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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 9.2k views

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Hidden content!
#include <stdio.h>

int main(){
** ** ** * ** **** * * str[500];
* ***** **** ** * ** ** sizeof(str), stdin);
**** ** * ** * ** * * i=0;
* * **** ** ** * * * d=0,a=0,o=0;
* ** *** * * * * ** ** * **
* *** ** *** * * ** *** * * ** * * * * * ** * ** *** * * *** * ** d++;
* * * **** ** * ** * ** ** * * * *** * * * *** ***** *** ** ***** **** * ** * * * ** * ** ** a++;
* ****** *** * * * ** * ** *** * * * ** *** *** o++;
* * **** **** * *** * * * ** * * * ** **
    }

** ***** * ** ** * * ** * * *** * ** ** * **** * ***

* **** * **** *** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* **** * * *** ***** str[500];
***** * * ** **** ** *** sizeof(str), stdin);
* * *** ***** **** ** ** i=0;
******* * * ** * *** * **** d=0,a=0,o=0;
* * *** * ** * ** * * **** * **
* * * * ** * **** ** *** * *** ** *** **** *** **** ****** *** * * ** ** **** d++;
** * ** ** ** *** **** **** ** * **** *** * ** ** ***** ***** ** **** * *** * * **** ** *** * *** * * a++;
* * * ** ** * *** ** ****** ** *** * **** ** * * * *** *** o++;
*** * *** * ** * ** * * ** ** * *** **
    }

** * ** * ***** ** **** * * ** *** ** * **** * * // remove enter count

* ** * * * * *** ** * ** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * ****
#include * * * * ***

int main()
{
* * * * ** * ** * * A[1000];
* *** *** ** *** * ** i, digit=0, * *** * other=0;
* * ** * * * ** * 1000, stdin);

* * *** ** * * ** * ** * *** i++)
*** ** * * * * **** * ***
** ***** ** * **** * ** * * *** * ******* ** **** >= '0' * * ** A[i] <= '9')
* *** ****** * *** * * *** * ** * * ** *** * * * ** * ** * *** **** = digit + 1;
* * * * ** * * ***** * * ****** * * if((A[i] >= 65 ** ***** A[i] <= 90) || (A[i] >= 97 ** * * A[i] <= 122))
** ** * * *** ** * *********** *** ** *** ** **** * ** ** * * * *** * *** = alphabet + 1;
** ***** *** * * * * * * *** *** * ** *** * ** if(A[i] > 31)
** * ** ** * **** * *** * * ** * ** * ** **** * * * ** ** * = other +1;
* **** ** ** * * * * * *

* ** * ** * ** * ** ** ** * ** *** * digit);
** ** *** * *** * * **** ** *** * ** ** ***** * * alphabet);
**** ** *** ** * * *** * ** * *** ** * other);

* * * * **** * *** ** * * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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