0 like 0 dislike
8.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** ** *** ** * ** x[] = {77,22,88,11,22};
* * * *** *** * size = 5;
    
*** *** * * ***** * * print the array */
*** * **** * * **** * * * i = 0; i < size; i++){
* ** *** * * *** **** * * ** * * * *** * * * **** ", x[i]); * * ***** * ** ** **** **** *
** *** * * ** * * *
** *** *** * * **** * ****** * *
**** ** *** * * * ** *
* * *** *** ** *** ** * I need this to happen size-times */
***** ** * ** *** * j = 0; j < size; j++){
* *** * * * ** * * **** ** * ** * * from left to right */
**** * **** ** * **** * ** ** * * * ** * ** ** * *** ** ** i = 0; i < size-1; i++){
*** * * * ***** * * ** ** ******* * ******** * * **** * * ** * ** ** * i-th element with its neighbor to check if they are in order */
********* ** * ** *** ***** * *** * * * * * **** * ** ******* ** > x[i+1]){
* * *** ** * ** * ** * ** **** ** ** ***** *** ** * ** * *** ** ** * * * ** * * * *** exchange the values of x[i] and x[i+1] */
* ** ** * ****** * **** *** *** * *** *** * * *** * * * * * * ** * ** * **** ** *** * * temporary; ** **** * ** ** *** ** * * ****
**** * * * ****** * * *** *** ***** *** * *** ** * ** * ** ** * ** *** * ***** = x[i];
* * * ** * * ** ** * * ***** ** ***** ****** * * *** * ** ** * ** *** * ** * ** * = x[i+1];
*** *** * * * * *** * * * **** ** ******* * *** * * *** *** ** * * ***** * * ** ** * * = temporary;
* * * * ** ** ** * * * ** ** * ** * * ** * * *** ** * * ***** * * * *** *
* * ** * * *** ** * ***** ** * * * ** ** **
** * ** * * * * * * * ** *
* ** *** ** * * ***** * *
* **** * ***** * * print the array */
* ** *** * ***** ** * sorting: \n");
* ** * * * * * * i = 0; i < size; i++){
*** *** ** ** * * ** **** ******* ******* **** * ***** ", x[i]); ** * * * * * * * * *** * *
* ** * * * ** * *
* * ** * * ****** ** * *** ** ** ** *
* * ****** **** * **
** *** ** **** ***
*** * * * * * ** ** ****** * * ** * *
** * * * *** ** * ** * *** * * * ** ** * * * *  
**** ****** ** * * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** *** * ** * *** * x[] = {77,22,88,11,22};
* **** * * ** * * *** *** size = 5;
    
** ** ** * *** ***** print the array */
*** ******* ***** * ** * i = 0; i < size; i++){
* *** ** * ** ** * * **** * ** * ** * * * ", x[i]); ** * * **** * ** * * * ** *
** * * * ** ** ** * * *
**** ******** *** * * * *** * *** **
*** * ****** ** * * *
* * ** * * * * I need this to happen size-times */
*** * * * ** *** * j = 0; j < size; j++){
* * **** * ***** ** ** * * * * * * * ** from left to right */
* * **** ** ** * * * * *** * *** * * ** i = 0; i < size-1; i++){
* * ** *** * ** ** ** * ** ***** **** ******** * * ** i-th element with its neighbor to check if they are in order */
* ** * * * * ** ********** * *** * *** * ***** **** * > x[i+1]){
*** ** ** * * * * * ** *** ** **** * * * ** *** ** ** ** * *** * *** ** ******* * exchange the values of x[i] and x[i+1] */
*** **** ***** ** * ** * * ** * ** ** * ** * * * * * * * * ** * *** ** ** * ** *** * * ** * temporary; * ** *** ** **** * **** *
****** * * ** * * ** * *** *** *** * * **** * ** **** ******* ***** ** ** **** **** ** *** *** *** = x[i];
** * * ** *** ** **** ***** *** *** ** *** * * * * ** * **** ****** * ******* * = x[i+1];
* **** * * ********* * ** *** * ******* *** ** * * *** * * ** **** * ** * * ** *** * * = temporary;
* * * * * * *** * *** * **** *** ** * ** ** * *** * **
* ***** *** **** * ** * ** * * ************** ** **
* * * *** * * ***
**** ***** * * **** *
**** * *** **** *** * * * print the array */
** **** *** ** * * * * * sorting: \n");
** * * ***** * ** * * ** i = 0; i < size; i++){
*** ***** * *** * ** *** * ** ** *** * *** * * ***** * ", x[i]); * * * * **** * * *** ***** **** * ** *
* **** * *** * **
** * ***** ** ** * * * ** *** * * *
***** * * * ** ** * *
** * * * ** * **** * **
** * ** * *** ** ** * * * *** * ** ***** *
* *** * * *** ** ***** ** ** *** *** *  
*** * * ** * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** * * ******* x[] = {77,22,88,11,22};
* *** *** ****** ** ** * size = 5;
    
* * *** * ********* * print the array */
* * ** * *** ****** *** * i = 0; i < size; i++){
** *** **** *** * ** *** *** ** **** *** * ***** * * * ", x[i]); * * * * **** * *** ** * *** ****
* * * * ** * *** * * ** *
** * * ** *** * * ** ** **
****** * ********** * ** **
****** * *** * * * I need this to happen size-times */
******* ** * * ** * * ** ** j = 0; j < size; j++){
** ** * ** * * *** ** * *** * * from left to right */
* *** * ** * * * *** * * * * * * ** i = 0; i < size-1; i++){
* *** * *** ** **** * ** ** ** * * *** ** * ** ***** * ** * * * ** i-th element with its neighbor to check if they are in order */
*** * * * * ** * ** * * * *** ** ** *** ** * * *** ** * * > x[i+1]){
* ** ******** ****** ** ***** * *** * ** ** * * ** * * ** * * * * *** *** * ******* * * * exchange the values of x[i] and x[i+1] */
** ** * * * * * * * * * * ** * ** *** ** * ** ** *** * * ****** * * *** * **** ** temporary; ** * *** ***** * * * ******* *
*** * ** * ** * * *** ** ** * ** * * ** * ****** ** * * ** * * * ** ** * ** ***** = x[i];
** ** *** * * * * * *** ** **** * * ****** * *** * * *** * ** * * **** * * * = x[i+1];
* ** ** ** * * * **** * ***** ** * ** *** * ** * * ***** ** ** * ** * *** = temporary;
** * ******* ** ** ** ** ** * * * * ** * * *** ***** *
** ** * * * * * * * * * ** * ***
* * ** ** * * * * *** *
* * * * * * * ** **
** * ** * * *** * print the array */
* ********* ** ***** *** ** * * * sorting: \n");
* ****** * * ** *** i = 0; i < size; i++){
**** * * ** * ** * ** * **** *** *** ** ", x[i]); ** **** * ** ** * * * ** * * **
**** ** ** *** * **** * *
* * ** * *** ******* * * ** ***** *
**** * * **** ** * ** *
* *** ** * *** *
* * *** * ** ** ** * *** * * * **
* * ** * * *** * *** * * * ** ** * *** ****  
*** * ******* * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * ** ** x[] = {77,22,88,11,22};
****** ** * ** *** *** size = 5;
    
** *** * ** ** * print the array */
* ** * * * ** * *** ** * i = 0; i < size; i++){
* * ** * * ***** * ***** ** ** ** * * * * ** * * * * ** ***** ", x[i]); * **** *** * * ** ** * ***
** * ** * * * * ** *
* * ** * * * ** * * ** * ***** ** *
* * *** ** * **
** ****** * * * * * * I need this to happen size-times */
** ** * * *** ** j = 0; j < size; j++){
** * **** **** **** * **** * * *** * ** from left to right */
* * * *** * *** ** * * * * * * *** ****** ** * ** i = 0; i < size-1; i++){
** * * *** * ***** * * ** ** * ** ** * * ** ***** * ** * ***** i-th element with its neighbor to check if they are in order */
* * * ** *** * *** * ** * ** ** ** * * ***** ** **** ** ** * ** * > x[i+1]){
**** * ****** *** **** ** * ** * * ** *** *** *** * * **** ** **** **** * ** * *** ** ** exchange the values of x[i] and x[i+1] */
* * ** ** * **** * ** * *** ** ** ** * ** * * ** * * * * **** *** ** * * * * *** *** *** * * * temporary; ** ******* * * * ** * *** * *
** *** * ** * * ** *** * * * **** *** **** * * * * ** * * * *** * *** * * ** * *** * = x[i];
** ** ** ** * * ** *** *** ** * *** * ** * * ** ** *** ** ** *** ** * * * * ** ** = x[i+1];
**** ********* * * * ***** *** *** **** * ** ** * * * *** ** * * *** **** * ** ** = temporary;
*** *** * ** ** * * * *** ** ****** * ** ******** * ** * ** * **** * ** * *
* * ** ** *** * ** ***** ** ** *** * * **** * * **
* * * * * **
* ** ** * * * *
* * ** ***** **** *** print the array */
* ** * **** *** *** ** sorting: \n");
* ** * * ***** ** *** * i = 0; i < size; i++){
* **** * ******* ******* * * ** * * * ** * ***** ", x[i]); * ** * * **** * * * * **
* ** * * * ** **
**** * **** *** ** ** ** ** * * *
** * * ** *** * * *
* * * * ** * ** **
** * * * * * * * ** * *** * * * ** **** * *
* * **** ** ** ** *** * * * ** *** * * ** ******* *  
** ** **** * * ** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * ** * ** ** x[] = {77,22,88,11,22};
**** * ** ** ** ***** ** * * size = 5;
    
** * *** ** * * *** ** print the array */
** * * * ** ** **** * i = 0; i < size; i++){
* * * *** * *** ** * * * **** **** * ** * * ** * **** ", x[i]); * * * ** ***** ** *** ** * **
* ***** ** ** ** * ** *
** *** * * * **** * * * * ** * **
* *** * ** * * **
* *** *** ** ** * * I need this to happen size-times */
****** * ** ** ** * * j = 0; j < size; j++){
* *** * *** ** * ***** * * ** * **** *** * from left to right */
* *** * **** **** ***** ** ********* ** **** ** * * * *** i = 0; i < size-1; i++){
* * ** ** * ** *** * ** * ** **** ** * ******* **** ** * * * * ** i-th element with its neighbor to check if they are in order */
* *** ***** * ****** ** ** * * * ***** **** * ** * * *** * > x[i+1]){
** **** * *** * * * * ** ** * * * * *********** ** * ***** ** ** * **** ***** ** exchange the values of x[i] and x[i+1] */
* * ** * ** ** ** * ** * *** **** * * * ** * ** * * **** * **** *** **** temporary; ** ** * * * * * ***** * * *
***** ** * * * * ** * ** * * **** ** **** * * ** * * ** ** ** * * ***** *** * ***** ***** = x[i];
******* * * ***** *** *** * * * ** * ** ** **** * ***** * *** * * *** * * ** * * ** * = x[i+1];
* * ** * ** * * ***** ** **** * * * ******* * ***** * ** ***** ** ** * * ** * ** ** = temporary;
** **** * * * ** * ** * *** * * ** ** *** * ***** **
** * ** * ** ** * ** * * *** ****** * * *
** * *** * *** * ** ****
** * * * * *** * ** *
***** ** * * * ***** print the array */
* * * ****** ** **** ** ** *** ** * * ** sorting: \n");
* ** * * ** ** * * * i = 0; i < size; i++){
* * **** **** ** * * ** * * **** * * * * ", x[i]); ** ** * * * ** ** * **** *
** * * ** *** *****
**** * *** **** ***** **** *** *** **** * ***
*** * * * * *
******** * **** **
* * **** ******* *** ** * *
*** *** * ** ******* ** *** * * *** **  
* **** ** **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** ** ** ** ** x[] = {77,22,88,11,22};
* ***** **** * * **** size = 5;
    
* **** **** * * ** *** *** print the array */
* ** **** * **** * * ** ** i = 0; i < size; i++){
** ** * * * *** * ** * * * * * ** ***** * * ", x[i]); * * * * *** * ***** * * * *** **** * *
**** * * *** **
**** ** ** ** * ** * *** ** * ** *
** * * ** ** ** * *
*** ** * ******** * * **** * I need this to happen size-times */
* * * * * ** **** ** j = 0; j < size; j++){
* ** * ** * *** ***** * ** * *** * * from left to right */
***** *** ******** ** * ** * ** *** * ********* * i = 0; i < size-1; i++){
* *** ** ***** ******** ***** * * * *** ** * **** * * * ** * ** ** i-th element with its neighbor to check if they are in order */
* ** * ** ** * * * *** * *** * ** *** * * ****** * * > x[i+1]){
* ** * *** * *** * ** * * ** * *** ** ** * ** ** *** **** ************ * * *** * exchange the values of x[i] and x[i+1] */
*** **** **** * * * * * * ** * **** * **** * * ** *** * * *** **** * ** *** * ** ***** temporary; * **** ** * ***** * * **
** *** * * * * ** ***** ** ** * *** * *** ** * ** * * * * * * *** = x[i];
*** ** * * *** *** * * **** ** * * * * ** * * * ** * * * **** ** *** ** * *** ** * = x[i+1];
***** * * * ******** * ** *** ** * * ***** ** * * ** * ** * * * * * *** * *** *** * * = temporary;
** * * ** ** *** ** ** *** ** * * * *** *** ***** * * *
** * ********* * *** ** * * * * * * *
** * ** *** ***** * * * *
** * ** *** * * **
* * ** * * **** ****** ***** print the array */
* * ********** * * ** * **** ** * * sorting: \n");
* **** ** ** ******* ** * i = 0; i < size; i++){
*** ** * * ***** *** *** * * ** * ** ** ** * * * * ", x[i]); ** * ** *** ** * ** * ** ** *
* * **** ** ****** *
*** ** **** * * ** ** ** ** ** ** *****
***** * ** **** **** *
* ** * * *** * * *
**** ** * ** * * ** * *** *** * ** * *
* * * * * ** * * ** * ** * *** * * * **  
* *** *** ** ***** * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * ** * * x[] = {77,22,88,11,22};
** * ** ******* ** * * * size = 5;
    
** ** ** ** * * * print the array */
* * ** * *** * * * i = 0; i < size; i++){
*** * * ** * ** * * ** ** ******* ** ** **** * ***** * ** ", x[i]); * *** ** * ** *** *** *** **
** ** * ** * ****
* * ** ** * ** * * *** * ** *** ** **
* ** * ** * * **
** ** * * * * * ** * *** I need this to happen size-times */
**** * ** * * * * **** * ** j = 0; j < size; j++){
* *** ** ** ** ** ** * ***** ** * from left to right */
* ** * ** * * * * ***** ** **** * * * * **** ** i = 0; i < size-1; i++){
**** * *** **** ** ** ******* * * * * ** * * ** ** * * ** * * i-th element with its neighbor to check if they are in order */
****** * **** ***** **** * * * * ** ********** ** * ** ** * * *** > x[i+1]){
* *** *** ** ****** * ** *** ** * ** ** ** * ** *** * * ** * ** * ** ** *** ** exchange the values of x[i] and x[i+1] */
****** ** ** ** * * * ** *** ** * * ** * * ** * ** ** * * ** * ***** **** temporary; *** * ** ** **** * ** ** ** * * *
* * * *** * * ****** ** ** **** * *** ** * *** *** * * ***** ** ** * ** *** * * * ***** * = x[i];
***** *** * * ** * * * * **** * ** * ** * *** ** * * * * * * * *********** * * = x[i+1];
* ** ** * ** * * * ** * *** * *** * * ** ** ** ** * *** * * * *** ** **** * *** ** = temporary;
* ***** ** * * * * * ***** ** * ***** *** * *** *** * *******
*** * * * *** **** ***** * ** * *** ** ** * *
*** * **** **** * **
* * * *** **** * * ** ** * * *
*** ** ** **** * ****** print the array */
* * * * *** * * * * ** ** * *** sorting: \n");
* ** * ** * ** ***** **** * * i = 0; i < size; i++){
***** * ****** *** ******* ***** * * * **** *** ", x[i]); *** ** * *** * * **** ** *
*** ** **** * *
* *** * * * *** ***** * ***** * *** * *
** * * * ** * ***
** **** * * * * ** * **
** *** *** ** * * ** * * ***
***** ** * * ** * *** * ***** * * * ** * ***  
** **** * * * * ** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * ** *** ** x[] = {77,22,88,11,22};
***** ** * ** * ** * size = 5;
    
** *** * * * * * print the array */
*** * ** * ** * ** *** *** i = 0; i < size; i++){
*** * ** * * * * * ** * **** * ****** * ** * * ** ** ", x[i]); ** ******* * * ** ** ** * * *** *
*** * ** * * ***
* *** ** ** **** * ** * ** * * ***
*** * * * ** * ** * *
* * ****** * * * * I need this to happen size-times */
** * ** *** * *** ** * j = 0; j < size; j++){
* ** ** * ***** * *** ***** ** **** from left to right */
* *** *** ** * ** *** ** **** *** * **** ***** i = 0; i < size-1; i++){
* * * **** * * ** *** * ***** * * * * ** ** ***** i-th element with its neighbor to check if they are in order */
** ** * ** * * ** ** *** * ** ** ** * * * *** * *** * ** * *** * * > x[i+1]){
****** ***** * * * * * * * ** * **** * * **** ** * * **** ** * * ** * *** exchange the values of x[i] and x[i+1] */
******* *** ** * ******** ** ** ***** * **** ** * *** * ***** ** ** ** *** ** temporary; * ** *** ** **** **** * * * * *** *
****** ** *** * ** * ** * * * ** ** **** * *** * * ** * * * *** ****** **** * ** ** ** = x[i];
* * * ** ** * * * * ** * * * **** * * * ** ** * ** * * * * * *** ** * * ** **** = x[i+1];
* ** * **** * ** ** ** * *** ***** * * ** ** ** * * ** * *** *** ** * * * ** ***** = temporary;
*** * * * * *** * * * ** * * ** ******* * *** * ** ** *** *
** * *** **** *** *** * **** ** **
** * ** * **
** * ** * ** ** **
** * *** *** *** ** * * * ** print the array */
* * *** * **** ** **** *** * sorting: \n");
* *** **** * * **** * * i = 0; i < size; i++){
* **** *** * * * * ** ** * * * ** * * ** * ** *** * ", x[i]); ***** * *** ***** * * ** **
*** * ** * **** *
* * ** * ** *** ** ** *** *** **
** * * ** * * ** ****
* * ** * ** *** *
* * * ** * * * * * *
**** * * * * * *** * * ** *** * **** * *****  
** **** ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * * ** ***** * * x[] = {77,22,88,11,22};
** * * * * * * size = 5;
    
* * * * ** * **** * **** print the array */
* * *** **** * * *** * ** i = 0; i < size; i++){
****** * * * **** ** * * * * ** ** * ** * **** * ** ", x[i]); * **** * ***** *** ** ****
* * *** * *
***** * ** ** **** *** * *** * **
* ** ** *** ** ** * * *
** * * ** ** I need this to happen size-times */
* * * ** **** j = 0; j < size; j++){
** *** * ** ** ** ** * *** * * * * * from left to right */
*** ** **** *** * *** * ** * *** * ** ** ** i = 0; i < size-1; i++){
* * * * * * ** * * **** *** * * ** ** * ***** * * ***** ******* ** *** ******* i-th element with its neighbor to check if they are in order */
* *** * ** * **** *** * ***** ***** * ** *** ** * * ** * * * * > x[i+1]){
* * * * * * ** *** **** ** * * ** *** * *** *** * * * * **** *** * * * ** *** exchange the values of x[i] and x[i+1] */
* *** *** * ** *** *** ** * ***** * * * ***** ** * ** ** ** * * * ** * temporary; *** *** * * * * ** **** ***
* ** **** ** *** ** ***** * * * * *** ***** ** ** ** ** * *** ** * ** * * * ** ** * ** * * = x[i];
* ** * ** * * ** * * **** ** ** * * **** * * * *** *** * * * * * ** * * = x[i+1];
** *** * * * * ***** **** * *** **** ** * ** * * *** *** * ** **** ** ** ** ** * **** * = temporary;
*** *** * * *** ** * * ** * **** *** * * * * **** * **
********** ** ** ** *** * * * ** * **
* * **** * * * ** * ***
** * * ** ** * ** ** ** *
**** * * *** ** * print the array */
** ******** * * ** ** *** ** sorting: \n");
* ** **** * * **** * **** i = 0; i < size; i++){
* *********** *** * * * ** * ***** ** ** * ", x[i]); ** * **** *** * * * ** * ** * *
* * * *** * * *
* ** ** ***** * *** ** * **** ** * **
**** * ** *** * *
* * **** * ** * * * *
* **** ** ** ** * * * ** **** * ***
** * * ** * ** *** ** *** * * **** * **  
** * ** * *** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * * *** ** ***** * x[] = {77,22,88,11,22};
* * **** * ** * ** ***** size = 5;
    
* * * *** print the array */
* ** *** * ** *** ** ** ** ** i = 0; i < size; i++){
** ** *** * ** * **** ** ***** * ** * ******* * **** ** ", x[i]); ** * ** ** ****** **** *
* * ** * * ** * **
** * ******** * * * ***** ****** * **
** ** *** * ** * **
* * * ***** * * ** ** I need this to happen size-times */
* ** *** ** * j = 0; j < size; j++){
*** ** ***** ******* * ** ** ****** * * *** from left to right */
* ** * * ** **** * ** ** * * * *** ****** i = 0; i < size-1; i++){
** *** * * ******* ** * ** * * * *** *** ** * * * ** * * i-th element with its neighbor to check if they are in order */
* * * * * * * * * ** *** * * ** * **** * * * * * *** * *** * ** > x[i+1]){
** * * * ** ***** * * * ****** * * * ** ** **** ** * ** *** *** * * * ***** * *** ** exchange the values of x[i] and x[i+1] */
* * ** *** ** ** ***** * ** ** ** ** ** * ** ** ** * * * **** * ** *** ***** * * temporary; *** * * **** *** * * ** ** * * *
** ** * ** * * ** **** * ** * ** * * ******* * *** * *** *** * *** * * **** ** **** **** = x[i];
* ** ** ** ** ***** ** * ** *** **** * * * ** * * * ** * * ******** * = x[i+1];
* *** * ******* * * * ****** * *** **** * ******* ** * ** * * **** * * * * ***** * = temporary;
* * ***** *** * * ***** ** **** ** * * *** ** * **** *** *** ** *
* ** * * * *** ** * ** ** ** ** **** * * ***
*** * * ** * ******* ***
** * *** * ** *** *
** ***** ** *** *** print the array */
* *** **** ** *** * ** * ** ** ** * sorting: \n");
* * ** * * * * i = 0; i < size; i++){
** ****** *** * * * *** *** * ** ** * *** ******* ", x[i]); ****** *** ** * * * **** * **
* ** * * * * * ****
* * * * ** * * ***** *** ** * ****** *****
* * *** ** * *****
* ** * ** ****
* * * * *** * * * * * * **** ** * * *
* * *** * * *** * ** * * * * ******* *  
* * ** ***** ** * ** ******* * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.66
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users