0 like 0 dislike
8.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * **** * * x[] = {77,22,88,11,22};
* * *** * ***** * * * size = 5;
    
* ** ** *** * *** *** print the array */
** * ** ** * * * * i = 0; i < size; i++){
* ** * ** * * * * ** *** * **** * * * * * * * * ** ***** ", x[i]); *** *** * * ** * ** ** *** ** ** *
* * *** * **
*** ** * ***** * **** * * * * **
** * **** * * * ****** *** *
*** * ** *** ** * ** I need this to happen size-times */
* * ***** * * ** j = 0; j < size; j++){
** * ** ** ***** * * * * ** * ** ****** * *** * from left to right */
** ***** ***** * *** ****** ** **** *** * ** ***** * ** i = 0; i < size-1; i++){
* *** * ******* ****** * ** **** * * * * * * ** *** *** * ** * i-th element with its neighbor to check if they are in order */
*** ** ****** **** * * ***** * ** *** ** ** **** ** ***** * * > x[i+1]){
** * * * * * ******** * * * * ******* * * ** * ** *** * *** ** *** * *** ** ***** exchange the values of x[i] and x[i+1] */
* * * * * * * ***** * * *** ***** * * * * * * ** * * * * * * * ** * * * temporary; ** *** **** ** ** * ***** *
* ** * * * ** * * ** * ** * * * ** ** * * ** *** ** ** **** * ** * *** * *** ** **** = x[i];
* ** * ** * * ** * * * * *** * *** ** * * *** **** * * ** * * *** * * ** ** * * ** ** = x[i+1];
* ** * *** * ** * * * **** * * * * * * ** * **** * * ** **** * * * * ** ** **** * * * * * = temporary;
* * ** * *** ** **** * **** *** * * ** * ** * ** ** * ** * ** * * *
* * * ** * ** ** * * * * *** **
* * * ****** ***** * * **
** *** *** * * **** * *
* * * *** ** **** * **** print the array */
***** * * *** * *** * * ******* ** * sorting: \n");
****** * **** *** *** i = 0; i < size; i++){
*** ** * * *** * ** * ** * * * * * * * ** ** ** ** ** * ", x[i]); ***** * ** ****** * *** ** **
** **** * * * * * * *
*** *** ** * ** * * * ** * ** ** ** * * * *
*** *** * * **** ** * ***
** ***** * * * * ****
** **** * * * * * * * * * * * ***
* * ***** * * * * ***** **** ** * *** * ** *** * **  
* * * ** ** * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * ** ** * ** x[] = {77,22,88,11,22};
**** * * **** * * size = 5;
    
*** * *** * * * * * *** * * * print the array */
* ** * * * * ** * ** ****** i = 0; i < size; i++){
** ***** * *** * * **** ** **** ** ** * ** ** ***** * ", x[i]); * ** *** *** *** ** ***** *
* * * ***** * * * ** * *** *
*** * * *** * *** ** * *
** ** *** **** *** * * *
** * * * *** * I need this to happen size-times */
* * * * * * * ** * ** j = 0; j < size; j++){
******* ** ** * ***** * *** ** * * ** **** * *** from left to right */
**** * * ** * * ** * ******* ** *** **** ** ** * * i = 0; i < size-1; i++){
* **** * * *** * * ** ****** *** * ** * ** * * *** * * *** i-th element with its neighbor to check if they are in order */
** ***** * *** * ** * ** ** ** ** * * * *** **** * ****** ***** * * > x[i+1]){
* ***** * ** ** * **** ******* * ** ** *** * ** ** * ** ** * * * * ** ** ** * exchange the values of x[i] and x[i+1] */
*** *** * *** ** ** * * * * * * * * ***** * ** ** ** ** * **** * * ** *** ** *** ** temporary; * ** ***** * * * *****
** * ** * * **** *** *** *** * ** * * ****** ** * * * * * ************ * * * * * * * ** ** * * * = x[i];
* *** ** **** * * ***** * ** ***** * ** * * * * * * * ** ** ** ****** * * * * ** ** * ** = x[i+1];
** ****** ***** *** * ** * ** * * * ** * ** * * *** * * * * * * * ***** * * * = temporary;
*** * * * ** ** ** ** * * *** ** * ** **** ** **** ** * * ** ***
*** * ** *** * * * ******* **** * ** ** ** ***
* * **** * ** ** * * * *
* *** ** ** * * ** * **
** ** * ******* * *** * print the array */
* * * **** * **** ** * ** ** sorting: \n");
* * * * * **** * * * * i = 0; i < size; i++){
* * ** **** ** *** * **** ***** * ** ***** * * ", x[i]); ** * *** **** ***** * **** * **
*** * * * **********
****** ** **** ******** ** ** * ** *
****** *** * ** **
* * ***** *** ***
*** * * ***** * *** * * ** * *** * *
* * ** * ****** * ** ** *** * * * ** *** *  
***** **** * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** ** * **** ** * * x[] = {77,22,88,11,22};
** * **** ** * ** size = 5;
    
*** *** ** ** ** print the array */
***** * * ***** * ** *** ** i = 0; i < size; i++){
*** ** ** ****** * ** ** * * * * ** ***** ******** ", x[i]); * * *** *** ** **** *** * *
* ** * * * * ** ** * * * ***
*** *** * * ** ** ** ** * * *** * ***
* * **** ** *
**** * * * ** * * * *** I need this to happen size-times */
* **** **** * *** * j = 0; j < size; j++){
******* ** ** ** ******** ** * ******* * from left to right */
* * * **** ** * * * ** *** ** * * * * * **** i = 0; i < size-1; i++){
** ****** * * ****** * * *** * **** * * **** * * ******** * * ** * * i-th element with its neighbor to check if they are in order */
*** ***** *** * * * * ** *** * * * *** **** * ** *** ** **** *** * * > x[i+1]){
**** * *** * * * * * ** * ** * * ****** ** ******* *********** * * ********** ** * * *** ******* exchange the values of x[i] and x[i+1] */
** * ** ** * **** * * * * * ***** * *** ** * ** ** * ** * ***** * **** **** * * *** * temporary; ********** **** * * * *** *
** * * *** * * * * ***** * * *** ** * * *** * *** * * * * * ** ** ** ** * * * ** * = x[i];
* ** * * ** * ** * *** ** * ** * ** ** ** ** ** *** ** * * * * *** * ********** = x[i+1];
* *** * * ** *** * ** * ** * ** * * *** * * * ** * * ** ******* ******* ** *** *** = temporary;
** ** **** * * *** ***** * **** ** * ** *** **** **
* **** ** **** ** * * ** * *** * * ** *
** ****** * ** *** *
*** ** ** ****** * *
* * ** * * * * ***** print the array */
* ** ******** * ***** ** * ******** * sorting: \n");
* ** * **** * *** * ** * i = 0; i < size; i++){
* * * *** * * * ** *** *** *** * * * * **** * ", x[i]); * ** ** ** * ** ** **
* ***** * *** * ***
** * * *** ** * **** ** **** **** * ** * **
** * * * **** ** * ***
* * ***** * * ** ****
* ***** * ********* *** * ******* ** **
** **** *** * ***** * * *** * *** *** *** ***  
* * * ****** *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ***** * *** * ** ***** x[] = {77,22,88,11,22};
* ** * * ***** * * * *** size = 5;
    
* *** ***** * * * * *** print the array */
* * * * **** * * * * * *** * i = 0; i < size; i++){
** *** * * *** ** * * * *** * * * ** **** **** * ", x[i]); * ** ***** * * ** ** ** **** *
** * * *** ** * * **
***** * * * * * *** * **** ** *
**** ** ** *
****** **** *** * I need this to happen size-times */
****** ** * ***** ** * * ** j = 0; j < size; j++){
* ** ** * * ** * ***** * *** * * *** **** * * from left to right */
** * *** * * * * * * ** * ** * i = 0; i < size-1; i++){
* *** * * ** ** ** ** * ** * * * ** * ***** ** **** * *** * *** * *** ** i-th element with its neighbor to check if they are in order */
******* *** * * ** * ** **** * * *** ** * * * * * * ** * *** * * ***** * * > x[i+1]){
*** **** ********** *** ** * * ***** * * ** * * ** * *** **** *** * ** *** ***** * * exchange the values of x[i] and x[i+1] */
*** ** * ***** * *** * * * *** ** * *** ** *** **** ** ** ** * ** * * * **** temporary; ** ** * ** ** * * * *** ** **
* ****** * *** ** ***** * * ***** ** **** ** * ** ** ** *** ** * * ** * *** ** * * ** = x[i];
* *** **** * ** *** ** ***** * * * * ******** * *** ** * **** **** *** * ***** * = x[i+1];
** * * ** ****** * * * **** * ** *** **** * * **** ** ****** * ** * * * *** **** ***** * ** = temporary;
** ** * * ** **** * * * * ** ** ******** * **** ** * *
**** * * ** * * ** * ** * ** * ** * * *
* ***** ** ** ** ** ***
*** ** * * * * * *** **
* * * * *** * ** ** ***** print the array */
* ** ** *** * * * sorting: \n");
* ** * ** *** * * * i = 0; i < size; i++){
* **** * * * * ** * * ** *** ** ** ******* ** *** *** * ** ", x[i]); * * * ** ******* ** * * ** *** *
** * * ****** ********
* * *** * * ** * * * *** ** ** * * * *
** ** ** * *** * * * * *
** * **** * * * ***
* * **** * * **** *** *** **
* * * ** ***** ***** ** ** * * ** ***  
***** ** ** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * **** * ** *** ** * x[] = {77,22,88,11,22};
* ** * * * ** **** size = 5;
    
** ***** * *** ** * print the array */
* **** ****** * ******* * ** i = 0; i < size; i++){
** * ****** ** ** * * ** *** *** * * * ** * ***** *** * ", x[i]); * *** * * ** * ** ** * * * *
* * * ** ** **** ** **
* * * ** ** * * *** * * * * **
* * * ****** ****
******** *** ** * * ** I need this to happen size-times */
** * ** * ** * ** * * * * j = 0; j < size; j++){
* * * ** * ** * ** * * ** ** **** * ** ** * from left to right */
* **** * * **** * ** * * * *** ***** i = 0; i < size-1; i++){
* * * *** * ** ** * * ** ** *** * *** * * **** * ** * *** * * i-th element with its neighbor to check if they are in order */
* * * *** ** * * **** * ** * **** *** ** **** *** *** * ** *** * ***** * > x[i+1]){
* * *** ** * *** * *** ** **** ** * * * ** * * **** * * **** * * *** ** * * * * exchange the values of x[i] and x[i+1] */
* *** * *** **** ***** ** ** ** * * * *** * * * **** * * **** * ** * **** ** ** ** **** temporary; ** * ** ** * * ***
** * * * * * ***** * * ** * * * * * ** * *** ** *** * * * * ****** *** ** * = x[i];
* * *** * *** ** ****** * * ** * * ** ** ** * **** * ** ** * * *** * *** *** * ** ** * = x[i+1];
** ** ** ****** ** * * ** * *** * * * ** ** * ** * * *** * * * ** * ** ** ** ** * = temporary;
* *** * ****** ** * ** **** ** ** * * * * *** ****** *
**** * * *** ***** ** * * * *** * * *
* ****** * *** * **
** ** **** * * *
* * **** ***** * * * print the array */
** ** ** * **** * * sorting: \n");
*** * ****** * ** * ** *** * i = 0; i < size; i++){
** *** * ** * ** *** * * * ** ** *** * * **** * ** ", x[i]); ***** ***** ** * ** ** ** ** *
* **** * * * ** *
** *** * **** ** * * ** **** * * ** *
* ** ** * * * **** ** *
* * * * *** *** ** *
* * ** * ** ** * * * * * * ** **** *
* *** * ** * * ** * * * * * ** ** *  
** * * * **** ** *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** *** * * ** * x[] = {77,22,88,11,22};
* * * * * *** *** ** size = 5;
    
* * *** *** * * * *** print the array */
* * ** ** * * * * ** i = 0; i < size; i++){
* ** ** * *** * ** * *** * ** ** * * ** * * ** * ", x[i]); * ** * ***** * * **** * **
* ******* * * ****
*** **** * **** ****** ** * ** ********
* * * * ** * ** *
* ** * ** * * ** I need this to happen size-times */
*** * **** * * *** ** * j = 0; j < size; j++){
*** ** *** * * * * * * * *** ** ** ** * from left to right */
*** *** * * * *** *** * *** i = 0; i < size-1; i++){
* * *** ** * * *** *** * ** ** *** ******** * ** * * * * i-th element with its neighbor to check if they are in order */
* ** * * * * ** ** * * * ** * ** * ** * * * * * * * * *** *** ** > x[i+1]){
* * * * * * * **** * * **** * * ** *** * *** ** * * * * ** * * exchange the values of x[i] and x[i+1] */
* ** **** * *** *** ******* *** ** ** * * * **** * * ** **** * **** * * *** * temporary; ** *** * * ** ** **** ** *** * ***
*** * * *** * ** **** ****** ** *** * **** ***** *** ** **** * * ** * ** **** * = x[i];
* *** * * *** * ** ** ** ** ** * * ** * * * *** * * *** ** ** * *** *** * * * * * *** * = x[i+1];
*** ** * * ** * ***** * * ** * * *** * *** * * ** * * ** * * * * * * *** * * ** ** = temporary;
* ** **** **** * **** * ** ** * * ** ** ** **
* *** ****** * *** * * ** * * * ** ** *
** * * ** * * * ** * *
*** *** ** *** ** *
* ************ * ** * ***** *** print the array */
** *** * ** ** ** * * * * * sorting: \n");
* ** ** *** * * **** * i = 0; i < size; i++){
**** * ***** * * * ** **** ** * ** ** ** ** * ", x[i]); ***** ** * * * * * ** ******* *** * *
** *** ** ** * **** *
* * * ****** * ** *** * * *
* **** *** * ** ***
* * ******** *** * * *
*** * * * ** * * ***** * * *** ***** * * ***
*** *** *** * * *** ** *** * * * * *** * * *  
** * * * * ******** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ** * * * * * *** x[] = {77,22,88,11,22};
* * * * * * * ***** size = 5;
    
* ** ** * **** *** * *** print the array */
*** * **** * * ** ** i = 0; i < size; i++){
* * ** * *** *** * * * * * *** * * ** *** * ** * * ** ", x[i]); * * * * ** ** * * ***** * **
** * ** * *** * * *
*** *** *** ** * * * * ** * **** **** *
* * *** * ** ** **** *
* **** *** * * ** * ** * I need this to happen size-times */
*** ** ***** * *** * * * j = 0; j < size; j++){
** * * * * * * ** ** * ** * * * * ** * from left to right */
** * * ** * ** *** **** ** * ** * ** ** i = 0; i < size-1; i++){
* ** * ** *** ** * * * * *** ** ** * ****** * * * ** * *** * i-th element with its neighbor to check if they are in order */
* * * * * * ********** ** ** * ** * * * * * ** * ** * *** * ******** * * > x[i+1]){
* ** * ***** *** ** ** * * * ** * ** **** **** * * ** *** * * * * ** ** exchange the values of x[i] and x[i+1] */
* **** ** ****** *** * ** ***** ** ***** * * * ** ** ******* ** * ** * *** *** * * ** **** temporary; * * ** ** **** ** **
** * ** * * * *** **** * * * * * *** * * ****** * *** * * *** * * * ** * * ** * * = x[i];
** * **** * * ** ** * * ******* * **** * * ** * *** *** *** * * ** * *** * * ** ** = x[i+1];
*** * * * ** * ** ** ** * * * * ******** ** *** *** * * ** * *** * ** * ** ** **** * = temporary;
* * * * *** * *** ******* * * ** ** * *** * ** * *** * * * **** **
** * ** *** * * * * * ** ** * * *** * **** ***
* * * * * * *** ** **
***** **** ** * * *****
* ****** * * **** print the array */
******** *** ****** * ***** ** * * sorting: \n");
*** * *** * * ** i = 0; i < size; i++){
* ****** * * * * *** **** ** ** ** * *** * * ** *** * * **** ** ", x[i]); * ** *** * ** *** ** ** ***** **
**** ***** * * ** * **
* * ** **** *** * * * * * * * * ***
** ** * * * **** **
* * ** * * * * * * ** *
* ** * ** *** ** * **** * * ** ** * ** * * *
* * * ** * ** * * **** *** **** ** ** *  
*** * * * ** ** * *** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ****** * * * x[] = {77,22,88,11,22};
** * ** ** * * **** size = 5;
    
** ***** ** * * * * * **** ** print the array */
*** * *** * * * * ******* * * i = 0; i < size; i++){
* *** *** *** * *** ** * * *** * * * *** * * *** *** ", x[i]); * * *** * ***** ** *** *
** * * * ** * * * * *
** ******** ** ***** * ***** ****** * *
* * * * ** * ****
* *** ** *** * * I need this to happen size-times */
* ** **** * * * * * j = 0; j < size; j++){
* * ** * * * * ** * * ** ** * * * * *** from left to right */
** *** ** * ** ** ** ** * ** * * * * * ** * * i = 0; i < size-1; i++){
******** * * * ** **** * * * * * * ********* ****** * * *** * * i-th element with its neighbor to check if they are in order */
** * * * **** * *** * * *** ** * ** ******* *** * ** *** * * ***** *** *** > x[i+1]){
*** * ** ** ** ** * *** *** ** ** ** * ** * * * * * * ** ** ** * * *** * * *** * ** *** * * exchange the values of x[i] and x[i+1] */
* * * ***** * * ** ** ** ** * ** ** **** * *** ** *** * ** * *** * * * **** **** * * * * * temporary; * ***** * ***** * * ******* * ** **
******* ** * ** *** * * * * * * *** * ****** * * *** ** ** * **** * * * * ** ** * * **** * * ** = x[i];
* ** ****** ** ** ** **** * * * ** ** * * ***** ** * **** **** * * ** * * = x[i+1];
* ** * * * **** * * **** * **** ** *** **** * * ** * * **** * *** **** ** = temporary;
* **** * ** * ** * ** *** * *** ** ** ** *** * * * ** **
** * *** ** * * * *** * * * * * * * **
*** ** *** * ** *** ** *
** ** *** * * * * *
* ** ** *** ** * * print the array */
* * * *** * * *** * **** ** ** ***** sorting: \n");
** * * * *** * * * i = 0; i < size; i++){
* **** ** ** * ** *** * **** * ** **** * * * ** * ** ", x[i]); * * * ** * * * * ** * ** *
**** * * **** * ** ** *
** * *** ** ** * * * **** * *** * ******
*** ** *** * *****
* * ** * ** * *** **
* * * **** * *** *** ****** **
* *** ** *** * ** * * * * * ** *** * ***** ** **  
* **** * * ** ** ** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ******** * * *** * * * x[] = {77,22,88,11,22};
* * * * * * * * * ** ** size = 5;
    
*** * * ******* * ** * print the array */
* * ** *** * * * * * * i = 0; i < size; i++){
** ** ** ** ****** * **** ** * ** ** * * *** * * * * ", x[i]); **** ** * ** * * * * ** *
* ** ** * **** ** *
** * * * ***** * *** * *** **** * * ***
* ** ** * * *** * *
* ** ** ** * ** ** * * *** I need this to happen size-times */
* * * * ** * *** * ** * * * * j = 0; j < size; j++){
* * ** * ** * * ** * *** * ** ** *** * * ** ** from left to right */
*** ** * *** ** * *** * * * * *** * * ** ** i = 0; i < size-1; i++){
* *** * * ** * *** * *** ** ** * * * * * * * * **** * ** i-th element with its neighbor to check if they are in order */
******** * **** * ** ** * * * * ********** ***** * * * ** > x[i+1]){
** * ** * ** ** * * ** * ** *** ** ** * ** ** * * * * *** *** ** ** ** exchange the values of x[i] and x[i+1] */
*** * **** ** * * * * * ** * * **** * ** ** * * ** * ****** ** * * * ** *** temporary; ** *** * ** * * * ** * **
* * *** * * * *** ** **** * **** * ** * * * * *** ** * * * * * * * * * ** * * * **** = x[i];
****** **** ******* ** ** *** *** **** ** **** * * **** * * ** ** * * ** **** ***** * ** * * * = x[i+1];
** * * * * ** *** * **** ** * * * * ** ****** *** *** ** * * * * * *** * ** * *** = temporary;
* *** * * * * * * *** ** * *** ** * * *** * * * **
****** *** * * ****** ***** * * * * *
** * * *** * **** *
* * **** * ** ** * *
** * * **** * * * print the array */
** * * ****** ** ** * * * *** * *** sorting: \n");
* ** ******* ****** i = 0; i < size; i++){
** * **** * * * * **** * * * * * * ** * ** * ** *** ", x[i]); * *** ******** * * * * **
* ** * * * ***
* ** **** * * *** ** * * * * ** **
** * ** * ** * ** ***
*** ** *** * **
** *** ** ** * * *** *** * * ** * ** ***
***** *** ** ******* *** ** * *** * * * * ****  
* ** ** * ** * ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * **** ** * x[] = {77,22,88,11,22};
******** ****** * * ** * * * size = 5;
    
* * * **** * ** ** print the array */
* **** **** ** * * * * i = 0; i < size; i++){
** **** *** ** **** * * ** * * ** **** * ** * * ", x[i]); ***** * * * * * ** * * * *
* * ** * * * * * ** * ***
* * ** * ** * ** **** * ** * * *** *
* ** **** ** * * * *
* *** * * * * ** *** * ** ** I need this to happen size-times */
** * * *** * *** * ** ** j = 0; j < size; j++){
* ** * * * * ** * * * ** * *** * * ** from left to right */
**** * * **** * * ** * * ***** ** *** * i = 0; i < size-1; i++){
* * ** * ****** * * * * ** **** ** * * *** ** * ** * * ** * * * ** i-th element with its neighbor to check if they are in order */
* * * * * ** * *** * ** * * *** * * * ** * ** ****** * ********* > x[i+1]){
** * ** ** * * *** **** * * ** **** * * * **** * * *** **** * **** * * *** * exchange the values of x[i] and x[i+1] */
**** *** ** * ******* * ** * **** * **** * ** ** ** ** * ***** * ****** ** * * temporary; *** ***** *** ********* **** * *
** ** * * * ** ** * *** ** * * *** * * *** ******* ** * ** *** **** **** *** ** = x[i];
* ** ***** * * ** ** ** * ** * * **** * * ** ** ** * * ***** ** * * ***** ** *** * * = x[i+1];
* **** * *** ********* ***** **** * * ** * ** * ** * * * * ****** * **** * ** ****** = temporary;
** * * ** * ** ** *** ** ** ***** ** ** ** * ****** ** ***** *** ** ***
* ** * * * * ** ** ***** * * ****
* **** * *** ** * * * *
* ** * * *** *** ** ** **
* * **** * ** **** print the array */
* * * ** ** ** ** * *** * ** sorting: \n");
**** * *** *** ******* * * *** i = 0; i < size; i++){
* ******** ** * * ** *** ***** ** * ** ", x[i]); ********** * * * * * ****** * * **
** *** ** * ** * *
**** * * * ** * * * ** *** * * *
* ** * ** ** * ** **
* * **** *** ** * ****
* ** * ** ** * *** ** **** ** * ** * * ** * *
* * ** * *** * **** * **** *** *** ** *  
** * * **** ** **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.232
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users