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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
*** ** * *** * * str[500];
**** * * * ***** * * * *** sizeof(str), stdin);
**** ** * ** * * * ** * i=0;
*** * * ** ** ** ** d=0,a=0,o=0;
* **** ** * ** * * *** *
** * ** * * * * ** ** ** ** * * **** ** * ** **** ** * * * * * d++;
** *** * **** * ** * * *** * *** * ***** * ** ** * *** * * *** * * * * * ** * ****** ** * ** ** a++;
******* * *** * * * ** * * ** * ** * * o++;
* ** **** * * ** **** * * * ***** ** ** * ***
    }

** ** ***** ***** *** * * ** ** * ** * * * *

* **** * * * * * **** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** * ** * * ** * *** * str[500];
***** * * *** ** * * * ****** sizeof(str), stdin);
**** ** ** * **** i=0;
* ** * * * * **** ***** d=0,a=0,o=0;
*** * * ** **** *** ** * *** * *
* *** * * * ***** * ****** * ** **** * ** ** * * * **** ** *** *** **** ** d++;
* ** *** ** **** **** ***** * *** * * **** * ** * * * * *** * ** * ** ** * * * * * * ****** * ****** **** ** a++;
* * *** ** * *** ** * * * * * * **** ******* o++;
** * * ** * * * * * ** *** ** ** *** * ** ****
    }

* **** ******* * ** * * * * *** * * * *** ** ** ** * * // remove enter count

*** **** ** * ****** * *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * ********* *
#include ** ***

int main()
{
** * * ** * ** * * ** * A[1000];
**** **** * *** ** ** i, digit=0, **** *** other=0;
** ** **** * *** *** * 1000, stdin);

*** * ***** * * * * ** * *** i++)
**** ** **** * * * **
** ********** * **** *** * * **** * * * ** **** ******* >= '0' * *** A[i] <= '9')
* * * * ********* *** * * ** * * ** * ** * * * ** ** ** ** = digit + 1;
** * * ** *** * *** *** **** ** ** * ** * ** *** if((A[i] >= 65 * ****** A[i] <= 90) || (A[i] >= 97 * *** **** A[i] <= 122))
* * **** ******* * ** * ** * * * * *** * * * *** ****** ***** * * = alphabet + 1;
* *** * *** ** *** **** * * ** ***** **** ** if(A[i] > 31)
* * ** ** ***** ** * * * * ** * * * * **** * ****** * **** ** *** = other +1;
*** * ** *** ***** ***

** ** *** * *** ** * ** * **** ** ********* digit);
* *** ** * ** * * * * *** ** * **** * * ** alphabet);
**** ** ** ****** * * * ***** * * **** other);

* * * * * ** * ***** ** 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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