[Exercise 16] Arrays: Bubble-sort

Question

11.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64

[Exercise] Coding (C) - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited | 11.6k views

46 Answers

Page:

« prev
1
2
3
4
5
next »

410630017 · Answer 1 · 2017-12-20 14:35:47

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**  * ***   * *   ****   ********* x[] = {77,22,88,11,22};
** **  * *** ***  * ***    size = 5;
    
** **      *   ****** ***  print the array */
** *   * *   * * * **    **  *   * i = 0; i < size; i++){
  * **** *  *    **  *  *   * **** * *  **     *  ** ***   **       * ", x[i]); *** *   *********     *   ****   *****
* *** ********  ****** * * * 
     * *** **   **** ** **       **    *** **  * ***
***  *** **  *  * * *** * 
**  **  ***    ****  *  ***  I need this to happen size-times */
 * **    * **  * *    *    ** * j = 0; j < size; j++){
 ** ** ** *  **** *  * *** *  * *  *** * ***  * *  * *** from left to right */
   ** * ***** *****  ** **  ** **  **  **  *  *   **  * *    *    i = 0; i < size-1; i++){
  *  **  *  ** ***   * **  * ** ****   ** * *   *  * * ****       *  ***  **  *     ***   ** i-th element with its neighbor to check if they are in order */
   *  ** *    *    *  * * ** ***  * * * ***** **** *** *  * ** ***** * * *    **** *   *   *    > x[i+1]){
 *****    * ** **      *  **  * * ** ***  ***     * *  *  ** *** *   *  * *  ***    *  ***** *  *  * * *** exchange the values of x[i] and x[i+1] */
 * ** *  ** ***    * ** *** ***  * ***  ** ***** *****    * * *****  **  *  ***** *** **  **  ** * * *   *  *   * * *  temporary;   *     ** *** **  * *  *    ***** *
*  ** *** *   * *  *   *  * ***** * * *********** ******* **  *  *** * ***    *  * ***  *** *       *  **** ****  * *  = x[i];
 **   **** ** *  ****  ***  * * *  *  ***  *** *    ** **  ** * * *  ***   ****   ** ** * *  ***   *****  = x[i+1];
*****   * *  * *****    *   * *** * * **  **** *  *  * ** ******* *    ****  *   *  * **  ******** ***  ** ** ** * = temporary; 
**** *  *       * ** * *  *  ****   *   ***    * **  **  ** *   **  *    * 
 * * ******  *** *   *** **  ***     *  * * ** ***    *
      ** ** ********* 
****   ***  *****  ** *
* **  ***   * *** **  *  *   *  print the array */
  **** **** ** * **  **   *    * ** ***** sorting: \n"); 
 ***  ** ***  **  **   * ****  *    i = 0; i < size; i++){
** *  ****  *  **  *  * ****** *  * ** *  *   ***  ***    *  **    **** ", x[i]); *******    ** *** *****    ** *** *    **   
* ****  *   *    *** ** ** 
 * *    **  *    ***  * ** ***** *   ** ** ****  
    *  * *  **         *** * *
*** *     *  ** * *** * ***  *
 * **   **     **  **     *    *** *  **** * ***  * 
 * *   * * *  *** *  *  *** * *  *  * *** *  *  ** ** *    **   
 **    *   *  ** * * *****  * * 0;
}