0 like 0 dislike
9.3k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.3k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * * * ** x[] = {77,22,88,11,22};
* * **** * * * * * * * size = 5;
    
***** ** * ** *** print the array */
* * * * * * ** i = 0; i < size; i++){
*** **** * ** **** **** * * ** * ** *** ** ** * *** ** * * ", x[i]); ** * ** * ***** ** *** *** ******
* * * ****** ** *** *
* * ** ** * * *** * ** * *
* * * * * * * **** ** *
** * * * ** * * * I need this to happen size-times */
*** ** * * ** * * **** j = 0; j < size; j++){
* * * * *** ** * * * ** * ** * ** * * * * from left to right */
* * * * ** * **** **** **** **** * *** * * ***** i = 0; i < size-1; i++){
* * * ** * ** **** * * * ** * * * * ** ** *** ** ** *** ** * * * i-th element with its neighbor to check if they are in order */
** *** ** * ** ** * * * *** ** **** * ** * ** ** * *** ** ** * * > x[i+1]){
*** * *** * * * *** * * * ** **** * * * * * * ** ** ****** *** * ** * * exchange the values of x[i] and x[i+1] */
**** * ** **** ** **** * ** ** ****** * * *** * **** * * * ** * ******* ** * ** * * * temporary; * * ** * ***** * * * **
** ** * * ****** * ** * * ** *** **** * * ** ***** ** ** *** * ** * ** ** ** * * ** ** = x[i];
** ****** ** * * * * **** * *** ** * * * * * * ** ** ** * * * * * * * = x[i+1];
** * * * * ** ***** * ** ** ** * ** * * ***** ** * * *** * *** *** *** ** *** * * = temporary;
** * * ***** * * * ********* * *** **** * ** ** * * ****** *
**** ** ** * *** *** ** *** **** * * * * *
******* * * ** * * *
* *** * * ** * * ** * ***
* **** * * ****** * * print the array */
** * ** * * ******** * * * * ** **** sorting: \n");
* * * ** *** ** * * * * ** i = 0; i < size; i++){
* ** * * * **** *** * * * * * ** *** * ***** * * ", x[i]); * ** * *** * * *** ** * *
* ***** ** * ** *** ***
**** * *** ** ***** ** * *** ******
* * ***** ** * **
* ** ** * * * * * *
* ***** ** ** *** *** ** * * * * ** **** ***
**** * * ** * *** ** ****** * *** * *** * ***  
* * * ***** ** * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * **** ** x[] = {77,22,88,11,22};
* *** * **** * *** size = 5;
    
** * ** * * **** ** * print the array */
* * * * * * * ** * *** i = 0; i < size; i++){
* * *** * ** *** * * ** * ** *** * * * *** **** ** * **** * * ", x[i]); * * ** ** *** ** ** *****
*** *** ** *** * **** * *
* ****** ***** * ** * * * ** ***
******* * * * **** ** *
** ******* * * ** ***** I need this to happen size-times */
**** * *** * *** *** j = 0; j < size; j++){
** * **** * ** * * * * ** *** * * *** * * from left to right */
* * * * **** ** * * ** * * ** * * ***** ***** ** *** i = 0; i < size-1; i++){
** * * * *** ** ******* * * * ** * * * * ** ** ** * * * ** * * i-th element with its neighbor to check if they are in order */
*** * * * ***** * ***** ** **** ** * *** ***** * * * * * * **** > x[i+1]){
* * * **** ** * * ** ** * *** ******* ** *** * **** * ** ** * *** * * ** * * ** * * * exchange the values of x[i] and x[i+1] */
* ***** **** ***** *** * *** ** * *** * * *** * ******** * * * * *** *** * ****** ** ** * ** * * temporary; * * * * * *** * ******** *
** *** **** * * ** ** * ** ** * ** * ** * **** * ** ** * * * * ** * * * ** * * = x[i];
* * ** *** **** * * * *** ******* * * * * **** * * *** *** ***** ** * ** ** * * * *** * = x[i+1];
* ****** ** ** * * * **** * * ***** * * * **** * ******** * * ****** * * * ***** * ******* = temporary;
** ** * * * * ** ** ** ** ** * ** ** * *** * * *** * *** **
*** * * ****** ** *** ****** * * * * ** *
*** *** * * * ** * * * ***
* * ** * * ** ** * * ***
* * * * * ** ** ** print the array */
* * ** *** * * * * **** * ** **** * sorting: \n");
** * * * ** ** ** * ** i = 0; i < size; i++){
* * ***** * *** * * *** * ** ** * ********* * * ", x[i]); * * * ** * ** * **** ** ** * ** **
** * * ** * * ** * *
** * * * * * ***** ** ** ** *** * **
* * ***** *** * ******
**** ***** ****** * ** *
** ** ** ** ** * ** * * *
* ** ** ** *** * * ** *** ** * ** * ** ** *** **  
* * * * * ******* * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** ** * * *** * x[] = {77,22,88,11,22};
** ** * * ** *** size = 5;
    
* * * * * **** ***** ** *** ** print the array */
* * ** * ****** * *** * * * * i = 0; i < size; i++){
* ** * * *** ** *** * * **** * * **** **** **** ", x[i]); * ** * **** ** * **** **** * * *
*** ** * * * * * *
* * * *** * * * * ** * * ** *** **
* * * ** ***** ** *
*** ***** * ** * ** *** I need this to happen size-times */
* *** * * ** * ** * j = 0; j < size; j++){
* * *** ** * * * *** * * * **** * ** ** ** from left to right */
* ** * * ** ** ** ** * ** * * * * ****** *** * i = 0; i < size-1; i++){
* **** ** ****** ** ** *** * ** **** ****** ** *** * * **** * * * i-th element with its neighbor to check if they are in order */
***** ******* *** * ** ** *** * **** * * ***** ** * ** * ** * ***** ** > x[i+1]){
* * ** * * * ***** * ** * * * * * ** * * **** ** * ** * *** **** * ** * ***** exchange the values of x[i] and x[i+1] */
** ** *** *** * * * * * * * * * ** * ****** * * ** *** *** * * temporary; ** * * * ***** * ****** ** **
** *** *** * ** * * * * *** *** * ** ** *** *** ***** * **** *** *** ** * **** *** * * ** = x[i];
** ** * * ** ** *** * * * ** * ****** ** *** ** ** ** ********* * *** *** * *** * ** = x[i+1];
** **** * * * * * ****** * ******* * * ** ** * **** * * * * ** **** * ** *** **** * = temporary;
* ** * * * * ** ** **** ** ** * ** **** * * ** * * * * * * * * *
* ** * * * * *** * * *** ***** * ** ****** * * *
** * * ** * * ****
* * ****** ** **
* ** * *** print the array */
* ** *** * * *** *** * ** ** sorting: \n");
*** * * ** ****** * * ** i = 0; i < size; i++){
** * **** * * * ****** ******* * *** * ***** ** * * ", x[i]); ** ** ** * **** * * **** ** *
* ** **** * * **
* * * * *** * * * * ** ***** ** * ** *
* *** *** * * * * **
* * ** * * ** **
**** * * ***** ** * ** * * *** ****
* * ** * * *** * * ** **** * ** * ** * *  
* * *** * ***** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * ** * ** ** x[] = {77,22,88,11,22};
* ** *** * ** size = 5;
    
*** * * ******* * print the array */
* *** *** * * ** * *** i = 0; i < size; i++){
** *** * ** * *** **** * * * ** * * ", x[i]); * * ** * * *** ** * *** * **
** **** * ** ******* * *
* ***** *** * * * *** **** **
**** * ***** *** **
*** ** ** * * ** * I need this to happen size-times */
* ** * *** * * ** * j = 0; j < size; j++){
***** * *** ** ** * ** *** * ** * ******* from left to right */
* * * ***** * * **** ** *** * * ** * ** * i = 0; i < size-1; i++){
***** *** * ** *** * * * * * * ** ** *** * **** * *** * * ***** i-th element with its neighbor to check if they are in order */
*** ***** * **** * * * ** * * *** * ** *** *** > x[i+1]){
* ** ***** * ** ** ** * * **** * * ** ***** *** ** * * * * * ** *** * ** ** *** * exchange the values of x[i] and x[i+1] */
* * ** * * * **** * * ******* * *** ** **** * * **** ** * * ** ** ** * * * *** *** * ** * * temporary; * **** ** ** **** *** *** *
** ** ** *** ** * ** * ****** *** *** ***** ** * * * * * ** * ***** * ** * * * **** ** = x[i];
* ********* * ** **** ** *** ** * * * ** * ** * * *** ** *** * * * * *** ** ** = x[i+1];
* ** ** *** * * ** ***** *** *** * *** ** * ** * ** * ***** * ** * * ** * ******** = temporary;
* ** * ** * * * * * *** ** * ** * *** *** **** * * * ** **** * * ** *
*** * * ** ** * *** * * *** * * * *** **
* *** * * * ** ** *
* *** ** * *** **
** *** * * ** * * * print the array */
* *** * * ***** ******** **** * sorting: \n");
**** ** ** *** ** ** i = 0; i < size; i++){
* * ** ** ** **** ** *** * ** *** **** ** ** * * ", x[i]); * * ** ** * ** ** ** ** * ** * *
**** * ***** * ** * *
** * *** * ** * * * * * ***
* **** ** ** * ***
* * * * * ********** **
** * ** * **** * *** ** ******* * **
*** ** * **** * * ** * * * ** * *** * * * **  
**** * * **** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * ** * ** * x[] = {77,22,88,11,22};
* *** ** * * * * * *** *** size = 5;
    
** *** * * * ** print the array */
*** ** ** ** ** *** * * * i = 0; i < size; i++){
** * * ** * **** *** ** *** * * * * ** * ** * * ", x[i]); * * **** ** * ** * *** **** **
*** *** ** ** * **
* ** ** ****** * ** * * * ** * * * * *
* * * ***** ** * **
* *** ******* * * * I need this to happen size-times */
*** ** * * ** * * **** j = 0; j < size; j++){
** * * * ** * * * * ** * * ** ** * from left to right */
** ** ** * *** * * ** * ** * * *** **** *** i = 0; i < size-1; i++){
** ***** * *** * ** *** *** * ** * * * * * * * *** ********** *** * * *** * i-th element with its neighbor to check if they are in order */
** ** *** * **** * * *** ****** * * * * ** * *** * ******** *** *** > x[i+1]){
* ****** *** * ** **** * *** **** ** ** * * * **** * ** ******** * ** **** **** ** ****** ** exchange the values of x[i] and x[i+1] */
* **** * * ** * ** * * * ** * ** * * * ** ** * * * ** * * * * ***** * * * ** temporary; *** *** * ** **** * * * * * **
** ** ****** * * ** *** * * ** * * * * * ** ** * ** * * * * * * * * * * **** * *** ***** * * * ** ** * * = x[i];
**** * ** ** * * ** * * ** * * * * * ** *** * *** * * *** ** *** ** * * **** * = x[i+1];
*** * * *** * ** *** * ** *** ** ***** * ***** * ** ** ***** * * * * * ** * * * = temporary;
* * ** ** * * * * **** * * *** * *** * *******
****** ** ** * * ** ***** * * * * * * *
** * * * *** * *
* * ********** * * ***
**** * * ** ** print the array */
** ** ** *** * * ** **** * sorting: \n");
* * ******** ** ** *** * * i = 0; i < size; i++){
* ***** * * * ** * * * * * * ** *** *** * ** **** * ", x[i]); * ** * ** * ** ** ** * * **
* *** ** ** * ** * *
** *** ** * ****** *** ** ** * **
** * **** ** **
** * * ** *** *
* * ****** ** ***** * ***** *** ** * ****
** * * ** * *** ** * *** *** ***** * * * *  
* * *** ** *** * ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * ** * ** * x[] = {77,22,88,11,22};
* **** * ** *** * * **** size = 5;
    
** * * * ** ***** print the array */
* * * **** ** * * *** *** i = 0; i < size; i++){
* *** * * * * * * *** *** ** * * **** * ****** **** ", x[i]); *** * * ** * * **** * *****
* * * ***** * ** * *
* ** * * * * * * * *** ** * *
** * *** ** * *******
* ** ****** * *** ** * I need this to happen size-times */
** ** * *** * *** *** j = 0; j < size; j++){
* ** ****** * * * ** * * *** * **** * *** ** from left to right */
** * * **** *** * ** * * *** * * * *** *** i = 0; i < size-1; i++){
**** ** * *** ** **** * * * * * * *** ***** ** ** ** **** ** *** * * i-th element with its neighbor to check if they are in order */
** ** * * ******* * **** * **** ** **** ** *** * * * * * * * * > x[i+1]){
* ** * * * * **** **** * ***** * ** * * * ** * * **** *** * **** exchange the values of x[i] and x[i+1] */
** *** ** ** *** **** * * * * * *** *** ** * * ** * * *** * * * ** * * ** *** * temporary; ** ** ** ** ***** *** ** *
* ** ** ** * ****** * ** * ** *** ***** ** *** * ** ** * * ** *** * * * = x[i];
* ** * * * *** ** * ** ***** ** * ** *** * ** * * *** **** ** ** * * **** ** = x[i+1];
** * ******** * *** **** *** * * * * ** * * * * * ****** *** ** * * * * ** ** * *** = temporary;
* * * * *** * ** * * *** ***** * **** **** ***** * * * * * ** *
* * ** * * * ** *** * ** ** * ** **** *** **
* * *** ** * *
* * * * * ** ** *
* ** * *** ** *** * print the array */
* * * * * * **** ** *** * sorting: \n");
** ** ** ** *** * *** i = 0; i < size; i++){
**** *** ** * ** * * ** * * * **** * ** * * * ** ", x[i]); ** **** * *** **** * * *** * *
* ** * * ** * * **
* * * * * ***** * *** ** * ***** ** ** ** **
* * * * *** ***
**** ** ** **** *** *
* * ** *** * * * ** * ** * *** *** * * *****
* * ** ** * * * * * * * * * * ******  
**** ** * * *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
********* * ********* * * x[] = {77,22,88,11,22};
** ** *** ** *** * * ** * size = 5;
    
** *** **** * *** * ** print the array */
* *** ** * * **** * * * i = 0; i < size; i++){
** * ******** ** ** * * * * ****** ***** * ** * ** ** * ", x[i]); * * *** * * ** * * * * ** * **
* * * * * * ** *** *** *
* * * *** *** ***** *** * * ** * * * *
** * * ***** * * ****
*** * * * * * ** * ** I need this to happen size-times */
** ** *** *** * * **** j = 0; j < size; j++){
*** *** * ** **** *** ** * * * * *** ** * ** from left to right */
* * *** *** * ** * ** **** * *** * * ******* * i = 0; i < size-1; i++){
* * * *** *** * **** * ** * * * * * * * **** ** * *** * *** ** *** i-th element with its neighbor to check if they are in order */
** * **** *** * * * *** * ** * * * * * * ** *** * *** ***** ** > x[i+1]){
*** * * * ** *** * * ** ** *** * * * ** * * ** * *** ** *** * *** * **** exchange the values of x[i] and x[i+1] */
* * * * *** ** * * * * * ** * * *** * ** * *** * * *** **** * * * **** *** temporary; *** ** * * **** *** * * * ** *
** *** * **** **** * * * * **** * * * * ***** * * * * * * ***** * *** * *** ** *** * = x[i];
*** * ** ** * * * ***** **** ** * * * *** ** *** ** ** ** ****** * * ** = x[i+1];
* **** * * * * * ** * * * *** * ** * * * * *** ** ** *** *** * ** * * = temporary;
** *** ** * ****** * ***** * ** * ** ***** * *** **** **** ** ** ** ** ** *
* * * * * * ** *** * *** * * * ** ** *
* * ** ***** ***
* **** * ** ** **
** ** ***** ** *** * * print the array */
** * * ******* * * ******* * * * ** sorting: \n");
* *** ** * *** * *** i = 0; i < size; i++){
* *** * ** ** * *** * * * *** ** *** ** ** *** *** ", x[i]); *** * * ***** * ** *
*** **** * ** * *** *****
* * * ** ** *** ** ** ** * ** * *** *
* * ***** ***** **
** *** * ** * ** ** ** * *
* ** *** *** ** ** *** *** * * ***
* * * * **** *** ** * * * ** ** ** ** * ** ** * ** * * *  
* * ** * ** ** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ***** *** **** * x[] = {77,22,88,11,22};
*** * * * *** * * * size = 5;
    
*** **** * * *** ** * print the array */
* ** * ** * * ** *** *** i = 0; i < size; i++){
**** * ** **** * *** *** * * ** ** * * ** *** * ", x[i]); *** *** * * * * * * * ** ***** ** *
** *** * * * * ***** *
* ** * * * ** * * *** ** ** * * * * ** ***
**** **** * * **
** **** * * ** *** * ** I need this to happen size-times */
* * * ** * ** * * ** j = 0; j < size; j++){
**** ***** *** * ******* ** * *** ** * ** from left to right */
*** *** * * * **** *** * * * * * * * ** ** i = 0; i < size-1; i++){
* * ** ** * * * ** * ** *** *** * * *** * * * * ** * * i-th element with its neighbor to check if they are in order */
** * * **** *** * **** ** **** * * * * **** * ** **** ***** **** ** * * > x[i+1]){
* ** ** * * **** ** * * ** ** * * *** ******* **** * * ******* * *** * * ** * ***** exchange the values of x[i] and x[i+1] */
* ** * * * ** * ***** ** * *** * ******** * * * * * *** ** ** * * *** * ** ** * ** * temporary; ** ** * ** * * * *** * *** *
* *** * **** * **** * * * * *** * * * **** *** ***** ** *** ***** *** *** * ** ** * ** ** = x[i];
* * * *** * * ** * * * * * *** * ** *** *** *** * * ** * * = x[i+1];
* *** ** ** * * ** * ** *** * *** ** **** **** * * **** **** * ** ***** = temporary;
** *** * * * * * ** * ** * * *** * *** * * * * ***** *** * *
* * ** * *** **** * ** * * * **** * * *
* ** ** * * *
***** *** *** ** ***** **
** ** ** *** * * * * print the array */
**** * *** * ** ** *** * sorting: \n");
**** *** ***** *** ** * * * i = 0; i < size; i++){
* * ** * * ** ** * *** ** * * **** * *** ** * * ", x[i]); **** ****** ** * * **
*** *** **** ** *** **** *
*** ** ** *** * * * ** **** *
** * * * * **** * *
* * ******* * **
* ** * ******* ** *** *** ** * ** *** ** *
** ** **** **** ** * * ** ***** ** * * ***  
**** * ** **** ** * ***** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * *** **** * x[] = {77,22,88,11,22};
**** *** ***** ** * size = 5;
    
*** * * * * ** * * print the array */
* ** ***** ** *** i = 0; i < size; i++){
*** ***** ** * **** * ** *** ** * ** **** ** * ** *** ** ", x[i]); * * *** * ** *** * *** * ** *
* * * * * ** ** *
* **** *** ** * ** *** * ** *
***** * **** ****** **
** ** *** ** * *** * I need this to happen size-times */
** * * *** ** * *** * ** j = 0; j < size; j++){
** ** ** ** ** * ** ** ** ** **** from left to right */
* ******* *** *** **** ** * * *** * ** * *** i = 0; i < size-1; i++){
* * ** ** ********** ** * * *** *** * * ** * *** ** * ** ******** i-th element with its neighbor to check if they are in order */
* * * ** * * ** ** * * * * ** * ** ** ** * *** * > x[i+1]){
* ** * * * * * * * ** * * ** * * * ** *** * * ****** * * * * ** * ***** *** exchange the values of x[i] and x[i+1] */
** * ****** *** * ** * ***** *** * **** *** * * * * * * * * ** * * ** * ** * temporary; *** *** * * *** ********* * *
* * * ** * * **** ** ** * * ***** * *** * ** * ** * * **** * * *** * * ** *** *** * = x[i];
*** * * * ** * ** * * * *** * ** * ** *** * * ***** * ** ******** ** * ** **** = x[i+1];
*** * * * * ** * ***** * * * * * * ** **** * * * * * ** * ** * * * * * * = temporary;
* * * *** *** * * * * **** * * ** ** * ** *
* * * * *** * * * * **** *** * ** * * * * *
* ** * * * * * ****
*** * ******* * ** ** *
** ** ** ** * ** ** print the array */
****** * * **** ** **** **** ** * * sorting: \n");
** ***** * * *** i = 0; i < size; i++){
** * ****** **** ** * ** ** * * * * ***** * * * ", x[i]); * ****** ** **** *** * * *
* ** *** * * * ** **
*** ** * * ** **** ** ** * * * **** **
* * * * * *** ****** * *
* * * * * ** * ***
*** * * * * **** *** * *** ******* **
* * ** ** * * ** * * * *** ** * * ** *****  
* ** * ** * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ***** ** * * * * x[] = {77,22,88,11,22};
** * * ** * ** * * * *** * size = 5;
    
* * *** ****** * ** * * * print the array */
* ** ** ** * * ** * * ** * i = 0; i < size; i++){
* *** *** * * * ** ** * * * * **** *** * *** ", x[i]); * * *** ** * * * ** ** * * *
* **** * ** * **
*** * **** * * ** ** * ***** *** * ********
*** ** ** **** ** ***
* *** * *** ** ** * I need this to happen size-times */
** * **** * * * *** ** ** * j = 0; j < size; j++){
* * * * *** ******** * *** ** * * ** from left to right */
* ** * * ** * * ** * * * ** * *** * * * i = 0; i < size-1; i++){
** * * * * ***** ** *** * * *** ** * * * ** * * *** ******* *** * * ** i-th element with its neighbor to check if they are in order */
** ** * * * * * * * ** * * ****** * ** **** * *** * * * ****** **** > x[i+1]){
* ******* ** ** * ** *** * *** * *** *** * * * ** ** *** ** * * * *** ******** * * * ** exchange the values of x[i] and x[i+1] */
* * ** ** *** * * **** ***** ** ********* * ** *** ** * ** * *** ** ******** ** *** temporary; * *** * * ***** * **** * *** ** ***
* *** ** * * ** * ** *** * ** ** * * * *** *** ** * *** * * * * * ** * **** * * *** * * = x[i];
** * ** * ** * * * ** * *** * ********* * **** *********** * ** * * *** ** ** * *** * = x[i+1];
** * * * * *** * *** * **** * * ** * * * ** *** * * * * ** ** ***** * **** **** * = temporary;
***** ** **** ** ** ** * * **** *** ***** *** ***** * ** * * * *
* *** * ** * ** * ** * * **** **** ** **
* * ** ** ** **** * * *
* * * ** ** ** * ** **
* * * * * * * * print the array */
***** ** ** ** ** * * ** ** **** sorting: \n");
****** ******* ****** *** i = 0; i < size; i++){
** * * *** * *** * ** ** ** * * * * * * ** ******* * ", x[i]); * *** ** ***** * * * * * ****
* *** * *** *** * *
***** ****** * * ** * **** **** * * * * *
* **** ** * * ** * * ***
* * *** * *** * * *** **
* * *** ****** ******* * ***** ** ******* * *
* *** * *** ** * ** * * * *** **** ***  
***** ** *** ***** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.67
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users