0 like 0 dislike
6.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 6.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * **** *** * * ** x[] = {77,22,88,11,22};
** ** * * ** size = 5;
    
* * * ** ** **** * * * print the array */
****** * * ** * * ******** i = 0; i < size; i++){
** ** *** ** * ** * * ** **** * * ** * ** ** ", x[i]); *** * * ******* * ** * * *
** ***** * * ***** * ***
* * ** * *** * ** ** * *** ** *****
** * *** * * **
*** * ** * *** * **** ** I need this to happen size-times */
** *** * * * ** * * **** j = 0; j < size; j++){
******* ****** ** * * ** ***** * * * ** ** from left to right */
*** * * * * * *** * * * * ** ** ** * * *** **** i = 0; i < size-1; i++){
************ ** * ** ** ** ** ** *** * ** * * * * * * ** *** ** ** * i-th element with its neighbor to check if they are in order */
** **** * * * *** * * ** * *** *** * *** * *** ** *** * * * *** ***** * * ** * * * > x[i+1]){
*** ** * ** ** * * * * ** * *** ** * * * * ***** * * ** *** * * **** ** exchange the values of x[i] and x[i+1] */
** ** * * **** * * * ***** * **** ** ** **** * * *** ** * ** * * * ** * * *** temporary; ** * ** * *** * * * *** * *
* **** * ** **** *** * ** * ** * ** * ** * * * **** *** *** * *** *** * ** * * * ** = x[i];
* *** ** * **** * **** * ** * * ** ** * * *** ** * **** * ** * * * ** * ** ** * *** *** ** = x[i+1];
* *** ***** * ** * * ******* ** *** ** * * * *** ***** *** * * ** ** * ** * * ***** = temporary;
** ** **** ** **** ****** * *** *** * * ***** ** * ** * ** ***** * **
* * *** * ** ** * * **** ** * *
** ** * * * * ** *
* ** ** * ***** * ** * *
** **** * ****** print the array */
*** ******* * * **** * sorting: \n");
* ** * * * * * * * * * i = 0; i < size; i++){
* * * ** * ***** * * **** * * * ** * * * * * * ******** * ", x[i]); *** ****** ** * **** * *** ** *
* ** ** * * *****
* * ** * * * * ** * * ** ** * * * **
* ** * * * *** * *
* **** ** * *** ** * *
* *** * *** ** *** ** * *** * * * * * **
** * * ** * * ** ** * * * ** * ** * *  
*** * ** ** * * ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * * * **** x[] = {77,22,88,11,22};
* ** **** *** * **** size = 5;
    
* ** ** ** ***** * * * * print the array */
****** * * * * * * ** i = 0; i < size; i++){
* *** * ***** ** ** * *** ** * ****** * *** ", x[i]); **** * * * ** ** * * * ** ** * **
** * *** * * ** ** * **
** * * ** * ** *** ** * * *
* * * * ** * *
**** * ** * * **** * * * I need this to happen size-times */
* ** * * * * * * * ****** j = 0; j < size; j++){
* * * * ***** ** * * * * ** ** ** *** * *** from left to right */
*** ** *** **** ** ** * * **** ***** * * **** i = 0; i < size-1; i++){
* * ** ** * * *** * * ******* ** * **** * *** *** * ** ********** * i-th element with its neighbor to check if they are in order */
* **** ** * * ** * ***** * * * * * *** * * * ** * * ***** ** * > x[i+1]){
*** * *** ** * ** ** **** ** * * * *** * ** * * ** * ** * * * * * *** ** exchange the values of x[i] and x[i+1] */
* * ****** * ** ** * * *** **** * **** **** ** *** * * * * **** * * *** * ** * * * ** * * ** temporary; * * *** * ** * * ****** *** ** *
* * * * * * * *** **** ** **** * ****** ** * ** * * ** * **** * * ** * * * * = x[i];
** * * * ** ** * ** ** * * * * * * ***** * * * ** **** * * * * * ***** * * = x[i+1];
** * *** * *** *** **** * *** ** ** ** * * ********** ** * * ***** ** ********* ** **** * * = temporary;
*** **** * * * * * **** * ** *** * ** ** * *** * * * * ** *
* *** * **** ** ** **** ** ** *** *** * *
** * * ** * * * * * ** **
*** * **** ** ***
* * * * *** * * * ** print the array */
** ***** * ** * ******** ** sorting: \n");
* * ** *** ** * * * * ** i = 0; i < size; i++){
** ** ** ** * * ** *** * ** * * ** **** *** * ******* ", x[i]); * * **** ***** ** * ** * * ** **
**** * * *** ***
* *** * ** *** **** ** ** *** ** **** *
* ** * * * * * *** * ***
** * * *** * **** ** * *
*** * * ** * * * * * * * * * *
* *** ** * * * ** * *** * **** * *** ** **  
***** *** * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** ****** ***** * x[] = {77,22,88,11,22};
* ** * * * ****** size = 5;
    
** ***** ** * * * print the array */
*** ***** ********* * ** * * ** i = 0; i < size; i++){
* * * ** * **** ** ** * ** * ***** * ** **** ** * ** ", x[i]); * ** * ** *** ******* * ** * *
* ** * *** *** * *
* ** * * * * * ** * ** * * *
** ** *** * *** *** *
** *** ** **** * I need this to happen size-times */
*** ** * ***** * * * j = 0; j < size; j++){
* * ** * * * ** * * * * * * * * ** from left to right */
*** * * ** ** ** **** ** * * * * ** ** ** * i = 0; i < size-1; i++){
* ** *** * * * * ** * * *** *** ***** *** * * * ** *** ** * *** i-th element with its neighbor to check if they are in order */
* * **** **** * * * *** * * * * * * * * * * * * **** * ** > x[i+1]){
** * *** ** * * * * * * * ** **** * ** **** *** * *** *** ** * * * * * * * exchange the values of x[i] and x[i+1] */
* * ** ** * * * * * * ** ** * * * ** **** * ** ***** * * ** * * * * * temporary; * ** ** * * ** * * * *** * * *
* **** ****** * * * ** **** * * * * **** * * * *** **** **** **** * ***** * ***** **** ** * = x[i];
** *** * * * *** *** ** *** *** **** * * * ** * * *** ** * * * ** * * * **** = x[i+1];
*** ** ** * * * * ** * *** ** ** *** *** ** ** * ** ** * * * ** * * ** * * **** * * **** ** * = temporary;
* ***** * * * * ** ** * * * *** * * **** ** ***** * * * *
** * * * * ** ** *** * *** *** * **
* * *** * ** **** ** ***
*** * ***** ** * *** **
* ** * * *** * ** * * **** print the array */
** ****** ***** * * * ** ** sorting: \n");
* * ***** *** * * ** ** i = 0; i < size; i++){
* ******* ******* *** * * * *** * * * ", x[i]); **** ** ** *** * * ** * **
**** * **** ** * ** * * **
* **** * * ****** * ** * * * * * ** * * **
* *** * * * ** * ** * *
* * ** **** ***
** *** * * ***** * *** *** **** *** **
* * ** * * * * * * ** * ** *** ** ** ***  
** * * **** * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * *** ** ** * * x[] = {77,22,88,11,22};
*** ******* ** * size = 5;
    
** * * * ** * * * print the array */
* *** * ****** * i = 0; i < size; i++){
** * * ***** * ** * ****** **** ** * ***** ***** *** * ", x[i]); * * **** * ** * *** * *
** * *** **** **
*** * ** * *** * * * ** **** *** ****
* ** ** *** * ****
****** ** * * ******** * I need this to happen size-times */
**** * ** *** ** * * j = 0; j < size; j++){
** ** * * ** ** **** ** * ******* *** ** **** from left to right */
* *** * *** * * ** ** **** ** *** * ** * ** * * * i = 0; i < size-1; i++){
*** ** ** *** ** **** *** ** * ****** * * * *** *** ** ** * i-th element with its neighbor to check if they are in order */
* * * * **** *** ** * *** * * ** *** * * ******** * * * > x[i+1]){
**** ***** *** * * **** ** *** ** *** * ** ** * **** * ** ** **** * * * * * ** * ** **** * exchange the values of x[i] and x[i+1] */
** * * ** ** * ** * * ** * * * ** * * ** *** ** ** ** **** * ** * temporary; ** * ** **** **** * * * *
*** * ** ** * *** * * * ***** * **** ** *** *** * **** ** *** **** * * * **** ** = x[i];
***** * *** * * * * ** *** * *** *** ** * ** ***** ***** ** * **** ** ** * * *** = x[i+1];
* * ** * ** ** *** **** * * **** * **** * **** * * ** *** * * * * * * * ** = temporary;
*** * * * * *** * ** * * **** ** * * * *** *** **** *
* *** *** ** *** **** * * *********** * *
* *** * **** * * **
* * ** **** ** * * ***
* ** * *** *** *** ***** print the array */
* * *** ** * ** **** * * * * ** sorting: \n");
** * ** * ** * ** * * ** * i = 0; i < size; i++){
** ** * ** * * ** * * **** * *** **** ** * ****** *** ** * ** ", x[i]); * * *** * * **** ** ** ** * * * * ***
* * * ** ** **** **** ** **
* ** *** * *** * * *** * *** *
* *** *** *******
* * ** * ** ** * *** ** **
***** ** **** * ** ** ** ** * * *** *****
******* ****** ** **** * ** * ** **** * * * * **  
* *** **** ** ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * ********* x[] = {77,22,88,11,22};
** * **** * * * ** size = 5;
    
* ** **** * * * * * print the array */
* *** ** * *** * * * * ** * i = 0; i < size; i++){
*** ******** ************ **** ******* * * ** **** * *** **** ", x[i]); ** *** * **** ** * * *** ** *
* ********* * ** * ****
* ******* * *** * * * * * **
*** * * * * * ** *
** ** *** * * ******* I need this to happen size-times */
* *** *** * ** **** ** j = 0; j < size; j++){
* * ** * ** * *** * ****** * ** * *** from left to right */
* * * * **** * ** * ********* ** * ***** i = 0; i < size-1; i++){
*** * * * **** * * * * * * * ** * ** ** * * *** **** ** * *** i-th element with its neighbor to check if they are in order */
*** *** ** ** * * * * * * *** * * ** *** ** ** **** ** * > x[i+1]){
* ** * ************** ** * * * *** *** *** * * * ** *** * **** *** * *** ** * * ** **** exchange the values of x[i] and x[i+1] */
*** *** * * ** * * * ** ****** ** * *** * * * * ** * **** *** * *** *** temporary; * * * ***** * ** * *** *
* * * * ** * * ** ** * * * **** ** ** * * * * ** ** *** * * * *** ***** ** * = x[i];
* * ** * * * ** ** ***** * **** ** * * ** ** ***** * *** * * ** ** ** * ** *** * = x[i+1];
** *** ** **** *** * *** * * *** * * * * * ** ** * * ** ** * ** * * * ** * * = temporary;
* ** * ** * * ***** ***** * * * ******** *** * * ** ** * ***
******** **** * * * **** * ** * * ***
*** ** * *** **
**** *** **** * *
* * * * ** ** ** *** print the array */
*** *** ****** * * *** ** * *** sorting: \n");
* ** *** * ** ** **** i = 0; i < size; i++){
* *** ** ** ** * ** **** ** ** * ***** ** ** * * *** * ", x[i]); * ** **** * **** * ** ** **
* ** ** ** *** * * **
* ** *** *** * * *** * ***** * ***** ***
** *** * **** *** **
* * *** * ** *
*** *** ** * * *** *** * ** ** *
* * * * * * ** * * * **** * **** * * * **** * **  
* ** * ********** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * * * ** ** x[] = {77,22,88,11,22};
*** * * * * *** *** * *** size = 5;
    
* * *** ** *** * **** print the array */
* *** * *** * ** * * ** i = 0; i < size; i++){
* * ***** * * * * ** * * * * * ***** ", x[i]); * * * * ** * *** ***** ***
* * * ** **** * *
* * * * * * ** * * ** ***
** ** * * ** * ** **
* * *** ** * *** **** ** I need this to happen size-times */
* * ** * *** ** * * ** ** j = 0; j < size; j++){
* * * * ***** * * * * ******* ******* * * ** from left to right */
* *** *** ** ** ****** * * * *** * ** * * ** i = 0; i < size-1; i++){
** * * *** ** * ** * ** **** * * * **** * ** ***** * *** ** * **** i-th element with its neighbor to check if they are in order */
*** * ** * * * * * * *** **** *** * *** * ** **** * ** ***** * > x[i+1]){
* *** * * ** ***** * ** ** * * ** ** * * * ** ** *** ** *** * **** ** * ***** * ** * exchange the values of x[i] and x[i+1] */
***** * * * * * ****** *** ** ** ** ** **** *** ** *** ** ***** ** * * **** **** * ** temporary; * * ** *** **** *** ******* * ** *
* **** * * * * ** ***** * * * * * * **** * **** ** *** * * * * ** ** * * * * ** * * * = x[i];
**** * * * ** *** * * *** * * *** ** ***** * *** ********* * ** *** *** ** * ** **** * ** ** = x[i+1];
* **** **** * * * * ** * * *** *** ** *** ***** * * * * ** * * * * **** * * * * * *** * = temporary;
* * ** ***** * ** * ** * * * ***** ** ** * ** * * * * ****
** * ******* *** ********* ** * ** * *****
** *** * *** **** ** ** *
* ** *** *** *** * * * ***
*** ** *** * *** * * print the array */
*** * ** ***** ** * * * * * * * sorting: \n");
**** ** ** * * ** ** * * i = 0; i < size; i++){
* ** * ** * **** * **** ** *** ** ** * * * ***** *** * ", x[i]); ** *** * * * *** * **** *
* **** ** ** ***** ***
**** * ** ** ** * ** * * *
**** * * ** ** * *
** ** *** * ** *
** *** **** * * *** ** * *** *** * **
*** * ** ** **** * ** **** ** * * *** **  
* * ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * * * ** * * x[] = {77,22,88,11,22};
****** * ****** ** * size = 5;
    
* **** ** ** ** ** ** print the array */
**** * ** * **** * * * * ** * i = 0; i < size; i++){
* * * * ** * * ***** ******** * *** *** * ** ", x[i]); * * * * * * * * * * ** *
**** *** * * ** * * * *
** * *** * ** * * * * * * **
**** ** *** *** *** * **
* ** * *** * * * * * *** I need this to happen size-times */
* *** * * * * * * * j = 0; j < size; j++){
* * * * ** * *** **** ** *** from left to right */
* ***** ** *** * *** * * *** *** * * *** *** * i = 0; i < size-1; i++){
* ** * ** ** ** ** * *** * * * ** **** * ** * ** ** * ** * i-th element with its neighbor to check if they are in order */
* **** ** ** * * * ** * ** **** *** * ** * *** * ** * ***** * > x[i+1]){
* * *** * * *** **** *** * *** * * * ** * * * * ** ***** ** ** *** ** * ****** * exchange the values of x[i] and x[i+1] */
** *** * * * * * ** ** * *** * ***** ** * **** * ** * ** * * **** ** *** ** * * ** * *** temporary; * * * * ** * *** * ** * * **
**** ****** * * *** ** ** * ** ***** ** * * ** * * * **** * * * * * ** ** * * ** * ** = x[i];
** * * ** ***** **** * * * * * **** *** ***** * ** * ***** * * * * **** **** * * = x[i+1];
**** * ***** * * * * * * * * *** ** * ** * * ** * ** *** * ** * ** * ** ****** = temporary;
* * * ** * ** * ** * * * ** ** *** * * ** * * ** ***
* * * * * *** **** ** ** * * * * *
* *** * ** *** * * * ***
* *** *** * * * ***
**** ** * * *** *** * ** ** print the array */
**** ** ** ** * * * * * * **** *** sorting: \n");
* *** **** ** * * * ** *** i = 0; i < size; i++){
* ** * ** ** * ** * ***** * ** * ** *** *** ** * *** * ", x[i]); * * * * ****** * * *** * * *
* *** * **** * ** * * *
* ** ** * ** * * *** * * ** * * * * **
* *** * * ** ** ** *
** **** * * * **** *
* ** ** * * * ** *** * * *** * ** *
** ******** ** * ** ** ******* **** * * **** * *** * **  
** ***** ** ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** ***** ** * * x[] = {77,22,88,11,22};
** * * *** ** **** *** * size = 5;
    
** * *** * *** * ** **** print the array */
* * * ** ** * ** * * ** * i = 0; i < size; i++){
* * ** **** ** * * * **** * ** * ** ", x[i]); *** ** * * ** ** * ** * **** **
** * *** ** *
**** * **** ** * ** * * * * *
** ** * ****** * *
* * * ** ****** * ** I need this to happen size-times */
** * ** * ** * * *** * * j = 0; j < size; j++){
* ** *** * * *** * ***** ***** **** * * * ** from left to right */
* ** ** * ** ** * ** ** ** ** * **** * * * ********* i = 0; i < size-1; i++){
* * * * * *** ** * ** * *** * * * * * ****** * * ** **** ** * ** ***** i-th element with its neighbor to check if they are in order */
**** ** ** * * * * ** **** ** ** *** * ** * * ** * ** * > x[i+1]){
***** * * *** * * *** * ** ********** *** ** ** * * * * * *** **** * * * *** * * *** ****** * exchange the values of x[i] and x[i+1] */
** * *** * * * * * * *** ** * * * ** ** ** ** *** * * * **** ***** * *** * *** * temporary; ** ** ** *** *** * *
* * * * * * * *** **** * * * ** * * ********** * * * * * ** ** *** * ** ** * = x[i];
**** * *** **** * **** * ** *** * * * * * * ** * *** * * ** *** * * = x[i+1];
*** ** * * ** * ****** **** * * * * ** ** * * * ** ** **** **** * ** **** * * ** ** *** * ** * * * = temporary;
** * * *** * * * * * ** * * ***** * * * *** ** * * * * * **
** * ***** ** ** **** *** ***** * * ** *********
** * * * ********** *
*** * * * **** * * ***** **
* * * **** *** * * * * *** print the array */
* ** * ***** * * ** * *** ***** sorting: \n");
* * * *** * * ** i = 0; i < size; i++){
**** * ****** * * *** **** ** ******* **** **** * ", x[i]); * *** * * ** * **** * *** *
* * * * **** * ** **
* ** * ** *** ** * * * * * *** ** ** * **
*** *** * *** * * * *
* *** * **** * * *****
* ** ** * * ** *** **** ***** * *** * **
* * ** ** ** * **** ** * *** * *** * *  
* * ** * * ** ****** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** * * * * ** x[] = {77,22,88,11,22};
* *** ***** * ***** * size = 5;
    
*** * ** * ** ** * ** print the array */
* * ****** * *** **** i = 0; i < size; i++){
* ** ** * * ** * * * * ** * ** ", x[i]); * *** *** ******** * *** * ** * *
* * * ** * ****
*** * ** *** **** *** * *** ** *** ** *
* ** ** * * ** ****
* * * *** ** * * ** ** * I need this to happen size-times */
* * * * ** * * **** * ** j = 0; j < size; j++){
** * ** ** * * ****** * ** ** ** **** from left to right */
**** ****** * **** * * * * * * **** * ***** i = 0; i < size-1; i++){
** ** * ** ** **** ** *** ** ** * ** **** ***** * * ** * ** i-th element with its neighbor to check if they are in order */
* ** * * * ** * * * **** * * ***** ******* ** *** * *** * * ** * * * ** * * > x[i+1]){
*** * * * * * * * * * ** ** * * ** * * * * ** * ** * **** *** ** * ** ***** *** *** exchange the values of x[i] and x[i+1] */
* ** ** ** ** ** * * * *** ** ** * ** ** * * ** * * * * ** * * * **** *** * temporary; ******** * * * ** * * *** * **
****** ** ** ***** * ******* * * * *** * * *** * * * ** * * * * ** * * ** ** = x[i];
** * * * ***** * * *** * * * * * * * ** * ** ** * ** ** ** * ***** * *** ** * = x[i+1];
** ******* ** * **** * * * * *** * * * * * ** * *** ** * * ** * **** *** * *** ** * * ** = temporary;
** ****** *** * * * *** *** ** * ** * ***** * ****** *** *** * ** * **
* * * * * * * **** ** * * * * *** * **** ***
* ** * ** * ** * **
* ** ** ** *** ******
* *** ** * ** * ** print the array */
* ***** * * * * ** * *** ** sorting: \n");
* * * * * ** * i = 0; i < size; i++){
*** *** ** * * ** * * * *** ** ** ** ** * ** ** * * **** ", x[i]); * * * * *** * * * * ** ** *
** * * * ** ** * * ***
*** ** ** ** ***** * * ** * *** * ***
* ** ** ** * * **
*** ** * * ** * * *
** ** ** *** ** ** * ** *** * * * ** *
* * ** ** ***** *** *** *** ******* *** **** *  
* * * ** *** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
****** ** * ** *** * * x[] = {77,22,88,11,22};
* **** * * ** ** * ** * **** size = 5;
    
* ** *** ** * print the array */
*** * ** * *** * ** * **** i = 0; i < size; i++){
* ** * **** *** **** ****** ** * ** ** * ** ** ** *** * *** *** ", x[i]); ** * *** ****** ***** * ***** ***
* * * * * ** **
** **** * * * * ** * * **** * *** ** * **
* * * * ** ** * *
** * *** * *** ********* * I need this to happen size-times */
* ** * **** * ** * **** ** j = 0; j < size; j++){
* * * * *** * * ** * * *** *** ** * from left to right */
**** * **** * ** **** ***** *** ** * * * * i = 0; i < size-1; i++){
* * ** ** **** ** * * * ** *** *** ** *** * ** * *** ** * * ** i-th element with its neighbor to check if they are in order */
* ** * ** * ** **** *** *** * ** *** * * * * *** ** * ** **** > x[i+1]){
* *** ******* * * * ** *** * * * * * * * * ** * * *** * * ** * ** * * *** * * * ** * * exchange the values of x[i] and x[i+1] */
** * *** * **** * ** **** ** *** * *** ** ** ** *** * * *** **** * *** ** *** ** ** **** temporary; * * * *** * * * ** * ** *****
* * * * * * * *** * ** * *** *** *** *** **** * ** * * * **** **** *** **** * *** * = x[i];
* * **** * ** *** * *** * * ** ***** * * ***** **** *** *** ** * ** **** * *** *** *** = x[i+1];
* **** * ** * * * ** **** * * ** * *** ** **** * ****** ** ** * **** ** ***** *** * * ** = temporary;
*** * * ** * * * * * * ** ** ** ****** ** ** * ***** *** ** * *
* ** ** ** *** * * ****** * ******* ** ** *
*** * * *** * ***
*** *** * ** *
* * * * * ** *** * * print the array */
* * * * * *** *** * **** * ** sorting: \n");
*** ** * * ****** **** * * i = 0; i < size; i++){
* *** * * ** ** *** * * * * * * * * ** * * ** * ", x[i]); *** * * * *** * ***** *** *** *
**** * * *** * *** * ***
** **** * * * * ** * ***** *
* * ***** **
* * * * ** * *** ** * *
* * * * ** ** * ** ** *** * *** *
* * * ** * *** * ** ** * * *  
* ** * ****** * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.242
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.2k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users