0 like 0 dislike
7k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 7k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** * * * * x[] = {77,22,88,11,22};
****** ***** **** *** * size = 5;
    
* ** *** * * ***** * * ** print the array */
*** * * * *** *** * * i = 0; i < size; i++){
* * * * * ** * * * * * *** **** * * * * ***** * ", x[i]); ** *** * ***** ** * ** *** ***
** * *** * * ** **** *
** * *** *** * **** ***** ** * ** **
* ***** ** * *** **
** * ** ** * ** * ** I need this to happen size-times */
*** * ** * *** ** j = 0; j < size; j++){
* * ******* ** ** * *** *** ***** * * from left to right */
* *** ** * * ** **** *** * * * ** * *** **** i = 0; i < size-1; i++){
* ** * ** * * ** ** * ** * * * * * ** * **** *** * * * * *** ** ** i-th element with its neighbor to check if they are in order */
* ** ** * ** ** * *** * * *** * **** *** ** * ** * ** * * * ** * * *** > x[i+1]){
* * * * *** *** * **** * * * * * *** **** * * * * * * * * ** * ** ** * * * **** * * * * * exchange the values of x[i] and x[i+1] */
* * * ** ** ** * * **** * * ** * * *** ** * * ** * ***** * * * **** * ** temporary; * * * * ** ** * ****** * * *
* ** ** * * *** * * * ****** * * * ****** *** ** ** * ** **** * ** * * ***** = x[i];
**** *** * * *** *** ** ***** * * *** **** * **** ***** ** *** * * * * ***** ******* = x[i+1];
* *** * *** * * ** **** * * * *** *** **** ** ***** *** * ** ** * * *** * * * *** ** * = temporary;
* * * * *** ** *** * * *** ******** ** **** ** ** ***** * * * ** *
** * ** **** * ** ** * * * *** ** **** ** *
**** *** ** * *** * ** *
** * * ** * * *******
* * * * *** ** * * print the array */
* ** * ** * * *** * ** * * **** sorting: \n");
* ***** * ** ** * * i = 0; i < size; i++){
** *** *** ** * * ** * ** * * * *** * ** * * *** * ", x[i]); * * ** * ** * **** **** ** *
* * * * ** * * * *
* ******** ** * ** *** *** * * ** ** ** ***
* * * *** ** *
* * ** ** * * ** ** * *
****** *** * * *** * * * * * * * * * **
* * * * *** ** * *** * * * ** *** **** **  
*********** **** * ** ****** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * * ** * x[] = {77,22,88,11,22};
********* * * * *** ******* * size = 5;
    
* * **** * * * * ** print the array */
* ***** * *** * * * ****** i = 0; i < size; i++){
*** * ** * *** * **** * * * *** ** *** * * ** *** ** *** * ", x[i]); *** * **** * ** * * * ** ***
****** ** * * * * *
* * ** ***** ** * ** * * **** * *****
**** ** * * ** ** *
** * ***** ** ** ** * I need this to happen size-times */
* * * * * * * ** *** **** j = 0; j < size; j++){
* * *** ** ** *** ** * * ** * * * *** * from left to right */
* *** *** **** * * *** * ****** ** * * * ** **** ** * i = 0; i < size-1; i++){
* ** * * **** * ***** * * * * ** * *** *** ** ** ***** * * * ** * ** i-th element with its neighbor to check if they are in order */
******** ****** * ** ** ** *** ****** ** **** ** ** * *** ** ** > x[i+1]){
* **** ** * *** * **** **** * * ** *** **** ** * **** * *** * ** * **** ** *** **** * * * **** ** exchange the values of x[i] and x[i+1] */
* * * * *** * ** ** * * *** ***** ** * * * * * * ** ** * ** *** *** ** * *** * * temporary; * * ** ****** * * *
* * * * * * *** * ** * *** **** ***** **** * * * *** *** * ** *** **** ** **** ****** * * * = x[i];
* ** *** * * ***** ** * * **** ***** ** ** * * ** * * * * * * *** = x[i+1];
**** **** * * * * * * * * *** * *** ** *** ** * ** * **** * ** * * * * ** * * * ** = temporary;
* * ** * * *** * ****** * ** * * * ** * * ** * * *** ***
** * * ** ** * ** *** * * ** ** *** * * *
* * ** * * * * **
* ** ** * ** *** * ***** *
****** * ** *** ** print the array */
* * * *** * * ******** * ** sorting: \n");
* * ** *** * * i = 0; i < size; i++){
** * *** **** ** * * * * ** *** ***** * ** * ", x[i]); *** ** * ** * *** *** * * **
** ** *** * *** * ** * *
* ** ** * ** ** ** * * **
*** * * ** ***** * ****
* * *** * * *** **** **
**** ** ** * ***** * * * ** ** * **** **
* ** * * * * * * **** * * * * **** ***** ** *  
** *** *** * * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * ***** * ** * x[] = {77,22,88,11,22};
* **** * * * **** * ** size = 5;
    
* * ** * *** *** **** *** print the array */
** **** * * ** * ** i = 0; i < size; i++){
* ** * *** ** * * * *** * ** * * ** ** ***** *** ** ", x[i]); **** * * ** *** * ** ** ******* **
* * * *** *** * *
** * * **** * ******** *** ***** * ****
* * * **** *** ** **
* * *** *** * * ** I need this to happen size-times */
****** ****** * * ** ****** ** j = 0; j < size; j++){
** * * * ***** * * **** ***** * * * * from left to right */
* *** * * ***** * ** ***** *** ** ** * * i = 0; i < size-1; i++){
* * ** ***** ** * * ** * ** *** * * * * * *** ** * * **** * * i-th element with its neighbor to check if they are in order */
* *** * ** * * * ******** ***** ** * *** ** ** * *** * * ** * * * * > x[i+1]){
* * * * ***** ** * **** **** * **** * *** *** * ** ** * * *** * *** *** ** ** ** ** * *** exchange the values of x[i] and x[i+1] */
*** * * ** * * ** *** ***** * *** * * * **** **** *** ** * * ** * * * ** * * temporary; ** **** ******* * * * * ** ** *
* ***** *** ** * ** ** ** * * **** * ** ****** **** * *** ** ** ** ** ** * *** * ***** = x[i];
*** **** **** * * * * * **** ******** * ** * * ** * *** * * *** * * ** * ** **** = x[i+1];
** * * **** ** ** ** ** **** *** ** * ** ** * ** * * * ******** ** *** * * ** * *** * ** * * * = temporary;
* ** * ************ ** * ***** ** **** * ** * **** ** * **** ** ***
** * * ****** * ** ****** ** ** ***** * * *
** ***** * * **
* * * **** ****** * **
* ** * ** * * print the array */
** * * * ** ** * *** * * * sorting: \n");
* * * ** * * * **** ** ** ** * i = 0; i < size; i++){
* * * ** ** **** *** * * * * * *** * * ** * *** *** * ", x[i]); * * *** ** * *** * *** * *
** ** ****** *** ** **
** * ** * * ** ***** * * * * * * * ** ** **
* ****** * ** *** * *
** * ** * ** ** * * ***
* * * **** *** * ****** * * ** ** * * ****
** ** *** **** **** * ** * ** * **** * **  
***** * * ******* *** * ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ***** * *** * x[] = {77,22,88,11,22};
* * * * * ** * * size = 5;
    
*** * * ***** * * * *** * **** print the array */
*** ** **** ** * * * * i = 0; i < size; i++){
* * * ** * **** ** * **** * * ** * * * * * *** ", x[i]); * ** * **** ** * * * * * ***
* *** * * *** * *********
* *** * * * *** **** ** ****** **
** * **** ** * *** * ** *
**** ** ***** ** *** **** * I need this to happen size-times */
**** ******* * * * * j = 0; j < size; j++){
* * * ******** *** * *** * *** from left to right */
** **** * ******* ** ***** * * **** ** ** ** * ** i = 0; i < size-1; i++){
** * ** * * * * *** * ** **** * ******* ****** * * * *** ******** *** i-th element with its neighbor to check if they are in order */
* * ** * ** ** * *** *** * * * *** * *** * * ** **** > x[i+1]){
**** * *** * * * ** * *** * ** ** * ** ** * **** *** * **** ***** ****** * *** * ** * exchange the values of x[i] and x[i+1] */
* ** ** ** * * *** * * **** * * * * ** ** * * * **** * *** ************ ** ****** * ** * * ** temporary; **** * * * * **** *
* * ** **** *** * * *** * ** * ******* * *** * * *** ***** * ** ****** ** * ** ** * * * = x[i];
** * * * ** *** ** * ** * ** ** * * ** ** *** *** * *** * * * * *** * *** * ** = x[i+1];
* ** *** ** * * * *** ** ** **** * **** ** ** ** * * * ** * * * ** * * ** ** **** = temporary;
*** * ** * ***** ** *** * ** ***** * *** * *** * * **** *
** * * *** * * ** *** * * * ** * *** ** ** *
* *** ****
** ** ** *** * ***** ***
** ** *** * *** * ** * *** print the array */
******* ** * * * *** * * sorting: \n");
************ ** * *** * * i = 0; i < size; i++){
*** * * ** * *** * * *** * ****** * *** * *** * ", x[i]); *** * ** ***** ********* * * **
* * ** * * ** **** **
** * * * * * ** ** ** ** *** * * **
*** ** * ** ** ******** * *
* ** * ** ** * ** *
* ***** * ** * **** ** * ** * ** * *
* * * * ** *** ** **** ** ** *** *****  
** * ****** * * ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** * * **** * * x[] = {77,22,88,11,22};
** * ** * ** * * ** * size = 5;
    
** ** * **** **** * ** print the array */
* * * * *** *** * * * ** ** * i = 0; i < size; i++){
** ** ** * * * * * ****** **** *** ** * * * ", x[i]); * * *** *** * * * ** ** * ** * *
*** ** * ** * *
* ** * ** * * * ** **** * ****** * *
* * * ** ** ** **
** * * *** * * ** ** ** I need this to happen size-times */
**** ***** ****** ** * * ** j = 0; j < size; j++){
** * *** * **** ** * * ******* * *** * from left to right */
* *** **** * * * ** ** * * ** * * **** *** * **** i = 0; i < size-1; i++){
* ** ** ** * * * ** * ** * * * *** **** ** ***** ********** * *** i-th element with its neighbor to check if they are in order */
* * *** * ***** * * * ** * * * ** ** * ** ** * ** * * * * * > x[i+1]){
**** ** * ****** *** ** **** * * * * * * * ** * * * * ** ** ************* * * ** ** exchange the values of x[i] and x[i+1] */
** * * **** ** *** * **** * * *** * * *** * *** * *** * * *** * * **** *** * * ** temporary; * * * **** * * ** **
* ** ** *** * * ***** * ** ** * ** ** * * * * ** * * *** * * * * *** **** * * ** * ** **** *** = x[i];
* * **** ** *** *** ** ** **** **** **** ** ** ** ** ********** * * * ** ** * * * = x[i+1];
** ***** * * * * ** * * ** * * ** ** * **** * * ** ** * * ** ** * ** **** * *** *** ** = temporary;
**** **** ***** **** * * ** * ** *** **** ** *** * *** * * * ** *** * *
* * * *** ** * * * * * ** * * * * *
*** ********
** * * * ** * ** * *
** ** * ***** * ** * * * print the array */
******** *** * **** ** * * **** **** sorting: \n");
* ******** * *** ***** * i = 0; i < size; i++){
** *** ** *** * *** ** ** * ** * ** ** * ** * * ", x[i]); ** * * * *** * * **** * ** ** ** * ** *
** *** ** ** ** * ** *
* ** ** *** ** ** * ** * ** ** *
** ***** **** * ** * *
*** ** * * ** *
* ******** *** *** * * * ** ** ** * * *** ** * **
** * * *** * * * **** **** ** ***** * * * * **  
* * ** **** ** *** * * ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ** * * *** * ** x[] = {77,22,88,11,22};
**** ** * ** ** ** * ** size = 5;
    
*** * * * * * * print the array */
* ** *** * *** * **** i = 0; i < size; i++){
** * *** ** * ** ** * * * *** *** * * ** * ** ", x[i]); * ** **** ** ** *** * * ***
** *** * * ***** ** *
* ******* * * * ** ** *** * * *** * * *
* * ** * *** *** *
* ** ** **** * ******** I need this to happen size-times */
* ** * ** * * * ** * * **** * j = 0; j < size; j++){
* * * * * ** * * * ** ** ***** *** * * ** from left to right */
** * *** * ** *** *** * * **** ** * ** * *** **** * i = 0; i < size-1; i++){
* * * * * *** * * * ** ** * * * * * * *** ** **** **** *** * ** ** * i-th element with its neighbor to check if they are in order */
** * * * *** ** * ** * ** * ***** * ***** *** * *** *** ** * * > x[i+1]){
** * * * * * **** ***** * ** ** * * * * ** * **** * * **** *** ** ** * * * exchange the values of x[i] and x[i+1] */
***** * ** *** ** * * *** * *** ** **** *** * *** * ** ** * * * ** * * * * ** * ** *** temporary; * * ** * ** ***** * * *** ** ** *
*** * ** ** * * * * ** * * *** * * * * * * * ** *** * **** * ** * * * * * * ** * * ** = x[i];
* * * *** *** **** ***** * ***** ** * ****** *** * * * * ** **** * * *** * ** * * * * ** = x[i+1];
*** *** * ** * ** * ** ** * * *** * * ** ** *** * *** * ** * * * *** ** * = temporary;
**** ** * * * * ** * * ** * * ** * * * ******* ** ****** * * * * ** *
** * * * * *** * * * * *** * ** ** **
**** * * **** * * *
* * * * *** *
** * * ** * * ** * * **** * print the array */
** * ** ** *** * * ** * ** sorting: \n");
** * ** ** ** * ** **** i = 0; i < size; i++){
******* * * ** * * ** * * * * * * ** * ** * * * * ", x[i]); * * *** ** * ** * * ** ****
**** **** * * * * *** *
** * * ** *** ** * **** ** * ** ****
** * * * *** * * ** ******
**** * ** ****** **
*** ******** * * ** * ** **** * * * *
**** * ** ** ** ** ** *** *** ** * ***** * * *  
* * ** ******** ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * **** *** * * ** x[] = {77,22,88,11,22};
** * ** * * * size = 5;
    
* **** * * * *** * ** print the array */
*** **** * *** * i = 0; i < size; i++){
*** ** * * * ******** * *** * * * *** * *** * ", x[i]); ** ** * * **** * ** * **
** ** **** **** * ** * ***
* * **** * * ******* * ****
** * * ** * * * ** ****
* ***** ** *** * I need this to happen size-times */
* **** * * ********* * * ***** j = 0; j < size; j++){
* *** *** * *** * ** * *** ******* * *** *** * *** * from left to right */
* * ********* ** * ** *** * * *** ***** i = 0; i < size-1; i++){
** * * *** ** * *** * * * ** * ** ** * * ** * ** ** **** *** *** **** ** **** i-th element with its neighbor to check if they are in order */
** * * * * * * * * ***** ** * ***** ** * ** ***** * ** * * > x[i+1]){
**** ** **** ** *** * ** ** ** * ** ** ** ** ** ** * * * * * * *** * * * * * * *** exchange the values of x[i] and x[i+1] */
** * * *** ** ** ** ** ****** * ** * * ** ***** * * * * ***** *** ***** * * **** * *** * * * temporary; ** * ** ***** ** * **** * *** * * ** *
** *** ** ** **** **** * *** * * * * ** * * ** ** ** *** * * * * * * ** * * ** = x[i];
* *** *** * ******* ** * * * * **** ** ******* *** * * *** ** ** ** ** * = x[i+1];
*** ** **** * ** * ** * ****** * ** *** * * * ** ** * ** ****** ** * * * ***** * * ** * * * = temporary;
*** *** **** ***** ** * * * *** ** **** **** *** *** *
*** ** *** * * * * * ** * *** *** ** ** **
* * * * ** *** *** *
* *** * ** * ***********
** * * *** * * *** * ** ** * print the array */
***** * *** ** * ** * * *** * * * sorting: \n");
** * * *** *** **** i = 0; i < size; i++){
* * * * ****** *** ** ** ** * * * ** * * * * **** * * ** * ", x[i]); ** ***** ** * * * *** * * ** *
* ***** **** ** * *
* * * *** ** ** ** ** ***
* * * * * * *** * *
* * *** * *** **
* *** * *** * *** * * *** * * *
** ** * * * ** ***** ** ** ** ** ** * ** * *  
** * * * ** * *** * ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * ** *** *** * ** * x[] = {77,22,88,11,22};
* * ***** ** ** *** size = 5;
    
* * ** * *** ** ** ** ** print the array */
* * * ** *** * ** i = 0; i < size; i++){
***** * *** * ** **** *** *** *** * * * * ** ** ", x[i]); ** * **** ** **** * * * *
** *** * *** **
* * * * **** * * *** * ** * ** *
* * **** * ** *
** * **** * ****** * * * I need this to happen size-times */
* **** * *** *** *** j = 0; j < size; j++){
* ** *** * **** * ** ** * ** ** ** * ** *** from left to right */
** ** * ** ** * * * * ** * ** ** **** ********* * * *** i = 0; i < size-1; i++){
* * ** ** ** *** * * *** * ******* * * * * * * * *** ** * * i-th element with its neighbor to check if they are in order */
*** * *** *** * ** **** * *** ***** * *** * * * ** *** * * > x[i+1]){
* * * ** * ** *** * ** *** * * ** ** * ** * * * *** ** * * **** * ** ** * *** exchange the values of x[i] and x[i+1] */
* ** * * *** ** * **** ** * * * * ** * ** ** * * ** **** * * *** *** **** *** ** temporary; ** **** ** * * ** ** * * * * *** *
* * **** *** ** * * * ** * *** ** * * *** ** ** * ** * *** * ** * * **** * *** * * * * * = x[i];
* *** *** * *** ** * ** ** * * * * ** *** ** * ** ** ** *** * * ** *** **** *** * * = x[i+1];
* *** * ***** * *** * * * ** * * * * ** * ** ** **** * * *** ***** * * * * * * = temporary;
* * *** * * ** * * ** * **** ** ***** * * ** * * * * * ** *
** ** * *** * * * * ****** **** *** * *** * * * **
* ** ** ** * **** **
**** * ** * ** ****
*** *** * * *** print the array */
* ** * **** * * *** * * ***** *** * sorting: \n");
** ** ** * **** **** *** * * i = 0; i < size; i++){
** * * *** * ** ** ** *** * *** * **** * **** ** ", x[i]); * *** ** ** * ** * ***** *** * * *
* * * ****** * ** * * **
* *** * ** *** * **** ***** **** **
**** * ** ** *** ** *****
** * * * * ***** * * **
* ** * ** ** *** * *** * * ***
* * *** * * *** *** * * ** ** ** ** *** **  
*** * * ******** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** ** ** * ** *** ** * x[] = {77,22,88,11,22};
*** ***** ** *** ***** size = 5;
    
* ***** * * * * *** print the array */
**** * * ** ** ** ** * * i = 0; i < size; i++){
** ********* ** * * * * * ** * ** * ** * **** * ", x[i]); *** * ****** ** ***** ** ***** * *
** * ** ** ***** ******
** ** * **** * *** ** * * * * * * * *
*** * * ** * ** * *
*** ** **** * * * I need this to happen size-times */
*** * ****** **** * ** *** * j = 0; j < size; j++){
** ** * * * *** ***** *** * * * * * ** * * from left to right */
* ** * * * **** * * ** * * * ** * ** * * i = 0; i < size-1; i++){
* * * ** * ** *** * ** * * ** * ** * * * * * ** * * * * * * * ** i-th element with its neighbor to check if they are in order */
*** ****** * * * * *** * * * * ** * *** *** *** ****** * * ** * > x[i+1]){
*** * ** ** * * **** * * ** * *** *** * ** ** *** **** * ** * **** ** ** * ** * * *** * **** ** exchange the values of x[i] and x[i+1] */
* * ***** * ** *** * * * ** ** * * * ** * ** * * **** * *** * ** ******* *** **** temporary; * ** *** * * ** *** ** ******
* * ****** ** * ** * * * ** * *** * ** ** * * ** * * * * ** * * ** ******** ** * = x[i];
* *** ******** * * *** * * * * **** ** ** * * ** ** ** * ** **** **** * * *** *** * ** = x[i+1];
** * * * ***** * ***** * ** ** * ** * * * * * ***** ***** * * * ** * = temporary;
** ******* *** * * ****** ** * * * ** * * ** *** **** **
** *** ** * * *** * * *** * * ** * *
* * ** * ** * ** * **
** * * ** * * ***
** ** ** ** * ** *** * print the array */
** **** * *** * ******* * ** * * sorting: \n");
******* * ** * * *** * * * * i = 0; i < size; i++){
* * * * ** * * * *** * * * * ****** * ** ** ", x[i]); * ******* * *** * ** ******* *** * * **
** ** * * * *** *** * * *
*** * * * * * * **** * * * ** *
** **** *** * * ***
* * * ***** ** * * *****
* * *** ** * * ** ** ** ** ** **
** *** * * * * * * * * ** * * ** ** *  
*** *** * * *** * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * **** * * * ** * * x[] = {77,22,88,11,22};
** ** ***** *** * * * ** size = 5;
    
** ****** * * ** *** print the array */
** *** * *** * ** ** * i = 0; i < size; i++){
* ** **** * * ** * * ** * * ***** ****** * * * * ** * ", x[i]); * *** * *** * * ** *** ** * *
* * **** * ** *
* * *** *** ***** * ** * * ** *** * * * **
* ** * ** * ****
*** ** * * ** I need this to happen size-times */
* * ***** *** ***** * ****** j = 0; j < size; j++){
* *** ** * * * *** * ** * * * from left to right */
* * * ** * ** * * ** * * * * * * * ** * i = 0; i < size-1; i++){
*** * **** * * * * * ** * * * * ** ** **** * ** ** * ** *** i-th element with its neighbor to check if they are in order */
** **** * ** * * * ***** * * * *** * **** ** * ** ** *** * * * *** * > x[i+1]){
*** * ***** * * ** * * * * **** * *** * * * ** * **** * * *** * * *** *** * * * * exchange the values of x[i] and x[i+1] */
* ****** * * * * ***** * ** * **** * * * * * * * * * * **** * **** * * **** temporary; * ** * * ** ** ** * **
**** * ** * *** * * * * **** * *** * ** *** * ** * * * * * *** * * *** *** ** * * = x[i];
** * * ** * * * *** ** ***** * ** * ***** * ***** * ****** * *** *** *** * * ******** * * = x[i+1];
****** ** ** * ** * ******* * * * * ***** ** *** ** ** * * * * *** ** * = temporary;
* * * *** ** ** * * **** ****** * *** * * *** * *** * * *
* * ** * * * * * * ** **** * * * *** * *
*** * *** * * ** *
* ****** * *** * **
***** **** * **** * print the array */
* ** * *** ** * * * * ****** ** ** sorting: \n");
* * **** * * ** * ** i = 0; i < size; i++){
******* *** *** * ***** * * ** * ****** *** ** * ** * ", x[i]); * * ** ***** * ** * ***** ****
* * ***** **** * **
************ ** ** ** *** * *** *** * * ***
** * * ***** * * *
** ***** * ** ******
* **** * ***** * ** * ** * * ***
** ** * * * * * ** * ** * * * ** ***  
** ** * * ** * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.125
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users