[Exercise 16] Arrays: Bubble-sort

Question

12.1k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64

[Exercise] Coding (C) - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited | 12.1k views

46 Answers

Page:

« prev
1
2
3
4
5
next »

410630017 · Answer 1 · 2017-12-20 14:35:13

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***   **  *****   *****  *  x[] = {77,22,88,11,22};
*** ** *    ***       *  * size = 5;
    
 **   ** ***** *     ****  print the array */
    *      * *   *   *** *     * i = 0; i < size; i++){
*** ****     ****  * *  *  * *****  **  *      *  *****  ******** *  *  ***  ", x[i]);  **** *  **       * **  *  *   * *** 
***** * *  **  **   *   **
 * **  *   **    *** *   ****  ***  ** * *  * * ** *** 
 *****  ** ** ***  * * *   **
**     * *** ********* * *   *  ** I need this to happen size-times */
 *   *** * ** * ** *  ****  *      j = 0; j < size; j++){
    *        * * **  *** **  * **  * **  *****  * * * *   from left to right */
* * ** *    *** ****   ***** ***  *****   * ** ** *   ***   i = 0; i < size-1; i++){
** * ***  ** * *  *    * *   * * *** *  ****    * *  * ** ******* ** **** * ***   *      i-th element with its neighbor to check if they are in order */
  ** *     * **    ***   *  *  **** **** **   ** ** *** ** ** ***      **  *** **  *   ***   > x[i+1]){
    *   ****  ** **** ***        **    *** *   **    * ****** *** ***   *     * * ****  * *  **** ***** * exchange the values of x[i] and x[i+1] */
 * * *** ** *  **   * ***      *** *** ********  * * *   ** * **  * **  ***** ***   *      ** ** *   *  * *   temporary;  *   *** * ****  **  **   **     ** * *  
 **  *** *** ** **      *    *** *   *     *      *    ** ****  *  *** **** **  ** *****   **   * ****     * ***  * = x[i];
   **** **  *** ****   ****** **** *** *   **  *    *   *     * *   *  **   ***  **  **     * * *    *******      * *  = x[i+1];
** ** * *  * ** ** * *     *    ** ** **   * ** **  * **  *    ** *   * **     *** * ** *  *  * *** ** ***  *  ** *  = temporary; 
   *  ** ***    * **   ** ** **   *** ** * **  *      **  * *** *** *  ***   ***   
* *  *  ***    *    *   *  * *  ** **     * **  
 *  * ** * ** *   *
  *     * ***** ***** **** ***
   *   *** *   * ** * *   * print the array */
* ** *** * **  * ** *   ** *  *****  *  * sorting: \n"); 
** ***  * **   ** * **  **  i = 0; i < size; i++){
**  * * *  *  ***** ****   * **   * **** * ***   *** ** **  ** * *   ** ", x[i]); *** ** *** **** ****    **    **  *     
     * ** **    *  *  
** ***  ***  * ****  **   *** **  *  *  *   *******
*   **** *      * ** 
 *      *   * ** *  * *  
 ** * * *  **   *** *   *  *   * * ** *    ** ** ** 
* **  ** *         * **     *   **  *    * ***  **  *    
**    *    ** ** * * *     0;
}