0 like 0 dislike
8.7k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.7k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * **** * * ** *** * * x[] = {77,22,88,11,22};
** * *** * ** * **** size = 5;
    
**** ** *** ** ******** * print the array */
* ** *** ** * ** * **** ** i = 0; i < size; i++){
* *** ** * * * * *** ** * * * * * * **** *** ", x[i]); ** **** *** * * ** **********
**** * * * ** * *
** ** * * * * ** ****** * * **
*** ** * * *** *** ** *
* * ** * * * * * * * I need this to happen size-times */
* ** ** ** * ** *** * *** j = 0; j < size; j++){
****** * * *** *** * * **** * ** * *** from left to right */
* *** *** * * *** * * * * * ** * ** ** * * i = 0; i < size-1; i++){
* * ** * ** * * * * ** ** ** ** * ** ** * *** * *** * ** * * i-th element with its neighbor to check if they are in order */
* ** * ** ******* * ** ** ********* ** * ** ***** * * ** * * *** * * > x[i+1]){
* ** * ** **** ** * * ** ** *** ******* ** ** * *** ** ** * * *** * ****** ** exchange the values of x[i] and x[i+1] */
** * *** ***** ** ** **** * * **** ** ** * * **** * ** * * * *** ** * ***** ** ** * * ** temporary; ** ** ** ** *** * **** * * * * **
** * * **** *** * *** ** ** *** * * * * *** * ** ***** ** ** * * * ** ** **** * ** ** ** ** * ****** * = x[i];
* * * * *** * *** ** * * ** * * * * ** ** *** *** * ***** * **** *** ** ** *** * * = x[i+1];
* ** * * ** *** **** ** ** ** ** * *** ** **** ***** * ** ***** * *** ***** * *** * **** * = temporary;
* * * **** ** *** * ** * * * * ** ** *** **** ** ** *** * *
**** ** ** ** * * ** *** * * * ** * * * *** *** *
****** ** * * * * * *
* * ** ** * ** ** * ***
* * * * * * * *** * print the array */
****** * * * ** ** * ****** ** * sorting: \n");
* * *** * * *** * * i = 0; i < size; i++){
* *** ** * * * * * * * * * **** ***** ** ** * ", x[i]); * * * ** * * * * * ****
* ** * ** * * * * *
**** * * **** **** ** ** ** * *** * ** * * *
* ******* ** ** *
* * ** * ** * ***** *
* * * * * *** * * ***** ** *
* * **** * ** ** * ** ** ** * **** ***  
* * ** *** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** ** * *** * x[] = {77,22,88,11,22};
**** *** * ** **** ** size = 5;
    
* *** ** ** * * ***** print the array */
*** * * *** * ** * * i = 0; i < size; i++){
* ** **** * ** ** *** * ** * * ** *** * ****** ******* *** ", x[i]); * ** * **** * **** * * ** * *
** *** ***** * *
** ****** *** ** ** *** ***** * ***
* * **** * * ** * ***
* ** * * ** *** ***** *** I need this to happen size-times */
** *** ** ** *** *** j = 0; j < size; j++){
** * * * *** ** * * *** ** ** *** * * *** * *** from left to right */
**** * **** * * ** **** ** * * ** * i = 0; i < size-1; i++){
** ** * * *** * * ** * **** * ** ** * * ** * * * * * * ** **** i-th element with its neighbor to check if they are in order */
** ** ***** * ** ** ** * * * ******* * ** * *** * ** ** * > x[i+1]){
** * **** * * * * * * * * *** ** ** * * ***** * ** ** * **** ** ** * ** exchange the values of x[i] and x[i+1] */
* ** * * * *** **** *** ** ** * * * ** ** ** *** * * **** * * ** **** * * *** * * temporary; * *** **** * *** * * *** * * ** **
* ** * * * ***** * * ** ** * ** **** * ** ***** * * ** * * **** ***** * * * * * = x[i];
* * ** * * * * * * * * *** * ** * ** * ** *** ** * *** *** *** ***** *** **** * **** * * = x[i+1];
** * ** *** * * * * *** * *** * ** *** **** **** * * ** * ** * * ** ****** ** * *** ** * *** = temporary;
* * * ** * * * ** * * **** *** * * *** ** ** * * *** ** *** * *** *
* * * * ** * * * ** ** * *** ** ** * * * *
* *** *** *
* ********** ** *** * * **
* * * * * ***** *** * print the array */
* ** * ****** *** ** * ****** sorting: \n");
* * ** *** *** ** *** i = 0; i < size; i++){
* ** * * * * *** **** ** * *** ******* ** * * ** ** ", x[i]); ** * ** *** *** * ** * ** *
* ** *** ** *
*** ***** * **** ***** * ** ****
** * * *** * * * * *
** **** *** * * * ** *
** ** *** ** *** ** * ***** * * * *
*** * ** * * ** **** * ** *** **** ** * **  
* * * * * *** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * ** **** * ** * * x[] = {77,22,88,11,22};
* *** ** ** * * * size = 5;
    
*** * * * ** ** * * * *** * print the array */
******* * * *** ** * i = 0; i < size; i++){
**** ** *** ** **** * * *** * ** ** * ** * ** *** ** * * ", x[i]); * ** * * *** *** ***** * * * * *
* * *** *** *** *
** ** ** **** ** ** *** * *
* **** * ** ****** *
***** * * *** * * ** ** I need this to happen size-times */
** * * * ** *** * *** * * j = 0; j < size; j++){
* ** **** ** * ** * **** ** * ** from left to right */
** * * ** ** *** **** * ** *** ** i = 0; i < size-1; i++){
***** * * * *** * ** ** ****** ** * ** *** * *** * ** * ** * i-th element with its neighbor to check if they are in order */
* * ** * *** * * *** ** * *** *** ** * * * ** *** *** ** ** * > x[i+1]){
*** * ** ** ** ** * *** ** * * * * ** * * * ** * * * * * **** * *** exchange the values of x[i] and x[i+1] */
*** * * ** * **** *** * *** * *** * * ** * *** ** * ** * ** * * ** ** *** *** * *********** * * temporary; ** * **** * ** * ** *
* * ****** ** *** **** * ** * ** *** * * * * * ** **** * * ** * * * **** ** * *** = x[i];
* *** * * * * ** * * * ** ** * *** * ***** * ****** ***** * * * *** * *** * * = x[i+1];
** * * **** * * ** ** *** * ** * * **** ******** * ** * * ** * ** * *** ** **** * ** = temporary;
* * * * ** * * * ** ** *** *** * *** * ** ** ****** ** *** *
* * ** *** * * * *** *** * ** ** * * *
* * * ** * *
** ** ** * ****** *
*** * ** ** ** ** * *** print the array */
* * * ********* * * * ***** * ** sorting: \n");
* ** *** * * ** ** i = 0; i < size; i++){
** ***** * ** * ** *** ** * **** * ***** * * ** * * ** ", x[i]); * ** * ** *** * ***** *
* ** ** * * **** ***
* * * * * **** * * * * *** *** *
** *** * ** ** *
**** ** ** *** *** * ** ** *
** * ** *** ** *** * * * ** ** * * *
* ** ** **** * ** * ** * * * **** * * ** *  
* ** * * ****** ** * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * * x[] = {77,22,88,11,22};
* * * ** * * * * * ** *** size = 5;
    
* ***** * **** * ** ** * print the array */
* * * * * * ** * * i = 0; i < size; i++){
** ** ****** * ***** ***** ***** ** *** * ** ** * ***** ** *** ** ", x[i]); ** * * * **** ** ** *** ** ***** ** *
** *** * **** ** ** * **
***** * **** * ** ** * * ** *** *** *** **
** ** ** * * ***
* * ***** ** ** *** I need this to happen size-times */
******* * ** * * * * * * j = 0; j < size; j++){
** * ** * * * *** * * **** ** ** * * * ** * * ** from left to right */
* ** *** * * * * ** *** ** * ** ** * i = 0; i < size-1; i++){
** *** ** * * *** ** * ** * * * * * * ** * ** *** *** * ** * ** * i-th element with its neighbor to check if they are in order */
* *** *** ** * * * ** * * ** *** * ** **** **** **** **** *** * *** **** > x[i+1]){
* *** ** ***** * ** ** ** * * ** * ** * **** * **** ** ** * * * ** * ** * *** exchange the values of x[i] and x[i+1] */
* ***** ** **** * ****** * * **** * * *** ** ** ** * * * *** * * ** ***** ** ** * * * temporary; *** * * * ** *** *** ** **
******** * * * ** ****** *** * * * ** * * * ** ** *** ****** *** *** * * * ** **** * = x[i];
** ** ** * * ** ** ** * * * * ** * ** * * ** * ***** ** ***** ** ****** *** * ** * *** ** = x[i+1];
* ** ******** * * ** * *** * ** ** * ** ** ** * ***** ** * * * *** * * * ** ******** * = temporary;
* ****** * ***** * ** * * **** ** * ** ** ** * **** * **** * * *
* ** ** ** * * ******** ** * * ** * ****
******* * * *** * * * * *
** *** ** ** * * *
** ** *** ** ** * * print the array */
* * * ** * * * * * sorting: \n");
*** *** ** **** ** * **** i = 0; i < size; i++){
*** ** **** *** * * *** * * * * ***** * * ** *** ", x[i]); ** * **** * ** ** * ** ** *
* *** *** *** * ** ***** *
*** **** ** ** * * * *** * * * *** *** *
*** * * * * * **
* * * ** *****
******* * * * ** * * * * * * * ***
* ** * ** * ** * **** * * * ** *** **** ** *  
********* * ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * ** ** ** * * * x[] = {77,22,88,11,22};
* ** ** * *** size = 5;
    
*** * * *** * * * ** print the array */
*** * **** * ***** i = 0; i < size; i++){
** * * * * ** * ****** ** ******* ** * ** * ** ****** ", x[i]); * *** ** *** **** * ****
* * ** *** * ** *
* ** * ** * *** *** ** *** ** * *
** * * * * ** *
** * ** * ** * *** ** I need this to happen size-times */
** ** ** ** **** * * ** j = 0; j < size; j++){
* * **** ** * * * ** ** * * **** ** * * * ** from left to right */
* * * * **** **** ** ** * ** *** * ** ** * * i = 0; i < size-1; i++){
*** * *** * ** * **** * * * * * * ** * * * ** ***** * * i-th element with its neighbor to check if they are in order */
**** *** *** * * ****** * * *** ** ** ** * ** **** * * * > x[i+1]){
*** * * * *** * * ** *** * * ** * * ********* * ** ** *** ** * * ** * * * * *** ** * **** exchange the values of x[i] and x[i+1] */
*** **** * * ** ** * *** ***** * *** ** *** * ** ** * ** * ** * ***** ** **** temporary; **** * ** * * *** ***** *** * **
* ** **** * * * * ** *** *** ** * *** * * *** **** *** * * * ** * *** * ** * ** ** = x[i];
*** *** * * ** ** *** * * * * * * *** * * *** *** ** ** * * *** ***** **** ** ** ***** * = x[i+1];
****** *** ******** ** *** * * * * **** * ** *** *** * ** * **** * * ** * * * *** = temporary;
** ** * ** ****** * ****** *** * * * * *** *** * * * * *
** * * * * * ***** * ** *** * * ** ** **
* * *** **** **** **
* * * * *** **** **
** * * **** ** * *** ** print the array */
*** * ** * ****** * * * *** * * sorting: \n");
* ********* ** * *** * * * i = 0; i < size; i++){
* *** ** * ****** * * * * * * ***** ** ****** ", x[i]); * * *** * ** * * * * ** * **
* *** * ** * * * ** *
*** *** * * *** * ** * * ******
* *** * *** * *** *** ***
** ** ***** * * *******
* *** ** *** ***** *** * * * * * *
**** * * ** **** * * * * ** ** *** *  
* * * ** * * * * * * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * ***** * * * ** x[] = {77,22,88,11,22};
***** *** * * * **** size = 5;
    
*** ** * * * * * **** print the array */
* * *** * *** ***** i = 0; i < size; i++){
** ** ** * *** * ** * *** * * * * * ** ** *** **** ", x[i]); *** * * ** ** * ****** ** ******* ***
* * **** * * **** ** * *
** * * ** * * * ** * ** * * ** * * * **
* * ** * ****** * **
* * * ** * ** * * I need this to happen size-times */
** * ** ** ** ** *** *** **** j = 0; j < size; j++){
* ** * ** ** * **** * * * ** *** **** * *** from left to right */
* * * * ** * * * * * ** ** * ** ** * * i = 0; i < size-1; i++){
* * *** ** ** *** ** ** ** ** * * ** * * * * * * *** * ** * * ** i-th element with its neighbor to check if they are in order */
* * * *** ** * * * * ** * ** * * *** ** *** * * ** * ** * ** ** * ** > x[i+1]){
* ** * **** ****** * * ** *** ** * * * * ** * * **** **** * ** ***** * * ** *** * * exchange the values of x[i] and x[i+1] */
** ** * ***** ** * * * **** * **** * * *** ** * ** * *** ** * ** *** * * * * * temporary; * ***** * ** * * ** * ** * *
** *** ** * * * *** * *** **** ***** * ***** * * * ** ** * ***** *** ** **** ** = x[i];
* * *** * ** * ** * ** * *** ** ******* * * * * * * ** **** * ** * ** ** * * = x[i+1];
* * * * * *** * ** **** *** * ** ** * * * *** * ******* * ** *** ****** ** * = temporary;
* * * **** * ** * * * * * * ***** * * *** * ** ** * **** ******
** ** * ** * *** * * * * *** ** * *
**** * * **** * * * *** *
*** * ******** *
* * ** * * * * print the array */
* * * *** * * ** * * sorting: \n");
* ****** ** * * ** * ** i = 0; i < size; i++){
** * ** *** * *** ** * **** * ** *** *** * ", x[i]); * * * * * ****** * * * * ****
** *** * ** ** * *
* * * * * * *** * * * **
* ** ** *** * * * * *
** *** *** *** * *** *
******** * * **** **** ** *** * * * * *
* ***** * ** ****** *** * * *** **** * **  
* ***** * ** **** **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * ** ***** x[] = {77,22,88,11,22};
* * ** * ** * * ** size = 5;
    
** ** * ** **** ** print the array */
**** ** * ** ** ** * ** * ** i = 0; i < size; i++){
** * **** * *** * *** ******* ****** * ** * * * ** *** ", x[i]); * * *** * * * ***** * *******
****** ** * * * ** **
* * * ** *** * * ***** **** * **
* * * ** ** ***** **
* * ** **** *** ** *** ** I need this to happen size-times */
* ** ** ** * *** **** *** * j = 0; j < size; j++){
* ********* ** * * * **** * ** ** * * ** * from left to right */
* ** **** ** * ******* ** ** ** * * ** * ** i = 0; i < size-1; i++){
** * * * ** * ** * ******* ***** * ** *** **** ** * ** **** * * ** ** * i-th element with its neighbor to check if they are in order */
** * ** * *** ** ***** ** * ** ** * ***** ** *** * * * * * * * ** * * > x[i+1]){
** ****** ***** * * *** * ** * ** ** ********** *** ** * * * ****** * ** * * ** * exchange the values of x[i] and x[i+1] */
* * ***** * * *** * *** * *** * ** ** * * ** ** ** ** ** * * * * * * ** * ** * ** * * * temporary; * * *** * *** * ** * * ** *** * **
* **** * * ** * **** * * ** * * * ******** *** * *** ** * *** ** * ******* ** ***** * = x[i];
* ** ** * * ****** ** * ** * ******** *** * ** ** * * ** * ** * ** ** ***** * = x[i+1];
* * * * ** * * ** *** * ** * ***** ** * * * ** * ** * * ** ** *** ** ****** * ** = temporary;
* ** ******* ******* * ** * *** * * * **** ****** ** * * **** * *
* ** ** * ** * * *** ********* *** * *** * *******
**** *** ***** *
**** ** * * * * * * *
** ** * ** * * *** * ****** print the array */
**** * *** *** * * ** * sorting: \n");
** * * * ** * i = 0; i < size; i++){
* ** * * * * * * * ** *** ** ** ** *** * * ", x[i]); ** * ** * *** ** * * * **** *
* * *** * * * ****
* ** * ** * ** * * **** * * *
* * * * * **
* * ** ** ** * * ***
* * * * * * * * *** ** **
** * * * * ** *** ** ** * * * ***** ** ** ** *  
**** ** ** * * * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * ** * ** ** ** x[] = {77,22,88,11,22};
** ** ****** * ***** size = 5;
    
* **** * *** ** * print the array */
** ** *** *** * i = 0; i < size; i++){
** * * ** * ** ** ** ** ** ** * **** ****** *** * * ", x[i]); * * *** * * * * ** **** *** * **
* * ** * * **** * ** *
** ** *** ** * * * ** ** * * ****** ****
* ** * **** *** ** **
**** **** * ** * * I need this to happen size-times */
* * * * * * * * * * j = 0; j < size; j++){
* ***** * * * ** ** * * * * * * ** *** * from left to right */
* ** ** * * * * ** *** * **** * *** i = 0; i < size-1; i++){
* ** * ** * * ** *** ** * * *** * * *** ******* * * ****** * * ** i-th element with its neighbor to check if they are in order */
* ** * ** * ** **** * ** * *** ** ** * * * ** * > x[i+1]){
* ** ** * * * ** * ** *** ** * * ** * ******* * *** * ***** *** *** * * * * exchange the values of x[i] and x[i+1] */
****** * * * * *** * ***** *** ***** * * * * * * * *** *** *** * ** * ** *** * * ** * *** * temporary; * * ** ** * * * ** ** * * ** ** *
**** * * ** ** * ** ** * *** ** * ********* * *** ** ****** * * * * ***** ** ** * *** = x[i];
** * * ** * * * * * ** * ** ** ***** ***** ** * * ** * * *** * **** *** * *** * * = x[i+1];
** * * * * **** * * *** ***** ** * * *** * * * * ** *** * * ** * ** ** * = temporary;
* **** * * * ******* ** **** * * ** * * * * * *
* ***** ****** * ** * * ** * **** ** * * *****
*** * ** *** * ** ***
** * ***** ****** *** *
******* ** ** * * print the array */
*** **** * **** * *** * * * * ** * sorting: \n");
*** ** *** *** * * ** * * i = 0; i < size; i++){
* ** ***** * * ** ** **** * * * * ** ********* *** ** ", x[i]); ** * ** * ** * **** *** **
* *** ** *** ** *
** ** * **** * *** * ** * *** *** *
** *** * * * ** ******
* ** ** *** * * * * *
******* * ***** * * ** * * * ** ** *
* ****** *** * ** * * **** * * * * * *****  
* * * ** ** *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * * ***** **** ** x[] = {77,22,88,11,22};
* ** * * *** * ** * * * * size = 5;
    
* * ** ******* * ** print the array */
** ***** * *** ** * * i = 0; i < size; i++){
** * **** **** ** * * * * * ** ** ***** ****** ******** ", x[i]); **** ** **** * *** * *** * *** * **** *
* ** * * ** * * ******
*** * * * * * ** * ** * * ** ***** *******
* * * * * *** ** **
** ** * ****** ** * I need this to happen size-times */
* * **** ****** * * *** * j = 0; j < size; j++){
* ******** ** * *** *** * ** ***** ****** * ***** from left to right */
* ***** * ** * * ** ***** * * * * ** * *** ** i = 0; i < size-1; i++){
* * **** * * ****** ** * * * ** * ****** * * * * * * ** ** * i-th element with its neighbor to check if they are in order */
* **** ** ** ** **** ***** ** ** ***** * * **** * ** ** * ***** *** **** > x[i+1]){
** ** ** *** ** * * * * * * ***** * * * ** ** * *** * ** **** * * ** * ** ** * *** * * * exchange the values of x[i] and x[i+1] */
**** * ****** * ***** *** * * *** * ** ** * ** *** * * * *** * *** *** * *** ** * * *** * temporary; * ** *** ** * * ** * * * *** ** *
** ** * ** * **** * **** * * * ** ** *** **** * ***** * * * *** * ***** ** * * ** * = x[i];
* ** * * **** ** **** * *** ** * ** ***** * *** ** ** * * * ** *** * *** * * **** = x[i+1];
* ** * * * * * ** *** *** * * * ** ** ** * * ** * ** * * ********** * * * *** ** * = temporary;
*** * * * * *** *** *** * * **** ** *** *** * * ** * * ** * ***
* ***** * * * * ** * *** ********* * * * * *** *
*** * * ** * * * *
********* * *** * ** *** *
*** * * * * * print the array */
* * **** ** * * ** * ** ** *** **** * sorting: \n");
*** ** ** ** * ** **** i = 0; i < size; i++){
**** ***** ************ * *** * * * * ** ", x[i]); * *** **** * *** *** ** ***** ** *
**** *** * * * * * *
** *** * *** *** ** *** * * **
* * ** * ** * *
* ***** * ** * *
* ** * * *** *** ** * *** * ** ***
* * * * * ** *** **** * * * * * * * * * *****  
****** * ** ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * **** ** * * * * * x[] = {77,22,88,11,22};
*** ** ** ****** * ** * size = 5;
    
* * * ** * * print the array */
* * ** *** ** i = 0; i < size; i++){
**** **** *** ** **** * *** * * * *** * * * ", x[i]); * * * * ** * * * * ** * **** *
**** ** * * * *****
* * * ** **** *** ** ****** * **** * **
*** * * ** * * **
* ** * *** * ** ** I need this to happen size-times */
** * ** ** ** * *** * * j = 0; j < size; j++){
* * **** *** * * * * * *** * *** from left to right */
* *** * * * ****** * *** ** ** ****** * * * ** ** * i = 0; i < size-1; i++){
* ** * ****** ****** * ** *** * * ** ** *** ** ** ** * ** * * *** ** * *** i-th element with its neighbor to check if they are in order */
** * * * ** *** ** * * ** *** * * ** ** * **** > x[i+1]){
** * ** * **** * * ** * **** *** * * * **** * * ** * * * * * ** * * ***** exchange the values of x[i] and x[i+1] */
* *** *** * **** ** * **** **** * * ** *** ** *** ** ** *** ** ****** ** *** * ** temporary; ** ** ** ** * **** *** * * * *
** ** * * * *** ** *** * *** *** ** **** * * * * * * * ** ** ** * *** * * * * ** * = x[i];
* ** * * *** ** ** *** * * * * * ** * **** ** *** ** * * ** ** ** *** * = x[i+1];
* ** ** ** * * * ** * ** * *** * * * ** * * ** * *** ******** * * ** * *** * ** = temporary;
* * *** * * *** *** ** * * ** * ** * *** * ** ** ** ** * * *
** * * * * **** ** *** *** * ** ****** * *** ***** ** *
* **** ** * * **** **
** * ** * ** * ** *
* * * ** ***** * *** *** ** print the array */
* * * *** ** *** * * * * **** * **** ** sorting: \n");
******* ** ****** * *** i = 0; i < size; i++){
* *** * * * * * *** ** * * * ** **** * ** *** * * * ", x[i]); * * ** ** *** * *** ** **** ** *
* **** * * * * ** ** * *
* * *** * * * ** ** **** * * ***** ** ***
* *** * **** *
* * * * * ** ** * ***
** ***** ** * * ** * *** *** * ****
* ** * ** ** *** * *** * * ** ** ** **** ** * * ***  
* ** ** **** ** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.194.138
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.7k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users