0 like 0 dislike
8.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** *** * ** *** x[] = {77,22,88,11,22};
** ** * **** * ** * *** size = 5;
    
** ** * ** * * print the array */
** * ** ** * * **** * * i = 0; i < size; i++){
* ** ****** **** * * *** * * * **** *** * ", x[i]); * * * ** * ** ** **** * **** ** *
* * * ** * * * * **
*** *** *** * *** * * **** * *****
* **** ** ** * * * **
* ** ** * * * * * **** **** ** I need this to happen size-times */
***** ********* * * ** ** * j = 0; j < size; j++){
** ** ** * **** * * ***** ** ** * * * *** * **** ** from left to right */
* ** * ** ** ***** * * * ** * * ** ** *** i = 0; i < size-1; i++){
** * * * * ***** * **** * *** * **** * * ***** * * * * ** * * * i-th element with its neighbor to check if they are in order */
******* * ** **** *** ** ** *** * ***** ** * ** * *** **** ******** > x[i+1]){
*** *** * ** * * ******* ** *** ** * ** * *** * ** ** ** * ** * ** * * * *** *** exchange the values of x[i] and x[i+1] */
* * * * * ** **** * ** **** *** * ** ** * * ** * * * * * ***** * * *** * * * temporary; * ** * * * ** ** * ** *
** * ******* * * * * ***** ** ** * * * *** * ** *** ** ****** * ** * * *** * * *** ** * * * **** * * = x[i];
** ** * ***** ** ** *** *** ** *** * *** ** * * * ** * ** ** * * **** ** ** = x[i+1];
* * * * *** *** ** * ** **** ** * ** **** ** ** ** * ****** *** ** *** ** = temporary;
** * **** ** ******* *** * *** ** * * **** * * * * * ***** ** *
* * * ** *** ***** * ** * * * * ** *
** * **** * * * * **
* * * ** ** * ******
** ** * * ** ** ** * print the array */
** * ***** *** *** * ** * ** sorting: \n");
*** * *** * **** * * * * i = 0; i < size; i++){
** * * **** * ** * * * * * * ****** **** **** * * ** * ", x[i]); * **** **** ** ** * *** * * *
* * * * * ** ** ** **
* *** * ** * * ** * * **** * * * *
* ** ** *** *** * **
** ** ** * ** * * * **
** * * * * * * **** **
**** ** *** *** * * * *** * ** ***** * *  
*** ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** ** *** * * * * x[] = {77,22,88,11,22};
**** *** * * * * ** **** ** size = 5;
    
** ** * *** * * ** * print the array */
** * * ** ** * ** ******** ** * i = 0; i < size; i++){
* *** ** ** ** *** * ** *** ** * ** * * ", x[i]); *** *** ** *** * ** ** ***** * ** *
** * * * * * * * **** *
** * * * *** **** *** ** ** * * ** ** ** *
* ** *** * * *** * * *
** *** * ** * * * ** * ** I need this to happen size-times */
* * * * ** ** ** * * ***** j = 0; j < size; j++){
* * * * * *** * ** * ** * ** * ****** from left to right */
**** ***** * ** ** * *** * * * * **** ** i = 0; i < size-1; i++){
** ** ****** ** **** * ***** * ** ** * ** ** ** * * * * * ** * ** ** * * * i-th element with its neighbor to check if they are in order */
**** ** ** *** * ****** ** * * * ** ** ** ** * * **** **** * ** > x[i+1]){
***** * *** *** *** ***** * * * * * * * * *** ** * * *** * **** * * *** ***** ****** * ** exchange the values of x[i] and x[i+1] */
*** * ** ** *** ** ***** **** * * *** * * * *** **** ** * **** * *** **** ** * * *** temporary; * ** * *** * * * * * * *** **
**** * ** * * *** ** * ***** ****** * ** * ** ** * * ** ** * ** * * *** * ** ** * = x[i];
** * ** * ** ** * *** *** * * ** ****** * **** * *** ******** * ******** ** **** = x[i+1];
* * * ** * * ** ** ** * * ** * * *** ** ** * * * * * * ** *** * ****** **** *** * ** = temporary;
** * ****** * ** *** * ** **** * * ** * *** * * ***** * * * *** *** *
*** ** **** ** **** ***** **** *** * ** * * *
* ** * ** ***** *
* ** * * ** * ** * ***
* ** * ** *** * * ** print the array */
** *** *** *** ** **** ** * * ** sorting: \n");
* * * ** * * * * i = 0; i < size; i++){
* * * **** ** ********* * * * * **** * * * **** ** ", x[i]); ** * ** **** *** * **** ** ***
* ** **** *** **** *** * *
* ** ** * ** * ** ** * * * * * ** * **
* ** * * ** ** * **
** * *** * ** * * ** ******
* ** **** * * * * ** **** ** ** *
* * * * ** * * * * * * * **** * * * ** *  
* ** ** ** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** **** *** * ** * * * x[] = {77,22,88,11,22};
********* **** **** * size = 5;
    
* ** *** * *** * *** print the array */
** ** * *** *** ** i = 0; i < size; i++){
* *** **** * ** * *** * * * * *** ** *** * **** ** ", x[i]); * * ** * * * * * * * *** *
*** * *** ** * ****
**** ** ** **** ****** ***** **** * * *
** ** ** ** * * *** *
* ** **** * *** * * * I need this to happen size-times */
** ** *** * ** ***** * ** * j = 0; j < size; j++){
* *** * ***** **** * * * ** *** * * ******** *** * from left to right */
****** * * * * ** * * **** *** * * * *** * ** i = 0; i < size-1; i++){
* ** * * * * ******* ** *** * * ** ** * * * * ** ** ** * ********* * * ** i-th element with its neighbor to check if they are in order */
* * ** * * **** * ** * ** *** * * ** * * *** * ***** *** * **** * > x[i+1]){
****** * * * * **** * **** * ** * *** **** * * ** ** * **** *** ** * ** * **** exchange the values of x[i] and x[i+1] */
*** * * *** * ** ** * * * * *** * ** *** * **** * * * *** * * *** * *** * *** * *** temporary; *** * * * ********* ** **
* * * **** * **** ** * * * * * * ****** ** * * ** **** * * * *** ** ****** * ** *** = x[i];
**** * * *** **** * * ***** ** ** ** ** * * ** ** * ** * ** ************ ** *** * * **** = x[i+1];
*** ** * *** *** * ** ** * * ** * * * * * * *** ** * * ** * * ***** ***** ***** = temporary;
* * ****** *** ** *** ** *** ***** ** **** * ** * * ******** * * *
* * * ** ** *** ** ** ** * *** * * ** * *
* * *** * *** * *
*** * ** * *** *** * **
* * **** **** * **** print the array */
** * ** *** *** *** * ** sorting: \n");
* * * * *** ** * * i = 0; i < size; i++){
** *** ** *** * * * * * *** * ** *** ** **** * ", x[i]); ** * ** * * * * ****** *** ** ***
* * **** ** * ** *
* ** *** * ** * ** * * **** * ** ** *
* ** ** * ** * * *
*** * ** ***** *
* * * * * ** ****** ** ** ***** *
* * ** * * ** *** * *** * * * ** * ** *  
**** *** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * ** ** * * x[] = {77,22,88,11,22};
* * ** **** * ** * size = 5;
    
* * * **** * * * print the array */
* * ***** ** * * * * i = 0; i < size; i++){
** * * * ** * *** *** ***** * ** * * * * *** * ", x[i]); *** * ** * * *** ** ** * *
** *** *** ** ** *** *** *
**** * ** ** *** * ** ** * * * * ** ** **
** ** * * * ** * **
* *** * ** * * * * ** I need this to happen size-times */
*** * *** * * * ** * * ** * j = 0; j < size; j++){
** * * **** ** * ** * * * * * **** * ** from left to right */
* ** * **** * * ****** * ***** **** * ** ** i = 0; i < size-1; i++){
* ******* * * *** **** * * * ** * *** ****** ** * **** * ** * *** i-th element with its neighbor to check if they are in order */
***** * *** *** ***** * * *** * * ** ***** ** * * * > x[i+1]){
* * * * * ** * **** ** ** *** *** ***** ** *** * **** ** *** **** ****** ** * * ** ** * * exchange the values of x[i] and x[i+1] */
**** * * * ** ** * *** * ***** *** * *** ** ******* * * ** * * ** *** * ****** ** ** * temporary; * ** **** * ** *** ****** * *
*** ** ** * * * * ** * * * * * *** ** *** * **** *** ** * *** * ** *** * ***** *** * = x[i];
** ** * ** * * *** * * ******* * **** * *** **** ** * * **** ***** * ****** * * * ** ** = x[i+1];
*** * * **** *** ** * ** * *** * ***** * * * * *** * ** * *** ** * ** * * * * ** *** *** = temporary;
***** * * **** ***** * ****** *** *** * * ** *** ** * * ** * * *
* ** ** * ** * ** ** * * * ** ** ******
** ** ** * * * ** ** *
* ** * ** ***** * *
* * * ** * * *** *** ** * * print the array */
** * ** ** * ** * * * *** * sorting: \n");
* ** ** *** * * * * ****** i = 0; i < size; i++){
********** * * * * * * * *** ** * ** ** * * * ** * ", x[i]); * *** * *** * * * * **** **
***** * * *** * **** ** *
* ** ** **** * * ** * * **** * ** ***
*** **** *** *** ***
** ** ** ** *** * *
**** ** ** ** ****** * * * ** * **** * *
*** * * ** *** ** ** * ** * * **** ** * * *  
**** * ** * * * ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** * * * ** ** *** * x[] = {77,22,88,11,22};
* * *** ******* ** *** * ** ** size = 5;
    
** * ** *** * ** **** *** print the array */
*** *** * * **** i = 0; i < size; i++){
* ** ** ** * ** ** ** * * ** ****** ** * ******** * ", x[i]); * * * * **** ** *** * * ** ** *
* * *** * ** **** * **
** ** * * * * * * * ** *
* * * ***** * ***** **
* **** * * ** * ****** I need this to happen size-times */
*** * *** ** * ** ** ** * j = 0; j < size; j++){
* * ** ** ** * ***** ********* ** *** * * *** from left to right */
* ** * ** ** *** *** ** ** * * *** * * ********* *** i = 0; i < size-1; i++){
** **** ****** * ** * * ********** * ***** ** * ** * *** ** * * * i-th element with its neighbor to check if they are in order */
*** ** * ** *** * * **** *** * * * **** * ** ** * *** * **** * > x[i+1]){
* * * **** *** *** * *** * * * * * * * *** * * * ***** ** ** * ** * * * * * ** * exchange the values of x[i] and x[i+1] */
* * * * * * **** * * ** * * ** *** **** * * **** * ** ****** * **** * * * ** temporary; *** * *** * * *** * ***** * **
* * ** *** * * *** * * ** * *** * *** * *** **** ** ** ** * ** *** * *** * ****** ** * = x[i];
** ***** * ** **** ** * * ** * **** *** * ** ****** **** * * * * = x[i+1];
* * * ** **** * **** ** * *** ***** ** * * * *** * * * * ******** * ** ** * * * * *** = temporary;
*** ** * ******* * **** ****** * * * ******* * ***** *** ** *
****** ** *** * * * **** ** ** ** * ** * *
***** *** * ** **
* * *** ** ** * * * ** ****
* * ** * ** ** **** * * print the array */
* * *** ** * * * * * * ** ** * sorting: \n");
* ******** * * * * i = 0; i < size; i++){
* * ** * ** * **** ** * * *** * * * * * ** * ", x[i]); ********** * ***** * ** **
*** * * * ** * ** *
*** **** * * * ** * * * *** ** * * *
** ** **** ** **** **
* * * * **** * **
** * *** * * *** ** ** * ** * *** * *
**** ** * ** * * * ** * *** * *** * * *** **  
* * * * *** * ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * ** * ** **** x[] = {77,22,88,11,22};
* ** * ** ** *** ** size = 5;
    
****** ***** **** * ** *** print the array */
** * ** **** * * **** i = 0; i < size; i++){
* * *** * ** * ***** ***** * * * ****** *** * ******* * ", x[i]); * * *** * ** * * * *** * ** ****
* *** *** * * * **
* * *** *** * ** *** * * * *** **
* *** ** ** ***** **
** *** *** ** * ** I need this to happen size-times */
*** * * * * * * ** ** j = 0; j < size; j++){
* * ** *** *** ** ** * ***** * ** *** * *** * * from left to right */
** ** * * **** * ** *** ** ****** *** * ** i = 0; i < size-1; i++){
***** ** ** * * *** ** ** * ** * * * *** * ** * * ** * * i-th element with its neighbor to check if they are in order */
*** * ***** * * *** *** * ** * * ** ** ** * * * * * ** * * > x[i+1]){
*** * *** *** **** * * ** ** ** * * * *** * * *** * * ** ** * **** * ** *** exchange the values of x[i] and x[i+1] */
* ********* ****** * * * * * * *** *** ** ** * ** ** * * * ** * ** * **** ** *** ** * temporary; * ****** ** * ** * *****
** * ***** * * ** * ** * * * ***** * * ** ***** * * *** ** * * * * ** = x[i];
*** ** *** * *** * ** * ** *** *** ** **** ** * * ** * * **** * * * *********** ****** *** * ** * = x[i+1];
* * **** * ****** * ****** **** ** * * * * * ** * ** ** * * * * * * * ** * * ** * * = temporary;
** * ******* *** * * * * * *** *** * ** ** * ** ** * *** * * * *
* ********** ** **** * * * * *** ***** *
***** ****** * ** *
* * ** * ** * *** ** *** **
* ** * * ** * **** * print the array */
* *** ** * * * **** **** * * sorting: \n");
* *** * * ** *** ** * i = 0; i < size; i++){
** *** *** ****** * ** ** * ** * ** * *** ***** ", x[i]); **** * * * * ** * **** * ** **
* * * * *** *** ** ****** ****
* * * ** * * * * ** * * ** * **
* * ** *** * * * ** *
****** *** * * **
** ** * ** * * ****** * ** *
***** **** * ** ** * ** * * ** ** ***  
** ** * ***** ** * ***** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** ** x[] = {77,22,88,11,22};
* * ** ** * ** * * size = 5;
    
* ** ** *** * * ** * * * * print the array */
** ***** ** ** **** i = 0; i < size; i++){
** ** * * * *** * * ** * * ** * * **** * * ******* ** ** ", x[i]); **** *** *** * **** * * ** *** ** *
* *** * * * * * ** ** ****
* * **** *** * * * ** * ** * * ** **** * ******
**** * * *** * *
* * * * * * ** *** * I need this to happen size-times */
* * * ** ***** * * **** j = 0; j < size; j++){
* * * ***** ** * ** **** * *** ** ** * from left to right */
* ** * ***** * ** **** **** * * ** * * * i = 0; i < size-1; i++){
* ** * * * * ** *** * * * ** * *** ** * ** * **** * **** ** *** * i-th element with its neighbor to check if they are in order */
** ** **** ** ** * ** **** * * ** ** **** * ** *** * * > x[i+1]){
* * ** * ** ***** * ***** * ** ** ** * * * * *** *** ** *** * * *** * * *** * *** * * * * * exchange the values of x[i] and x[i+1] */
* ** * * **** *** * **** * * * ** * * * *** *** ** ** ** *** *** *** * * * ** *** ***** ** ** temporary; * ** * *** ** ** *** * * ** *
** ** *** **** ***** ** * ** ** ** * ** * * ** **** * ** **** ** ** ** ** ** * * * * ** ** = x[i];
**** * * * ** * **** ******** ******* *** * ****** ** ** ** * ***** ** * * *** ** = x[i+1];
* * *** ** ** * * *** * **** * ** ** ***** * * *** * *** **** *** * * * * ** ** ** = temporary;
*** * ** * * ** *** * ** * ** * *** **** **** * * * * * * *
* * * **** *** * * * * * * * **
* * * *** *** * **
* * * ** ** * * *
** ** ** * ** ** * * print the array */
**** *** * ******** ** ** ** * ** * sorting: \n");
* ** *** * **** **** ** i = 0; i < size; i++){
* * * * *** * *** * * * * * ** * ** ", x[i]); * * ** * * * *** * * *** **
** * **** * *** * *
* *** * *** * ** * ** ****
* * ** * **** *
* *** ** ** ** * ** **
* * * * * ** ***** * **** * ** *
*** * *** ** ** * ** * *** **** * **** ** *  
* * ** * ****** ****** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** ***** ** ** ** *** x[] = {77,22,88,11,22};
** * ** * * * ******** size = 5;
    
* *** *** * ** ** *** * ** print the array */
* * * ** **** * * **** i = 0; i < size; i++){
* **** * ******* *** * * **** * **** * ", x[i]); * *** ***** * ** * ** *** *** *
* ** * * *** * * * *
* * * * ****** ** ** * * **** ******
* ** * *** * **
* ** * * ** I need this to happen size-times */
** * ** * *** * *** * j = 0; j < size; j++){
** * * * ******* * ***** * * * *** * * ** from left to right */
***** ** * **** * **** ** * *** ** ** * ********** i = 0; i < size-1; i++){
**** **** ******** * *** ** * *** ***** *** ** **** ** * ** ** ** * * * i-th element with its neighbor to check if they are in order */
*** * **** *** * ** * *** *** * * ***** ** * * **** * * > x[i+1]){
* * * *** * * * ** * ** * *** * * ***** * ** ** * * ** *** * * ** * * * *** * * exchange the values of x[i] and x[i+1] */
* * ***** ***** * *** *** ** *** ** **** ** ** ** ** *** * **** ** * * * * ** *** * temporary; ** ** ****** * ****** * ** ** ****
***** ** ** * * ** * * * * *** * ** ** * * * * * * ** * *** ***** *** ** ** * *** ** * = x[i];
** *** ****** * *** * * ***** * ** *** * ***** * *** * ***** *** * * * = x[i+1];
** ******* ** ** * * *** * * ** * **** * * *** ** * * * * * * * *** *** * * ** *** ** = temporary;
********* * * * * *** ** ** * * **** ** **** ** * * *******
** **** * * * * **** * * * ** * * ** * *
* ** * ** *** *** * ** * * * **
* * * * ** ** ***
** ** * ** * * * ** ** print the array */
** ** * * **** *** * *** * ** sorting: \n");
* *** * * ** * * ** * * i = 0; i < size; i++){
* * *** ** * **** * * * * *** *** * * ** ** ** ** * *** ", x[i]); * ** * * * * * *** *** * *
* * ** ** ****** *
** ** * ***** ****** ** **** * *
* * * * **** * * * **
**** *** * *
* ** * * ** ** * * ** * * * **
** * * ****** * * ** ***** * ***** * * * * * **  
* ** * * ** ** *** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ***** ** ** **** * x[] = {77,22,88,11,22};
** *** *** *** ** * * size = 5;
    
* * * * ** * ** * print the array */
** * ** ***** * * ** * * i = 0; i < size; i++){
** *** * ** * * * * * * *** * ** * * ", x[i]); ** ** *** **** *** ***** ** **** *
** *** ** ***** * ** *
**** ** * ** * ** ** *** ** *** **
* * ** ** ** *** **
** * ** ** ** * ** * I need this to happen size-times */
* * **** ***** * *** j = 0; j < size; j++){
* **** * * *** ** *** ** **** ** ** * from left to right */
* ** ** ** ** * * *** ** ** * * ** * * * ** i = 0; i < size-1; i++){
* *** * * * * * * ** * *** ** ** * ** * *** ** * * i-th element with its neighbor to check if they are in order */
* * ***** *** * * **** ********** * * * * * ** * ** *** **** * * > x[i+1]){
** * * ** * * ***** ** * **** **** ** * * * * ** * * * * * * *** * * *** * exchange the values of x[i] and x[i+1] */
* * * * * *** ** * ** ** ** * ****** * * ** **** * * * *** * * * ******* * * temporary; ** * *** * * * * * * ****
*** ***** * * ** * ** * * * ** ** * * * * * ** *** * ** * ** ***** * * * ** *** *** * = x[i];
** ** * ** ** * * * * ***** ** ** ** * ** *** ** * ***** ** **** * * *** * * = x[i+1];
* * * *** **** *** * * * ** ** * *** * *** * **** * *** * * ***** * * **** * ** = temporary;
* *** ** ** ** *** **** **** * ** *** ** * * * *** * ** *
* * * * *** ** * * * *** ** * **** * * * *
* * ** ** * ****
* ** ** * * **
* * * *** ** * * * *** print the array */
* * * *** *** * * * * * sorting: \n");
* ** *** ** * ******** ** ** i = 0; i < size; i++){
* * * ** ** * ** ** ** ** * * ** * ** **** ", x[i]); * ***** ** * ** * * ** *** ****
* ******* *** * **
** ** ** * ** ** ******** * * * *
* * ** * *
** * ** ** ****** * **
* *** * * * * ********** * * * * * ***
* **** ** * * ** *** * *** * * * ** **** * * *  
* * * ** *** * * ** ** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** *** * x[] = {77,22,88,11,22};
* ** ** * * size = 5;
    
* ** * * * * *** * print the array */
* ** * * * ** *** ***** * i = 0; i < size; i++){
* * * * * *** **** * **** ** ** **** ** * ", x[i]); * *** * * * * ** * *** * ** * *
*** *** **** **** *** *
* *** *** *** **** *** * * ** * * ** *
**** ** * * *** * * **
* * * * * * * **** * I need this to happen size-times */
* * ******* * * ***** j = 0; j < size; j++){
** * * * ***** * ** *** * *** ** * ** ** **** ** from left to right */
* * * * ****** * * *** * * **** ***** *** * * ** i = 0; i < size-1; i++){
* * ** *** * * * ** ****** * ** * ** ** *** * * * *** *** i-th element with its neighbor to check if they are in order */
* ** * * ******* * * ** *** ** ** * ** * ** **** *** ****** * * * ** > x[i+1]){
* * * * * *** *** * * * * * ** * * ** *** * * **** ***** **** ** * * * * ** ** * * ***** * * ** exchange the values of x[i] and x[i+1] */
* *** * * *** *** * * * * * *** ** ** ****** * * ** * ** *** * *** ** * **** ** ** * *** * temporary; * *** * * ***** * * ** *
* * ** ***** ** * ******* * ** ***** * ** **** ** * **** ** ** * ** * *** ** ** * ** ** ** = x[i];
**** *** * * ** *** * *** * * ******* * * *** * * *** * * * * * * * ***** ** ** * = x[i+1];
* *** * * * **** * * ** * * *** *** ** ***** *** ***** * * * **** * * ** * ** *** * * = temporary;
**** * ** * * * ** * ** **** *** ** **** * * *
*** **** *** ** * ***** ** * ***** * ** ******
** ** ***** * * ** * *
* *** *** * * * *** ***
**** ***** *** * *** print the array */
** ** * *** * * * *** sorting: \n");
* * * * ******* **** **** i = 0; i < size; i++){
* * **** *** * * * ** * **** * *** ***** ** ** * ***** *** * ", x[i]); * *** ** * ** * * * * * * * *
* **** ** ** * * *
*** * ** ****** ** * ** ** * *** ****
*** * * * ** * *
*** ** ** * ****** ***
*** ***** **** * **** **** * ** *
* * * ** ** *** * ** * ** * ** ** * * * ** **  
** **** ** **** * * * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.67
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users