0 like 0 dislike
8.3k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.3k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** ** ** * **** ** x[] = {77,22,88,11,22};
** * *** * ** *** * * ** size = 5;
    
* **** * * * * * * ** * print the array */
**** **** * **** * ** i = 0; i < size; i++){
* * ** * *** * * * ******* **** * * *** * *** *** ", x[i]); *** * ******** **** ** ** ** * *
**** * * ** ** **
* * * *** * *** * ******* * *** * ** * ** ** *
* **** ** *** * ** *
******** ** ** * * I need this to happen size-times */
* * ** * ********* j = 0; j < size; j++){
* ** * ***** ** * * * * ** * ** * * * ** * * * from left to right */
* * * * * * * * ** **** *** * ***** * i = 0; i < size-1; i++){
* * * ** ** * ** * *** ** * * ***** * **** ** * ****** ** * *** * * * ** i-th element with its neighbor to check if they are in order */
* * **** * ** * * **** *** ****** ** * * ****** ** **** *** **** * * > x[i+1]){
* *** ***** * * * *** * ** ** * ** * *** ** * * * * * ** ** **** * ***** exchange the values of x[i] and x[i+1] */
***** ** *** ****** * ** * * *** * *** * * *** ** ***** * * ** ** * **** * * * ** ** ** * * * temporary; **** ** * * * * * * * ** * *** *
* * ** * * ** * *** * * * * *** * * * * ** ** * * ** * * *** * *** * ** ** * *** ** *** * = x[i];
** * * ** * *** * **** ** ** ************** * * * * * * *** * * * ***** **** ***** ** = x[i+1];
*** * ** ** * * ** * * * * * *** **** *** ***** * * * * ** * * *** * * ***** = temporary;
* * * ** * *** ** ****** * ** *** * **** *** * **** * ***** * ** ****
***** *** ***** *** ** * * * **** **
* ** ** * * ** * * **
*** ***** ** * * ** ***
* ****** * * * * ** * ** print the array */
* **** * * ** * * ******** *** * sorting: \n");
* ** **** **** * ** **** i = 0; i < size; i++){
*** ** * ** ***** ** *** *** * *** * * * * *** * * *** ", x[i]); ** * * * ** *** * * **
** * ** * * * * *
***** **** **** * **** *** * ** ******
*** *** ** *
* * ** * * * * * *
*** * ********* * ** *** ** *** *** * ****
*** * *** ** ** * ** * * *** * ** * ** ***  
** * * * ** *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** * * * ****** * * x[] = {77,22,88,11,22};
******** * ***** *** ******* size = 5;
    
** ** ** * ** * * * * *** print the array */
* * ** ** * * ** ** * * * i = 0; i < size; i++){
* ***** * *** ** * * * ** * * ***** *** * *** * ", x[i]); * * *** *** ** * * **** ** *
* **** ** * ** **
** ** *** * * * * * ** ** ** ** ** *
* * * ** * ***** *** ****
** ** * * * * *** * * ** * I need this to happen size-times */
* ** * ** * ** * *** * * * j = 0; j < size; j++){
**** * *** *** * * ** * ** ** **** ***** * from left to right */
* * ** * ** **** * * ** * * * * * **** i = 0; i < size-1; i++){
**** * * * ** * * ** * ** ** ** * * * * ***** ** *** i-th element with its neighbor to check if they are in order */
* * * *** *** ** ** * * * * * **** * *** * * * *** ** ********* > x[i+1]){
* ** * **** ** ****** ** ***** * * * * * ** *** * *** * *** * **** *** * * ***** * **** * * exchange the values of x[i] and x[i+1] */
* * **** ***** ** ** * * * ** ** ** * ** ********* ** * **** * ***** * **** temporary; ** ** *** **** * ***** *******
* **** **** *** * ** * * * * * **** * * *** *** ** * ** ***** ** ** * * **** ** ** * ***** * * * *** = x[i];
*** * ** *** * * ** **** *** * ** ** ** * * * **** *** * * ** * * *** ** *** * * * *** *** = x[i+1];
*** ** * * ** * ** ** * * * *** *** ** *** *** **** ** *** * ** * * * ** * * * * ** * = temporary;
* * * *** ** *** * * * ** ***** * * ** * ** ** ** * * * *
** **** ***** **** * ** ** ***** ** * * * **
* * *** **** *** *
* *** ** * *** *** * * ***** *
** ****** ****** * * print the array */
*** * **** * * ** * ** ** * ** sorting: \n");
* * * * * *** ** ** i = 0; i < size; i++){
* *** * *** ** * **** *** ** ** *** ** * * **** * ", x[i]); * * *** * * *** * * *** *** * **
* * ***** ** *
** * * ** * **** ** * ** ********* * **** *
* * ** * ** ****** ***
* * ** * **** ***
* * *** * *** ** * ** * * **
** ** ** **** * *** **** ** ** * *** ** **  
** **** ** ****** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ***** * * * ** * * x[] = {77,22,88,11,22};
* * ** * *** ***** size = 5;
    
* * * * * **** *** print the array */
* ** * ** * * *** * ** i = 0; i < size; i++){
** * *** * ** **** *** * ***** * ** * * ** ** * ", x[i]); * * * **** * ***** ** **** * *
* *** * ** ********* * **
*** *** * * ** ** * * * **** ** ** * ****
**** ** * *** ** **
* ***** * ** * I need this to happen size-times */
* * * ***** * * ** * * *** j = 0; j < size; j++){
**** ** * * * * ** ** *** *** * **** * ** * ** ** from left to right */
** *** *** * * ** *** * * *** * *** ****** * * * * * i = 0; i < size-1; i++){
*** * *** * * * * ** * *** * ** * ** * * * ** * * * ** * ****** * i-th element with its neighbor to check if they are in order */
* * ****** ***** ** * ** * *** ** * *** * ** * * ** ***** * **** > x[i+1]){
*** * **** ** * * ** ** ** ** ***** * *** * ** * * * *** * ** ** ****** *** * *** * * * exchange the values of x[i] and x[i+1] */
* * * ** **** * * *** * * ** * ** * ** *** * **** * * * * ** * * *** * * temporary; *** ** ** ** * *** * * * ** ** **
* * ** * *** ** * ** **** * *********** ** * * ** * ** * **** * * ** **** * *** ***** ** * ** = x[i];
* ** * * * *** *** * * ***** ** * * * *** **** * * *** **** * * ***** ****** = x[i+1];
* ** * ** * *** * **** ** **** ** * ** * * * *** * ** * * * ***** ** ** * = temporary;
* *** * **** * * *** **** ** * ** * **** ** ** *
** *** * * **** ** *** * * ** * * ***
* ** ** * * * * **
**** ****** ***** * * * *
** ** ***** ** * * *** print the array */
** ** * * ***** * * **** **** sorting: \n");
* * * ** ** *** * **** i = 0; i < size; i++){
*** * ** * *** **** * ** *** ** * * * * ** ", x[i]); ** * * * ** ***** ** * *** ** * **
** ** * ***** * **** *
** *** *** * * * ***** ** ** *
** * * ** * ** *
* ** * * * * * **
*** *** * ** * *** ** * ** * * * * ***
* * *** ** * * ** * ** * ** *****  
** * ** * * * *** ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** **** * * * * ** * x[] = {77,22,88,11,22};
** * ** * * *** * * * * size = 5;
    
**** * * *** * * print the array */
* * * * *** ** ** ****** i = 0; i < size; i++){
* * * ***** **** ** **** ** ** * * ****** * * ", x[i]); * *** * * ***** * ** **** * *** **
* ***** * * * ** **
** * ** * ** ****** * ** ** **
* ** * * ** * ** * * ***
** * ** *** ** * I need this to happen size-times */
* * * * * **** * ** *** ** * j = 0; j < size; j++){
********* ** ** ** * ** ** * ** * * ** **** from left to right */
* * * ******** ** ** ** * ** ** ***** * ** ********** i = 0; i < size-1; i++){
* * * ** *** * ** * * *** *** **** ** *** * * ** ***** *** ** ** i-th element with its neighbor to check if they are in order */
* * ** * ** *** * * * * * * *** * * * ** * *** **** * * **** > x[i+1]){
**** * ** ******** * *** *** *** * * * **** ***** * * * * ** * * * ******* ** exchange the values of x[i] and x[i+1] */
***** * *** * * * **** * ** ** ** * * * * *********** ** * ** *** * ***** ** * * * * * temporary; * * ** **** * **** ** * * ** ***
****** * * * * *** ** ** * *** **** * * * * * * ** * *** * *** ** *** ** * * = x[i];
**** ** * * *** * ** ** ** * *** ********** * * ** * ** ** * *** ***** * * ** * * * = x[i+1];
*** * *** * ** * ** ** *********** * * * * * * *** *** * * ** ***** ** * * * ** = temporary;
* * *** * * * * ** ** ** * * ** **** *** * ** ** **
* *** * * ** * * *** * * * * * * ** ****** * * *
* *** ** *****
******* ** * *** *
*** ** * * * * * *** * ** print the array */
***** * *** * ** * * *** ** ** * * sorting: \n");
* * ** ** * * * * i = 0; i < size; i++){
** * ** *** * * ** * * * * * * *** * * * ** * * ** ", x[i]); * * ***** * * * * ** ** * *
* * * * * * *** ** *
* * * * ** * * * ** *** ** * * **
*** *** **** ** * *
* * *** ** * * **
* * * **** * * **** * * ** * ***** * * *
** * * *** ** ** ***** *** ** ******  
* ******* ** * * * ** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * ***** ****** x[] = {77,22,88,11,22};
** ** **** * ** * ** size = 5;
    
* * *** * * ***** print the array */
* ** ** * * * * i = 0; i < size; i++){
** * * ** * * *** ** * *** * * ** ** * * * * ", x[i]); * * * * * * *** ** * ***** ** *
* *** * ** ** * * **
******* * ***** ** * * ** ** * ** ** ** *
* ***** *** ** ** *
* ****** * * *** *** I need this to happen size-times */
** * *** ***** *** * * * * j = 0; j < size; j++){
* * ** * * ** ****** * * ** ****** * * * * * from left to right */
** * ** * *** * *** *** *** *** **** * * * ***** * i = 0; i < size-1; i++){
* **** *** * * ** ** * * * * * ***** ** ** *** ** i-th element with its neighbor to check if they are in order */
* ** **** * ** *** * ** *** *** ** *** *** * ******* *** * * ******* ** * ** > x[i+1]){
** * * * * *** * ** * *** *** * ** * ***** ** **** **** * * * *** * * * ** exchange the values of x[i] and x[i+1] */
* * **** * *** * ** ** * * ** * * *** * ** * *** ** **** **** ** **** * temporary; **** ** * * * *** ** ** ** * **
** *** * ***** ****** ** ** ** * ***** * * **** ** * ** * ** * **** ** * **** * * = x[i];
** ** ** ** * * ** *** *** * ** * * * * *** ** ** * * * ** *** ** *** ** *** * * ** * = x[i+1];
***** *** **** ** *** * ** ** ** ** * * *** *** * ** ** * * * * * * * * ** * * * = temporary;
**** ** ** ** ** * * * * * * * ******* *** ***** * ** * * * * **
* ** * ** * ** * ** * *** ** ** * *** * * ** *
* **** **** ** * ** * *
** * ** *** * * * *
**** ** * ** * * print the array */
* * ** * ** ** * ** **** * ** sorting: \n");
*** * * * ** * * * ** ** * i = 0; i < size; i++){
*** * * ***** *** * * **** * * **** ** * ** * * * * * ", x[i]); **** * * **** *** * * ** ** **
* * * ** * ** *
** ** ** * * ** ******* *** ***** **** ** ** * * *
* *** ** * * *
* ***** ** * * * * ****
* ** *** * * * ** **** ** * **** **
* * ** * *** * ******* * ***** *** ****** * ** **  
* * * ** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ***** * * * ** ** * ** x[] = {77,22,88,11,22};
* ** * ** * * * ** *** * size = 5;
    
* * * * *** * ** * * * * print the array */
* ** * * * ** * *** ** i = 0; i < size; i++){
* **** *** * *** ** ** ******* * * * * * * * * * * * * ", x[i]); ** * ****** * **** **** **** **
** * * ** *** *** ***
* *** ** * * **** ** * * ** * * *
*** * * * ** * * * *
* ** * * * *** * * ** * I need this to happen size-times */
*** ** *** * * *** **** * j = 0; j < size; j++){
*** * * ** * *** **** ** * * *** ** *** ** *** from left to right */
* * ****** * * ** ***** *** *** * *** *** * ** * i = 0; i < size-1; i++){
* ** ** * * * * * * * ** ** *** *** *** *** * * * * ** * ** * * * i-th element with its neighbor to check if they are in order */
** * * * * ** ** * * * ** * * * * * *** * * * ** ** *** *** *** > x[i+1]){
* ******* * ** * * *** * * * *** * * * ** * * *** * * ***** ** * * ** **** * * exchange the values of x[i] and x[i+1] */
* ***** * * ** **** * **** ***** * * * ** * ** **** ** * * ** * * * * ***** ***** * temporary; ** * ** * **** * **** * * ** *****
** ** * * * * * * ** ** * * * *** ** **** * ** ** ****** * ** ** ** ** * ** * ** * = x[i];
* *** ** * * *** * * * * * ** * *** ** * ** * *** * * ** *** * *** **** * *** ** * * **** = x[i+1];
***** *** ****** **** ** ** * ** ******* **** *** *** * * ***** * * *** * * * = temporary;
* ** ** ** *** * ***** *** * * **** **** ******** *** ** * *
* * * ** ** * ** ** ***** * * *
**** * ** ** * * **
* ***** **** ** *
* ** ****** * **** print the array */
* * * ** ****** * * ** * **** sorting: \n");
** * *** ** **** *** ** i = 0; i < size; i++){
* *** * * ** * ** * ** *** * * *** ** *** * ** ***** * ", x[i]); * ** * * * * ** * ** * ***
* *** **** * *** * *
* ******** ****** ***** * * * ** * *** *
** * ** * * *** *
***** *** * * ** * ** ** *
* **** ** * * ***** * * * ***
* **** * * * *** * ***** ******* ***** * ** * *  
**** * * ** * * ***** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** * * ******** * x[] = {77,22,88,11,22};
**** * **** * * * * ** size = 5;
    
*** ** ** * **** print the array */
* * ** ** ******** * * *** i = 0; i < size; i++){
** ***** ***** * * ** ** * * ** ** *** ***** * ** ", x[i]); ** * ** * * * ** * * ***
** * ** * ** * **** * **
****** * *** * ** * * * * ** * * * ****
** * ** **** * ** *
**** * *** ** ** ** I need this to happen size-times */
* * * * * * ***** *** **** j = 0; j < size; j++){
** ** ** * ** * * *** * * * * * *** ** * **** * from left to right */
* * * *** * * * ** * ** **** * ** ** ** ** i = 0; i < size-1; i++){
*** * *** ** * ** * * ***** * ** *** ** * *** **** ** ** i-th element with its neighbor to check if they are in order */
***** * * ***** ** * * * * * ** * ** * * ** * ** * * *** * *** * > x[i+1]){
* ** ** * * ** * **** ** *** * * * * * * ** * * ** **** ***** ** * * * * * * * * exchange the values of x[i] and x[i+1] */
** * *** ** * ** * ** * ** * * *** * **** * ** * ***** ** * * ** ** ** * * **** * temporary; * * * **** ** * * **** ***
*** **** * * *** ** * ** * *** * * * ***** *** *** ** * ** * * ** * * = x[i];
* *** ** * * * * * * * *** ** * * ** * ** * * * * *** ** * * **** * * * = x[i+1];
** * * * ** * *** ** * * * ****** * * * ***** ********** * * ** * * *** ** = temporary;
*** *** ** * ** *** *** **** * * * * * **** *** ***
** * ** *** *** ** *** * *** * * ** *** *** *
**** *** * **** * * *
* ** ** * ** * *** *
* **** ** ** print the array */
* * * *** * * * * * * * **** * sorting: \n");
****** **** * ** i = 0; i < size; i++){
* * ** ** ** * * * *** *** ** * * ** ***** **** ", x[i]); ** * * * * ** * **** *** **
* * * ** * * *** **** *** *
** *** * * *** * * * **** ** ** * ** * *
** * ** * ** ***
***** * * * * **** **
** * ** * * ** * * ** * * * ** **
** *** * * *** * ** * ******** * **** ***  
** * ** ** ** * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** * * * * * * * **** x[] = {77,22,88,11,22};
** ****** * * ** * size = 5;
    
* * * ***** ***** * * print the array */
**** *** * *** * *** * i = 0; i < size; i++){
** ** ** ** *** *** ** * * * * * *** * * ** *** ", x[i]); * * * ** * * ** * * * *** * ** * **
* * *** * ***** * ***
*** * *** ** *** * ****** *
*** * * *** ** * * ** ** ***
*** ** **** ** * * *** I need this to happen size-times */
** * * * * ** * * ***** j = 0; j < size; j++){
* ** ** ***** * * ****** ** **** * * from left to right */
* * * * * *** **** * *** * * ****** * i = 0; i < size-1; i++){
** ** * *** ** *** * *** * * ** ****** * ** *** * ***** *** **** ** * * i-th element with its neighbor to check if they are in order */
* ** ** **** * *** ** * * *** * * *** **** * * ** **** ** > x[i+1]){
* ** ** **** * ** ***** ***** * * ** * * *** ** * * * ** *** * ** * **** ** exchange the values of x[i] and x[i+1] */
* * ***** * * * *** *** * * ** ** ******** * *** ** ***** ** ** *** * * ** * ** temporary; * *** * * * **** * ** * * *** *
* **** * ** * * *** *** * * ** **** * *** **** ** * *** **** * ***** ** * * * = x[i];
* *** * * *** * * ** ** * ** * **** * * * * * * * ** ** ** * ** * * * * * *** **** * * * ** * = x[i+1];
** * **** ** * ** * * * *** * ** * ** ** * * * *** ** * * * ** ** * ** * * ** ** * = temporary;
* ** * * * * * *** *** * * ** * ** *** *** * * * * ***** *
* * * *** ** ** ** * ** ** * * ** * * **
** *********** *
* * **** * * * * * *
* * *** * * * * * * *** print the array */
* * **** * **** * ** **** *** * ** sorting: \n");
* * **** * * * * i = 0; i < size; i++){
* * * *** ** * * * * ** ** ** * **** * * ** * * ** * ", x[i]); * *** * * *** * ** * * ** * *
* * *** ** * * ** * **
* ** ** *** * ***** ** ** ***** * ****** * **
* ** * * ** * ** ** *
* * ** * * **
* ** * **** ****** **** * * * ** ** *
** * ** * * * * * * * ******* ******** * * ***** *  
* **** * * *** **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** * * * x[] = {77,22,88,11,22};
* **** * ** size = 5;
    
*** ********** *** *** ** print the array */
** * * * * *** * * ***** *** i = 0; i < size; i++){
* ***** * * ****** * * * * **** * ** * * ** * *** ", x[i]); *** * * * * ** * ** **
* ****** ** ** *** * * *
* * * ** ** * * ** ** ** * **
*** * * * * * ** ***
* ** *** * * * ** *** * I need this to happen size-times */
* ** * * * ** ** ** j = 0; j < size; j++){
** ** * **** * *** * **** *** * * ****** * * from left to right */
* * *** * ** **** **** ***** ******* ** * **** i = 0; i < size-1; i++){
* **** *** *** * **** **** * ** ****** * * **** * * ** *** * * *** i-th element with its neighbor to check if they are in order */
** ** *** * ** ** **** * * * *** ** *** ** ** * * ***** ** ** *** ** * * > x[i+1]){
*** *** ** * * *** * * * *** ** ** * ** * ** *** * ** ** *** **** * *** ** exchange the values of x[i] and x[i+1] */
* ** * * *** ******* * *** ** * * ** * * ** ** * * ** * * ** * ** *** * ** temporary; * * * ****** * * * * ** ** *
*** * * ** ** *** * * *** ****** * *** ** * * ** * * ** **** * * * **** * ** * ** * * = x[i];
** ** * * * ****** ** ** * * * ****** * *** ** * * * ** * * ** * ****** ** ****** ** * * = x[i+1];
* ** *** **** ** ******** * **** ** ****** ** *** ** * * *** **** * ** * ********* = temporary;
* ** * * * * * ****** *** * * * ** *** * ** * * * * * *
* * ** **** * *** * * *** ** **** *
** *** ** ***** * *
**** * * *** * *
** ** ** ** ***** *** * * * print the array */
** *** ** * ** * * *** * *** * sorting: \n");
** ** * * ** *** ******* i = 0; i < size; i++){
** ** * * *** * * * * ** *** *** * * ******** ", x[i]); ** * *** * * * * * **** *
* ** * * * * * ***
** * ** * *** * ** ** ** *** *
* * ***** ** * *
** ***** * **** * ***
** *** * ** * * *** ** ** *** *
* * * * * **** ** ** ****** **** * *  
** *** * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ****** ****** x[] = {77,22,88,11,22};
* *** **** ** ** ** * * * size = 5;
    
****** * * ** * ** print the array */
* ** ** ** * * ** **** * i = 0; i < size; i++){
* *** ** **** *** **** **** **** * * ***** ******* *** ", x[i]); **** * ** * * * ** ** * *** * *
* * * ** * * * * * *** * ** **
* **** *** ** * * ** * ** ** *** *
***** *** **** * **** *
* * *** * ***** * I need this to happen size-times */
* * ******** ***** *** * **** * j = 0; j < size; j++){
* * ** ** ** ** * * * *** * * *** from left to right */
***** ** ** * * * * ** * ** * ** * ** *** * * i = 0; i < size-1; i++){
** * * ** *** * * * * * * * * * ** *** ** * *** ****** ** ** * **** * * * i-th element with its neighbor to check if they are in order */
***** ** ** * *** * ****** * ** * **** * ** * * * *** *** * > x[i+1]){
* ** * * ** * * * * * **** * * ****** *** * ** ********* * * * * **** ** * **** exchange the values of x[i] and x[i+1] */
* * * * *** * * * * *** * ** ** * ** * * * ***** ** **** * * * * ** * * * temporary; * **** ********* * ******* * * * *
* * * *** ** * *** * * * ** * ***** *** * ** * * ** *** * ** * *** * *** ** ** * *** ******** ***** = x[i];
* * **** * * * *** * ** * * * ** *** ** *********** * ** * * ** *** * * * * *** = x[i+1];
** * ** ** * * ** **** * ***** * * * ** **** ** ** ** **** * **** * ** * * * * ** ** * = temporary;
* ****** * * * * *** *** * **** * * ** ** ***** * ** ****
** ** * * ** ** * * * ******* * ******* *
* * ** * *** *** * *** *** * * **
*** * *** *** ** * ****
* ** ** **** * * print the array */
* *** ** * * * *** * * * sorting: \n");
** * * **** * *** ** * ** i = 0; i < size; i++){
* * * ** * ****** ** ** *** *** **** * ** * * ** ", x[i]); * *** **** * * * **** * * * ***
* * * *** * * * *
* ** * ** * ** **** * **** ** ** * *
* ** * **** ** ** * *
* *** * * * ** * **
* ** * * * * ** * * ** ***** **** ***
** * ******* * **** * ** *** * * ** *****  
* * *** *** * * ** *** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.116
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users