0 like 0 dislike
12.9k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 12.9k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** * *** * x[] = {77,22,88,11,22};
** ** *** * * *** *** size = 5;
    
*** *** * * *** * * * * print the array */
* * *** * ** ** **** *** ** i = 0; i < size; i++){
* * * *** * * ** ** *** ** *** * *** ** *** ** ", x[i]); * ** ** * ** ***** ** * *** *** *
*** * * * * * * ****** **
* *** ** ** ** * ** ** * * * ** * **
* * * ** ** ** ** * *
* ** ** ** ** * ******** * * I need this to happen size-times */
* ** *** ** ** *** * j = 0; j < size; j++){
* ** * * *** * * ** *** * * ** * *** from left to right */
* *********** * * ** * *** ***** *** * * i = 0; i < size-1; i++){
** ** ** ** ** *** **** ** * * * *** ** * *** ****** * ** *** *** * *** * i-th element with its neighbor to check if they are in order */
* * * * * * * *** ** ** ** * ** ******* * * **** * ** *** > x[i+1]){
*** ****** *** * ** *** ** * ** ** *** * ** ** ** ** * *** * *** * * ** * * ** exchange the values of x[i] and x[i+1] */
*** *** * * ***** * * ** **** ** **** *** * * * ** * * *** ** ***** * *** * ** * * ****** temporary; * *** ** * ******** **
* *** * ** ** * ** * ****** * * *** * ** ****** ** *** ** ** * * ** ** * **** * * * ** * * = x[i];
* ** ** * * * * * * ** * ** **** **** ** ** *** ***** * * * * * * ** ** * * ** = x[i+1];
** * *** *** * * **** * *** * * * * ***** ** ** * * *** * * *** * **** *** = temporary;
** **** ** * *** ** ******** *** ** ** * ** ** *
* ** * * ** * * ** * ** * ***** ** * *** * **
**** ** *** ******** **
* * *** ****** *
*** * * * *** ** print the array */
** * * ** * ** ** *** * ** ** ** sorting: \n");
* * *** * ** * * ** ** * i = 0; i < size; i++){
* * * ** * ** ** * * ** * * *** * * * ** *** * ** ** ", x[i]); ** ** ** * *** * **** ** * * **
* * ** * ** *******
* ******* * * * * * *** * * * ** **
* * ** * ** ** ****
* * * * * ** * **
** ** * * * * ** *** ** * * *
* * * ** * ** * * * **** * ** ** ****  
** **** * * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** *** ** * ** * * * * x[] = {77,22,88,11,22};
* ***** * * * * ***** size = 5;
    
* ** ** * * * * *** *** print the array */
** * * * ** *** ***** * i = 0; i < size; i++){
** ***** * **** *** * **** * **** * **** * * * * * * ", x[i]); * * * * ** * * ** * * ****
**** * ** ** **
** * ** ** * ** * *** *** * ** *
* * * *** ** ***** *
*** **** * ** ** * * * I need this to happen size-times */
** ** *** * ** ** ** j = 0; j < size; j++){
*** *** * ******** ** * * ** **** ** from left to right */
* * ** ********* **** *** * * * ** i = 0; i < size-1; i++){
** ** * ***** * * *** * **** * * * ***** *** * * * ** ** * **** ** i-th element with its neighbor to check if they are in order */
* ** *** * *** ** ** * * * * * ** * * ** ** *** ***** **** *** * ** * * * * > x[i+1]){
*** *** ** ** *** * ** * * **** **** *** * ** *** ** * ****** ** ** ** * ** * ** * ***** *** * * exchange the values of x[i] and x[i+1] */
* * **** * * * * ****** * ** * *** ** ** * * * * *** * * * * * * * * * **** * * ****** * temporary; * *** ***** ****** * * **** * ****
* ** * * * *** ** *** **** *** * *** * ***** ** * ** * **** **** ****** * *** **** * * ** ** * * = x[i];
* * **** * **** * ********** *** * **** ** *** * * ***** ** ***** * ** ** * * ** * * * = x[i+1];
* * * * * * * * ** **** ** * * * * * * * ** ** ** ** **** **** ** * * * *** = temporary;
** ** *** * * * ** ** ** * ** * ** *** ****** *** * * *** * *
** **** *** * * * *** * ***** ** * ** * * ***
* **** ** **** * * ** *
******* * *** *
* *** * * * * * ** print the array */
* * ****** * ** ** ** *** * ** sorting: \n");
* * * * ***** * * *** i = 0; i < size; i++){
*** * * ** *** * * ** * * * ** ** ** ***** ** ** ** ", x[i]); * * * * * ******** *** ***** * *
**** ** * **
*** * * * * * **** * * **** ** ***
* * * * * ** *** *
* * * **** * **
* ** **** * * * * * * ** * * *
** * * **** ** * *** * * ** *  
*** *** * ** * ** * *** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * ** * ******* * x[] = {77,22,88,11,22};
* ** *** * * * ********** size = 5;
    
*** **** * ** * * ** print the array */
***** * **** *** * *** i = 0; i < size; i++){
* * * * * * * * ** * * * ** * ** * * ** * ** ** ** ", x[i]); * ***** *** * ** * *** ** * * *
** * * * *** * *
* ***** * ** * * *** **** ** ***
* * * *** * ** * ***
** *** **** * ** *** * *** I need this to happen size-times */
* ** * ** *** * **** * * j = 0; j < size; j++){
** ** * * * * * *** *** * * *** ****** ** from left to right */
* * *** **** ** * * * * *** *** *** ** ** ** ***** i = 0; i < size-1; i++){
***** * * * ** * *** * ** *** ** ** * ** * * * * *** * i-th element with its neighbor to check if they are in order */
** * * * **** * ** * ** * * * ** ****** * * **** > x[i+1]){
* ** ** *** ** ** *** * * * * **** * * *** *** * ****** * ** *** * * ** ** *** * ***** exchange the values of x[i] and x[i+1] */
* * * *** * *** ** * * * ** **** * * *** * *** * * ** ** * * ** *** * * ** *** **** temporary; * * *** *** * *** ***** **
* * ** * ** * ** * * ** ** * ****** ** ** * ***** *** ** *** ** ** ***** *** *** * = x[i];
* *** *** * * *** * ** ** ** * ***** * * ** *** ** **** *** ** * * * * * **** ******* ** = x[i+1];
* ** * * ** * *** **** * * * ** * * * *** **** *** ** * * * * * * ** ** * * * **** = temporary;
* * *** * *** ** * * * ** ** * *** * * *** * ** ** ** * *
* * * * ***** *** * * * * * *** *** **** **
* * *** ** * ** *
*** ***** ** * *
*** * * * * ** *** print the array */
* ** * * * ** ***** * * ** * ** sorting: \n");
**** *** ** * * i = 0; i < size; i++){
**** * * *** ** * ** ******** * * * ** *** *** * *** ** * * * ", x[i]); * * * **** *** * * * * ** * *
*** * ***** ** ** ** * * * *
* * * * * * ******** * * * * **
*** **** ***** * *
** * * * * **** * *
* ** ** * * ** ** ** * * ** * ********
* * * * * ** * **** * ** * * ** **** *  
* ** ****** * * ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * * ***** x[] = {77,22,88,11,22};
** * *** ***** *** * * * size = 5;
    
* ** *** ** * * ** print the array */
** * ** * ******* i = 0; i < size; i++){
*** * ** * ******* * ****** * ** ** * * *** ****** ", x[i]); * ** ****** * ** * * ** *****
*** ** ** ** * * ** * **
** * * **** * *** * ** **** * * *
* ** **** * ******
** * * * ***** * * * I need this to happen size-times */
* *** *** ** ***** ** * j = 0; j < size; j++){
* ** * * * * * **** * * * * *** **** * *** ** from left to right */
**** ** **** ** * * * **** * * * ** * * *** *** * i = 0; i < size-1; i++){
*** * ** *** * ** ** * ***** ** * * * **** ** * ****** * * ** i-th element with its neighbor to check if they are in order */
* ** ** ** ** ** ** * * ** * ** * *** * * ** * * ** > x[i+1]){
* **** * ** * * * ****** * * * * * * ** ** ***** * **** * * * **** * *** *** ** *** * exchange the values of x[i] and x[i+1] */
** *** ** ** **** ** ** * * * **** * ** ******* * ******* ** *** * * * * * ** * ***** * temporary; * ** * ** * ******** * * * **
*** ***** * * * ****** * ** *** ** * * * **** ** ****** * * ** ** * * ** * *** * * *** = x[i];
* * * * * * * **** * * ** * * ** ** *** **** * ** * * *** ** ** ** * ** * ** * *** = x[i+1];
** ** *** * **** * * ******* * *** *** ** * ** * *** * ** **** * * * *** * = temporary;
* ** * * ** * * ** **** * * * * * *** ** *** * *
* *** ***** * * * * ** * * *** ** ** * **** *
** ** *** ** ****** ** * *
** ** **** *** * *** *
* *** * * ** **** ** * **** print the array */
* *** *** ** * ***** * * ** * sorting: \n");
*** ** ** ** * * * ** * i = 0; i < size; i++){
* *** *** ** * ****** * * * * ** ** * *** *** * ", x[i]); *** * * * ** * * *** ** * ** * ******
* * * * *****
***** * ** **** **
** *** * * *** * ** ** *** *
**** * ** ** ** *
* *** * ** * * ** ****** * ****
* * *** * ** * * * * * * ***** * ** * * *** *  
* **** * ** * * * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * * * * ** x[] = {77,22,88,11,22};
* ** * * * * * size = 5;
    
* * *** *** *** print the array */
* * ** ** * ** ** * * i = 0; i < size; i++){
* * * * * *** * ** *** * * *** ** **** * ***** ", x[i]); * ** * * ***** ** ** * * * **
** * * * ******* *
***** ** * * * ** *** * ****** ** * *
* ** * * * **** ***
** * * * ** ** * I need this to happen size-times */
* * * * ****** *** ** j = 0; j < size; j++){
*** *** * **** * * * * ** * * ** ** * * * from left to right */
** *** * * ***** ** * *** * **** **** * * i = 0; i < size-1; i++){
*** * ** ** * * * * * ** * * * ** * * ** * ** *** *** * **** i-th element with its neighbor to check if they are in order */
* * * *** ******* * ** ***** ** * *** **** **** * ** * ****** ** > x[i+1]){
** * * **** ***** ******** * * * ** * * * ***** * * * ** **** * *** * * *** ** * *** * ***** exchange the values of x[i] and x[i+1] */
** *** *** *** *** * **** *** * * * *** * * * * * ** ** *** ** * * * * * * * * * * temporary; * * ********* * * * *** *
*** * ** * * * ******** ** * * ***** ** *** ***** ** ** ** *** * ** * *** ** * * * * *** ** * = x[i];
*** ** *** * * * * * ** ** **** * * **** * ** * *** ** * ** * * * * * ** ** * * * * ** *** = x[i+1];
* *** *** ** ** *** ** *** ** * ********* * * ** ** * ** ** * ** **** = temporary;
* *** * * ** * * *** ** *** ** * * ** ** *** * * * * * ***** *
** * * * * ** * ****** ** * ***** * * * **
* * *** ** **
**** * *** *** *
** ** ** **** ** print the array */
* ** * * ** **** * ** sorting: \n");
* * ***** * ** * ** *** i = 0; i < size; i++){
* * ** *** ***** **** * *** * ** * * * * * * ** * ** ** ", x[i]); * ******* * * *** * ** * * * *
** * ******** * * ** ****
* * * * * * * *** * * * * * *
*** * * * * ****
** *** **** * * *****
** * ** *** *** *** ** ** * ** * ** **** *
** ***** ** * ** **** **** ** ****  
* ** * * * * * * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * **** ** * * x[] = {77,22,88,11,22};
* * * * ** ***** * * * size = 5;
    
* * ** * **** ** *** print the array */
* * ** ** * ** * * ** i = 0; i < size; i++){
**** **** * * * *** * ************* *** ** ** ", x[i]); * ** * * * * ** ** ***** ** *
** * ** * ** ** * ***** ** **
*** * * ***** *** * * *** * ***
* ***** **** * ** *** *
** ** * * *** * ** ** I need this to happen size-times */
* * * *** * ** ** * ** j = 0; j < size; j++){
* *** * * ** * ** ** ******* * * ** * from left to right */
* * * ** ** * ** * * *** *** * * * * * ** ** * i = 0; i < size-1; i++){
** ***** * * ** ** * * * * ** * ** * ** ** *** * * *** * ***** i-th element with its neighbor to check if they are in order */
** * *** * * ** * * * * ** * *** * ** * ** *** * ** ******* * * * * > x[i+1]){
*** * * * ** ** * ** * * ** ** * * ***** ** *** * * ** * * *** * *** * * **** * * *** * exchange the values of x[i] and x[i+1] */
* * * * * *** * *** *** * ** * ** ** ** * *** *** ** ** * ** * ** * *** * **** ** * * temporary; *** * ** ** * ** * *** ** ** *
** * * ** * ****** *** ** ** * ** * * * * **** * ** * * *** *** * ** ** * * ** *** ** = x[i];
** * * * * *** ** ** * * ** ** * ** * * ** ** * ** * * * **** * * * ** * = x[i+1];
* * * ** * **** **** * * ** ***** * *** *** * *** ****** ** * * * = temporary;
** * * ** * * * * ** ** * ***** *** *** * * * ** ***** * * *** * * **
**** * ** ** ** * *** * ** * ** ** *
* * * ** ** ** **** *
* ** *** * ** **** ** **
* * * * * ** ** **** *** ** print the array */
* ***** * ***** **** * * ** * * * sorting: \n");
* **** ** * **** *** * i = 0; i < size; i++){
* * ** ** * ** * * *** * **** * *** * **** *** **** * ", x[i]); * * * *** *** * * * **
** * * * * * *** *
** * ***** * ** * ** * * ** * * ** ** **
* * * * *** * ******
* ** * ** ** *
** *** *** *** * * *** * * *** * **
**** * *** ** * *** * *** * ** *  
* * *** * * * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ***** *** ** ******** *** x[] = {77,22,88,11,22};
* *** **** * * * **** size = 5;
    
* **** * * ** * * * * print the array */
*** **** ** * *** * ** i = 0; i < size; i++){
*** * * ** **** * **** * * ** * * * *** ** * * **** ", x[i]); * * * * ** ** * ***** * * * *
* ** * * ** **** * * * *
*** * ** ** *** ** * * ** ** ** * * ***
* * *** *** * ****
** *** * * ** * *** * * I need this to happen size-times */
***** ** ** ** ** * *** **** j = 0; j < size; j++){
** ** ** * ** * *** * * * ** * * ** * ** * * from left to right */
* * ******** * ** * * ********* * * i = 0; i < size-1; i++){
***** ** *** * ** ** * ** * * * * * * * **** *** * * * ** i-th element with its neighbor to check if they are in order */
* ** * ***** ** * *** *** * * * *** *** * ** ** * ****** * > x[i+1]){
* *** **** **** * * ** **** * * * * * * ** *** *** * * * * ** * * * * * ******* * ** * **** exchange the values of x[i] and x[i+1] */
* *** ** * * *** * * * ** * ****** * * *** **** * * * ** * * * *** * *** * temporary; * *** ***** * * *** ** ** ***
* **** * * * * **** *** * *** ** * *** * * * * * ** *** ****** **** * ****** ** ** ******* = x[i];
* * * *** * ******** *** * * ** ** * **** * ** ** * ***** ** * * ** = x[i+1];
** *** * * ** * **** ** ** **** * **** * * * ** * * *** * * * * ** ** * ** ** * **** **** * = temporary;
* * * * * ** * * ** * * * *** * * ** * ***** * * ** ***
* * ***** * *** * ***** *** ** **** * ** ***
* * * * *** *
* * *** * ** ** * ** *
** * * * ** ** * * print the array */
*** * * * *** ** * * * * * * ** sorting: \n");
** ** * * ** * **** i = 0; i < size; i++){
***** * ** * * ** * ** * *** ****** * *** ** ** *** * * ", x[i]); * * *** ***** * * **** * ** **
**** ** * * ** **
**** * ***** ** **** * ** **
* * * ** * * *
*** *** ** ** * * *** ** *
* ** ******* ** **** * **** * * * ** ****
* * *** * ** ***** *** *** **** * * ** ** ** *  
** ** * * ***** * * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** *** * * * ** * x[] = {77,22,88,11,22};
* * * * ***** * *** ** size = 5;
    
* ** * ** ** * print the array */
***** ** * *** * **** i = 0; i < size; i++){
*** * * ** * * ** * * **** *** * ** ** **** * * ", x[i]); ** * ****** *** ** *** * * * *
** **** * ** * *
* * *** * *** **** ****** * * ***
* * * * *** *
*** ** * * * ** ** *** I need this to happen size-times */
* ****** *** **** * j = 0; j < size; j++){
** * * ** *** * ** ** * **** * * * * **** from left to right */
** * **** * * ** ** * * * **** * *** * ***** i = 0; i < size-1; i++){
* * * ****** ** * ** * * * * ** * * ** * * * * * **** * * ***** * * ** * i-th element with its neighbor to check if they are in order */
* * ** ** *** ** ***** ** * * * ***** ** **** * * **** * *** ** * * * * > x[i+1]){
** * *** * ****** *** **** ** *** ** * ** * **** **** * ** *** ** ******* * * * exchange the values of x[i] and x[i+1] */
** * ** * * ******** * ** * * ** * * ** * ** *** * * * ** * * *** ** * ** * * * * temporary; * * * **** ** **** * * **** **
*** ******* * *** * * * ** *** ** ***** * ** *** ** * ** * *** ** * * *** **** = x[i];
** * ** * * * *** **** * * * * * * *** **** ** ** * ** * **** * ** **** **** * ** *** * = x[i+1];
* * * * ***** ** ** * * * * ** ********** * ** * * * * * ** ** * * * * * * ** **** = temporary;
* * ** * **** * ** *** *** * * ** * ******** * *****
** * * *** * ** *** ** ** * ** ** *********
** * **** * ********
** ******* *** * *
* * * * *** * ** *** print the array */
* ** * * * ** * * *** * * * sorting: \n");
* * ** ** ** * *** *** * * *** * i = 0; i < size; i++){
* ** ** * * * * * * * * * ** * * * ** * * ", x[i]); * * *** ** * * *** * **
* *** * *** * * *** ** * **
** *** * *** * * **** * ** * **
* **** ***** * * *** **
** * *** ** ******* *
*** ** * * ******** * * ****** * * *****
* *** **** * *** * ** * ***** * * * * **** * *  
** ** ******* * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** * * * ** * x[] = {77,22,88,11,22};
** * * * * ** ** **** size = 5;
    
* * * **** * ** * * print the array */
** * ** *** * ** *** ** i = 0; i < size; i++){
*** * * * *** **** * * * ***** *** * *** * * **** * ** ", x[i]); *** ** * * ** * * ** * * *
* * ** * * * *
***** * ***** * * * ** * * * *** ******
* ***** * * **** ** *
** ** *** * ** **** *** I need this to happen size-times */
*** *** **** ****** * * * * j = 0; j < size; j++){
** * * * ** *** ***** * * ** ****** * from left to right */
**** ******** * ** * *** ** * * ** ******** * i = 0; i < size-1; i++){
** ** ****** * * * * *** ** * *** ******* ** * ** ** ****** * * ** * i-th element with its neighbor to check if they are in order */
* * ** * *** ** * ***** *** ** *** ** **** * ** ** *** ** * ** > x[i+1]){
** * ** ** * ****** ** * *** ** * * ** * *** * * * * * ** * ** * * * *** *** ** exchange the values of x[i] and x[i+1] */
* * * * *** * * * ** ** ** * * ******* * * ** **** ** * * *** **** ** * ** *** temporary; ** ** ********** **** * **** *** *
* * * **** ** *** ** * ***** * ***** *** * * * * * ***** * * ** **** * * * ******** * ** = x[i];
**** * *** * *** * ** *** * *** *** * *** ** * ** *** * * * * * **** * * * * ** ** = x[i+1];
** * * ** *** * ** * ** * * * ** ** **** * * ** * *** * ********** **** * * *** ** * * = temporary;
* ** * * * * ** * * * *** * *** ** * ** *** **** * * * * * ***
* *** * *** *** ** ** ** **** * * ** ** **** * **
* * *** * * ***** * *** *
* * * * *** *** *** *
* ** ****** *** ** * print the array */
** * *** **** * ** * * *** * sorting: \n");
** ** * * * * * * **** i = 0; i < size; i++){
* * ** ** * ** ** * * ** ** ** * ** ** **** ", x[i]); * * * **** * * * ***** ****** * **
* **** * * * ** ***** *
* * ** * ** * * **** ** ** * *****
** *** ***** * *
**** **** ** *** **
* * ** ** * * * ** ** ** * * * * **** * * *
* * * * *** ** * ** * ** **** * * ** ***  
* ** * ** * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * *** * * * x[] = {77,22,88,11,22};
* ***** * *** * * ** * size = 5;
    
*** ******* * ** * * print the array */
** * ******* ** * ** * * i = 0; i < size; i++){
* * * * * * * ** ** ** * * * ** *** *** * * * * ****** ** * ", x[i]); ** *** ***** ** * ** *** * * ***
* ** *** ** ** *
* * * ** **** ***** * * * * * *** **** *
* ** * * ** ** *
* ***** * * * *** * * I need this to happen size-times */
** *** * *** * * * ** j = 0; j < size; j++){
*** * *** * ** ** * *** * *** * ** * * * from left to right */
**** ***** * * ** * **** * * * **** *** *** ****** i = 0; i < size-1; i++){
*** * *** ** ** * * ** ** ** * * ****** *** * *** * ** ***** ** ** * **** i-th element with its neighbor to check if they are in order */
* * ** **** *** ** * * ***** ** **** * * * * * **** ** * * * *** > x[i+1]){
* *** * ** *** * ** ** ** *** * **** ***** ***** * * * ******** ** * * * * *** ** *** * * exchange the values of x[i] and x[i+1] */
** *** ** * * * * * *** ** * *** * * ** ** * ** * * ** *** *** *** *** * * * *** temporary; **** * *** ** * * **** **** ** ** *
***** * * ** * * * * **** * * * * ** * **** * * * ** * * ** * * *** * = x[i];
* * * ****** ***** **** *** * * ** * * ** ** **** ** *** * * ** * *** * * ** ** * *** = x[i+1];
* *** *** * * * ***** ** * * *** ***** * * *** * * ****** ******* ** * ** * * * *** ** = temporary;
**** * * * * * * * **** ** ** * * ** * ** * ****
* ** ** *** ** **** ** *** * * * *
** *** **** * **
***** * * * *** * ** *
* **** * ** ** print the array */
* * * * ** * *** *** ** * * * sorting: \n");
* ** ** * **** *** **** * i = 0; i < size; i++){
* * ** ***** * ** * * * * * * ** ***** *** ** * * ", x[i]); * ** **** **** * * ****** *
****** * *** ** ** * * *
* *** ** * * * *** ** **** ** ** *
* * * ** * ** ** *
** ** * * * *** **
*** * ** ** * *** *** * ** ***** *
*** * * * ****** * * * * ** ******** * * *  
** *** * ** * ***** ***** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.8k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 6.9k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users