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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 16.4k views

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Hidden content!
#include <stdio.h>

int main(){
**** ** * **** * ** str[500];
*** ** **** **** *** * ** ** * * sizeof(str), stdin);
* * * * *** * * ***** * i=0;
* * *** * ** ** **** * ** d=0,a=0,o=0;
** * * * ** * ** * * * *** **
** * * **** ** **** ** **** * *** **** *** *** *** * * * * * * * ** * * * * ** * ** d++;
** * *** ***** * ** ****** ** * **** * * * * *** ** *** ** * * * *** * * *** ** *** ** *** ******* a++;
* * * **** ** * ** * * * * * * * o++;
*** *** * * ** **** * * ** ** * * ** **
    }

*** **** * * * * * *** ** ** ** ** *** ** * * * * **

* * ** ** * *** ** ****** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * ** ** ** ******* * str[500];
***** * ** ********* ** * * sizeof(str), stdin);
**** ** * * *** * * i=0;
**** *** * ** * * * * * d=0,a=0,o=0;
* * ** * *** **** * *** **** * *
*** * * * * ** *** * * * * **** * ** ***** * ** * ** * d++;
* * *** * * ** *** ** * ** ** ** *** * * ** ** *** ** **** ** ** ** ** ** * * ****** ** * *** * * ** * * * *** a++;
*** * * ** ** ** * *** ** ** ** * * ***** *** o++;
*** **** ** ** *** ***** *** ****** *** ** *
    }

* * ** ** * ** * * ** *** * * * ** ** * *** // remove enter count

* * **** * * *** * * *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** * * * *
#include *** *** ** * *

int main()
{
* *** * ** * ** * ** A[1000];
*** ** * * * * * **** * i, digit=0, * * * other=0;
* * * * **** ****** * 1000, stdin);

** * ** * ** ***** * ** * ** ** ** i++)
** * * * * * *
* ** ** * ** ***** * * * * **** * ** ** >= '0' * ** **** ** A[i] <= '9')
*** * ** * ** ** ****** **** * * *** * ** *** * ** ** * ** * = digit + 1;
* * * * * *** * ** * * *** * *** * * ** if((A[i] >= 65 ** ** * ** A[i] <= 90) || (A[i] >= 97 ** ** * A[i] <= 122))
* * * *** ******** * * * *** ** ** ******* *** * * * ** ****** ** * = alphabet + 1;
*** ** * ** * ***** * * *** * *** * * * ***** if(A[i] > 31)
* * * **** * * * ** ** * * * ** *** *** **** * ** * * * *** * **** = other +1;
* *** ****** * *

** ** * * * * ** * ** * *** ** * ****** digit);
*** * * * ** * * ** ***** *** ** ** alphabet);
* **** * ** *** * ** * * ** **** * * * other);

* ** *** * ** ** * *** ** ** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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