** * d=0,a=0,o=0;
* *** *** *** *** * ** ** ** *
* **** * ** * * * ** ** ***** * ** * * **** * *** * ** ** * * * ** d++;
*** * ** * * * *** * * * *** ** * ** * ** ** * * * ** **** * ** ***** * * *** * ** *** ******** *** a++;
* *** * * *** * ** * * * * ***** * *** ******* ** o++;
***** * * **** * * ** * * ** * * ** **
    }

*** * *** * ** * * * ********** *** *** * ******** * *******

**** * ** * * ** ** ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* *** *** ***** ** * *** * * str[500];
* ** *** **** ** * ** **** ** sizeof(str), stdin);
* ** * *** * * * *** * i=0;
* *** *** *** d=0,a=0,o=0;
* * * ** * ** ** * *****
* **** *** ** ***** ** ** * * *** ** * * * ** ** ** ** * * * ** * d++;
* * ** **** * *** ** * ** * * ** ****** *** *** *** * ****** * * ** ** ** * ** ***** * ** * * * * * *** **** * a++;
** ** * ** * * * ***** *** ** ** * o++;
* * * ***** * * ** * ** * ** * *********
    }

** ** * *** * * *** *** * ** *** * * ** * ** * * *** // remove enter count

* * **** * *** * * ** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ***** * ** ***
#include * ** * ** *

int main()
{
***** *** * ** * ** A[1000];
*** ** * *** * ** i, digit=0, ** * other=0;
* * * * * ** ***** **** * **** 1000, stdin);

*** * * *** ** **** ****** * * * i++)
** **** * ** * **** *
* * ** ** *** * * ** * * * *** ***** ** * * * ** >= '0' * ** * * A[i] <= '9')
*** ** * * ******* **** **** * * * ** ** * *** ** * ** * * ** = digit + 1;
* **** *** ** ****** * *** ** ***** **** *** ** if((A[i] >= 65 **** * ***** A[i] <= 90) || (A[i] >= 97 *** * A[i] <= 122))
* * *** ** ****** * ** ** ** ** * * ** ** ** **** *** * *** * * **** = alphabet + 1;
** ******* *** * ** * ** * * * ******* * ** * * if(A[i] > 31)
** ** **** * * ***** **** *** * * * ******** ***** ****** * * = other +1;
*** *** * ** ** * ** *

* * * ***** ** * * ** *** * * ** ** ** * digit);
* *** *** ** * * * * *** ** * * ** ** *** * alphabet);
* * * * **** ***** ** * * ** *** *** * * * * other);

**** *** *** * * ** 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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