0 like 0 dislike
17.4k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 17.4k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * * *** *** * * ** * %d",&a ,&b );

* * ** ** ** ** * **** i=a;i<b;i++){
**** * * ** * * * *** ** * ***** * * ** *** * ** j=2;j<=b;j++){
* * * ** *** *** * * * *** ** * ** *** * ** * *** * *** *** && i%j==0) break;
** * * ***** ** * *** ** * * * ****** ** ** *** * * * *** * *** if(i==j){
* * * **** ** * * * *** * * *** * * * ** * ** *** * *** * * ** * * * ** **** ***
* * **** ** ***** * *** * ** * ********* * *** ** ** * ** * *** * *** * ******* * * * * ** ** * ** ***** ** ** ** **
* * * ** *** *** ** ***** * ** * *** * ** ** * * * * * ** ** * *** ****** * * * * * * * *
** * ** ** *** ***** * ** ** ******** * * * ** ** ** * ** ** ** * ** *** *** ***
* *** * ********* * * ***** **** * * * * * ***** ***** ** * * * * * ****** ** * * ****** * **** * printf(" %d",i);
** ** *** ** ** * * ****** * ** * * * ** * ** *** ***
** * ** ** * * * ** ** *** ** * ** ***** ***

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * ** * **** * **
** *** * * *
* * ** * ***

int main()
{
int i,n,m;
***** *** ****** **** ****
* * * *** *
* * * ** *** *

{



* * * * ** ****
{
****
*
}
** * * *** *

* *


*** * * *


}}
** ** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * ** ***
* *** * * * *** * **
* *** * * * * * *

int main()
{
int i,n,m;
** * ** * ** * * **
* * * ******** * *
* * * ***

{



*** ****** * * **
{
* * *

}
**** *** **

* ***


** ** * **** ** **


}}
*** * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
** ** * * ** ** * ** *** ** %d",&a ,&b );

******* * * *** **** * * *** * i=a;i<=b;i++){
**** * ** ** * *** *** * ** * * *** * **** *** j=2;j<=b;j++){
* **** * * * ** **** ** * * ** ****** *** * ** * * * * * ** **** && i%j==0) break;
* *** * * *** *** ** * ** ** ** * * * * ****** ***** * ** *** ** *** if(i==j){
* * *** * * * * * * * *** * ***** ***** ** * * ** ** * * ** * * * * * * *
* *** * * * * **** * * * * * * **** **** ** * * * ** * * * ** * * ** * ***** ** * ** * *** ** *** * *** * * *
**** * ** *** ** **** * * * * *** *** * * ** ****** *** ** *** ** ** * * ** * *
*** * * * ** ** * *** * * *** * ** *** * * * ** * ** ** * * * ** * * * *** ** **
* ****** ** ****** *** *** ** * ** * **** * ** *** * * ** * *** ***** * * *** * printf(" %d",i);
**** * * ** ****** * * * * * * * * * *** * * ** * * *
** *** ** *** ****** * ** * ** ** ** ***** * **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* ** ******* * * * a,b;
*** * * * *** * * *** *** * * ** %d",&a ,&b );

* *** **** ** *** * * i=a;i<=b;i++){
* * ***** * *** * *** ** **** ** * * j=2;j<=b;j++){
** ** * ** ** * **** * *** ** ** * ** * ** *** * && i%j==0) break;
** ** * * * * ** ***** ** *** * *** * ** * * ** ** *** if(i==j){
* * * * * * ***** ** ** *** **** ** * ** * * *** ** *** * * ** * ** *** ***** * *** *** * *** * *** ** ",i);
*** * * ** * * * **** **** * * ** * * **** *** ** * * ******* **** * * ** **
* ** ** **** * * ** * *** *** ** * *

* *** * * ***** **** ***
***** * *** * * ** * * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * ** * **
* ** ** ** * **
int main(){
* * * * *** * ** a,b;
* * * ** **** **** **** ** ** **** * *** * ,&b );

**** ** ** *** * * ** *** ** i=a;i<=b;i++){
*** ** ** ** * ** ** * * ** ** ** ** **** * ** j=2;j<=b;j++){
* * **** * * **** ** *** ** *** ***** * * ** * * * *** *** * && i%j==0) break;
* *** * * * * **** * ** * * *** * * ** * *** **** *** ** *** ** * if(i==j) printf("%d ",i);
* *** ** ** *** * ** **** * * * ** * ** * * *
**** * * *** *** * **
** * **** * * ** * *** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *** * * ** ** m, n, divider, prime[100], cnt=0, i=0;

* * **** **** *** *** *** * ** * * %d", &m, &n);

* ** *** ** *** * * ** * * = m + 1; m < n; m++)
* * * ** * ** **
* *** * *** **** * * * * * ** * * ***** ** * * = 2; divider < m; divider++)
* * * * * ** ***** ** * * ** *** ** ** **** **
* * * * * ** ** * * ** * * ** * ** * ** ** * * ** ** * ** % divider == 0)
*** * * ** * ** ** * ** ** ** ** * ******* * ** * * ** * *** * ****** *** * ***** * *
****** * *** ****** ***** * * ** * **** *
**** ** ** ** * **** * * * * *** * * == divider)
* ** ** * * ** ** *** ** ** ** ** *
***** * *** ** ** ** * * ** ** * *** ****** * * * ** ** ** ****** **** = m;
* ** * *** * ** ****** ***
* ** ** ** * *
* ** ******** * * * * * * i<cnt;i++)
**** ** ** ** *
* *** * **** * ** * ** * *** ** ** * * *** * *** * ** prime[i]);
* *** * ** * * ** ** * ** * * * * *** * * +1 < cnt)
** **** * * * ***** * * * *** ** *** **** ** * * * ** * * * * *** ** ");
    }

* * * **** *** ** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* ** * ** *** **** **** ** * **
** ** ***** * * * * * * * **** * * * * * * ***** * **
* * * * **** * ** *** * * * * ** * ********** **** * **** * * *** * ***
***** * * **** * **** * ** ***** * * **** * * ** **** ** * ** *** * ** * **** ******* *
* *** *** ** ** * ** * * ** * * ** ** * ** *** * ***** * ** * *** * * *** ******
* ** * ** * ***** **** *** * * * * * ** * ****** ** * *** * * ** ** * * *** **** * *** ******* * ***** ",i);
* *** ** * ** *** ** * ** ** * *** * * * * * * * *** * ******** * * ** *
* * * ** * * **** * ****** * ** ** ** * * ****** * * * * *** ***
***** * ** ** *** * * * ** * ** * ** * * ** * *** if(k==0){
*** * ** * * *** * ** * * * ** **** * * ** * **** **** ***** * *** *** ***** **
******* * ***** * * * * ****** ** * **** *** * ** ** ***
**** * ** * * *** * ** ** ****** * ** ** *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d *** * * * * * ,&b);

for ** ** * *
{
**** *** * *** **** * ********* is testing\n",i);
* ** ** ** * * j=0;
* * **** ** ** ** ** * * = 1;
** * * * * * * *** (j=2;j<i;j++)
*** **** * *** * * * *
** ** * * *** ****** ** *** * *** ** ** **** * * *****   %d is mode\n",j);
* * ** * ** * * ** * ** * * * *** ***** * * reminder=i%j;
* * **** * * * * * ** * * ** *** * * ** * * (reminder == 0)
* ******* **** *** * * * ***** *** **** *
* ***** * * * * * ** * ** ******* * ** * ** * * * ** * ** * ** ** *** * * ****** *
* * * * * **** * ***** * ** *** ** * * ** *** * *** *****
* ** * ********* * * **** ** * *** * **** * **** *** * * ** * * ** *
* **** ** * * * * * * *** ** * * * ** * *****
*** * * ** * * ** * *
** * ** * *** * (flag==1)
* ****** * * ** ** ** * ** ** ***** * ** ** * ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.233
©2016-2025

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 12.1k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users