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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* * ** *** ** * ** * str[500];
** ***** * ** ****** ** * **** * sizeof(str), stdin);
* * * *** ** i=0;
**** *** ** *** * *** d=0,a=0,o=0;
* *** *** * *** * *** **** **
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* ** ** **** *** ********** ****** * ***** * ** *** o++;
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    }

** * * * ** * * * * *** * *** **** * * * ** *

* *** ** * ** * *** * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** * * *** * * str[500];
* ***** ** * * *** * **** * sizeof(str), stdin);
******* * * * * ** * i=0;
**** * * * ***** ** ** * **** d=0,a=0,o=0;
**** * *** * * *** * ** * **
**** * ***** ** * * * * * * * * ***** * **** * * * * * d++;
* *** ***** *** * * **** ** ***** * * *** * ** * ** ***** ** ****** * * *** * * ** *** * * *** ** * ** * ** * a++;
** *** ****** * * * ** ** ******** ** * *** * o++;
** ** ** ******* * * * ** ** * *** *
    }

** *** * **** * * * * ****** * * * * *** ** * ** ** ****** // remove enter count

* * * **** * *** ***** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * ** * **
#include * * * *

int main()
{
* ** * ***** *** * A[1000];
** * * * * * ** * * *** i, digit=0, * ** ** other=0;
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***** ** ** * ** * * ** * **** ** ** * i++)
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** *** ** ** * ******** * * *** *** ** * *** *** * * ***** * * * * ** * = digit + 1;
* * **** * *** **** ** * ***** * * * ** ** * if((A[i] >= 65 ** * * * A[i] <= 90) || (A[i] >= 97 ** ******* A[i] <= 122))
* * ** * *** ** ** ****** * *** * ** * * ** ** * * * *** **** = alphabet + 1;
** ** * *** *** *** *** * *** ***** ** * ** ***** if(A[i] > 31)
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* *** * * * ** * ***

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* ** *** ** * * * ** ** ** ** * * ** alphabet);
** * * ** * * * * * ** * other);

** ** *** * ****** * *** ** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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