0 like 0 dislike
9.2k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.2k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ** * ** ** * * x[] = {77,22,88,11,22};
** **** * * **** * * *** * size = 5;
    
* ** * **** * ** * * * ** print the array */
**** ** * * ** ** * i = 0; i < size; i++){
* * * * ** ** ****** * ** **** * ******* * ** * ** * * ", x[i]); *** *** ** * * ** * ** *****
** * * ** * * *** *
** ** * ** **** ** * * *** ** * * *** **
****** ** *** ** ******
**** ** * ** ** * ** * I need this to happen size-times */
********* * * * * * ** ** * j = 0; j < size; j++){
**** ****** * * ***** * * ** ** * * * * * * from left to right */
** ***** * * * ** * *** ** * ** * * * ** ** ** ** i = 0; i < size-1; i++){
* * * *** ***** * ** * ***** ** * ****** * ** *** * * * * *** * ** i-th element with its neighbor to check if they are in order */
**** * * * * * * * ** ******* * *** * * * * * ** *** ** > x[i+1]){
*** ***** **** **** * *** *** * *** * * ** ** * * ** * ** * ** * * ***** * ** **** exchange the values of x[i] and x[i+1] */
******** ** ** ** * * *** ** ** ** * ***** * ** * *** *** * * * ** ** ** ** ** * ** * temporary; * * **** ** * ****** * * * * * * **
* ** ** * *** * ** ** * ** *** * * * * **** *** * **** * ** *** * ** ** ** * * * * *** ***** = x[i];
* * * ** ** * * * ****** ** *** *** * ** ***** ** ** ** ** * * * * **** * * * * *** = x[i+1];
* * **** ** * * *** * ** *** ** * * ** * ****** * * ** ********* ** *** * * * ** * * = temporary;
* ***** * ****** *** * *** ** * *** * * ** *** *** ***
* ** ** * **** * *** * ** *** *
* ** ******** ******* *
* ** ** * *** ** *
* * * * * * * * * * ** print the array */
* * *** * * ** * ** **** *** * sorting: \n");
* ** * * * * * *** *** *** * i = 0; i < size; i++){
* **** *** * * ** ** ** * * **** **** ** *** * *** * ** ", x[i]); ****** ****** ** * * **** ***
* **** * * ** *** *
***** * * * * *** *** **** * * ** * **
*** ** * **
**** * *** ** ** * * *
* ** * **** * **** * * * * *****
* ** *** ** * **** ** ****** * ***** **  
*** ** ** * *** *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** * ** * ******* * x[] = {77,22,88,11,22};
* ** * * ** * size = 5;
    
* * * ** **** * ****** print the array */
* * * * **** * ** * * i = 0; i < size; i++){
** *** ** ** ** *** ** * * * ******* * * * * * ** ** * ", x[i]); * * * * *** * * ** * *** * *
* ***** * * *** ** *
* *** * **** * ***** ** * * * *
** * *
* ********** * ** * *** * I need this to happen size-times */
** * ** **** ** * * *** ** * j = 0; j < size; j++){
**** * * * * ***** ** **** * *** ***** ** ** * * from left to right */
* * ** ** ** ** ** * ** ** ** * i = 0; i < size-1; i++){
* *** ** ** * ** *** * * * * *** * * * *** * ** *** * * * * ** ** ** i-th element with its neighbor to check if they are in order */
*** * * * *** **** ** *** ** * ** ***** *** * *** ** * ***** * * ** *** * > x[i+1]){
* * * * * ** * *** * * * *** *** ***** * ** * **** * * * * * * ** *** ** ** * * * ** * exchange the values of x[i] and x[i+1] */
* * * * * *** * * * * ** * ** **** ** ** *** ** * * * * ** * * ** * ** * * * ***** *** * * temporary; * * * * * ***** * ***** *** **** ******
* ** * * * * *** * ****** ** ** * *** * ** *** * ***** * ** ** * * ** * ** * * ** * ** * *** = x[i];
* ** * *** **** * * ** ****** * *** * * **** * ** * ** *** * ******* ** ***** *** * = x[i+1];
* ** ** ** *** * ** * ** * ** ** ** *** * ** ** ** * * **** ******* * * * * * *** ***** = temporary;
** * ** ** ** * *** **** * * * ** * **** ** ** * * ***** *** **** *
* ** *** ** **** * *** *** * *** *
** **** *** * * ** ** * **
*** *** * ** * * **
** **** * **** * ** print the array */
* * * * ** * * * * ** * ** sorting: \n");
**** ** * ***** * **** i = 0; i < size; i++){
*** * * * * *** ***** **** * * ** * ** ** ** ** * * ", x[i]); * * ** * * * **** ** * * * *
* * * ** ** *** ** * ** *
*** **** ** ** * ** ***** ** * * * **
* * ****** *** *
* * ** * * **
****** ** * * * ***** ** ** * *
** ** * * **** * ** * ** **** * **** * * * ***  
* * * *** ** * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ******** ** ** * **** * x[] = {77,22,88,11,22};
* * * *** * ** * * ***** size = 5;
    
** * * *** * ** * * * print the array */
* * *** ** * ** *** *** * * i = 0; i < size; i++){
** *** ** * ******* ** * * *** * **** ** * * ", x[i]); * ** * *** * * ***** *** * * **
** ** * * ** * **** **
* * * *** ******* * *** ** ** *****
** **** * * ****
* * ** *** * * * * * I need this to happen size-times */
* ** *** * * *** * ** **** j = 0; j < size; j++){
** * * *** * * * * ** * * * *** ****** from left to right */
* * ** * ****** * *** * *** * *** **** * *** * * i = 0; i < size-1; i++){
* * ***** * * * ** * ***** *** * *** * *** * * * * * **** i-th element with its neighbor to check if they are in order */
* * * * **** *** ** * * ** ** * *** *** *** ** *** * **** * > x[i+1]){
****** * ****** ** * ** * * ******** * * * ** * ***** ** * ** * * ********** * ** * ** * *** ** *** exchange the values of x[i] and x[i+1] */
***** *** ** **** * *** ** ** * ** * *** ** *** * * *** * * * * * * **** * * *** temporary; * * * * ** ****** *** * ** ***
** ** ** * * * * ** * ** * ** **** ************** * * ** * *** **** *** * * * * * * * * = x[i];
** * * *** *** ** * ** ** * ** * * * * *** * ** * * ******* * * * * * * * = x[i+1];
* ***** * * *** * * * *** ** *** ** * * * * ** * * * **** ** * * ** ** **** * ** * * ** * ** * = temporary;
*** * ** ********** * * *** * ** ** ** ** ** * * * *
*** * *** *** * * *** *** *** ***** ** ***** *
* ** **** *** ** * * * *
* ** * ** * **** *
* *** * *** ** * *** *** print the array */
*** * * ** ** **** * ****** *** ** sorting: \n");
* **** * * ***** * * * i = 0; i < size; i++){
**** * * *** * * **** * * *** ******* * *** ** * ", x[i]); ** ** * * * * **** *** * * *
*** * ** * ** * **** * *
* * *** *** * ** * ** ********* *
* ** ** * * * * *
** * * * ***
* * * ** * * ** ** * ** *** ** * *
* ***** * *** *** * *** **** * * ****** * * *  
* * * * ** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * ** ***** ** x[] = {77,22,88,11,22};
**** * * * *** **** * * * size = 5;
    
* * ***** ** * * ** ** print the array */
* * * * *** * * ** * * i = 0; i < size; i++){
* * **** **** * * * * *** * * * * * * ** * *** ** ", x[i]); * ** * * * **** ** * ** ***
*** * * ** ** ** * ***
* *** ***** * * ** * * * *** * ** ** * ****
*** * ** * * ** **** * *
* ** ******** * * * I need this to happen size-times */
*** * * * ** * * j = 0; j < size; j++){
*** * **** * ** ** * * * *** * * *** from left to right */
* * ** ***** *** * * ** ** ** * ** * *** ** *** i = 0; i < size-1; i++){
*** * ** ** * * * * * **** ** ** ** * * ***** ******* * * * i-th element with its neighbor to check if they are in order */
* *** * * ** ** ** ** * * ********* * ** * **** * **** *** ** *** > x[i+1]){
* * * * * *** * ** ** ** * **** *** * ** * * *** ** *** * * ** ** ** * * *** * * exchange the values of x[i] and x[i+1] */
* * *** * * *** ** * ** * * * * ** **** * * *** * * * * * * ** * * * * ** * *** temporary; * * * * * * * *** * *
*** * ** ** ******** * * * * *** * ** * ** * * * * *** * * * * * ** * * **** = x[i];
* * * *** ****** ** * * ****** ***** ** * ** *** ******* ***** ** * ******* ** = x[i+1];
*** * * *** * * * * * ** * *** ** *** * * **** **** * * ** ** * **** ** **** = temporary;
* * ** * * ****** ** **** * * ** * ******** ** * ** * **
** * ** ** * * * * *** *** ** ** **** *
* ** ** ** ** * * **
* ** * * *** * * * *
* * * * * ** **** * print the array */
*** ***** ***** * * * sorting: \n");
****** * ** ** * *** ***** i = 0; i < size; i++){
* ** ** * * ** ** * * * * *** ** ** * * ** ** ** ", x[i]); *** * * * ** *** * ** * **
* * ** ** * * ***** **
** * **** * * ** *** * ** ** * ** * **** * **
* ** * * *** ** * * *
** ****** ** * **
** * * * ****** * * *** ** ** ** ** * **
* * ******* * * *** * **** * **** ** *  
**** ** * ** * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** **** ** * * ** x[] = {77,22,88,11,22};
********* * * ** ** * size = 5;
    
* ** *** ** * ***** print the array */
* * * * ** ** * *** i = 0; i < size; i++){
* * ** * *** * *** * ** ** * ** ** ***** ** * * ", x[i]); ******** * ** ** * * ** *** * **
*** * * * ** * ****
* ** ***** ** * ** * * *** * **** ***
* ******** ******** * *
** *** * **** * * * * * I need this to happen size-times */
** *** *** ** **** *** * * * j = 0; j < size; j++){
* ** * ****** **** * ** ** * * **** *** * from left to right */
***** ******** * ** * * * *** *** * * i = 0; i < size-1; i++){
**** * * *** * ** * * ***** * * *** *** * * **** * *** * * ** * * i-th element with its neighbor to check if they are in order */
* *** * * * * ** * ** * ********** ** **** * * * * * ** ** * > x[i+1]){
* * * **** ** * * * * ** ** * ** * * * * * * * * * * * * ** * ******** * * * * exchange the values of x[i] and x[i+1] */
* ** ** ** * * * **** **** ** *** ***** *** ***** * * ** ** *** * ** * * ** * * ****** * * * temporary; ** * **** * ** * *** ** * ** **
* *** ** ***** ******** ** *** * * ** ** * * ** ** * ** * * ** * ******* ** * * *** **** ** ** = x[i];
* ** **** * **** * * * * ** * * ** * * ** **** ** * * ** * *** * * ** * * **** * = x[i+1];
*** * ** * **** * * * *** * * * * * * ** * * ** * * ** ******* * * * * ** = temporary;
** ** * * ****** ** **** ** ** * * **** * **** * * ***** * * * * **
* * * **** * **** **** ** * ** *** **** **** * *** * *
* *** * * **** * *** *
* ** ** ** ** *** * ****
* ***** **** **** * * ** * print the array */
* ** * ** *** *** * ** ***** *** sorting: \n");
***** * * * * * * i = 0; i < size; i++){
* * *** *** ** * ***** * * * * ** ** * *** * *** ** **** ", x[i]); * * * * ******* * * * * *** **
*** ** * * * * * * * *
* * * ** ** * ** ** * * * ****
**** * * * * * *** ** **
** *** * ******* * * *
* * * ** * * * * ** **** ****** ***
*** * ** * * * **** ****** ** *  
** ** *** * ** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** ** * * x[] = {77,22,88,11,22};
* ** ********* * ***** size = 5;
    
** * * ***** ***** * print the array */
* *** * * ** * i = 0; i < size; i++){
*** * ** * *** ** ** * * ** *********** **** * * * * ", x[i]); * * * ** ** * * * ** * ** ** * *
* ** * ** *** * * *
* * ****** * **** * * * * * *** * * **
* *** *** *** * * * *
** * ** * * ** ** * I need this to happen size-times */
* * * ** * * * * j = 0; j < size; j++){
** * ** ** **** * ** * * * *** ** ****** * **** * * from left to right */
** *** * ** ** * * * * ** *** ***** * * ** ** ** * i = 0; i < size-1; i++){
** ** * ***** *** * * ** * * * ** *** ** * ** * ** ** * ***** ** * i-th element with its neighbor to check if they are in order */
* * * * * ** * * * * ***** ** * * ** * **** ** * ** * * > x[i+1]){
* ** * *** * * * * * * *** ** ** **** * *** ** ** **** * ** ******** *** **** * * *** ** * * * exchange the values of x[i] and x[i+1] */
* ****** ** ** *** ** * * * ** * * *** **** * * * *** * ** * ** * * * ****** * * ** * ** * * temporary; * * ** * * * ***** *** * * * ***
*** * *** ** * ** * * * * * *** *** * * ** ********** **** ** * * ** * **** ** ***** * = x[i];
* * * * *** * * * *** * ** *** ** * * ** * * * * * ** ** * *** * * * *** * *** *** = x[i+1];
* * * **** ** * * * * * ** * * * * *** ** * ** * * * ******* * * * * *** * * = temporary;
***** ** ** * * ** * * *** ** * * **** * * * * *** * ** ** ******
**** ** * * *** *** * * * * ** * ** * * ** *
*** *** * *** ** * *** *
* *** * ** *** * *** **
*** * ******** * print the array */
***** ** *** * ******** * *** * sorting: \n");
**** * ** ****** * * *** i = 0; i < size; i++){
** * *** ** ** ** **** ******* * ***** * * ** ** ", x[i]); * ** ******** **** * * ** *
** * * * ** ** ** * *
** * * * * * ** * ** *** * * * *
***** ** **** * ** ***
* ** ** ** ** ***
*** * *** ** ** ** * ** * *** * ** **** **
* ***** * * *** * * * * * * * * * * ** *  
* ********** * ** ***** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * ** * ** * * * * x[] = {77,22,88,11,22};
* * * * * ******** ** size = 5;
    
** ** *** ***** ** print the array */
* * ** ** * * * *** ***** i = 0; i < size; i++){
***** * ** * * ** ** * * * ** * *** * * *** ** * ", x[i]); * * ** ** **** ** ** *
***** ** * ** *** **
* * * ** **** * * * * ** *** *** ** ** *
* ** *** *** **
* ** * * ** * * ** * * I need this to happen size-times */
* ** ** *** *** j = 0; j < size; j++){
* ** * * ** *** * * * ** * ** ** ** * * * from left to right */
* * * ** * * ** * * * * ** * * ** ** ** ** ** *** i = 0; i < size-1; i++){
** *** * * ** ** ** ****** *** * *** **** * ** * * ** * ** ** * ** i-th element with its neighbor to check if they are in order */
* *** * ** **** ** * * ***** * * * * ** * * * *** *** ** > x[i+1]){
****** ** ** * ** * **** *** * ** * ***** ** ***** ** *** * ** * * ** *** * * * * * **** * ** * * exchange the values of x[i] and x[i+1] */
**** * ** * * ** ** *** * * * *** ** ** * * * *** * * ** * * * * ** * * * * temporary; * * * * * ** ** ** * **** *** *
* ******* * ***** *** * * ** ** ** * * * * *** **** * * *** * ** * ** ** ** ** * * ** ** * = x[i];
** **** * **** * * * ** *** * * * * * * * ** ******* ** * *** ** * ** ** *** **** **** ** = x[i+1];
* * * ** * * * * * * * * * * * ******** * ** * ** *** ***** * * ** *** * ** ** * ** = temporary;
* ** ** ** * * * *** **** ** * * * * * * * ** * ****** * *
* ** * * * *** * * ******** * ** *** * * *** * **
***** * *** * * **
** ** * * * *** ** **
** *** * ** ********** print the array */
** *** * * ** * ** * * ***** sorting: \n");
* ** ** * * * *** * * * ** i = 0; i < size; i++){
* * * * *** **** *** * *** ** ****** * ***** ", x[i]); **** * * * ** **** *** ** ***** *
*** *** * * **** ** * ***
** ** **** ** ******* * ** * ** * **
** * * * * ** * *** *****
* * ** * * **
* ** * * * * * ** ***** * * ** *
* * * ** *** ** * * * *** * ** ***** **  
* **** *** * * **** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** ** ** x[] = {77,22,88,11,22};
* *** **** ** * * ** ** ** * * size = 5;
    
* * * ** ****** ** * print the array */
* * * *** ** ** ***** ** * i = 0; i < size; i++){
* * * ** * *** * ** ****** **** **** ***** * **** ", x[i]); * ** *** ** * **** *** **** ** *
* *** ** * **** ** **
** *** *** ** ** * ** ** ** *** * ** * **
* *** * * * *** *** *
* *** * ** ******* * ** I need this to happen size-times */
* * *** *** * * * * j = 0; j < size; j++){
*** * ** * * ** * *** * * ** * *** * *** **** from left to right */
** * * * * * ***** ** ** * ****** * ** ** i = 0; i < size-1; i++){
* ***** * * * * ** **** ** * * ** **** *** ** * *** * *** ******** ** * **** i-th element with its neighbor to check if they are in order */
** * * ***** **** * * ********* ***** *** * * * ** * * * *** ** ** * > x[i+1]){
** *** * ** *** ** ****** * ****** * * * ** * *** * **** ** * * ** ** * ** **** exchange the values of x[i] and x[i+1] */
* ** * * *** * **** * *** * * * ** ** ******* *** * ** * * * * *** * **** temporary; ** ** ** * *** * * * *** *
* *** ** ** *** ** ** * * * ******** ** *** *** ** * * * *** * * * * ** * ** * * * * ** = x[i];
* * * ** * * ** * * ** ** *** * * * * * * ** * * * ** * * * * * * ** ** * = x[i+1];
** ****** * ** * * **** *** ****** * *** ** * ** * * * * * * **** * * * * ** * = temporary;
** ** ** *** * * ** * * ** * ***** * * ***** * * *** * ** * ** *
* * * * * * * ***** * * ** *** * *
** * ******* * * ** * **
* ** * * * ***
* * *** ***** * ** * print the array */
* * * * **** ** * * * * ** sorting: \n");
* * *** * **** ** ***** i = 0; i < size; i++){
* * * *** * * * * * * ***** * * * ** *** * * ** * ", x[i]); * ** * * ** * ** ******** *
* * * ****** * ** *** * * *
** * **** **** * * *** * * * ****
* * **** * ** * * ** *
* *** *** ***** * *
* ** * ****** ** * **** ** *** **
* * * ** ***** ** **** * * ** *** *** *** *  
* ** ****** * ** *** *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * ** ** x[] = {77,22,88,11,22};
** ******* * ** size = 5;
    
** ** * * * * ***** * print the array */
** * * **** ** ** * **** ** i = 0; i < size; i++){
* ** ** * *** ** * * * **** * **** * * ** **** * * ", x[i]); *** ****** *** * ** * ** * * ** * *
*** * ****** ** ** ****
* * ** * * *** **** * * * * * * *
* *** * * ******* ***
* * ** * ** * **** * I need this to happen size-times */
* ******* * * * ***** * j = 0; j < size; j++){
* * ** **** * * * ** * * * *** * ** * * * from left to right */
* * ** * *** *** * * * **** *** ** ** *** *** ** ** * *** * i = 0; i < size-1; i++){
* *********** ******* ** * * * *** ** *** *** *** * * * ********* * ** * * * * i-th element with its neighbor to check if they are in order */
*** * * * ** * * * ** ** * * **** *** **** ** *** * *** ** > x[i+1]){
** * *** ** ***** * ** * ** * ***** * * * * * ** ***** * * * * * ** * *** * ** ******* ***** * ** exchange the values of x[i] and x[i+1] */
*** ** * * * * ** * ** * ** * ** *** * * * * ******** ** * ** * ** * * ** ** * *** temporary; * * ** * * *** * * * *
** ********* * * *** * * *** ** *** ****** *** * ***** * * * * ** ** * ** * * * ** *** * = x[i];
* * ****** ** *** * * *** ***** ** **** *** ** ** * ***** * ** * ****** * * * * = x[i+1];
* * **** ***** * * *** * ** * * ** ** * * ** * ** * **** ** **** ** * * *** **** * * * = temporary;
* * * * ** ** ** * * * * ** * * ** ** ***** * * * **
** * * * * * ** ***** * ** * * ** * ** * *
* **** ** ** **** *
***** *** * **** ** ** *
** * * ** * * ** * *** * print the array */
** * * *** * * ** ** ** sorting: \n");
* ** *** * **** *** * i = 0; i < size; i++){
**** * * * * *** * * * * ** ** ** **** *** *** * ", x[i]); * ** * *** * * ***** * ***** **
* * ** ** * * * ** **
* **** **** * *** * * * * * *
**** * * ** * * *
*** * ******* * ***
* * * * ** ***** ** *** * ** ** *
* * * ** * **** ***** **** ****  
*** * ****** * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******* * * *** ** ** x[] = {77,22,88,11,22};
* ** * ** * *** **** size = 5;
    
** * * * * *** * * *** ** * print the array */
**** * * ** * * **** ** ** * i = 0; i < size; i++){
**** * *** *** * ** * * * ********** * ***** * ", x[i]); * ** *** * * * * ** * *** *
* *** ** * *** * * *
**** *** * * *** ** **** * *** * ** *
*** * * * ** *** * *****
* * ** * *** I need this to happen size-times */
***** *** * ** * * j = 0; j < size; j++){
** * ** * *** * * *** * * ** * * * ** * * * from left to right */
*** ** ** ******* ** ***** * * ******* *** * ** * * i = 0; i < size-1; i++){
*** ** **** ******* * * * **** ** ***** **** ** ** i-th element with its neighbor to check if they are in order */
** ** * * **** ********* ** ** * ** * * * ** * *** ** * ** * * > x[i+1]){
** ** ****** * * ** * * * * ***** * ***** *** **** ** ** *** * ** * * * ***** ** exchange the values of x[i] and x[i+1] */
* **** ** ** * * ** **** * ** * * * * ** ** ** * ****** ** * * *** * * * ****** * ** * temporary; * * ***** ** * * ***** * * *
* ** * * * * * ** * ** * * * ** * * *** *** * * * *** *** ***** **** ** *** *** * = x[i];
* * ** **** * * * ** *** * * *** ** *** * *** * * * * ** ** * * ** ** *** ** * ** ** * ** = x[i+1];
*** * * **** * * *** *** ** *** *** * * *** ** * ***** * ** * * * ** **** * **** * **** = temporary;
** ** * **** * ** * **** ***** * * *** * * *** * * **** * * *
******* ****** ** ** * ******** **** ** * * ** * **
** * ***** ********** * *
* *** * * * ** * * **
*** ** * * * * *** print the array */
*** ***** * * *** ** * * * * sorting: \n");
** ******* *********** * **** i = 0; i < size; i++){
**** * ** *** * * * * ** *** ** ** ** * * * ** * * ", x[i]); * * ***** * * * *** ** *
** ** * ** ** ** ** *
******** * * * * * * * **
**** ** ** **** * *****
* ** ***** * * *
* * * * * * *** ** ** *** * * * **** ***
* ** * * * ** *** ** * **** * ** * *** * * * **** **  
* ******** ******* ** * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.26
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.8k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users