0 like 0 dislike
13.3k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 13.3k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * * * * * *** ***** *** * %d",&a ,&b );

** * * **** ** * * * ** *** * i=a;i<b;i++){
* * * * * * * * ***** *** *** * ** * * * *** ** j=2;j<=b;j++){
** * **** * ** * * * *** * * * * * ** * * * ** * **** ***** ***** && i%j==0) break;
**** * ** ***** *** **** * * ** * * *** * * * ** * **** * ** *** if(i==j){
* *** ** ** * * *** ** *** ** *** * * **** ****** ***** * * * ** ** ** ** ** * ** ****** * ** *
* **** * *** *** *** * ** * *** *** * **** * * * *** ********** * **** * ****** ** * *** ****** * * *** ** * ** * ******** *** * *****
*** * **** **** ** * ** * * * * **** *** ** ** * **** ***** ** ** *** * * ** ***** **** **** ** **** *
****** ** ** * ** * * * * * ** * ** **** ** ** * * *** * * * ** * * *** **** ***
* * *** * * * * ** **** * * ** ** * ***** * * * *** * ** * ** ***** printf(" %d",i);
** ** * * * * ** * * * ** **** * * * *** **** * ** * * **** ** ***
******* * ** * * ***** * * * * * *** * * * * **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** ******* ** **
* ** * *** **
** *** ** *

int main()
{
int i,n,m;
** * ***** ******** * * ** ***
** ** ** *** * * * *
**** * * ***

{



* * * * * * *
{
* ***
*** *
}
* ** *** ** ***

**


*** * * ** * ***


}}
* ** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** * * ***** *** * *
** * ** **** **
*** * *

int main()
{
int i,n,m;
* *** * ** * * ** *** *** **
* * ** **** **** * ** *
* * * * ****** * *

{



* * *** **** * *
{
*
* *
}
*** **

*


* ** * ** ** *** *


}}
*** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* ** * ** *** *** ** * %d",&a ,&b );

*** ** * * *** * * * ** i=a;i<=b;i++){
** ** * * ** ** *** * *** **** ** ** *** ** ** j=2;j<=b;j++){
* ** ******** ****** ***** * ** * * * * * *** *** ******** * * **** * && i%j==0) break;
* * ***** * ** ** * ** ** * ** ***** ** * ** *** * * * *** * * ** * if(i==j){
*** *** * *** * * **** * ****** *** * *** ** ** * ** *** * **** * * ** ** ******* * * *
* * **** ** * * * **** * *** * * * ** * * * * * ** ********* ** ** ** * ***** * * ***** *** ** * * * ** * *
* * * * * * * ******** * ** * * * *** ** *** ***** * * ** * ** **** ** *** * **** **** ** * ** * * *****
** * * * ** ** *** * * ** ** * * *** * *** * ** ** * ***** ** * * * *** *** * * ** ** **
* ** * ** * ** * ** * * * ***** ** * ** *** * **** * * * * ** ** * ** ******* * ** * * ** * *** printf(" %d",i);
* * * **** * ** *** ** * * * ** **** * * * ** * * * ** * * * *
* ** *** * * * ** * * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
*** *** * ** ** ***** * a,b;
** * * ** **** ** * * ** * ** * %d",&a ,&b );

* * * ** * ** ** * i=a;i<=b;i++){
** ** * **** * **** * ** * ** * *** * ****** j=2;j<=b;j++){
* * * * ** ** * * * ***** * **** ** *** * ** ** * **** * ** * * ** && i%j==0) break;
** * * *** * ****** ** * * ** * ** * ** ** ** * ** *** *** * * *** *** * * if(i==j){
*** * ** *** * * * *** ** *** ** ** * * ** *** * ** * * * ** ** * ** ** * *** ",i);
* ** ** * ***** **** ** * * ** * ** *** *** * * ** ** * * * * **
* * **** * * *** * ** * * ** * * * **

***** * * * **** * * * **
* * * ** * * * ** ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * ** * *
* * ** * *
int main(){
**** ** **** * **** * a,b;
** ** **** * ** * **** * *** * * * ** * *** * ,&b );

** ** * * * * *** * * i=a;i<=b;i++){
* ** ****** *** * ******* *** * ** * * * * ** j=2;j<=b;j++){
* * * ** *** *** ***** *** **** **** *** *** ** * **** ** ** * *** * && i%j==0) break;
** * ** ** * * * ** * * *** * * *** ** *** *** * * * * * if(i==j) printf("%d ",i);
* *** ** *** * * *** * * * * * * ******* * *
***** * ** ** * ***
* * *** **** * * ** ** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ***** ** * * * * *** m, n, divider, prime[100], cnt=0, i=0;

* * *** * * * *** ***** * * * %d", &m, &n);

* ** *** *** * *** = m + 1; m < n; m++)
*** *** * *** ** * *** *
**** * *** * *** ***** * **** ** ** * * * * * * *** = 2; divider < m; divider++)
** * ** *** * ** ****** * * ** ** * ** * ***
* ** ** * **** * * * **** * *** * * * *** * * * * * * * * *** ** ** * % divider == 0)
** * ** * * * **** * * *** ** ** *** * ******** * *** *** ** * ** *** **** *** * ** * ***
* *** **** ****** * ** * * ** *** *** **
** * *** * * * * ***** *** * **** * **** == divider)
* * * * * * ** * *** *** * * *** * ** *
* * * * **** *** * *** * ** * * * ** * * * * * * *** *** *** * = m;
** *** ** **** ******* * ***** * * * * * * **
** ** ** **** * ** ** ****
* ** * * * * * * *** i<cnt;i++)
**** ** * *** *
* * *** ******* ***** *** ** *** * * ** * * * * ****** ** * prime[i]);
**** ***** *** * ** ** * * * * ** * *** * +1 < cnt)
* * *** * * * * **** ** ****** ** * * ** * ** * * * * * *** * * * ** * * **** ** ");
    }

* * * **** * * * ** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* *** ** ***** * * * * * * *
*** * * * * ** * * * ** **** * * * ** *
******** *** ****** ** *** * *** ***** *** ** * * ** * ** ****** *
* * * ** ** * ** ***** * * *** ** * * * * * ** ** **** * ** * ****** ** * ** *
*** ** * **** * *** * *** * * **** * * ** * * * * **
** ** * * ** * * * * * * *** * * * * * * ** ** * * ** **** * **** **** * * * * ** * * * *** * ** * * * ",i);
** ** ** * ** * ** * ** ** *** * ******* ***** * **** * ** ** * * * * * **** **
* *** ******* * * * **** * ***** * ** ** ** ** * *** ** ** **
*** * ** * ******* *** * ** ***** * * * ** * ** * *** * ** ** * * * if(k==0){
* **** * ****** * ** * * *** * ********** * ** ** * * * ** * * ** * * * * * *
* * *** ** ** * * **** * * * * ** * ** * * ** ** *** * *
*** ** * **** * ** ** * * ***** *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * * * * * **** ,&b);

for ** *
{
** * * ****** ** * * ** is testing\n",i);
* * ** * ** * * ** * j=0;
***** * * * * ** ** = 1;
*** * * * ** * * *** (j=2;j<i;j++)
** ** ** * ** *** * * *
* * ******* * *** * * * ** *** * **** ** * *** * * * * ***   %d is mode\n",j);
* * * ******* ** ** *** * ** * ** reminder=i%j;
******** * * * * **** ** * * ** ****** *** (reminder == 0)
* * * * ** **** ***** * * * * ***** **** *
* ***** * ** *** ********* ** * **** **** * ** * * ** ** * ****** * ** * * * ** ** * * * **** ****
* * * * ** ** ****** * * * ** ** * *** * **** * ** **** ****
* * ** **** * * * ** ** **** *** ** **** * * * ** *****
** * * * ** * **** ** * * ** * * **** ** ** **
** *** * * * * ** ** **
*** *** ** * ***** * (flag==1)
* ** *** **** ** * *** **** ** * * *** *** *** * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.101
©2016-2025

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.1k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 10.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users