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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
******* * ** ** *** str[500];
******* ****** **** * ** * sizeof(str), stdin);
*** * ***** * * * **** i=0;
** ************ * *** * d=0,a=0,o=0;
* * *** ** * ** * **
** * * * ****** ** * *** * * * ** ** * **** ** * ************ * * d++;
**** **** ** * *** ** ** ** *** * ** * * * * *** ** * ***** * * * * ** ** * ** ** *** ** * a++;
* ***** ** * **** ** * ** ***** ** * *** ** * o++;
** *** ****** * * ** * * ** * *** * **
    }

** ** * ** * * * *** ** * ** * ***** * ** * ** * **

** * **** * *** *** ****** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* *** ** * ** * ** * str[500];
* ** ***** ** *** ** * sizeof(str), stdin);
* * ** * ** * *** ***** * * * i=0;
* ** **** ** *** * * * d=0,a=0,o=0;
* *** * * ** * ** ** * *
* ** * ** *** ** * * * *** ** * * ** *** * *** ** * * ***** * *** d++;
* ***** * ** ** *** * *** ** * * * *** ** * **** * * ** * * * **** * ** *** * **** * * ** ** * a++;
* * * * **** ** * * * *** *** * * * o++;
** * ** * ** *** **** ** * * ** *** ** * *
    }

* * * * ** * * **** ** ** * * * *** ***** ** * *** * ** * * // remove enter count

* * *** * ** * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * * *
#include ** * ** *

int main()
{
** * **** * * * **** **** A[1000];
** * * * ** ** ** i, digit=0, ** *** other=0;
***** * *** ***** ** * 1000, stdin);

* * * * * * * ** * ** ** * ** i++)
* ** * * ** **
* ** ** *** * ** * * ** * * * * * * *** >= '0' * *** * A[i] <= '9')
* *** ** **** ** ** ** ** ** ** * ** *** * * * ** * ** ** ******* = digit + 1;
* * * * ****** *** * * ****** ** * * ** if((A[i] >= 65 *** ***** A[i] <= 90) || (A[i] >= 97 ** ** A[i] <= 122))
***** * *** * * * * ** * **** *** *** **** ** * * *** * * * * = alphabet + 1;
* * * *** * * * **** * *** * * * ** if(A[i] > 31)
** * *** ** * * ** ** ** ** * * ** ** *** ** * * **** ** = other +1;
* * *** ** *** * ** **

** **** ** * * * * * * ** * ***** ***** ** digit);
** ** * * * * * * * *** ** * * * ** ** * * alphabet);
******** * * * * ** * * * * * * **** other);

* * * *** * * ** * * * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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