0 like 0 dislike
8.3k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.3k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** * * ** * * x[] = {77,22,88,11,22};
** ** ** * *** *** * size = 5;
    
*** *** * * * ** * * print the array */
* * * * * ******** ***** i = 0; i < size; i++){
***** * ** * **** * * *** * * * * * ** ** * * ****** * * ", x[i]); ***** ** ** * ** ***** ***** *
* ******* * *** * *
*** ** ** ** * *** * * * **** * *** **
** ** *** * ** ** **
* ** * *** **** ** *** * I need this to happen size-times */
****** * * ****** *** *** j = 0; j < size; j++){
* * * * ** * * * * ****** * ** * ** ** ** * * * from left to right */
**** * *** ** ****** **** ****** * *** ** ** * ** i = 0; i < size-1; i++){
* **** * * * * * *** ** *** * * *** **** ** ** * *** * ****** ** ** * i-th element with its neighbor to check if they are in order */
** ** ** ***** * ** * ** * **** ***** * *** ** *** ** * * > x[i+1]){
**** **** ** ** ** * * * *** *** * ** ** * * *** * *** * * **** * * * * * ***** ** ** exchange the values of x[i] and x[i+1] */
*** ** *** ** ** *** *** * * * ** ** * ** *** * ** * * * *** **** * ** **** * temporary; * * * * ** * * **** * ***
* *** ** ** **** * ** ** ** * * ** **** * * * * * * ** ** ** *** **** ** *** *** *** *** ** = x[i];
* *** ** ***** * * * *** ***** **** * ** ***** * **** *** ** * ** * *** * = x[i+1];
* *** ** * ** * * ** ******* * * ** *** * ** * **** **** ** * * * * * *** ** * = temporary;
** * ** * ** ** ** ******** * *** * * *** * ** ** * * *
* * * *** * ** * ** * * ** ** *** * *
** ** * * ** * *
** ****** ** * * **
** * * * * *** ** ** print the array */
* *** * * * ** * * ** **** ** sorting: \n");
* **** **** * *** * * * i = 0; i < size; i++){
* ** **** **** * * **** *** * * * * ** * * * * * ** ", x[i]); * ****** *** * **** ** * ** *
** *** *** * **** *
*** * * * * *** * ** * * ** ** ***
* * * * * ** *** *
* *** ** ***** **
* * * ******* ** ******* **** * * * *** *
* *** ** ** * ******* ** * * ***** * *** ***  
** * * *** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * *** *** * * * ** x[] = {77,22,88,11,22};
* * ** ** ** ** * ** size = 5;
    
***** ** **** ** * * ** * print the array */
*** * ****** ** ********* i = 0; i < size; i++){
* *** ** * * * * ** * * ****** * * * * * ", x[i]); * ** * * ** * ** * *****
* **** ** * * ** * * *
* ** * *** **** **** ** * ****** * * * ***
* ** **** * * *
* * ** * ***** * I need this to happen size-times */
* *** *** *** ** * * * j = 0; j < size; j++){
*** ** * ** **** ** ***** * *** * * * * * * * from left to right */
** *** * ** * ** * ** *** * * * ********* i = 0; i < size-1; i++){
* ** * **** *** * ** ** * ** ** * * **** ** **** *** * **** * ** **** * * i-th element with its neighbor to check if they are in order */
* ** * * **** * * *** ** ** * * ** * ** * * * **** ** * * * * * > x[i+1]){
*** * * * ***** **** * * **** *** * * **** * *** ** ** * ***** *** ** **** * **** * ** ***** exchange the values of x[i] and x[i+1] */
* * * **** **** * * *** ** * **** * * *** * *** * * *** * ***** ** * *** ***** temporary; * * ** * * * * ** * * * * **
* ** * ****** * *** * **** * * ** * **** ** *** * * * *** * ** * *** = x[i];
*** * ** * ** * ** * ** * ** * * * * **** * **** * * * ** * ***** * * ***** * = x[i+1];
* **** * * *** * * ** * * ********** * * ** * ** * * * * * * * ** * ***** ** * ****** ** = temporary;
** ** ** * *** * ***** ** **** ** ** * **** ** * ** * **** ** **
* ***** * ** *** * * * *** *** * * *** ***
* ** **** ********* * **
* * * * ** ***** * **
* * *** *** * ** print the array */
* * ** * ***** * ***** *** *** sorting: \n");
* ** * * *** * ** i = 0; i < size; i++){
* * * ** * * ** * * *** **** *** **** ** **** ", x[i]); * * ** * ****** **** * * *** * **
**** *** ** *** * **** *
* * ** * * ** * * *** **** * *
* ** * **** * ****
* * ** ** ** ** *
* ** ** **** * * **** ** * * * ** *
* **** * * ** * ** *** ** * * * * **** *  
*** * ** ** *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * * ***** ** x[] = {77,22,88,11,22};
*** * *** ****** *** **** size = 5;
    
* * ** ** **** ** * *** print the array */
* ** *** * *** i = 0; i < size; i++){
*** *** * **** **** ***** ** ** * ** * ** *** * ", x[i]); ** *** * ** * ********** ** ****
** * **** * * **** *
** ** *** * **** * **** ** * * ** *
* * *** ** * * ** *
* ** * *** ** * * *** I need this to happen size-times */
** * * * * * ********* *** j = 0; j < size; j++){
* ** *** * * * ***** * ** * *** * ** * ** from left to right */
* * ** * ** ** * * * ** * ** ****** ** * i = 0; i < size-1; i++){
* * *** ***** ****** * *** * * * * ** ** * * * ***** * ** * ** i-th element with its neighbor to check if they are in order */
** ** ********* ** * **** ****** *** * ****** * * ** * * **** > x[i+1]){
** * * ** ** * ***** ** * **** *** *** * * *** ** ** *** ** *** * ** *** ** ** * ** * exchange the values of x[i] and x[i+1] */
* **** * * * * **** ** * ** ** * * ** ** ** * * **** ** ** * **** * ** ** ** * * *** temporary; ** * * ** ***** * * * ** **
* **** **** ** * ** *** ***** *** * *** * * * * ** * * ** ** ** * * * ** * ** * = x[i];
* * *** ****** *** * * ** ** ** * * **** ** * * *** * * * * ** * ** = x[i+1];
** * ** ** ** * * * ***** *** **** * *** * *** ***** * **** ****** ** = temporary;
**** ** **** ** *** * *** **** **** ** * * * *** ** ** ***
* *** ** ** ** * *** * * *** **
* *** * ***** ** ** *** * **
* ** *** *** **
* ** *** * * ** print the array */
****** *** **** ** **** ** sorting: \n");
* * * * ** * * ** * i = 0; i < size; i++){
** * ****** ** ****** * * * * ** **** *** * * * ", x[i]); ** * * **** *** * ** ** *
* * *** ****** ** *** *
* * * * * * * * * ** *
* * ***** ** ***** * ****
** * ** * * ** **
* * ** * * * *** * * ** * **** ** ** * *
** * * ***** * ******* * * * *** * **** * ** **  
** * ** * ** * *** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * **** *** x[] = {77,22,88,11,22};
***** * ** * * * ** * size = 5;
    
*** * ** * ** * * * print the array */
** *** * * * * ** ** *** * i = 0; i < size; i++){
** * ******* * * *** ** * * * * *** * ** *** ", x[i]); * *** * * ** ** * **** **** *****
** * * *** ** * *
* * * ** ** ** * * * * * *** ** *
** * ** *** ** * *
* * *** * * * * * * * I need this to happen size-times */
* *** ** * * * * * j = 0; j < size; j++){
** ** * * ** ** ** * **** *** * *** * ** ** from left to right */
* * ** * **** *** * ** ** ** ** * **** * ** i = 0; i < size-1; i++){
* * * ** ** * ** *** ** ** ** *** ** * * *** * *** * * *** * ** i-th element with its neighbor to check if they are in order */
** * ** ** * *** * * * * * * * ** * ****** * * * * **** ** ** * *** *** * > x[i+1]){
* *** * * * *** * **** ** **** * *** * **** * *** ** * * ** *** * * exchange the values of x[i] and x[i+1] */
* * * * * *** * * * *** * * * * ** ** * *** * * * * ** ** ** * ** temporary; *** * ** * *** * * ** ** * ** *
* **** * *** *** * ** * * * ** * ******* *** ******* * * * ** * * * ** **** * * * * = x[i];
* **** * **** **** * ** * * ** * * * * *** * * *** ** * ** ***** * * ** = x[i+1];
* ** * * * * * * * **** ** * **** ***** ** ** ** * * ** ** ** * *** * ** * * * ******* * ** ** = temporary;
* ** * ** *** ** * ** * *** ******** * **** * * ** * * * *
** * *** **** * ** * *** * * * ** **
** **** * *** * * *****
*** * * *** * ** **
* * * * * ** ** * * * print the array */
* ** *** * * * ** **** ** * ** * *** sorting: \n");
* * ** * ***** ** * *** * i = 0; i < size; i++){
* ** **** ** *** ********* * ** * * * * ", x[i]); ****** * ** * * ** * ** * ** * * *
* * * * ** * * * **
*** ** * * *** * *** ** ** * *** * * * * *** *
* * *** ** * ** ** * ** *
* ** * *** * * **** *
**** ** * * * *** * ** * ** *
* **** * ** *** * *** * *** * * * * * ** *  
**** ** * *** *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * ** * ** x[] = {77,22,88,11,22};
*** * *** * **** * ** size = 5;
    
** * ******* * * ** * * print the array */
* ** ***** * ** ** ** i = 0; i < size; i++){
** * ** * ** * * * ** ** * ** ******* ** *** **** ** * ** ", x[i]); ****** ********* ******* * ***** *
********* ** * * *** ** *
* *** * ******* ****** * *** *** *** ***
* * *** * *
* ** * * * * ** ** I need this to happen size-times */
* * ** * ** ***** ** j = 0; j < size; j++){
* * *** * * * *** ** * **** * * **** * ** from left to right */
* ** ** *** * ** * ** * * ** * **** *** * i = 0; i < size-1; i++){
*** *** ** * ***** * * * * *** * ******* * * *** ** **** ** * ** * i-th element with its neighbor to check if they are in order */
** ** ** * * ** ** * * * ** *** ** ** ** **** * * * * * * > x[i+1]){
* **** *** * * *** * * ** * ** * ** * *** **** * * * * ***** *** ** * *** ** * ** * * exchange the values of x[i] and x[i+1] */
** ** * ** * * * * *** * * * * * **** * ** *** ** ** ** ** * *** * * *** *** temporary; * * ** * * ** ** * ***
* ** * * * **** * * *** * * * * ** ** * ** ** * ** ** ** ** * * ****** * * * = x[i];
****** *** * * * * * * * ** * * * * ** ** **** ** * **** * ** ** * ***** * * * * = x[i+1];
* ******** **** * * ** * * *** ** * * * ** * *** *** * ** * * **** * ** * *** * = temporary;
* * * * *** ** * *** ** ** * * * * *** * * *** * * ** *
* ** *** ** ** ** * ** * * *** * *** ** *
**** * **** * *** **
* *** **** * * * * * *
** * ** **** * *** * print the array */
**** * * ** * * **** *** * *** sorting: \n");
** * * * **** * ** * i = 0; i < size; i++){
***** * ** ***** * ** ***** ***** * * * ** * *** * ", x[i]); *** ** * * ** * * * *
*** * ** *** ** * ****
* ** ** ** * * * * ** * **** ** **
* * *** * ** * * *
* * ** *** * * * * *****
* * ** ** ** ** ** * *** ****** ** **
** ****** *** * ** **** ** * ** * *  
*** * ** **** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******** ***** ** ** * * ** * x[] = {77,22,88,11,22};
* * * **** * ***** ** * size = 5;
    
** * ** *** ** * * *** * * * print the array */
** ***** *** ** * ** * ** * * i = 0; i < size; i++){
**** * * *** **** * * * *** ***** * * ** ** ** ** * * * ", x[i]); * ** * * *** * ****** * **** * *
** * **** * *** *** *
* ** ** * * * * * * * ** * *** * *
*** * ** *** * * **** * ** ***
*** * * * ***** *** ***** I need this to happen size-times */
** ********* ****** *** j = 0; j < size; j++){
* ** * ***** * ** **** ** *** ** * * **** from left to right */
* * * ** *** ** ** *** *** ***** * ** * ** * i = 0; i < size-1; i++){
** * * * * * **** * * ** *** * *** ** * ** *** * *** ** * *** ** ***** * * * i-th element with its neighbor to check if they are in order */
* ** * * * * * * *** ** * ** ** **** **** ** ******* ****** > x[i+1]){
* *** ** * ** ** * * * * * * *** * * *** * ** ** * ******* * ***** * * * exchange the values of x[i] and x[i+1] */
* *** * * ****** ** * * * * ** **** * ** *** ** * * *** * * * * ** * *** ***** *** temporary; ***** * **** **** ** *** **** * **** *
** ***** ** * **** ** *** * ** **** **** **** ** * * *** ***** * * *** **** * * ** *** = x[i];
* * * * ** * * * ******** * * * * * ***** ** ** * *** ** * * ** * * * ** * * ** ** = x[i+1];
** ** **** *** ** * * ** ** * * *** * **** * * * ***** ** * * * * **** *** * ** * = temporary;
* *** * ** * ** * * * ** * ** * *** * * ***** **** ** *
* * * * * * ** *** * ** * ***** ** **** ** ****
* ** * * ** ** **
** ** * * * * ** **
** * * * * * print the array */
*** ** * * **** * *** * * ** * ** sorting: \n");
* *** * ** * * ** ** i = 0; i < size; i++){
** **** ***** *** ** * * ***** *** ** **** ", x[i]); * * * * * ** * *** ** * ** **
* * * * ** ** * **
* ****** * * ** * * * **** * ** *
* ** * * ** ** *
* ** *** *** *** * * *
* ** * * **** * * ** ** **** * ** **
* *** * **** * * ** * **** * * **  
* * **** *** ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** *** * * * *** * * x[] = {77,22,88,11,22};
* * * ** ** ** **** * ** * size = 5;
    
*** ***** * ***** ** ** * print the array */
*** * * * * * * * ** *** * i = 0; i < size; i++){
**** **** * *** * * * * * * * *** * * ** ** * * * ****** ", x[i]); **** * * * ** *** * * ** ** *****
* * ** * ** ***
* *** * *** * **** ***** *** ** * * **
** ** * ** * *** * ***
* **** ** * *** * * * I need this to happen size-times */
* * ** **** * * ** * ** ** j = 0; j < size; j++){
**** * **** * *** *** ** **** * * * * * ** ** *** from left to right */
* * *** ** * * * * ** * * * ******** ** * * *** i = 0; i < size-1; i++){
*** * * * *** ** **** **** * * ** * ** ** **** **** ** * * * * ** ** i-th element with its neighbor to check if they are in order */
* * * * * ****** ******* * * * ** * * * * * * **** * * * **** ** > x[i+1]){
* * *** ** ****** * * *** * * ** * * * **** ** ** **** * * ** * ** ** * *** * * * *** * *** exchange the values of x[i] and x[i+1] */
** ** * * * * ** * * * ** * * * * * * * *** *** * ***** * * * ** ** * * *** * * ** * * ** temporary; *** ** ** * * ** * ** ***** * *
* * * * * ** * * * ** * *** * * ** ** *** * * *** * ***** * ** ****** * * = x[i];
* *** ** * * **** * * ******* * ***** * ** * ** * **** ** * ** *** * ***** *** * ** = x[i+1];
** * * * **** ****** ******** ** * * ** * * * ***** *** *** ** **** * * * ** * = temporary;
** **** * * * *** * * ** * *** *** * ** * *** **** ** * * ****
* **** ***** * * * ** * * **** ** ** * *
** * **** ** * * ** * *
** * * ***** * * ** * ***
*** ** *** **** * * * ** * print the array */
* * * *** * * * ** * sorting: \n");
** ** ** * * * * i = 0; i < size; i++){
** ** **** * * * **** *** * ** ** ** ****** * * ****** ", x[i]); * *** ** * * * * *******
**** * * ** * **** * ****
* *** ** *** * * ** * ** **** **** ** *
* ** ** * * ****
****** * * * ****** * *
* **** * * * * ** *** * *** *** **
*** * * * ** * ** * * * * ********  
* * * * * ** * *** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** * * ** *** *** x[] = {77,22,88,11,22};
* ** *** ****** ** size = 5;
    
** ** * ** ** **** * *** print the array */
*** * * * *** * ** * *** i = 0; i < size; i++){
* ***** * * * ********** ** ** * ** ** ** **** * ** **** ", x[i]); * ** **** * ** * **** ** * ** * ***
**** ** ***** **
** * **** * **** * *** ** * ***** * * *
* ** *** ****
** * ** * * ** *** I need this to happen size-times */
**** * * ** * * ***** * * j = 0; j < size; j++){
** ** *** * * * * * * ** ** * *** * ** ** from left to right */
* * * * **** * * * ***** *** *** ** * ***** i = 0; i < size-1; i++){
**** * * * *** * ** * **** *** ** * * ** ** ***** * ** *** *** ****** *** *** * i-th element with its neighbor to check if they are in order */
*** * **** ** * ** *** * * *** * *** * *** * *** * * *** * * * > x[i+1]){
* ** ** * * *** * ** * *** * * **** **** ** * *** * * *** * * * * *** ** exchange the values of x[i] and x[i+1] */
* * **** ** * ** * ** ********** * ***** ** *** * * ** * *** ** * ** *** * ** * ** temporary; ** * ********* **** * * * * ** *
* ** *** *** * ** * *** ** * ***** * *** * * ** * ** ** ******** ***** ***** ** ** ** ** * = x[i];
**** ** *** ****** ** ** *** ** * * * * * * * * ** * * *** ** **** * ***** = x[i+1];
** * * ** * * ** *** ** ** ** ** ***** *** * ** *** *** * *** **** ***** *** * *** * = temporary;
* * * *** * ** *** ** *** *** ** * ** *** **** *** * *** * ** * *
* * ** * * **** * * **** ** * * * * ** ** *** *
** ** ** **** *** ** * * * *
* ** ****** * * *
* ** * *** * ******** * print the array */
* ** * ** ** * * ** *** * * *** sorting: \n");
* * * * *** ****** * * i = 0; i < size; i++){
* *** **** ** **** ** ** ** * ******* *** ** ***** * * ", x[i]); **** * * ** * * *** * *** * **
* ** **** * * ****
* * *** ** * ** ** * *** ** * *** * * *
** *** * * * * * *
** * *** **** *** * * *
* ** * * * * * * ** * **** ** **** **
* * *** * *** * **** ***** ** ** **** * *  
* * ** ** * **** ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
************ **** ** *** x[] = {77,22,88,11,22};
** * *** ** * * size = 5;
    
*** * *** * * * ** print the array */
** ** *** ** ** ** ** * * i = 0; i < size; i++){
* * *** *** * *** * * ** ** * * * ** * ** ** * * ", x[i]); ** * ****** ** * * *** *
* * * * ** * ** **
* * * *** ** * * * *** * *********
* ** ** *** ** * ** *
** * * ***** * I need this to happen size-times */
* ** * * * * * * j = 0; j < size; j++){
* ** **** * * ** *** ** * * * * ** * * from left to right */
** *** ** * *** * ** * * ** ** ** ***** * i = 0; i < size-1; i++){
* * *** * ** * ** *** * *** * ***** * ** * ** * ***** * * ** * * ** i-th element with its neighbor to check if they are in order */
** ** **** * * * * * *** *** ** **** *** ****** ** *** *** **** * ** > x[i+1]){
**** ***** ** ****** ** *** * * * **** **** * * ** * ** * *** * ***** ** exchange the values of x[i] and x[i+1] */
* * ** *** ** * ** * **** * * * ** *** *** *** * * * *** * *** * **** ** ** temporary; **** * * ** ** * * * ** ** **
**** ** * * * *** ***** * ******* **** *** * ** * * * ** * * * ** * * ******* ** ** * * = x[i];
* * * * ******** ** ** * ** **** * *** * *** ** ** ** **** ** * ** * * *** ** ** * = x[i+1];
**** **** * *** ***** ** *** *** * * * ** ** *** * **** * * ** *** * * ** * * ** * ** = temporary;
** * ** * * ** * * * * ** ***** *** ** * * ******* * * * ** * * *
** ****** ** ** *** * ** * *** * **** * ** **
* * **** ** ** **
* * ******* *
*** ** * *** * * * print the array */
* ** * * ** * ** ** * * ** * sorting: \n");
*** * **** * ** ***** * * * i = 0; i < size; i++){
** * * ****** *** * * * ***** ***** *** * * * * ** ", x[i]); ** *** ***** * * * * **** ***** **
*** *** * *** *** ***
* ** * * * * ** * * * ** *** *
** * * ** **** * * ******
** ** ** ************ *
* ** * ** * ** ** *** **** * ** * * *
** ** * *** *** *** * ******** * ** ** ** * ** ***  
** **** * * * ** *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * * *** ** x[] = {77,22,88,11,22};
* ***** *** ***** ***** size = 5;
    
** **** *** **** * print the array */
** * ** * * * * **** ** ** i = 0; i < size; i++){
*** * * * ***** * **** * * *** * *** * * *** ** **** ", x[i]); * * ***** ***** * * ** * * *
* ** * ** *****
* * * * ** ***** ** * * ** **
** * **** ** * * **
* * **** * ********* * I need this to happen size-times */
**** ** * ** * * j = 0; j < size; j++){
** * ** * * ** * * * * ** ** ** from left to right */
* ** ** * * * *** *** * ** ** **** * ** i = 0; i < size-1; i++){
* * * ** ** * **** * * ** ****** ** *** ***** * *** ** **** ****** * * i-th element with its neighbor to check if they are in order */
* ******** * * * ** * ** * ** * ** * **** ******* * * * ***** * * **** * * **** ** > x[i+1]){
** ** * * * * * * ** ** * ** * * * ** *** * * ** * * * * * * * * **** * * * * * * exchange the values of x[i] and x[i+1] */
* * ***** * ** *** ***** **** * * * ** * ** ** * *** * ** *** * *** * temporary; *** * ** *** * * *** ****
** * * **** *** * ** * ** ** ** ** * * *** * * ** * * * *** *** *** * ** ****** * ** ** ** = x[i];
* ** *** ** * * ** * * * *** * * ** * * ** ** * * * ** ** * *** *** *** ** *** * * = x[i+1];
** ** *** * ** ****** ** *** * * ** * *** ***** *** ** * ** **** * * * ****** ** ** = temporary;
* * ** * ** **** **** * * ******* * * * * * **** * * * ** **
**** * **** * ** ******** * * ** * ******* ** ***
** * *** ** *** * **
* *** * * * ** *** *
** **** ** * ****** *** * print the array */
* * * * * ** ** * * ******** ** * sorting: \n");
** ** * ****** ** ***** * *** i = 0; i < size; i++){
** **** ** * * **** * * * * ***** * * * * ** * ", x[i]); * ******** * **** ** * * * *** ** ****
* * *** **** ** * **** **
* ** * ***** * *** * * * *****
** * * *** * *** * ***
*** ** * *** * ** ***
* *** * * * * *** **** ** * ** * * *
* ** * ** ** * * ** * * *** ** *** ** ****  
* *** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.175
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users