0 like 0 dislike
8.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******** *** * * * * x[] = {77,22,88,11,22};
** **** ** *** ** ** size = 5;
    
* *** * * ** ** * print the array */
*** ** *** * ** * i = 0; i < size; i++){
* * * ** ** *** ** * * * * * ** ** * * * * ** ** ", x[i]); * ** * * * * * ***** ** * * * ** * *
** * * ** ** * * * * ***
****** * * * ** * ** ** ****** * *
** ** ***** ** *** ** *
* ** ** ** ** * *** * * I need this to happen size-times */
** *** * ** ** * ** * ** j = 0; j < size; j++){
**** ** *** * * ********* **** ** ** * from left to right */
** *** ** ** *** ** ***** ** * ** * *** *** * ** * i = 0; i < size-1; i++){
* ** * ** * ** * * ******* ** * * * * * ** * * **** * * * ** * ** * * i-th element with its neighbor to check if they are in order */
* ** ***** *** * * ** * * ** * *** * * ** **** *** ****** ** > x[i+1]){
** ** **** ** * ***** ** * *** ** ** * ** * * * ** ** ** * * ** * * ** exchange the values of x[i] and x[i+1] */
* *** * * ** * ** ** * * * * ** * *** * ** * *** * ** * *** * ** * * *** ****** temporary; ******* *** * ** ***** * * ** *** *
* ** * *** ** * ** * *** * * * **** * ** *** ** * * * ** * * *** * * * ** ** ** * * = x[i];
**** * ******** * *** * *** * ** * * * ** **** ** * *** ** ** ** * * * * * * = x[i+1];
**** * ** * ** **** * * *** **** *** * ** ** ** * *** *** * ** ******* * * ** *** * * = temporary;
* ** * * * **** ***** *** * * * * *** *** * * **** * *
* * ** *** * ** ** ** ** **** * * * ** **
*** *** * ** * *******
* ** ** ** * ** *
* ** * * ** **** **** print the array */
** * ***** **** * ** *** ** *** **** sorting: \n");
* * *** **** * ** * * *** * * i = 0; i < size; i++){
*** * * ***** **** ** * ******* * * **** ** * * * * * * ", x[i]); ** * ** ** *** *** * **** ** **
* ** ** ** ** * ** *
* * * * ** ** * * ****** ** *
* * * * * ***********
* ** ** * *
* * ***** * * * ** * * ** ** ** * **
* * * **** *** * * *** * **** **** ** * * * ***  
* * ******* ** ** ** ***** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ** * ** x[] = {77,22,88,11,22};
*** * * ** * * * size = 5;
    
* ** ** ** ** * *** print the array */
* *** ** * * ** * * *** i = 0; i < size; i++){
* ** * * * * ** *** ** ***** **** ******** **** ", x[i]); * *** *** ** * * * ** * *
** **** * * ** ******
* * * *** ** **** * ********* **
* * * * **** *
* *********** * * ** I need this to happen size-times */
* * * *** * * * ** *** j = 0; j < size; j++){
****** ** * * * * ** ** ** **** * * * from left to right */
* * ** * * * ** ** ** * **** ** ** ** **** *** i = 0; i < size-1; i++){
* ** * **** **** * * * ** ** * * * * ** ** ** * * * i-th element with its neighbor to check if they are in order */
* * ******* * * ** ** ** * **** ******* * ** ** * * ** ***** ***** * *** > x[i+1]){
*** * * ** * ****** ** **** ** ****** ***** *** * * * ** * * * exchange the values of x[i] and x[i+1] */
* ******** ** *** ** * ** ** * * * ****** ** * * * ** * *** ** *** **** * **** *** * **** temporary; **** * *** * * * *
**** ****** * * * * ** ****** ** * ** * *** * ** * * *** * **** * ** * = x[i];
* * * ** ** * * * * * * * ** * *** * * * ** ** ** *** * ** * * *** *** **** * * ** ** = x[i+1];
* * * * * * ** * ***** * * ** * * * * * *** ******* * * * ** *** * ** * ****** = temporary;
*** * * *** * ** * * * * ** ** * * * * * * * * * *** * ****** ** * * *
******* ** * *** ** *** ** * *** ** *** * * **
**** * ***** ******** *
* *** *** ****
* * * **** * ** *** * print the array */
*** **** * **** * * * * ***** ** * * sorting: \n");
**** ** ***** **** ** * **** i = 0; i < size; i++){
**** ** ** * *** ** **** *** * * * * *** ** ****** * * ** ", x[i]); * ** * ** * * *** * ** *
* * * * * **** *
* ** ** * * ** * * **** * *
* * * *** * ** ** * **
******** * **** **
***** ** *** ** * * ** ** * * **** * **** **
**** * ** ***** *** * * **** ***** *** * *** *  
* ***** * ** * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** ** * x[] = {77,22,88,11,22};
***** * ** * ** * * ***** size = 5;
    
* * ** *** **** ** *** print the array */
* **** * * * *** * *** * i = 0; i < size; i++){
* * *** ** ** * *** * * * *** ** * * ***** * * ", x[i]); ** *** ** * * ** * * * * * ** * * *
***** * ** * * * ** **
* * * ** * *** * **** * * *** ** * ** *
** * *** * **** *
* * * * * * * ** ** * * ** I need this to happen size-times */
* * *** * * *** ** * j = 0; j < size; j++){
** ** * *** * *** * **** *** *** * ** *** ** from left to right */
* *** ** ** * * ** ** * ** ** ** *** ** * * * * * **** i = 0; i < size-1; i++){
** * ** * * *** * * * * ** ** **** * ** ***** *** * * ** i-th element with its neighbor to check if they are in order */
** * ** ** * **** ** * * * * * * * ** **** * * * * ** * ** * > x[i+1]){
*** ** ** * * * ** ** ***** * ********* **** *** ** * **** * * * * *** ** * * ** * * exchange the values of x[i] and x[i+1] */
** * ** * * * *** * * * ***** * ** ***** **** * * ** * * * ** * ** * * * **** temporary; **** **** * ** *** **** *********
* * **** * ** *** *** * *** * * *** * *** ***** * ** * ** * ** ** ** * *** ***** = x[i];
** * ** *** * * *** * * ** * * *** *** **** ** ** * * ** ****** ** ******* * * * *** = x[i+1];
* * *** * * ** ** ** ** ** **** * * * *** * * ** ** * *** ** ***** * * * ** * *** * *** = temporary;
* * ** * * ********* * * *** * ** * * * * * * * ** ***** ** ** ***
**** ** *** * ** ** * ** * * * * ** * *** *
*** ****** * *** * ** ***
***** ** ** * * ****
* * ** * ** *** ***** print the array */
** ******* ** ** * ** ** * * ** sorting: \n");
* *** * * *** *** *** * i = 0; i < size; i++){
* ** ** ** ***** * ** * * *** * ** * ** * * * *** ** * ** ** ", x[i]); * ****** ******* * * * ****** **
* * *** **** *** *** ***
** * **** * *** ** ** * * * **** * *
* ** *** **** * * *
* *** **** * ** *
* * * ** * ** ** **** * * * * ** * * * *** *
**** * *** ** * * ****** * ****  
** * ****** ** *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * **** * ***** *** x[] = {77,22,88,11,22};
**** * * * *** *** * size = 5;
    
* ** *** *** * * * * print the array */
* * * ** *** ****** * * ** i = 0; i < size; i++){
*** * ** * **** ** **** * ** *** ** ** ** *** **** * ", x[i]); ***** * * ** * * * ** *
* *** ** * * **** * ** *
****** * *** *** ** * * * * ***** ***
* * ** * ***** ** *
**** ** ** * * * I need this to happen size-times */
*** ** * ** **** * ** * * j = 0; j < size; j++){
*** * **** * ** * ** * **** *** *** *** * from left to right */
* * * ** ** * * * * *** * * ** *** ***** ** i = 0; i < size-1; i++){
* * * ***** **** * * * * *** *** ** * ** * ** * * ** ** * i-th element with its neighbor to check if they are in order */
** * * *** * ** * ** ** ******* ** ** * * * * * ** ** * ****** * > x[i+1]){
****** * * * *** ** * * *** * * ** ***** * * ** * *** * *** * **** ** * * *** ** exchange the values of x[i] and x[i+1] */
* * *** * * * * * * ***** * *** ** * * * * **** * ** ** * ** *** * * ** * * temporary; * *** * *** * * *** ** * * * ***
* * * * * ** * * ** *** ** * * ** * * * * *** *** **** * * * *** * ** * * * * * *** ** ** = x[i];
* * * *** ** * *** *** * * ** * * * ** ********* * * ***** * **** * * *** *** * ******* * *** = x[i+1];
* ** ***** ** * * * *** *** * * * * * * * * * ** ** ** ***** ** **** ** ***** = temporary;
* *** ** * ** ** *** ** ** *** * * *** * * ** *** * ** * ** **
** * * ** **** ****** * * * * * ** * *
** * * *** * **** *** *
* *** ** * * ** *** *
**** ** ****** * * * print the array */
** *** * ***** ** ** * * * ** * sorting: \n");
* * * * ** * ** ** * * i = 0; i < size; i++){
*** * ** ** * * * ** *** ** * *** ** **** * * * * ", x[i]); ** *** ** ***** ** * * * * ** * ** * **
* *** * **** * * * *******
* * * * ** * ********** ** ***** * **
**** * *** ** * * *** * *
* * * **** * *
** * * * ** * * *** *** *** ** * * * **
* * ** * **** *** * * * ** ***** * * *  
*** **** * ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** ** * ** * **** * x[] = {77,22,88,11,22};
** * ** * * * **** ** * ** size = 5;
    
* ** * *** **** ** ****** print the array */
** * * *** * * ** * * * * i = 0; i < size; i++){
* **** * ***** *** * * ** ** **** * ** ***** * ** *** * ** ", x[i]); ***** * * * * * ** *** * *
* * * *** ***** * * *
*** **** * *** **** *** ** * ***
* ** * ** * ***** *
*** * * * *** *** * *** I need this to happen size-times */
*** **** * * ** ***** j = 0; j < size; j++){
** ****** * *** ***** * * * ** *** * ** **** * **** from left to right */
* ** * * *** ** *** * ** * * * *** ** ****** * i = 0; i < size-1; i++){
** *** ** * *** ** ***** * ** ** * * * ** * * * ** * ** * ******** *** i-th element with its neighbor to check if they are in order */
** * * ***** **** * ** * **** **** *** ** **** ** **** **** * ** > x[i+1]){
* * *** ** * ** ** * * ** * * * * *** ** *** ** * * ** ** * **** ** ** * * * *** ** exchange the values of x[i] and x[i+1] */
* ** *** * ** ** *** * * * ***** * * * * * ******* * * *** *** * *** * * temporary; ** *** * * *** **** ** * **
* ** * *** ** * ** * * * * *** *** * ** *** * ***** **** *** **** * ** *** * * ** *** *** = x[i];
** * ** * ** *** ** **** * ** * **** * * * * ********** *** ***** * *** ******* ** ** * * * ** * ** = x[i+1];
* *** * * ** * * * * * ******** * ** * * **** ***** ** ** ** * * *** ** * * * * = temporary;
* ** * ** ** ** * * * * * * * * ** * ******* * ** * *
* *** * ** **** * * * * * **** * * * *
** **** ** * * * *** ** *
* *** ** ********* **** *
*** * * * ** **** ** * * print the array */
*** * * ***** * * ** * * * * * * * sorting: \n");
* ** * *** ** i = 0; i < size; i++){
** * * * ** * * * * ** * * * * ** * * * * * * * **** * ** ", x[i]); ***** ** *** ** * ** ** * * * **** *
** * * * * *** * * *
**** ****** * * ** * ****** ***
* *** ** * * *** *
** **** ** ***** *** **
*** **** *** * * *** ** * ** * * *
* * * * ** * * * * ***** * *****  
* * * * ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * *** * *** ******** x[] = {77,22,88,11,22};
** * * * ** ** ** ** *** size = 5;
    
** * *** ** * * ** print the array */
* * * * *** ** ** ** * i = 0; i < size; i++){
*** *** * ***** * ** ** * **** * * * *** * **** * ** * * * ", x[i]); *** *** ** * * ** ** * ****
** **** ** ** * **
* ** *** * * * * * ** **** * * *
* * *** *** *** * *
** * ****** * **** * * I need this to happen size-times */
* *** ** ** ** ** ***** j = 0; j < size; j++){
* ** * *** **** ** * * ** ***** * * ** * ** from left to right */
* ** * ** * ** * * * * * * *** * ** * ** ** i = 0; i < size-1; i++){
*** * **** ** *** *** **** * ** ** * * * * * ***** **** ** * ** * ** ** i-th element with its neighbor to check if they are in order */
**** **** ******* * * * * ** ** * *** *** * ** * ******* > x[i+1]){
** ** * ** ** ** ** ** * * *** *** * ** * ** * * * * *** * ** * ** ** * **** exchange the values of x[i] and x[i+1] */
*** *** *** * * ** * ***** ** * * * * * *** * * ****** * * * ** *** * * ** ** * temporary; ** ******* * * ****** ** *
* ** ** * * **** ******* ********** *** *** * ***** ***** * **** * ** ** ** ** ** * * * * ** * = x[i];
* ** ** ** * * * ** * * * ** ** * * * * ** * ** * ** ** *** * * * ** * *** * * *** *** * * = x[i+1];
*** * *** ** ** * ** ** * ** *** ** *** * * * * * ***** ***** * * *** ****** ** * * ******* * = temporary;
** * * * **** * ** ** * *** *** ** * *** * * ** * * * * * * ** * *** *
** *** * * ** *** * * * * *** ** ** ***
**** **** * * ** *
* * *** * ** ** *
*** ** * * * ** ** print the array */
**** ** ** **** ** ** ** ** * sorting: \n");
** * * * *** * * i = 0; i < size; i++){
* ** *** * ** *** * * *** * *** * ** ** ** ****** ** * ", x[i]); *** * **** * ** * * ** *** *
* * * * **** * * * *
*** **** **** * ** *** ** * * * ****** *
**** ** * ** * **** * *** *
** * * * ** *** *****
* ****** ** * * ** ****** ***** * **** *
**** * * * *** * * * ** ** ** *** *  
**** ** * * *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** **** * x[] = {77,22,88,11,22};
***** *** * *** * * ** * * size = 5;
    
** * *** *** * print the array */
*** ** ** * ***** * i = 0; i < size; i++){
* * *** *** * * * *** * **** *** * * **** * * * * ", x[i]); *** * * *** * ** * * ** ** *** *
* ** * * * ** ** ** **
***** ** * * *** * *** ** * ** * *
*** ****** * *** *
** ** * *** * ******* I need this to happen size-times */
* * * ** ** ******* * * **** * j = 0; j < size; j++){
**** * ******* * * * **** ** ** ** * ** * from left to right */
* ** * ****** ** ** * * ** ***** **** * * i = 0; i < size-1; i++){
*** ** ** * * * * **** * ** * *** * * * *** * * *** **** *** i-th element with its neighbor to check if they are in order */
* ** * ** ** * * * *** **** * * * ** * * ** ** * * * ** ***** ** * > x[i+1]){
*** * * *** ** * * *** * * * ** ** ** **** ** *** * * ** ** * * * ** **** * * exchange the values of x[i] and x[i+1] */
**** *** ** ** * * * ****** *** * * * ******* *** * * * * **** * * ** * * * ** * ***** * **** temporary; **** * * * * * * * **** * * *
*** * * * * * *** ** * *** * ** ****** *** ** * ** * *** **** *** *** **** *** = x[i];
***** * * * * * * * ** ** ** ** * ** *** * * ** ** ** * * * * * * ****** *** *** ****** = x[i+1];
** * * ** ** * * * * **** * * * ** * **** ****** ** * * * ** **** * * ** * ** *** = temporary;
* * ** * * ** ** * ** * ** * ** ** * * ** * * * **
** * * *** * * ****** ** * * **** *** * *
* ** * ** * *** ***** * * *
*** *** ** * ** **
** ***** * * * * print the array */
** **** ** * **** ** * * * * sorting: \n");
** * * *** ** * ****** ***** i = 0; i < size; i++){
***** ** **** * ** * * ** * ** *** *** * ****** * * * ", x[i]); * ****** ** ** ** * ****** *
* * * * ** * * * *****
** * * * * * **** ** * ** * *
* * *** * * * ** **
****** **** * ** * * *
* *** ** ** **** *** * *
****** * * * ** *** ** * * * ** **  
* * * * * * ** ** ****** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** ** ** * *** * x[] = {77,22,88,11,22};
* * ** * * ** * *** size = 5;
    
* * * ** * * * *** print the array */
*** * ** * * * ** * * *** ** * i = 0; i < size; i++){
***** *** ** *** * * * * * ** *** * * *** * ** ", x[i]); **** ****** * ** ** ** * * *
* *** * ** ***** * * *
***** * **** * * * * * * * *
** ** ** **** ***** ****
*** * * **** * * **** I need this to happen size-times */
* ** * ** ** * ** *** **** ** j = 0; j < size; j++){
** * * ** ****** * * * * * ** ******** * ** * from left to right */
* * *** ** * * * ** * * *** *** i = 0; i < size-1; i++){
* *** * * * ***** * ** * * * ** ** * * ** * * *** i-th element with its neighbor to check if they are in order */
* * * *** ** * * * *** * * * * * ** * * ** ***** *** ** * * * *** * > x[i+1]){
* ***** *** * *** * * **** * * * * **** ** * * ** **** *** * **** * *** * ***** * exchange the values of x[i] and x[i+1] */
*** * * * * ***** * * * **** * * ** * * ******* * ** **** **** ** * * ** * temporary; * * ** * **** **
* ** * * * ** ** ** * ** * * * **** **** ** * * * ** *** * * ***** **** = x[i];
* *** * *** ** ** * ** ***** * * ** ** ** ** * * *** * ** ** * **** * ** * ****** * * * * = x[i+1];
* ** * * * ** * *** * * ** ** * * * ** ** ** *** ***** **** * * * * * ** ** = temporary;
*** ** ** ** *** * * * * * * *** ** * **** * * **** * * * **
** ** * * * * * ** *** ** ** * * **
* * **** * * ** * * *
* **** ** ** ***** *
* * * * * ** * * * print the array */
** ** ** * *** * * * * ** ***** sorting: \n");
* * * * ** *** * *** * * * * * i = 0; i < size; i++){
** * * *** ** ** ****** * *** * * * * ** * ** ** ", x[i]); * ** ** **** * ** *
* *** ** * * * * *
** * *** * ** * ******** **** * ***
* * ****** ** ***** *
* * * * * ** ** *
* * ****** ** * ** * * ** **** **** * ** *** *
* * *** * ** * **** * * * * *** *****  
*** * ***** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** * * * * x[] = {77,22,88,11,22};
* * * * ** ** * size = 5;
    
**** **** **** print the array */
*** ** * ** *** * ** **** * i = 0; i < size; i++){
* * ** *** * * * * * * *** * *** *** * * ", x[i]); * * *** * ** * * ** * ******
** * *** ** *** * * ** * ****
***** * *** * * *** ** * ** ** *
** * * ** *** * ** * *** **
* * * * * * * * ******** I need this to happen size-times */
* ** **** * * * ** * * ** j = 0; j < size; j++){
**** ** * * * **** ** ***** ** ** ** ** * ******* from left to right */
**** *** ** * *** * *** ***** ** ** * i = 0; i < size-1; i++){
** *** * *** ** *** **** * * ** * * * * * ** * ******* * ** i-th element with its neighbor to check if they are in order */
* **** ** ******** * * * * * *** ** ** ******* ***** > x[i+1]){
** * * * ** * * ** ** * *** *** ***** ** ** ** ** * * ** *** ** ** * ** * ** * ****** exchange the values of x[i] and x[i+1] */
* * * ****** ** * ** ** ** * ** *** *** **** * ** ** ** * * * **** ***** * *** * *** ** * temporary; * * * *** * ** * ** ** *** *
* ** ** * *** * * *** ** ***** * * * * * *********** * * * ** * **** **** ** ** * ** * *** = x[i];
** ***** * **** * * * ** ** * ** ** * ** * * * * ** **** ** **** * * ***** * *** = x[i+1];
* *** ** * ***** ** * ** *** * * * * ** ** **** **** * * * * **** ** * ** *** *** ** = temporary;
* * ********** **** *** * ** * * ****** *** ** ***** * * * ***** * ** *
* * **** * * * ** ** * * * * * **** * ***
* ***** * * ******* **
**** **** ** * * * ***
* *** ** * print the array */
*** *** *** *** *** **** * * * ** *** sorting: \n");
** * * *** * * * * * ***** * i = 0; i < size; i++){
* * ** * ******* *** **** ** ** * *** ** ** * *** * * ", x[i]); * * ** *** * ** * ** ** * **
** * ** *** * ** **
** *** *** **** ** * * * ** ****** **
* * * * * * *****
* ** * ***** * *
** ***** ** * *** **** * * * ***
* *** * * * * * * *** ****** *** *** *  
***** **** * * *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ***** * ***** * ** * x[] = {77,22,88,11,22};
***** * * *** * ** size = 5;
    
* ** **** * * * * ** ** print the array */
* * ** ***** * * * * * * i = 0; i < size; i++){
* * * * **** * *** * * * * * * ** * * * ** * * * *** ", x[i]); * * * * **** * * * * ** * ** * *** *
**** * * * * * * ** * *
* *** ***** * * * ** * * ** ** ******* *
** ** **** ** *
****** *** * ** ** ***** I need this to happen size-times */
** * *** ** ** * * * j = 0; j < size; j++){
* **** * * * * ** * * ** * ** ** * from left to right */
*** ** * ** ** *** ***** * **** * ** * * ** * ** ** i = 0; i < size-1; i++){
* *** ** * * **** *** * * * ** * *** **** *** * * ** ***** * **** i-th element with its neighbor to check if they are in order */
* * ****** ** * * *** * ** * *** * ** * * *** * *** * ** * ** *** ** ** > x[i+1]){
** *** ** * *** ** * ** * * **** ** * * *** ******** * * * **** * * * **** * * ***** ** ** exchange the values of x[i] and x[i+1] */
***** **** * * * ** * * * **** **** **** ** ** **** * ***** * * * *** *** * * ** * ** **** temporary; * * *** * * *** ** *
** * * ** **** ** ** * ** ******* ** * ** * ** * * ***** *** ** *** * ***** ** = x[i];
** * ** * ** ** **** * ** ** * *** * * * * *** * * ****** * * ** * ** = x[i+1];
*** *** * ***** * ** ** * * * ** ** ** * * ** * *** * *** *** * * ** * * * * **** * * * = temporary;
**** * ** * * * * **** * * ** ** ***** *** * *** ***** * * * * *
* * * ** * ** *** ** * * * *** * **
* * * ** *** ***
* ********* ***** *** *** **
** * **** **** * print the array */
* ** * ** ** * ** * * ***** ** *** sorting: \n");
* * * * ***** * ** * * * i = 0; i < size; i++){
***** *** ** **** ****** ** ***** ** * * * ** **** ** ***** ", x[i]); ** *** *** * *** * *** ** * ** *
** * ** *** ***
* * ***** * ** *** * ** * ** * * * *
***** **** *** * * *
* *** * * * * *
* *** * * * * * * * * * * **** **
* *** ** * * * ****** * * **** * *** * *  
* *** ** **** * * * ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.194.138
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users