0 like 0 dislike
6.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 6.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ***** ** ** ** * * x[] = {77,22,88,11,22};
*** * *** * * * ** * * size = 5;
    
****** ** * * **** * print the array */
** ** * * * ** * *** ** * i = 0; i < size; i++){
** ******** * * ** * ***** * * * ******** ** ", x[i]); * * * *** *** ** * * *
*** ****** * **
* * ** * * ** ** * * ** * * **
** * **** ********* *** *
* **** * ** * * * I need this to happen size-times */
** ** ** ** ** * j = 0; j < size; j++){
**** ** *** * * * * ** * * ** * ** *** ** from left to right */
* ** * ** *** ***** * ** ** ** ***** * **** ** i = 0; i < size-1; i++){
** ***** * * * * *** ** * **** ** ******** * ****** ** * * ** i-th element with its neighbor to check if they are in order */
** ** * * ** *** * * * * * ** * * * ****** * **** ** * > x[i+1]){
* *** * * ** ** * ** * * * * ******** ***** * ***** * ** ********* * *** *** ** ***** * * * **** exchange the values of x[i] and x[i+1] */
* ** * ** * * * ** * * * **** * * * ** * * * **** ******** * ** * * *** * * ** temporary; *** * * *** * *** ** * *** *
* *** *** ** **** * ** * * **** **** * * ***** * * ** ** * * * ****** ** **** ** *** = x[i];
* ** *** * ** ****** * *** *** * * ** ** * * ** ** * * * * *** ** *** ******** = x[i+1];
*** * * * ** **** * * * ** * *** * *** *** ***** ** * * ****** * * ***** ** * * * ** = temporary;
***** * * ***** *** ** **** ** * ** * ******** * * ** * * * * **
* * * ** * ** * ** * ** * * ** ** ** * ** *
* *** * * * ** ***
**** * ** *** * ***
***** ** ** * ** *** print the array */
* * * ** *** **** *** ****** sorting: \n");
**** ** *** ** * * * i = 0; i < size; i++){
* ** *** * * * * * * * * ***** *** * **** ** ", x[i]); * ** * ** * ** ** * *
* * ***** *** **** ** * **
*** **** * ** **** * ****** * * ***
**** ** * * * * * ***
* * ** **** ** * *
** ******* * * * * ** ** * ** * * ****
*** **** ** ** *** * ** *** ** * **  
*** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
****** * * * **** ** x[] = {77,22,88,11,22};
** * * ***** ** *** size = 5;
    
** *** *** ** ** * print the array */
* ** ** ** ***** * * * * ** i = 0; i < size; i++){
** * ** * *** * * * * * ** ** * ** * * *** ", x[i]); * * ***** ** ** * ** **** ****
* * * ** * ** ** ** ** *
* ** *** * * * * * * ** *
* *** * * ** * **
*** ** * ** * ** * I need this to happen size-times */
* ** ** *** ***** * **** j = 0; j < size; j++){
* ** * ** ** ***** * * ** ** * * ******* ** from left to right */
* ** ** * * ** ** * ** * * *** ** * ** *** * i = 0; i < size-1; i++){
* * ** * * * *** * * * * ** ** ** * * ***** ** * *** * * ***** ** * i-th element with its neighbor to check if they are in order */
** ** * ** * *** * **** **** * *** * ** * *** ***** * * * * * > x[i+1]){
** ** * * *** *** ** * ***** * ***** * * *** ***** *** * *** * * * * * ** * * * exchange the values of x[i] and x[i+1] */
** * * ** * ** ***** ** ** *** ** ** ***** * *** * *********** ** * * ** * * ** ** temporary; ** ** *** * * ** *** *********
* * * ** ******* ** * ** ** **** ****** * ** ***** ** * **** ** * * ** ***** ***** ** **** * ** * * * * = x[i];
* * * * * ***** *** * * ***** * ** * * ** *** * *** * * ** ******* **** ** = x[i+1];
** ** **** ** *** ** * * *** * * * ****** *** ******* ***** * * ***** * *** ** = temporary;
** * **** * * *** ****** * * *** ** **** * ** * * ******** ***** **
** * *** *** * *** * * * * ** * * * * ******
* * * ** ** *** *****
** * * **** * * ** ***
* ** * *** * ** ** * print the array */
* * ***** * * *** * ** ** ***** ** * sorting: \n");
**** * * * * * ** * i = 0; i < size; i++){
** * * *** * ** * * ** ** ** ** **** * * * * ", x[i]); * ** * ** * * * * ***** *
*** ** ** ** * ** * *
* * * ** ** *** **** ** * * * *** * ** ** **
* * *** ** ** * * *
* ** * * *** * *
*** ** * * *** * * * **** ** **
* *** * ** * **** * ** * *** ** *** ***  
** ***** ** * ********* ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** **** * * * *** * *** x[] = {77,22,88,11,22};
* *** * ** * ***** ** * * size = 5;
    
** * ** * *** * * ** **** print the array */
* ** **** ** *** ** * * *** * i = 0; i < size; i++){
**** **** ** ******* ** *** * * ** * * ** *** * * * ", x[i]); * ***** *** * ** ** * * * *
****** ***** ** ****
* * *** ** * * * *** * *** * * * * * *
** * ** **** *** *
** * ** ** *** I need this to happen size-times */
** * ** * * * ******** ** ** j = 0; j < size; j++){
* ** * * * * ** * ** ** **** ** * from left to right */
** * **** * *** ** * ** * * * * ***** ** * ** * i = 0; i < size-1; i++){
** ***** * * ** **** ** *** * ** *** ***** ** ** * *** ** ******* i-th element with its neighbor to check if they are in order */
*** * * * * ******** ** ** *** ** ** * ** * *** **** * *** ** * * * * > x[i+1]){
** ** ** ** * ****** * * ** * * * * * * ** * ** * *** ** * *** *** * * * ** *** * ** exchange the values of x[i] and x[i+1] */
** * ** * * * * ** * *** * ** ** ** *** * * ** * **** * ** *** * * * * **** * *** * ** * temporary; * ** * ** * * * * * *
***** * * * * * ** ** ** * * * ** ** ** **** * * * *** ** *** * * * * ** *** * ** ** = x[i];
* * *** * * * ** * *** * * * * *** * ** ****** * ** * * **** ** ** * ***** = x[i+1];
* * * **** * ** ** * **** * * ** *** *** * **** * ** * * *** ** ** **** * * ** *** * *** = temporary;
* ** * * * *********** **** * ** ** *** ** *** * * * * * *
** ** ******** * * ***
** * ***** ** ** ******
* * **** ** * ** * *
* **** ** * * * * * print the array */
** * * * ** * *** * * ** sorting: \n");
** * * *** ****** ** ** * ** i = 0; i < size; i++){
* * ***** * * * *** *** ** ** ** ** * * ********* ", x[i]); * * *** ** * *** * ** ** **
*** * ** *** ** * **
*** ******* * * *** ** * * ** * *** **
* * *** * ** **
* **** * * * *
* * * * * ***** * * *** *** * *
* * *** ** ** * * ** * *** * * * *** * **** *  
** * * * ** * * * * ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * ** ** ** ** ** *** * x[] = {77,22,88,11,22};
** * ******* * ** * * * size = 5;
    
* **** * ***** * print the array */
*** * * * ** *** **** **** i = 0; i < size; i++){
* ** ** *** * * * * * * ******* ***** * * * * ", x[i]); * ** *** * * * **** *
* * * * * * *
* ** * ** * **** * ** ***** ***
* ****** * * ** ** **
* ** * * ****** * I need this to happen size-times */
*** * ***** * * ***** * * * j = 0; j < size; j++){
**** *** * * * *** ** ***** *** * **** **** * from left to right */
* * * ** **** * ** * *** ** * * * * * ** * * * * i = 0; i < size-1; i++){
* *** ** ** * * ** *** ** ** *** * **** ** * * * * ** * * ** * * * ** * i-th element with its neighbor to check if they are in order */
* ** ** * *** * *** * * * * * ** ** *** * *** * * * ** *** * * > x[i+1]){
** * ** * * * ** ****** **** * ** *** *** * **** ********* ********* ** **** *** **** ** * *** ***** exchange the values of x[i] and x[i+1] */
* *** *** * * * * ** ******* ** * * ** ** * *** ** ** * *** * * ** *** *** temporary; * * * * ** * * ** * * * * ***
* * ***** * * ****** ***** ** * * ** * * * ** * ** ***** ** ** ** * ** * = x[i];
* * ** * ** * * * * * * * * * * ** *** ** ** * ** ***** *** * * *** ** * * * * * = x[i+1];
* ** * *** * ** * * * ** * * * ** * * * **** ***** * * *** **** ** *** * **** * = temporary;
* **** ***** * ***** ** * ** *** * ** * ** ** * ** * * * *
*** * ** ** * * ** ** * *** *** ** * * * * *** *
* * **** * * * ** **
** * ** * *****
*** ** ** * * ***** print the array */
***** * * * ***** ** *** * * sorting: \n");
* * **** ** ** ***** i = 0; i < size; i++){
* * * * *** * * * * * ** * * * ** ** * *** * * * *** ", x[i]); * * * * * ** ** * ** * **
** * *** *** *** **
* * * * ***** ******** ***** ** * *
* * * * * *** *
***** * ** * * * * * * *
** ** ***** * *** * * * * ** **
****** * * *** ***** * ** ** * * * *** * **  
**** ** * ** *** * *** ** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ***** *** * ****** x[] = {77,22,88,11,22};
** *** *** * ** * *** * ** * size = 5;
    
* ** * * * ** * *** print the array */
* * **** * ** * * * i = 0; i < size; i++){
**** **** ****** *** *** **** * ******** * * * * *** ** ", x[i]); ** ** ** *** * **** * ** **
* * * * *** * *
* *** *** ***** *** * * ** * * ** ***** **
* *** ** *** ** *
** ***** ** ** ** * * * I need this to happen size-times */
*** **** ** * **** * * * *** j = 0; j < size; j++){
* * ***** * ** * * * * **** *** * *** *** from left to right */
**** ** *** * * * * **** ** * ** * ** *** * ***** * i = 0; i < size-1; i++){
* * ** * ***** *********** * * **** * * * ** ** * * * ** * ** i-th element with its neighbor to check if they are in order */
* * * ** * * * **** * **** ** ** * * * * * ** ** * ** * * * *** ***** ** * > x[i+1]){
* * * * *** * ******* * * *** ** * * * ******* * * ** * * * ****** * * **** exchange the values of x[i] and x[i+1] */
** * ** * * ** * ** **** ******* * ** ********* ** * * ** * * *** * ** * * *** ** * temporary; *** * *** ** * * * ** * * * *** *
* ***** * * ****** *** ** * *** * * * ***** * * ** ** * * * * **** * * ** ** = x[i];
* * *** *** *** * * ******** ** ** ** ** * *** *** *** ** * * ** ** * *** ***** * = x[i+1];
** ***** ** ** * ** * * *** * ** * *** ****** * ** *** * * ** * * ** **** * = temporary;
*** * * * ** ** * * * * * *** * * * ** * * * * * *
* ** * * * ** * ** ** ** *** * ** *** * *
*** *** * * * * ***** * *
** * ** * * ** ** * * * *
* * * * * * ** ** *** print the array */
* **** * * * **** *** ****** * sorting: \n");
*** * * * * ** ** * **** * i = 0; i < size; i++){
*** *** ** * * ** * ** * ** * * * ** * * ** * * * * * * ", x[i]); * * *** ** *** * *** *** **
* * * ** * * ** * **
* ** * ** *** * ** * * ****** *** *** * * **
*** * * **** * **
** * *** ** *****
* * * * * * * ** ** ** * ** * **
* * * * * * ***** * * * *** *** ** * *  
* *** * *** **** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** * ** * ** ** ** * x[] = {77,22,88,11,22};
* ** * **** ** * * * size = 5;
    
** * *** * print the array */
** *** ** * **** ** * * ** i = 0; i < size; i++){
* ** * * *** * ** ** * * * **** ** * ** * * ** * * ", x[i]); ** * * ** * * ****
** ***** * * ** **** **
* *** *** * **** ** ** * * ***
** * ****** ** *
**** *** ** * I need this to happen size-times */
* * **** ** * *** ** * ** j = 0; j < size; j++){
**** ***** * * * ** * * * ** **** * ** * * * * * *** from left to right */
* *** ** ** * * * * * ** * ** **** ** ** *** i = 0; i < size-1; i++){
** *** *** **** * *** ** * ** * * * ** ** * ** *** * ** * * ** * ******** *** i-th element with its neighbor to check if they are in order */
* * * *** ** * * * ****** *** *** *** ** * * * * **** * ** * * *** > x[i+1]){
**** ***** ** ** * * ** * * **** **** ** * * * * ***** *** **** * * **** * ** * exchange the values of x[i] and x[i+1] */
***** *** * ** * * * **** * *** * * * ***** ** * ** * ** *** * * *** * * * temporary; ** * *** ** * *** * ** ** * * *
* * * * *** *** * * * * ** ** * *** **** *** ** * * * * * * ** ** * * * * ***** * = x[i];
* ** ** *** ** ** ** ** * * *** *** * ** ** * ** * * ** ** ***** **** ** *** * * * *** *** ** = x[i+1];
** * *** ** *** * ** * *** ** ** ******* *** ** * * * *** *** ** * ** = temporary;
** * ***** **** *** ** * ***** ** * * **** * **** ** * * ** *** ** *
* **** ** ** * * ** * * *** *** *** * *** * ** *
** * **** * *** * * * ** *
* * ** *** *** *
**** ** * * ** * print the array */
* * ***** * * * * * ** ** * ** * * sorting: \n");
***** * ** **** *** ** i = 0; i < size; i++){
** ** * * ** * * * * * **** **** ***** *** ****** * * ", x[i]); * * **** * * **** * * **
* **** **** * *
**** ** * ** ** **** ** ** ***
** ** * * * * * * **
* *** ** *
* * ** **** * * * * ****** * ****** * * ** *
**** * * ******* ** ** ***** ** ** ** *** ** **  
* * * *** * *** *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * * * * * x[] = {77,22,88,11,22};
**** * * *** * * * size = 5;
    
** ** * ***** * *** * * * print the array */
* * * ***** **** ** *** * * * * i = 0; i < size; i++){
** ** ****** * * * * * * ** * ** *** * ** * ", x[i]); ** * * * * * *** *** ***
* * * *** * ***** ** * *
** * ** * * *** * * * * * ** **** * *
** * * * **** * ****
* * ***** * * ** ** *** I need this to happen size-times */
* * * * * * ** * ** ** * *** j = 0; j < size; j++){
* * * * ***** ** * * * ** * ** ** *** * ***** from left to right */
* *** *** * * * * * * * * * ** ** * ** *** i = 0; i < size-1; i++){
*** * *** * * ** * * ****** * ** *** **** * ** * * ** ***** ** i-th element with its neighbor to check if they are in order */
* * ** **** ** ** * ***** ***** ** * ** ** *** * ** *** ** * ** *** > x[i+1]){
****** *** * * * *** ** ** ** ** * **** * * ** ** * * *** ** * *** * ******** exchange the values of x[i] and x[i+1] */
* *** ** * * *** * ** * ** ** * * ** * * * *** ** * ** * * **** ** * *** * temporary; ***** ***** * * ** ***** *** **
*** ** * *** * * **** * * *** * * * *** *** * * ** * * * * * * * ***** ** ***** * = x[i];
* * * * * * ***** *** *** * *** * * * *** * * * ***** ** ** * * ** *** * * * ** ** * * = x[i+1];
** ** * * * * ** * **** * * ** * ** * * ** ** * ** * ** * * *** = temporary;
** ** * *** * * * *** ** **** * ** * * ** * * ** *** *** * * **
*** ** * * ** *** * * * * *** *** * *** *
** ** *** ***** ******
* ** **** ***** **** **
* * **** * * ** print the array */
** * * ** * **** ****** *** * * * * sorting: \n");
* * * * ** ** ** ** ** * i = 0; i < size; i++){
*** ** ** * * * * ** * *** *** * ** * * ******* ", x[i]); **** * ** * * * * * *
* * ****** ** ***** *** *
* ** * * * ***** ** ** ** * ** *** * ***
* ***** * ** **** **
* ** ** * * ****** * *** *
**** * * ** * **** *** * * * * *** ** * *
* *** * ** * *** * *** * ** ** * * * *** ** ** *** * *  
* * * ** ** ** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * *** * * * ** *** x[] = {77,22,88,11,22};
* * *** **** * * ** * ** *** size = 5;
    
** * ** * ****** * * print the array */
** * * * * * ******* i = 0; i < size; i++){
** * ** * *** ** * *** **** * * * * * * ** ***** * * * ", x[i]); ** *** * ***** * ** ** * ** * *
** * *** * ** * * ** * * ***
* ***** ** * * ** ** ** ** ** * *
*** * **** *********
***** * * * * * * I need this to happen size-times */
** **** **** * ** * ** * ** * j = 0; j < size; j++){
** * *** * * * * ** ** *** *** ** ** * from left to right */
** * ** * * *** ** ** ****** ** i = 0; i < size-1; i++){
* **** *** *** ** * * * * ******* *** **** * * * *** *** *** * * * * i-th element with its neighbor to check if they are in order */
** ** * ***** ** * ** *********** ** ** * * * * * * * ****** ** *** > x[i+1]){
*** * ** * * * * * * **** ** * ** *** * * *** ** *** ***** **** ** * * **** * ** * * exchange the values of x[i] and x[i+1] */
* * *** ** * **** * * * * * * * * * *** *** * * * * *** **** * ** temporary; ** * ** ** *** **** ***** *** * ***
****** *** *** * * ** ** * ** ***** ***** *** **** **** *** ** **** * ** **** ** * = x[i];
** ** ** **** * * * *** * ** ******** * * ** ** *** * * * ** * *** ** *** **** **** = x[i+1];
* * * * * * *** ******* * * ** * *** ** ***** *** ** ** * ** *** * * ** ** * * = temporary;
**** ***** ** * ** ** * * * * **** **** * * **** ** * ** * ** *
** ****** * * * * **** **** * ** * * * * * **** * **
* ** *** * * *** * * **
*** * * **** **
** * * * ** * ** ** * * * print the array */
*** ***** * ******* * * **** * ** sorting: \n");
*** * ** * *** ** * ** i = 0; i < size; i++){
** *** * ******* ** * ** ** * * ** ** ** * ", x[i]); *** * * * ** * *** ** ****** *** * * **
** ** * ** *** *** **
* * * ***** * ** ** ** * * * *** *
* * * ** * ** *** ****
*** * *** * * *
**** *** **** ***** * ***** * ***** **
* ** **** * ** ** * ** *** * * * * *  
* *** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * **** *** ********* * ** x[] = {77,22,88,11,22};
* * ***** * * *** ** size = 5;
    
* * *** **** ***** *** print the array */
** * * *** * ** ** * ****** i = 0; i < size; i++){
* ***** * * ********* ** * **** * * ** * * * * ** * * ", x[i]); **** ** * * * * *** *** * * * *
* * ***** ** * * * * ***
* ** * * * * * * **** * * ** ** * * *** *
* *** * *** * *** ***
** * * ** * ** *** ** I need this to happen size-times */
* * * ** * * ** * ** **** * j = 0; j < size; j++){
* * ** * * *** * ** **** * ** **** ***** *** * ** from left to right */
* ** * * ** ** ** ** ***** **** * * * * i = 0; i < size-1; i++){
** ** * *** * * * ** *** ***** * *** * * * ** * *** * * * * i-th element with its neighbor to check if they are in order */
** *** * ** ** * * **** * ** **** **** * ** ****** ** ***** * * > x[i+1]){
*** ** ** **** ** * * *** * * * ****** ** * *** ** *** * * * * * * * **** *** exchange the values of x[i] and x[i+1] */
* * ** * * **** * * *** * ** *** **** **** * ** * * * ** * ** ***** * * * * temporary; ** * * * * * ** * ** * **
* *** ** * * * * * ** * * *** ************** ** * * * * * ** * * ** * * * * **** * ** = x[i];
* ****** * ** * ** ** *** * * * * *** *** ** *** * * ** *** *** *** * ** ** * = x[i+1];
* * ** * ** ** ***** **** *** * *** *** *** ** ** *** **** ***** ** **** * * * = temporary;
** ****** *** *** * **** ** * *** * ** * ** ** ** ** * ***
** * ** ******* * * * ** ** ** * * ** * * ** *
** **** ** * *** *******
** *** ** * **
** * * *** ** * * ** print the array */
*** * * * * *** * ** * * sorting: \n");
* * * * * **** * ** ****** *** i = 0; i < size; i++){
* ** * ** ** ** *** ** ** * * ** * * * * * *** ** * ", x[i]); * * * ** **** * ** * * * * **
* ***** **** ** * *
* **** **** * * * **** * * ** ** * * ***
** ** * ** *** ** *** * *
*** *** *** ** ** * **
* * *** *** ** ** ***** ** * * ** * *
****** * * * * ** * *** * **** ****** *** * ** * **  
* *** ** * ** ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** *** * ** * * x[] = {77,22,88,11,22};
* * ** ** * ** * **** size = 5;
    
* ** *** * * * ** * print the array */
*** * * ** ******** i = 0; i < size; i++){
* * * ***** * * * * ** *** * * * ** ** * * * *** * * ** *** ", x[i]); * ****** * **** * *** * * * *** *
* ** * * ***** ***
* ** * ** * *** ** **** * ***
** * ** *** * ******
* ** * ** * ** **** * * * I need this to happen size-times */
** * * ** ***** ** * *** j = 0; j < size; j++){
** **** * * ** * * ** * * * * ****** * from left to right */
* *********** * ** * * * * ***** * ** ** ** i = 0; i < size-1; i++){
**** *** ** * * ** * ** *** * * ** ** * ** ****** * **** ** ** ** i-th element with its neighbor to check if they are in order */
* * ***** * * ** * ** *** ** * ** ** **** ** ** * * * **** * * > x[i+1]){
** ** ****** ** *** * ** * * ** *** ** * **** * ***** ***** * * * * * * ***** * * ** exchange the values of x[i] and x[i+1] */
** * * ** *** ** * * *** ** ****** *** ** **** * *** **** * *** ** * * * temporary; * * * * *** **** ** * * *** * **
* * ***** * * * * ** *** *** * *** * * **** * * *** * * ****** * * * ** * * = x[i];
*** * ** **** * *** ** *** * * * * * ** * ** *** * ** * * = x[i+1];
** *** * * ** * *** *** * ** * * *** * * ****** * ** * ** ** ** * * ** ****** ** * ** ** = temporary;
* ** ** ******* * ** * ** * * * *** ** *** *** * * ***** *** * * * * *
** ** *** **** ** * * * **** * * * *
* *** ** * * *** ** *
** * * ** ** * * *
*** *** ** ** ** ** * print the array */
* *** * ****** * *** * ****** ** sorting: \n");
** * ** *** ** **** * * ** i = 0; i < size; i++){
*** **** * ** ** * *** * **** * **** * ** * ", x[i]); *** * **** ****** * *
* ** * * ** ** * *
** *** * ***** ** * *** **
** ** *** * **
* *** **** * **** * * *
*** ** *** * * ** * * ***** * ** * **
** * ** * * ** ** ** * * * ***** ** * *  
* * * ** * * *** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.192
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.2k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users