0 like 0 dislike
13.7k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 13.7k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * *** * * * * x[] = {77,22,88,11,22};
* ** * ** ** * * * ** * * size = 5;
    
*** **** ** ** * ** * print the array */
**** * **** * * ** ** * * i = 0; i < size; i++){
*** * *** * * *** * * * **** **** ** * * * * ", x[i]); * * * * * *** * ***
*** * ** * ** ** ** * *
* * ** **** *** * ** * * ** * *
*** ** * ** * **
****** * * ** * ** * * I need this to happen size-times */
* * * ** * * * * ** j = 0; j < size; j++){
** *** * *** *** * * * * * * * ** *** * * ** *** from left to right */
*** * *** ** * * ****** * * * *** *** ** i = 0; i < size-1; i++){
** * * ** * * **** * * * ** ** * * ** ** * *** * *** *** ** i-th element with its neighbor to check if they are in order */
* ** ** ** ****** **** * * * ** * **** * * ** ***** * * ** > x[i+1]){
**** * * ** ** ** * **** ** * ** * ** *** ** * * * * ** * * * * ** * ** * * *** * * * exchange the values of x[i] and x[i+1] */
* ** * ** * * ** ** **** ** ** ** *** *** * ** ** * * ** * *** * * ** * * * *** * ** temporary; * *** *** * * * **** *** * *** *
*** * * * * ** * ** * * * *** * ** * * * * * **** * ** * * *** ** * * * * ** * ***** * ** ** *** * * * *** = x[i];
** ** **** ** ** ** * * * * ** * ** *** * *** * * **** **** * ** * * * **** * ** ** = x[i+1];
* ** * * ** * * *** * ** * * * * * * * ***** * ** * * * ** * ** * = temporary;
** *** * * * * ** ** * ****** * * *** *** * * *** * *** * *** ** ****
****** * * * ** * * **** ** * **
* * * * * ** * * * * **
**** ****** * * * * ** **
***** *** *** *** print the array */
* ** * *** * ** * * *** ***** * * ** sorting: \n");
*** * * * ** ** * ** i = 0; i < size; i++){
* * **** ** ** * * *********** * **** ** * ** ", x[i]); *** ** * **** ** ** * * * * *
** * ** **
* ** * * * * * * ** * *** *
** * * * * ** * **
* * * ****** * * *
* *** * * ** * * ** * *** ** *** *
* ** * * * *** * * * ** * * ** * *** * *** * * *  
** * * ** * ** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ***** ** * **** ***** x[] = {77,22,88,11,22};
* ** * ****** * ** ** * size = 5;
    
*** ***** *** *** ** print the array */
* * * * * * *** * * * * * i = 0; i < size; i++){
**** * * * * ** * * * ** **** **** ", x[i]); ***** ***** * * ** ******* * * *
**** * ** ****** *
* * * **** * * ** ** * **** **** * *
* ** ** * * * ** *
* *** ***** * * I need this to happen size-times */
****** ** * * ** ******** * ** j = 0; j < size; j++){
*** * * * * * ** * ***** ** ** *** ** ****** *** ** from left to right */
** * *** **** ** *** * *** * ****** *** i = 0; i < size-1; i++){
** ** ** *** ** * * *** ** * **** * ***** **** * * * **** ** ** * i-th element with its neighbor to check if they are in order */
* ******** ** ** * * ** **** * ** ** ** ** * * * *** * * * **** * *** *** > x[i+1]){
* *** ** * *** ****** * ** * * * ***** * * * * ** ** ** * * *** * * * * ** exchange the values of x[i] and x[i+1] */
* * * ***** * *** ** * ** **** * * ** ** * ** * * ** * ****** * * ** * * * ** temporary; * ** ********** *** ** *** *
* * * * ** ** * *** ********* ** * ****** ** *** * ** ******* ** ** * **** ******** * ** = x[i];
** * * **** *** * ** * *** * ** * * * ** ** * ** ** ** *** ** * * * * * ** * ** = x[i+1];
* * * * * * ** ***** ** ** * * * ** * ** * ** * * * * ** ** * * * *** ** * * *** * ** * * = temporary;
**** ** * * * *** * **** * ** * * * ***** ** * * ** *
* *** ** **** * * * ** ** * * **
* * * * * * * ** * * * *
*** * *** * * **** * * *
* ** * *** * ****** ******** * print the array */
* * * *** *** * * * *** sorting: \n");
* *** * * ****** ** ** ** ** ** i = 0; i < size; i++){
*** ** * **** **** ** *** *** * ** * * *** **** * ** * ", x[i]); * **** * *** **** *** ** *
** * * ** ** * * *
* * * * * ***** ** ** **** *** ** * * *****
* * * * ** * **
* *** * ** ** ****
***** ** ** ** * * ** **** ** **
**** * * **** * ** * * *** * * ** * *** *  
** * * ** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ** * * ** * x[] = {77,22,88,11,22};
* *** *** * * * * * * size = 5;
    
***** *** * * * ****** * *** print the array */
* ** **** *** ***** * * * i = 0; i < size; i++){
* ** ** ** *** * * *** * ** ** * * * * * ", x[i]); * * * * ** ** ** * * *
** * ** ** **
*** ** ** * * * *** * ** * * * ***
** **** * * ** *
* * ** * * **** *** I need this to happen size-times */
** **** **** ***** *** j = 0; j < size; j++){
** * * * * * * ** *** * ** * *** ***** from left to right */
* * * ** ** ** ** ** ** **** * *** ** *** i = 0; i < size-1; i++){
** * * * * ** * * ***** * ** **** * * ****** * ** ***** ** * ** * *** i-th element with its neighbor to check if they are in order */
**** * * * * ** ** * ** ** * ***** ** * **** * * *** * > x[i+1]){
*** ** * * * * * *** ******* * *** * **** * ***** * ****** ** ** ** * ** ** * * * ** ** ***** exchange the values of x[i] and x[i+1] */
**** ** ** ** * **** *** * ** * ** * * *** *** ** * * * ** * * **** * temporary; * ** * **** * * * *** ** * * * *
* * * * * * ** *** ** ** ** * * * * * * **** ****** * * * **** ***** * **** *** *** ** ** ** = x[i];
*** ***** *** ** * * ***** * * * ** * ** ** * **** **** * ** ***** **** ***** **** ** = x[i+1];
**** ** ** * ** * ** * ** ** ********** ** * *** * ** ** ** * **** ****** * ***** ** = temporary;
** **** ** * * ** *** *** **** ** * ** ******* ** *****
* ** ** * * *** ** * *** * * ** ** *** **** *
*** * * ** * * *** *
* ** * ** *** **** **
*** *********** * * ** ** print the array */
*** * **** ** ****** ***** sorting: \n");
** ****** ** * * * * * * * * * i = 0; i < size; i++){
** * ** ** * * * * ** * * * * * * *** **** ", x[i]); * * ***** * * * * * ** *****
*** *** * ** *** * * ****
*** **** ** *** * *** ** ** ** *** ***
* **** * * * ****** ** **
* ** * ** * ** ** * *
* * * *** * *** * * * * * * ** * ** ***
** * ** * * * ** ***** * * * **** **  
* ** ** * *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * * ** * ** ** ** x[] = {77,22,88,11,22};
*** * * ** ** ****** size = 5;
    
* * *** *** * * ** print the array */
** * **** ***** * *** * ** i = 0; i < size; i++){
***** **** ** * * *** ** *** * ** ** ****** ** ", x[i]); * ** *** **** *** ** *** *** * *
* ***** *** ****** **
** *** * * *** * ** * * ** *** **
** ***** ** * * *** *** *
* **** * *** ** ** *** * I need this to happen size-times */
* **** ** ** * ** *** * *** j = 0; j < size; j++){
* * ** * * * * ** ******* ** ** ** *** from left to right */
* * * ** ** * **** ** * * * * **** * * ** *** ** i = 0; i < size-1; i++){
** * ******** * * * * ** * ** ** * ** ** * ** * ** ** ** * * *** * * i-th element with its neighbor to check if they are in order */
** * ******** *** *********** ** ** * * **** * ** * * * * * * * ** ** > x[i+1]){
** * * * ** *** ** * * * * * * * *** * ** * * * * * ** * * *** ** * ****** * ******* ** exchange the values of x[i] and x[i+1] */
* * * **** * * ** * ** * *** * * *** *** *** * * *** *** *** * * *** temporary; ***** * * *** ** * ***** ** ***
* * ** **** ** * * * * * * * **** ** * * ******** *** * **** * * ** * * * * * * * ******* * = x[i];
** * * ** ***** ** * * * ** * ** ** ** ** * * * * ** * * ** * * *** *** * = x[i+1];
* *** ** * * * ** ** *** * * ***** * * **** ** * ** ******* * * * * *** * * = temporary;
* * * **** * * *** * * * * * ** * * * ** *** ** ** * * ** ** ** ***
** * **** ** ** * ***** ** * *
* ** *** * ** *
* * ********** * *
** * * * * ** ** ** ** ** print the array */
** * * **** * ** * * ** * ** sorting: \n");
** * ** ** * * ** ** ** * i = 0; i < size; i++){
** * * ** * ***** *** * ***** ** * * * ** * ** ", x[i]); * * * ******* * ** * ** * ** ***
*** * * * ** * * * **** ***
** ** * * *** * * ** * * * **
** * * * * * *** * **** * **
* ** * * *
* * ** * *** **** *** * *** * * *
**** ** * ** * * * *** ** * ** * ** ** **** * * *  
********* *** ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * *** * * * ** ** *** x[] = {77,22,88,11,22};
* * * ** * ** *** * size = 5;
    
**** * * ** *** ** * print the array */
* * * ***** * * * ***** i = 0; i < size; i++){
*** **** ** ** * *** * * * * ** **** **** * *** ** **** ", x[i]); * ** ** * * ** **** * * **** * *****
*** * * ****** ***
*** * * * * ** * *** * ** * * * **** *
** ** ** ** ** ** *
**** *** * * ** *** * I need this to happen size-times */
** ** ** ****** * ** j = 0; j < size; j++){
* * ** *** ** ****** * * ** * * ** * * * from left to right */
** ** **** * *** * * ***** ***** * **** **** i = 0; i < size-1; i++){
* ** ** *** **** **** * * **** **** * * *** **** * ****** * ** i-th element with its neighbor to check if they are in order */
** *** ** ** * * * * * * * ** * ** ***** * ** * *** ** *** * > x[i+1]){
** ** ** * * * * ** * ** **** * ** *** * * * **** ** *** *** * * ***** * * * * * ** ** * ** * *** exchange the values of x[i] and x[i+1] */
* * ** * * *** ** * * *** * *** ** ****** * *** * * ** ** *** **** * * * *** ** * * temporary; * ** * * * ** * * ** * * ** * * *
** *** * * * **** * * ** *** * * ** * * ** * * ** * * * **** * * * ******* *** * = x[i];
** *** * ** ** **** * * ************** ** *** ***** *** ** * * ***** ***** * * * ***** * = x[i+1];
* * * * * *** * * * * * ** * * * ***** **** * * * ** * ** * * ** ** * ** = temporary;
** * ** *** * ****** * ** *** * *** **** ** *** **** * ** ** ***** *
* ** * ** **** * ** * ** * *** **
*** ** * *** * * * *** *****
* ** ** * * * * ****
* * ** * **** ** * print the array */
* **** ****** *** * ** ***** ** *** sorting: \n");
*** * **** ** *** ** * *** i = 0; i < size; i++){
* * ** **** * ** * * ** ********** ****** * ** * *** * ** ", x[i]); * * * *** *** * * ** ** * * *****
***** * * * ** *
**** ** * * * * ** * *** *
* **** * * **
* *** ** * *** * * **
* * *** * * ** * ** ** * * * * * **
* * *** ** * ** * ** * * * * * ** * * ** * *  
* * * * **** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ***** * * * ** ** x[] = {77,22,88,11,22};
********* *** * * ** * size = 5;
    
*** * * * * * * * * print the array */
* * * *** *** * ** * *** *** i = 0; i < size; i++){
** ** * * * *** ** * * * **** **** * *** * * *** ** ", x[i]); *** *** * * ** * ** * *** ** *
* ** * ** ** *
** ** *** * ** * ****** ******* **
*** ****** ******** *****
* *** ** **** * * *** I need this to happen size-times */
* * *** ** ** *** *** ** j = 0; j < size; j++){
* * *** ** ** * * **** * * *** * from left to right */
* * * ** * * * *** * **** ** *** *** * * ** i = 0; i < size-1; i++){
** *** ** * * * * * * * * * * * ******* *** ** * * ** **** ** ** * ***** i-th element with its neighbor to check if they are in order */
**** * ****** * * ** *** ** * * **** ***** * * * ** ** *** ** * ** ** ** * ** * ** > x[i+1]){
** ** * ******* * * * * * * * ** ** * ****** ** * ** **** * *** * ** *** *** * exchange the values of x[i] and x[i+1] */
**** ** ** ** * *** * * * * * *** ** ** * **** ** * * ** * *** * *** * * ** * *** **** * * ** temporary; * ****** * ** *** ** ** *** *****
** * ***** * ****** * *** **** *** ** * ** ** * * * * * **** * * * * ** * * * = x[i];
* * * ** ** ** * * *** * **** *** ** * * ** ******** * * ** * ** *** ** * **** ** ** * = x[i+1];
* ** * ** * * **** ******* **** * * *** * * * ** * **** **** * *** **** *** * = temporary;
*** * * * *** *** * * * * * * ** * * * ** * ** ***** *** * * * *
***** *** *** ** * * ** ** * * * ********* * ***
***** ** ** ** *** *
* * ** * *** ** **
* * * * ** ** * * print the array */
* * ** * *** * ** * * * * *** *** sorting: \n");
* ** ** * * ** * ** * i = 0; i < size; i++){
*** ** * **** * * * * * * * ** * * ** *** *** ", x[i]); ** * * * * *** * *** *
* * ** * * *** * * *
* * * ** * ** ** ***** ** * * * **
* *** ** ** * ** ******
* * * *** ****** *** *
* * * ** * * * *** ** * ** ** **
*** * **** *** *** ** **** ** * ***** * ** ** * **  
* *** * * * *** * *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * ** * x[] = {77,22,88,11,22};
* *** ** * *** ** * * size = 5;
    
* * * ** ***** ** **** print the array */
* ** **** * * * * ***** i = 0; i < size; i++){
*** *** ** *** ** * * ** *** ** **** * ** ** * ** **** ", x[i]); * *** * * *** ** * * * * *
* *** * * *** *
** * * ****** * *** ** ** * ** ** * * * *
* * * * * *
* ** ** * * * * I need this to happen size-times */
*** * * * * *** **** * * * j = 0; j < size; j++){
* * *** * ** ****** ***** **** * * ***** * *** ** from left to right */
*** * ** ***** * * * ** * * *** ** * * i = 0; i < size-1; i++){
***** * * * * ** * * ** ** ** * *** * ** ****** * ** * * * * ** * * * * i-th element with its neighbor to check if they are in order */
* * * * ********* * * * * ** * ***** * * ********* * * **** * * **** * * > x[i+1]){
** *** ***** * * ** * * * ** * * * * ** *** ** ******* * ***** *** * ** ** * * exchange the values of x[i] and x[i+1] */
* ** * ** * ** ***** * ** * ******* ** ***** *** * * * *** ** * * * *** ***** *** **** **** temporary; * ** ** *** ** * *** ** * * * * ** *
* * ****** ** ** ******** * * ** * * * * * ** * ** * ** * * *** *** ** *** * * = x[i];
* ******* ** * * * ** *** *** ** * ** *** * * ** * * ** **** * *** * ** * ** * * * = x[i+1];
** **** * * * ** *** * * * ** ** * * ** * ** *** ** *** * * * * * * * * ** **** * = temporary;
******** * * * ********* ** *** * ** ******** *** * ** *** *
***** ** * ** ***** ** * * ** * **** *
** ** * * * *** *** * **
** * * **** * *** ***
* * ** * * * ** print the array */
*** * * * ** * *** ** * ** ** sorting: \n");
* *** ** * * * * ******* i = 0; i < size; i++){
* *** * *** ** * *** ** * * ** * *** *** ** ********** ", x[i]); *** ** ** * ** ** * ****** *
*** ** ** ** ** * *
* * * *** ** * ** ** * ******** *
* * * * ** ** ** ** **
* * * * * * ** *** *
****** * * ** **** * * * * ** **** *** * **
* * * *** *** ** * * * * * ** *****  
*** * ** * *** * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * ** x[] = {77,22,88,11,22};
** * * ** ** **** size = 5;
    
* * **** ** * **** ** * print the array */
* * * * * * * * * ** * * i = 0; i < size; i++){
* **** * ***** * *** * * ** * ***** ** ** * ****** ** * * ** ", x[i]); * * * * ** ** *** ** ** * *
* ** ** ** * ** ***
**** * * * * ** *** ** ** ** * * *
* * * ** * * *** **
* * ** * ** * * **** * I need this to happen size-times */
* **** *** **** ** * * * ** j = 0; j < size; j++){
* ** ** ** * * ********* *** * ** ** * * ** * *** from left to right */
** * *** * * * ** ** ** ** * * ** * ** *** * * i = 0; i < size-1; i++){
* * * * ** * ** * ** * * ** * ** **** * *** * **** ** * i-th element with its neighbor to check if they are in order */
* * * * * * * ** ****** * **** * * * **** * ** * * * **** * ** > x[i+1]){
* ** * * ** **** * * ** * *** * * * **** *** * ** * *** ** ** ** * * ** * **** ** * exchange the values of x[i] and x[i+1] */
* * ** * **** * **** * * * * * * * ** ** * ** * * * * * ** ** * * ** ** *** * temporary; * * * ** ** * * *** * * *
**** * **** * ** * * * **** * ** * ** * ** * ** * *** ** * * *** * ***** * ** * * ** *** * * = x[i];
* * ** * ** * *** ***** *** ** * *** * ** ** *** ***** * * **** * *** ** * ** * * * * * *** = x[i+1];
**** * * * * * * * * ** *** *** *** * ** ** *** * *** ** ** **** * * *** **** = temporary;
** ** ** *** * ** ** ** ** ***** * * *** *** * * * *** * ** ** * *
* ** * * ** ** * * **** *** * *
******** * ** * * *
** ** * * ** ** * **** *
* * ** * * * * ** * **** print the array */
** * * ***** ** ** * ** ** sorting: \n");
* ** ***** ** *** * ** * ** i = 0; i < size; i++){
*** ** * **** **** *** *** * * * * *** *** ", x[i]); * *** ** ***** * * *** * * *
** * ** * * * ** *
* * * * * * * * * * ** * * ****
* * ** ** * * **** **** *** **
* ** ** * **** * *** *
*** * **** * *** ** * *** * * * *
* *** * *** * ***** * * * * ** *  
** **** **** * ***** ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * ** * * *** * x[] = {77,22,88,11,22};
** **** ** * * **** size = 5;
    
**** * ** * ** ***** * * print the array */
*** * * * * **** * * * * i = 0; i < size; i++){
* ** ******* ** * ** * * * ** * * * ** ** *** ** ", x[i]); * * ** **** * ** * * ***** *
** * **** ** * * * ** *
**** *** **** * ***** * *
** * * * **** ** **
**** * * * **** * * I need this to happen size-times */
**** ** * **** * * * j = 0; j < size; j++){
** * ** * * * ** * *** * * * * ** *** * ** * from left to right */
* ***** ** * ***** ** **** *** * * * * ** **** i = 0; i < size-1; i++){
* * *** * ** * * ** * * ** * ** ** ** * * **** * ***** * ** ***** * i-th element with its neighbor to check if they are in order */
* * * * * * ***** *** * * * * ** ***** * ** * * * ** > x[i+1]){
** * * ***** * ****** * ** * * ** * * * * * * *** * * * **** ** *** * * ** exchange the values of x[i] and x[i+1] */
** ********* *** *** ***** * * ** ** * ** * * * ****** ** * *** * ** ******* * *** * ** ** temporary; ** * ****** * ** *** * * ***
** ** **** * ****** ***** * ******* *** ** * * * * *** * * * ** * * **** ***** * *** = x[i];
** ** ** **** ** * * ****** *** ** * ** *** * * * ** ** * * * * * * * *** = x[i+1];
* * *** * * ** * * * ** *** * ** * ****** * ******** ** * * * ** * * * * * * * * = temporary;
* * ** * *** * * * ** * * * * * ** * ** ** ** * * ** *
** * * ** ******* ***** *** * **** * * *
* * * * *** ** * ** * **
* ** ** **** ***
** *** ** ******** ** **** * print the array */
*** ** **** ********* * * **** ** * sorting: \n");
*** *** * * ** * * * * * i = 0; i < size; i++){
* ** ****** * ** *** * *** * ** *** *********** ", x[i]); * * ****** * * * ** ***** ***
* * *** ** * * * * ** *
** * ******* ***** *** *** ** ** **
*** * *** * *
*** ** ***** * ** * *
* **** * * * * * * * * * *** ***** *
***** * * * ** ***** * ** ** * * *** *** *** *  
***** ***** ** * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** ** *** **** **** x[] = {77,22,88,11,22};
*********** *** * * *** size = 5;
    
* ** ** ** *** print the array */
** * ** * *** **** ** i = 0; i < size; i++){
* * **** ** ** * * ** * ** ** ** * ***** * ** ** * ", x[i]); * * * ** * * * *** ** * * ** *** **
** *** * ***** * **
* ** * ***** *** ** ***** ** * ** **
* * * ** * * *
* * **** ** ** **** I need this to happen size-times */
** * ** * * ** ***** j = 0; j < size; j++){
* * * * *** * ** ** ** ** **** ** * * * * from left to right */
* ** *** * * * ** *** * *** ** ** **** ** * ** i = 0; i < size-1; i++){
**** * * * * *** * * * ** * ** * ** ** ** *** **** * * * * i-th element with its neighbor to check if they are in order */
* ***** * *** *** * * *** ** ** ** ** * ** * * * * * * ***** ** * > x[i+1]){
*** * * ** * ** * ** ** * * *** *** ** * * * *** * **** * * *** * *** * * ** * exchange the values of x[i] and x[i+1] */
* ** * * * * ** * *** * * ** * * *** * * * * * *** ** * ** **** ** * * * * * *** temporary; ****** *** ** * * ** ** * ***** ** * *
* ** **** ***** ** ** * ** ** * * * * **** * * *** * **** * *** = x[i];
* ** * *** * * ** *** * * ** ** * ** * ** ** * * ***** ** * *** * * ** * ***** ** * * ** *** = x[i+1];
** *** ** ** * * *** *** ** * *** * ***** * * ** * *** * **** ** * * * * ***** = temporary;
* * * ** **** * * ** * * ****** * ** * *** ** * * *** ***
* * * ** *** * **** ******* * ** * ****
**** * * * *** ** * *
** * ** * **
***** *** ** ** print the array */
* ** ** * *** *** * ** ** ** sorting: \n");
*** * * ** ** * *** i = 0; i < size; i++){
** *** ** * **** *** * **** ** *** * ***** ", x[i]); * * * * * ** * * ***** *****
* ** * * * ** *
** * ** ** ** ***** *** * * * ** ** *
* * *** * *
* * ****** * * * ** ***
* ** * ***** ** ***** * * ***** ** * ** *****
* ****** * * * * ** * * * * * **  
* * * ** * * *** * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.28.171
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 8.4k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 4.2k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 7.3k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users