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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 16.6k views

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#include <stdio.h>

int main(){
** * **** ** str[500];
* **** *** * ** *** *** ** ** * sizeof(str), stdin);
*** * * ** ** **** i=0;
* ***** **** *** * ** ** ** d=0,a=0,o=0;
** * * * * ** **** ** *** * *
* ** * *** ** * **** ** * * **** *** **** * * ** * * ******** * * ***** d++;
* * * * ** ** **** ** ** ******** ** * * * ** ****** * *** * * *** ** * * ***** ** * *** *** * ** *** a++;
*** ** * * ***** * **** * * ** ****** * * ** * o++;
* ** * * * *** ***** *** * * * * * **
    }

* ** ******* * * **** ** ***** * * * ***

* * * ** * * ** * * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** ****** * * * * * ** str[500];
* *** ***** * * ** **** sizeof(str), stdin);
* ** * *** * * * * * i=0;
* ** **** * * ** ** ** d=0,a=0,o=0;
* * ** * ** * ****** ***** * * *
***** * * ** * ** ** * * * * ** *** **** * ** * * * * * * * *** d++;
********* *** ***** * ** ****** * ** * * ** ** * * **** **** *** *** ***** ** * * *** ** *** * ** * * ** ** * a++;
* * * * ******* * ** * *** * * * ** * ** o++;
**** * * * *** ** ********* ** *** *** * * ** *** **
    }

** * * ** **** ***** ** **** * * * * ** * * * * * **** // remove enter count

***** ** * * * * * ** * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * * * *****
#include * * * * * **

int main()
{
******* **** * ****** A[1000];
* **** * * * ******** i, digit=0, *** other=0;
** * ** ****** * ** ** 1000, stdin);

*** * ** * * ** *** ** * * * *** * * i++)
* * * * *** ** * ** ** ***
*** * ** ** * **** ** ** * ** ** * * * * >= '0' * * ** *** A[i] <= '9')
*** ** * ** * ** *** * * * * *** * * * * **** **** * = digit + 1;
*** * * ** * **** ** * *** * * ***** ** if((A[i] >= 65 * * A[i] <= 90) || (A[i] >= 97 *** * **** A[i] <= 122))
* ***** * * ** *** ** *** *** * ***** * **** * ** * * ****** * * * = alphabet + 1;
* * ** * * ** *** * * * * * *** ** ** * * if(A[i] > 31)
** * * * ** **** ** * * ** *** * * *** ** * **** ** * = other +1;
* * **** * * ***

* *** *** ** * ** ********** * ** * * ***** * digit);
* ** ** * ** ** ** ** *** ****** * * * ******* alphabet);
* * * * *** * * ** * *** * * * * * other);

* * ** * * * * ***** ** * *** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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