0 like 0 dislike
8.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * ** * *** ***** *** x[] = {77,22,88,11,22};
* *** * * **** ****** size = 5;
    
* ** * * ** ** print the array */
* **** *** * ** * ** * i = 0; i < size; i++){
** * * ** * ** **** ** ** ** * * ***** * * * ", x[i]); * * * ** * * *** ** * * * * ** *
*** ****** ** * *
****** ****** ** ** * * *** * *
* * ** ** *
* * ** * ** ** * * ****** * I need this to happen size-times */
**** * *** ***** *** * * j = 0; j < size; j++){
* ** * * * * * **** ** * ** * * * ** **** * ** * from left to right */
* * **** ** ** ** ** ****** ** * * * **** ** i = 0; i < size-1; i++){
* * ****** * *** ** * * ** * * * ***** *** ** *** ** * ** i-th element with its neighbor to check if they are in order */
* ** *** * * ***** *** * *** *** ** ** * **** ** ***** * * * * ** * *** * > x[i+1]){
* ** *** ******* * ** **** * *** ***** *** * * * * ** * ***** *** ****** * * * * * exchange the values of x[i] and x[i+1] */
*** ** *** *** * * ********* ***** * *** * ** * *** *** **** * * *** * **** *** * * * * temporary; * ** * * ** *** ** *** * * * *
**** *** * * * * ** * *** ** * *** ** ** * * * * ** * **** *** * ** * * * * ** * * **** * = x[i];
***** * *** ** ****** * ** * * * * *** **** * * * * ** * * **** * * **** *** = x[i+1];
* * ***** ** * *** * **** * * * * ******** ** *** **** * **** ** *** * ****** * * = temporary;
* * *** ********* *** * **** ** * * * ***** * ****** **** *
** * * * **** * * *** * *** ** * *** ** ****
*** * *** ***** * ** * * *
** * * **** * ** ** ** *
*** ** ***** *** * * print the array */
* * ** * ** * ** * * * * ****** sorting: \n");
* ** ** * **** ** * **** i = 0; i < size; i++){
*** * ** * *** * * ** ** * ** *** **** ", x[i]); * * * * * * * * *** * **
* * ** ** ** * * *
*** * ** ** *** ******** ** * **** **** * * *
* * *** * *** * ****
* *** ** * * * ** * * *****
* ** * ** * ***** * * *** ** *** * * *
* * * * * ** * *** * ** ***** *** ** ******* ***  
***** * * * * *** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** * **** **** x[] = {77,22,88,11,22};
***** * * * * ** * ** size = 5;
    
* ** * * * ** * ** print the array */
* ******* ** ** * **** **** i = 0; i < size; i++){
*** * *** * ** * ** * **** * * *** * *** ** * * ", x[i]); * **** * * * ***** ** * * * * **
* * * * * *
**** * * ***** * * * *** **** * * * ** *
*** * * * * * ***
* *** * * ******* ** I need this to happen size-times */
* * * *** ** * * ***** * * j = 0; j < size; j++){
* *** *** * ** **** ** **** * * *** ****** ** from left to right */
*** *** * * * ** *** ** * * ** *** ** * i = 0; i < size-1; i++){
* ** * * ** ***** * ** *** ***** * ** ** ** * *** **** * ** * * * **** i-th element with its neighbor to check if they are in order */
* ******* * * * *** ** * * ** ** *** ** ** ***** *** **** * > x[i+1]){
* **** * *** *** ** ***** ******* ***** * * * * * * * *** *** * ** exchange the values of x[i] and x[i+1] */
*** * * ***** * * ** *** *** * *** * ** * * * * * ** *** * *** * * *** * **** * temporary; * *** * * * ****** * * * * *
** ***** *** * * * *** ** ** ****** ******* ******* * * * * * * * *** *** *** = x[i];
* *** * * *** * *** * ***** * ** *** ** *** ** * * * *** * *** * ***** = x[i+1];
****** * ** ***** * *** * *** **** * ** **** **** * * * ** **** * * *** * ** * ** * = temporary;
** ** * * ** * ** * * * **** * * * * * ** * * * ***
** ** *** * * * * * * * * ****
** ** * ** ** *****
*** * ** * * ** **** *
*** **** * * * *** ** print the array */
* * ** ***** * **** * * * * * * * * * sorting: \n");
* *** * *** *** ** ** *** i = 0; i < size; i++){
* *** * ** ** * * * ** * * *** * *** *** ", x[i]); *** * ** * ** * ** * *** *
** * ** ** *
** ** * *** ** ** ** ** **** * ** **
* * * * ***** * **
* * ***** * ** * ****
******* * ** * * * * * *
** * * * ** ** * ******* * ** * ** ** ***  
* ** * * * ** * * * * **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * * * * * * * * x[] = {77,22,88,11,22};
* ****** * ** * * ** * * size = 5;
    
* ** * ** ** ** * * * * print the array */
** * * *** *** * *** **** i = 0; i < size; i++){
* * * * * * * * * * ** * * ** **** * *** ** * ", x[i]); ***** ** * ***** ** *** ** * * * *
* * ** *** ** *
***** *** *** * **** * ** ** *** *** * *
** * ** * * * ** * ***
*** * * ** * * ** ** * ** I need this to happen size-times */
* **** ** * * * * * *** * ** j = 0; j < size; j++){
***** ** * ** ** * * * * ** * * * from left to right */
* * * ***** * * * * **** * *** *** * * i = 0; i < size-1; i++){
**** * * * * * * ** ** ***** **** ** ** ** **** * *** * i-th element with its neighbor to check if they are in order */
** * ** * *** * * **** ** *** ****** ***** * ** ** *** * * * * ** > x[i+1]){
* * * * ** * ** **** ** ** * *** **** * * ** ** *** *** *** *** *** * * ** exchange the values of x[i] and x[i+1] */
* * * **** ** **** * * * * * ** * ***** * * ** ** * ** * ***** ** ** * temporary; * * **** * *** * * * ******* *** **
* * * * * * * * ** * * * ** * * * * *** * **** * ** * * **** * * *** ** * ** = x[i];
* ********** * * ** * ***** * ** * *** * ****** *** ** * * *** **** * * * ** * * ** = x[i+1];
* * * * * ** * ** ** * * * ** * * * * * ** * ************ * *** * * * ** ** *** * * ** = temporary;
** *** ** * ** ******** **** *** ** ** * * * ** * * **
* * ** * *** ** ** *** * ** ***** * ** ***
*** * ** ** * **** **
* ** * *** ** *
** ** * * * ** * print the array */
** ** * ** ** *** * * ** * *** sorting: \n");
**** **** ** * * i = 0; i < size; i++){
* * ** ** * *** * * ** * *** *** * * ** * ** * **** * ", x[i]); * ** **** ** **** * ** ** ** * * *
* * *** ** ** * ** *
* * *** * * ***** * ******** ** * * *
** *** * **** * * ****
* ** ** * * ** *
* * ******* *** * * *** ***** * * * *
** * ** * ** **** **** *** *** * *** ** * ** * *  
** * **** ******* *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** **** * * ** x[] = {77,22,88,11,22};
*** ** *** * ** *** size = 5;
    
** ** * *** **** *** print the array */
** * ** * * *** * * * * i = 0; i < size; i++){
* * * * ** * * ** ** * * **** * * * ** *** ** * * * ", x[i]); * **** * ** ** **** * ** *
* ** *** ****
* * *** **** ** * *** * * * * ** ** *
******* * * *** ** ***
* *** ** ** ** ** * I need this to happen size-times */
* *** * *** ** * j = 0; j < size; j++){
* * ** * ** * * * * * * *** ** *** * * *** from left to right */
**** *** **** ** * * ** * * * * * *** * * * i = 0; i < size-1; i++){
**** * * **** ** ** ** ** ** * * * ******** *** * * *** * **** ******* i-th element with its neighbor to check if they are in order */
** * ** * ** * * * ** ** * * * * *** * * * ****** *** * *** * > x[i+1]){
** ** * *** * * * * * * ** * * * **** * *** * ** * * * * ** ** * * * * * * *** * ** ** exchange the values of x[i] and x[i+1] */
* ** * ** * * * ** ** * * * **** ** * * * ** ** *** ** * * * ** * * ** * *** ** * temporary; * * * *** ** * * * *** **
* **** * * ***** *** ** ** ****** * * * **** * ** * ** * * ** * * ** * * ** = x[i];
* ** * ** ****** * * * * * *** ** * ** *** * * * * * * *** * *** * ** * *** ** * * * = x[i+1];
** * ******* * ** * ** *** ** * * * ** * * * * * * **** * * * * * * * * *** ** * = temporary;
* * * * * ***** ****** **** * *** * **** ** * **** *** ******
* * * * * * * * * * ** * * * * ** * * **
** ** ** **** * *
* ** ** ** * ** *** ** ***
* * * * ** ** ** **** print the array */
*** * *** ** * ** * * **** * sorting: \n");
* ** * * ******* *** ** i = 0; i < size; i++){
** ** *** * ** * *** * * *** * ** ***** ** ", x[i]); * * * * * * **** * * ** *
***** ** * * ** * * **
**** * *** ** *** * ** *** * * **** * ** ***
**** * * *** * *** * * *
* * * **** * * ****
** * * ** *** ** ** *** * * ** ** * **
* *** * * *** * ** ** * ** * * * * * *  
*** ** **** * * ** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** ***** * * * ** x[] = {77,22,88,11,22};
* * *** * ** * ** *** * size = 5;
    
** * * * * ** ** * *** ** * print the array */
** * * * *** ** * * * * i = 0; i < size; i++){
* * ** * ****** ** * ** **** * ***** *** * *** * * ** ", x[i]); *** * * * * * ** *** * *** * **
* * * * * * * ** * *
* * ** * * *** ** ** ** * * ** **
** * ** *****
*** ** **** * ***** * ** I need this to happen size-times */
* * * * * *** **** * ****** j = 0; j < size; j++){
* * * * ** *** * ** * * * * ** * * *** ** from left to right */
* ***** * ** ** *** * ** * ** * * * * ** **** * * i = 0; i < size-1; i++){
** * * * * ** * * * ** ** * ***** * * ***** *** ** * ** * ** * i-th element with its neighbor to check if they are in order */
**** *** * ****** ** * ****** * ** **** * ** * ** * **** ** * * * ** > x[i+1]){
** ** ** *** * *** * * * * * *** * **** * *** **** **** * * * * ******* ** ** *** * * ** * exchange the values of x[i] and x[i+1] */
** *** ** * *** ** **** **** ** * ** ** ***** *** ****** * * * * * * * *** ** temporary; * ** * *** *** ** ** * * *** *
* * *** * **** * * * **** ** ** ** ** * * * * * * *** * * * * * * * * ** ** * **** **** = x[i];
** ***** * ** * * * ***** ** ** ** ***** *** * * ** *** *** * ** * ** * * ***** ** * * * *** = x[i+1];
* *** * * **** * * ** ****** * * * ** *** ******* ** * *** * *** * * ** * **** ** = temporary;
**** *** ** * **** * * * * **** * *** * * *** * * **** *** ****
* * * ** ***** ** * * * * * ** * ****
** ***** ** * ** **
* * * * ****
* * ** ** ** *** * * print the array */
* * ** ** *** * * *** * * sorting: \n");
* **** ** *** ** * * i = 0; i < size; i++){
* ** ***** ************* * *** ** *** *** * *** *** ", x[i]); * ** * * ****** *** ** *** * ** * * *
* * * * ** * *
** ** * * ** * * ** * ** ** *
* * * * ***** *** **
* * * * *
** ** ** *** * * ** **** * * * *
**** * ******* *** * * * ** * ** * ***  
* ** **** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * ** * x[] = {77,22,88,11,22};
** * **** *** ********* ** size = 5;
    
* *** * * ***** ** *** print the array */
**** * * * *** * * ** ** i = 0; i < size; i++){
* ** *** ** * * * * * **** * ** ** ** * * * * * ", x[i]); ** ** *** ********** ** * ******* *
**** **** * * * * * *** *
* **** * * ** * * ** *** * *
***** * *** * * * * * **** *
**** * * ** ** * * * ** * * I need this to happen size-times */
* **** * *** * ** * ** ** ** * * * j = 0; j < size; j++){
**** * * * ***** * * * * *** * * * ** **** ** *** from left to right */
*** ********** ** ** * ** * * ****** * * i = 0; i < size-1; i++){
* * *** ** * ** *** * * ** * * * * *** * * *** ***** *** ** * **** * i-th element with its neighbor to check if they are in order */
**** ** * ** **** * ** * * * ** * * * ***** * ** * *** * ** ** * * > x[i+1]){
**** * * * ** ** ***** ***** ** ***** * **** * *** * * ** * * ******* * **** * ** * * exchange the values of x[i] and x[i+1] */
** * * * * ** * **** ** ** * *** ** * * ** ** ** * * * * ** * ** **** ** *** temporary; **** *** ** * ** *** * * * * *
* * * * ** * * ** * * ** * * ****** * * * ** ** * ** ** *** ** ** ** * * * ** * * *** = x[i];
** * **** * *** ***** ***** ***** * * ***** * * * * ** ******** ** ** * * = x[i+1];
** * * * * * **** * * ** ** **** **** ** * * * * * * * * * * ** * * **** * ***** ** ****** * = temporary;
****** * ** *** ** ** * **** **** * * **** *** * * * ** **
* ** * * ** * *** ***** * ************ * ** *
*** * *** * * ***
* ** * * *
** * * ** * *** * *** *** print the array */
* * * * *** * *** ******* * * * sorting: \n");
* *** * ** * ** i = 0; i < size; i++){
*** ** * * *** * * * ******** * * * * * * * ** *** ", x[i]); **** * ** ** ** ** * * * **** **
***** * *** * * *
** ** * **** * ** ** *** ** * ** *
* *** * *** ** ***** *
* *** ** **** *
* * * **** * * *** ** * * ** *** *
* ** * * * * ** * * ** ** *** **** * *  
* * * **** * ******* * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * * ****** ** x[] = {77,22,88,11,22};
**** * ** * ***** *** * size = 5;
    
* * * ** ** * ** * * print the array */
*** ****** ************ * * * i = 0; i < size; i++){
* * * * ** ** ***** ** * ** * ** * *** ", x[i]); ** ****** * * * *** ** *** **
** ** *** * * * * *
* ***** ** *** * ** * * * ** * *
** ** * ** *** * * * *
*** * ** ** **** **** I need this to happen size-times */
* ** * *** ** * ** *** j = 0; j < size; j++){
** *** * * * ** * ** * ** * * ** * * ****** ** ** from left to right */
* ** ***** * * * * * * ****** * * * * * i = 0; i < size-1; i++){
*** ** *** ** ** ** * ** ** * * *** ** *** ** * * * * *** * * ****** **** * i-th element with its neighbor to check if they are in order */
*** * * * ** ** * * ** * ** ** * ** * * *** * ** > x[i+1]){
* ** *** * **** ****** * **** * * ** ** *** * *** *** * ** * ** * *********** * ** exchange the values of x[i] and x[i+1] */
** *** * * *** * * ** * * ** * ** * * * * ** *** * * * * *** * *** * * temporary; ** *** * **** ** * * ** * ** ***
*** * *** ***** ** ******* * *** ******** ** **** * ** * *** * ** * * ***** *** *** = x[i];
* ** * ** * *** *** * **** * * ** * ** **** * *** * * * * * * ** *** * * * *** = x[i+1];
* * * * * ** ** * **** * * * * ** ** * ****** * ** * * * ** ** * * ** *** = temporary;
*** ** * ** ** * ** ** ** * * ****** ** * ** ** ** ** * * **
**** *** * **** * ** * * ** ******* * * * *
** * **** ** * **** * ***
** ****** * ** * ** *
* * ** ******* ** ** print the array */
**** * * * * * ** * * * * ** ** * sorting: \n");
** ** ** * *** ** ** i = 0; i < size; i++){
******* * ** ** ** ** *** ** ** ** ****** * ** ***** * * ", x[i]); * * ** ** * *** ** * *
* ***** * ** * ** ***
* ***** * * ** ** ** **** * *****
* * ** * *** ** **
** * * * * ****** * * *
** *** * **** *** *** * * ** *
*** ** * * * *** * ** * ** ** * * *  
* * * * ** *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** *** * **** * * x[] = {77,22,88,11,22};
* * ** *** * *** * ** size = 5;
    
* *** ***** *** * * * print the array */
* * *** ** * i = 0; i < size; i++){
***** * * **** * * * * *** ** * * * * * ** ", x[i]); * ** **** *** * * ** **** **
*** * * * ** * ** **
* * *** ** *** * * ** ****** ****
** ** * * * * *
* * ** * ** ** **** I need this to happen size-times */
*** * * * * *** * * ** j = 0; j < size; j++){
* ** * ** ***** * * ****** ***** **** from left to right */
**** * ** ** * * * ** *** * * **** *** * * i = 0; i < size-1; i++){
*** * ** *** * ** *** * ** ** * * * ** * *** ** * ** ** * ** *** ** * i-th element with its neighbor to check if they are in order */
****** * * ***** * * **** ***** *** ** * * *** ** *** * ** *** > x[i+1]){
** ** * *** * * * *** * * * ****** ** *** * ** *** * * * * * * ****** *** ** exchange the values of x[i] and x[i+1] */
* **** * **** * * * * * * * ** ** ** *** ** * * * ** **** *** *** *** ** * ** ** temporary; * *** ** * * **** ** * ** * *** *
*** * ** **** * ** * * * * * ** *** ** ***** * * ** * *********** * * ** ** * * = x[i];
*** * * * ** ** * ** *** ** * ******* * **** ** * *** *** * ** ** *** ** * * ** * = x[i+1];
* *** * * * * ***** *** ***** ** * * ** * * ** * * ** * ***** * * * * ** * ***** * * ** * *** * = temporary;
***** * ** ********** *** ** * * ** ***** ****** * * * * ***
* ** *** *** *** **** * ** ** *** * * **
******* * * * * * * ** ** *
* **** * ******
**** * ** ** ** ** ***** print the array */
*** *** **** *** * ** * * * sorting: \n");
* * * * ** * ***** * * * i = 0; i < size; i++){
* * *** * * * * **** * * ** **** ** * * * ** * * ", x[i]); * * *** *** ** * * ** *
** **** * ** * * ** ** **
* ** * * *** ** *** ** * * * ** **** *
* * * * ** * * * *
* ** * **** * * * ** * *** **
* * ** * * ** * ** ** ** * ** * ******* ** **
* ** ** * ** ** ** * * ** * *****  
** **** * ** *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * *** **** x[] = {77,22,88,11,22};
* * * ** * ** ** * size = 5;
    
* *** *** * * * ** **** print the array */
**** * ** ***** * ***** * * i = 0; i < size; i++){
* * * ** * * ****** ** * ****** **** * * * ****** ", x[i]); * * * **** ****** * ** * **** * *
* ** ******* * * *
***** **** * *** ** * * *** ** * * **
* * ** * * ** * * *
*** ** * * * ** *** ** ***** I need this to happen size-times */
* * ** ** * * * j = 0; j < size; j++){
******* **** * **** * ** ** * *********** ***** ** * from left to right */
* * ** *** * * ** * ** * ** ** * * * i = 0; i < size-1; i++){
* * ** * * *** * **** * * ** * ***** * ** *** *** * * * ** * * * i-th element with its neighbor to check if they are in order */
* * *** ** ** * ** **** *** **** ** * * * * * ** ** ** ** * *** > x[i+1]){
* ** **** * *** * ** ** * ** * * ** ******** * **** * * * ******* ****** ** exchange the values of x[i] and x[i+1] */
** * * ** *** * * * * * ** *** * * *** ** ** ** * *** ** ** *** * *** ** **** ***** ** **** **** temporary; ** * ** * ** **** * * * * ** ****
* ** ** **** *** * * ******* *** ** * * * ** * * *** *** * * * * *** **** ** * * * = x[i];
* * * * * * **** * *** ***** ** * * * * *** * ** ****** * ********** ** ** * * * = x[i+1];
* * ** * ** **** ** * ** *** *** * **** **** *** * ** ***** * ** * ** ** * * *** ** ***** = temporary;
***** ** * ** * ** * * * * * ** ** *** *** ** ** ** * ** **** * * *** *****
***** * * * *** * * * ******* * *** * * * *
******* * * ** * * ** * *** *
* * * ***** ** **** ***
* ***** * * **** print the array */
* ******* ** ** * * * * **** **** ** ** sorting: \n");
************ * * *** *** *** * i = 0; i < size; i++){
* * * **** *** * * * ** * * * *** *** ** * *** ", x[i]); *** * ** * *** * ** ** **** *
* * ** *** ** **
*** ** * *** * * * ** ***** * * ***
* ** ** *** * * ****
*** * **** * ** * * ***
** *** * ** * * * ** ** * * * ** ** *
* * * ** ***** ** ** * * ** * * ** ** * * ***  
* * ** * * *** *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * * x[] = {77,22,88,11,22};
* * * * ** **** **** * size = 5;
    
* ** ** * ** ** ** * ** print the array */
* *** **** * ** * *** ** * * i = 0; i < size; i++){
** * * * *** * *** * *** ** * * * ** * * *** **** ", x[i]); ** * *** **** **** **** * *
* *** * * ** * * *
** * ** * * * * * * * ** ** ** *** *
* * ** ** * * * *
***** * * *** * ** I need this to happen size-times */
*** * * ********* * * ** j = 0; j < size; j++){
** * * * * * * * ** ** * ** * ***** * from left to right */
******* *** ** * ****** *** * * * *** ** *** * i = 0; i < size-1; i++){
**** * * ** * **** * * ** ** * ***** ** * ** * *** * ** * * * i-th element with its neighbor to check if they are in order */
** *** ** ** ******** ** * ** ** *** * *** * * ** * **** * * > x[i+1]){
** * ** * * * * * * * * * *** *** *** ** ** *** * * * ** ** ******** ** *** ** * exchange the values of x[i] and x[i+1] */
** * * ** * * * * * **** * * **** * ****** ** * * *** * ** ** ** * * ** ** temporary; * * * * ** *** * * *
**** * ** ** * ** * ** * *** * * ***** ** ** ** ** * * * ** * * * ** * * * *** * * = x[i];
* * * * * * *** * *** ****** * * * ** ** * * *** * * * ***** ** ** * * ** * * * = x[i+1];
* ** * ** * ** *** ** * * * * * ** * * * * * * ** ****** * ******** * * * * ** ** ** = temporary;
* ** * *** * * * ** **** ** * ** * ** ***** ***** *** *****
** * ** * * *** *** **** *** ****
**** *** ** *** * **
*** * * * * ******
** * * * **** * * *** print the array */
* ** * * * ** **** ** * * *** sorting: \n");
* * ** ** * * ** * * i = 0; i < size; i++){
* ** ***** * * * * * * ** *** ****** ******* ** * ", x[i]); * * * ** ** * * * * ** ** * *****
* ** *** * * * ** ** *
**** * * **** ** * * * * * *** *** *
***** * * * * *** * * **
* *** * ******* * *****
* ** **** * *** **** ** * * * * **
** ** * * * * * ***** * * * ************ *  
* ** *** * ** ** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.67
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users