11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
19.9k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 19.9k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
**  * ****** ** ***     ****** * *****  *  %d",&a ,&b );

** *  *  *  **    *   *    *   i=a;i<b;i++){
*    ** * ** *      * ** *  * ***  *   ** ** * *   *  ** j=2;j<=b;j++){
 **  ******   *** ** ***       * * **********      ** ***  **  * * **** ** **  ** **   && i%j==0) break;
*** **    * *  * *   **   ****   * **  *     *** ***    ***  ****** ** *  *  * ** if(i==j){
  ***** ** *  ** ********    **** *   ****  * * *       * *    *  *** *****   *  ****  *    *    *   *  * * *****
** *    ****  *     * *    *** * * **   *  * *        *** ***  ***    *     ** ** *  *  * ****   *** * * ********   **** *  **  *** ** * ** * **** *   **
 * *  *  * ** *   *** * ** *  ****  * * ** ****  ** * * **  ***     *** * ***  ***   *********  **   ** ***    **    ** ** ***   *
******  **   *** *****  *  *  **** ******       *  *   **  * ***  *  ** *** * * **  * ** *  ****
**     ***    *       * ** *  **** *  **** *  ***** **    ** ***  ****** *  * *  *   * ******* *** ***  **** *   **  printf(" %d",i);
  **  *    *** *  *  * *     ** * ** ****  *** *  *   *     ****    **  * *** * 
* *****   ********** ***  *** *   ** * **    * ** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***  * * *  * * *  *** 
  *     *    *    * *  
**   ******  ***   

int main()
{
int i,n,m;
  **  *     * * ***  * ** 
  ********  *  * ** **    *
   *  * **    * *

{



* ***  ******** *     
{
** *  ***
*** 
}
 * * * ****  *  

****


*** *  *  *** ** ****   


}}
 * * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***  * * ** ***** *
* *** *  **  **     *  **
**** *** ***  * *    **

int main()
{
int i,n,m;
****  *   *** *   *** *     *  
 * * **  *  **   *   *  ****** 
 *  **** **   **  ***

{



*   ** * ****  *** *  **  
{
  **     
 *** 
}
**  * *   *****   

*   


  * * ****  *  ****** *** 


}}
*** * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
***  **  * ** ** ***       * *** * *  *  %d",&a ,&b );

**** * *   * **  * *** *   * * i=a;i<=b;i++){
*   ** **   *** *    * *  * ** **** * * **** * ***  *** j=2;j<=b;j++){
    * *** * *  *   **  ** *   * *****   ** *   *  *     *  ***** * *  ****** * **  *** && i%j==0) break;
** * *  *   *    * ** * ****  *   * ** ********* ********      ***** **    * if(i==j){
  ***** * ** * **   ****  ** *  **   * **      ***  * ** ***  ** **** *** *     *    **   **    * * * ***  ** * 
  *** * * *    ***        **  **     * * *     ** *** ***  *****      *   ** ****   **  * *     *** *    *   ** * *****  * *  * *  **  *    ***  ***
*** *** *** * * *   *  *      ***  **  *** * *  ***       **   * ****  *  *** ** *   * * *  *      ***** **  *   *** **** * *  *      **  * *
   * *   *    *** ***        ******** *  ***    ** *  **    ** *****  * * *   ****** * ***    **** ***** * *  *   ** 
  * * **     * ****  * **    ****  ******    * ***  * *   * * * ***  * *** **   *** *  *   **** **       ** printf(" %d",i);
*  **   ** **  *  * * *** *   **** * * ******   *  ** ** * **  *  * *** **   
  **    * *** * ***  *** *   * *            *** * ** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
** *    *    ** ****  *** ** a,b;
*    ** *      ******  * * *    * ** **  *  %d",&a ,&b );

** ***   * *  ** *  ***   ****   i=a;i<=b;i++){
 *** *    **      * **   *   ** *** * *   *   **  *   ** ** * * j=2;j<=b;j++){
    * * ***    **    * * *** ** * * ** * ***  * *    *  **   * *  *  *  ** ***** *   *  && i%j==0) break;
 * * * * *    *  ** * * * ** *    ** *   ** ***   ** * ** * ****  *  *  * if(i==j){
**** **    * *  * ****   ** ****  * * ** ***   *    **  *  ** **   ******          *   * ** *  * *** *  *******   *  * **** ",i);
  ** ** *** *  *  * *** * ** **   ******           *     ** ** ** *  * **  * *  * ***
****   *** ***  **** * ***  **  * *    * **  * *    * ***   

* ***** *  * *****  ***  
* **    * * *  *    **  * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ***  **   *       ***
  ******   ***  
int main(){
* ****   ******  ** **   *** a,b;
* **** *  * *  *  *  *  **** *    * *    * *** **  *** * ,&b );

   * *  * ** ** ******  * ** * **  i=a;i<=b;i++){
* *    *      * *   **  *  * *******  *   * *    ** ** * **    j=2;j<=b;j++){
*  * ** *     *** *  * * * ** ****** *  ** **** *** * *  **  ******** ************ *  && i%j==0) break;
*   ** * **          ***  * *** **  *** ** * *    ******  ***  *** **  *** *   if(i==j) printf("%d ",i);
***** ** * * * * ******  * **     * *   *   * **  *
     * ** ********  **** * ** * 
 * ** *** ******   *** ** *    0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  ***  *   ****   ** * **     m, n, divider, prime[100], cnt=0, i=0;

   *   ** ***   ***   *** * ***  ** *** %d", &m, &n);

** * ***** *     **  * *** * = m + 1; m < n; m++)
*  * ***  **   **  *     * ** * 
* **  ***  *   * *    *   **  * *     ** *  **     *   *  *   = 2; divider < m; divider++)
   *********  *** *   ******* ** * * ** * **   * ** ***
***  *   ***     ** *** *  * ** *  ** *****  *   *      * * *** * *  * * * *** % divider == 0)
    * *     * *  * * * * ****** *****  * *** *****  *   *   ***** **    *******   * * ** *    *  * ** ***** 
**  **      **   *** *   *   **   ** *  *****  * * * * *
 ** * * *  *  * *        *  * * *  ****  *** ** ****  ***   * == divider)
   *   **   * ****  *  * ** *** *** *** ****   *** *** * 
 *  * **      *    *    * * ****  ** * **    * * *  **  *  **   *** *** * * **  * *****   *** = m;
 *      **  *   *  *  **       *** ****  ***     **  **
 *   * * * * ****    **  *
*       ** *  **** **  * * * *  *****   i<cnt;i++)
  ***  *   * **   *  ****  
    * **  ****  * **   ** *  * *  *  * * *    *  **** ** *       ***   *** prime[i]);
 * *** ***   ***** * **  * *******  ***** *  *    ***** ** ** +1 < cnt)
    * **       *   *** * *****  *   *    * *    **  **     **** * **    * * ** * *  * * ****   ");
    }

 ***  * *     *  *   ** ***** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* *** *  * * * * * *** ** **** * **    * ** 
  **   * * **   *  ** * * * *  ** **  ** *     **** **  ** ** ***  *    *
*  *   **    **  *   *  *** **           ****   * **   * * ** ****     *  ** *  *
*** ***     * ** ***   * * **  *  ***  *  *    *** *   **    * ***** ***   *  ***  * *  *       *   * 
   *   **  *     *  *     *      *    * * * ** *  *** *** **** **  *  *   ** *****  ****   **   
*** ** * *    ******* ***    **    ****        * ***   *  *     ***  **   *  **** **   * **       **** *  * * **** *  ** ",i);
   * *** ** * *  * **   ** * *** * ** ***   *  *  *  ****** *** **  *    * *  *   *   *  * ** **    **** ** **
 * *   *  *****    * *  *** **   ** *** ** * *   **  *  ** * ****   ***  ** *   * * *
****  * *  *** *** *    * ** *  *  **  ** * **   ***     *   *  ** **       ** if(k==0){
 ** *  ****  * * ** ** *   **    ** ***  ** * * ******   *  ***** ***     *   * **  *  *  *   ** ** * * * 
**  * *** *  *   **  **** ** * **      * * *****  *  *  * **  * ** *  * ***         *  ** **
 * ***    *   * * * *  *      * ***  * ****  *** **  
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * ** ** **      ,&b);

for  *  **  ***  *** 
{
 *** **** * **   * **    **  *  ** is testing\n",i);
* **  ** *** *   * ** * ****   j=0;
***   ****** * *****    ** * ***** *  = 1;
  **  ***    ****  * **  * *  * * (j=2;j<i;j++)
 * *  *  ******     *  *  *** 
*   ** ***  * **   *** * * *  *   **    * ****  *  *    * *** *   %d is mode\n",j);
  ***  * *  **** *******  * *** * ****     *  **      reminder=i%j;
 *   * ***** ***  ****   **  ** * *** *****     *  *  * * * (reminder == 0)
 * *****   * ***  *  ** * * *** **  ***  ******  *      **
    * *    **** **  ** * *     *  *   **  ** **** * * * * *** * **         ****  ****  * *   * *  *    *   * *** ****  * **      *
 ** **  *  **** ** **     *        *  ****  **** **    **  ***  **  **    *  *  **
**   *   * * * * ** **     *   **  **   *** * **** ** ***  *** *       *  *          
**** **    ** ** *       ** ** *   *** ** * * ** ** *****  
**   * *** * ****  ** ** *   * 
* ** * *  **  *  *  ***  * *  * (flag==1)
*   *     *  ** ***** ***  *  ***  * ** ******* ***  * *** *   * **  *  * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.205
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.9k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users