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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 18.7k views

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Hidden content!
#include <stdio.h>

int main(){
* **** ** ** **** * ** ******** str[500];
**** ** ** * * **** **** ** sizeof(str), stdin);
** * * ** * * * * i=0;
* ** * ** * ** d=0,a=0,o=0;
* *** * ** * *** ** **
* ** * * *** * ****** * * ** * * ** * * * * ** * * *** ** ** **** ** * d++;
* * ** ** ** ** ** * ***** * * * * * ** ** * ** * ** * ** **** ** **** ** *** *** * ****** * ** **** * *** ** a++;
* ******** * * *** * * ******* *** * * * * ** o++;
** ** *** ***** * *** ****** ** ** * ****** **
    }

* **** * * ** * * * ** *** ** *** * * * **** **

*** *** ** ** *** ** * **** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * *** *** ****** * *** str[500];
* * *** * * * **** * ** sizeof(str), stdin);
* * * * * *** ** * **** i=0;
** * * * * d=0,a=0,o=0;
* ** ******* * * * * ***
** *** **** * * ** * * * * * * * ****** * * *** ** * * * ***** *** * * d++;
** * ** * ** ** * * * *** ** **** * *** * ** ** * * * *** ** ***** *** * ** * * * ** *** * * **** a++;
* ****** *** **** * ** * ******** * * ** ** o++;
* * ** * ***** * * ** * ** ** ***** * **** *
    }

** * * *** * * * * ***** * **** * *** * * **** ** ** * **** * **** * // remove enter count

* **** ****** * * * ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** *** * *** *
#include * * *** *

int main()
{
** *** ** ** * * ** A[1000];
** * ** * * *** ** i, digit=0, **** ** other=0;
**** ** * * ** **** * * 1000, stdin);

** * *** ** * * * *** **** *** *** i++)
* **** ** * * * ***
* * * ** * ** *** * * **** * *** ** * >= '0' ** ** *** * A[i] <= '9')
* * * * * * * *** ** ** ** ** ** ** **** * ** * ** * ***** = digit + 1;
**** * * * * *** * * ****** ** * ** * * if((A[i] >= 65 * *** *** A[i] <= 90) || (A[i] >= 97 * * ** A[i] <= 122))
*** * *** * * ** * ** *** ** *** * * * * ** * ** * * * * * = alphabet + 1;
* **** ***** * * * * ** *** * * if(A[i] > 31)
**** * * * **** ** * *** **** ***** * * * ** *** ** *** ** ** ** * = other +1;
* * * *** * * * *

* * * * **** * ** ** * **** ** * ** * ** digit);
* *** * * * * * * ** ******* **** *** ** * alphabet);
* * ** *** * * ** * * ** ** * **** other);

* * ****** *** * *** *** * * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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