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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
** * * * *** * * ** str[500];
* * ** * * * * *** * sizeof(str), stdin);
* * *** **** * **** i=0;
** * **** ** * * * ** * ** d=0,a=0,o=0;
** * ** * *** ** * ** *
* ***** **** *** ** ** * * **** ** ** * * * * **** ** *** * ** *** ** * * ** d++;
**** ** *** **** **** ** ******* * ** *** *** * **** * *** * *** * * *** * ** * ***** *** *** ** * *** *** **** * * a++;
**** * * * ***** * *** * **** ***** * ****** *** o++;
* * * * * **** * *** ** *** * * **** * ** ** **
    }

*** ** **** *** * * * * ******* ** **** ** * * * *

* *** ** * * * * * * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* ** * * ** ** * * ** ** str[500];
* *** * ** * ** ******* sizeof(str), stdin);
* * * * * ***** ** * i=0;
* * * *** ***** *** * d=0,a=0,o=0;
* ** * ** **** ** ****** * * *** * *
* ** ** * **** ** *** * ** * *** ***** ** ** ********* ** * * **** * * * * d++;
******* ************** ** * * * **** * ** *** **** ***** ** * * ** ** * ** * * * * ***** * * ** ** a++;
** ** * ** ** *** * * ** ** * ** ** * * * * * * * o++;
****** * * ** ** *** * *** * * * * * *** ** *
    }

** ** * * ***** * ****** * * *** **** ** * * *** * * ** // remove enter count

* * ** *** * *** ** **** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * ** *** *** *
#include ** ***

int main()
{
* **** * * *** *** * A[1000];
****** * * * **** i, digit=0, * **** * other=0;
** *** * * * * ** ****** *** 1000, stdin);

* ** *** ** ** * ** *** **** * ******* i++)
* ** ** * *** * **** **
*** * * ** ** *** * * *** **** * * * ** ***** >= '0' * *** ***** A[i] <= '9')
* * * * *** ** * ** * ****** ** * ** *** ** * ** * * * = digit + 1;
** * ** * * ** *** ** ***** * ****** * * if((A[i] >= 65 * ** * * A[i] <= 90) || (A[i] >= 97 * **** * * A[i] <= 122))
* *** *** ** ***** * * * * * * * * * ** * *** *** = alphabet + 1;
* * * * **** *** ***** ** ** ** * * * ** if(A[i] > 31)
* ** ** ** * ** ** *** * ** * ***** * ******** * ** * * * * *** ** **** ** = other +1;
* * * * ** * * * * ***

* ** ** * * **** *** ** ** * *** ** * * digit);
* ** * * * *** * ** * * *** ** * ** ** ***** * alphabet);
* *** ** ** * * ** *** * ** * ****** * * other);

* * * * ******* ****** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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