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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 16k views

53 Answers

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Hidden content!
#include <stdio.h>

int main(){
* ** * ****** * ** * *** * * str[500];
** *** *** ** *** ** ** * ** sizeof(str), stdin);
* * * * ** * * *** * i=0;
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** *** ** * * **** * * * * * **
**** * *** * * ** * ****** ** * * * **** * *** * * *** ** ** **** * *** d++;
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* ** ** ** * *** * * *** ** * * ******* * * o++;
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    }

* ** ** ** * * * ** * *** ******* ** **** * * ** * * *

* * * * * ******* ** **** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* ** * * * * * str[500];
**** *** **** ** **** * * sizeof(str), stdin);
* *** * ** ** * *** * * i=0;
* * * ** * * ** * d=0,a=0,o=0;
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** * * ** ** **** * ** * * *****
    }

* *** ****** ******** ** *** ** * *** *** * *** ** * ** *** * // remove enter count

** *** * ** ****** * * *** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * ** **
#include **** ** ** *

int main()
{
*** * ** * *** ** ** * A[1000];
* * * * *** *** ** * * * * i, digit=0, * other=0;
* *** * * *** * ** * 1000, stdin);

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** ** *** ***** ** ***** * **** * *** ** *** * >= '0' ** *** ** ** * A[i] <= '9')
** ********* * ** * ** * ** * * **** * * ** * * ** ** ** ** *** * = digit + 1;
* ** *** * *** * * **** ** **** *** *** * if((A[i] >= 65 ** ** ** ** A[i] <= 90) || (A[i] >= 97 *** *** A[i] <= 122))
* * ***** * ** * * * *** * ** * ** *** ** ** ****** ** * ** = alphabet + 1;
* * * * ** ** **** *** * ** * ** ***** ** * **** * if(A[i] > 31)
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**** ** * ** * ** ***

* * ** ** ** * * * ***** * ****** * * digit);
* * **** ** * ****** * * * **** * * alphabet);
** ** *** ** * ** *** ** *** * * ** *** other);

* **** ***** *** ** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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