0 like 0 dislike
7.1k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 7.1k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * **** * ** ** ** x[] = {77,22,88,11,22};
* * ** *** * ** * * * size = 5;
    
* * * ***** * *** ** print the array */
** * **** ** *** * ** i = 0; i < size; i++){
***** ** ** ** **** * * * * * *** * * * *** * ** **** ", x[i]); *** * ****** * * * * * * ** *
* **** *** *** * ** **
****** ** **** * ******** **** ** ** ** ** **
***** ** * ******** *
**** * *** * ** * I need this to happen size-times */
**** * ***** * * * * * j = 0; j < size; j++){
* * **** * ** **** **** ***** ** ** * ** from left to right */
* * * * ** * * *** ***** ** ***** * * * i = 0; i < size-1; i++){
* * * ***** * * * ** *** *** ** * * *** ** *** * ** * * i-th element with its neighbor to check if they are in order */
* * ** *** * ** ** * *** * * * ***** *** ***** * * * **** ** * ** > x[i+1]){
**** ****** ** * ** * *** * * ** ** * ** **** * *** ** ** * * ** **** * **** ** exchange the values of x[i] and x[i+1] */
** * ********* * * ** ** * * **** * * * *** * *** * * ** * * * * *** *** * * * temporary; ** *** * *********** *** ****** ** ***
* *** * ** *** ** * * * * * * * ** * * *** ** * * * *** *** * * * = x[i];
** ** ** ***** *** * ** ** ** * * ** * * * ***** ** * * ** * ****** * ** * * = x[i+1];
*** * ** * * ***** ** ** * * * ** * * * * *** * * * *** ** *** * ** * = temporary;
* ****** * * * **** * *** *** *** * * * **** * ** ** * *****
* * * ** * ** ** * * *** **** ** *** *
** * * *** ** ** * * ***
* * * ** * ** * * *
* *** * * ****** * ***** * print the array */
* * * **** * * * ** * * sorting: \n");
* * ** *** **** * * ** i = 0; i < size; i++){
** * * **** ** ** ** ***** ** * * * * * * * ** * * *** ", x[i]); *** ** * ** ** *** * ** ***
* ** ****** * ***
** *** * ** ***** ** * ***** * * * * * *
** ** *** * * ***
****** * ** * ** * **
* * *** * ** * ** ****
* ** ***** ** ** * ** * * * ** * **  
* * **** * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** ** ***** * * ** * * * x[] = {77,22,88,11,22};
* ** ** * *** *** *** size = 5;
    
*** * ** * * * * ** print the array */
*** *** *** ** ** * i = 0; i < size; i++){
** * * ******** * * ** * **** * * ** **** **** ** ", x[i]); * ** ** * ** ** * * ** **
* ** * * * ** * **
* ** ** * ** *** * * ** * *
* * *** * **** * * ** *
** * ***** ** * *** * I need this to happen size-times */
*** * * ** ** *** j = 0; j < size; j++){
* ** ** ** ***** ** ******* * ** ** * ** * **** **** from left to right */
* * * * ** ** * * * ** ** * ** **** * *** ** * * i = 0; i < size-1; i++){
** * ** ** *** ** * * * ** ** *** * ** ** ****** ** * ** * * * * *** * i-th element with its neighbor to check if they are in order */
****** * * * * * ** * **** ** * *** ****** ** * * * ** > x[i+1]){
** ** * * **** ** *** ** * * ** * * * * * * * * * ** **** *** * ** **** * ** * * ** ****** * * exchange the values of x[i] and x[i+1] */
*** * *** ***** ** * * ********* ** * * ** *** *** * ***** ** * * *** ** *** *** * * temporary; *** * *** * ** * *** **** **** **
* ** * *** ** *** * * ** *** * **** * * * *** * * **** * * * * ** * ******* *** * *** * * * * = x[i];
**** * ** ** * ******* ** *** **** ** *** ** * * * ** * * *** * * * * **** = x[i+1];
* *** * ** * **** * * * ** * * *** ** *** * * *** **** **** * * *** ** **** * = temporary;
** * ** ** ***** ** ***** *** ** **** ** * *** * * *** * * ** *** ****** *
* * * ** * * * * * *** ** * ** * ** *
*** * * * ** *** * * * *
** ** * ** * * * ** * *
* *** ********** * * ** ** ** print the array */
***** ** *** ***** ** * **** * * ** sorting: \n");
** ** ** * ** * * **** ** i = 0; i < size; i++){
* * *** * ** * * * * * *** * * * * * ** ** ****** ** **** * ", x[i]); ** * ** * * ** **
* *** * *** ** ** * *****
* ** ** ** ** * **** * * * *** **
*** ** * *** * * * **** * *
** **** * * ** * ** ** * **
*** * * * ** *** ** * * * *
* * * * ** **** * * * * ** * ***  
**** * ***** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** * * x[] = {77,22,88,11,22};
* * * **** **** *** *** size = 5;
    
* * ** * *** * * * * print the array */
**** * ** * *** i = 0; i < size; i++){
*** * * *** * * ***** * * * * ***** * * ** ", x[i]); ** * ** * ** *** **** ** * ** **
** ** * ** **** **
****** ***** * * ** * * * ** ** * **
**** * *** *** *
*** * *** * * **** ** I need this to happen size-times */
*** * * ** ******* *** j = 0; j < size; j++){
* * ** ****** ** *** * *** * ** * * ** * ** ** from left to right */
* ** * * * * * **** * ** * * * * ** * ** *** i = 0; i < size-1; i++){
* * * **** *** ** ** * * **** *** ** * ** *** * * * ** ** **** i-th element with its neighbor to check if they are in order */
** ** * * ******** **** ** * ** * * * * **** ** * ** **** ** * ** * > x[i+1]){
* * ** ***** * ***** ** * ** ****** * ** * * * * * * * ** ** ***** *** * exchange the values of x[i] and x[i+1] */
***** ** *** * *** * ** * * * *** * ** ** * * ** * ***** ******* **** * * * ** *** temporary; **** * ****** *** ** ** * ** ** ***
* * ** * ** * * ***** *** ** ** * * ***** ** ** * *** * * * * *** * ** ** * **** * * **** * * *** = x[i];
* * *** ** * * *** * ** * ** * ***** * * *** * ** * * * * ** *** * * * *** * = x[i+1];
* * ***** *** **** ** ** *** * * * * * *** * * * ** * * * ****** ******** **** **** * * * = temporary;
** * ** ** * ** *** * ****** * ** * * ** ** ** **** ** * * * *
* * **** ** * ***** ** *** * ** * *** * * * **
** ** * * * * ** * ****
* * * * ****** * ** ****
****** ** ** * * *** print the array */
* * * ** ** * ** **** * * * sorting: \n");
* ** ** * *** * * ** * i = 0; i < size; i++){
* * **** ** ** * ** ** * ** * ****** * ** * * * ", x[i]); ** ** * *** ** * * *** ** * * **
*** ** **** *** *** ****
*** ****** * ** * * *** ****
* * * *** ** ** **
** * * * *** *
* *** *** * * *** ** * * ***
* * ** * * * * *** ** * * ** * * * ***** * **  
** ** ****** ******* ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** ** * x[] = {77,22,88,11,22};
** *** * * **** ** * size = 5;
    
* *** **** ** ** print the array */
* * * * * ** ****** * ** i = 0; i < size; i++){
***** * * * ** ** * ** ***** * * * * ** * ", x[i]); * ** **** * * * *** * *** * * * ** *
* ** * * ** ** * * ** *
* * * ** * * ** *** ** ** * ** ** * *
* ** * ** ***** * * *
* * ** ** * ** ** * I need this to happen size-times */
* **** * * *** *** j = 0; j < size; j++){
** * * * ** *** **** * * * *** ***** ** from left to right */
** *** ** * * ** * *** * ** *** ** * * * *** i = 0; i < size-1; i++){
* * ** * * * **** * ** * * * *** ** * ** * *** * * * * ** i-th element with its neighbor to check if they are in order */
** *** * ** * *** * * * ** * * ** ****** *** ** * * * > x[i+1]){
* ***** * * *** * ****** * * ** * ** * * ** * * * * ** * **** ** * ** *** * * ** exchange the values of x[i] and x[i+1] */
*** ** * ** * * * * ** ** ** ** * ** *** * * * ** ** ** *** *** ** * temporary; *** * * * ***** ** *** **** ****
** * ** ** * * * *** * ** **** ** ** ** *** * * * ******* * * * ******* * * * * * * * * = x[i];
****** * *** * * * ***** * ** * ** * * * * ** * * * **** * *** * * ** ** * * * **** ** ** ** = x[i+1];
** **** * * ***** **** * ** **** * *** * * * * * * ** * * * **** * ***** ** * *** ** *** * ** = temporary;
** ** *** * ****** * ** * *** *** * ** ** ***** * *
*** * * *** * *** ** ** * **
** **** * * * ** * **
* **** * * * ***
****** ** *** ** * print the array */
* * *** * * ** **** *** * * * ** * sorting: \n");
* ***** **** * * ** * i = 0; i < size; i++){
* * * * ** * * * **** ** * * ** * * *** *** * ", x[i]); * * * **** ** * * ** ***
* ** ** ** ** ** **
*** * ** *** * ***** ** *** *
*** ** ** ** * **
* * ** * ** * ****
****** ** **** ** * * ***** ** * ***
* **** * * * * ** * ***** * * *** * * ** ** ***  
* ** ** * *** ** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** ** * * * *** ** * ** x[] = {77,22,88,11,22};
** **** * ** * ** * ** ** size = 5;
    
* * **** * ** **** * * print the array */
** * ** *** * * * * * ** * i = 0; i < size; i++){
* * * ** *** **** * * *** *** * * *** ** * ", x[i]); ** * * ** *** ** * * * * * * *
** **** * * *** * * ***
** * ** ** * **** * * * * * ***** ** ***
* * * ***
***** ** ***** * ** ** I need this to happen size-times */
** ** * **** * * ** ***** j = 0; j < size; j++){
* ** *** * * * ******** *** ** *** * from left to right */
* ** * * ** *** * * ** ** ******* ** i = 0; i < size-1; i++){
****** **** * ** * *** ******* ** **** ******* * * ** * ** * * * ** * i-th element with its neighbor to check if they are in order */
* *** ** ** * ** **** * **** ** ** * ** * * ** ** * ** *** > x[i+1]){
* ** ** ** * *** ** * *** ***** **** **** **** ***** * ** * ** * *** *** **** ** * exchange the values of x[i] and x[i+1] */
*** ** * *** * * * * *** ** ******* *** * * * ** * *** * * * * * ** * **** * * ** temporary; * **** ** * * ** * **** ** **
** ** * * **** * * ** ***** ** * * * * ** * ******* ** *** ** ** ** ** * ** * * * ** ** = x[i];
**** * ** * ** * * ** ** * * * * **** ** * * * * * * * * **** *** ** * = x[i+1];
* * ** * * ***** * * *** **** ** * ** ** ** ** * * * ** * * ** ** * = temporary;
*** * ** * *** * ******** ** * **** * ** ** * ** * * *
* **** **** ***** **** * * **
** ** * ****** * *
* * ** *** * ** * *
* * * * **** *** ***** ** print the array */
** ** ** * **** * ** * * ** sorting: \n");
** * * ** * ** ** * * * i = 0; i < size; i++){
* ** * ** ** *** * **** * **** ** * * * * ** ", x[i]); * ** *** ** * * ** * *** ** ** **** **
*** ** **** **** ** *** **
** * ****** ** * * * * ** * * * * * *
** *** * ** ** *
** * * * * * * **
** ** * * ** * * **** * * * ******* ****
* ** * ***** * ** * ** * * ** ** ***** ** **  
* * * *** *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * ** ** ** * x[] = {77,22,88,11,22};
* * *** ***** *** ***** size = 5;
    
**** * ** * ** * * * * * ** print the array */
* ** * * ** ** * * * ** * * i = 0; i < size; i++){
* ********** ****** * ** ** * * *** **** * * *** *** ** ** ", x[i]); * ** * * * * *** * *****
* ****** * **** ** **
** ** * ******** *** * * * * *** * * *
* ** *** ** * * * ** *
*** ***** * ***** I need this to happen size-times */
* * * ** *** **** * ** * *** * j = 0; j < size; j++){
* *** *** ** * * * * *** **** ** * ** * * * * from left to right */
* ** * *** ** ** * ** ** **** ****** ** * * **** i = 0; i < size-1; i++){
** ****** *** * ** * * * * *** ** **** ** **** * ** * * * ** ** * ** * i-th element with its neighbor to check if they are in order */
* * *** ** ** ******* * **** * * * * ****** * * **** ***** * * * * ** * * *** *** > x[i+1]){
**** ** ** ** *** * * * * * * *** * * *** *** * *** * *** * exchange the values of x[i] and x[i+1] */
*** ** ** ** *** ** ***** ********** *** ** * *** **** ** ** * * * * ********* temporary; * * * * * * * ** ***
* *** * *** ******** * ******* ** *** *** * ** * * * *** * ***** *** *** ** * **** ** * = x[i];
** ** * ***** * *** * * * ****** *** * * * * * * * ** **** ** ** ** * ** * * ** ** = x[i+1];
*** * ** *** * * ** * * ** * **** *** * ** * * ***** **** ** ** ** * * ** *** *** = temporary;
* * * * * ** *** * * ** * * *** ** * * *** * * * *
****** *** **** * * * * * *** * *** ****** ****
** * * ** ** **
* * * * * ***** * *
* *** *** * *** * * print the array */
* *** ** ** * * **** * * ** * *** * sorting: \n");
* *** ***** **** * i = 0; i < size; i++){
* *** * *** * * * ** * * ***** * * * ** * ", x[i]); * * *** **** *** * * *** *****
*** **** *** * ** *** ****
* ** * *** * ** ** *** ***** * *****
* ** ** *** ** *** ** * *
** *** ***** *** * **
** * ** ** * * *** * **** * *
* * * ** * * *** *** * *** * ** * ****  
* * * * ** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** ***** * **** **** * x[] = {77,22,88,11,22};
** * * * **** ** * * size = 5;
    
** ******** * *** * ** * print the array */
*** * * * * * ** * * i = 0; i < size; i++){
** * *** * * **** * ** *** * * **** * ** ** * * * ** * ", x[i]); * * ** *** ** ** ***
* * * ** * **** ********
*** * * * * *** * * * ** *** ***
** * ** * * * * *
* * ** ** ** **** * * I need this to happen size-times */
** * ** * ** ******* ** ** j = 0; j < size; j++){
** ** ** ** ** ** ** *** ** *** from left to right */
** ** ** **** ******** ** * * *** **** * * **** i = 0; i < size-1; i++){
*** ** ***** ** ** * *** ** ** * * * ** * **** ******** ** * *** ** *** i-th element with its neighbor to check if they are in order */
** * * * *** *** ** *** ** ** ** **** * * **** ** *** * > x[i+1]){
* * * * * ** *** * ** * **** * ** ****** * * * * * ** ** ** ****** exchange the values of x[i] and x[i+1] */
** **** * * ****** **** *** * **** *** * **** * * **** ** *** * * ** ** *** * * * ** * * *** temporary; * * * * ** ** ** * * * ***** *******
* **** * * * ** *** * ** ** * ******* **** ** ** * * ** * * * * ** ** **** *** * ** = x[i];
** * * * *** * * ** * * * ** *** ***** * * * *** *** ** * * * * ** * ** * * = x[i+1];
* ***** **** ** * ** *** * * **** ** ** * * *** ** *** * **** * ** ** ** *** = temporary;
* * ** * ** * * * **** * ** * * * * * * * * ** * *
** ** * * * *** * *** * *** ** * * *** *
*** * ** *** ** ** *
* * * * ** ****** *
** * **** ** ** * * *** print the array */
* ** **** * * * ** ** * *** ** * * sorting: \n");
*** * *** ** ** ** * ** * * i = 0; i < size; i++){
*** ** * ** ** *** * * * * * * * *** ** * * ** ", x[i]); * ** *** ** *** *** * * **** * **** **
** ** ** * * * *
* ** * * ** * *** * * * * ** * *** ** *
* ** ** *** * **** *
* ***** *** * *
** ** ** ** ** * * ** ***** *
**** *** ** * ***** * * ******** * * * * * *  
** ** ** * *** * **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** * *** **** *** x[] = {77,22,88,11,22};
** ** *** ** * ** size = 5;
    
* ***** * *** ***** * *** print the array */
** * * * * * *** ** i = 0; i < size; i++){
***** ***** * **** * ** * * ***** * * * ", x[i]); *** ** * **** * * *** * ** * ** ** ***
* * *** * ** * * *
* * ** * * ** ** * * ** ** *
* **** ** *** ** ** * **
* ** ** * * ** *** * I need this to happen size-times */
*** ** *** ** *** * * j = 0; j < size; j++){
* *** ** * * ** * * ** **** ** * from left to right */
* * ***** * ** * * ** * **** ** * ****** *** i = 0; i < size-1; i++){
* * * * * * * * * ***** * ***** * ** *** ** * * * *** *** ** i-th element with its neighbor to check if they are in order */
* * * * * ** * ** ******** * * * * * *** ** * * * ** ******* > x[i+1]){
** * ** * **** *** * *** * ** ** * * ** * ** * *** ** *** * **** * * * * *** *** ** ** **** exchange the values of x[i] and x[i+1] */
** * * *** **** ** * * * **** ** * * * ** * * ** **** * ** * ** *** ** ** * *** temporary; * * *** * * ****** **** *
* * * ****** * ** * * *** ***** ** ** * *** ** * ** **** * * ** * ** *** **** ** * * * = x[i];
* * **** *** * ** * **** ** ****** ** ** **** ** **** ** ***** * ** * * ** * ** * = x[i+1];
* * *** **** * ** *** ** * * * ** * **** **** ** * ** * * ** * ** * * * * ** * *** * *** * ** = temporary;
** ****** * * *** * ** * *** * *** * **** ** * * * * ** *
**** * * ** * * * * **** ** * **** *** * *
**** * * * ** *
** * * *** * ******
* **** * ** *** **** ** * print the array */
** ** * **** * *** * * * *** ** * sorting: \n");
*** ** ** * ** **** i = 0; i < size; i++){
* *** * * ** ***** * ** ** **** * ** * * ** ** *** ", x[i]); *** * **** * * ** * * * *
* * * * * ** ***** *
* * * * * * *** ** * * * *** * *** **
* * **** * ** * ***
* *** * ***** *
* ** *** * ** ***** ** ** ** ** *** ***
* ** ** *** * * ** *** ** ** * ** * * *  
** * ** **** ** ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * **** *** * **** * * ** x[] = {77,22,88,11,22};
** * * * * * * ** ** size = 5;
    
* *** * * * * ** *** * print the array */
*** * * **** * *** * i = 0; i < size; i++){
*** ** * ** * *** * * * ** * ********* ** ****** * ** * * ", x[i]); ** *** ***** *** ** ** ** ****
*** **** * ** * * *
* * * * * * ** ** ** * * * **
** * * ** * * * *
**** *** ** * * ** I need this to happen size-times */
** * ** ***** ** * ** * * * j = 0; j < size; j++){
** ** * * * *** ** * * * ** * * * * * from left to right */
* * ** ** * * ***** * ** * * * * ** ** i = 0; i < size-1; i++){
** ** * * *** * **** * *** * * *** ** *** * *** * * ** * ******* * i-th element with its neighbor to check if they are in order */
* ** ****** ** * ******** ** ** **** * **** ***** *** ** ** * * ** * > x[i+1]){
* * * * * ***** * * **** ******** * **** * * ** *** *** ** * * ** *** * ****** ** ** exchange the values of x[i] and x[i+1] */
******* ** * * ** * ** ** ** ** ** *** *** * ** * ***** ***** * ** * * * * * * * *** temporary; **** ** *** ** * *** * ***
*** **** * * ** * * ** ** ** * ** * * * * * ** *** * ** ** * * * ** ** * * * * ** = x[i];
* * ***** * ** * ** * * * ****** *** * * * ****** * *** ** ** * **** = x[i+1];
* ** * * *** ***** ** * ** * ** *** * ** * ** ** * ** ********* * ***** * *** * ** **** = temporary;
******** *** ** * **** * * **** ** * * * * ** *
** * * ** * ********* ** ** ***** *** * **
* ** ****** * ***
**** *** * * * ** *
** * **** * *** * * print the array */
* ** ** * * * * * **** * * * * sorting: \n");
** * *** * * * * i = 0; i < size; i++){
* **** ** * ** ** *** * * ** **** *** * * * * * ", x[i]); * * * * *** * ** * * *****
*** ** ***** * ** * *
*** *** *** * ***** **** ** *** * * **
* * * * * * ***
** *** * *** * * **
* ** *** **** *** * *** * * *** ***** * *
* *** * * * * ** ***** ** * * ********* *  
** *** * **** ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * *** ** * ** x[] = {77,22,88,11,22};
*** **** * ***** * ** * size = 5;
    
** ** ** *** *** **** print the array */
** ** *** * *** * ** i = 0; i < size; i++){
*** * *** * ** * * * *** * * * *** * *** *********** * ", x[i]); ****** *** * **** ***** * ***** **
** * ******* *** ****
* * ** * ***** ** * * * ** ** * ***
**** * * * ** * *** * *
* ***** * ** ** I need this to happen size-times */
** ** * * ** **** * ***** * j = 0; j < size; j++){
* **** * * **** * * **** ** * * * ** * from left to right */
** ***** ** * * ** ** * **** ** *** ** ******** * i = 0; i < size-1; i++){
*** * * * * ** ** ** * ** * *** * * * ****** * ** **** * * * **** i-th element with its neighbor to check if they are in order */
*** * **** ******** * **** * ***** * * * ** * **** *** * ** * ****** **** > x[i+1]){
* ****** * ***** * * * *** * * ** * * * * ****** ***** * * *** *** *** * * * * ****** exchange the values of x[i] and x[i+1] */
** *** * * * * ** ***** ** ** **** ** * ** * * * **** * **** ** *** * * **** * * temporary; * ** * ** * * * * * **** **** **
*** * ** * * ** * * ***** ** ***** * *** ** **** * ******* ** * *** * * *** = x[i];
* * ***** ** *** * * **** ** ** **** * * *** * * * * * ** ** * * * **** * * = x[i+1];
** * * * ******* **** ******** ** * * * *** * * * * * ** ** ** ** * * * ** * * * * = temporary;
*** ***** * * ** * * * * * *** * * * ******* * ** ****** * **** **
* *** ** * ** *** *** * *** * ** * ** ** ******
*** ** * ** ** * * ** * *
** **** * ***** ***** *
*** ** * ** ** * ** * print the array */
***** *** ***** * **** ** * ** * sorting: \n");
* ** * * * ** *** * * * * i = 0; i < size; i++){
** ** ** * * * * ** * *** * * * * ****** * ", x[i]); * ** **** * * ** *** * * *
** * ** * ** * * * * *
** *** ****** * *** * ** *** ** ***
* * ***** * **
** * ** ** * ** *
* * * * ** * ** * * ** *** ** ** *
* *** ** *** ** **** ******* * * * ** *** * * ****  
* ** * ** ** ** ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.10
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users