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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* *** ** * ** **** * *** str[500];
*** ** ** ** * * ******* * *** sizeof(str), stdin);
*** *** * ******** ** ** ** i=0;
*** ** *** ** *** d=0,a=0,o=0;
* ** * *** * ** * *** * *
** * * ** *** * * ***** * **** * * * * * * ** * * ** * * * * ** * d++;
*** * ****** * * ** ** * * * * * ** ** ** * * ** * * ******* * ** ** ***** ** * * * *** a++;
** * *** * * ** *** ** * *** * ** **** * o++;
** * ****** *** * ******** * *** *** * *** * *** *
    }

**** * * ** *** * ** * ** ** * * ** ***** ****** * * *** * *

* * ** *** * **** ** ***** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* *** ** ****** * * ***** * ** str[500];
** *** * ** **** ** sizeof(str), stdin);
**** * * * * *** i=0;
** ** **** **** *** * * * * ** d=0,a=0,o=0;
** ** ** ***** * * ** ** ***
* * **** * ***** * * * ** * ** * ** ** * * * ** ** ** **** * * ** d++;
* * * * * * **** *** * * * * *** * * ** ** * **** **** * *** * ** ***** ** * * ** * * **** * * ** a++;
** * * ** * ** *** * **** * ** * *** * o++;
* ***** ** ** ** * * * * ** * ** * ** *
    }

* * * ** *** * ** * * ***** * *** * * * ** ** * ** // remove enter count

* *** ** * **** * ** * * **** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** *** * **
#include ** * ** * ****

int main()
{
* * * * *** *** * **** *** A[1000];
** * * ******** * ***** i, digit=0, *** other=0;
* *** ** * **** * * * 1000, stdin);

** ******** ** * * ** *** ** * ** ** *** i++)
** * ** ** * * * * * *
* **** ** * **** *** * * ** ** **** * * ** >= '0' ** A[i] <= '9')
* * **** ** *** * *** *** * * * ** * *** * ** ** ** * * * * = digit + 1;
* * * ** * ****** * ** *** * ** *** * * **** ** ** * if((A[i] >= 65 * * * * A[i] <= 90) || (A[i] >= 97 * * * * A[i] <= 122))
* * * **** * *** ** * * * * ** *** **** *** * *** * ** ** *** ** ** = alphabet + 1;
* * * * ** ** * * *** ** * *** ** ** ** *** ** if(A[i] > 31)
* ***** ** * * ** * * * * * *** *** ** ** * * ***** * = other +1;
*** * * * * **

* *** * * ** **** *** * * * ** * ******* * digit);
** ** * * * ****** * *** * *** * ** * alphabet);
* *** * * ******* * * * * ** * *** * * ** other);

** * * ** ** *** ** ** 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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