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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 18.7k views

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Hidden content!
#include <stdio.h>

int main(){
*** * * *** * ** *** str[500];
** * * **** ** * * *** ***** ** sizeof(str), stdin);
* * *** *** * ***** * ** i=0;
* * * ** * * * ** d=0,a=0,o=0;
** *** * * * * * ** * ** * ** *** *
** * * * * * * * * ** * * * *** ** ** * * ** **** ** ** * *** * *** * d++;
** **** **** ** * * ** *** * * * *** *** * ** ** * * ***** *** * * ** ** *** * ** * **** * * * **** * ***** * * a++;
** ** ** * ** * *** * * * **** *** ** *** o++;
* ** *** *** ** * * *** ** ** * * * ***
    }

** * ***** * ****** ** * ** * ** ** *** ** *** *

** * ** ** * ** ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
*** ** * * * *** * * str[500];
*** *** ** * ** * * ***** * * sizeof(str), stdin);
** * *** * ***** * *** i=0;
** * * ********* ** ***** d=0,a=0,o=0;
***** * * **** ****** * * ***
** *** * **** * ** * ** ** * **** * * * * * ** ** ** ***** * ** *** d++;
* * * *** * ** *** * * ** ** * * ** * **** * * * ** *** *** ** * **** ** **** *** ** ** * * a++;
** **** * ** ** * * * ***** * * **** * o++;
*** ** * ** ** * *** *** * * * ** ** **** * *** *** * * *
    }

*** ** * * ** ***** * **** ** * *** * * * **** * // remove enter count

* *** *** **** * ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * ** * * ** *
#include ** ** * * *

int main()
{
* * **** ***** * A[1000];
* ** * ** * * * * i, digit=0, ** *** other=0;
* * *** **** * * * *** 1000, stdin);

* ****** * **** ***** * * * * ** * * i++)
*** ** * *** **
* ** * **** *** ****** ********** * *** * ** ** >= '0' * * ** * A[i] <= '9')
** ******* * ** ** * * * * * *** ** * ** * * *** * *** * *** * * = digit + 1;
* * **** **** ** * * *** ** * * ** *** *** * if((A[i] >= 65 * ** A[i] <= 90) || (A[i] >= 97 * * ** A[i] <= 122))
*** * * ** * * * * ***** * ***** ** * * * * * * * * ** * * ** * *** = alphabet + 1;
* ** ** ** ** * * ** *** * ** ***** if(A[i] > 31)
*** ** * *** ** *** * ** ** * * ** * *** * * ** **** **** ***** * * = other +1;
**** *** * ****

*** * * * * * ** * ******* * * ** ** * * * digit);
*** * * * ** ** *** * ** * ** *** * ** ** alphabet);
** * ** * *** * * * **** * ** * * ** * other);

* * * * * * *** ** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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