11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
17.4k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 17.4k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
*    **  *** *  *** ****    ** *****   %d",&a ,&b );

   * **   *****   *   **   **    i=a;i<b;i++){
*  * *   ***  *     ***  **  *  ***   *    * *** *  *   * ***        j=2;j<=b;j++){
 *   * *** *         **** *  *  ** **   ***** ******   * *  *** * ****  ** *  * && i%j==0) break;
**       *** * *   ****   * ** * *   *   *      ** * *      ** ****  *    * * ***   ** * if(i==j){
* *  * * **  * **    ***  **   *** ***  * * * * *** * *  * ***   *** ***     **  ***** *  **     * * *********    * * * *
** **   * ******   *    **  ** *   ***     *****  **   ******  * *     * ********  **  ****  ***     * *   ** *   *  ** *  **  **  **   ****  
** *******      *  * * **  *   * ***  ** *    *  * **   ** *  * *** * *  * * **     ** * ** **  * * *  ***     * *** *      ** *******   * **
 *  *  * * ** *   ** *     * **** **    * * * *** ****** *** *** ******    * ** ******* *   * *  * * * * * 
*  *  * *** ***   * *** * **  *   **** ** **    *** ***  *   *  *  *   * ** ** ** * *  * *  ***** * *   ***** printf(" %d",i);
  * *  * * * ***  * *  ***** *    * ****     *    *     **** ***       *******  ** * ***
 * *  *     ******    *   * *** ***    * * * *   *    * 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ****  * *     * *  *** * 
    **  * **   *     
  *   *** **   * *  

int main()
{
int i,n,m;
** **   *** * *  * *  * 
  ***   * * **   *   **   *  
* *    *    *   *   

{



    * *** *** * **** 
{
 ******  
 ******
}
** **   ** ** *

 ** *


* * ****** ** ** * * **** **


}}
 * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ***  *  * * **  *  *
* * *   *   ** ***
        ****   **    **

int main()
{
int i,n,m;
* **  *****  **  **  * 
 * *  ***** * **   * *** ** *
 ** **   ** *    * ** 

{



** * *  ***   ** **   *
{
** ***
   
}
***     ****    **

  * *


 **  *     * ****      * *


}}
* *  0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 ** * ** *  *       *  **   *      %d",&a ,&b );

 ******  **** * ** * *  *   ******   i=a;i<=b;i++){
**** * *    ** * *** * **  ** ** **     *** * ******* ** j=2;j<=b;j++){
*  ** * *** ***** ** * * **** *  **** ***  *  ** * ***  *  *   *  ** **  **  *   ** **  * **   * && i%j==0) break;
     *    *  * ****   ** *   ***     * *******  * ****   * ****    * ***    *  *** * **     * ***      if(i==j){
  *     **   ****** * **** ** * *       * **    *  ** **** *    **** * * **  *****   * * ***   * * * **** *  ***   *
     *** *  * ****** *  *   ********* *********   ****** *   *** * * *  * *  * **  * * * ***  * ****** * * **    * ****  ** * *  ******* *   *    ** * * 
*    ***  * ** ****    * ******* * ** *******  ***      *  ** ***    ***      **** *** * *   * * **  *  ** *   * *   ** **  ****   *****  *  
** ***  **   *   *** * * *   ***  * ** ******* * * *  *    ****** * ***    ** ***  * *    * * **   ** * * * ***** * **   *
   ****  ** ** *    ** * **** *  ***  ** ** * *  ***   *** *  **    *** *    *  *  ****   *** * *   printf(" %d",i);
  *   *   * * * * *** * *  *   * ****   * * ** ****     **    * ***      *      ** * ** 
 *  ****  *****   **  * *  ********** ** ***  *** **  **    **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
       *** *  **  * **   * *    a,b;
** * *  **  ** *  ** ** * **   ** * * %d",&a ,&b );

**    **** ** * ** **       ** *   i=a;i<=b;i++){
*  *   ** *    *   *  *** **   ** **** *  ****   **** **  *   * j=2;j<=b;j++){
****** * **** * ** *  * * * ** * *  **   ** *** * * ** * ** ***  *  *  ** **** && i%j==0) break;
* * ****  *** **       * ***    **   *  * ** **      * *  *****   ***   **   * ***    ** * if(i==j){
 * *  *  * **  * *** *** * ** **   ******  *** **   ********  **  * * ** *** **    *   * * **   *  ***** *  * ** **  ",i);
  * *   ****    * * ***  * ** * **** * *  *******  *        **   * *  *   *** *
***    ***** **  *  **    * **  **** *     *** *  ** ** **  

* *    **   *** * ****    * 
*    ***    * *  ** ***  *   * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *****  * **** *
* *  *        ** * *
int main(){
 ***  * **   *    **  *    ** *    a,b;
**** **** ** **  * ****   *  ****   * *  **   ** *  * ** ,&b );

*  *     *  * * ******  *   *   i=a;i<=b;i++){
*  *    *  ********  * **   *  **** ***  *****  * ***  j=2;j<=b;j++){
   * *  * * *    *    * * *    *   *       * *******   ** *   *  **   *   * **** **   && i%j==0) break;
 * **       **   * * *   *  *     *     *   **       *** ****** ** ** * *  ***   ** * * if(i==j) printf("%d ",i);
******  *  * *   ***        *  * *         ** *   **
**    *  ***** **  **  
  * ** *  **   ** * ***** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
     * *** * *******   **  *  m, n, divider, prime[100], cnt=0, i=0;

*** *** ** *  **** ** * **  * * *  ****** %d", &m, &n);

***  * ** *** **** *** * *    = m + 1; m < n; m++)
** *  * *    *  * *  *  ******  *
       ** *     * **   *** *  *  *  * *  *  **   ***  *****     = 2; divider < m; divider++)
 *   * **** *    ******* *** **** * ****  ***  * *
  *  * **   **       *******  *  ** *** *  **** * * *  *** *      * *  *  ** % divider == 0)
   *    **  **   *       **** **   * ****  *  **   ***    *   ** **  ** ** ** *  ***  * **       * ***     * 
** ***  *** * *   **        *** * *  **  **    *    
 * ****   *    * **  * **   **  **   *     ** ** *  *****   == divider)
***    ** ** **** ** * **   ****   *** **  *    * **  * 
   *  ****      ** *      * **  ** *    * *  * ** ****   ***** ******** ***      ****  = m;
       * ** * * * * *** **** *  * *    ** ***  **  * 
 ** * **** * *  *  **** ** 
* *     **  **  * **  *** * i<cnt;i++)
** *   *****   * ***    *** 
  * ***  *** **   * *  * *       *  *     ******      * *   * *   *** * prime[i]);
* *  * * ** * **   **** * ** **       * *    *  *  * **   *   *  +1 < cnt)
  * *   *   *  * *          ******      ****** **** **** *** * *  ** *** *      *** *   * ** ** *  *  ");
    }

   ** ** *  *  ** ** *   * * * *  *  0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
   ***    *     *   *   *** *  **   ***   *******
*  ***  **  *    **** * ** *  *   ** *  *    *    * ** ***   ** *  
*   *    **  *   **   ***  **   * * **   * **   ***     * *    * *   * *     ****** * *  **
***** **   * * * ** *   *     ** *  *** ***      * *    * ** *      * *   * ***** *** ** ** ***    * * ** *
* *  **** **   ****     * *      *  *   * ******* **    *  * * *   **   ****** **** *  *     **  
** *    *  *    * ** * *** *  *** * **  * *            ** *  *  ** ***   *   *    * * *  **   * * * **** ***** *   **  *  * *   *   ",i);
*********  *** ***** *** *   * * ***   * *   *****      ***  ***   * ******   *       * *  *  *  ** *   ********
 * ********  *  **    * *     ****  * **     **     **  *  **   **  *    ** * *
    *  **  ***    **   ***** **  *    *     *  * *  *** ** *   *****   ********* * * if(k==0){
***   ***       *   **  ** ** **   *      *****  *  ** * *  * ** ***   * *   ***  ** *  **** * **  *** 
    ***** **   * *   *    **  **  *   ** ** ** * *    ** ** **  ***    *   *
 * *  *** ***  *  *   ** ***** *    ***  * * **** * * *** 
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d  ** *   * *  ** ,&b);

for *      **********
{
  *   *  *** ***  * *    * * *   * **   * is testing\n",i);
*   * ***        ****  **   * j=0;
     *    ***  * ** **  * * ****** * = 1;
  *    * **  **   *     ** (j=2;j<i;j++)
  * * * **     *   ****    *
**   *  ** **     ** *  * ** *    ***  **** *   *  * * **    %d is mode\n",j);
  *  *  * **   * **   ********** *       *   * ****** reminder=i%j;
*  ** *****  ** ***   * * ** * *  ** ** * *  *   *** * (reminder == 0)
  *  *** **     * *  ***** *** *  *****     ***  *****
** *** *** * ** **   *** **  *   *  * *   * *    **** *****  *** * *        *     ***     *   *  *   **    *   **** **** * * * * 
 **  **    *** **  *** ** ** * *   *   * ** * *   * **** * *  *    ** * * ** * * *  * *****
* * **    ****  ****** *** **  ********  *  *** ****** **       *  * *   *  ***   * *
 * * *** * * * *   ***   * *      * **   ** ** *  ** ** ***  
 * * *  **** ***  * * *** 
* *    * ** **** *  ******* *  (flag==1)
 * *  ** ** ** *          *    *** *   * *     * *  *  * * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.204
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 12.1k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users