[Exercise 16] Arrays: Bubble-sort

Question

9.3k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64

[Exercise] Coding (C) - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited | 9.3k views

46 Answers

Page:

« prev
1
2
3
4
5
next »

410630017 · Answer 1 · 2017-12-20 14:35:13

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
****   *  * ***** *    * **   x[] = {77,22,88,11,22};
** * *    ****  **  * * ** *****  size = 5;
    
   *  **** **   ** *    ** print the array */
* **  * ***    ***  *    ** ** * * * i = 0; i < size; i++){
  ***  **  * * ** ***    * **** ** *   *** *  ** ** *   *  *     * * ", x[i]); * *  * *     *  *******       **  **  **   
 ** **  ** ** *** **  
  *    *  **  ** ****** ** ***   * ***   *  *     
*     * *  ******     ** 
*  ** *** ** ** ***     *****  I need this to happen size-times */
 ****   * ****  *  ***  **     *   ** j = 0; j < size; j++){
 *  *    *   * ** **      * *  *****    **  *     ** ***    from left to right */
* ** ** *   ** *  ** *   *** ***     **  *  * * **    ****     *** i = 0; i < size-1; i++){
    *    *** * * ****    * **** * *    *** **** ** * *   ********* ***     ** **   **   i-th element with its neighbor to check if they are in order */
  ******   *   ***     *****    ** *    *  *** *  * * *    * ****   * **  * * ** > x[i+1]){
  * *  *  * * * *  ** ** ****   * *  * * ***** * *   *  * *** ****** *** * *  *      * * * *** *       ****** * **** * exchange the values of x[i] and x[i+1] */
 ** * *     ** **  ***   **  **  *   ** *  ***  ***** *********      * ** * ***** * * *  * ****       * * * temporary;  *  * * *  ****   * *  * ** **    **  ** **
** * ***** * ***  ** ****** *  *  * ********   ****** *   ****** **** * ***   ** **  *  * *** * ***   ****  * = x[i];
  ** *  ****  *  *  ***** * * ***  ***** ****    * * * *  **  **** ** *  * **   *** *  **   * *    **  *   * ** = x[i+1];
 **  ** *        **  *** *  *     * ****    *  **** * *** ***** **  *    * *  ***  * ** * ****  ***  * **       = temporary; 
   ** **** **   *** **  ** **  *        *** * *   * ** ***** *** ***  * * *  *** 
* * ** *  *  *    * *  **  ** * *   ***  * *** **  * *
 ** *     *** ** * ***  ***  
 **  ****  * *   ***** ** 
 **  * **     *  ** **   * * * print the array */
  *** **   *   *** ** * **   ** **** *  * *  sorting: \n"); 
*  ** * ***   * * **  *   **  * i = 0; i < size; i++){
 *  *   **      ** *****  * ***  ****    ***   * ** * **  ** *     ", x[i]); * ****  **  ** **   *  **  *** *****      
*****  **  *****   *  **** *  * *** 
**  * * *****  * ***      *   * *   *  *   **    
***  *  **  ** ** **     * *   
**  * *     *** ***   * **  
*** *** ****  *  ****   ** *  ****   ****   **** * 
* *  ** *  ****  ***    *** *   **   *** ** ** ** **  *     
*  *** **   *  *** *  * ** 0;
}