0 like 0 dislike
8.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * ** ** * ** * *** x[] = {77,22,88,11,22};
* *** * *** ******* size = 5;
    
***** **** ***** ** ** * print the array */
* ** ***** * *** ** * ** * i = 0; i < size; i++){
** * ** *** * * * * * * ** * *** ******** *** ", x[i]); * ******* ** * * * *** * ***
** * ** * **** **
* ** ** * * * *** * * * ** *** **
****** ** *** * *
*** * * ** * ** * **** I need this to happen size-times */
*** ** * ** * ** * * j = 0; j < size; j++){
* *** * * **** * * ** **** *** * * * *** * * * from left to right */
*** ** * * * ** * * * ** * * * * * **** i = 0; i < size-1; i++){
* ***** ** * ** **** * ** ** **** ** ** ** ** ** * * ** * ** * *** * i-th element with its neighbor to check if they are in order */
*** **** * * * * * *** * * * * ** ****** * * * * ** * * * ** > x[i+1]){
** * * * *** * * *** * * ** ******* ** * ** * ** *** ********* *** * * **** exchange the values of x[i] and x[i+1] */
** ** **** * ** ** ** * ** * ** **** * *** ** * *** *** * ** * * * * * * * ******* * * temporary; ** ** **** * * ** * * *** * * *
***** * * * * ** * * * * * * ** *** * * * ** ** * * **** * * * ***** * ** = x[i];
*** * * * ** * ** ** **** ** * **** * * ** *** ** ** * * * **** ** ** * ** ** ***** **** = x[i+1];
* * * ** * *** * * ****** * ** ** ** * *** * * * * * ** ** ** * * ***** * = temporary;
** * ** * * * * *** * * * * * * * * ** **** ** ** ** **
* ***** * ** * * ****** ** * ** *
* * * *** ***** **
* * ** *** * ** * **
* * *** * * ** * ** print the array */
*** *** * ** ** * ** ** ** ** sorting: \n");
****** * ** ***** ** **** i = 0; i < size; i++){
* ** * * * *** * ** * ** * * *** * * * ** ** * ", x[i]); * * * ** ** * * *** * *** *****
* *** * * ** * ** *
* *** * * * * ** ** ***** * * * * ***
* *** * * **** ** * **
* ** * ** ** *****
* ** * ** * *** * * * * *****
******* * ** * * * * *** * *** ** **** * ****  
** * ** ** ********* * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** *** ** * x[] = {77,22,88,11,22};
** * * * *** * * size = 5;
    
** *** * * ** ** print the array */
** ******* * ** * * i = 0; i < size; i++){
* * * ** * * ** *** * * * * * ******* ***** ** ** ** ", x[i]); * ** * ** * ** * * ** * *
* * * ** ** *** ** ** *
* * * * * *** * ** ** ** *****
** * * *** * *** ** **
* * * ** *** * * * I need this to happen size-times */
* ** ** ** *** *** **** j = 0; j < size; j++){
* ***** ** * * * **** **** ***** ** *** *** * * from left to right */
* ** * ** * * * ** **** * ****** * * * * i = 0; i < size-1; i++){
**** * * *** * * * * ** * * *** ** ** ** ** * * ** ** * *** * * * i-th element with its neighbor to check if they are in order */
*** ** * **** * * * *** ***** * ** * ** ** ** ** ** * ***** * * > x[i+1]){
* * ** * * * **** * *** **** * ** * ** ** **** ***** ** * ** **** ** ** ****** **** * * ** * exchange the values of x[i] and x[i+1] */
* **** * * ** * * *** ** * * * ** ***** ** **** * **** * * *** *** * * * * * ***** * * * temporary; * * ** ** * ** *** ****** ***
**** * * ** *** * * *** ** ** * ** ** * * ** * ****** ** * * ** * * * * **** * = x[i];
* ** ** * *** *** * *** * **** * * * * ***** * ***** ** * *** * * * ***** ** **** ** * ** * = x[i+1];
*** *** ** ** ** *** *** ** * **** * * *** * *** * * ** * ** *** ** ** * * *** * * * = temporary;
*** ****** * ** **** *** ** * *** *** * ** * * * * * * ** **** *** *
** ** * * *** *** ** * *** * * * **** * * * ***
** ** ** * ***
*** * ** * ** * * *
** *** *** * ** **** * print the array */
* * *** * **** **** * * ** sorting: \n");
* * * *** * ** * *** * * ** i = 0; i < size; i++){
* * * * * ** ** ***** ****** * * * * * ** **** * ", x[i]); ** **** * * * ** * * ** *
* ** * **** * *** *
** ** * * **** ********* ***** *** ** *
* * * *** ** *** * ** *** *
** ** ****** * ****
** * * *** ** * * *** *** ** ** * **
* ** *** ** * * * *** ** * **** ** ** ** *** *  
** * * * ***** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * **** ** ***** *** x[] = {77,22,88,11,22};
*** * ** **** ***** * size = 5;
    
* ** * ** ** * * * print the array */
* ***** ** * ***** ***** * i = 0; i < size; i++){
* * **** ** * * * * *** * *** * * * * ***** ** ** * ", x[i]); * *** * *** ** * * * * * * * **
* ** ** * ***** ****** **
* ** * *** ** **** ** * * * * *
**** * * ** ** **
* ** * *** ** ** **** * * **** I need this to happen size-times */
** ** * ******** *** * * j = 0; j < size; j++){
** * ****** *** ** *** ***** *** * ** * * ** * from left to right */
* * * ** * * **** ** ** ** * *** *** **** ** i = 0; i < size-1; i++){
*** * *** * * * * ** *** *** * * ***** * * * ** * ** ** * ***** ** * i-th element with its neighbor to check if they are in order */
* **** * * *** * * ** * * ** * * ** **** ** * * * * * > x[i+1]){
** **** * * *** * ** * * * ** ** ** ****** * * * ** *** ** * * *** * * * * **** ******* exchange the values of x[i] and x[i+1] */
* * **** * * *** *** ** * * * * ** ** ** * ** ** *** * ** * ** ** **** * * * * * * *** temporary; * * *** * ***** ** ** *
****** ** *** **** ** * *** * * * * *** * * * ** * ** * * **** * ** ** ** * * ** * ** = x[i];
* * ** *** * * ** ** * *** *** **** * * ******* * ** ** ** * * * * * * * **** * * = x[i+1];
** **** ****** * ** *** *** * *** *** ** * * * * ** ** ** * * ** *** ** * * *** * * * * = temporary;
* ** * * **** ** * ** * ** * *** * ** ** *** ******* * * * * * * *****
**** **** * *** **** *** * * ******** *****
** ******* * * * *** **
*** * * ** *** * *
*** * * *** * ** print the array */
* * * * * *** *** * ***** * * * *** * sorting: \n");
** **** ** ** * ** * i = 0; i < size; i++){
** * ** * ** *** * ** *** * * ** * * ", x[i]); * ** *** * * * ** * ***** *
* * * * ** ** **
* *** **** ** ** * * * ** * * * * ** *
* * * ***** *** * * * *
* * * ** * * * * *
*** * * * * * * ***** * * * * *** ** *** *
* * ** ** * * * ** * * ** ** ** * * *** ** ***  
** *** ** *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * * ** x[] = {77,22,88,11,22};
* *** * * ***** **** * size = 5;
    
** * *** * * * **** ** * print the array */
* *** **** * ** * ** *** i = 0; i < size; i++){
* ** ** *** * * *** * *** ** * *** * ** * **** ", x[i]); * ** * * * * ** * *** *
*** * **** * *
* * *** * * ****** * *** *** ******* ****
* ** * * * ** * *
* * * * * *** * * I need this to happen size-times */
* * ** * * * *** ***** * j = 0; j < size; j++){
* *** * * ***** * *** * ** * * ** ** from left to right */
* ** * ** * ** ***** ** * * * * * ******* ** i = 0; i < size-1; i++){
** * *** * *** * ** * * * * ** ** * * ** * ***** ** ** ***** * * ** i-th element with its neighbor to check if they are in order */
* * ** * ********* ***** ** ****** ****** ** ** *** * ** * **** ** * * ** > x[i+1]){
* ** * ** * ** *** * * ** ** ** ** **** * ** *** *** * ****** * ** ******** ***** * * exchange the values of x[i] and x[i+1] */
** ** ** * * *** * * * * ** * *** * * * * * * * ** * * * * * * ** * ** * ** *** * temporary; * ** *** * * * * ** * ** *
** * * ******* * * * *** *** * ** **** *** ** *** **** ** ** ****** ****** * * * * * ** **** = x[i];
* **** * * **** *** **** ** * ** *** * * **** * * * ** * * * * * **** * * ** * *** = x[i+1];
** *** **** * * * ** * ** * ** **** ** * ***** ** * * * *** * *** *** * *** ** * = temporary;
* * * * ** * *** ** ** ** * * * *** ** * * * * * **
******* * * *** ** ** ** * * ** ** * ******
* * ** *** ****
** * * *** * * *
** * * * *** *** * * *** print the array */
** * *** * ** * ** ** *** ** sorting: \n");
* **** * * * * * ** * **** i = 0; i < size; i++){
*** * * ** ** * * * ** * ** * ** ** ** **** ", x[i]); * *** ** * *** * * * * *
* * ***** ** * ***
* * ** * * * ** ** ** * * **
* * *** * ** * * *
* **** * ** * * * ***
**** ** *** * *** *** * ** * * **
** *** * **** *** * *** *** *** * * ** ** *** *  
* ** * * ** * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * * * **** x[] = {77,22,88,11,22};
** ** ** **** * * ** *** * * size = 5;
    
*** * ** * ** * * * *** ** print the array */
** * ********* * ** * * ** i = 0; i < size; i++){
* *** * * * **** ***** * * * ***** ** * * ** * ", x[i]); ** * *** ** * *** * ** ** * *** **
**** ** ** * * *** *** *
* ** * * *** ***** **** * ** ** * ** * ** *
* * ** * *** * ***
** *** **** *** * I need this to happen size-times */
** * **** **** **** j = 0; j < size; j++){
**** * * ******* * *** * * ******** ** from left to right */
* * ** * ** **** ** * ****** * **** * ** ** * * * * i = 0; i < size-1; i++){
******* * * * **** ** ***** * * *** ** ** ** * * *** ** *** * *** * *** ** *** * i-th element with its neighbor to check if they are in order */
** * * ** ** **** * **** * ****** ** * * * ** ** ** ***** * * * * > x[i+1]){
** * * *** *** *** *** *** * ** *** ** * * *** * **** *** * *** * *** *** * ** *** * ** * * * exchange the values of x[i] and x[i+1] */
* * ***** * ** ** *** * ** * ***** * ** **** **** ** * * * *** ****** **** * **** **** * temporary; *** *** ** * ** ** * * * *
***** * * * * * *** * **** ** * * * * ** ** * * **** ** ***** * * * *** * ***** * * = x[i];
* * * * * ***** * *** * ** *** ***** * **** **** *** * * **** ** * * * ** = x[i+1];
* * * * * * ****** *** * * * * * * * * * * ** ** ** * ** * * * * * ** * * * ** ** * = temporary;
****** **** ***** * *** ** * * ** * ****** * **** * **** * *** ** ****
* *** ** * * ** * * * *** ** * ** **
** ** * * ** *** ***
* * * ***** ** ** ***
* * * * ** *** ** * * * * print the array */
* * ** * * * * ** *** ** sorting: \n");
*** * ** ** ** * * ** * *** * i = 0; i < size; i++){
* * * * ** ***** * ** *** ** ****** ****** * ** * * ", x[i]); ** ** * * * * ** ** ** * * *** *
***** * * * * * ** * ** *
*** * ** * * ** **** ** ** * ****** **
** ** * ** * ** * * *** ***
** * ** * ** * * *
* ** * * * **** ** ** * ***** ** *
* * * ***** * ****** * ** * *** * * *  
* * ** * * ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * ** x[] = {77,22,88,11,22};
* * * *** *** *** * * * size = 5;
    
* ** ** ** * **** * print the array */
* * * * * ** **** * ** * i = 0; i < size; i++){
** ** ** ** ** * * ** * * ** ** * * **** * * * ** ", x[i]); ** ** * * * * ***** * * * * **
** **** * *** ** * *
**** * * * * * ** ** *** ** * ***
* * * * **** ***
*** * *** ***** * ** * * I need this to happen size-times */
** *** *** ****** * ** * j = 0; j < size; j++){
* * ** ** * * * ** ** * ****** * *** **** * from left to right */
* ** * ******** *** * * * * * * ** * * * ** ** i = 0; i < size-1; i++){
* ******* ** *** ** ** ** *** * * ** *** ** * * ** ** * * ** i-th element with its neighbor to check if they are in order */
**** * ** * * ********** ***** ***** * ** *** ***** * * ** * ** > x[i+1]){
* ** * * ** * * ** ** * * ** ** * ***** *** **** * * * ** * * ** * ****** * *** exchange the values of x[i] and x[i+1] */
*** *** * * ** *** ** * *** ** * * * ** * ***** ** ** *** *** ** ***** * * * ** temporary; * * *** * * * * * * * * * * **
** * *** * * * ** * **** ** **** * * ** * * * *** * * * * ** ** * **** ** ** * = x[i];
* *** ** * * ** * * * * *** * ** *** ** * ** * * * *** ****** ****** * * ** * = x[i+1];
* ** * * * * ** **** *** ** * * ** * *** ** * ** ** * ** ** ** * ** * ** * * * ** = temporary;
* * * *** * * ***** * * ** ** * **** ***** ** * **
*** *** ** ******* ** *** * * * **
* * ***** *** * * * ** *
* * **** * * *****
* *** * *** * * * ** * print the array */
* * ***** ** *** * **** *** ** ** * * sorting: \n");
* * * ********** * * * i = 0; i < size; i++){
* * * *** ********** *** ** * ** * ** * *** **** * ", x[i]); ** ** * ** * **** * * ***** * ** **
** *** * ** * * **
* * * **** * ** ** * ** ****** * * * *
* * * *** ** * ****
**** * * **** * *
* * * *** **** *** ** * * ** *
* * * * * * * * ** * **** ** ***** ** **  
*** * *** ** * **** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** * * *** ** * * * x[] = {77,22,88,11,22};
* ** * ** ** * ** **** ** size = 5;
    
* * * ** ** *** ** print the array */
* * * * ** ** ** *** ** i = 0; i < size; i++){
* ** * * * ** ** * * * *** ** * ***** *** ", x[i]); ** ** * *** **** * *** * ** ** ** * *
* *** * * ** * **
** ** * * *** ** * **** * ** ** *** **
* * ** ******** ***
** ** *** * * * * * I need this to happen size-times */
** * * ** * * ** j = 0; j < size; j++){
* ** *** * ******** ***** * * * ** * ** * * from left to right */
* **** ** * * * ** **** ** *** * *** *** * * * **** i = 0; i < size-1; i++){
* * * * * ** **** * ** * * *** *** * ** * ** * ** * * * *** *** * i-th element with its neighbor to check if they are in order */
**** * *** *** * * **** * * *** ***** ** * * * * * * * ** > x[i+1]){
* *** ***** ** **** ***** * * ** * ** **** ** * * *** * **** * ** * *** exchange the values of x[i] and x[i+1] */
* ** ** * ** * * ***** ** ** ** * * **** * *** *** ** * * ** *** * * * temporary; ******* ** ** * * * ***** ****
* ** * * * * ****** ** * ** * * ** * *** ** **** * * *** * * * ** ** * *** ** * * ****** = x[i];
** ** * * * * * * ** * ***** ** ** * * ** ** ** * ** ****** * ******** * *** *** ** ** *** * ** = x[i+1];
*** ** * * ** * *** * * ** *** * ** ** * * * *** * ****** ************ * * * * ** ******* = temporary;
************* ** * ** *** * * * * * * ** * ** ** ***** ***** ** *
** *** ** * ** **** * ** * ****** * * * *
* ** ** * **** * * * * *
* **** * ** * ** * ***
** * ** *** * ** print the array */
** * ** * ** * * * * *** * * * sorting: \n");
* **** * ** ** ** i = 0; i < size; i++){
*** *** * * ** *** **** ** *** *** * * * * * * ", x[i]); * * ** ** *** ***** * *******
*** ** ** ** * ***
***** ***** ** *** * ** **
** * *** ** * ** *
** * * *** * * **
* * ** *** ** *** * *** ** * * * * ***
* ****** * * ****** * ** * ** * * **** ***  
******** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** **** ** * ** x[] = {77,22,88,11,22};
* * **** ** * * *** * * size = 5;
    
** ** **** * * * * * print the array */
* * * *** ** **** * i = 0; i < size; i++){
* *** ** ** ****** ** * * * * ** **** *** * ****** *** ", x[i]); *** ** **** * ** ** * ****
** **** **** * * **** ** *
* ** * ** *** ** * **** * **
******** * * * ** *
** ** * *** ***** *** ** I need this to happen size-times */
** ***** ** ** * *** *** ** * * j = 0; j < size; j++){
** * * *** * * ********* * * * *** *** * * from left to right */
***** * ** * * * ******** ** **** * **** ** i = 0; i < size-1; i++){
** * ** * ** **** * * * * **** ** * * * *** ** ****** * ** *** ** i-th element with its neighbor to check if they are in order */
** ** * * * * ** **** ***** *** ** * * ***** **** * ** * ** * *** > x[i+1]){
* * ** * * ** ** *** * * * ** * * ****** * *** *** * ** * * ***** *** * ** *** exchange the values of x[i] and x[i+1] */
* ******* * ** * ******* ** * * * * ** * * * * ** * **** ** * * * *** * ** * * * ** temporary; ** * * * * ** **** *** *** * **
* * * * ** *** * * *** *** ** ** * ** * * * * *** *** ***** * ** ** ****** ** ** * ** = x[i];
* ** * * * ** * *** **** ** * * * * *** ** **** * * * * ** **** * * * * ***** *** ** * * = x[i+1];
* *** * ** ** * ** ** ******** ***** *** *** ** ** ** ** * * * **** * * * **** ** * * ** * ****** = temporary;
* * * ** * * * ***** * * ***** * * * * * * * * ***** * *
* * * *** * *** * *** ** * * ** * *
** * * *** * *
* **** *** ** **** *
** * ** ** * *** * ** ** ** print the array */
* * **** ***** ** ** ** * * ** * sorting: \n");
** ** * ** ** * * * *** i = 0; i < size; i++){
** * *** * *** *** **** *** *** * ** * *** * * ", x[i]); ** ** *** * * * ** * *
* ** ** * * * * **
* * * * * ** * ** * *** * **
* * * ** * *** *** *
** *** * * *** ***
**** *** ****** * * * ** * * ***** * * **
*** * * ** * * **** * ** *** *** * ***  
*** ** * ** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** **** * *** ** * x[] = {77,22,88,11,22};
* ** * ** * * * * * * **** size = 5;
    
* ** ** *** * * **** print the array */
****** * * ** * * *** * **** i = 0; i < size; i++){
*** ** * ** ** * * * *** *** **** * ** ** * * ** * * ", x[i]); * * * *** * ** * *** **** ** * ****
*** * * * ****
** *** * * ** ** *** ** ** * ** ** * * *
** * * * * **** ***
** ** ** * * ** * ** I need this to happen size-times */
* ** ** ** * *** **** *** j = 0; j < size; j++){
* ** * ** * * ***** ** *** ** ** * ** ** from left to right */
* ** * ** ** * * *** *** * ** * **** * ** * ** * i = 0; i < size-1; i++){
* ***** ** ** * ****** * ** ** ***** ** * *** * * * * * * * i-th element with its neighbor to check if they are in order */
* * * ** * *** *** ****** * * * *** * * * * * * * * ** ** * * * ** > x[i+1]){
* ** ** ** * * * ** ** **** * *** * * * **** * * *** * * **** * * ** * * * * * exchange the values of x[i] and x[i+1] */
** * * **** * ** ***** ** *** **** * * * * *** * * ** *** ** **** *** *** ** ** * * ** * * ***** temporary; * ** ****** * *** ** **** * * **
* * * * * * ** * * * ** * ** ** **** *** *** *** ** * *** * ** * ** * * *** ** = x[i];
* * * * **** ** ** * * * * ****** * * **** * * * *** *** * ** * *** * * ** = x[i+1];
* ** * * * * ** * ** * * * * * * * * * *** * * * ***** ***** **** * ** = temporary;
** * * ** * * ** * * *** ** * **** * * *** ** * ** * * *
*** *** * * ** * **** **** * * * * ** ****
****** * * * * ***
********** ** * * * *
* * ** *** ** * ** print the array */
**** *** ** * * ** ****** *** * ** sorting: \n");
** *** ** * *** ****** i = 0; i < size; i++){
* ** ** **** ** **** * * *** * * * ** ** ** * *** * * ", x[i]); * * ****** * * * * * * * ****
* * ****** *** ** ** *
******** ** *** ** ** *** * * * * * ***
** * * ********* **
********* ** ** * *
* *** ** ** * * ** ** *** * ** * **
** * ****** * ** ** ** **** * ** * * * * * ** *  
**** * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * ** * * x[] = {77,22,88,11,22};
* *** * * ** * * * * size = 5;
    
* * * ** ** * * ** ** ** print the array */
* **** *** *** * ** ** i = 0; i < size; i++){
* * *** * * * **** * * ****** * *** * ** * ** ***** * ", x[i]); ****** **** * ** * *** ** *****
** ** * ** ** **** *
* * *** * ** * **** **** ** ****** * * *
* ** * * ** ******* * * *
* * * ** **** ****** * I need this to happen size-times */
** * *** *** * * * * j = 0; j < size; j++){
** ** * * * ** * * * * * *** * ** * * ** * ** from left to right */
** ** ** ** * * ** * *** ** *** ** *** ***** *** i = 0; i < size-1; i++){
***** * * *** * *** ** * ****** * * ** **** *** * * * * **** * *** i-th element with its neighbor to check if they are in order */
******* **** ** *** * * * * ** * *** * *** **** * * * * **** * ***** > x[i+1]){
* * *** * * * ** ** ** * * *** * ******** * ** * ** ** * *** * * * * exchange the values of x[i] and x[i+1] */
* * *** *** ** *** ** ****** * ** *** * ***** ** *** * * * ** ** * * * *** * *** **** * temporary; * * *** **** ** ** * ** *
* *** * ** ***** * * * * ***** ** * ** ** * * *** *** *** * **** ** * *** * = x[i];
*** * * * ** ** *** ** ** ***** * * ****** * *** * ** ** * ** **** * ******* ********* ** ** * = x[i+1];
* * **** * ****** *** * * ** ** * * * * * *** **** ** * * * * ** * * = temporary;
*** * ** * **** ***** * ****** * **** ** ** * **** * * * * * *** *
* *** ***** * ***** * * ** * ** * * ** ****** *
**** *** ** *** *
***** * * * * **** *
** * * * *** print the array */
* * *** * *** * * * * sorting: \n");
******** ********* **** * ** i = 0; i < size; i++){
* * **** * *** ** ** ****** ** *** * **** ** * *** ** ", x[i]); ** ***** ** * ** * ** * *
* ** *** * *** * *
** * ****** * ** ** **** * *** * * * * *
* * * ** * * **** * **
** *** * ** ** * *** * *
* * ** * * **** * * ** * ****
** * ** **** ** * *** ** *** * *** * * *  
* * ** * ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.33
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users