[Exercise 16] Arrays: Bubble-sort

Question

12.1k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64

[Exercise] Coding (C) - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited | 12.1k views

46 Answers

Page:

« prev
1
2
3
4
5
next »

410630017 · Answer 1 · 2017-12-20 14:35:13

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
 *      *   **** ** ***  *   *   x[] = {77,22,88,11,22};
 ** * *****   * * * ***    * ******* size = 5;
    
 *    ** * **  * *** * **    * *  print the array */
*  *      * ** ** ** * *  *    *     i = 0; i < size; i++){
***  ** * * **  *   *  *    ******   **  ***  ** * **** ***  ****   ", x[i]);      * *   *  ** *  ****   *** ** ** * **  
*      * *  ******** ** * *   
   *  **   * ** ** ** ** ***  ***  ** *     *  *  *
*  *  *****  *  *  * ** *** ** 
 *       *     * * * *    I need this to happen size-times */
*** **** *  ***     ** * *  ** * j = 0; j < size; j++){
  *  *  ***** *   *  * ** *    ****   ***  *** *** from left to right */
 ** * * ***   *   ** *   ** *  *** ***     * **   * **   ***  i = 0; i < size-1; i++){
*     * * *  * *  ****   *  **  **   ***** *  ****   ** ******   *  ** * * * *  *   *  i-th element with its neighbor to check if they are in order */
** **  *** ***    *  *   **  * *  *    *  *     * *     * *** **  *   ***   *  ***** > x[i+1]){
 * ** ***** ***  **  *  ***   **   ********  *   * ***   * **   **    ***     *  *  * *  **  **  **** *   *    exchange the values of x[i] and x[i+1] */
* ** **  **** *  * ** **      * *  **   **  *  *  ***  * **   *  * **    *     ** ** ** ** *** *      *** temporary; *********** ***   * ****** *    ***  * 
   *** **  *  ***  **   ** **      **  *  **  * *      *    * *  * *  *  *   ** *  *  *    * *  **** * ****   * * * = x[i];
  *** ** *  *  ***  ***   *** * *  *   * ***     *  * ** * ** **** *** * *  * **   **   * * * ******* = x[i+1];
    * * ***   ****   *****   ** **  *    * *  *  * **  *  *****   *  *  * **    * **  ** *** ** *    * **  * = temporary; 
* * ********** ** *    *** ***** *** ****  *  ** ***  *     * ** ** ** *   **
 *      * **   * ** **    *   * * * ***  **  * ** *****  ***
 ** *  ***     **      ** *   
  ** * * *  *  **** *  *  
   ** * *** *  *   *  ** * print the array */
   *     *     *** *   ***** *    *  **  sorting: \n"); 
* ***     ****   ****  **  ** ** i = 0; i < size; i++){
  *   * * *   *** **  * ** ** **  *  ***** **    *  *      *      ", x[i]);   **  *  ** * *      ** *     ** * * *   
****  *      *** * * *** ****
*   **** ******* * *  * ** * *     * ***  ***  **
**    ***** *  *   ** *    * 
*** ** *   *    *  ***  *
 * ***** *   ** *  * *   ***  *     ***  *    *  
  ** ***** * * **** ****  ** ** ***     *** * **  * *     
 **  *  * ****** *** *****  *** **  * 0;
}