0 like 0 dislike
10.9k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 10.9k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** *** * * ** *** * * x[] = {77,22,88,11,22};
** * * ****** * *** ** size = 5;
    
*** * * * * *** * ** * * * print the array */
**** *** * ** ** * *** i = 0; i < size; i++){
** ** * ** * ** * ** * * ***** * ** *** * * ** * ", x[i]); ** * *** *** ** ** *** **
** * ** * *** * ** **** *
*** **** ** * ******** ** ***
***** **** *** *
** ***** * * ** * **** I need this to happen size-times */
*** * * * ** ** * ** * j = 0; j < size; j++){
* **** * ** * ** **** *** * ***** * ** *** * * * from left to right */
****** * *** ***** * * *** * *** **** ** i = 0; i < size-1; i++){
** * ** ** ** * * *** * ***** ***** *** ***** * * **** ****** * * i-th element with its neighbor to check if they are in order */
** * * *** * * * ** * ***** * ** ***** ** * **** * ****** * *** > x[i+1]){
* ** * * * * **** ** ** * * **** *** * ******* ** * *** ****** * ** * ******* * *** * exchange the values of x[i] and x[i+1] */
** * * * ***** * ** ************** *** * *** ** * ** ** * ** * *** ** * *** * ** **** *** * temporary; * * ** ** * ** * * * ** ** **
* *** ** ** * *** *** *** ****** **** * ** * * *** *** **** * * * * * *** ** ** *** = x[i];
**** * ** * * ***** * * * ** * ** ** * * *** * ** * ** ** * * **** ***** * * * * ** ** = x[i+1];
*** * ** * *** * ** ** *** **** **** * ** * * **** ****** * * * * ** = temporary;
* * ** **** * *** ** ** ** *** * * *** *** *** * *** **
********* * * ** ** ****** * * * ** * * ** * * *
* * ** * ** * *
** ** * * * **** **
* * ***** ** * * * ** * * * print the array */
* ** * *** *** * * * ** * * ** ** sorting: \n");
* * *** ** * ** * * ** ***** i = 0; i < size; i++){
* ** * *** * * * ** * * * ** *** **** * *** **** ** ", x[i]); * * * ** * * * * *** ** *
* * ** * * ** * ** * **
** ** ** * * * ** * * *** * *** * ** *
* *** * ** *
* ** * * * * **
* * * *** * ***** * *** *** * * *** *
* *** * *** * ** *** * ********** * * ** **  
* * ** *** * * ** ***** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * ** ** ** * * ** x[] = {77,22,88,11,22};
**** * * **** ** * * *** size = 5;
    
* * * ** * ** * * * ** ** print the array */
* * ** ** *** *** * i = 0; i < size; i++){
* **** * * ***** ******** ** **** * * ** ** * *** *** ", x[i]); ***** ** * ** * ************* ********
* * * * * * ** * ** ** * *
* ** * ** * * * * * *** * ** ** **** *
**** * ** ** * *
* * * * * * * I need this to happen size-times */
** * ** * ** ** ** j = 0; j < size; j++){
* **** * * * **** ******* *** **** ** * * ** * from left to right */
** * * ** *** *** * *** * * **** ****** ** * * i = 0; i < size-1; i++){
* * * * ** ** ** * **** * ** ** * * * * ** * * *** * * * *** ** i-th element with its neighbor to check if they are in order */
*** * **** * * * ***** * ** ** * * * * * * *** ** * **** ** * ** > x[i+1]){
* **** **** *** ***** ** ** * * ** * ** * * * * * * * * * ** * ** ** ** * ** * * ** * ** exchange the values of x[i] and x[i+1] */
* * ** *** * *** * *** *** * * * * ******** ** **** ** * ***** *** *** * * * temporary; * * **** ***** ***** *** *** * ***
* * * * * * * *** ** *** * *** * ** ** * * * * ** *** * *** * * ** ** * = x[i];
** *** * * * * * ** * * * *** * ** * ** * ** *** ** * * * * ** * * ** * *** * = x[i+1];
* * *** * ** * ** ** * ** **** * * * * * ** * **** * * * * * ** ** **** * * **** * = temporary;
* **** *** * ** * * * ******* ******* * * * * *** *** ** ***
** * **** * * *** * * *** * **** *
* *** * ****** ** * *** *
* *** *** * *
***** ** * * ** ** ** ** * print the array */
** *** * * * * * ** * ** ** sorting: \n");
* * * * * * ** *** i = 0; i < size; i++){
* * * * * * ** * *** ** **** ** * * ** ", x[i]); * * *** * * *** *** * * * *
**** *** ** * * * * ****
* ** ** * *** * * *** * * ** * * * * *** **
* * * * *** ** ** * *
* * * *** *** *
** * * * * ** *** ** * * *** *** ****
** **** * * ** ** ***** * * *** *** ** ** * ** ****  
** ** *** *** ** *** ********* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** * ** ***** ** ** x[] = {77,22,88,11,22};
* * * * * ** ** ** * ** * size = 5;
    
* *** * * * *** * * print the array */
* ** * ** * ** * * * * i = 0; i < size; i++){
** ****** ** * * * * * * **** * * * * **** ** * * ", x[i]); ***** * * ** * ******* ** * ** ****
*** ** ** **** ***** *
* * ** ** ** * **** * * *** *** ** ******
* * ****** *
* * ** * * * * ** I need this to happen size-times */
* * * * * * ** * * j = 0; j < size; j++){
* * * ** * ** **** *** * * * ** *** ** ** from left to right */
* ** ** ** * * * * **** * *** ** * **** i = 0; i < size-1; i++){
** **** ** * ** * * * ** * * * **** ***** * * * * ** * * i-th element with its neighbor to check if they are in order */
** * ** *** * * ***** *** ****** * * *** *** **** * * * * > x[i+1]){
* * * *** *** * * * ** * * * * * * ** ********** **** ****** **** ** * * *** ** ** ** exchange the values of x[i] and x[i+1] */
* ** ** * * ** ** *** * * * ** **** **** * ** * * * * * ** ** * ** *** * * ** * temporary; ** * *** * * * * ** ** **
** * ** * * *** * ** * * * ** ** *** *** **** ** * ** *** ** ***** *** ** ** * * * *** ** = x[i];
** **** * * * * * * ** ** ** * ** ** * * ** * * * ** * ** * * * ***** * * *** ** * = x[i+1];
**** * ** ** * *** ** *** * * ****** ** ** ** * **** **** *** * ** * **** * **** **** *** = temporary;
* ******* * ** *** ** ******* * * ** * * ** ** ***** * *
** ** * ** ** *** **** *** * *** * * **** *
* ** * * ******* * *
* *** ** * * **
** *** ** * * * ** *** * print the array */
******** * * ** * ** * * *** * sorting: \n");
* ***** * * **** * ** i = 0; i < size; i++){
*** * * * ** * * ******** ** * * * *** **** * **** ", x[i]); ** * * * * *** ** * * * * ** ***
** **** * ***** ** *
** ** * *** ** * * * **
**** * * * * * ** *
** ** ** * * ** ** ***
* *** * ** * ** * * *** * ** *
* ***** * * * *** ** ** ** ***** *** * **  
*** ** *** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ****** * * * * *** x[] = {77,22,88,11,22};
** * * *** ** * ******** * * size = 5;
    
* ** * * ***** * ** *** * print the array */
* * *** ** **** * ** * * i = 0; i < size; i++){
* *** ** * * * * *** *** * ** ** * * *** * **** ", x[i]); ******** * * ** *** *** ** ***
* *** * * **** * *
*** * * ** *** ** *** *** *** *** *** ** ***
*** ** * ** ***** **
** ** ********* ** ** ** I need this to happen size-times */
* * * * * * ** ***** ** ** j = 0; j < size; j++){
* ** * * * **** *** ** * *** * **** ** * from left to right */
*** *** ** * * * * **** * ** ** ** ** ** i = 0; i < size-1; i++){
*** * * ** ** * ** * *** ** * **** ***** * * * * ** ** ** * *** * ** i-th element with its neighbor to check if they are in order */
** **** *** * * * *** * * * * ** ** ****** *** ** *** * ** > x[i+1]){
* *** ** * * * ** * * ** * * ** * * **** **** * *** *** ** * *** *** * ** exchange the values of x[i] and x[i+1] */
* ***** * * ** * ** **** * **** ** * * * * **** * * ***** * * ** * * * ** ** * * temporary; *** ** * ** **** ** ***** * * *
*** * * **** ** ** ** * * * ** * ** ** * * * *** * * * * * * ** *** * * * ** * ** = x[i];
* * ** * * ** ** **** ** * * *** * ** ** ** * * * * * ** * ** ** * *** * **** * *** ** = x[i+1];
** * * ** *** * *** *** * ***** ** ** *** ** *** **** * * **** **** ***** = temporary;
**** *** * **** *** * ** * * * * * * * ***** * ** * ** **
*** * ****** * **** **** ** * * ** * * **
** * * *** * * *** ** *
** **** ** * ** ** *** ***
** *** * * ** *** print the array */
** * * *** * ****** * ** * * ***** sorting: \n");
** ** * * *** *** * * i = 0; i < size; i++){
* ********** * ** ** *** * ** **** ** * ", x[i]); *** * * ** ****** * * * * * ***
** ****** ** * * **
* **** ** ***** ***** * * * * ** ** ** **
* * ******** * ** * ****
**** ** * ** * *** *
* ** * *** ** ** * * *** * * *** * ** *
**** * * * * * * ** * * * * * * * *** * ** **  
** ** * * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ******* ** * * * **** x[] = {77,22,88,11,22};
* * * *** * * size = 5;
    
** * * * ** * * * * print the array */
*** * * ***** * ***** * ***** i = 0; i < size; i++){
** * * * * ** * ** ***** ** ***** ** ** *** ", x[i]); * ** * * ** * **** * * **** * **
** * ** * * * ***** * *
** * * ** ** * *** ****** *** *
* *** ** *** * *****
** ** * *** ** ** * * *** ** I need this to happen size-times */
* * ****** *** * * ** j = 0; j < size; j++){
**** * * **** * * **** ** ** ** ** ** * from left to right */
** ** **** **** ****** * **** *** ******* * * **** i = 0; i < size-1; i++){
* * ***** *** ** ******** ** ** * * * * **** * *** ***** * ********* *** * i-th element with its neighbor to check if they are in order */
**** * * * *** ** ** * ** ** * * ** ** ***** **** *** * > x[i+1]){
* ** * * * * ** **** * ** ** * ** * * *** ** * * ** ***** ******* ** * * * * *** exchange the values of x[i] and x[i+1] */
* ** * *** * ** *** * * * * * ** * ** * ***** *** * ** *** ** ** ** * *** * ** temporary; ****** * ** * **** * ******* * **
**** ** ** * ****** ** * * * ** **** ***** * * ** * *** * ** * * * * * * * ** *** *** = x[i];
*** * * **** * * **** * ********* ** **** * * * **** ***** * * **** * ** * * * ** *** * = x[i+1];
* * **** **** ** ** ** * * *** ** * * * ** ***** ** * ** ** ** ** ***** ** **** * **** * = temporary;
*** * ***** * * ** * * * * **** * ***** ** ** *** ***** * *** * ** *
***** * *** * *** * ********* * *****
* *** * * ****** * * * ***
** ** * *****
* * * * * *** *** *** print the array */
** * *** ** * **** * ****** ** * ** sorting: \n");
** *** * * ** **** ** * ** i = 0; i < size; i++){
* * **** ***** ** ** * * ** * * * * ** ** ** **** ", x[i]); ** *** ** * * *** * * **** * **
* * * * *** *** *
* * * ** * * * **** **** **
* ** * * * * **** * ******
* ** ** *** *** **
** * * * ** * ** *** ** * ** * *** **
* **** *** *** * ******* * ***** * ***  
*** * * * ** *** ** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * **** *** **** * x[] = {77,22,88,11,22};
* ** ** * *** * * ** * ** * * size = 5;
    
**** * ** * *** * *** * * print the array */
** * *** ** **** * i = 0; i < size; i++){
* *** ** ** ** *** * * *** ****** * ** *** * ** * ", x[i]); * ***** * * * * * ** **** * *
** * *** ******
** * ** ** * * * ** ***** *****
* ** * ** * **** *** **** *
* **** * * ** *** ** * **** I need this to happen size-times */
* **** * *** * ** ** ** ** * * j = 0; j < size; j++){
*** *** ** * * * * * ** ** ** ** * * *** from left to right */
*** * * ** *** ** ** * * ***** ** * ** i = 0; i < size-1; i++){
** * ** * ** * * *** * *** * *** * * * * * * * * *** ** * i-th element with its neighbor to check if they are in order */
** * * ** *** * ** *** *** **** * *** *** ** * * * *** *** * * > x[i+1]){
**** ** * ** *** * * * *** * * ** * ** *** * ** *** * * *** * * *** * exchange the values of x[i] and x[i+1] */
* ** ** ** * ** * * * * * ** * ** * * ** * ** ** *** **** ***** * * **** ** * * temporary; *** * **** * * * * ** ***
**** **** * * * * * **** * ** * * * *** * ** ** ** * * * *** * * ***** ** ** * * * = x[i];
* * * **** *** *** ** ** * * * * ** ** ** * ** * ***** * * *** * *** * * *** * ** ** = x[i+1];
** ** * * * ** * ** ** * ** **** * * ** * * *** * ****** * * * ******** * ** *** = temporary;
* ** * * *** * * **** * ** * ** * ****** * * ** * *** * *
* * *** ** ******** ** **** * * * * * *** ***
* * * ** ** **
** * ** * *********
* ** ** ***** print the array */
****** * * * **** ** * * * * ** sorting: \n");
*** * * *** * * * * *** ******* i = 0; i < size; i++){
**** * * * ** ** * * **** ** ***** * ***** * ** ****** ", x[i]); ** * * * ****** *** * **
** * ** * ** * *
* *** **** * **** * * * *** *****
*** ** * ** *** ***
** *** * **** * *
* * ** * * * ****** ** ****** * * **
* ** ***** ** * **** * *** * *** * * *** *  
** * **** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** * ** ** * ** x[] = {77,22,88,11,22};
* *** * ** ** * size = 5;
    
** ** * * * print the array */
**** * * * * * ** *** * ** * i = 0; i < size; i++){
* * ** ** ** * * * * * * ** * **** ** * ** ** ", x[i]); *** ******* * ** ***** ** ****
* *** * *** * *
** *** * ** *** ** * * * * * ****
** ** * ****** * ****
* *** * ** ***** ** I need this to happen size-times */
* **** **** ** ***** * ** j = 0; j < size; j++){
*** * *** ** *** * ** * * * * * ***** * * ** ** from left to right */
* * * * ** * **** * **** ** * ** * * *** * **** i = 0; i < size-1; i++){
* ** *** * * * * * * **** *** * * * ****** **** *** * * ** ****** ** * *** i-th element with its neighbor to check if they are in order */
*** * * ** * * ** * * * ** * **** **** ** ** * * * * * * * * ** * > x[i+1]){
******* ** ** ** * *** * *** * ****** * *** *** * ** * * *** ** * ** ** ** ** * * exchange the values of x[i] and x[i+1] */
* * ***** * * ** ** * * * * *** *** * **** * ** * ** * * * ** ** * * *** ** ***** temporary; ** ** * ** * ** * ** ** **
*** * *** * *** * * * ** * * ****** ** * ** * ** ** * * ** * * * ** ** * * * = x[i];
* * **** * * **** * ** * * * * **** *** * ******* **** * * * ** **** * * ***** * = x[i+1];
** *** ** * ** * * *** **** **** *** * * ** * * * ***** * * * * ** * ** * * * ** ** = temporary;
*** *** ****** * * * ** *** ****** ** ****** *** * * ***** *
*** *** * *** * * * *** * ****
* * * * *** *** * *
* *** * ** * ***** ** **
* ** ****** * ****** * ***** print the array */
*** * * *** ** * * ***** ** ** * sorting: \n");
* **** *** * * ** * * * i = 0; i < size; i++){
** * * *** * * ** *** ** * * **** * * ******* * * * *** ", x[i]); * ** ** * **** **** **** **** ** ***** *
* * ** ** **** *** ***
** *** ** * ** * * * ** * ** * * *** *
***** *** ** ** * *
** ** * * * * ** *****
* * *** * ** * *** * * ** **
***** ***** * * * ** ** **** ** ** * * *** * * * ***  
**** ** * * * * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * ** *** * ** ** x[] = {77,22,88,11,22};
*** * * *** * ** ** *** * size = 5;
    
*** * * * * ** * ** ** * print the array */
* * * ** ** ** * ** ** * ** i = 0; i < size; i++){
* * * * ** ** * ** * ** *** * ***** ** * * * * * * * ** ", x[i]); ** * * * *** * ***** * * * **
* *** * ** *** * ****
* ***** * ******* ***** * * ** * * * ****
* *** ***** **** * *
* * ** * *** ** **** *** I need this to happen size-times */
* * ** * * * ** *** * j = 0; j < size; j++){
* * ***** * * * ** ** *** * ** * * * * ** from left to right */
** **** * **** ** * *** * * *** * * ******* i = 0; i < size-1; i++){
**** * * * * *** * ** *** *** ** * ** * * * * * ** *** *** * *** * * * i-th element with its neighbor to check if they are in order */
** * * * * * ** * ******** * * ** * *** **** * * *** ** * *** > x[i+1]){
* **** * ** * ** * * * ** ** * * * * ** * * ***** * ** * **** ** * * * *** ** ******** *** * * exchange the values of x[i] and x[i+1] */
*** * * ** **** **** *** *** **** *** *** ** * ****** ** * ** * * *** ********* ** * ** temporary; *** **** * * ** * ** * *** * **
****** ** ** ** *** ** * * * * * * ** * *** * **** ** ** * ******* * *** *** **** ******** *** = x[i];
* ** * **** * ** * * **** * ** * ** ** ** *** ** * * * ** * * * * **** *** **** = x[i+1];
* * * * * * * ** ******** **** * * * * ** * * ** *** *** * * * * ** = temporary;
** *** * *** ** **** * * ** **** * * ** *** * * *
* * **** ***** *** **** * ** *** **
*** * * * * **** * *
*** ** ** ****** *
*** * * ** ** * *** print the array */
** * ** ***** * ***** * * * *** sorting: \n");
* ** * ** * **** * *** i = 0; i < size; i++){
* ** ** * ** ***** ** ******** * * *** *** * * ** * ", x[i]); *** * ** * * * * ** * * *** * *****
* *** * ** * * ********
** *** * ***** * * ** ** *
* ** * *** *** * *
* **** * * * *
* * * * ** * * *** * * ** * *** ** *
** ** ** * * *** * *** ***** ** **** **** * * *  
* ** * * *** * * **** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** ***** ** * * * x[] = {77,22,88,11,22};
* * * *** * * ** * size = 5;
    
* * ** * * * ****** * print the array */
* * * ** * *** ** ** i = 0; i < size; i++){
* * * ***** * * **** * *** ** * * *** * * * *** * * * ", x[i]); ** ** ** ******* **** * * *** *
* ***** ** * * ** ** **
*** ** * * ***** ** * ** ** * *** **** *
**** *** * * ** * * *
* * ******* ** * ** * * * I need this to happen size-times */
** * * ** * * * * ** j = 0; j < size; j++){
*** * * * *** *** *** * ** * ** * from left to right */
***** * ** * *** *** ** * * *** ** ** i = 0; i < size-1; i++){
* ** ** ** * * *** * * * * * ** **** ** * ** * *** * ** ***** * * * i-th element with its neighbor to check if they are in order */
* * * ** * * * * * ** ** * ** * **** **** ****** * * * *** *** ***** > x[i+1]){
* ** ** **** * * * * ** * ******* ** **** * ******** **** ** * ** * * * ****** * ** exchange the values of x[i] and x[i+1] */
* **** ** ** * ** * **** * *** * * ** * * * * ** * ** * * ** ** ** ** ** temporary; ** * * * ** ** * **
* ****** * **** ** **** *** ** ** * *** ** ** * **** * * ***** *** * * * * * ******* * * = x[i];
* ** ** *** * * * *** *** *** **** * *** *** *** ** * *** * * ** * * * * * * ** * = x[i+1];
***** * * *** ** * ** ** * * * ** ***** * ** * * * * * * * **** ** ** * **** ** * = temporary;
* ** ** *** * * ** ***** * ***** * **** *** ** * * * * * * ****
** *** ** ***** * ** *** ** *** * * * ** *
* * ** ** ** ** *
* * ** ** * ***
** * * * ** ** * * print the array */
* ******** *** ** * **** * ** *** sorting: \n");
***** * * * * * * * * * ** * ** * i = 0; i < size; i++){
** * * ** *** * * * * * * * ** * * * *** ** **** * ** ", x[i]); * *** * * *** ** * **** * ********
** **** * *** * ** ***
* ** * * ** ** *** * ** *** * ** * **
** * * ** ** * * * **
**** *** ** * **** *
* * ** * * *** * * ** * ** ** ** * **
* * * * * **** ** *** *** ** * ** ***  
** **** * * ** * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** ** ***** ******** * x[] = {77,22,88,11,22};
******** ****** * ** ** * size = 5;
    
* *** * * * ** * * print the array */
** ** **** * *** ** * * * * i = 0; i < size; i++){
* ** * ** *** * * *** ** * * *** ** ** * **** ", x[i]); * * *** ** **** * * * * ** ***
*** ** *** * **
******* * ** ** * *** *** * * * *
* * * * **** ** * * *
** * **** ** ** * * ** ** I need this to happen size-times */
*** * *** **** **** ** j = 0; j < size; j++){
** **** * * * * ** * * *** ** * * * * * *** * from left to right */
* * ** * * * * * * *** * ** * * * * * ** * i = 0; i < size-1; i++){
*** * ** ******* * ***** ** * ** ** * ** * ** **** ** *** * **** ** i-th element with its neighbor to check if they are in order */
*** * * *** ** * * *** ** * ** * * **** *** ** ** * * * *** ****** > x[i+1]){
**** * * * ******** ** * * * * *** *** * * * ** ** * *** ** **** ***** * ** exchange the values of x[i] and x[i+1] */
* **** **** ** * * ** * *** **** * * ** *** * * * * * * * *** ** ******** ** * ** * temporary; ** ** * * * ** *** ** ** ** ** * *
* *** **** *** * * * ** * * * * ** *** * *** *** *** * * ***** * ***** * * * *** ** * * = x[i];
* * **** ** **** * ***** * * * * ** * ***** * ** ***** * * * *** * * *** * ** = x[i+1];
* *** ** ** * ** * * ** ** * * * ** *** *** *** * ** * ** * ***** ***** ** ** = temporary;
**** * ** *** ** * * * * * * ** * ******* * * * * * *** * * ****
*** * ** * * * ****** * * *** ** ********* **
*** *** * * ********** **
**** ** * * * * ***
* * * * * * ** * print the array */
* ** ***** * * * ** ** *** ** *** sorting: \n");
* * ** * * ** *** **** i = 0; i < size; i++){
** *** * *** * ** * ** ****** * ***** * * ****** ", x[i]); *** * ** ** * * ** ** *
* * ** * * * ** * *
** * *** **** * * ** ** ** ** * ****** * *
* ** ** * * *** *
*** ***** **** ***** **** * *
** *** **** * * ** * ***** ***** * ** *
* * ** * ** ***** * *** *** *** * ** *  
*** * ** * * * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.217
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.9k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users