[Exercise 16] Arrays: Bubble-sort

Question

7k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64

[Exercise] Coding (C) - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited | 7k views

46 Answers

Page:

« prev
1
2
3
4
5
next »

410630017 · Answer 1 · 2017-12-20 14:35:47

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
 ** *  **   * *  *   *   ***  x[] = {77,22,88,11,22};
  *  * *   *  *  ***       * *  size = 5;
    
 *   * *  * * *** *  **  *   **  print the array */
*  ** *****  *  *    *  ** * ** *** i = 0; i < size; i++){
*** *  *   *   * **     *      * *********   ***   ******   ** * * * ", x[i]);   * * * *** *  *  *     ***** ** *** ** **  *
*  * **    *   * * *  *  *  **
 ** * *  *  ** ** * *  * ** ******   ** * *  **  *  *
****         * **   *  *  *
*****   * **  *   ***  *      ** I need this to happen size-times */
      ** *  *    ** * *   * **   j = 0; j < size; j++){
 *   ** *   **** **** *       ** ***  ****      *** * * *  from left to right */
 **  ***** * * **  * * ***   *  *   **      ***  * i = 0; i < size-1; i++){
 *  *    * **      * * **     * *  ****** ** *  *** * * *  * * *** ****** *** * * * ** * * ** i-th element with its neighbor to check if they are in order */
       *    *** *** * * * ***      ***   ***    ** *** **  *   *** * *** ** *********  **  **  > x[i+1]){
 * ***  *   * ***** * ***    * **** *   *****       *       * *  * **      **  ******     * ***** ** *   *  exchange the values of x[i] and x[i+1] */
*    * **   ** *****  *** *   **   *    * *  * ***    **  ****** ** ** *** ****  ***  * ** * ** **** * *  ****** temporary; **    *********      *  ***** ** **   *
*  *     *** ** * ****    **    *** **  *  * *      ** **  * * * ** * *   * ** **  ** *** ***** ****   * * **  = x[i];
** * * ** ****   *  ***  *  * ** **  *     ** * * ***** ** **  *  ** * *** * ****  ******      ** ***    = x[i+1];
** *      **   **    **  * * *  * *  * *** ** ** * **** *** *** ***  *  * **  ***** *  * *** *    *    = temporary; 
** ** ** * *****  *  * **** * * **** **   * *   **********    *** *     * ***    * ** * *  *
 * *** **   ** *  * *       * **  *  **  * * *   
*  * * ***   ****** * **
*     ***** * *  ** **  *   
  *     ***  ***      **  * print the array */
 **  **** *** *** *  ** **      * * *** * * sorting: \n"); 
  **  ** ****  *** * ** *  * * *  i = 0; i < size; i++){
  *  * *****  **** *  **** *   ** * * * ***   *  *  ****   **   * ", x[i]);  **** * *** **   ** * *****    * *** 
 *****      *    * ***  *
* * * * *  *** ** * *  ***  *** ******** * ** * * 
**   * * **  * *** *  **
     *  ***  *** **       *
   *  ***    *  * *   * ** ** *     ** *  ** *    * * *
  * **   * ** *** * ** *** **** *  ***** ** *** **  ****    
  **  **  * *  ***  *** *** ** 0;
}