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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 13.4k views

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Hidden content!
#include <stdio.h>

int main(){
* * **** **** * ** **** str[500];
* * * ** ** ** *** ** *** sizeof(str), stdin);
* * *** ****** *** i=0;
** ** *** ** * ** * *** d=0,a=0,o=0;
* * * * * *** *** * * ***** * *
****** *** ** * * ** * ** *** ** ** *** * * ** * *** * **** ** ** * * ** * d++;
** ** * * *** * * ** * ** * * * ** * ** ** * * * * * * ** * * ***** * ** ** *** * * * * * *** * a++;
* ****** **** ***** ** * ** ** ** * ************ ** o++;
* * *** *** ** ** * * * ** **** * ** *
    }

** **** ** ** * * * *** * ** * * ****** ** ** * ***** * **

** *** **** * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * * ** * ** ** * * str[500];
**** ** *** * ** ** *** sizeof(str), stdin);
* ***** * * * *** ** ** ** * i=0;
* *** ** * ** * d=0,a=0,o=0;
***** * ** ** ** ** * * *
* **** * * * * * * ** * ** *** ** * * * ****** **** ** * * * * * * * *** d++;
** ****** ** ** ** ** * * ****** * ** * **** ********* ** ******* * * *** * ** *** * * * * ** ** * ** * *** a++;
***** * * * ** * ** * ****** ****** *** * * *** o++;
** * ********* * *** * ***** * ** * * * *
    }

* ** * ** * * * * ** * *** * * * *** ** * * * ** * *** ** * // remove enter count

* ** * *** **** ******* 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ***** * *
#include * *** * *

int main()
{
* * * ** * *** * ** A[1000];
* * ** ** ** **** * * * i, digit=0, ** ** other=0;
***** * *** **** **** *** 1000, stdin);

** * * **** *** * * *** ** **** *** ** i++)
** *** *** * * * *** *
* * *** ** * * * *** ** * * ** *** **** * >= '0' ** ** * A[i] <= '9')
**** * * **** * ** * **** ** * * *** * **** ** * *** * = digit + 1;
* * *** **** ******** ** * * * * * * * * if((A[i] >= 65 * * * A[i] <= 90) || (A[i] >= 97 ** ** * **** A[i] <= 122))
** * ** * ** * ** ** ***** *** ** * **** * * ** *** ** * * *** = alphabet + 1;
* * **** *** * * ** * ** * *** * * ** ** ***** if(A[i] > 31)
* * * ***** * ** ** ** **** * * *** * * * * * * * * * * = other +1;
* * * **** ** * **

** * ** * * ** * *** * ** * ** ********** digit);
** *** * ** *** * * ** * ** * ** ** * alphabet);
* * * ** *** * *** ***** *** ****** * other);

* * * * ** * * *** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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