11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
3.8k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 3.8k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 **** **   *    ** ***    *     * *  * %d",&a ,&b );

** * *  *  *  ** ****  ***       i=a;i<b;i++){
    * ** *** ** **    **      * * ****          ** ***  j=2;j<=b;j++){
*  * *   ***  **  * ** **  ***  **  ***  **     *********** * ***  * *   ** * ***** * * && i%j==0) break;
** ***  * * * * *  **** * * *  ** **  ***  *   * * *  ******  *  * ** * *  * **  **   * if(i==j){
**    **  ***    *  * ** *   *         ****   ***  * * ******   **  ** *   *  *   ******* *  * ** *  **  *
* *****     ** ** *****  * *  ***         *** * **  *  ** ****    *   *****    * * * *  *****  **   *       *  *** *   * *   *  ***   ***    *  *       *****  ** *** *
* ***  * ** * *   **  *  ** ** *  **** ** *** * ** ** *    *** *** **  * * * *  **** * *       *  ** *** * ******  * * * ***   * * *
**  *    *  * *    * ***   * *    ** **   ** *** * *  *** **   **  **** * ** *  *    ** *  * ***     *******
** ***  *****  **** * ***  * ** * * *  *** *    *  *   * **  **   *   *** *   *  *  ** ** *  **  ** * printf(" %d",i);
  *  * ***   ***** ******  **    **    *** ***   *   * **** **  *  *  *  * **     *  *    
 * *    *  ** *  ********* * * * ***   *** ****   *  

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ** **  * ** * * 
 ***  * * * * *  ** ***
*    *    * **** ** *****

int main()
{
int i,n,m;
*  ***** * * **  *  ****     **
  * ** * *   ***  * * * ***
 * * ***   *   **

{



    * *  **   *****     * * 
{
 * * ***
  **
}
* ***  **  * * * 

 *   


 **   **   *   **  *  *  


}}
  ** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ***** **  *   * * ****   
**** *****  *  *  **
*****   **    *   *  **

int main()
{
int i,n,m;
*  * * ** * ***    * * *   *
 *    **  ** ** ** **** ******* 
 * ***  **** * * * * 

{



    ****** *    ** 
{
 ****  
* *** 
}
     **  * * *    

   


** ***  *     * * *   *   


}}
** *** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 *      **    ** **** *    *  *** *  %d",&a ,&b );

**  ** *  ** *  *   ** * ****   * * i=a;i<=b;i++){
*  *** * ***  **** **** * * * ** * ***** ** * *  ** * *  * j=2;j<=b;j++){
*  ******  ** * * ** * *   *     * ** * *   *      * * ****   ***  * * *  ** ** && i%j==0) break;
 *****     ***  **  **   *      ** *  **  *     *   ** * ** * *  * *   * *     *** if(i==j){
 * **    *  *   *   *  **  *   * ***  * ** *   ** *   ***  **    * * ***  * *  ** *  *   * **   *      *** *** * ***
* ** * ******  *** *** *  *   *   ****   *    *****  **   ******  ****  * **    *  *** **  *  *  ** * *  *  ** * ******* *  **** *** *****  * * **** 
* *  **   * * ** ** **** * * * ***  * ** * * *  ** **** ** **** *   *******  ** * *   *********   ****      *   **        **  *  *  ****     *
 **      *    ****     *   * **   * *  ** *    *** ** *   *** * ***  **  * ***  ** *********  ** * *  *****
 ** *  * *  ****      *      **  *****   *****  *  ***       *  *************     ****  * * *     * *  *** ** ** *  *  printf(" %d",i);
  *   **  * *  * *  **  **   *     * * * * *   ** ** *      ****** * *   ** * * ***** 
** **   * * **   *       * * *   * ** ** *  **** *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
 *    *  *   *  *   *     ***  a,b;
 *      **   ****     **  *  **   ** * * %d",&a ,&b );

  * ** ***  *** *   *  *  *  **  * * i=a;i<=b;i++){
  *** ***** *** **  ****  ***  *******  ** *  ** * ******  j=2;j<=b;j++){
 ** ***  **   ******  **  **    * *  * ***   *  *** ** ** **   ***  * * ** ** **  *  && i%j==0) break;
*   * *     **  * ** *  **  *****     **  ******  ** ** **  *** ***  **  * * ** * * **  if(i==j){
****** ** * ****  **  **  **        **  ****         *    * * *  *    ****  *  ** * **   * ** ***** ******** * * *  *   *    ",i);
 **  **** *****  ***  *** ****      *****  **** * *      ** * ** ** **   *    
 ** *  ** * ***   *****    **  ** * ******   ** * *   * **** **

 **  *    *  * * * ******  
***     *********    ** * * ** ** **  0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * ** * **  ** **  
  *** ****  *    * 
int main(){
* * ***  ****  *     *   * * a,b;
**   **  *  ** *** * ***   ** **  **  * ***   **  **  ** * ***** ,&b );

* ** *  * ***  *   **  *   *  **   i=a;i<=b;i++){
 *   *  ** *** * * * *     *   **   * *   **  ** *   *  * j=2;j<=b;j++){
**** **  * * * * ***** *** ***    **        * *   **** * ** *** *  *    * *   ***** **  * **  && i%j==0) break;
***  *  ** *** **  *   ***  *** ** *  ** * *****    *  **  *** * * *****   if(i==j) printf("%d ",i);
   * ****  *    *  **  * * ***  * *  * ** ** * *****
  ** *** *  *  **   *  *** * 
** *  ****          *  * ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *** ** * **  * *  **  ** * ** **  m, n, divider, prime[100], cnt=0, i=0;

** **   *  *****  *  ** **  *****     %d", &m, &n);

 ***** ** *   * ****    *   ** = m + 1; m < n; m++)
*  *   * *****  * **  * *  *
* * *** * *     * ***    *  **     * * *   *  *  * ***  ** ****  = 2; divider < m; divider++)
* *  *        * ******   **** ** ******  *   *** * *  **  
 * * *    *** **  * *  * ***** *        *  **   ***** **        *  ***   ** **     % divider == 0)
 ** *   *   ** * *  *  **  **** ** * *** *  *** **  *   *       **   * **  **  *  *** *  ***  * * ** 
 **  ********** **      *      *   * *  ***  **** * ** **
  *** *  * **  *** **  ***** * ** *    * ** *     *   ****  * == divider)
  *  * ** ** ***    *  *** *  ** **     * ** ***  *** ** *  
*  *   ** *** ** *** ** *   **** * *  *****   ******   *** *     * * *  ***      *** *** *  **  = m;
**  ** ** * **     *******  *  ******** ***** **  *  
  * *    *    ** ** * ***
  *    ** *** ** ** * *  *    i<cnt;i++)
   * ** *    *  *****  * * 
   *  **** * *    *  ***  **   ** ***** *  ** *  ***  ** *       **** **  *    prime[i]);
   *   * *    ***** * * ***** * * ******    *       **   +1 < cnt)
***        * *  *  *  ****   *    * ** *  ** * *       * *  ** *  *  *******  ** ***  ** * *    * ");
    }

** ** *   * ***** ** *  * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* ***  * *** *   ** ***  *  *  *  * * * *
** ** ***  *  **   * ** ***** ****   **** **  ** *  *  * *  *  **    
  *** *    * *** ***  ***    ***  *   * ****** * *     ****  *     * * *      ** **      *    
 **  **** * *  * *    *   * * ****      ** *      *** * * * ****** ** * * ***   **  *****     *   ** ***
  *  *** *  **  * *    * ******  * *  *   **  **** ***  ** ****  *  *** ** **  *  ** ** 
*  **********  **    **   **   *  * *** * *  ** *  * * *   * * ****   ** * ** ** * * *****   ** * *   *  ******      ** ** ",i);
  ** ** *****  *  **  *** * *  * *  * ** **  * * * **  *  ****** ** ** * ** **  *  * **    **   *    * ** *  **** **   
    **  *  **    *  *** ** * * *** *****   ****    **  ** *    ****  *  *  
* *  **  * *   *      ** *  ***  **     *  *** * * **** *     **  *            if(k==0){
* ****  *    *     * *   * * * ** **** * *    ** * **   ***** * *  *  ***    * ****  **  *   **   * ****  
 *  * **   *         *** ***  **   *  * *** * **  *****   *    * **  ***  **** ***  
*  * *  * ** *   *  **  *****  * **      **   * ** ** ***
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * * ***   ***  ,&b);

for ** *** * * ***
{
  * ** *  * *   *******  * * ***  *  ** is testing\n",i);
* ** * ***  * ** *  *   *  j=0;
 **  *  * *    * * ** * * * = 1;
* * * ****    * *   * **   *  (j=2;j<i;j++)
*   ****     *** ** * **
**   *****    *** *  *   *    **  ****    ***  * * *    ** *  ***** *   %d is mode\n",j);
* * *  **  **   *** * ** * **   *       * ***   *****    reminder=i%j;
  * ** **  *  *   * *   ***** ** **** * ** **   *  ** * ** ** (reminder == 0)
 * *     ****    *  *  *  * **  * * ***   ** *** *  *  *
** *       * ***    * *   *  * * * ***   *      *** ** ** **  * ****   *** ****** *   *** **  * **   **  **** * *  **** *** *  *
***  ***   *** *  **** *  *   ***   **  * **      *  *****   * *   *   * **    ** ** *   ** *  **
****    * *       **** * ****** ** *  **** ************ * *          *   **** *** * 
  *    * ****    ** ** *****  *** *** *   * * *** **  
 *** *     * *  *  *  **  * ** *
   *     ** * ** ***   *  ***   *   (flag==1)
* *  ***  * *     * *   ***   * **   ***  *    ****** **    ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.213
©2016-2024

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.6k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 3.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users