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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* **** * * * ** ***** * ** str[500];
* * * ** ****** * * **** ** * * sizeof(str), stdin);
* ** ***** * *** * i=0;
* *** * * * ** ** *** d=0,a=0,o=0;
*** ****** * * **** ** **
* ** ** **** ** ** ** * *** * * *** * ** *** *** *** *** * * * d++;
*** ****** * * * ** * **** * * *** ** ** ** **** * ** *** ** * * ** ********** * *** * * * * ** ** * a++;
**** * * * * * * * ****** * *** ** **** ** *** o++;
* * * * *** ** * *** * *** *** * *** ** * ** *** ** *
    }

** * * ** *** * * ** *** ** ** *** * * *** * ******* * **

*** *** * **** ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
*** * ** * ***** * ******* str[500];
** * * * * ** *** * ** sizeof(str), stdin);
*** ** ** * * * * i=0;
* * * * * *** * * d=0,a=0,o=0;
* * * * ** *** ** ** * ***
* * * * ** * * * * * * * * **** * ** * * * * ** ** ** * ** * d++;
** * * * * *** ****** * ** * * * * *** * ** * **** * ** ******* *** * ** ***** * ** ****** *** * * ** ** ** * a++;
** ** * * * * *** ** ****** ** *** ** o++;
** *** ** * ** * ***** ** ** * ** * *** * * * * *
    }

** * * * * * *** ****** * ******** * * *** ** ** * ** ** * ** // remove enter count

** * * * *** * ***** *** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * ** ****
#include * ** ** *

int main()
{
* * * ** * * ** * ** A[1000];
* *** * * * *** * * ** * * i, digit=0, * * other=0;
** * *** * * ******* *** * * 1000, stdin);

*** * ** * *** * * *** ** * * ** *** i++)
*** * * ** * * **
* * ** * ** ** ** ** ** *** *** * ****** * * >= '0' * ***** *** A[i] <= '9')
** * *** * * ** * ** ** *** * * * * ****** * * ** * * ** * * ** * = digit + 1;
********* *** ** * ** ** *** ** * ** * * * * if((A[i] >= 65 * ** **** A[i] <= 90) || (A[i] >= 97 ** * ****** A[i] <= 122))
* * *** * * ** * ***** ** * ** ** * * * * ***** ***** * = alphabet + 1;
******* *** * * * * * * *** *** * * * * *** *** if(A[i] > 31)
* ** * * * *** ******* *** ** * * * **** ** ** *** * * * *** = other +1;
**** * * * * * ****

**** * * * ** ** * ** ******* * **** * digit);
* ****** * ***** *** * ** * * * ** ** * alphabet);
*** * ******* * *** *** **** *** **** **** * * ** other);

* * * ** ** ** ** * * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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