0 like 0 dislike
6.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 6.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ** * ** ** ** ** ** * x[] = {77,22,88,11,22};
** ** ** ** *** * * ** size = 5;
    
****** * ** ***** * * * ** print the array */
** ** * * *** ** ** ** * i = 0; i < size; i++){
* * * ** *** *** * *** ** ** * *** * * ** **** * ** * ", x[i]); ** * * **** * * **** ** * ** *** *
* * *** *** *** ******* *
* * ***** ** * * **** ** * * * *******
* * ***** * * *** ** * * *
*** ** ** * ** * * ** * I need this to happen size-times */
* * * ** * * * * **** ** * j = 0; j < size; j++){
* ****** ** *** * * * ****** * ****** from left to right */
*** * ** * ** ****** **** *** **** ** * i = 0; i < size-1; i++){
* * * * * *** ******* * * * * ** * ** ****** ** * *** * * **** i-th element with its neighbor to check if they are in order */
*** ** ** * *** ** *** *** ** ******* * ** *** * * *** *** * ** **** * > x[i+1]){
* **** * * * * * ** ** ** * * * **** ** * * *** * * *** ** *** ** * * exchange the values of x[i] and x[i+1] */
* * * * ** ** * * * *** ** ** * ** ** * ** ** * ***** * ** * * ** ** * * ******* * temporary; ** * * *** ** * * **** *
* * *** ** * * *** * * * * * * * ** ** * * * **** *** ***** * ******** **** * * * * = x[i];
* *** **** ** ** ******** * ** *** * * ** ***** ** * * * * *** ** * **** ** * * ** ************ = x[i+1];
* *** **** * **** *** * ***** * ** ******* **** * ** * * ***** * * * * * ** * * * = temporary;
* * *** ** ** ***** ** * ** * * * **** * **** *
** * * * * * * * ***** ****** * ** ** * *** ** **
** ** *** * ** ***
* * * * **
* ** **** * ** * print the array */
****** ***** *** * * * *** * * sorting: \n");
* ***** ** * * * * * ** * i = 0; i < size; i++){
**** * * *** * ** ** ** * ** **** *** * *** *** *** ", x[i]); ** **** * * ** * ***** * *** ** *
** ** ** ** * ***
* ** * * *** * * * ** **** ***
*** * * ** ** * * * * ***
** * ** **** * ** *** *
** * *** * ** * ***** **** * * * ** * * **** * *
** ** *** ***** ****** * * * **** *****  
*** ****** *** **** ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** *** * * * ** x[] = {77,22,88,11,22};
* * ***** * ** * ** * size = 5;
    
****** * **** *** print the array */
** *** **** *** * * ** i = 0; i < size; i++){
*** * * * * **** ** ** ** * ** ** * *** ** ** ***** **** ", x[i]); * * * ** * **** **
* ** ** * ** ** * ** *
** ****** * * * * ** * ** * *** * *** * * ****
*** *** * *
* * * *** ** * ** * I need this to happen size-times */
**** * * * *** *** ** * * j = 0; j < size; j++){
* ***** *** * ** ** *** ** * * * ******** * ** from left to right */
* * *** *** ** * * * ** *** * **** ** * **** * * i = 0; i < size-1; i++){
* * ** ***** *** ** * * ** * ****** * * * * ** ***** ** * * i-th element with its neighbor to check if they are in order */
* * **** * * ******* ** * *** * ** ** * * ****** * * * ** *** * * > x[i+1]){
*** ** ** * * * ** * ** * **** * * * * ** *** ** * * * * * * ** * ** * *** *** * ** exchange the values of x[i] and x[i+1] */
* *** **** ** * ****** * *** * ** ** * ****** *** * *** * *** * * ** * ** * * * * temporary; * ** * * **** * * ***
** * ** * * * * * *** * * *** * ** **** * *** * ** ***** ** * **** ******* = x[i];
* * ** * * * *** **** * * ****** ** ** * * ** ** * ** * * * ** * ************ = x[i+1];
* * **** * ***** *** **** * * * * * * ** * * *** * * * * *** * *** * * *** *** ** * * = temporary;
*** * ** ** ** * *** * **** **** * * * ** * * ** ** * ** ** ***
* ** * ***** ** * * ** * * ** *** ** **** * *
** **** ***** * ***
* * * * ** ** * * *** ****
** * * ** * * * * print the array */
******** * * * ** ********* *** ** sorting: \n");
* **** ***** * * * ** * i = 0; i < size; i++){
* * ***** * * *** ***** ** * ** **** * * * ** * ** ** ", x[i]); ******** * ** *** ** * * **** ****
* **** ** * * * *
* * * ** *** *** * * * ** * ** * *
* * ** ** ****** ***
***** *** * * **
*** *** * *** * ** * *** ***
**** * * ***** * * * ** **** * * * **** * **  
** * ** *** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** **** *** ** * * ** ** x[] = {77,22,88,11,22};
* ** * ** ** ** ** * * * size = 5;
    
* *** * * * * ** ** ** print the array */
* * * *** ******* * *** i = 0; i < size; i++){
* ** * *** * * * **** ** *** * * ****** *** ** * *** * ", x[i]); *** ***** * * ** ** ** * *** * * **
** *** *** *
* ** * * * *** ** * * *** *****
** **** * *** ** *
** ** *** ******* * I need this to happen size-times */
*** *** ** * *** ** * ** ** j = 0; j < size; j++){
** ** * *** * * * * * * *** * ** from left to right */
***** * * * * * ***** *** *** *** * *** ** i = 0; i < size-1; i++){
* * ***** *** ***** ** * * *** **** * ** ** * * ** ** * ** * ***** ** *** i-th element with its neighbor to check if they are in order */
* ** *** ** * ** ** ***** * ** ** ***** * **** * ** *** **** ** * > x[i+1]){
* * * ** ** **** * *** * *** * * *** * ********* *** ** * ** * ** * ** * * * * ** * exchange the values of x[i] and x[i+1] */
*** **** * ** * ***** * ** *** ** ** * ***** ** * * ** * *** * * * * * *** ** ** temporary; *** *** * * *** ** ** ** ***** **** * *
* **** * ** * * *** * * **** *** ** **** ** * * ** * * *** * ** **** *** ** * * ** * = x[i];
* * *** * * ** * **** ***** * * * * *** ** * ***** *** * * ***** *** * * * ** ** = x[i+1];
******** **** ** ** * * * * * *** * * ** ** * * * * ** * * * * * * *** *** *** = temporary;
* ** ** * **** * ** * * * *** * ***** ** * * * * * * *** **** *
* * * * *** ** **** ** * * ** * * ** * *** **
* ** * ** * *** ******
**** * ** * * * * *****
*** * * * *** * ***** print the array */
** * * **** ******** * **** *** ** ** sorting: \n");
* * *** *** ** *** ** i = 0; i < size; i++){
** ** ***** ** ** ** *** **** * * *** ** ** ** *** * ", x[i]); * * * ** * *** ** **** * ***
* * ** ** ** * ** * ****
* ** * * ****** ** * ** * **
* **** ** *** * * *
* * ** **** ** * * * *
* ** *** * * * * * * ***** ** ***
* ** ******* ** * ** * * * *******  
*** ** * ****** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ***** * ****** x[] = {77,22,88,11,22};
***** ****** * * *** size = 5;
    
** ** * **** * ******** print the array */
** **** * * * ** ** i = 0; i < size; i++){
* *** * * * ** * * * * * * ** *** *** ***** ** * **** ", x[i]); ** * ** ** * * * * * *** *
* *** **** * *** *******
* *** ** **** ** * *** * ***** *
* * * ** ** ***** *****
** ** ** * ** ***** * *** * I need this to happen size-times */
* * ****** * *** * ** * * ** j = 0; j < size; j++){
** ***** *** ** * * ** * * * ** * * **** from left to right */
** * * ** * **** *** ** * * * ** i = 0; i < size-1; i++){
* * * ** * * * ** ** * * ** * ** * * * *** ** * * *** ** ** ** ** i-th element with its neighbor to check if they are in order */
* ***** * ***** ****** ** * **** * *** *** * *** * * * * ** * ** * * > x[i+1]){
* * * ** * ** * ****** ******** *** * * **** * * * * * * ***** * *** *** * ****** exchange the values of x[i] and x[i+1] */
* * * * * * ***** * * *** * ** * *** ****** * * * ** ** * * * * * temporary; * **** ** * * ** *
** *** *** ***** **** * ****** ** ** * *** ** * *** * * ** * ** * *** ** * ** * * ** = x[i];
*** ** ** **** ** ** * * * * ****** * ***** * *** * * ****** *** * * * *** ** * ** *** = x[i+1];
* * * * ** *** *** * **** * * *** **** * * * * * ** ** * * **** ** ** * ** *** = temporary;
* ** ** * * **** * ** ** *** *** * * * * ********
* * * * ** ** ** * ** ** * **** * ** **
* * * **** * ***
** *** * **** * *****
* ** **** * * ** ** print the array */
* * * **** * *** * * ** * * ** sorting: \n");
**** ** ***** ** * i = 0; i < size; i++){
* * * * *** * * ** ** * * *** **** ******* ***** ", x[i]); *** ** ** * * ** *** * **** *** * *
** ** *** * ** * *
** * * ** **** * *** **** ** ** * ** **
*** * ****** ** *
** * * ** ** *** * *
* **** * ** * * * * * * **** * ** * *
* * * * * * * * * ** * * * * * ** *  
* ** * * * ***** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * ***** * * * x[] = {77,22,88,11,22};
*** * ** *** * * * ***** * size = 5;
    
**** * ** ** *** ** *** print the array */
** *** ** * * * * * * i = 0; i < size; i++){
* ** * * ** *** * * * * ** * * * * * * * *** * **** ", x[i]); ** * *** * * *** * *** *
*** *** * ****** * ** *
* ** ** ** * ** * * ** * ******* * *
* ***** ****** ** *** **
* * ** * * **** **** ** * * I need this to happen size-times */
* ** * * * ** * ** *** j = 0; j < size; j++){
* * ** ** **** ** * *** * ** *** *** * **** ** *** from left to right */
* * *** ** * * ** ** * ** * **** * * i = 0; i < size-1; i++){
** * *** * * ** * ***** ***** ** * * ** *** ** * * ** ***** *** i-th element with its neighbor to check if they are in order */
* * **** * * *** *** ** * * * ** ** * * ** * * ***** *** * > x[i+1]){
* * * * * ** * * ****** ** * ** ** * * * ** * * * * *** * * * ** *** * **** ** ** * ** ** exchange the values of x[i] and x[i+1] */
** *** ** ** * * **** * * ** * * *** *** *** * ** **** * * * * * * * * * **** * temporary; * ** * * ** * ** ** **** ***
* ** * ** ***** * * * * ** * ***** ** ** *** * * * **** * * * * * **** ** *** * = x[i];
** *** ** ** *** * *** * * * * ** * *** **** * * ** **** * * **** * = x[i+1];
** ** ***** * * * * ** ** * * * * * * * * *** * * * * ** *** ** ******* * * = temporary;
* * **** ** * **** * * * * *** * * * * * * ** ** ** **** * ** **
* *** * * * * * * * * * ***** ** *
* * * ** * ** **** *** *
*** * * ** * ******
* * ** * * * *** print the array */
*** * * * * * *** * **** * ** * sorting: \n");
**** * ****** *** * * * * * * i = 0; i < size; i++){
* * * * * * * * * * * **** * ** *** * * *** *** ", x[i]); **** * * ** ** ***** *** * *
* * ** * ** * ** ***
* *** **** ** *** **** * **** ** * *** * ***
** ** * ** * * *
* ******** ***** * **
* *** * ****** *** ***** **** * * *
** * **** * ** **** **** * * *** * ****  
* * * ** ** ** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** * ** * *** ** * x[] = {77,22,88,11,22};
* * *** * * * *** ***** * * size = 5;
    
* ** ** ***** ** **** ** print the array */
** ** ******* *** * * ** * **** i = 0; i < size; i++){
****** ** * * * * *** * ** ** * * * * **** ** * *** * ", x[i]); * * * * *** * ** * **
** **** **** * *** ******
*** * ** * ** *** * ***** * * ***
** * * *** ** * **
** *** ** * **** ** I need this to happen size-times */
* **** ** * * ** *** * * * j = 0; j < size; j++){
*** ** * *** ** ** * * ***** * ** ***** from left to right */
* * * * ** ** ** **** * ** ** * *** ** ** ** ** i = 0; i < size-1; i++){
* * **** * *** * * ** * ** * **** ** * * ** **** **** * * ** *** * *** * i-th element with its neighbor to check if they are in order */
** ***** ***** * * * * *** ** * ****** ** * ** * ****** ** * * * > x[i+1]){
* * * * ** ****** * *** *** * * *** * ** * ** *** * * ** * ** * * * * * ** * ** exchange the values of x[i] and x[i+1] */
* ** ****** * * **** * * * * * * * * **** * * ***** *** * * ** * * ** * *** * ** temporary; ***** ** * ** *** * *********** *
** *** ** ** * * * * ** ** ** * * ** * * *** ***** * ** * * * ** ** * *** * ** * * * ** * * = x[i];
* * ** ** * * * ** ** * * * * * ** **** ** ** * * ** *** * * ** * ** * ** ** * * * = x[i+1];
* * * * * ** *** * **** * * ** ** * * * ** * * * * * *** * ** *** ***** * *** ** * = temporary;
**** ** * * * * *** *** *** ****** * * * * * * ** * * * **
*** ** *** * ** * * * * ** ***** * ** **
* * ** * * ** ** * * *
*** * ** * **** * ** ****
**** * * * ** print the array */
** * * * * * * ***** ** * **** *** sorting: \n");
* * ** *** ** ** * ** * i = 0; i < size; i++){
** * *** ** * * *** * * * * **** *** * * * * ", x[i]); ** * *** ** *** * ****** ** * *
* * * ** *** ** *
* * * * *** * **** * * *** **** * * *
* * ** * ***** ****
* * *** *** ** *
* *** * ** *** * * * ** * * * ** * *
** ** * * ** *** *** *** ** ** * * * *  
*** * ** * *** ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * *** * *** ** * ** x[] = {77,22,88,11,22};
* ** * size = 5;
    
* * * * ** **** * ** print the array */
* * ** *** ** * i = 0; i < size; i++){
** * ** * * ** * *** ** * ***** * * ** * * * * * * * ** ", x[i]); * * * ** * * * * *** ** * * ******
** * ** *** **** * *
******** * * ** *** * * * **
* * * * * ** * ***
*** * * * * ** * * * *** ** I need this to happen size-times */
* * **** * * ***** * *** * j = 0; j < size; j++){
** ** * *** * * * * ** ** * ******** ** ** ** from left to right */
** * **** ***** **** * * * *** *** ** * i = 0; i < size-1; i++){
* **** *** * * * * * ** * **** ** * *** ** * ** * * * i-th element with its neighbor to check if they are in order */
***** ** ** ** * * * *** * * * ** * ** ** * ** * * * * **** *** * * * * > x[i+1]){
******* * * * * *** * ** ** * * ** ** * *** * ***** * ** * *** ***** ***** **** exchange the values of x[i] and x[i+1] */
*** *** * ** * * * * * * *** * ** ***** * ****** * ** * * ** ** * * ** *** ***** * **** temporary; * **** ***** ** * **** ****** ***
* * * * ** * * * *** * *** ** **** *** ** ***** * * * * * ** ** ** * * * * = x[i];
* ******* *** ** ** ** ******* * ***** * * ** * * **** **** * *** ***** = x[i+1];
** * * ** ** * ** * * * * ** *** * * * ** * * * * ** ** ** *** * * * ** *** * * ** * * ** * = temporary;
* * ***** ** ** ** *** ** ****** * * ** * * * *** * ** **** **
**** ***** * * *** ****** *** *
* * * ** * ** * ***
** * * ***** *** * *
** * ***** * ** * print the array */
* ** ** *** * ** * * ** * * * sorting: \n");
* * * *** ** * * * ***** i = 0; i < size; i++){
**** * ** * * * ** ****** *** * *** *** ", x[i]); * * * ** * * * * * * ** *** * **
*** * ***** * * *** *
** ** *** * ** * * * ** * * *** *
* ** *** * ** * **** * **
**** * * *** *
** ** * ** ***** ****** ** * * * * *
* ** **** ** ****** *** * ** * **** **** ** *** *  
* ** ** * **** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** *** ****** * x[] = {77,22,88,11,22};
* ** * ** * * **** ** size = 5;
    
******* ** *** * * * * print the array */
** * * * *** **** * *** i = 0; i < size; i++){
*** * ****** * * ** * ** ** ** ** *** **** *** * * * * * ** ", x[i]); * * * ** * **** * ** *** *
****** ** ** * *******
** * * **** ** ** ** ** * ** * * *** **
* ** *** * * *** **
*** * * ** ** ** * * *** ** * I need this to happen size-times */
** * * ** ** **** * * * j = 0; j < size; j++){
* * ** *** ** **** * * * ** * ** * ** from left to right */
* ***** **** * *** ** * ** ** *** * * * * * *** i = 0; i < size-1; i++){
** ** * * ***** * * * * ***** * ** * ** ** *** * **** ** ** i-th element with its neighbor to check if they are in order */
* * ** * *** ** * ** ****** * *** * ** * * ** * * * * ** *** * * > x[i+1]){
*** * * ****** ** ** * * * * * * ** * ************* ** **** *** * * *** ** exchange the values of x[i] and x[i+1] */
* ** * ** * *** * * ** * ** * * ** *** ** ** ** * * *** * * ** * * *** temporary; * * * * ** ** ** * ** *** *
***** ** * * * * *** ** ** ** * *** ** * * *** * * **** ** *** *** ** * ** ** ** * = x[i];
*** * * * ***** * * **** *** **** * ** *** * * ** * ** *** * * ** ** * * *** ***** ** ** = x[i+1];
** **** ***** **** * ** ** * * ******* * * ** * *** ** *** *** * * * **** *** * * * * * = temporary;
** ******** * *** * ** **** * *** * * ** *** ** * ** ********* *
** *** ** ** **** * * ** * ** ** * **
* * ** **** ***
***** * * *** * * *
*** * ** * * ** * ** print the array */
** * ** **** * * ** * * * ** *** *** sorting: \n");
** * * * *** * * ***** ***** * * i = 0; i < size; i++){
* **** * **** * **** ** ** * ** * ****** ** ** * * ", x[i]); ** * * * * * *** * *** **** * *
* *** *** ** * * *
* * **** ** * ** * ** * ** * *
* * ** ***** ** * *** *
**** * * * * **
*** * * * ** * ** **** ** * *** ******
** ****** * *** * * ** * *** ** * * ** ** ** ** * * *  
* * * ** * ** ** ** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** ******** ** * * ** x[] = {77,22,88,11,22};
* ****** * * * * ****** *** size = 5;
    
* * ** * *** *** * print the array */
* **** * * ******* ** * * * i = 0; i < size; i++){
**** * *** * * **** ** *********** ** ** *** * ** *** ", x[i]); * **** ** * **** * * **** * * **
** ** *** * ** **
* *** **** * ********* *** ** ****** *
******* * * *******
** *** ** * ****** I need this to happen size-times */
** * * * **** *** ******* ** j = 0; j < size; j++){
* ** * * * ** *** * ** * * ****** * ** from left to right */
********** ** ** * * ** * *** ** ** ** * i = 0; i < size-1; i++){
* * * * ****** * ** * * ** * * *** ** *** *** **** * * * i-th element with its neighbor to check if they are in order */
** ** * * * * * * *** * ***** * * * * *** ** * * * * > x[i+1]){
* * ****** * ** ** * * * ** * **** * ** **** ***** * * **** ** * ** **** ** * * * * exchange the values of x[i] and x[i+1] */
***** * * **** *** *** * ** **** ** *** ** ** ******* * ** ** *** * * *** *** * * * ** *** ** temporary; ** ** * *** ** * ** * *
* ** ** * *** ** * * ** *** * *** ***** * ** * * * * * ** * **** * * * = x[i];
* ** * *** * ** * * ** *** * ** ** *** * ** **** ** *** **** * ** ** * * * ** = x[i+1];
*** * * **** *** ** * * **** *** * ** * *** ** ** * *** * * ** * * * ** * * = temporary;
** * * * * * * * * * ***** * * * ** ** * * ******** *
** * * * *** ***** * * *** * ** * *** *** *
*** * ** **** ** * *
*** * * ** * * ** * ***
*** * * ***** * * * * * print the array */
* * * **** * * ** sorting: \n");
*** ** ** ** ** ** ** i = 0; i < size; i++){
***** * *** * ** * ** ****** * * ** ** * ** ***** *** * ", x[i]); * * *** ** * * * ******** *** **
* * ** * * * * * *** **
* ** ** * ** *** * * * *** * *** *
* * ** * * * **
* * ** * * **** *** **
**** ** * * * * * * * ** **** ** *
** * ****** * * * ** * ** ** * *** * * *** *  
***** ** **** **** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * **** *** * ** x[] = {77,22,88,11,22};
**** * ** * ** * * size = 5;
    
**** * *** ** *** ** print the array */
* ** * ** *** * * ** i = 0; i < size; i++){
** * * ********* * * *** * * * * ** * ** ** * ** ** ", x[i]); *** ** ** ****** * * * * ***
* * **** * ******
** * ** ** * ** ** * * * *
*** ** * *** * * ***** *
** ** * *** *** * I need this to happen size-times */
** ** ******* * *** j = 0; j < size; j++){
*** ****** ***** * ** **** ** *** ** * ** ** ** **** * from left to right */
* ******* ***** ** * * ** * *** **** * *** * * * i = 0; i < size-1; i++){
* *** * * ** * *** ** *** ** * * ***** ** * * ** * **** ** *** * i-th element with its neighbor to check if they are in order */
* ** *** *** ** *** ** **** **** * ** * ***** **** ***** * * * > x[i+1]){
* ** **** * ** * * *** * ** * * * ******* ** * * * ** * *** ** * ** ** **** *** ** exchange the values of x[i] and x[i+1] */
** * **** * ** * ***** * * ** * ** ** * **** * * * ***** * * * * * *** * * *** ** temporary; ** **** *** * ***** ***** ***
* * *** * ****** ** ***** * ** * * * * * * ** * ** ** ** ** *** * ********* *** = x[i];
*** ** ** ***** * ** ***** * ** ** ** * ** ** * ***** ** ******** ****** * **** * * ** ** *** = x[i+1];
* * * ** * * ** ** * *** ** *** * ** * * * ** *** ** *** * ** * *** **** * ******* = temporary;
* *** ** **** * * * ** ** * ** *** * ** ** * * * * * ***
** * * * ** * * **** ** **** * *** * * * * * *
*** ** ** **** ** * * **
*** * * * * * ** ** * *
* ** * * * * * * * * print the array */
* **** ** ** *** * * ** ** ** ** *** sorting: \n");
* * ** ** ******** * ** * * i = 0; i < size; i++){
*** * * * ** ********** **** * * * ** *** * * ** * ", x[i]); *** **** * *** ** *** * ** *
* *** ** *** * *****
**** ** * * * ****** ** * *** ** * *
** *** ** * * * * *
****** * * * * * **
* *** * ** * ** * ***** * * * *** *
* * ** ** ***** * ** * ** * *** ** * ***** *  
*** ***** ** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.211
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users