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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
**** * *** ***** * * ** * ** * str[500];
*** * ***** * * * * * ** *** * sizeof(str), stdin);
** *** * ** * * * **** * i=0;
** * * *** * * ** **** d=0,a=0,o=0;
*** * * * * *** **** * ** *** * *
* * ** ***** * ** * ** * ** * **** * * ** * *** ******* * * * ******* * ** ** d++;
** * * * * * * * **** * ** * * * * ** ** * ** **** *** ** ** ** ** * *** ** **** * *** * * * **** a++;
** *** **** ** *** ** * ** * * ** * * *** o++;
* * * *** * *** * * ** * * ** **** **
    }

** ** * * ** *** *** * **** ** * ** ***** * * ** * * ****

* * *** *** ***** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* ** * * * **** *** * str[500];
* ** * * **** ** * * ** * sizeof(str), stdin);
* ** * * ************ * * i=0;
* * * *** ** *** * * ***** * d=0,a=0,o=0;
*** * *** * * * *** * *** *
* **** * ** * * ** * * ** ** **** * * * *** * ***** ** * *** ** * * * d++;
* ** * ** *** ** * * * ** ** ******** * * * * * ** * * * * ****** * *** ** * * ** * * ** *** * a++;
*** **** * **** **** * *** *** * * ** *** o++;
* * ***** * * * ** * * **** * * ** **** ** *
    }

******** **** ** ** * ******* * * * ** *** * * * * ****** * // remove enter count

* * * ******* * *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * *
#include *** * * **

int main()
{
***** * *** * ** * * ** A[1000];
** ******* * *** * ** i, digit=0, ** * * other=0;
* * ****** * ** ***** * 1000, stdin);

* ** *** *** ** ** ** * ** i++)
* * ** * * **
* * *** ** ** ** * * ** ** * ** *** * ** ** *** * * >= '0' **** *** * *** A[i] <= '9')
** *** *** ****** * *** ** * ** *** * * * ** ** * ** *** ** * ** = digit + 1;
**** * * ** ***** *** * * * * * *** ** if((A[i] >= 65 * * * A[i] <= 90) || (A[i] >= 97 * * * A[i] <= 122))
** * * * * * **** * * * ** * * **** ** **** ***** ** * ** * *** * * ** * = alphabet + 1;
** *** ** ** * * * * ** ****** * * if(A[i] > 31)
* * ** * *** ** ** ** * * ** ** * * ** * * ******** ** = other +1;
* * **** * * *

**** ** * *** **** *** **** * * * * * *** digit);
* * * *** * * * *** *** * * **** ******* *** alphabet);
*** * ****** *** ** * * **** * * ** * * other);

*** ******* * **** * * ** * * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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