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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* **** ** * * **** ** * str[500];
** ** * * ** *** ** * sizeof(str), stdin);
** *** **** * * * * *** i=0;
* **** **** * * ** ** d=0,a=0,o=0;
* * * * **** ** * * * ****
* *** * ** * * ****** ***** *** * * * * *** *** * ** * ** ** ***** ** d++;
* * ******* * * * ** * * * *** * * ******** ***** ** * ** *** ***** * * **** **** *** a++;
**** * *** ** * ** * **** * * * ***** * * o++;
*** * * * ** * *** * * ** ** ***** * * *
    }

* * * ** * ** * * ***** * * ** * * ** ** ****** **

* * ** * * * ** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* ******** * ** * * ** **** str[500];
** * * **** **** *** ** ****** sizeof(str), stdin);
* ** * **** ***** * * ** * i=0;
** * *** ***** * * d=0,a=0,o=0;
* ** * * ** ** ** *** *** ** * *
*** **** * * ** **** * ** * * ** * ** * ********* ** *** * * * ** * * * ** *** d++;
***** * *** * * * ** * * * * ** * *** * * ** * ** **** * * ** * * * ** ** * * * ** ** a++;
**** ** ** *** * * ** * ** ***** *** o++;
* ***** * * * ** * * *** * * * *
    }

* * ** ** * * * ** ** ** * ** ** * ** * ***** *** * ** * // remove enter count

** *** *** ** * * **** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** ** *
#include * *** * *

int main()
{
* * ** * * *** * * * *** A[1000];
* ** * ** * * * * ** * * i, digit=0, *** * other=0;
*** *** **** * * * * * * ** 1000, stdin);

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* **** ******* *** * * * ** * ** ** ***** ** *** * * *** *** * ***** ** * = digit + 1;
** ** ** ** * * ****** ** **** * * ** * if((A[i] >= 65 ** * ** A[i] <= 90) || (A[i] >= 97 ** * * * *** A[i] <= 122))
* **** ** ** **** ***** *** * *** * ** *** * * **** * * ****** *** * * = alphabet + 1;
*** ** ** **** * ** * * *** *** ** ** *** * if(A[i] > 31)
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* * * ******* * ** * *

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** ** * ** * ** * * * * ** ******* **** alphabet);
** *** ** * *** *** * * * ***** ** * * other);

*** ** * * ***** * * ** * * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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