0 like 0 dislike
10.3k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 10.3k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** **** * ** * * x[] = {77,22,88,11,22};
* **** * ** * * ** *** ** size = 5;
    
* ***** ***** * **** print the array */
* * * **** *** ****** * i = 0; i < size; i++){
** * *** *** * * * ** ** * * *** **** * * * * * **** ", x[i]); *** ** * *** * * * * * *
* * * * *** * ** *
** ** ** ** * ** * ***** *** * *** ***
*** *** ** * * *** **
** ** *** * * * ** ** I need this to happen size-times */
* * **** **** * * ** * * * j = 0; j < size; j++){
* ** * * * * ****** * *** ** * ** *** * * from left to right */
** * ** ** * ** *** * ** ** * * ** * ** * * ** i = 0; i < size-1; i++){
* * * **** ** * * ** * ** * * * ** ** * ** * * * * * * * **** * i-th element with its neighbor to check if they are in order */
* * *** **** * * *** * * **** * * ** ** ** ** * ** ** > x[i+1]){
**** * ****** * * ** * * * ** ***** * * * * * ** ** * * * ** ** * * *** ** ** ***** ** exchange the values of x[i] and x[i+1] */
* * *** * * * ** *** ** * *** ***** * * ** *** * * * * * ****** * ** * *** * * ** * *** temporary; ** ** ****** * * * ** ** ** *
** * * **** * **** * * ** ** ** * * ** ** **** * ** * * *** ***** *** ***** * * * * = x[i];
*** *** *** * ** *** * **** * ***** ** ** ** * * **** ** ** * * * * = x[i+1];
* * ******** ** * *** *** ** ** * * ** * ** * ** * * *** * ******* * * ** * * = temporary;
*** * *** * * * * ** * *** *** * ** * * * * * ** ** ** ** **
*** * ** **** * ** ***** *** ****** ** **
** * * * ** ***** ***** *
* * * ** ***
**** * * * *** * ***** print the array */
* * * *** *** *** * * * ** sorting: \n");
**** ***** * * * **** i = 0; i < size; i++){
** ** * *** * ** ** *** * * *** * *** * ** ", x[i]); **** * * * * * ** ****** * **
**** * ******* * * *** * *
*** **** * * * ** * * * * ******* *** * *
** ** ** * *** ** * *****
* ***** ** *** * **
** ** * ** * ** **** * ** *** ****** *** *
* **** * * * * ** * ** * ** * * * * *** ** **  
* ** *** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * *** **** x[] = {77,22,88,11,22};
* * * * * ** * *** size = 5;
    
** * ** *** *** * print the array */
* * * ****** ** * ***** * i = 0; i < size; i++){
* ** * * *** * * * ** * * * **** *** * *** ", x[i]); * * ******* ** ** **** *
* * * * **
** * * * ** ** ** * * ** * * *** *
*** *** * ** * *** *
* ******* * * * * **** I need this to happen size-times */
* ** * ******** * j = 0; j < size; j++){
** * ** ** *** ** ** ** * **** ** * * from left to right */
***** ** ** * * ******* * ** ** *** ** * * i = 0; i < size-1; i++){
* *** * ** * ** * *** *** * * * ** ** * * * ** * * * * * * ** *** i-th element with its neighbor to check if they are in order */
* * ** ***** ** * ** ** * * * ** * * * ** ** * ***** *** * ** * * ** > x[i+1]){
* **** ***** * ** * ** * * * *** ** * * **** * * **** * * * **** **** * * * * ** ** *** * ** * exchange the values of x[i] and x[i+1] */
* ***** * * *** * * ** * ** * *** * * * * * * *** ** **** * ** * * ** *** ***** temporary; * ***** ***** * * * * ** * * * *
** ** * * * * * * * * * * * * ** * * ** ** ***** *** ** * ** * *** **** ****** * = x[i];
****** * * * **** * * **** * ** * * ** **** * * ***** * *** * * * * *** * * * **** = x[i+1];
** *** **** ** * *** **** * ** * * ***** ***** * *** * * * *** *** * * * * ** = temporary;
* ** ** * * ** * * * * * ** ** * * ** * ** * **** * *
***** * * ** **** * * * * ** *** **
** ** ** ** * * * *
****** * ** ** *** * ***
* * ** ** **** * print the array */
**** ****** ** *** * ** ***** * * *** sorting: \n");
* * * * **** * ** i = 0; i < size; i++){
*** * * **** ****** ** * ********* *** * * * ** ", x[i]); ** * ** ** * * * * ** ** * ******
** ** * ** * ** *****
* * * * * * * ***** ** * ** *** *** **** **
** * **** * ** *
** ** * * * **** **** *
* * * **** * *** * ** * ** ** * * **
** * * ****** * * * *** * * * * * ** * *  
** * *** ** * *** ** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * ** ****** *** x[] = {77,22,88,11,22};
** ** ** **** * size = 5;
    
* * * * ** ** ** ** *** * print the array */
* ** * * * *** * * *** i = 0; i < size; i++){
* ****** * *** * ** ** ** * * ** **** * *** * * * * ", x[i]); ** * * ** ** * *** ** ** **
** ** ** * * *
*** * * * * **** * *** * * * * * *
* ***** * * ** **** * *
*** ** ** ******* ** I need this to happen size-times */
** * **** ** ** j = 0; j < size; j++){
* * * * * * * * * * * * ********** * from left to right */
* * * * * ** * * ** ** * * ** ** *** * * * i = 0; i < size-1; i++){
** **** * * * * * ****** * ** ** ** *** ******* ** *** * * * * *** * i-th element with its neighbor to check if they are in order */
* **** * * ** ***** * * *** ** ** *** ** * *** ** * * * ** * > x[i+1]){
* *** ******* * * * **** ** *** *** ** * ** * ** *** * * *** * **** ** * *** * *** * exchange the values of x[i] and x[i+1] */
* * * *** **** * * * * **** * *** ** * * * *** * ****** * *** ** * ** ** *** ***** ****** temporary; * ** *** ******* * * * * ** *** * *
* * * * ** * * * ** * * * * * * ** * ** **** * * ** * * * ** ** * * ** = x[i];
*** * ** * ******* ** * * **** ** ***** ** * * * ** * * * *** ** * *** * * * * ** * * * = x[i+1];
******** *** **** ** ** ** * ** **** * *** * **** *** * **** ***** * * * **** * * ** * = temporary;
* * ** ** ** * *** ** * ** ** * **** * ** * *** * * * **** * ******
****** * * ** * ** *** * ** * * * **
** * *** * *** * * * ** *
* * ** ** **** **
** * ** * *** * * * *** * print the array */
*** ** ****** ******** ** ** *** sorting: \n");
*** **** ** * ***** **** ** i = 0; i < size; i++){
**** ** * * * * **** ** ***** * * ** * **** ** ** * **** ", x[i]); * ** *** *** ** * *** * * ***
* *** * * *** ** * * ***
* ** ** ** ***** * *** * * * ****
* ** * * * * * *
* ***** ** ** *
** * ** * ** ** * * ** * *** * * **
***** * ** ** ** ** * ** * * * ** * * *  
* ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * ** * ** * x[] = {77,22,88,11,22};
* * * * * * *** * * size = 5;
    
*** ***** * ****** print the array */
* *** ** * * * ** *** ** * i = 0; i < size; i++){
* *** * ** ** * ******* *** **** ** * *** * ", x[i]); * * ** * ***** *** * ***** *** **
* * * ** * * ****
* **** * **** ** **** * ** * *** ** * ** ** *
** *** * * * ******
** * * **** ** ** I need this to happen size-times */
**** * * ** * ** *** ** j = 0; j < size; j++){
** ***** * ** * * * **** *** ***** * ** *** * from left to right */
** * * * * ** **** * * * **** *** * ** **** i = 0; i < size-1; i++){
* ** ** *** * **** * * ***** ****** * * * *** ** * * * ** * i-th element with its neighbor to check if they are in order */
*********** ** * * ** * * * * **** * * * * * ****** ***** * *** * > x[i+1]){
* ** * *** * ** **** **** * ** * ** * * * * * ** ** ** * *** * ** * ** exchange the values of x[i] and x[i+1] */
** * * * * ** ** ** ** ** ** ** * **** * * * ** * * * ***** * **** * ** * * **** ** **** temporary; * ** ** * ** ** * **** ** ** * *
** ** * ** ** * * * * * ***** *** ** ***** ***** * ** * * ** ** *** * * * * * * ** ** ** = x[i];
* **** * * ** * *** **** * ** * * * ******* ** ****** * ** * * * * ** ***** *** * ** *** * ** * = x[i+1];
* ** ** * * ** **** * ** **** *** *** *** ***** *** ** * ** *** * * * *** * ** * * ***** * **** = temporary;
* ***** * ** ** * ** * * * * * ** * * * *** * * * ** *
** ** ** * *** **** ** ** * ** * * * *
* * *** * ** *** *
* * * ** ** ** ***** *
***** * *** *** * print the array */
* ** *** * ** **** *** sorting: \n");
****** ** * * * * * * i = 0; i < size; i++){
** * * * ** * ***** * *** * ** ** * * * ****** * * ", x[i]); ** * *** ***** ** **** *** * **
** *** * * *** ** *
* * *** * * * ***** * * *** * **
* ** *** * ** ***** * *
** * ** * **** * ** **
* * **** * ** * ** * * * * * ** * *
**** ** * **** * ***** ** * ** * ****  
** ***** * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** * ******* * *** x[] = {77,22,88,11,22};
* ** ** ** ****** * ** size = 5;
    
****** * ** *** * * **** * * print the array */
** *** * *** * ******** * * i = 0; i < size; i++){
*** * * *** * ** ** ** **** ** ** ** ** ** * * ** * *** ** ", x[i]); *** * * ***** **** * *
* **** **** * * ** **
* ** *** * ** *** * * * * ** *
******** * * * ** *
** * * **** *** *** *** * * I need this to happen size-times */
***** * * ** * *** j = 0; j < size; j++){
** * * * ** * ** **** * ** ** * ** **** from left to right */
** ** * *** ** * ** * ** * **** * * **** ***** i = 0; i < size-1; i++){
** * * ** ** ** ** * * ********** * * ** * * *** ** ** * i-th element with its neighbor to check if they are in order */
**** * ** * ** *** *** ** ******* ** * ** * ** ** * *** ** * *** *** > x[i+1]){
*** ** ** * * ** *** * ** ** * ** ** *** * **** * * ** **** * **** *** * ** * ** exchange the values of x[i] and x[i+1] */
*** *** * ** ** * *** * ***** **** ** ** * * * ** *** ***** * **** ** *** * ** * ** ** * * ** temporary; *** * * ** *** * * *** **** ****
* * * * *** * * * ** ** * *** ** * *** * ** * ******* * ** ** ** ** ** * * ** ** * * * *** = x[i];
* * ** * * * * * * ** ****** ** * ** **** ** ** * ** * ** * * * * *** ** * ** = x[i+1];
**** * ** *** *** ** ****** ***** * ** * * ****** * ** * ***** *** ** *** ** *** * ** = temporary;
* *** *** * **** * ** *** * ******** ** ** * * ***** ****** **** ** ***
** * * * * * * * * ****** **** * ** * ** *
** ** * * **** *** *
* ****** * * ** * *
* *** * * * * *** print the array */
* * ** * * * **** * ** *** * * sorting: \n");
** ** ** * ** *** * *** i = 0; i < size; i++){
*** *** * *** * * * ** * ** ** * * * * * * * * * ", x[i]); ****** ** ** ** * *** ** ** * * * *
* * * * * *** * * *
**** ** *** * *** * * * ** * ** **
*** * ********** *
* ** * ** ** *** *
** ** ******* * * ** *** ** * * * *** *
* * ** ** *** ** * **** * * ***** * *  
**** *** ** * * * *** * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * ** * ** ** * * x[] = {77,22,88,11,22};
* * * ******* ** size = 5;
    
* ** * * * ** * print the array */
* ** * **** *** ** i = 0; i < size; i++){
* * * ** *** * ***** * ** * * ** *** ******* * * * * ** ** * ", x[i]); * *** * ** **** * ** * ****
* ** ***** * ****
* * *** * * *** * * ***** ** * * * * * * **
* ** * *** *** ** **
***** ** * * * *** **** I need this to happen size-times */
* ** * * * * * ** ** * ** * j = 0; j < size; j++){
** * ** * ** ** **** * ** ** ** * * * * from left to right */
** *********** * **** *** ** * * * * ** * i = 0; i < size-1; i++){
* * *** * ** * *** ***** ** * * *** *** * * * * * * **** ** * ** i-th element with its neighbor to check if they are in order */
* * * ** * * * * ** * * ** * *** * *** * * *** * ** **** * **** * * > x[i+1]){
* ***** * * * *** * ** ** ** *** ***** * ** * * * *** *** * * * * *** **** ** exchange the values of x[i] and x[i+1] */
*** * * **** * ** ***** * * * ** **** ** * ** * *** * ****** *** * *** ****** * temporary; *** ***** **** * *** ** ** ** * *
***** **** ** ** * ** ** *** * * * ** * * ** * * * * * * * ** *** * * *** * ** ** ** *** * = x[i];
*** *** * ** ** *** * *** *** *** * * ** * * ** * * * *** **** * * ****** * * *** ** * **** = x[i+1];
* ** * *** ** * ** ** **** * * * ***** *** * * * ****** **** ** * ** = temporary;
** ** ** * *** * ** * * * ***** **** ** * ** ****** ** * **
*** * ****** * * *** * *** * * * * **** ** **
** *** *** ** ** * *
* * ** ***** *** *
* ** ** * * ** ** print the array */
* * ** * ***** *** ** *** * * *** * * * sorting: \n");
** ** ** ** * *** i = 0; i < size; i++){
** * * * * ** **** * ** ****** *** ** *** ** * * ", x[i]); * * * * * **** * ****** *** *
* **** ** * ** ***
* * *** ** ** ** * ** ** ********
**** * * ***** * ***
* * ***** *** * * ** *** **
* ** * * ** *** * ** * **** **** * ** *
** * ** * *** * ** ** * ** **** ** ** ****  
* **** ** * * * ** * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ***** ** * *** ** x[] = {77,22,88,11,22};
**** * * * **** ** * * size = 5;
    
** * *** **** * ** print the array */
*** * * * **** ** ** * i = 0; i < size; i++){
* *** ** ** ****** * ** ** ** * *** *** * * * * ", x[i]); * * **** * * * * * ** ** *
** * ** * ** * ** **
* * * ***** ** * * *** * *** * **
** ** * * * ** ** *
**** ** **** * * ** * I need this to happen size-times */
* * ** ** **** * j = 0; j < size; j++){
*** * * * * **** *** * * * * ** * ** * * from left to right */
* * * ******* * *** ** * * * * * * ** ** i = 0; i < size-1; i++){
* * *** *** ***** ** * ** ** * **** *** * ** * * * * ** **** ***** * * * * i-th element with its neighbor to check if they are in order */
* **** * ** * ** ** * * * ** **** ** * * ** ** **** ** * *** ***** ** * > x[i+1]){
* ***** * * **** **** * * *** * * ****** * * **** *** * * *** ***** * **** * * exchange the values of x[i] and x[i+1] */
*** * * ** ** * * * ** ** ** ** *** * * * **** * * * * ** * * **** * *** temporary; *** * * * ** ** *** * * *** * **
* * * ** *** * * *** * *** ****** ****** **** * * ** * * * ** * * * * * *** ** ** *** *** = x[i];
*** * * ******* * * ** * * * *** * *** *** * * ** ** *** * * **** * * * * * ** = x[i+1];
* * * ** *** ** * ** * ** *** ********* * ***** *** * * * * * * *** * *** * * * * *** = temporary;
*********** * *** ** * * * * * * *** ** ** * * ********* *** ***
* ** ** *** ** * * * * **** * ** * ** *** ** **
* ** * * * ****
* * ** *** * * *
*** ** *** ****** * *** ** * print the array */
***** * * *** ** ** *** * ** * * sorting: \n");
** * *** * * *** * ** i = 0; i < size; i++){
* * * ** *** *** * ** * * * *** ** * ***** *** * ** ", x[i]); * ** * * * ** ** * ** * ****
*** ****** * * * * ***
* * * ** * * ** * ** ** *** * ******* *
*** ** ** ** * ****** *
* ** ** ****** * ***
* * * ** ** **** * *** ***
* * * *** ***** *** * * * ** ** * ** * **  
** * ** *** * ** * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * * x[] = {77,22,88,11,22};
* * **** *** ** size = 5;
    
* ****** * * ** * * ** print the array */
** * ** ** **** * * * * * i = 0; i < size; i++){
* *** * ** * ** *** * *** * * ** * *** * * ", x[i]); *** ******* *** * **** * * ***
** *** **** ** ** *
* * ** * ** **** ** * ** * * ** *****
**** * * ** ** * * ***
** *** * * * *** ** * I need this to happen size-times */
* ** ** ** **** * ** * * j = 0; j < size; j++){
* * ** * * * ** ****** *** ** * * * * ***** from left to right */
* * * *** ** ** ** ** * ***** *** * * ** * i = 0; i < size-1; i++){
* *** ** * ** **** ** * * ** * ** ** * * **** * *** * * ** **** * ** i-th element with its neighbor to check if they are in order */
* *** * * **** * ** ** ** **** * *** * * ** * * ****** **** > x[i+1]){
*** *** * ** * ** ** ** *** *** * * ** * ** ** * *** *** ** ** * *** * ** *** ** * * ****** exchange the values of x[i] and x[i+1] */
** * * * * **** * ** ** * * ** * **** * *** ** * ***** * ********* *** ** ** temporary; ** *** *** ****** *** * ** * **
* * * *** ** ** ** *** *** **** ** *** * * ** ** * ** ***** * * *** ****** * *** ** ***** = x[i];
* * * * ** ** * * ***** ** ***** *** **** *** **** *** * * * * * * * * *** ***** = x[i+1];
* * ** ***** * * *** ** ** *** * * * * ** ** ** * * ** **** * * ** ** * *** *** * * ** *** = temporary;
*** *** *** ** * **** ** * *** * * ** * * * * ** ** ***
* * * * * ** **** * * *** ** * ** *
* * * * ***** ** ***
* * * ***** * * **
** *** ** * * ***** print the array */
* ** * * * * ** * ** *** * * sorting: \n");
** * ****** ** ** * * * * * i = 0; i < size; i++){
* **** *** ** *** **** ** ****** * ****** ******* ", x[i]); **** * ** ** * * ** * * * ** *
* ***** * * * * * *********
* * * * *** **** *** **** * * * ***
*** * ** ** ** * * *** **
* * * ** * * * * **
** ** * ***** ** ** *** **** * ** ** *
* * * * ****** * ** * * ** * * * ** **  
* * * * ******* * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ** ** * * * * * x[] = {77,22,88,11,22};
* * **** * ** *** ***** * size = 5;
    
****** * ******* * ****** print the array */
* * * ** * * ** **** i = 0; i < size; i++){
** *** ** ****** * * *** ** ** ** * *** * * * * **** ", x[i]); * ** * *** ** ** ** **** * ******
* ****** * * * * ***
* * * * ***** ** ******** ** ** * ** * *
* * *** **** **** **** *
** ** * * * ***** ***** I need this to happen size-times */
**** *** * * ***** *** *** j = 0; j < size; j++){
* ** * * ** ** ***** * *** ***** * * ******* * * * ** *** from left to right */
* ***** * * * ** * * * * ******* ** ** * * * i = 0; i < size-1; i++){
* ******* ** * * ******** * ** ** ** * ** * ** ****** * ** * *** i-th element with its neighbor to check if they are in order */
***** * ** * ******* * *** ** ** *** ** * *** * * * * *** ** * ** *** > x[i+1]){
****** ** * **** ** ** * * * ** ******* ** *** * ** * * * ****** * ********** ** **** * exchange the values of x[i] and x[i+1] */
* * * **** * ***** ** * *** ** ** ** * * * * ** ***** **** **** * ** * * * **** temporary; * ***** ** * *** * **** ** **
* * * *** *** * ** ** * * ** * ** ** * **** * ** *** ** ** * *** *** ** ** ** *** = x[i];
* * * ** * *** * * * ** * ** ********** * * * * ** * * * ** ** * * ** ** ** * = x[i+1];
* * * ** * * * * * ** *** ** ** *** ******* ** ***** * * * *** ***** *** * ****** * ****** = temporary;
**** * * ** * * * * * * * *** * ** * * * * ***** * * * ** **
* * * * * * * *** ** ** ** * *
* * * *** * * * * * ****
**** * * **** ** ** * *
*** * * * * ******* * print the array */
* *** * ***** * ** *** **** sorting: \n");
** ****** *** *** *** ** * i = 0; i < size; i++){
* ******** ** **** *** *** * *** ** * **** * ", x[i]); *** * ** * *** * *** * * ** * ***
* ** * * * * *
* * ** * ** * ****** ***** **
* * *** * **** ** ** **
** * * * *** ** *** *
** *** ** ** * * * * *********** * * ** *
** ** ***** *** ** * * * * * *** ** * ***  
* ** * ** ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ******* ** * * x[] = {77,22,88,11,22};
** ** *** **** * ** size = 5;
    
* * **** ** *** * * * print the array */
** * * ****** *** ** *** * * i = 0; i < size; i++){
** * * * * * *** **** ** * ** ** * * ", x[i]); * **** ***** * * ** ** **** *
****** * *** ** * * * **
** * *** ****** **** **** * * ***
*** * ** * ***
** ** *** * * I need this to happen size-times */
**** *** * ***** * * *** *** j = 0; j < size; j++){
**** **** *** * * * * ** * * *** * ** * ** * from left to right */
***** * * * * * *** ***** * * **** * **** *** i = 0; i < size-1; i++){
* * * *** * * * ** * ** ** * * * ** ** ** * ** * ******* * ** * ** * ** i-th element with its neighbor to check if they are in order */
******* ******** *** * *** ** * *** * * * * ** * * * ** * ** ** > x[i+1]){
* *** * * ** * * * ** * * ** * *** ****** *** ** * ** *** ** * * ***** * * exchange the values of x[i] and x[i+1] */
* *** * ** **** ** *** ** * * * * ** ** * * **** ***** * ** * ** ** ******** *** temporary; ** * ** * * * * *
* ** ** * *** ** ***** * * * ******* * * *** ******** * * * ** ** *** ** ***** * ** * * = x[i];
* ** * * * * * ********** * *** * * ** *** * **** *** *** **** ** *** ** * * = x[i+1];
* * ** **** ** *** * * ** ** **** * *** ** * *** ** *** * *** * * * ** **** ** * * *** **** = temporary;
***** *** ***** ** ** *** ** * * * ** ** * **** ** * *****
** * ** * * * *** * ** ** ** *** **
* ** * ****** *
* * ****** *** ** *
***** ** * * * * * ** ** print the array */
* * **** * * * * * * * ** ** * * sorting: \n");
* ** **** ** ***** * i = 0; i < size; i++){
* ** ** * ***** * ***** * ** **** ** * ***** ** ** * ", x[i]); * *** * **** * * * * * *** * *
******** *** *** *
* * * * * ******** ** * * ** * *
*** * * ** * ** * * * ***
* *** *** * ** ** *
** ** * **** * *** **** ** * **** * * *
* * * * * **** * * * * ** ** *** *** ** *** *** * *  
* * ** * * * * *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.201
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.6k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.3k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.6k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users